You're wrong here, my friend. You can have any value you like.
value="@£$ASDFSDF   ASDP fosifu @}{$#%/&@   " would work.


Niklas

-----Original Message-----
From: hugh danaher [mailto:[EMAIL PROTECTED]] 
Sent: 1. helmikuuta 2002 10:48
To: Luke Welling
Cc: Php-General
Subject: Re: [PHP] Re: Anyone Up?


I think you'll need something like this:
VALUE=\'Your Name1\'       / /single quote marks I believe (and I
certainly
could be wrong).
otherwise it'll truncate at 'Your'
of course, if this is what you want...
Hugh

----- Original Message -----
From: "Luke Welling" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Thursday, January 31, 2002 11:50 PM
Subject: [PHP] Re: Anyone Up?


>
> "Jtjohnston" <[EMAIL PROTECTED]> wrote in message 
> [EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> > Luke is that 6:47 pm tomorrow? :) You lost an entire day! Enough Oz 
> > Jokes. Here is my predicament in Canada :-)
> >
> > $varname = "Check".$i;
> >
> > $varname = "Check1" but I want $varname = "Your Name1" to "Your 
> > Name12".
> >
> > One more try? :)
> >
> > <INPUT TYPE="checkbox" NAME="Check1" VALUE="Your Name1"> <INPUT 
> > TYPE="checkbox" NAME="Check2" VALUE="Your Name2"> <INPUT 
> > TYPE="checkbox" NAME="Check3" VALUE="Your Name3"> etc.
> >
> > for ($i = 1; $i <= $NMax; $i++)
> > {
> > #$varname = "$Check".$i;
> > $varname = "Check".$i
> > #echo $varname;
> > if ($varname)
> > echo "$varname = $i<br>";
> > }
>
> In that case it is easy, I did not know that the ids were just 1 to 
> 12, I thought they could be anything spat out by the database.
>
> How about something like this:
>
> for ($i = 1; $i <= $NMax; $i++)
> {
>   $varname = "Check".$i
>   if (isset($$varname)
>     echo $$varname."<br>";
> }
>
> Luke Welling.
> --
> PHP and MySQL Web Development
> by Luke Welling and Laura Thomson 
> http://www.amazon.com/exec/obidos/ASIN/0672317842
>
>
>
>
>
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