Certainly. "u/y applies the dyad u between the items of y".
This means that u is applied (#y)-1 times. And an error would be inconsistent with the concept expressed for the case where 0=#y. Thanks, -- Raul On Thu, Sep 11, 2014 at 1:50 PM, Dan Bron <j...@bron.us> wrote: > Pepe wrote: >> My only question is: Does the Dictionary support this behavior? > > Raul responded: >> Yes, it does. > > I am intrigued. Can you elaborate? > > In particular, can you help me see, given only the text of the Dictionary, > that u/y where 1=#y must be y ? And not, for example, an error? > > -Dan > ---------------------------------------------------------------------- > For information about J forums see http://www.jsoftware.com/forums.htm ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
