--- Bertrand Mansion <[EMAIL PROTECTED]> wrote:
> <[EMAIL PROTECTED]> wrote :
>
> >>>> I guess I am going to have to write stupid code such as:
> >>>>
> >>>> switch ($param1) {
> >>>> case 'parser1':
> >>>> return parser1::method();
> >>>> case 'parser2':
> >>>> return parser2::method();
> >>>> }
> >>>
> >>> call_user_func(array($param1, 'method'));
> >>
> >> No. Undefined variable this in $param1. Get it ?
> >>
> > No. The code you displayed (in the switch block) is 100% identical to the
> > code Derick offered (except for the fact that Derick's example will handle
> > any class name while yours is limited).
> >
> > $classname::method() === call_user_func(array($classname,'method'));
>
> No. $classname::method() is illegal and is in no case === to
> call_user_func(array($classname,'method')) as you state it.
>
> Class foo {
> function bar() {
> echo $this->param;
> }
> }
>
> Class MyObject {
> var $param;
> function MyObject($param) {
> $this->param = $param;
> foo::bar();
> }
> }
>
> $obj = new MyObject('out of this');
>
> will print 'from MyObject'.
This SHOULDN'T print 'out of this', This seems like a bug, and you SHOULDN'T
depend on this functionality. The scope of $this inside class foo method bar,
Should be to foo::bar NOT MyObject::MyObject. Which if my memory serves me
right $this inside a static method will just be the string of the current
class?
>
> While,
>
> Class MyObject {
> var $option;
> function MyObject($option) {
> $this->option = $option;
> call_user_func(array('foo', 'bar'));
> }
> }
>
> will return 'Undefined variable: this'...
This should be the way that both examples function.
$this is a refrence to the current object. inside a static method like
foo::bar() there is no $this defined because its static.
- Brad
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