RE: Oracle-L at UKOUG

2002-11-22 Thread Docherty, Heather
Yes please.  I am flying down from Edinburgh on the Monday morning and I
have never been to this before so any guidance about what to do would be
appreciated.  
 
Beer / food sounds good, though.
 
Heather

-Original Message-
Sent: 19 November 2002 20:19
To: Multiple recipients of list ORACLE-L


Anyone interested in an Oracle-L get together at UKOUG for those of us poor
souls who were not able to attend Oracle World? OW attendees welcome also!
 
Dan Fink

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Storing of number datatype in table

2002-11-22 Thread Sathyanaryanan_K/VGIL
Dear List

Have a look at the sql !!!

SQL create table trnid
  2  ( trn_id number(10));
Table created.

SQL insert into trnid(trn_id) values('11');/* 10 1's inserted*/
1 row created.

SQL insert into trnid(trn_id) values('1');/* 9 1's inserted*/
1 row created.

SQL commit;
Commit complete.

SQL select trn_id from trnid;

   TRN_ID
-
1.111E+09
1

can anyone tell why the number(10) is stored in exp format

Regards,

Sathyanarayanan


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RE: Oracle-L at UKOUG

2002-11-22 Thread Mark Leith
Hi Heather!

Gerry is coming along as well, so I'm sure he can will give you guidance if
you need it. I'll get him to email his mobile number over to you just in
case.

Anybody else that has been before have any ideas on a place to eat? I know
of the couple of cafe restaurants at the back in Brindley Place, and of
course places like Hard Rock Cafe, TGI's and a whole host of other kinds of
food down Broad Street.. Anybody have any preferences?

-Original Message-
Heather
Sent: 22 November 2002 10:49
To: Multiple recipients of list ORACLE-L


Yes please.  I am flying down from Edinburgh on the Monday morning and I
have never been to this before so any guidance about what to do would be
appreciated.

Beer / food sounds good, though.

Heather

-Original Message-
Sent: 19 November 2002 20:19
To: Multiple recipients of list ORACLE-L


Anyone interested in an Oracle-L get together at UKOUG for those of us poor
souls who were not able to attend Oracle World? OW attendees welcome also!

Dan Fink

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RE: Storing of number datatype in table

2002-11-22 Thread Jack van Zanen
I believe that one position is used for positive/negative value. So it
wouldn't fit otherwise

-Original Message-
[mailto:[EMAIL PROTECTED]]
Sent: vrijdag 22 november 2002 12:24
To: Multiple recipients of list ORACLE-L


Dear List

Have a look at the sql !!!

SQL create table trnid
  2  ( trn_id number(10));
Table created.

SQL insert into trnid(trn_id) values('11');/* 10 1's inserted*/
1 row created.

SQL insert into trnid(trn_id) values('1');/* 9 1's inserted*/
1 row created.

SQL commit;
Commit complete.

SQL select trn_id from trnid;

   TRN_ID
-
1.111E+09
1

can anyone tell why the number(10) is stored in exp format

Regards,

Sathyanarayanan


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Re: Storing of number datatype in table

2002-11-22 Thread Joe Testa

its not stored that way internally

its just displayed that way.

do a set numwidth 20

joe


[EMAIL PROTECTED] wrote:


Dear List

Have a look at the sql !!!

SQL create table trnid
 2  ( trn_id number(10));
Table created.

SQL insert into trnid(trn_id) values('11');/* 10 1's inserted*/
1 row created.

SQL insert into trnid(trn_id) values('1');/* 9 1's inserted*/
1 row created.

SQL commit;
Commit complete.

SQL select trn_id from trnid;

  TRN_ID
-
1.111E+09
1

can anyone tell why the number(10) is stored in exp format

Regards,

Sathyanarayanan


 


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RE: Storing of number datatype in table

2002-11-22 Thread Paul Heely
I think the number is still being stored as 11, but only being
displayed in E notation.  When I try it I get:  

scott select * from trnid;

TRN_ID
--
 1
 1
11
11

Elapsed: 00:00:00.00
scott

I entered both as a number 1 and a character string '1',
like you did.
Have you specified a format for the trn_id column?

--
Paul


-Original Message-
[EMAIL PROTECTED]
Sent: Friday, November 22, 2002 6:24 AM
To: Multiple recipients of list ORACLE-L


Dear List

Have a look at the sql !!!

SQL create table trnid
  2  ( trn_id number(10));
Table created.

SQL insert into trnid(trn_id) values('11');/* 10 1's inserted*/
1 row created.

SQL insert into trnid(trn_id) values('1');/* 9 1's inserted*/
1 row created.

SQL commit;
Commit complete.

SQL select trn_id from trnid;

   TRN_ID
-
1.111E+09
1

can anyone tell why the number(10) is stored in exp format

Regards,

Sathyanarayanan


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Re: Storing of number datatype in table

2002-11-22 Thread Morten Egan
Try this before your select:

set numwidth 38

Then is should work. The reason is that sqlplus has a default length 
value for showing number fields. Before setting it to something else, 
try and type:

show numwidth

that should tell you the default.

Thanks,
KidRac

[EMAIL PROTECTED] wrote:

Dear List

Have a look at the sql !!!

SQL create table trnid
 2  ( trn_id number(10));
Table created.

SQL insert into trnid(trn_id) values('11');/* 10 1's inserted*/
1 row created.

SQL insert into trnid(trn_id) values('1');/* 9 1's inserted*/
1 row created.

SQL commit;
Commit complete.

SQL select trn_id from trnid;

  TRN_ID
-
1.111E+09
1

can anyone tell why the number(10) is stored in exp format

Regards,

Sathyanarayanan


 



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partitioning questions

2002-11-22 Thread becker . bill

Hello,

We are planning to move to Oracle 9.2 on as-yet-undecided platform
(probably red hat linux on ibm hardware).

We finally pursuaded management to purchase the partitioning
license, and I have some questions on partitioning:

Scenario:
Range-Partition tableA on a service_date field by year;
Range-Partition tableB on a posted_date field by year;
These tables are frequently joined using a separate field
called charge_id, a surrogate key.

Queries against these tables usually include some sort of
date filter, join on the charge_id field, and are done in parallel.

1) Would this configuration promote the use of partition-wise
   joins between tableA and tableB by the optimizer?
2) Would it be better to partition the tables (either range or hash)
   by the join field, charge_id?
3) If we range-partition by date, subpartition by hash (charge_id),
   would queries that do not reference the date field, but do join
   the tables by charge_id still benefit?
4) Is it more expensive, less expensive, or about equal to do a
   full table scan on a partitioned table vs the same table non-partitioned? 

As always, thanks to any responders.
[EMAIL PROTECTED]

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Re: Storing of number datatype in table

2002-11-22 Thread Arup Nanda
The number is more than the numwidth specified. Try this

SQL set numwidth 13
SQL select trn_id from trnid;

Your numwidth is perhpas defined as 9; so anything of more precision is
displayed as exponetial notation; internally all numbers are stored the
same.

HTH

Arup Nanda
www.proligence.com

- Original Message -
To: Multiple recipients of list ORACLE-L [EMAIL PROTECTED]
Sent: Friday, November 22, 2002 6:23 AM


 Dear List

 Have a look at the sql !!!

 SQL create table trnid
   2  ( trn_id number(10));
 Table created.

 SQL insert into trnid(trn_id) values('11');/* 10 1's inserted*/
 1 row created.

 SQL insert into trnid(trn_id) values('1');/* 9 1's inserted*/
 1 row created.

 SQL commit;
 Commit complete.

 SQL select trn_id from trnid;

TRN_ID
 -
 1.111E+09
 1

 can anyone tell why the number(10) is stored in exp format

 Regards,

 Sathyanarayanan


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Ltrim?

2002-11-22 Thread Roland . Skoldblom
Hallo,
Anyone whom could help me how to write in cron when
scheduling the start of a unixprogram.

I would like that the unix script will run every monday on 6 am.

I have tried but it fails. Any suggestions, please help

Roland



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Re: partitioning questions

2002-11-22 Thread Stephane Faroult
[EMAIL PROTECTED] wrote:
 
 Hello,
 
 We are planning to move to Oracle 9.2 on as-yet-undecided platform
 (probably red hat linux on ibm hardware).
 
 We finally pursuaded management to purchase the partitioning
 license, and I have some questions on partitioning:
 
 Scenario:
 Range-Partition tableA on a service_date field by year;
 Range-Partition tableB on a posted_date field by year;
 These tables are frequently joined using a separate field
 called charge_id, a surrogate key.
 
 Queries against these tables usually include some sort of
 date filter, join on the charge_id field, and are done in parallel.
 
 1) Would this configuration promote the use of partition-wise
joins between tableA and tableB by the optimizer?

  I do think so.

 2) Would it be better to partition the tables (either range or hash)
by the join field, charge_id?

  I doubt it, because the main benefit of partitioning is clipping -
trying to limit searches to a few partitions. In other words, you should
partition on a criterion you have input (I mean something which appears
as WHERE PARTITION_KEY = constant or (better) bind variable in your
queries). If charge_id is just use for joins, it means that in a way it
is derived from something else (condition on dates) and therefore using
it as a partition key would be useless.

 3) If we range-partition by date, subpartition by hash (charge_id),
would queries that do not reference the date field, but do join
the tables by charge_id still benefit?

  No for the same reason as above. It would be also interesting to check
whether you should rather have a LOCAL or GLOBAL index on charge_id in
this case. 

 4) Is it more expensive, less expensive, or about equal to do a
full table scan on a partitioned table vs the same table non-partitioned?

   With PQO probably less expensive, but I have not tested it
specifically.

-- 
Regards,

Stephane Faroult
Oriole Software

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RE: Ltrim?

2002-11-22 Thread Jack van Zanen
0 6 * * 1 script_name

-Original Message-
Sent: vrijdag 22 november 2002 15:19
To: Multiple recipients of list ORACLE-L


Hallo,
Anyone whom could help me how to write in cron when
scheduling the start of a unixprogram.

I would like that the unix script will run every monday on 6 am.

I have tried but it fails. Any suggestions, please help

Roland



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find the system process for an oracle session

2002-11-22 Thread Ruth Gramolini
Good morning,

Can anyone send my the sql to find the system process being used by an
oracle session.   I know this has been out here before, but I can't find it
in my saved stuff.

Thanks in advance,
Ruth

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RE: Ltrim?

2002-11-22 Thread Kevin Lange
The cron part is easy  but you have to make sure your Unix script works.

Next time, before you post a question ... please try looking up the answer
for yourself on any of the available sources.   In this case, the man
function of unix tells you exactly what you need to know.You should have
done a man on crontab.

00 06   *   *   5  your_unix_script

 minute (0-59),  00 = 0 minutes
 hour (0-23),  06 = 6 am
 day of the month (1-31),
 month of the year (1-12),
 day of the week (0-6 with 0=Sunday).  5 = Friday
 command name


-Original Message-
Sent: Friday, November 22, 2002 8:19 AM
To: Multiple recipients of list ORACLE-L


Hallo,
Anyone whom could help me how to write in cron when
scheduling the start of a unixprogram.

I would like that the unix script will run every monday on 6 am.

I have tried but it fails. Any suggestions, please help

Roland



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RE: Ltrim?

2002-11-22 Thread david hill
Title: RE: Ltrim?





Should be something like this


0 6 * * 1 ksh myscript.ksh 


-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]] 
Sent: Friday, November 22, 2002 9:19 AM
To: Multiple recipients of list ORACLE-L
Subject: Ltrim?


Hallo,
Anyone whom could help me how to write in cron when
scheduling the start of a unixprogram.


I would like that the unix script will run every monday on 6 am.


I have tried but it fails. Any suggestions, please help


Roland




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 INET: [EMAIL PROTECTED]


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Re: find the system process for an oracle session

2002-11-22 Thread Arup Nanda
Ruth,

If you mean the operating system process id, it's in v$session field
PROCESS.

the following will tel you the oracle server process

select spid
from v$process p, v$session s
where s.sid = your sid from v$session
and p.addr = s.paddr

HTH

Arup Nanda
- Original Message -
To: Multiple recipients of list ORACLE-L [EMAIL PROTECTED]
Sent: Friday, November 22, 2002 9:53 AM


 Good morning,

 Can anyone send my the sql to find the system process being used by an
 oracle session.   I know this has been out here before, but I can't find
it
 in my saved stuff.

 Thanks in advance,
 Ruth

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RE: find the system process for an oracle session

2002-11-22 Thread MOORE, Peter Rbh
select p.spid, s.sid, s.username, s.program
from v$session s, v$process p
where p.addr = s.paddr

p.spid shows you the o/s process ID for the session.

--
Peter Moore
Systems DBA,
Mid-Range Centre of Expertise,
Global Service Delivery,
SchlumbergerSema,
Reading

Phone: 0118 963 6827
Email: [EMAIL PROTECTED]


 -Original Message-
 From: Ruth Gramolini [mailto:[EMAIL PROTECTED]]
 Sent: 22 November 2002 14:54
 To: Multiple recipients of list ORACLE-L
 Subject: find the system process for an oracle session
 
 
 Good morning,
 
 Can anyone send my the sql to find the system process being used by an
 oracle session.   I know this has been out here before, but I 
 can't find it
 in my saved stuff.
 
 Thanks in advance,
 Ruth
 
 -- 
 Please see the official ORACLE-L FAQ: http://www.orafaq.com
 -- 
 Author: Ruth Gramolini
   INET: [EMAIL PROTECTED]
 
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Re: find the system process for an oracle session

2002-11-22 Thread Ruth Gramolini
Thanks!  I had a senior moment there.  Guess I'll get some coffee to wash
down my Ginko Biloba.

Ruth
- Original Message -
To: [EMAIL PROTECTED]; [EMAIL PROTECTED]
Sent: Friday, November 22, 2002 10:28 AM


 select p.spid, s.sid, s.username, s.program
 from v$session s, v$process p
 where p.addr = s.paddr

 p.spid shows you the o/s process ID for the session.

 --
 Peter Moore
 Systems DBA,
 Mid-Range Centre of Expertise,
 Global Service Delivery,
 SchlumbergerSema,
 Reading

 Phone: 0118 963 6827
 Email: [EMAIL PROTECTED]


  -Original Message-
  From: Ruth Gramolini [mailto:[EMAIL PROTECTED]]
  Sent: 22 November 2002 14:54
  To: Multiple recipients of list ORACLE-L
  Subject: find the system process for an oracle session
 
 
  Good morning,
 
  Can anyone send my the sql to find the system process being used by an
  oracle session.   I know this has been out here before, but I
  can't find it
  in my saved stuff.
 
  Thanks in advance,
  Ruth
 
  --
  Please see the official ORACLE-L FAQ: http://www.orafaq.com
  --
  Author: Ruth Gramolini
INET: [EMAIL PROTECTED]
 
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  San Diego, California-- Mailing list and web hosting services
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  also send the HELP command for other information (like subscribing).
 


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 individual to whom it is addressed. Any views or opinions presented are
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 SchlumbergerSema.
 If you are not the intended recipient, be advised that you have received
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RE: find the system process for an oracle session

2002-11-22 Thread Hately, Mike (NESL-IT)
Ruth,

select vp.spid
 from v$process vp, v$session vs
where vp.addr=vs.paddr
  and vs.sid=1

regards,
Mike Hately


-Original Message-
Sent: 22 November 2002 14:54
To: Multiple recipients of list ORACLE-L


Good morning,

Can anyone send my the sql to find the system process being used by an
oracle session.   I know this has been out here before, but I can't find it
in my saved stuff.

Thanks in advance,
Ruth

-- 
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-- 
Author: Ruth Gramolini
  INET: [EMAIL PROTECTED]

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RE: partitioning questions

2002-11-22 Thread Gogala, Mladen
That was not a good buy. Partitioning comes with Oracle 9, partitioning
option is no longer sold separately.

 -Original Message-
 From: [EMAIL PROTECTED]
 [mailto:[EMAIL PROTECTED]]
 Sent: Friday, November 22, 2002 8:44 AM
 To: Multiple recipients of list ORACLE-L
 Subject: partitioning questions
 
 
 
 Hello,
 
 We are planning to move to Oracle 9.2 on as-yet-undecided platform
 (probably red hat linux on ibm hardware).
 
 We finally pursuaded management to purchase the partitioning
 license, and I have some questions on partitioning:
 
 Scenario:
 Range-Partition tableA on a service_date field by year;
 Range-Partition tableB on a posted_date field by year;
 These tables are frequently joined using a separate field
 called charge_id, a surrogate key.
 
 Queries against these tables usually include some sort of
 date filter, join on the charge_id field, and are done in parallel.
 
 1) Would this configuration promote the use of partition-wise
joins between tableA and tableB by the optimizer?
 2) Would it be better to partition the tables (either range or hash)
by the join field, charge_id?
 3) If we range-partition by date, subpartition by hash (charge_id),
would queries that do not reference the date field, but do join
the tables by charge_id still benefit?
 4) Is it more expensive, less expensive, or about equal to do a
full table scan on a partitioned table vs the same table 
 non-partitioned? 
 
 As always, thanks to any responders.
 [EMAIL PROTECTED]
 
 -- 
 Please see the official ORACLE-L FAQ: http://www.orafaq.com
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 also send the HELP command for other information (like subscribing).
 
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RE: find the system process for an oracle session

2002-11-22 Thread MOORE, Peter Rbh
Ginko Biloba?
Isn't he a Brazilian footballer?

Pete


 -Original Message-
 From: Ruth Gramolini [mailto:[EMAIL PROTECTED]]
 Sent: 22 November 2002 15:51
 To: MOORE, Peter Rbh; [EMAIL PROTECTED]
 Subject: Re: find the system process for an oracle session
 
 
 Thanks!  I had a senior moment there.  Guess I'll get some 
 coffee to wash
 down my Ginko Biloba.
 
 Ruth
 - Original Message -
 From: MOORE, Peter Rbh [EMAIL PROTECTED]
 To: [EMAIL PROTECTED]; [EMAIL PROTECTED]
 Sent: Friday, November 22, 2002 10:28 AM
 Subject: RE: find the system process for an oracle session
 
 
  select p.spid, s.sid, s.username, s.program
  from v$session s, v$process p
  where p.addr = s.paddr
 
  p.spid shows you the o/s process ID for the session.
 
  --
  Peter Moore
  Systems DBA,
  Mid-Range Centre of Expertise,
  Global Service Delivery,
  SchlumbergerSema,
  Reading
 
  Phone: 0118 963 6827
  Email: [EMAIL PROTECTED]
 
 
   -Original Message-
   From: Ruth Gramolini [mailto:[EMAIL PROTECTED]]
   Sent: 22 November 2002 14:54
   To: Multiple recipients of list ORACLE-L
   Subject: find the system process for an oracle session
  
  
   Good morning,
  
   Can anyone send my the sql to find the system process 
 being used by an
   oracle session.   I know this has been out here before, but I
   can't find it
   in my saved stuff.
  
   Thanks in advance,
   Ruth
  
   --
   Please see the official ORACLE-L FAQ: http://www.orafaq.com
   --
   Author: Ruth Gramolini
 INET: [EMAIL PROTECTED]
  
   Fat City Network Services-- 858-538-5051 
 http://www.fatcity.com
   San Diego, California-- Mailing list and web 
 hosting services
   
 -
   To REMOVE yourself from this mailing list, send an E-Mail message
   to: [EMAIL PROTECTED] (note EXACT spelling of 
 'ListGuru') and in
   the message BODY, include a line containing: UNSUB ORACLE-L
   (or the name of mailing list you want to be removed 
 from).  You may
   also send the HELP command for other information (like 
 subscribing).
  
 
 
  _
  This email is confidential and intended solely for the use of the
  individual to whom it is addressed. Any views or opinions 
 presented are
  solely those of the author and do not necessarily represent those of
  SchlumbergerSema.
  If you are not the intended recipient, be advised that you 
 have received
  this email in error and that any use, dissemination, 
 forwarding, printing,
  or copying of this email is strictly prohibited.
 
  If you have received this email in error please notify the
  SchlumbergerSema Helpdesk by telephone on +44 (0) 121 627 5600.
  _
 
 
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RE: find the system process for an oracle session

2002-11-22 Thread Gogala, Mladen
 select s.username,s.sid,s.osuser,p.spid
 from v$session s,v$process p
 where p.addr=s.paddr
 and s.sid=sid

 -Original Message-
 From: Ruth Gramolini [mailto:[EMAIL PROTECTED]]
 Sent: Friday, November 22, 2002 9:54 AM
 To: Multiple recipients of list ORACLE-L
 Subject: find the system process for an oracle session
 
 
 Good morning,
 
 Can anyone send my the sql to find the system process being used by an
 oracle session.   I know this has been out here before, but I 
 can't find it
 in my saved stuff.
 
 Thanks in advance,
 Ruth
 
 -- 
 Please see the official ORACLE-L FAQ: http://www.orafaq.com
 -- 
 Author: Ruth Gramolini
   INET: [EMAIL PROTECTED]
 
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 also send the HELP command for other information (like subscribing).
 
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Re[2]: Ltrim?

2002-11-22 Thread Robert Eskridge
Roland,

By now you've seen several messages showing you the cron syntax to get
you task to start at the time you want.  There is characteristic of
cron that seems to catch first time users -- the environment settings.
As a shell users you'll be used to having your .profile or .login
(or similar script depending on what shell you use) run and set up
your environment.  And when you run at or batch jobs your current
environment is passed on to those scripts.  Job's that start from your
crontab on the other hand, have a stripped down environment.

Try running a crontab command that just does a set and compare the
email output to the environment that you have when you are at a shell
prompt and the differences will be obvious.  You'll probably see major
differences in $PATH and $ORACLE_HOME, either of which could keep your
script from executing properly.

The solution is to set your own environment every time a crontab task
starts.  I keep a stripped down version of my .profile that I name
.cron_profile that has the environment I need to run sqlplus scripts.
Then my crontab entries look like:

0 6 * * 1 . $HOME/.cron_profile; script_name

-rje



J 0 6 * * 1 script_name

R Hallo,
R Anyone whom could help me how to write in cron when
R scheduling the start of a unixprogram.

R I would like that the unix script will run every monday on 6 am.

R I have tried but it fails. Any suggestions, please help

R Roland

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Re: find the system process for an oracle session

2002-11-22 Thread Stephane Faroult
Ruth Gramolini wrote:
 
 Good morning,
 
 Can anyone send my the sql to find the system process being used by an
 oracle session.   I know this has been out here before, but I can't find it
 in my saved stuff.
 
 Thanks in advance,
 Ruth
 

Ruth,

  It depends on whether you want the client process (eg the sqlplus
process) or the shadow process identifier.

You find the first one as column PROCESS in V$SESSION, and identify the
row either by the SID (session identifier) or by saying AUDSID =
SYS_CONTEXT('USERENV', 'SESSIONID') to identify the currently running
session.
The second one is column SPID in V$PROCESS, and you can join V$SESSION
to V$PROCESS by saying V$SESSION.PADDR = V$PROCESS.ADDR.

-- 
HTH,

Stephane Faroult
Oriole Software
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RE: find the system process for an oracle session

2002-11-22 Thread Reddy, Madhusudana
There is a column 'PADDR' in v$session , join this with the column 'ADDR' of
v$process and look for column value 'SPID' from v$process.

Now write a query.

:)-


-Original Message-
Sent: Friday, November 22, 2002 8:54 AM
To: Multiple recipients of list ORACLE-L


Good morning,

Can anyone send my the sql to find the system process being used by an
oracle session.   I know this has been out here before, but I can't find it
in my saved stuff.

Thanks in advance,
Ruth

-- 
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-- 
Author: Ruth Gramolini
  INET: [EMAIL PROTECTED]

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error 472

2002-11-22 Thread April Wells
I have cloned an 8.1.7.0 database from another instance (clone doc from
metalink for Apps) on AIX 4.3.3.  I don't THINK this is connected to the
clone or (directly) to apps.

Since I brought the database back up after the clone successfully, it keeps
crashing with pick a process terminating instance due to error 472 

It comes back when I start it.

The interval between startup and crash appears arbitrary.

What can be accomplished while the database is up is logical stuff... I can
run apps jobs, I can update and select from tables, I can do ddl, I can
manually log switch.

Metalink has BOAT LOADS of docs on this happening, but I haven't found
anything that I am permitted to see that has a resolution.  I have an Itar,
but that is not yet yielding any information.

Has anyone seen similar problems, and (if so) IS there a resolution?

Thanks in advance for any advice
ajw

April Wells
Oracle DBA 
Great spirits have always encountered violent opposition from mediocre minds
-- Albert Einstein




begin 666 InterScan_Disclaimer.txt
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(]P96YI;F@86YY(%T=%C:UE;G0N#0H-@  
end

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Re: find the system process for an oracle session

2002-11-22 Thread Rodd Holman
This probably gives you more than you asked for, but it works.

select substr(s.sid,1,6) SID,
   s.serial#,
   p.spid OSPROCESS,
   substr(p.program,1,25) OSPROG,
   substr(s.osuser,1,20) OSUSER,
   status,substr(s.schemaname,1,20) SCHEMANAME,
   substr(s.machine,1,15) MACHINE,
   s.terminal,
   s.program
from   v$session s,
   v$process p
where  s.paddr = p.addr
order by s.terminal, s.schemaname, s.osuser;

On Friday 22 November 2002 08:53, Ruth Gramolini wrote:
 Good morning,

 Can anyone send my the sql to find the system process being used by an
 oracle session.   I know this has been out here before, but I can't find it
 in my saved stuff.

 Thanks in advance,
 Ruth

-- 
Rodd Holman
Enterprise Data Systems Engineer
LodgeNet Entertainment Corporation
[EMAIL PROTECTED]

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RE: find the system process for an oracle session

2002-11-22 Thread M Rafiq
Ruth,

Try this query...Will give you both PID and SPID. If you want to have it for 
all uesers connected with Database then remove vs.status = 'ACTIVE'.

set linesize 120
select substr(vs.username,1,10)username,
  vs.osuser,
  vs.sid,
  vs.serial#,
  vs.LOGON_TIME,
  substr(vs.machine,1,15)machine,
  vs.process,
  vp.spid,
  vs.last_call_et
from v$session vs, v$process vp
where vs.paddr = vp.addr
and vs.username is not null
and vs.status = 'ACTIVE'
/

Regards
Rafiq






Reply-To: [EMAIL PROTECTED]
To: Multiple recipients of list ORACLE-L [EMAIL PROTECTED]
Date: Fri, 22 Nov 2002 08:24:44 -0800

There is a column 'PADDR' in v$session , join this with the column 'ADDR' of
v$process and look for column value 'SPID' from v$process.

Now write a query.

:)-


-Original Message-
Sent: Friday, November 22, 2002 8:54 AM
To: Multiple recipients of list ORACLE-L


Good morning,

Can anyone send my the sql to find the system process being used by an
oracle session.   I know this has been out here before, but I can't find it
in my saved stuff.

Thanks in advance,
Ruth

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Re: partitioning questions

2002-11-22 Thread Igor Neyman
Mladen,

are you sure, partitioning is included with oracle 9?

Igor Neyman, OCP DBA
[EMAIL PROTECTED]
  


- Original Message - 
To: Multiple recipients of list ORACLE-L [EMAIL PROTECTED]
Sent: Friday, November 22, 2002 11:08 AM


 That was not a good buy. Partitioning comes with Oracle 9, partitioning
 option is no longer sold separately.
 
  -Original Message-
  From: [EMAIL PROTECTED]
  [mailto:[EMAIL PROTECTED]]
  Sent: Friday, November 22, 2002 8:44 AM
  To: Multiple recipients of list ORACLE-L
  Subject: partitioning questions
  
  
  
  Hello,
  
  We are planning to move to Oracle 9.2 on as-yet-undecided platform
  (probably red hat linux on ibm hardware).
  
  We finally pursuaded management to purchase the partitioning
  license, and I have some questions on partitioning:
  
  Scenario:
  Range-Partition tableA on a service_date field by year;
  Range-Partition tableB on a posted_date field by year;
  These tables are frequently joined using a separate field
  called charge_id, a surrogate key.
  
  Queries against these tables usually include some sort of
  date filter, join on the charge_id field, and are done in parallel.
  
  1) Would this configuration promote the use of partition-wise
 joins between tableA and tableB by the optimizer?
  2) Would it be better to partition the tables (either range or hash)
 by the join field, charge_id?
  3) If we range-partition by date, subpartition by hash (charge_id),
 would queries that do not reference the date field, but do join
 the tables by charge_id still benefit?
  4) Is it more expensive, less expensive, or about equal to do a
 full table scan on a partitioned table vs the same table 
  non-partitioned? 
  
  As always, thanks to any responders.
  [EMAIL PROTECTED]
  
  -- 
  Please see the official ORACLE-L FAQ: http://www.orafaq.com
  -- 
  Author: 
INET: [EMAIL PROTECTED]
  
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Oracle is a time machine!!

2002-11-22 Thread Freeman, Robert
Don't believe me?? Try this:

create table test(the_date date);

insert into test values (to_date('10-05-1582','mm-dd-') );

select to_char(the_date, 'mm/dd/') from test;  

What do you get? :-))

Robert G. Freeman - Oracle OCP
Oracle Database Architect
CSX Midtier Database Administration
Author of several Oracle books you can find on Amazon.com!

Londo Mollari: Ah, arrogance and stupidity all in the same package. How
efficient of you. 

 
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Re: Help me read my 10053 trace file

2002-11-22 Thread K Gopalakrishnan

Shao:


I think your program has become a victim of the new costing model
for bitmap indexes which was introduced in 8.0.6. Basically the
new costing model assumes the 80% of the rows are costed in the
old model and 20% of the rows are costed as they are spread across
ALL blocks.

Let us assume you have a table with 100 blocks and each block
contains 10 rows. In total you have 1000 rows and if your result
set finds 100 blocks, the cost is calculated as 100/10=10  blocks.
So while costing the bit map access cost, it just adds the cost
for 10 blocks with the bitmap index access cost.

In the new costing model, it assumes the 80% of the blocks are
accessed in the older model and the rest of the 20% blocks are
spread across the __ENTIRE__ table (with the absence of the
partition knowledge) and costs the table access costs accordingly.

You can use the event 10170 to tell the CBO to use the old
costing model which works best for partition tables.

(In the above said example the new costing mode will say
the table access cost as 28 blocks instead 10 blocks)


Please correct me (Esp:Jonathan Lewis) if I am wrong !!!



Best Regards,
K Gopalakrishnan
Bangalore, INDIA





-Original Message-
Chunning
Sent: Thursday, November 21, 2002 8:59 AM
To: Multiple recipients of list ORACLE-L


I have a query in which the predictate is like this:
 WHERE ln.metro_id = i_metro_id AND
l.metro_id = :b1 ANd
eld.metro_id(+) = :b1 AND
ln.status_desc = 'ACTIVE' AND
ln.daset_id = ld.daset_id (+) AND
ln.sect_id = ld.sect_id (+) AND
ln.life_id = ld.life_id (+) AND
ln.version_id = ld.version_id (+) AND
ln.daset_id = l.daset_id AND
ln.sect_id = l.sect_id AND
ln.life_id = l.life_id AND
ln.version_id = l.version_id AND
l.status_desc = 'ACTIVE' AND
l.ramp = 'Y' AND
l.daset_id = eld.daset_id (+) AND
l.sect_id = eld.sect_id (+) AND
l.life_id = eld.life_id (+) AND
l.version_id = eld.version_id (+) AND
eld.life_id IS NULL

If the table life is analyzed, the bitmap index is not used, and the
optimizer choose a full table scan, and it take hours to run.
But if the table life is not analyzed, bitmap index is used, and the query
is takes only 1 minutes.

Here is some related info from event 10053

With table life ANALYZED
***
Table statsTable: LIFE   Alias:  L
  (Using composite stats)
  TOTAL ::  CDN: 5485935  NBLKS:  7839  TABLE_SCAN_CST: 1190  AVG_ROW_LEN:
182
-- Index stats
  INDEX#: 3906609  COL#: 6 16
USING COMPOSITE STATS
TOTAL ::  LVLS: 1   #LB: 268  #DK: 2  LB/K: 10  DB/K: 11  CLUF: 293
  INDEX#: 3905350  COL#: 1 2 3 4 5
USING COMPOSITE STATS
TOTAL ::  LVLS: 2   #LB: 23411  #DK: 5485935  LB/K: 1  DB/K: 1  CLUF:
950571
  INDEX#: 3905296  COL#:
USING COMPOSITE STATS
TOTAL ::  LVLS: 1   #LB: 25  #DK: 100  LB/K: 1  DB/K: 1  CLUF: 800
  INDEX#: 3905332  COL#:
USING COMPOSITE STATS
TOTAL ::  LVLS: 1   #LB: 25  #DK: 100  LB/K: 1  DB/K: 1  CLUF: 800
***
***
SINGLE TABLE ACCESS PATH
Column:   METRO_ID  Col#: 5  Table: LIFE   Alias:  L
NDV: 15NULLS: 0 DENS: 6.6667e-02 LO:  1  HI: 48
Column: STATUS_DES  Col#: 16 Table: LIFE   Alias:  L
NDV: 1 NULLS: 0 DENS: 1.e+00
Column:   RAMP  Col#: 6  Table: LIFE   Alias:  L
NDV: 2 NULLS: 0 DENS: 5.e-01
  TABLE: LIFE ORIG CDN: 5485935  CMPTD CDN: 182865
  Access path: tsc  Resc:  1190  Resp:  1190
  Access path: index (equal)
  INDEX#: 3906609  TABLE: LIFE
  CST: 134  IXSEL:  5.e-01  TBSEL:  5.e-01
 Bitmap access path rejected 
Cost: 5223  Selectivity: 0
Not believed to be index-only.
  BEST_CST: 1190.00  PATH: 2  Degree:  1
***

With table LIFE not analyzed

***
Table statsTable: LIFE   Alias:  L
  (Averaging)
  PARTITION [0]CDN: 798014  NBLKS:  9770  TABLE_SCAN_CST: 1483
AVG_ROW_LEN:  100
  PARTITION [1]CDN: 1673215  NBLKS:  20485  TABLE_SCAN_CST: 3110
AVG_ROW_LEN:  100
  PARTITION [2]CDN: 590384  NBLKS:  7228  TABLE_SCAN_CST: 1098
AVG_ROW_LEN:  100
  PARTITION [3]CDN: 494246  NBLKS:  6051  TABLE_SCAN_CST: 919
AVG_ROW_LEN:  100
  PARTITION [4]CDN: 577478  NBLKS:  7070  TABLE_SCAN_CST: 1074
AVG_ROW_LEN:  100
  PARTITION [5]CDN: 1160673  NBLKS:  14210  TABLE_SCAN_CST: 2157
AVG_ROW_LEN:  100
  PARTITION [6]CDN: 1365282  NBLKS:  16715  TABLE_SCAN_CST: 2538
AVG_ROW_LEN:  100
  PARTITION [7]CDN: 654747  NBLKS:  8016  TABLE_SCAN_CST: 1217
AVG_ROW_LEN:  100
  PARTITION [8]CDN: 614969  NBLKS:  7529  TABLE_SCAN_CST: 1143
AVG_ROW_LEN:  100
  PARTITION [9]CDN: 427595  NBLKS:  5235  TABLE_SCAN_CST: 795
AVG_ROW_LEN:  100
  PARTITION [10]   

RE: partitioning questions

2002-11-22 Thread Freeman, Robert
Partitioning is still a separately licensed product.

RF

Robert G. Freeman - Oracle OCP
Oracle Database Architect
CSX Midtier Database Administration
Author of several Oracle books you can find on Amazon.com!

Londo Mollari: Ah, arrogance and stupidity all in the same package. How
efficient of you. 

 



-Original Message-
Sent: Friday, November 22, 2002 12:19 PM
To: Multiple recipients of list ORACLE-L


Mladen,

are you sure, partitioning is included with oracle 9?

Igor Neyman, OCP DBA
[EMAIL PROTECTED]
  


- Original Message - 
To: Multiple recipients of list ORACLE-L [EMAIL PROTECTED]
Sent: Friday, November 22, 2002 11:08 AM


 That was not a good buy. Partitioning comes with Oracle 9, partitioning
 option is no longer sold separately.
 
  -Original Message-
  From: [EMAIL PROTECTED]
  [mailto:[EMAIL PROTECTED]]
  Sent: Friday, November 22, 2002 8:44 AM
  To: Multiple recipients of list ORACLE-L
  Subject: partitioning questions
  
  
  
  Hello,
  
  We are planning to move to Oracle 9.2 on as-yet-undecided platform
  (probably red hat linux on ibm hardware).
  
  We finally pursuaded management to purchase the partitioning
  license, and I have some questions on partitioning:
  
  Scenario:
  Range-Partition tableA on a service_date field by year;
  Range-Partition tableB on a posted_date field by year;
  These tables are frequently joined using a separate field
  called charge_id, a surrogate key.
  
  Queries against these tables usually include some sort of
  date filter, join on the charge_id field, and are done in parallel.
  
  1) Would this configuration promote the use of partition-wise
 joins between tableA and tableB by the optimizer?
  2) Would it be better to partition the tables (either range or hash)
 by the join field, charge_id?
  3) If we range-partition by date, subpartition by hash (charge_id),
 would queries that do not reference the date field, but do join
 the tables by charge_id still benefit?
  4) Is it more expensive, less expensive, or about equal to do a
 full table scan on a partitioned table vs the same table 
  non-partitioned? 
  
  As always, thanks to any responders.
  [EMAIL PROTECTED]
  
  -- 
  Please see the official ORACLE-L FAQ: http://www.orafaq.com
  -- 
  Author: 
INET: [EMAIL PROTECTED]
  
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RE: find the system process for an oracle session

2002-11-22 Thread Gogala, Mladen
Nope. Brazillians do not have football, only soccer.
I've never seen a brazillian team going to the superbowl.
I believe that Denver and Packers will be going there this 
year. None of those two teams is from Brazil.

 -Original Message-
 From: MOORE, Peter Rbh [mailto:[EMAIL PROTECTED]]
 Sent: Friday, November 22, 2002 11:04 AM
 To: Multiple recipients of list ORACLE-L
 Subject: RE: find the system process for an oracle session
 
 
 Ginko Biloba?
 Isn't he a Brazilian footballer?
 
 Pete
 
 
  -Original Message-
  From: Ruth Gramolini [mailto:[EMAIL PROTECTED]]
  Sent: 22 November 2002 15:51
  To: MOORE, Peter Rbh; [EMAIL PROTECTED]
  Subject: Re: find the system process for an oracle session
  
  
  Thanks!  I had a senior moment there.  Guess I'll get some 
  coffee to wash
  down my Ginko Biloba.
  
  Ruth
  - Original Message -
  From: MOORE, Peter Rbh [EMAIL PROTECTED]
  To: [EMAIL PROTECTED]; [EMAIL PROTECTED]
  Sent: Friday, November 22, 2002 10:28 AM
  Subject: RE: find the system process for an oracle session
  
  
   select p.spid, s.sid, s.username, s.program
   from v$session s, v$process p
   where p.addr = s.paddr
  
   p.spid shows you the o/s process ID for the session.
  
   --
   Peter Moore
   Systems DBA,
   Mid-Range Centre of Expertise,
   Global Service Delivery,
   SchlumbergerSema,
   Reading
  
   Phone: 0118 963 6827
   Email: [EMAIL PROTECTED]
  
  
-Original Message-
From: Ruth Gramolini [mailto:[EMAIL PROTECTED]]
Sent: 22 November 2002 14:54
To: Multiple recipients of list ORACLE-L
Subject: find the system process for an oracle session
   
   
Good morning,
   
Can anyone send my the sql to find the system process 
  being used by an
oracle session.   I know this has been out here before, but I
can't find it
in my saved stuff.
   
Thanks in advance,
Ruth
   
--
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process question

2002-11-22 Thread Ruth Gramolini
Thanks to all who answered.  I have it now and I killed the dam@  process
that was the problem.

Ruth

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RE: error 472

2002-11-22 Thread Freeman, Robert
Did you look in the PMON trace file? Does anything appear there that might
shed some light on the problem?

RF

Robert G. Freeman - Oracle OCP
Oracle Database Architect
CSX Midtier Database Administration
Author of several Oracle books you can find on Amazon.com!

Londo Mollari: Ah, arrogance and stupidity all in the same package. How
efficient of you. 

 



-Original Message-
Sent: Friday, November 22, 2002 11:59 AM
To: Multiple recipients of list ORACLE-L


I have cloned an 8.1.7.0 database from another instance (clone doc from
metalink for Apps) on AIX 4.3.3.  I don't THINK this is connected to the
clone or (directly) to apps.

Since I brought the database back up after the clone successfully, it keeps
crashing with pick a process terminating instance due to error 472 

It comes back when I start it.

The interval between startup and crash appears arbitrary.

What can be accomplished while the database is up is logical stuff... I can
run apps jobs, I can update and select from tables, I can do ddl, I can
manually log switch.

Metalink has BOAT LOADS of docs on this happening, but I haven't found
anything that I am permitted to see that has a resolution.  I have an Itar,
but that is not yet yielding any information.

Has anyone seen similar problems, and (if so) IS there a resolution?

Thanks in advance for any advice
ajw

April Wells
Oracle DBA 
Great spirits have always encountered violent opposition from mediocre minds
-- Albert Einstein




begin 666 InterScan_Disclaimer.txt
M5AE(EN9F]R;6%T:6]N(-O;G1A:6YE9!I;B!T:ES(-O;6UU;FEC871I
M;VXL(EN8VQU9EN9R!A='1A8VAM96YTRP@:7,@W1R:6-T;'D@8V]N9FED
M96YT:6%L(%N9!F;W(@=AE(EN=5N95D('5S92!O9B!T:4@861DF5S
MV5E(]N;'D[(ET(UA2!A;'-O(-O;G1A:6X@')O')I971AGDL('!R
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MF4L(1IW1R:6)U=EO;BP@9ESV5M:6YA=EO;BP@=7-E+!OB!C;W!Y
M:6YG(]F('1H92!I;F9OFUA=EO;B!B2!A;GEO;F4@;W1H97(@=AA;B!T
M:4@:6YT96YD960@F5C:7!I96YT(ES('-TFEC=QY('!R;VAI8FET960@
M86YD(UA2!B92!I;QE9V%L+B!)9B!Y;W4@:%V92!R96-E:79E9!T:ES
M(-O;6UU;FEC871I;VX@:6X@97)R;W(L('!L96%S92!N;W1I9GD@=AE('-E
M;F1EB!I;6UE9EA=5L2!B2!R97!L2!E+6UA:6PL(1E;5T92!T:ES
M(-O;6UU;FEC871I;VXL(%N9!D97-TF]Y(%L;!C;W!I97,N( T*#0I#
M;W)P;W)A=4@4WES=5MRP@26YC+B!H87,@=%K96X@F5AV]N86)L92!P
MF5C875T:6]NR!T;R!E;G-UF4@=AA=!A;GD@871T86-H;65N=!T;R!T
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M8VEF:6-A;QY(1IV-L86EM(%L;!L:6%B:6QI='D@86YD('=I;P@86-C
M97!T(YO(')EW!O;G-I8FEL:71Y(9OB!A;GD@9%M86=E('-UW1A:6YE
M9!AR!A(')EW5L=!O9B!S;V9T=V%R92!V:7)UV5S(%N9!A9'9IV4@
M6]U('1O(-AG)Y(]U=!Y;W5R(]W;B!V:7)UR!C:5C:W,@8F5F;W)E
(]P96YI;F@86YY(%T=%C:UE;G0N#0H-@  
end

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RE: Oracle is a time machine!!

2002-11-22 Thread Hayes, Scott
It must have converted the date to metric.

-Original Message-
Sent: Friday, November 22, 2002 12:55 PM
To: Multiple recipients of list ORACLE-L


Don't believe me?? Try this:

create table test(the_date date);

insert into test values (to_date('10-05-1582','mm-dd-') );

select to_char(the_date, 'mm/dd/') from test;  

What do you get? :-))

Robert G. Freeman - Oracle OCP
Oracle Database Architect
CSX Midtier Database Administration
Author of several Oracle books you can find on Amazon.com!

Londo Mollari: Ah, arrogance and stupidity all in the same package. How
efficient of you. 

 
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RE: partitioning questions

2002-11-22 Thread Viral Desai

MyViews below...
Regards, Viral
Scenario: 

Range-Partition tableA on a service_date field by year; Range-Partition tableB on a posted_date field by year; 

These tables are frequently joined using a separate field called charge_id, a surrogate key. 

Queries against these tables usually include some sort of date filter, join on the charge_id field, and are done in parallel. 
1) Would this configuration promote the use of partition-wise joins between tableA and tableB by the optimizer? -- NO, they have to be equi-partitioned and you have to specify atleast the leading keys in the join for both tables.

2) Would it be better to partition the tables (either range or hash) by the join field, charge_id? 
-- SEEMS like a good choice since you always limit your query on charge_id, however data distribution in that column also plays a role.
  3) If we range-partition by date, subpartition by hash (charge_id), would queries that do not reference the date field, but do jointhe tables by charge_id still benefit? 
- Dont think that would help. However, you could have a global index on charge_id on both tables. If you insist topartition the data as mentioned in #3, then for the benefit of your queries you may want the exclusive globalindex on charge_id. (As there are pros, there are cons for this too)
Again depending on the type of the data contents/value of the columns, you could have 2 bitmap indexes (one on the date and another on charge_id, but this is not always advisable)



4) Is it more expensive, less expensive, or about equal to do a full table scan on a partitioned table vs the same table non-partitioned? -- I think it is same as non-partioned tables.


From: "Gogala, Mladen" <[EMAIL PROTECTED]>
Reply-To: [EMAIL PROTECTED] 
To: Multiple recipients of list ORACLE-L <[EMAIL PROTECTED]>
Subject: RE: partitioning questions 
Date: Fri, 22 Nov 2002 08:08:55 -0800 
 
That was not a good buy. Partitioning comes with Oracle 9, partitioning 
option is no longer sold separately. 
 
  -Original Message- 
  From: [EMAIL PROTECTED] 
  [mailto:[EMAIL PROTECTED]] 
  Sent: Friday, November 22, 2002 8:44 AM 
  To: Multiple recipients of list ORACLE-L 
  Subject: partitioning questions 
  
  
  
  Hello, 
  
  We are planning to move to Oracle 9.2 on as-yet-undecided platform 
  (probably red hat linux on ibm hardware). 
  
  We finally pursuaded management to purchase the partitioning 
  license, and I have some questions on partitioning: 
  
  Scenario: 
  Range-Partition tableA on a service_date field by year; 
  Range-Partition tableB on a posted_date field by year; 
  These tables are frequently joined using a separate field 
  called charge_id, a surrogate key. 
  
  Queries against these tables usually include some sort of 
  date filter, join on the charge_id field, and are done in parallel. 
  
  1) Would this configuration promote the use of partition-wise 
  joins between tableA and tableB by the optimizer? 
  2) Would it be better to partition the tables (either range or hash) 
  by the join field, charge_id? 
  3) If we range-partition by date, subpartition by hash (charge_id), 
  would queries that do not reference the date field, but do join 
  the tables by charge_id still benefit? 
  4) Is it more expensive, less expensive, or about equal to do a 
  full table scan on a partitioned table vs the same table 
  non-partitioned? 
  
  As always, thanks to any responders. 
  [EMAIL PROTECTED] 
  
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 INET: [EMAIL PROTECTED] 
 
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Identifying indexes

2002-11-22 Thread cemail2
I am trying to find out what indexes are in the database only for performance
reasons and do not enforce a constraint.  What would be the query to do that?
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Re: Oracle is a time machine!!

2002-11-22 Thread Viral Desai

I think this is because during this time Pope Gregory removed 10 days from the calendar to align with solar calendar...
check this out...
http://webexhibits.org/calendars/timeline.html


From: "Freeman, Robert" <[EMAIL PROTECTED]>
Reply-To: [EMAIL PROTECTED] 
To: Multiple recipients of list ORACLE-L <[EMAIL PROTECTED]>
Subject: Oracle is a time machine!! 
Date: Fri, 22 Nov 2002 09:55:21 -0800 
 
Don't believe me?? Try this: 
 
create table test(the_date date); 
 
insert into test values (to_date('10-05-1582','mm-dd-') ); 
 
select to_char(the_date, 'mm/dd/') from test; 
 
What do you get? :-)) 
 
Robert G. Freeman - Oracle OCP 
Oracle Database Architect 
CSX Midtier Database Administration 
Author of several Oracle books you can find on Amazon.com! 
 
Londo Mollari: Ah, arrogance and stupidity all in the same package. How 
efficient of you. 
 
 
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 INET: [EMAIL PROTECTED] 
 
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RE: Oracle is a time machine!!

2002-11-22 Thread Fink, Dan
Very simple explanation. That day does not exist.

Prior to 1582, every year divisible by 4 was a leap year. Since a year
contains only 365.242199 days (slightly less than 365.25 days), an error of
ten days accumulated over the centuries. To compensate for this error, Pope
Gregory XIII (after whom the Gregorian Calendar is named) decreed that the
ten days between October 5, 1582 and October 14, 1582 would be eliminated
from the calendar. This made October 1582 the shortest month, with only 21
days. After 1582, years divisible by 100 are not leap years unless they are
also divisible by 400. Thus, 1900 is not a leap year, but 2000 is from
http://www.wiskit.com/calendar.html




-Original Message-
Sent: Friday, November 22, 2002 10:55 AM
To: Multiple recipients of list ORACLE-L


Don't believe me?? Try this:

create table test(the_date date);

insert into test values (to_date('10-05-1582','mm-dd-') );

select to_char(the_date, 'mm/dd/') from test;  

What do you get? :-))

Robert G. Freeman - Oracle OCP
Oracle Database Architect
CSX Midtier Database Administration
Author of several Oracle books you can find on Amazon.com!

Londo Mollari: Ah, arrogance and stupidity all in the same package. How
efficient of you. 

 
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RE: Oracle is a time machine!!

2002-11-22 Thread Stahlke, Mark
Nothing unusual here. Ten days were skipped in October, 1582. It was called
the Gregorian Calendar Reform.

Mark Stahlke
Oracle DuhBA
Denver Newspaper Agency

 -Original Message-
Sent:   Friday, November 22, 2002 10:55 AM
To: Multiple recipients of list ORACLE-L
Subject:Oracle is a time machine!!

Don't believe me?? Try this:

create table test(the_date date);

insert into test values (to_date('10-05-1582','mm-dd-') );

select to_char(the_date, 'mm/dd/') from test;  

What do you get? :-))

Robert G. Freeman - Oracle OCP
Oracle Database Architect
CSX Midtier Database Administration
Author of several Oracle books you can find on Amazon.com!

Londo Mollari: Ah, arrogance and stupidity all in the same package. How
efficient of you. 

 
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Re: Oracle is a time machine!!

2002-11-22 Thread Rachna Vaidya
Does it have any relation to year 1752 adjustment for leap year?

Try following on unix ..

cal 9 1752

   September 1752
 S  M Tu  W Th  F  S
   1  2 14 15 16
17 18 19 20 21 22 23
24 25 26 27 28 29 30
 
-Rachna

- Original Message - 
To: Multiple recipients of list ORACLE-L [EMAIL PROTECTED]
Sent: Friday, November 22, 2002 12:55 PM


 Don't believe me?? Try this:
 
 create table test(the_date date);
 
 insert into test values (to_date('10-05-1582','mm-dd-') );
 
 select to_char(the_date, 'mm/dd/') from test;  
 
 What do you get? :-))
 
 Robert G. Freeman - Oracle OCP
 Oracle Database Architect
 CSX Midtier Database Administration
 Author of several Oracle books you can find on Amazon.com!
 
 Londo Mollari: Ah, arrogance and stupidity all in the same package. How
 efficient of you. 
 
 
 -- 
 Please see the official ORACLE-L FAQ: http://www.orafaq.com
 -- 
 Author: Freeman, Robert
   INET: [EMAIL PROTECTED]
 
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 also send the HELP command for other information (like subscribing).
 
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RE: error 472

2002-11-22 Thread April Wells
There is nothing vaguely resembling anything helpful in either the core dump
or the PMON file.  That is where the boat load of metalink docs say to
start, but there is nothing in there that is in any way indicative of what
is going on.

Driving me nuts!  There is no real commonality in when it crashes.  

April Wells
Oracle DBA 
Great spirits have always encountered violent opposition from mediocre minds
-- Albert Einstein



-Original Message-
Sent: Friday, November 22, 2002 11:59 AM
To: Multiple recipients of list ORACLE-L


Did you look in the PMON trace file? Does anything appear there that might
shed some light on the problem?

RF

Robert G. Freeman - Oracle OCP
Oracle Database Architect
CSX Midtier Database Administration
Author of several Oracle books you can find on Amazon.com!

Londo Mollari: Ah, arrogance and stupidity all in the same package. How
efficient of you. 

 



-Original Message-
Sent: Friday, November 22, 2002 11:59 AM
To: Multiple recipients of list ORACLE-L


I have cloned an 8.1.7.0 database from another instance (clone doc from
metalink for Apps) on AIX 4.3.3.  I don't THINK this is connected to the
clone or (directly) to apps.

Since I brought the database back up after the clone successfully, it keeps
crashing with pick a process terminating instance due to error 472 

It comes back when I start it.

The interval between startup and crash appears arbitrary.

What can be accomplished while the database is up is logical stuff... I can
run apps jobs, I can update and select from tables, I can do ddl, I can
manually log switch.

Metalink has BOAT LOADS of docs on this happening, but I haven't found
anything that I am permitted to see that has a resolution.  I have an Itar,
but that is not yet yielding any information.

Has anyone seen similar problems, and (if so) IS there a resolution?

Thanks in advance for any advice
ajw

April Wells
Oracle DBA 
Great spirits have always encountered violent opposition from mediocre minds
-- Albert Einstein





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MF5B2!G:79E;B!T:%T(%N2!D:7-C;]S=7)E+!D:7-TFEB=71I;VXL
M(1IW-E;6EN871I;VXL('5S92P@;W(@8V]P6EN9R!O9B!T:4@:6YF;W)M
M871I;VX@8GD@86YY;VYE(]T:5R('1H86X@=AE(EN=5N95D(')E8VEP
M:65N=!IR!S=')I8W1L2!PF]H:6)I=5D(%N9!M87D@8F4@:6QL96=A
M;X@268@6]U(AA=F4@F5C96EV960@=AIR!C;VUM=6YI8V%T:6]N(EN
M(5RF]R+!P;5AV4@;F]T:69Y('1H92!S96YD97(@:6UM961I871E;'D@
M8GD@F5P;'D@92UM86EL+!D96QE=4@=AIR!C;VUM=6YI8V%T:6]N+!A
M;F0@95S=')O2!A;P@8V]P:65S+B -@T*0V]R]R871E(%-YW1E;7,L
M($EN8RX@:%S('1A:V5N(')E87-O;F%B;4@')E8V%U=EO;G,@=\@96YS
M=7)E('1H870@86YY(%T=%C:UE;G0@=\@=AIR!E+6UA:6P@:%S()E
M96X@W=E'0@9F]R('9IG5S97,N(%=E('-P96-I9FEC86QL2!D:7-C;%I
M;2!A;P@;EA8FEL:71Y(%N9!W:6QL(%C8V5P=!N;R!R97-P;VYS:6)I
M;ET2!F;W(@86YY(1A;6%G92!S=7-T86EN960@87,@82!R97-U;'0@;V8@
MV]F='=AF4@=FER=7-ER!A;F0@861V:7-E('EO=2!T;R!C87)R2!O=70@
M6]UB!O=VX@=FER=7,@8VAE8VMS()E9F]R92!O5N:6YG(%N2!A='1A
-8VAM96YT+@T*#0H-@  
end


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Re: Oracle is a time machine!!

2002-11-22 Thread mkb
strange, I get 

TO_CHAR(TH
--
10/15/1582

and not 10/05/1582

mo

--- Freeman, Robert [EMAIL PROTECTED] wrote:
 Don't believe me?? Try this:
 
 create table test(the_date date);
 
 insert into test values
 (to_date('10-05-1582','mm-dd-') );
 
 select to_char(the_date, 'mm/dd/') from test;  
 
 What do you get? :-))
 
 Robert G. Freeman - Oracle OCP
 Oracle Database Architect
 CSX Midtier Database Administration
 Author of several Oracle books you can find on
 Amazon.com!
 
 Londo Mollari: Ah, arrogance and stupidity all in
 the same package. How
 efficient of you. 
 
  
 -- 
 Please see the official ORACLE-L FAQ:
 http://www.orafaq.com
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 Author: Freeman, Robert
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Re: find the system process for an oracle session

2002-11-22 Thread Stephane Faroult
Gogala, Mladen wrote:
 
 Nope. Brazillians do not have football, only soccer.

 No, futbol.
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Stephane Faroult
Oriole Software
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Re: Oracle is a time machine!!

2002-11-22 Thread Alan Davey
I get the same date for Oct 5 - 15 (10/15/02).

Good thing I don't deal with dates that far back.  ;^)

-- 

Alan Davey
[EMAIL PROTECTED]
212-604-0200  x106


On 11/22/2002 12:55 PM, Freeman, Robert [EMAIL PROTECTED] wrote:
Don't believe me?? Try this:

create table test(the_date date);

insert into test values (to_date('10-05-1582','mm-dd-') );

select to_char(the_date, 'mm/dd/') from test;  

What do you get? :-))

Robert G. Freeman - Oracle OCP
Oracle Database Architect
CSX Midtier Database Administration
Author of several Oracle books you can find on Amazon.com!

Londo Mollari: Ah, arrogance and stupidity all in the same package. 
How
efficient of you. 

 
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Re: Identifying indexes

2002-11-22 Thread Arup Nanda
The only indexes that enforce a constaint are primary key and unique key
indexes. You can easily spot them using

SELECT INDEX_NAME, OWNER
FROM DBA_INDEXES
WHERE UNIQUENESS = 'NONUNIQUE'

However, beware, there may be some unique indexes that may have been created
for performance reasons only, even though a secondary intent may be to
enforce a unique constraint. For instance Social Security Numbers are
probably unique, guranteed pretty much by the application but an index
defined on them will be defined as unique as unique indexes perform better.
Therefore the intent here was not to enforce the constraint but rather to
design a better index.

HTH

Arup Nanda
www.proligence.com
- Original Message -
To: Multiple recipients of list ORACLE-L [EMAIL PROTECTED]
Sent: Friday, November 22, 2002 1:39 PM


 I am trying to find out what indexes are in the database only for
performance
 reasons and do not enforce a constraint.  What would be the query to do
that?
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RE: Oracle is a time machine!!

2002-11-22 Thread Toepke, Kevin M
TO_CHAR(TH
--
10/15/1582

-Original Message-
Sent: Friday, November 22, 2002 12:55 PM
To: Multiple recipients of list ORACLE-L


Don't believe me?? Try this:

create table test(the_date date);

insert into test values (to_date('10-05-1582','mm-dd-') );

select to_char(the_date, 'mm/dd/') from test;  

What do you get? :-))

Robert G. Freeman - Oracle OCP
Oracle Database Architect
CSX Midtier Database Administration
Author of several Oracle books you can find on Amazon.com!

Londo Mollari: Ah, arrogance and stupidity all in the same package. How
efficient of you. 

 
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RE: Oracle is a time machine!!

2002-11-22 Thread Gogala, Mladen
Gregorian calendar input before 15th October 1582 or after 30th January 4247
is not valid.  There was wide variation in the date of adoption of the
Gregorian calendar.  For example, 
in Great Britain and colonies, the Julian date Wednesday 2nd September 1752
Old Style was followed the next day by the Gregorian date Thursday 14th
September 1752.
Oracle is taking the calendar change (Julian-Gregorian) into account.


 -Original Message-
 From: Hayes, Scott [mailto:[EMAIL PROTECTED]]
 Sent: Friday, November 22, 2002 1:19 PM
 To: Multiple recipients of list ORACLE-L
 Subject: RE: Oracle is a time machine!!
 
 
 It must have converted the date to metric.
 
 -Original Message-
 Sent: Friday, November 22, 2002 12:55 PM
 To: Multiple recipients of list ORACLE-L
 
 
 Don't believe me?? Try this:
 
 create table test(the_date date);
 
 insert into test values (to_date('10-05-1582','mm-dd-') );
 
 select to_char(the_date, 'mm/dd/') from test;  
 
 What do you get? :-))
 
 Robert G. Freeman - Oracle OCP
 Oracle Database Architect
 CSX Midtier Database Administration
 Author of several Oracle books you can find on Amazon.com!
 
 Londo Mollari: Ah, arrogance and stupidity all in the same 
 package. How
 efficient of you. 
 
  
 -- 
 Please see the official ORACLE-L FAQ: http://www.orafaq.com
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RE: Oracle is a time machine!!

2002-11-22 Thread Magaliff, Bill
Seems like the machine is frozen in time . . .
try the next day, too!

insert into test values (to_date('10-06-1582','mm-dd-') )



-Original Message-
Sent: Friday, November 22, 2002 12:55 PM
To: Multiple recipients of list ORACLE-L


Don't believe me?? Try this:

create table test(the_date date);

insert into test values (to_date('10-05-1582','mm-dd-') );

select to_char(the_date, 'mm/dd/') from test;  

What do you get? :-))

Robert G. Freeman - Oracle OCP
Oracle Database Architect
CSX Midtier Database Administration
Author of several Oracle books you can find on Amazon.com!

Londo Mollari: Ah, arrogance and stupidity all in the same package. How
efficient of you. 

 
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Re: Oracle is a time machine!!

2002-11-22 Thread Arup Nanda
May be it was called Gregorian Saving Time. Imagine ripping off ten days off
your desk calendar; And while you are at it, please check the smoke alarm
battery, check your basement for leakage...

Thank God they decided not to do it a every year affair.

Then again, imagine this, when you get to bed tonight, turn your calendar
and watch and sleep more - an hour longer, oh no, 10 days longer ... Holy
cow! I am all for it.
- Original Message -
To: Multiple recipients of list ORACLE-L [EMAIL PROTECTED]
Sent: Friday, November 22, 2002 1:53 PM


 Nothing unusual here. Ten days were skipped in October, 1582. It was
called
 the Gregorian Calendar Reform.

 Mark Stahlke
 Oracle DuhBA
 Denver Newspaper Agency

  -Original Message-
 Sent: Friday, November 22, 2002 10:55 AM
 To: Multiple recipients of list ORACLE-L
 Subject: Oracle is a time machine!!

 Don't believe me?? Try this:

 create table test(the_date date);

 insert into test values (to_date('10-05-1582','mm-dd-') );

 select to_char(the_date, 'mm/dd/') from test;

 What do you get? :-))

 Robert G. Freeman - Oracle OCP
 Oracle Database Architect
 CSX Midtier Database Administration
 Author of several Oracle books you can find on Amazon.com!

 Londo Mollari: Ah, arrogance and stupidity all in the same package. How
 efficient of you.


 --
 Please see the official ORACLE-L FAQ: http://www.orafaq.com
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RE: Identifying indexes

2002-11-22 Thread Kevin Lange
This may not do all you need but it will list out all the indexes in
dba_indexes that do not have a corresponding entry in the dba_constraints
table.  You might have to put a few other criteria on it ... but this might
get you in the right direction.

select 
  a.owner, 
  a.index_name, 
  a.table_owner, 
  a.table_name 
from 
  dba_indexes a
 where 
  not exists (
  select '' 
  from 
dba_constraints b 
  where 
a.owner = b.owner and 
a.index_name = b.constraint_name)

-Original Message-
Sent: Friday, November 22, 2002 12:40 PM
To: Multiple recipients of list ORACLE-L


I am trying to find out what indexes are in the database only for
performance
reasons and do not enforce a constraint.  What would be the query to do
that?
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Re: Oracle is a time machine!!

2002-11-22 Thread Alan Davey
Very tricky Robert.  ;^)

Spoiler Alert below!!!
























After some time to think about this, I did a quick search on Google and realized that 
this is when the calendar changed from Julian to Gregorian.

-- 

Alan Davey
[EMAIL PROTECTED]
212-604-0200  x106


On 11/22/2002 12:55 PM, Freeman, Robert [EMAIL PROTECTED] wrote:
Don't believe me?? Try this:

create table test(the_date date);

insert into test values (to_date('10-05-1582','mm-dd-') );

select to_char(the_date, 'mm/dd/') from test;  

What do you get? :-))

Robert G. Freeman - Oracle OCP
Oracle Database Architect
CSX Midtier Database Administration
Author of several Oracle books you can find on Amazon.com!

Londo Mollari: Ah, arrogance and stupidity all in the same package. 
How
efficient of you. 

 
-- 
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-- 
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RE: Oracle is a time machine!!

2002-11-22 Thread Louis BROUILLETTE
For what I can recall, there was an adjustment in 1582 in the calendar to 
make it fit with the reality.  They introduced the leap years and the cut 
10 days in october 1582.  I think they went from october 4 to october 15.

At 10:19 2002-11-22 -0800, you wrote:
It must have converted the date to metric.

-Original Message-
Sent: Friday, November 22, 2002 12:55 PM
To: Multiple recipients of list ORACLE-L


Don't believe me?? Try this:

create table test(the_date date);

insert into test values (to_date('10-05-1582','mm-dd-') );

select to_char(the_date, 'mm/dd/') from test;

What do you get? :-))

Robert G. Freeman - Oracle OCP
Oracle Database Architect
CSX Midtier Database Administration
Author of several Oracle books you can find on Amazon.com!

Londo Mollari: Ah, arrogance and stupidity all in the same package. How
efficient of you.


--
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Louis Brouillette
Analyste en informatique (DBA)
Universite du Quebec a Trois-Rivieres
Tel: (819) 376-5011 ext. 2435
Email: [EMAIL PROTECTED]

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RE: Oracle is a time machine!!

2002-11-22 Thread Toepke, Kevin M
okay, time to nip this discussion in the bud...

First of all, there are/were 2 calendar systems. The gregorian and the
juilan calendars. They both got out of synch with the seasons (due to no
leap year or something). They were both adjusted forward a number of days to
synch back up the real world.. One of them (the one Oracle uses) just so
happened to jump forward in October 1582. The other one (used by UNIX) on a
different date.

Read about it here...http://serendipity.magnet.ch/hermetic/cal_stud.htm

-Original Message-
Sent: Friday, November 22, 2002 1:19 PM
To: Multiple recipients of list ORACLE-L


It must have converted the date to metric.

-Original Message-
Sent: Friday, November 22, 2002 12:55 PM
To: Multiple recipients of list ORACLE-L


Don't believe me?? Try this:

create table test(the_date date);

insert into test values (to_date('10-05-1582','mm-dd-') );

select to_char(the_date, 'mm/dd/') from test;  

What do you get? :-))

Robert G. Freeman - Oracle OCP
Oracle Database Architect
CSX Midtier Database Administration
Author of several Oracle books you can find on Amazon.com!

Londo Mollari: Ah, arrogance and stupidity all in the same package. How
efficient of you. 

 
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OEM Config Assistant

2002-11-22 Thread Mike Sardina
Using OEM Configuration Assistant 2.2, I tried to set up a Management
Server/repository, etc. and through the gui I created a user with a password,
etc.  Now when I try to log into the Management Server with that
username/password, I get invalid credentials.  Through sqlplus I can log
into that username/password though.  Any ideas on what the problem could be?
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ROLLBACK SEGMENT Tuning

2002-11-22 Thread Seema Singh
Hi
I noticed few of rollback segment in one of Database are having few waits.Is 
it necessary to create rollback segment with new size? Can u please some one 
send some infor on rollback segment tunning?
Thx
-Seema





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Re: Identifying indexes

2002-11-22 Thread Stephane Faroult
Arup Nanda wrote:
 
 The only indexes that enforce a constaint are primary key and unique key
 indexes. You can easily spot them using
 
 SELECT INDEX_NAME, OWNER
 FROM DBA_INDEXES
 WHERE UNIQUENESS = 'NONUNIQUE'
 
 However, beware, there may be some unique indexes that may have been created
 for performance reasons only, even though a secondary intent may be to
 enforce a unique constraint. For instance Social Security Numbers are
 probably unique, guranteed pretty much by the application but an index
 defined on them will be defined as unique as unique indexes perform better.
 Therefore the intent here was not to enforce the constraint but rather to
 design a better index.
 
 HTH
 
 Arup Nanda

There may also be another problem, with indexes created on FKs to avoid
deadlocks - not quite 'performance index' as usually accepted even if
they cannot fully be considered as 'constraint indexes'. If you want to
detect them, you have to check in DBA_IND_COLUMNS and DBA_CONS_COLUMNS -
and I feel too lazy to write the query now.

-- 
Regards,

Stephane Faroult
Oriole Software
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RE: Oracle is a time machine!!

2002-11-22 Thread Freeman, Robert
Actually, I knew that part of it, I was thinking about that last night and
wondered how Oracle would handle
a date in that range (which in my mind is an invalid date).
 
RF
 

Robert G. Freeman - Oracle OCP
Oracle Database Architect
CSX Midtier Database Administration
Author of several Oracle books you can find on Amazon.com!

Londo Mollari: Ah, arrogance and stupidity all in the same package. How
efficient of you. 

 

 

-Original Message-
Sent: Friday, November 22, 2002 1:50 PM
To: Multiple recipients of list ORACLE-L



I think this is because during this time Pope Gregory removed 10 days from
the calendar to align with solar calendar...

check this out...

http://webexhibits.org/calendars/timeline.html
http://webexhibits.org/calendars/timeline.html 



 

From: Freeman, Robert 
Reply-To: [EMAIL PROTECTED] 
To: Multiple recipients of list ORACLE-L 
Subject: Oracle is a time machine!! 
Date: Fri, 22 Nov 2002 09:55:21 -0800 
 
Don't believe me?? Try this: 
 
create table test(the_date date); 
 
insert into test values (to_date('10-05-1582','mm-dd-') ); 
 
select to_char(the_date, 'mm/dd/') from test; 
 
What do you get? :-)) 
 
Robert G. Freeman - Oracle OCP 
Oracle Database Architect 
CSX Midtier Database Administration 
Author of several Oracle books you can find on Amazon.com! 
 
Londo Mollari: Ah, arrogance and stupidity all in the same package. How 
efficient of you. 
 
  
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 INET: [EMAIL PROTECTED] 
 
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RE: Oracle is a time machine!!

2002-11-22 Thread Freeman, Robert
Perhaps this Gregorian thing is just a government cover-up for a giant alien
ship having stopped time for 14 days back then??

I think I've been watching to much X-Files. :-)

RF

Robert G. Freeman - Oracle OCP
Oracle Database Architect
CSX Midtier Database Administration
Author of several Oracle books you can find on Amazon.com!

Londo Mollari: Ah, arrogance and stupidity all in the same package. How
efficient of you. 

 



-Original Message-
Sent: Friday, November 22, 2002 2:34 PM
To: Multiple recipients of list ORACLE-L


okay, time to nip this discussion in the bud...

First of all, there are/were 2 calendar systems. The gregorian and the
juilan calendars. They both got out of synch with the seasons (due to no
leap year or something). They were both adjusted forward a number of days to
synch back up the real world.. One of them (the one Oracle uses) just so
happened to jump forward in October 1582. The other one (used by UNIX) on a
different date.

Read about it here...http://serendipity.magnet.ch/hermetic/cal_stud.htm

-Original Message-
Sent: Friday, November 22, 2002 1:19 PM
To: Multiple recipients of list ORACLE-L


It must have converted the date to metric.

-Original Message-
Sent: Friday, November 22, 2002 12:55 PM
To: Multiple recipients of list ORACLE-L


Don't believe me?? Try this:

create table test(the_date date);

insert into test values (to_date('10-05-1582','mm-dd-') );

select to_char(the_date, 'mm/dd/') from test;  

What do you get? :-))

Robert G. Freeman - Oracle OCP
Oracle Database Architect
CSX Midtier Database Administration
Author of several Oracle books you can find on Amazon.com!

Londo Mollari: Ah, arrogance and stupidity all in the same package. How
efficient of you. 

 
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RE: OEM Config Assistant

2002-11-22 Thread John Weatherman
You need to log in as sysman/oem_temp through the gui.  The userid/passwd
you defined are for the database, not the management server.

John P Weatherman
Database Administrator
Replacements Ltd.



-Original Message-
Sent: Friday, November 22, 2002 2:59 PM
To: Multiple recipients of list ORACLE-L


Using OEM Configuration Assistant 2.2, I tried to set up a Management
Server/repository, etc. and through the gui I created a user with a
password,
etc.  Now when I try to log into the Management Server with that
username/password, I get invalid credentials.  Through sqlplus I can log
into that username/password though.  Any ideas on what the problem could be?
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RE: Oracle is a time machine!!

2002-11-22 Thread Weaver, Walt
I bet Goulet is old enough to remember when this happened.

He's probably still pissed off at missing a paycheck.

--Walt Weaver
  Bozeman, Montana

-Original Message-
Sent: Friday, November 22, 2002 11:19 AM
To: Multiple recipients of list ORACLE-L


I get the same date for Oct 5 - 15 (10/15/02).

Good thing I don't deal with dates that far back.  ;^)

-- 

Alan Davey
[EMAIL PROTECTED]
212-604-0200  x106

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RE: Oracle is a time machine!!

2002-11-22 Thread Fink, Dan
I wanted to see what was actually stored. So I inserted the following dates
in order 10/4/1582, 10/5, 10/15, 10/16. The result is:
TO_CHAR(TH DUMP_DATE
-- 
10-04-1582 Typ=12 Len=7: 115,182,10,4,1,1,1
10-15-1582 Typ=12 Len=7: 115,182,10,15,1,1,1
10-15-1582 Typ=12 Len=7: 115,182,10,15,1,1,1
10-16-1582 Typ=12 Len=7: 115,182,10,16,1,1,1

As you can see, the date is stored as 10/15/1582, so the conversion occurs
on the to_date function for the insert... Interesting...

DF

-Original Message-
Sent: Friday, November 22, 2002 1:10 PM
To: Multiple recipients of list ORACLE-L


Actually, I knew that part of it, I was thinking about that last night and
wondered how Oracle would handle
a date in that range (which in my mind is an invalid date).
 
RF
 

Robert G. Freeman - Oracle OCP
Oracle Database Architect
CSX Midtier Database Administration
Author of several Oracle books you can find on Amazon.com!

Londo Mollari: Ah, arrogance and stupidity all in the same package. How
efficient of you. 

 

 

-Original Message-
Sent: Friday, November 22, 2002 1:50 PM
To: Multiple recipients of list ORACLE-L



I think this is because during this time Pope Gregory removed 10 days from
the calendar to align with solar calendar...

check this out...

http://webexhibits.org/calendars/timeline.html
http://webexhibits.org/calendars/timeline.html 



 

From: Freeman, Robert 
Reply-To: [EMAIL PROTECTED] 
To: Multiple recipients of list ORACLE-L 
Subject: Oracle is a time machine!! 
Date: Fri, 22 Nov 2002 09:55:21 -0800 
 
Don't believe me?? Try this: 
 
create table test(the_date date); 
 
insert into test values (to_date('10-05-1582','mm-dd-') ); 
 
select to_char(the_date, 'mm/dd/') from test; 
 
What do you get? :-)) 
 
Robert G. Freeman - Oracle OCP 
Oracle Database Architect 
CSX Midtier Database Administration 
Author of several Oracle books you can find on Amazon.com! 
 
Londo Mollari: Ah, arrogance and stupidity all in the same package. How 
efficient of you. 
 
  
-- 
Please see the official ORACLE-L FAQ: http://www.orafaq.com 
-- 
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 INET: [EMAIL PROTECTED] 
 
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RE: Identifying indexes

2002-11-22 Thread Shao, Chunning
The following will give you all the indexes that belongs to a constraint

 select distinct t.owner as table_owner, i.table_name, o.owner as index_owner, 
o.object_name as index_name,s.name as constraint_name,c.constraint_type  from 
sys.cdef$ cd,dba_objects o,sys.con$ s,dba_constraints c,dba_indexes i,  dba_tables t 
Where t.Table_Name = i.Table_Name and i.owner=o.owner  and i.index_name=o.object_name 
and c.constraint_name=s.name  and cd.Enabled = o.object_id and cd.con# = s.con#  and 
o.owner not in ('SYS','SYSTEM') 


do a minus will get what you want.


-Original Message-
Sent: Friday, November 22, 2002 1:40 PM
To: Multiple recipients of list ORACLE-L


I am trying to find out what indexes are in the database only for performance
reasons and do not enforce a constraint.  What would be the query to do that?
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RE: Oracle is a time machine!!

2002-11-22 Thread Stahlke, Mark
Yes. This is where it gets interesting. England and the colonies didn't
adopt the Gregorian Calendar Reform until September, 1752.

October, 1582 had its normal 31 days in the British Empire and September,
1752 had its normal 30 days outside the British Empire.

So what does all this mean? Technically, Oracle's date routines are correct
in some parts of the world but not others.

Happy Friday, 
Mark Stahlke
Oracle DuhBA
Denver Newspaper Agency

 -Original Message-
Sent:   Friday, November 22, 2002 11:40 AM
To: Multiple recipients of list ORACLE-L
Subject:Re: Oracle is a time machine!!

Does it have any relation to year 1752 adjustment for leap year?

Try following on unix ..

cal 9 1752

   September 1752
 S  M Tu  W Th  F  S
   1  2 14 15 16
17 18 19 20 21 22 23
24 25 26 27 28 29 30
 
-Rachna

- Original Message - 
To: Multiple recipients of list ORACLE-L [EMAIL PROTECTED]
Sent: Friday, November 22, 2002 12:55 PM


 Don't believe me?? Try this:
 
 create table test(the_date date);
 
 insert into test values (to_date('10-05-1582','mm-dd-') );
 
 select to_char(the_date, 'mm/dd/') from test;  
 
 What do you get? :-))
 
 Robert G. Freeman - Oracle OCP
 Oracle Database Architect
 CSX Midtier Database Administration
 Author of several Oracle books you can find on Amazon.com!
 
 Londo Mollari: Ah, arrogance and stupidity all in the same package. How
 efficient of you. 
 
 
 -- 
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RE: Identifying indexes

2002-11-22 Thread Jacques Kilchoer
Title: RE: Identifying indexes





 -Original Message-
 From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]]
 
 I am trying to find out what indexes are in the database only 
 for performance
 reasons and do not enforce a constraint. What would be the 
 query to do that?


This query will show all indexes that do not enforce a constraint.
select owner, object_name
from dba_objects
where object_type = 'INDEX'
and object_id not in
 (select enabled from sys.cdef$ where type# in (2, 3) and enabled is not null)





RE: Oracle is a time machine!!

2002-11-22 Thread Fink, Dan
I wonder if this will be fixed in 10i (11i in some parts of the world, but
not others)

;)

-Original Message-
Sent: Friday, November 22, 2002 1:49 PM
To: Multiple recipients of list ORACLE-L


Yes. This is where it gets interesting. England and the colonies didn't
adopt the Gregorian Calendar Reform until September, 1752.

October, 1582 had its normal 31 days in the British Empire and September,
1752 had its normal 30 days outside the British Empire.

So what does all this mean? Technically, Oracle's date routines are correct
in some parts of the world but not others.

Happy Friday, 
Mark Stahlke
Oracle DuhBA
Denver Newspaper Agency

 -Original Message-
Sent:   Friday, November 22, 2002 11:40 AM
To: Multiple recipients of list ORACLE-L
Subject:Re: Oracle is a time machine!!

Does it have any relation to year 1752 adjustment for leap year?

Try following on unix ..

cal 9 1752

   September 1752
 S  M Tu  W Th  F  S
   1  2 14 15 16
17 18 19 20 21 22 23
24 25 26 27 28 29 30
 
-Rachna

- Original Message - 
To: Multiple recipients of list ORACLE-L [EMAIL PROTECTED]
Sent: Friday, November 22, 2002 12:55 PM


 Don't believe me?? Try this:
 
 create table test(the_date date);
 
 insert into test values (to_date('10-05-1582','mm-dd-') );
 
 select to_char(the_date, 'mm/dd/') from test;  
 
 What do you get? :-))
 
 Robert G. Freeman - Oracle OCP
 Oracle Database Architect
 CSX Midtier Database Administration
 Author of several Oracle books you can find on Amazon.com!
 
 Londo Mollari: Ah, arrogance and stupidity all in the same package. How
 efficient of you. 
 
 
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 Please see the official ORACLE-L FAQ: http://www.orafaq.com
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RE: Identifying indexes

2002-11-22 Thread Reginald . W . Bailey

I don't get it. Do a minus? Mr. Shao could you explain that please.

RWB




Shao, Chunning [EMAIL PROTECTED]@fatcity.com on 11/22/2002 02:49:15 PM

Please respond to [EMAIL PROTECTED]



Sent by:  [EMAIL PROTECTED]


To:   Multiple recipients of list ORACLE-L [EMAIL PROTECTED]
cc:


The following will give you all the indexes that belongs to a constraint

 select distinct t.owner as table_owner, i.table_name, o.owner as
index_owner, o.object_name as index_name,s.name as
constraint_name,c.constraint_type  from sys.cdef$ cd,dba_objects o,sys.con
$ s,dba_constraints c,dba_indexes i,  dba_tables t Where t.Table_Name =
i.Table_Name and i.owner=o.owner  and i.index_name=o.object_name and
c.constraint_name=s.name  and cd.Enabled = o.object_id and cd.con# = s.con#
and o.owner not in ('SYS','SYSTEM')


do a minus will get what you want.


-Original Message-
Sent: Friday, November 22, 2002 1:40 PM
To: Multiple recipients of list ORACLE-L


I am trying to find out what indexes are in the database only for
performance
reasons and do not enforce a constraint.  What would be the query to do
that?
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RE: OEM Config Assistant

2002-11-22 Thread Steve McClure
I believe the OEM ca sets up the username/password of the owner of the
management server repository.  That is the uname/password used to start the
management server.  The username password you use to login to OEM defaults
to sysman/sysman.  That should get you in, but do remember to change the
password ASAP, as it is a well known security loophole.

Steve McClure

-Original Message-
Sardina
Sent: Friday, November 22, 2002 11:59 AM
To: Multiple recipients of list ORACLE-L


Using OEM Configuration Assistant 2.2, I tried to set up a Management
Server/repository, etc. and through the gui I created a user with a
password,
etc.  Now when I try to log into the Management Server with that
username/password, I get invalid credentials.  Through sqlplus I can log
into that username/password though.  Any ideas on what the problem could be?
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Re: Identifying indexes

2002-11-22 Thread Tim Gorman
A MINUS operator in SQL will find the differences between two queries.  To
find indexes that are not associated with constraints (PK, UK, or FK), you
could you the following:

select table_owner, table_name, column_name, column_position from
dba_ind_columns
minus
select owner, table_name, column_name, position from
dba_cons_columns;

Of course, it wouldn't give you the name of the index, so you can make this
an inline view for a larger query to hit DBA_IND_COLUMNS again would...

- Original Message -
To: Multiple recipients of list ORACLE-L [EMAIL PROTECTED]
Sent: Friday, November 22, 2002 3:03 PM



 I don't get it. Do a minus? Mr. Shao could you explain that please.

 RWB




 Shao, Chunning [EMAIL PROTECTED]@fatcity.com on 11/22/2002 02:49:15 PM

 Please respond to [EMAIL PROTECTED]



 Sent by:  [EMAIL PROTECTED]


 To:   Multiple recipients of list ORACLE-L [EMAIL PROTECTED]
 cc:


 The following will give you all the indexes that belongs to a constraint

  select distinct t.owner as table_owner, i.table_name, o.owner as
 index_owner, o.object_name as index_name,s.name as
 constraint_name,c.constraint_type  from sys.cdef$ cd,dba_objects o,sys.con
 $ s,dba_constraints c,dba_indexes i,  dba_tables t Where t.Table_Name =
 i.Table_Name and i.owner=o.owner  and i.index_name=o.object_name and
 c.constraint_name=s.name  and cd.Enabled = o.object_id and cd.con# =
s.con#
 and o.owner not in ('SYS','SYSTEM')


 do a minus will get what you want.


 -Original Message-
 Sent: Friday, November 22, 2002 1:40 PM
 To: Multiple recipients of list ORACLE-L


 I am trying to find out what indexes are in the database only for
 performance
 reasons and do not enforce a constraint.  What would be the query to do
 that?
 --
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RE: Identifying indexes

2002-11-22 Thread Kevin Lange
1. Since DBA_CONSTRAINTS is already connecting to cons$ and cdef, why are
you using them in your join ?
2. Why are you joining to dba_objects ??  What purpose does it fill ?
3. Why not just join dba_indexes to dba_constraints and rule out the kind of
constraints you are not interested in ... i.e. Check Constraints ?









-Original Message-
[mailto:[EMAIL PROTECTED]]
Sent: Friday, November 22, 2002 4:04 PM
To: Multiple recipients of list ORACLE-L



I don't get it. Do a minus? Mr. Shao could you explain that please.

RWB




Shao, Chunning [EMAIL PROTECTED]@fatcity.com on 11/22/2002 02:49:15 PM

Please respond to [EMAIL PROTECTED]



Sent by:  [EMAIL PROTECTED]


To:   Multiple recipients of list ORACLE-L [EMAIL PROTECTED]
cc:


The following will give you all the indexes that belongs to a constraint

 select distinct t.owner as table_owner, i.table_name, o.owner as
index_owner, o.object_name as index_name,s.name as
constraint_name,c.constraint_type  from sys.cdef$ cd,dba_objects o,sys.con
$ s,dba_constraints c,dba_indexes i,  dba_tables t Where t.Table_Name =
i.Table_Name and i.owner=o.owner  and i.index_name=o.object_name and
c.constraint_name=s.name  and cd.Enabled = o.object_id and cd.con# = s.con#
and o.owner not in ('SYS','SYSTEM')


do a minus will get what you want.


-Original Message-
Sent: Friday, November 22, 2002 1:40 PM
To: Multiple recipients of list ORACLE-L


I am trying to find out what indexes are in the database only for
performance
reasons and do not enforce a constraint.  What would be the query to do
that?
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ora-2083,ora-1256 Urgent

2002-11-22 Thread Rick_Cale
Hi All,

I have a down production system on Win NT4,Oracle 8.1.6.
I just started getting ora-2083 database name has illegal character '-'.
When I try to connect via svrmgrl after setting oracle_sid I get tns-12560
tns protocol adapter error.

The other 2 instances work fine.  Nothing on MetaLink has been helpful
thusfar.

Any ideas on how to resolve.

Thanks
Rick


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RE: OEM Config Assistant

2002-11-22 Thread Steve McClure
The username password you use to login to OEM defaults to sysman/sysman.

I just reread my response, and saw I botched the default password.  The
password is actually oem_temp.

Steve McClure

-Original Message-
Sardina
Sent: Friday, November 22, 2002 11:59 AM
To: Multiple recipients of list ORACLE-L


Using OEM Configuration Assistant 2.2, I tried to set up a Management
Server/repository, etc. and through the gui I created a user with a
password,
etc.  Now when I try to log into the Management Server with that
username/password, I get invalid credentials.  Through sqlplus I can log
into that username/password though.  Any ideas on what the problem could be?
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Re: TEMP segments

2002-11-22 Thread Tim Gorman
Sorry it took so long to reply...

The first direct-path mechanism in Oracle (i.e. Oracle v6.0 FASTLOAD on MVS
platforms, followed by Oracle7 v7.0 SQL*Loader DIRECT=TRUE) did not create a
separate segment.  It merely made use of space in the existing table segment
above the HWM and performed loads there.  If the operation succeeded, then
the HWM was simply moved to include the populated blocks.  If the load
failed, then the HWM would stay where it was -- no need for a rollback!  The
blocks would presumably just get eaten over time as the HWM advanced
naturally...

Starting in v7.1 and continuing today, all new direct-path (now referred
to as APPEND) features create one or more separate TEMPORARY segment(s).
When the load completes successfully, the TEMPORARY segment is merged into
the table or index.  If the operation fails, the TEMPORARY segment is left
in place to be eventually cleaned up by SMON...

- Original Message -
To: Multiple recipients of list ORACLE-L [EMAIL PROTECTED]
Sent: Thursday, November 21, 2002 4:13 AM


 Okay, it's early here, I'm fuzzy.

 I think I meant the same thing (I'd had one of those user calls in
 the middle of the night)

 what I think I meant to say was that any operation that would end up
 adding blocks above the HWM if it COMPLETED would do it by creating
 TEMP segments that are converted to data blocks on commit of the
 operation.

 basically, temp segments are created for any operation that does not
 touch existing blocks

 or am I still fuzzy?


 --- Tim Gorman [EMAIL PROTECTED] wrote:
  No, only the original SQL*Loader DIRECT=TRUE does that (adding blocks
  above
  HWM), which was introduced with v7.0.x...
 
  Since then, all direct-path (a.k.a. append) operations (including
  SQL*Loader
  DIRECT=TRUE PARALLEL=TRUE, parallel CREATE INDEX, parallel CREATE
  TABLE AS
  SELECT, and INSERT /*+ APPEND PARALLEL */, etc) have created
  temporary
  segments for each parallel execution slave process which will be
  merged
  into eventual segment.  As Anjo commented, it makes for really fast
  and easy
  rollback;  just let SMON clean up the temporary segments...
 
  ...don't know if it's ever really been documented;  I did include
  this
  description in our books on data warehousing in 1997 and 1999...
 
  - Original Message -
  To: Multiple recipients of list ORACLE-L [EMAIL PROTECTED]
  Sent: Wednesday, November 20, 2002 4:08 AM
 
 
   Tim -- that adds new blocks above the HWM?
  
   I wonder if any command that adds new blocks (vs inserting rows
  into
   existing ones) automatically creates the new blocks as TEMP
  segments.
   Logically it makes sense but I wonder if it's documented anywhere.
  
  
  
   --- Tim Gorman [EMAIL PROTECTED] wrote:
...as does INSERT /*+ APPEND PARALLEL */...
  - Original Message -
  From: Fink, Dan
  To: Multiple recipients of list ORACLE-L
  Sent: Tuesday, November 19, 2002 1:15 PM
  Subject: TEMP segments
   
   
  I just found a new command that creates TEMP segments. It is
  well
known that index creations first create the index segments as
  TEMP
segments then 'convert' them to index segments upon completion.
  What
I just found out (thanks to a failed operation) is that 'CREATE
  TABLE
AS SELECT' (ctas) also creates the segments as TEMP first.
   
  Dan Fink
   
  
  
   __
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RE: partitioning questions

2002-11-22 Thread MacGregor, Ian A.
As of when?  It's still listed as a costly option on the Oracle Store web page.  
The perpetual license is $10,000.00 per CPU for the U.S. market.

Oracle 9i comes with lots of options  many of which cost extra.

Ian MacGregor
Stanford Linear Accelerator Center
[EMAIL PROTECTED]

-Original Message-
Sent: Friday, November 22, 2002 8:09 AM
To: Multiple recipients of list ORACLE-L


That was not a good buy. Partitioning comes with Oracle 9, partitioning option is no 
longer sold separately.

 -Original Message-
 From: [EMAIL PROTECTED] 
 [mailto:[EMAIL PROTECTED]]
 Sent: Friday, November 22, 2002 8:44 AM
 To: Multiple recipients of list ORACLE-L
 Subject: partitioning questions
 
 
 
 Hello,
 
 We are planning to move to Oracle 9.2 on as-yet-undecided platform 
 (probably red hat linux on ibm hardware).
 
 We finally pursuaded management to purchase the partitioning license, 
 and I have some questions on partitioning:
 
 Scenario:
 Range-Partition tableA on a service_date field by year; 
 Range-Partition tableB on a posted_date field by year; These tables 
 are frequently joined using a separate field called charge_id, a 
 surrogate key.
 
 Queries against these tables usually include some sort of date filter, 
 join on the charge_id field, and are done in parallel.
 
 1) Would this configuration promote the use of partition-wise
joins between tableA and tableB by the optimizer?
 2) Would it be better to partition the tables (either range or hash)
by the join field, charge_id?
 3) If we range-partition by date, subpartition by hash (charge_id),
would queries that do not reference the date field, but do join
the tables by charge_id still benefit?
 4) Is it more expensive, less expensive, or about equal to do a
full table scan on a partitioned table vs the same table
 non-partitioned? 
 
 As always, thanks to any responders. [EMAIL PROTECTED]
 
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tns-12500 unable to start dedicated server process.

2002-11-22 Thread Rick_Cale
I have 3 instances on Oracle 8.1.6,Nt 4.  They are all started but on one
instance I connect via the listener.  The only connection is at
the server not using service name.  I have the usual plenty of
memory,swap,etc.  It has been working fine until today.  I even stopped the
other 2 instances just to give more memory but still fails.  The
listener.ora has not changed. I have rebooted the server multiple times.
Oracle gives me the same old answer increase processes parameter,add more
memory,add more swap file,etc.

Anyone have any fresh ideas on how to resolve.

Thanks
Rick


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Re: TEMP segments

2002-11-22 Thread Rachel Carmichael
thanks! there was no rush on the reply, I know some people on this list
work on occasion (of course I'm not one of them yeah right but...) 
:)

I think I've got it now. And I think I had it straight in my head but
got it confused when it came out my fingertips.


--- Tim Gorman [EMAIL PROTECTED] wrote:
 Sorry it took so long to reply...
 
 The first direct-path mechanism in Oracle (i.e. Oracle v6.0 FASTLOAD
 on MVS
 platforms, followed by Oracle7 v7.0 SQL*Loader DIRECT=TRUE) did not
 create a
 separate segment.  It merely made use of space in the existing table
 segment
 above the HWM and performed loads there.  If the operation succeeded,
 then
 the HWM was simply moved to include the populated blocks.  If the
 load
 failed, then the HWM would stay where it was -- no need for a
 rollback!  The
 blocks would presumably just get eaten over time as the HWM
 advanced
 naturally...
 
 Starting in v7.1 and continuing today, all new direct-path (now
 referred
 to as APPEND) features create one or more separate TEMPORARY
 segment(s).
 When the load completes successfully, the TEMPORARY segment is merged
 into
 the table or index.  If the operation fails, the TEMPORARY segment is
 left
 in place to be eventually cleaned up by SMON...
 
 - Original Message -
 To: Multiple recipients of list ORACLE-L [EMAIL PROTECTED]
 Sent: Thursday, November 21, 2002 4:13 AM
 
 
  Okay, it's early here, I'm fuzzy.
 
  I think I meant the same thing (I'd had one of those user calls
 in
  the middle of the night)
 
  what I think I meant to say was that any operation that would end
 up
  adding blocks above the HWM if it COMPLETED would do it by creating
  TEMP segments that are converted to data blocks on commit of the
  operation.
 
  basically, temp segments are created for any operation that does
 not
  touch existing blocks
 
  or am I still fuzzy?
 
 
  --- Tim Gorman [EMAIL PROTECTED] wrote:
   No, only the original SQL*Loader DIRECT=TRUE does that (adding
 blocks
   above
   HWM), which was introduced with v7.0.x...
  
   Since then, all direct-path (a.k.a. append) operations (including
   SQL*Loader
   DIRECT=TRUE PARALLEL=TRUE, parallel CREATE INDEX, parallel CREATE
   TABLE AS
   SELECT, and INSERT /*+ APPEND PARALLEL */, etc) have created
   temporary
   segments for each parallel execution slave process which will
 be
   merged
   into eventual segment.  As Anjo commented, it makes for really
 fast
   and easy
   rollback;  just let SMON clean up the temporary segments...
  
   ...don't know if it's ever really been documented;  I did include
   this
   description in our books on data warehousing in 1997 and 1999...
  
   - Original Message -
   To: Multiple recipients of list ORACLE-L [EMAIL PROTECTED]
   Sent: Wednesday, November 20, 2002 4:08 AM
  
  
Tim -- that adds new blocks above the HWM?
   
I wonder if any command that adds new blocks (vs inserting rows
   into
existing ones) automatically creates the new blocks as TEMP
   segments.
Logically it makes sense but I wonder if it's documented
 anywhere.
   
   
   
--- Tim Gorman [EMAIL PROTECTED] wrote:
 ...as does INSERT /*+ APPEND PARALLEL */...
   - Original Message -
   From: Fink, Dan
   To: Multiple recipients of list ORACLE-L
   Sent: Tuesday, November 19, 2002 1:15 PM
   Subject: TEMP segments


   I just found a new command that creates TEMP segments. It
 is
   well
 known that index creations first create the index segments as
   TEMP
 segments then 'convert' them to index segments upon
 completion.
   What
 I just found out (thanks to a failed operation) is that
 'CREATE
   TABLE
 AS SELECT' (ctas) also creates the segments as TEMP first.

   Dan Fink

   
   
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Re: OEM Config Assistant

2002-11-22 Thread Sathyanaryanan_K/VGIL
some rights has to granted to the user n for setting up the repository u
may need to modify ur register entry for the mgmt svr. check out the
installation notes to the set the values of key in the registry.
Regards,

Sathyanarayanan




|+
||  Mike Sardina|
||  cemail2@sprin|
||  tmail.com|
|||
||  23/11/2002|
||  01:29 |
||  Please respond|
||  to ORACLE-L   |
|||
|+
  --|
  |  |
  |   To: Multiple recipients of list ORACLE-L   |
  |   [EMAIL PROTECTED] |
  |   cc: (bcc: Sathyanaryanan K/VGIL)   |
  |   Subject: OEM Config Assistant  |
  --|





Using OEM Configuration Assistant 2.2, I tried to set up a Management
Server/repository, etc. and through the gui I created a user with a
password,
etc.  Now when I try to log into the Management Server with that
username/password, I get invalid credentials.  Through sqlplus I can log
into that username/password though.  Any ideas on what the problem could
be?
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Re: Storing of number datatype in table

2002-11-22 Thread Sathyanaryanan_K/VGIL
Thank u list for ur imm resp. It was the prob with numwidth.
Now I have set the num width to 25 and s working fine.
But whenever i stat the sql the default is set to 9. how do i change the
def numwidth??
Regards,

Sathyanarayanan




|+---
||  Arup Nanda |
||  arupnanda@ho|
||  tmail.com   |
||   |
||  22/11/2002   |
||  19:38|
||  Please   |
||  respond to   |
||  ORACLE-L |
||   |
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  |   To: Multiple recipients of list ORACLE-L   |
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  |   cc: (bcc: Sathyanaryanan K/VGIL)   |
  |   Subject: Re: Storing of number datatype in |
  |   table  |
  --|





The number is more than the numwidth specified. Try this

SQL set numwidth 13
SQL select trn_id from trnid;

Your numwidth is perhpas defined as 9; so anything of more precision is
displayed as exponetial notation; internally all numbers are stored the
same.

HTH

Arup Nanda
www.proligence.com

- Original Message -
To: Multiple recipients of list ORACLE-L [EMAIL PROTECTED]
Sent: Friday, November 22, 2002 6:23 AM


 Dear List

 Have a look at the sql !!!

 SQL create table trnid
   2  ( trn_id number(10));
 Table created.

 SQL insert into trnid(trn_id) values('11');/* 10 1's inserted*/
 1 row created.

 SQL insert into trnid(trn_id) values('1');/* 9 1's inserted*/
 1 row created.

 SQL commit;
 Commit complete.

 SQL select trn_id from trnid;

TRN_ID
 -
 1.111E+09
 1

 can anyone tell why the number(10) is stored in exp format

 Regards,

 Sathyanarayanan


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