An undefined function error has nothing to do with where you are calling the function from. It has to do with whether or not you have defined the function you are calling.
-Rasmus On Sun, 22 Dec 2002, Beauford.2002 wrote: > Hi, > > I previously asked a question about getting undefined function errors in my > script and someone mentioned that it may be that I am calling it from within > an if or else statement. This turned out to be the case. Now the question - > is there a way around this? What I need to do resolves around many different > conditions, and depending on the what's what I call the necessary function. > I have looked my script over and over and can not see any other way of doing > this. I am fairly new to PHP and maybe there is a better way, and I'm open > to suggestions. > > TIA > > Example: > > if ($a == $b) call function one; > > elseif ($a > $b) call function two; > elseif ($a == $c) call function two; > elseif ($a < $b) call function two; > elseif ($c > $b) call function two; > elseif ($d == $e) call function two; > > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
