ID: 10026
Updated by: sniper
Old-Status: Open
Status: Feedback
Bug Type: *General Issues
Assigned To: 

I can't reproduce this (using code below):



for($i=0; $i<$c; $i++) {
    echo "yes\n";


Could you try this one?
And note: If the variable passed to count() is not an array,
it will return 1.


Previous Comments:

[2001-03-27 11:09:08] [EMAIL PROTECTED]
The code submitted is inside a function that is called recursively and its not exact 
copy of the code.

I've also tried to change the for loop to a while loop with the same result.


[2001-03-27 11:07:07] [EMAIL PROTECTED]
I have a strange situation;
I have this code : 

$c = count($myarray);
echo $c . '<br>';

for ($i=0; $i<$c; $i++) { 
   code goes here... 

echo often often output that $c is 0 BUT the for loop ALWAYS execute...
I also have tried to sorrund the for loop with this :
if ($c>0) {

and it STILL execute if $c==0


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