Github user mateiz commented on a diff in the pull request:
https://github.com/apache/spark/pull/1843#discussion_r16693014
--- Diff:
examples/src/main/scala/org/apache/spark/examples/SparkHdfsLR.scala ---
@@ -70,7 +70,7 @@ object SparkHdfsLR {
val sparkConf = new SparkConf().setAppName("SparkHdfsLR")
val inputPath = args(0)
- val conf = SparkHadoopUtil.get.newConfiguration()
+ val conf = SparkHadoopUtil.get.newConfiguration(sparkConf)
--- End diff --
IMO this should not even be using SparkHadoopUtil, as mentioned above; it
should just create a `new Configuration`. It's okay if it doesn't get the
`spark.hadoop.*` properties, after all you're doing this before initializing a
SparkContext.
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