Finally got it working, but I have no idea how. I rewrote the script
changing a few if's and elseif's so there weren't as many, but still calling
the functions from the if/else statements. The format of the new script is
the same as the old one, and other than a few modifications, I still can't
see where the old one failed. In any event, I appreciate the help from all
who responded.
Beauford
----- Original Message -----
From: "Rasmus Lerdorf" <[EMAIL PROTECTED]>
To: "Beauford.2002" <[EMAIL PROTECTED]>
Cc: "PHP General" <[EMAIL PROTECTED]>
Sent: Monday, December 23, 2002 2:40 PM
Subject: Re: [PHP] Undefined Functions
> I have no idea what you have done wrong. I am simply telling you how it
> works. Create a small test script that reproduces the problem and we can
> help you. What you have provided so far does not give us anything to work
> with.
>
> Try this, for example:
>
> <?
> if(true) func1();
> else func2();
>
> function func1() { echo 1; }
> function func2() { echo 2; }
> ?>
>
> When you run this you will see that it prints out 1 which should satisfy
> you that you can safely call functions inside conditionals and have them
> be defined at the bottom of your script.
>
> Your job now is to tell us how your script differs from the above test
> script, because as far as I have understood this is the exact situation
> you say isn't working.
>
> -Rasmus
>
> On Mon, 23 Dec 2002, Beauford.2002 wrote:
>
> > Then based on the one below that doesn't work, what is the problem with
it?
> > As I said, the functions are at the bottom of the script. The only thing
> > after them is the closing ?>. I also said that they work if I don't call
> > them from within an if/else. This tells me it is not where it is defined
but
> > where it is being called from. Your saying this doesn't matter, but have
not
> > given any reasons for my problems. If you could elaborate on this it
would
> > be appreciated.
> >
> > Beauford
> >
> > ----- Original Message -----
> > From: "Rasmus Lerdorf" <[EMAIL PROTECTED]>
> > To: "Beauford.2002" <[EMAIL PROTECTED]>
> > Cc: "PHP General" <[EMAIL PROTECTED]>
> > Sent: Monday, December 23, 2002 11:14 AM
> > Subject: Re: [PHP] Undefined Functions
> >
> >
> > > Like I said, where you define your function is important, not where
you
> > > call it. If you are defining and calling it all in the same place,
then
> > > yes, obviously it makes a difference.
> > >
> > > -Rasmus
> > >
> > > On Mon, 23 Dec 2002, Beauford.2002 wrote:
> > >
> > > > I have a function at the bottom of my script which is called from
> > withing an
> > > > if/else statement. If I take it out of the if/else and just call the
> > > > function it works fine (except I don't get the results I want). So
it
> > > > appears where you are calling it from does matter. See the examples
> > below.
> > > > This isn't the first time either, I have had to redo several scripts
for
> > > > this project because of it. If I'm doing this wrong based on the
> > examples
> > > > below, please let me know. Thanks.
> > > >
> > > > i.e.
> > > >
> > > > This doesn't work. This
does.
> > > >
> > > > some code ......
some
> > code
> > > > .........
> > > >
> > > > If ($bob) { gotofunction($bob); }
> > gotofunction($bob);
> > > > elseif ($sally) { gotonextfunction($sally); }
> > > > gotonextfunction($sally)
> > > > else { gotolastfunction(); }
> > > > gotolastfunction()
> > > > some other code ..... some
other
> > > > code
> > > >
> > > > function gotofunction($bob) function
> > > > gotofunction($bob)
> > > > function gotonextfunction() function
> > > > gotonextfunction()
> > > > function gotolastfunction()
function
> > > > gotolastfunction()
> > > >
> > > >
> > > > ----- Original Message -----
> > > > From: "Rasmus Lerdorf" <[EMAIL PROTECTED]>
> > > > To: "Beauford.2002" <[EMAIL PROTECTED]>
> > > > Cc: "PHP General" <[EMAIL PROTECTED]>
> > > > Sent: Sunday, December 22, 2002 11:16 PM
> > > > Subject: Re: [PHP] Undefined Functions
> > > >
> > > >
> > > > > An undefined function error has nothing to do with where you are
> > calling
> > > > > the function from. It has to do with whether or not you have
defined
> > the
> > > > > function you are calling.
> > > > >
> > > > > -Rasmus
> > > > >
> > > > > On Sun, 22 Dec 2002, Beauford.2002 wrote:
> > > > >
> > > > > > Hi,
> > > > > >
> > > > > > I previously asked a question about getting undefined function
> > errors in
> > > > my
> > > > > > script and someone mentioned that it may be that I am calling it
> > from
> > > > within
> > > > > > an if or else statement. This turned out to be the case. Now the
> > > > question -
> > > > > > is there a way around this? What I need to do resolves around
many
> > > > different
> > > > > > conditions, and depending on the what's what I call the
necessary
> > > > function.
> > > > > > I have looked my script over and over and can not see any other
way
> > of
> > > > doing
> > > > > > this. I am fairly new to PHP and maybe there is a better way,
and
> > I'm
> > > > open
> > > > > > to suggestions.
> > > > > >
> > > > > > TIA
> > > > > >
> > > > > > Example:
> > > > > >
> > > > > > if ($a == $b) call function one;
> > > > > >
> > > > > > elseif ($a > $b) call function two;
> > > > > > elseif ($a == $c) call function two;
> > > > > > elseif ($a < $b) call function two;
> > > > > > elseif ($c > $b) call function two;
> > > > > > elseif ($d == $e) call function two;
> > > > > >
> > > > > >
> > > > > >
> > > > > > --
> > > > > > PHP General Mailing List (http://www.php.net/)
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> > > > > >
> > > > >
> > > > >
> > > > > --
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> > > > >
> > > > >
> > > >
> > > >
> > >
> > >
> > > --
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> > >
> > >
> >
> >
>
>
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