Yes, position() should do the job for you. It specifies the position
within the context node list. When you select footnotes using
<xsl:for-each select="//footnote">, all of them are in the same node
list, so position() should work. What is wrong?
Petr
Örvar Kárason wrote:
> Hi all,
>
> When processing tags for footnotes in my documents I need to re-numerate
> them, so that the first one that appears is 1, then 2, ... etc. The original
> numbering can´t be used since a web page can contain more then one page of
> the original source, and thus more than one footnote number 1, 2 and etc.
> The footnote tag can appear almost anywhere in my document:
>
> /doc/source/footnote
> /doc/text/heading/footnote
> /doc/text/p/footnote
> ...
>
> <footnote value="FOOTNOTE_TEXT">ORIGINAL_NUMBER<footnote/>
>
> FOOTNOTE_TEXT is printed at the bottom of the page.
> ORIGINAL_NUMBER is not used.
>
> <xsl:number/> seem to be what I need but its not implemented yet.
>
> <xsl:template match="footnote">
> <SUP><FONT SIZE="-1">
> <A NAME="#BODY{ ??????? }">
> <A HREF="#FOOT{ ??????? }"> <!-- jump to the footnote text at bottom of
> page -->
> <xsl:number/> <!-- doesn't work! -->
> </A></A>
> </FONT></SUP>
> </xsl:template>
>
> I use position() to solve this when the footnote-text is printed at the
> bottom of the page.
>
> <xsl:template match="doc">
> ...
> <OL>
> <xsl:for-each select="//footnote">
> <LI>
> <A NAME="#FOOT{position()}">
> <A HREF="#BODY{position()}"> <!-- jump up into main text -->
> <xsl:value-of select="@value"/>
> </A></A>
> </LI>
> </xsl:for-each>
> </OL>
> ...
> </xsl:template>
>
> This seems to be such a simple problem, yet I have been unable to find a
> solution to it.
> All help would be most welcome. :)
>
> Örvar Kárason (XSLT newbie)
> [EMAIL PROTECTED]
--
Petr Cimprich
Ginger Alliance Ltd.
www.gingerall.com
