#17108: IncidenceStructure.degree(set={1,2,3})
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Reporter: ncohen | Owner:
Type: enhancement | Status: needs_review
Priority: major | Milestone: sage-6.4
Component: combinatorial | Resolution:
designs | Merged in:
Keywords: | Reviewers:
Authors: Nathann Cohen | Work issues:
Report Upstream: N/A | Commit:
Branch: u/ncohen/17108 | f82b9c41095b538a5da29ba015264c24adddc7c4
Dependencies: #17104 | Stopgaps:
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Comment (by dimpase):
Replying to [comment:20 ncohen]:
> What I am saying is that in this case, I do not know what do do:
>
> {{{
> sage: H = IncidenceStructure([[1,2],[1,Set([1])]])
> sage: H.ground_set()
> [{1}, 1, 2]
> sage: H.blocks()
> [[{1}, 1], [1, 2]]
> sage: H.degree(Set([1]))
> }}}
well, at least in set theory 1 is not equal to {1}. Thusly the answer
should be 1, as opposed to `H.degree(1)`, which should be 2.
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Ticket URL: <http://trac.sagemath.org/ticket/17108#comment:21>
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