ID: 10026
Updated by: sniper
Old-Status: Open
Status: Feedback
Bug Type: *General Issues
Assigned To: 

As I can not reproduce this with latest CVS please try
the latest snapshot from

And if happens with it too, create one 
short but self-containing script which can be used
to reproduce this anywhere without modifications
and add it into this bug report.


Previous Comments:

[2001-03-29 12:57:01] [EMAIL PROTECTED]
When i said ONCE - i didnt mean ONCE :)
It ALWAYS happen in the code referred...


[2001-03-29 12:55:32] [EMAIL PROTECTED]
Its not easy reproduceable - i have only seen this happens ONCE - in the specified 
function. Its NOT a simple for-loop - the for-loop executes INSIDE a recursively 
called function.

I've also tried this one :
$c = count($myarray);
if ($c>0) {
  echo "c is greater than 0<br>";
  for (...) {
then IF c is 0 the echo statement doesnt execute BUT the for loop executes...

I cant figure out why...

If some of you want it i can mail you the file so you can see the things in 

- Svein


[2001-03-29 11:55:23] [EMAIL PROTECTED]
I can't reproduce this (using code below):



for($i=0; $i<$c; $i++) {
    echo "yesn";


Could you try this one?
And note: If the variable passed to count() is not an array,
it will return 1.



[2001-03-27 11:09:08] [EMAIL PROTECTED]
The code submitted is inside a function that is called recursively and its not exact 
copy of the code.

I've also tried to change the for loop to a while loop with the same result.


[2001-03-27 11:07:07] [EMAIL PROTECTED]
I have a strange situation;
I have this code : 

$c = count($myarray);
echo $c . '<br>';

for ($i=0; $i<$c; $i++) { 
   code goes here... 

echo often often output that $c is 0 BUT the for loop ALWAYS execute...
I also have tried to sorrund the for loop with this :
if ($c>0) {

and it STILL execute if $c==0


The remainder of the comments for this report are too long.  To view the rest of the 
comments, please view the bug report online.

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