Hello,
First thank Greg and Mathias for looking at my problem.
And yes, the proposed solution is working! I didn't think at all by
putting a "module in the middle", to by-pass my cast operation.
Thank you!
Denis
On 04/16/2018 04:01 PM, Matthias Felleisen wrote:
Have you considered organizing your program as follows:
#lang racket
(module a racket
(provide f)
(define (f x) 10))
(module b racket
(provide g)
(define g (dynamic-require '(submod "foo.rkt" a) 'f)))
(module c typed/racket
(require/typed (submod ".." b) [g (-> Integer Integer)])
(g 20))
(require 'c)
That is, run the dynamic-require in an untyped module and then import it
at the desired type?
On Apr 16, 2018, at 5:22 AM, mailoo <dmichi...@mailoo.org
<mailto:dmichi...@mailoo.org>> wrote:
Hello,
I'm new to racket, and even more with typed/racket.
I play a little with the "Any" type (due to 'dynamic-require' which
return Any), and I'm not able to cast them back in a function.
I (over) simplify my question with this little program :
```
(: p Any)
(define (p i) (displayln i))
; Here I want to get back my function
(define proc (cast p (-> Integer Void)))
(proc 2)
```
but I get this error when I try to execute the function :
```
; contract violation
; Attempted to use a higher-order value passed as `Any` in untyped
code: #<procedure:p>
; in: Any
; contract from: typed-world
; blaming: cast
; (assuming the contract is correct)
; at: <pkgs>/racketFBP/test.rkt:13.13
; Context:
; /home/denis/dev/racket/racketFBP/test.rkt:1:1 [running body]
; [Due to errors, REPL is just module language, requires, and stub
definitions]
```
In reality, I get my function by `(dynamic-require path 'p)`, and I
didn't find a typed version of this function...
Is there a way to go from Any to a function, or to replace my use of
`dynamic-require`?
Thank you in advance,
Denis Michiels
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