On Fri, Jul 12, 2002 at 11:07:46AM +0300, Catalin Muresan wrote: > > Raspunsul corect este B : > > Nu exista netmask 255.255.255.208 > > dece?
256-208=48 .... nu este putere a lui 2 .. nu poate sa subneteze > > > ./ipcalc.pl 140.173.169.203/255.255.255.208 > > Corrected illegal netmask: 255.255.255.208 > > dece? > > > > > Address: 140.173.169.203 10001100.10101101.10101001.11 001011 > > Netmask: 255.255.255.192 = 26 11111111.11111111.11111111.11 000000 > > Wildcard: 0.0.0.63 00000000.00000000.00000000.00 111111 > > => > > Network: 140.173.169.192/26 10001100.10101101.10101001.11 000000 (Class B) > > Broadcast: 140.173.169.255 10001100.10101101.10101001.11 111111 > > HostMin: 140.173.169.193 10001100.10101101.10101001.11 000001 > > HostMax: 140.173.169.254 10001100.10101101.10101001.11 111110 > > Hosts/Net: 62 > > -- > Catalin Muresan > ASTRAL TELECOM > Internet Department > --- > Pentru dezabonare, trimiteti mail la > [EMAIL PROTECTED] cu subiectul 'unsubscribe rlug'. > REGULI, arhive si alte informatii: http://www.lug.ro/mlist/ > -- Teodor Iacob, Astral TELECOM Internet --- Pentru dezabonare, trimiteti mail la [EMAIL PROTECTED] cu subiectul 'unsubscribe rlug'. REGULI, arhive si alte informatii: http://www.lug.ro/mlist/
