ID: 10026
User Update by: [EMAIL PROTECTED]
Old-Status: Feedback
Status: Open
Bug Type: *General Issues
Description: For loop always execute
Its not easy reproduceable - i have only seen this happens ONCE - in the specified
function. Its NOT a simple for-loop - the for-loop executes INSIDE a recursively
called function.
I've also tried this one :
---
$c = count($myarray);
if ($c>0) {
echo "c is greater than 0<br>";
for (...) {
...code
}
}
---
then IF c is 0 the echo statement doesnt execute BUT the for loop executes...
I cant figure out why...
If some of you want it i can mail you the file so you can see the things in
perspective.
- Svein
Previous Comments:
---------------------------------------------------------------------------
[2001-03-29 11:55:23] [EMAIL PROTECTED]
I can't reproduce this (using code below):
<?php
$c=0;
for($i=0; $i<$c; $i++) {
echo "yesn";
}
?>
Could you try this one?
And note: If the variable passed to count() is not an array,
it will return 1.
--Jani
---------------------------------------------------------------------------
[2001-03-27 11:09:08] [EMAIL PROTECTED]
The code submitted is inside a function that is called recursively and its not exact
copy of the code.
I've also tried to change the for loop to a while loop with the same result.
---------------------------------------------------------------------------
[2001-03-27 11:07:07] [EMAIL PROTECTED]
I have a strange situation;
I have this code :
$c = count($myarray);
echo $c . '<br>';
for ($i=0; $i<$c; $i++) {
code goes here...
}
echo often often output that $c is 0 BUT the for loop ALWAYS execute...
I also have tried to sorrund the for loop with this :
if ($c>0) {
for(...)
}
and it STILL execute if $c==0
---------------------------------------------------------------------------
Full Bug description available at: http://bugs.php.net/?id=10026
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