;(<@(''"_`# @.(2018=+/))\.)\2^~i.>.%:2018
12
R.E. Boss
> -----Oorspronkelijk bericht-----
> Van: Programming <programming-boun...@forums.jsoftware.com>
> Namens R.E. Boss
> Verzonden: donderdag 24 oktober 2019 19:30
> Aan: programm...@jsoftware.com
> Onderwerp: Re: [Jprogramming] Quora problem
>
> Obviously the squares >2018 don't play any role whatsoever, so you can
> restrict yourself to %:2018
>
> >a#~2018=>+/ each a=.;<@(<\.)\2^~i.>.%:2018
> 49 64 81 100 121 144 169 196 225 256 289 324
>
> R.E. Boss
>
>
> > -----Oorspronkelijk bericht-----
> > Van: Programming <programming-boun...@forums.jsoftware.com>
> > Namens Skip Cave
> > Verzonden: donderdag 24 oktober 2019 19:12
> > Aan: programm...@jsoftware.com
> > Onderwerp: Re: [Jprogramming] Quora problem
> >
> > To me it seems that R. E. Boss provided the simplest approach.
> > Don't know about efficiency, but the results appear instantly:
> >
> > >a#~2018=>+/ each a=.;<@(<\.)\2^~i.100
> >
> > 49 64 81 100 121 144 169 196 225 256 289 324
> >
> > Skip
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> http://www.jsoftware.com/forums.htm
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