What about using inheritance or adding extra parameter to constructor? I think that it's wrong approach to skip calling constructors.
2009/9/10 dmbaggett <[email protected]>: > > As the subject says, I'm trying to call the constructor of my superclass's > superclass. In essence, I need to skip the superclass constructor, but still > run that class's own superclass's constructor. > > BTW, the reason I need to do this is to prevent my superclass from adding a > listener that I don't want. Since there is no way -- as far as I can tell -- > to remove a listener that was just added by my superclass constructor > without knowing the ID it returned, I have to find some other approach. > (Suggestions welcome.) > > Dave > > -- > View this message in context: > http://www.nabble.com/Call-constructor-of-superclass-of-superclass-tp25391812p25391812.html > Sent from the qooxdoo-devel mailing list archive at Nabble.com. > > > ------------------------------------------------------------------------------ > Let Crystal Reports handle the reporting - Free Crystal Reports 2008 30-Day > trial. Simplify your report design, integration and deployment - and focus on > what you do best, core application coding. Discover what's new with > Crystal Reports now. http://p.sf.net/sfu/bobj-july > _______________________________________________ > qooxdoo-devel mailing list > [email protected] > https://lists.sourceforge.net/lists/listinfo/qooxdoo-devel > ------------------------------------------------------------------------------ Let Crystal Reports handle the reporting - Free Crystal Reports 2008 30-Day trial. Simplify your report design, integration and deployment - and focus on what you do best, core application coding. Discover what's new with Crystal Reports now. http://p.sf.net/sfu/bobj-july _______________________________________________ qooxdoo-devel mailing list [email protected] https://lists.sourceforge.net/lists/listinfo/qooxdoo-devel
