[android-developers] Re: Loading from a compiled xml file
Hi John, Can copy here code to know how you are reading fron input stream. Thanks in advance. On Jul 1, 12:36 am, RespeckKnuckles (John Licato) respeckknuckl...@gmail.com wrote: Hey guys, I have some xml files with a custom format (based on the scxml specifications) that I want my program to read. I've already written the code to read it, but I'm running into problems actually reading the file itself. I want the file to be compiled with the apk, as it will not be changed at all during run time. So I put the file (test.xml) in the res/xml/ folder, and got the inputstream by using: getResources().openRawResource(R.xml.test); but when I read in this inputstream it is complete jibberish, which makes me suspect it is being read in binary, as openRawResource() is often used for binary files like images, if I am correct. What is the correct way to do this? -- You received this message because you are subscribed to the Google Groups Android Developers group. To post to this group, send email to android-developers@googlegroups.com To unsubscribe from this group, send email to android-developers+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/android-developers?hl=en
[android-developers] Re: Loading from a compiled xml file
Hey guys, I put the xml file into the res/raw directory and it works better, but still not working completely. Here is the code I'm using: InputStream toParse = getResources().openRawResource(R.raw.test); // file is in res/raw/test.xml DocumentBuilder db = DocumentBuilderFactory.newInstance().newDocumentBuilder(); Document d = db.parse(toParse); Element rootElement = d.getDocumentElement(); It fails at db.parse(), saying Unexpected end of document found. I've converted the toParse stream into a string and verified it is correct, and I simplified it so that the only xml it reads is: HTML/HTML and it still says the same thing. This may be more of a java DOM issue, but do any of you have any ideas? On Jul 1, 1:42 am, piyu spk2p...@gmail.com wrote: Hi John, Can copy here code to know how you are reading fron input stream. Thanks in advance. On Jul 1, 12:36 am, RespeckKnuckles(John Licato) respeckknuckl...@gmail.com wrote: Hey guys, I have some xml files with a custom format (based on the scxml specifications) that I want my program to read. I've already written the code to read it, but I'm running into problems actually reading the file itself. I want the file to be compiled with the apk, as it will not be changed at all during run time. So I put the file (test.xml) in the res/xml/ folder, and got the inputstream by using: getResources().openRawResource(R.xml.test); but when I read in this inputstream it is complete jibberish, which makes me suspect it is being read in binary, as openRawResource() is often used for binary files like images, if I am correct. What is the correct way to do this? -- You received this message because you are subscribed to the Google Groups Android Developers group. To post to this group, send email to android-developers@googlegroups.com To unsubscribe from this group, send email to android-developers+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/android-developers?hl=en
[android-developers] Re: Loading from a compiled xml file
Just in case the ?xml ? element was the problem, I tried this xml code instead: ?xml version=1.0 encoding=utf-8? HTML/HTML and still didn't work. On Jul 1, 12:46 pm, RespeckKnuckles (John Licato) respeckknuckl...@gmail.com wrote: Hey guys, I put the xml file into the res/raw directory and it works better, but still not working completely. Here is the code I'm using: InputStream toParse = getResources().openRawResource(R.raw.test); // file is in res/raw/test.xml DocumentBuilder db = DocumentBuilderFactory.newInstance().newDocumentBuilder(); Document d = db.parse(toParse); Element rootElement = d.getDocumentElement(); It fails at db.parse(), saying Unexpected end of document found. I've converted the toParse stream into a string and verified it is correct, and I simplified it so that the only xml it reads is: HTML/HTML and it still says the same thing. This may be more of a java DOM issue, but do any of you have any ideas? On Jul 1, 1:42 am, piyu spk2p...@gmail.com wrote: Hi John, Can copy here code to know how you are reading fron input stream. Thanks in advance. On Jul 1, 12:36 am, RespeckKnuckles(John Licato) respeckknuckl...@gmail.com wrote: Hey guys, I have some xml files with a custom format (based on the scxml specifications) that I want my program to read. I've already written the code to read it, but I'm running into problems actually reading the file itself. I want the file to be compiled with the apk, as it will not be changed at all during run time. So I put the file (test.xml) in the res/xml/ folder, and got the inputstream by using: getResources().openRawResource(R.xml.test); but when I read in this inputstream it is complete jibberish, which makes me suspect it is being read in binary, as openRawResource() is often used for binary files like images, if I am correct. What is the correct way to do this? -- You received this message because you are subscribed to the Google Groups Android Developers group. To post to this group, send email to android-developers@googlegroups.com To unsubscribe from this group, send email to android-developers+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/android-developers?hl=en
Re: [android-developers] Re: Loading from a compiled xml file
Put it back in res/xml/. Use getResources().getXml() to get an XmlPullParser on the file. On Thu, Jul 1, 2010 at 2:47 PM, RespeckKnuckles (John Licato) respeckknuckl...@gmail.com wrote: Just in case the ?xml ? element was the problem, I tried this xml code instead: ?xml version=1.0 encoding=utf-8? HTML/HTML and still didn't work. On Jul 1, 12:46 pm, RespeckKnuckles (John Licato) respeckknuckl...@gmail.com wrote: Hey guys, I put the xml file into the res/raw directory and it works better, but still not working completely. Here is the code I'm using: InputStream toParse = getResources().openRawResource(R.raw.test); // file is in res/raw/test.xml DocumentBuilder db = DocumentBuilderFactory.newInstance().newDocumentBuilder(); Document d = db.parse(toParse); Element rootElement = d.getDocumentElement(); It fails at db.parse(), saying Unexpected end of document found. I've converted the toParse stream into a string and verified it is correct, and I simplified it so that the only xml it reads is: HTML/HTML and it still says the same thing. This may be more of a java DOM issue, but do any of you have any ideas? On Jul 1, 1:42 am, piyu spk2p...@gmail.com wrote: Hi John, Can copy here code to know how you are reading fron input stream. Thanks in advance. On Jul 1, 12:36 am, RespeckKnuckles(John Licato) respeckknuckl...@gmail.com wrote: Hey guys, I have some xml files with a custom format (based on the scxml specifications) that I want my program to read. I've already written the code to read it, but I'm running into problems actually reading the file itself. I want the file to be compiled with the apk, as it will not be changed at all during run time. So I put the file (test.xml) in the res/xml/ folder, and got the inputstream by using: getResources().openRawResource(R.xml.test); but when I read in this inputstream it is complete jibberish, which makes me suspect it is being read in binary, as openRawResource() is often used for binary files like images, if I am correct. What is the correct way to do this? -- You received this message because you are subscribed to the Google Groups Android Developers group. To post to this group, send email to android-developers@googlegroups.com To unsubscribe from this group, send email to android-developers+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/android-developers?hl=en -- Mark Murphy (a Commons Guy) http://commonsware.com | http://github.com/commonsguy http://commonsware.com/blog | http://twitter.com/commonsguy Android Training...At Your Office: http://commonsware.com/training -- You received this message because you are subscribed to the Google Groups Android Developers group. To post to this group, send email to android-developers@googlegroups.com To unsubscribe from this group, send email to android-developers+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/android-developers?hl=en
[android-developers] Re: Loading from a compiled xml file
Sure. Design some XML language -- the one Google used for layouts would work but is rather complex and not focused on your particular problem -- and I think you'd have to reimplement it to use non- compressed XML. There's probably no need to give the server the ability to design completely arbitrary screens anyway. You might be able to leverage an existing dependency-injection package, like Spring. Then load this XML language and interpret it -- creating, adding, and configuring views as indicated by the XML. A HUGE downside to anything like this, is that you lose the ability to customize and localize the layout. So you may want to consider passing the screen resolution and size, language, and other potentially- relevant information to the server, so the server can potentially (possibly after release of the client) make decisions based on this information. On Jun 30, 10:53 pm, ABhi abhishek.gonda...@gmail.com wrote: I'm not sure if i understand the question correctly. My need is slightly different for dynamic screen generation. Hi All, I'm dealing with a problem you guys might not have faced earlier. I'm having a use-case in my Android application where the actual screen that i want to show to user is not stored in any layout file of my application. The layout of the of the screen is designed by server in this case, based on selection made by user on first screen. Let me elaborate here, 1st Screen : List of check box with different biller names. (Imagine i've selected 2 billers from this screen) 2nd Screen : (The screen that server has decided how it should look like) * Header, * 1st Biller name (Label) * Amount for 1st Biller TextBox * Image (a Separator image) * 2st Biller name (Label) * Amount for 2st Biller TextBox. * Here there can be a checbox/radio/another TextBox anything. * Image (a Separator image) * Button (to submit above form back to server) I hope makes some sense in what i'm planning to design. - The current issues i'm dealing with are as below. 1). How to draw this dynamic widgets? 2). How to fetch user Inputs from this dynamically created widgets? Thanks in advance. Regards Abhishek On Jul 1, 9:51 am, Bob Kerns r...@acm.org wrote: Don't put it in the xml/ directory. That does indeed get compiled into a binary format, and you'd need to use the corresponding API for reading it. (Or you could recode to use that API, and gain efficiency and space -- but first, you'd like to test the code you've already written, right?) So put your test.xml into the raw/ directory instead of the xml/ directory (and use R.raw.test). More info here:http://developer.android.com/intl/de/guide/topics/resources/providing... And if you want to move it back and get the benefits of using the compiled format, you'll access it starting with this API:http://developer.android.com/intl/de/reference/android/content/res/Re...) On Jun 30, 12:36 pm, RespeckKnuckles (John Licato) respeckknuckl...@gmail.com wrote: Hey guys, I have some xml files with a custom format (based on the scxml specifications) that I want my program to read. I've already written the code to read it, but I'm running into problems actually reading the file itself. I want the file to be compiled with the apk, as it will not be changed at all during run time. So I put the file (test.xml) in the res/xml/ folder, and got the inputstream by using: getResources().openRawResource(R.xml.test); but when I read in this inputstream it is complete jibberish, which makes me suspect it is being read in binary, as openRawResource() is often used for binary files like images, if I am correct. What is the correct way to do this? -- You received this message because you are subscribed to the Google Groups Android Developers group. To post to this group, send email to android-developers@googlegroups.com To unsubscribe from this group, send email to android-developers+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/android-developers?hl=en
[android-developers] Re: Loading from a compiled xml file
No idea off the top of my head, other than that something you think is true probably isn't. Not exactly a helpful observation... But why not try HTML/ instead of HTML/HTML, and verify that you're getting that. They're equivalent, but going to even simpler XML may lead you to discover the problem by getting you to go through things again. Make sure you didn't accidentally leave in the code to read from the stream and print it out! Also, make sure your input file is in utf-8. (Which in this case, is the same as ASCII/IS0-646). You may have used some editing tool that put it in UTF-16. Or perhaps there's a byte-order mark inserted, and perhaps the parser doesn't handle that properly. On Jul 1, 10:46 am, RespeckKnuckles (John Licato) respeckknuckl...@gmail.com wrote: Hey guys, I put the xml file into the res/raw directory and it works better, but still not working completely. Here is the code I'm using: InputStream toParse = getResources().openRawResource(R.raw.test); // file is in res/raw/test.xml DocumentBuilder db = DocumentBuilderFactory.newInstance().newDocumentBuilder(); Document d = db.parse(toParse); Element rootElement = d.getDocumentElement(); It fails at db.parse(), saying Unexpected end of document found. I've converted the toParse stream into a string and verified it is correct, and I simplified it so that the only xml it reads is: HTML/HTML and it still says the same thing. This may be more of a java DOM issue, but do any of you have any ideas? On Jul 1, 1:42 am, piyu spk2p...@gmail.com wrote: Hi John, Can copy here code to know how you are reading fron input stream. Thanks in advance. On Jul 1, 12:36 am, RespeckKnuckles(John Licato) respeckknuckl...@gmail.com wrote: Hey guys, I have some xml files with a custom format (based on the scxml specifications) that I want my program to read. I've already written the code to read it, but I'm running into problems actually reading the file itself. I want the file to be compiled with the apk, as it will not be changed at all during run time. So I put the file (test.xml) in the res/xml/ folder, and got the inputstream by using: getResources().openRawResource(R.xml.test); but when I read in this inputstream it is complete jibberish, which makes me suspect it is being read in binary, as openRawResource() is often used for binary files like images, if I am correct. What is the correct way to do this? -- You received this message because you are subscribed to the Google Groups Android Developers group. To post to this group, send email to android-developers@googlegroups.com To unsubscribe from this group, send email to android-developers+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/android-developers?hl=en
[android-developers] Re: Loading from a compiled xml file
That's a good thing to do, but he'll have to rewrite his code. It would be wise to test that his existing code is working as a baseline, and check it in to revision control, and write a few unit tests, before doing that. Unless his code is trivial, of course. Or his head gets too bloody from pounding his head against a brick wall... On Jul 1, 12:04 pm, Mark Murphy mmur...@commonsware.com wrote: Put it back in res/xml/. Use getResources().getXml() to get an XmlPullParser on the file. On Thu, Jul 1, 2010 at 2:47 PM, RespeckKnuckles (John Licato) respeckknuckl...@gmail.com wrote: Just in case the ?xml ? element was the problem, I tried this xml code instead: ?xml version=1.0 encoding=utf-8? HTML/HTML and still didn't work. On Jul 1, 12:46 pm, RespeckKnuckles (John Licato) respeckknuckl...@gmail.com wrote: Hey guys, I put the xml file into the res/raw directory and it works better, but still not working completely. Here is the code I'm using: InputStream toParse = getResources().openRawResource(R.raw.test); // file is in res/raw/test.xml DocumentBuilder db = DocumentBuilderFactory.newInstance().newDocumentBuilder(); Document d = db.parse(toParse); Element rootElement = d.getDocumentElement(); It fails at db.parse(), saying Unexpected end of document found. I've converted the toParse stream into a string and verified it is correct, and I simplified it so that the only xml it reads is: HTML/HTML and it still says the same thing. This may be more of a java DOM issue, but do any of you have any ideas? On Jul 1, 1:42 am, piyu spk2p...@gmail.com wrote: Hi John, Can copy here code to know how you are reading fron input stream. Thanks in advance. On Jul 1, 12:36 am, RespeckKnuckles(John Licato) respeckknuckl...@gmail.com wrote: Hey guys, I have some xml files with a custom format (based on the scxml specifications) that I want my program to read. I've already written the code to read it, but I'm running into problems actually reading the file itself. I want the file to be compiled with the apk, as it will not be changed at all during run time. So I put the file (test.xml) in the res/xml/ folder, and got the inputstream by using: getResources().openRawResource(R.xml.test); but when I read in this inputstream it is complete jibberish, which makes me suspect it is being read in binary, as openRawResource() is often used for binary files like images, if I am correct. What is the correct way to do this? -- You received this message because you are subscribed to the Google Groups Android Developers group. To post to this group, send email to android-developers@googlegroups.com To unsubscribe from this group, send email to android-developers+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/android-developers?hl=en -- Mark Murphy (a Commons Guy)http://commonsware.com|http://github.com/commonsguyhttp://commonsware.com/blog|http://twitter.com/commonsguy Android Training...At Your Office:http://commonsware.com/training -- You received this message because you are subscribed to the Google Groups Android Developers group. To post to this group, send email to android-developers@googlegroups.com To unsubscribe from this group, send email to android-developers+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/android-developers?hl=en
[android-developers] Re: Loading from a compiled xml file
Don't put it in the xml/ directory. That does indeed get compiled into a binary format, and you'd need to use the corresponding API for reading it. (Or you could recode to use that API, and gain efficiency and space -- but first, you'd like to test the code you've already written, right?) So put your test.xml into the raw/ directory instead of the xml/ directory (and use R.raw.test). More info here: http://developer.android.com/intl/de/guide/topics/resources/providing-resources.html And if you want to move it back and get the benefits of using the compiled format, you'll access it starting with this API: http://developer.android.com/intl/de/reference/android/content/res/Resources.html#getXml(int) On Jun 30, 12:36 pm, RespeckKnuckles (John Licato) respeckknuckl...@gmail.com wrote: Hey guys, I have some xml files with a custom format (based on the scxml specifications) that I want my program to read. I've already written the code to read it, but I'm running into problems actually reading the file itself. I want the file to be compiled with the apk, as it will not be changed at all during run time. So I put the file (test.xml) in the res/xml/ folder, and got the inputstream by using: getResources().openRawResource(R.xml.test); but when I read in this inputstream it is complete jibberish, which makes me suspect it is being read in binary, as openRawResource() is often used for binary files like images, if I am correct. What is the correct way to do this? -- You received this message because you are subscribed to the Google Groups Android Developers group. To post to this group, send email to android-developers@googlegroups.com To unsubscribe from this group, send email to android-developers+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/android-developers?hl=en
[android-developers] Re: Loading from a compiled xml file
I'm not sure if i understand the question correctly. My need is slightly different for dynamic screen generation. Hi All, I'm dealing with a problem you guys might not have faced earlier. I'm having a use-case in my Android application where the actual screen that i want to show to user is not stored in any layout file of my application. The layout of the of the screen is designed by server in this case, based on selection made by user on first screen. Let me elaborate here, 1st Screen : List of check box with different biller names. (Imagine i've selected 2 billers from this screen) 2nd Screen : (The screen that server has decided how it should look like) * Header, * 1st Biller name (Label) * Amount for 1st Biller TextBox * Image (a Separator image) * 2st Biller name (Label) * Amount for 2st Biller TextBox. * Here there can be a checbox/radio/another TextBox anything. * Image (a Separator image) * Button (to submit above form back to server) I hope makes some sense in what i'm planning to design. - The current issues i'm dealing with are as below. 1). How to draw this dynamic widgets? 2). How to fetch user Inputs from this dynamically created widgets? Thanks in advance. Regards Abhishek On Jul 1, 9:51 am, Bob Kerns r...@acm.org wrote: Don't put it in the xml/ directory. That does indeed get compiled into a binary format, and you'd need to use the corresponding API for reading it. (Or you could recode to use that API, and gain efficiency and space -- but first, you'd like to test the code you've already written, right?) So put your test.xml into the raw/ directory instead of the xml/ directory (and use R.raw.test). More info here:http://developer.android.com/intl/de/guide/topics/resources/providing... And if you want to move it back and get the benefits of using the compiled format, you'll access it starting with this API:http://developer.android.com/intl/de/reference/android/content/res/Re...) On Jun 30, 12:36 pm, RespeckKnuckles (John Licato) respeckknuckl...@gmail.com wrote: Hey guys, I have some xml files with a custom format (based on the scxml specifications) that I want my program to read. I've already written the code to read it, but I'm running into problems actually reading the file itself. I want the file to be compiled with the apk, as it will not be changed at all during run time. So I put the file (test.xml) in the res/xml/ folder, and got the inputstream by using: getResources().openRawResource(R.xml.test); but when I read in this inputstream it is complete jibberish, which makes me suspect it is being read in binary, as openRawResource() is often used for binary files like images, if I am correct. What is the correct way to do this? -- You received this message because you are subscribed to the Google Groups Android Developers group. To post to this group, send email to android-developers@googlegroups.com To unsubscribe from this group, send email to android-developers+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/android-developers?hl=en
