but without calling base(arguments) none of the superclass constructores are
called.
On Thu, Sep 10, 2009 at 10:31 PM, Petr Kobalíček
<[email protected]>wrote:
> What about using inheritance or adding extra parameter to constructor?
> I think that it's wrong approach to skip calling constructors.
>
> 2009/9/10 dmbaggett <[email protected]>:
> >
> > As the subject says, I'm trying to call the constructor of my
> superclass's
> > superclass. In essence, I need to skip the superclass constructor, but
> still
> > run that class's own superclass's constructor.
> >
> > BTW, the reason I need to do this is to prevent my superclass from adding
> a
> > listener that I don't want. Since there is no way -- as far as I can tell
> --
> > to remove a listener that was just added by my superclass constructor
> > without knowing the ID it returned, I have to find some other approach.
> > (Suggestions welcome.)
> >
> > Dave
> >
> > --
> > View this message in context:
> http://www.nabble.com/Call-constructor-of-superclass-of-superclass-tp25391812p25391812.html
> > Sent from the qooxdoo-devel mailing list archive at Nabble.com.
> >
> >
> >
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