[PHP-DB] Re: Nested SQL query problem...
Hello Srini, Don't speak english! :-) For example, what is the cost of 500 licenses of Product_ID 143 ? The slabs do not continue for an infinite number, hence I may only have slab pricing for 1-10, 11-100, and 101-200 with the assumption that if there are no higher slabs and I wanted say the rate for 500 licenses, I would use the highest slab unit available, in this case the 101-200 slab. My table structure is like so: Slab_Master ++-+--+-+-++ | Field | Type| Null | Key | Default | Extra | ++-+--+-+-++ | TInt_SlabID| int(11) | | PRI | NULL| auto_increment | | TInt_ProductID | int(11) | YES | | NULL|| | TInt_StartSlab | int(11) | YES | | NULL|| | TInt_EndSlab | int(11) | YES | | NULL|| | TDbl_SlabRate | float(10,2) | YES | | NULL|| ++-+--+-+-++ SKIP SELECT TDbl_SlabRateFROM Slab_Master WHERE TInt_ProductID = 143 AND TInt_StartSlab = 101; /*$MAX = 101*/ My examples: CREATE TABLE wm ( id int(3) unsigned default '0', tex char(24) default NULL, lic tinyint(3) unsigned default NULL ) INSERT INTO wm VALUES(1, w, 6); INSERT INTO wm VALUES(2, zz, 20); INSERT INTO wm VALUES(1, www, 5); INSERT INTO wm VALUES(1, ww, 7); INSERT INTO wm VALUES(5, z, 2); INSERT INTO wm VALUES(80, zzz, 1); My query: SELECT a.id, a.tex, MAX(a.lic) AS licens FROM wm a, wm b WHERE a.id=1 AND a.id=b.id AND a.lic60 GROUP BY a.id, a.tex HAVING MAX(a.lic)=MAX(b.lic) ^ Result: MAX licens = 7 -- Best regards, Zubarev Andrey mailto:[EMAIL PROTECTED] miranda-icq: 115959232 DelphiKingdom Team [http://www.delphikingdom.com] KZ - Ekibastuz -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] variables gone?
Dear All, I am probably doing something silly but I don't know what (story of my life). I have just upgraded to 4.2.1 and now all the variables I post in forms or in query strings are now coming up undefined errors and are in absent. I'm running PHP under IIS 4. What am I doing wrong? -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] variables gone?
In php.ini you need to turn register_globals on..you also might want to start using the $_GET, $_POST, $_SESSION global arrays ed At 02:49 PM 5/29/2002 +0100, Rob Fraser wrote: Dear All, I am probably doing something silly but I don't know what (story of my life). I have just upgraded to 4.2.1 and now all the variables I post in forms or in query strings are now coming up undefined errors and are in absent. I'm running PHP under IIS 4. What am I doing wrong? -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] REGEX help.
On Wednesday 29 May 2002 06:55, Kevin Stone wrote:
All I need to do is return anything matching the following pattern from a
specific column in a table. This is how I'd write it in PHP if I were
pulling the data from string. The string in this example is a direct copy
of one of the column fields..
?
$str = teaspoon_3 legends_3 lore_3 einstein_3 recipes_2 cups_2 plaster_2
paris_2;
// Search for einstein in the string and return the number associated with
that word.
preg_match_all('einstein_(\d)', $str, $matches);
?
What would be the SQL equivilant? I hate to seek a hand out here.. but I'm
struggling with SQL REGEX and there just aren't as many good examples out
there as there are for PHP. The MySQL manual wasn't much help that's for
sure. :-\
It doesn't seem possible. The MySQL REGEXP only returns a 1 or 0 to indicate a
match or no match.
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Open Source Software Systems Integrators
* Web Design Hosting * Internet Intranet Applications Development *
/*
You can't cheat an honest man. Never give a sucker an even break or
smarten up a chump.
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[PHP-DB] multiple queries
Hi to all,
I have a search form where users can search project by 'Project Name' after
they type in the project name, they will select which project they will like
to view from a drop down menu which contains: Management Approve,
Pre-Approved, Management-Not-Approved, and Pre-Not-Approved pproved.
I'm using switch statement
switch ($project)
{
case Management Approve
$sql = mysql_query(select * from project where project_name='$pro_name'
and final_approved='yes');
$result = mysql_query($sql);
$record_count = mysql_num_rows($result);
case Pre-Approved:
$sql2 = mysql_query(select * from project where project_name='$pro_name'
and first_approved='yes');
$result2 = mysql_query($sql2);
$record_count2 = mysql_num_rows($result2);
and so on...
My question is: how do I call $sql, or $sql2, and $result, or $result2 to
loop and put the fields into an array? The reason I'm asking is because the
users will be able to navegate through the recordset, so I need to call just
the query that match the criteria either '$result' or '$result2' to be able
to display the right information.
e.g.,
while($query_data = mysql_fetch_array($result)) //it can be $result2
{
$project_id = $query_data[project_id];
$project_name = $query_data[project_name];
}
I'm not sure if this explanation make sence to you guys, but if anybody
would like to take the time and try to help me out, that would be great
Thanks in advanced
Nato
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RE: [PHP-DB] variables gone?
Beginning in PHP 4.2.0, the normal behavior with respect to preloaded variables was changed (specifically, the default value of the register_globals configuration entry was changed from on to off). For details, see http://www.php.net/manual/en/language.variables.predefined.php --- Mark Roedel | Blessed is he who has learned to laugh Systems Programmer| at himself, for he shall never cease LeTourneau University | to be entertained. Longview, Texas, USA | -- John Powell -Original Message- From: Rob Fraser [mailto:[EMAIL PROTECTED]] Sent: Wednesday, May 29, 2002 8:49 AM To: [EMAIL PROTECTED] Subject: [PHP-DB] variables gone? I am probably doing something silly but I don't know what (story of my life). I have just upgraded to 4.2.1 and now all the variables I post in forms or in query strings are now coming up undefined errors and are in absent. I'm running PHP under IIS 4. What am I doing wrong? -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] dropping one word from column entries
I'm having a problem with this and suppose I'm looking for a handout. :| I am displaying names of product categories. The names of the categories are: Bird Cages Cat Toys Chinchilla Housing Products Dog Leashes Ferret Housing Products Mouse Housing Products What I want to do when displaying the names is to drop Products whenever it appears. What I want do display on the page instead is: Bird Cages Cat Toys Chinchilla Housing Dog Leashes Ferret Housing Mouse Housing And no, changing the names of the categories in the database is not an option. :) I'm completely missing the boat on this one... any help? Jen Swofford [EMAIL PROTECTED] -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] Re: multiple queries
What's wrong with this or something similar:
$sql= mysql_query(
SELECT
*
FROM
project
WHERE
project_name
= '$pro_name'
AND ( final_approved = 'yes' AND '$project' = 'Management Approve'
ORfirst_approved = 'yes' AND '$project' = 'Pre-Approved'
ORect...
;
$result = mysql_query($sql);
$record_count = mysql_num_rows($result);
HTH
Good luck Dan..
===
Natividad Castro wrote:
Hi to all,
I have a search form where users can search project by 'Project Name' after
they type in the project name, they will select which project they will like
to view from a drop down menu which contains: Management Approve,
Pre-Approved, Management-Not-Approved, and Pre-Not-Approved pproved.
I'm using switch statement
switch ($project)
{
case Management Approve
$sql = mysql_query(select * from project where project_name='$pro_name'
and final_approved='yes');
$result = mysql_query($sql);
$record_count = mysql_num_rows($result);
case Pre-Approved:
$sql2 = mysql_query(select * from project where project_name='$pro_name'
and first_approved='yes');
$result2 = mysql_query($sql2);
$record_count2 = mysql_num_rows($result2);
and so on...
My question is: how do I call $sql, or $sql2, and $result, or $result2 to
loop and put the fields into an array? The reason I'm asking is because the
users will be able to navegate through the recordset, so I need to call just
the query that match the criteria either '$result' or '$result2' to be able
to display the right information.
e.g.,
while($query_data = mysql_fetch_array($result)) //it can be $result2
{
$project_id = $query_data[project_id];
$project_name = $query_data[project_name];
}
I'm not sure if this explanation make sence to you guys, but if anybody
would like to take the time and try to help me out, that would be great
Thanks in advanced
Nato
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Re: [PHP-DB] dropping one word from column entries
use: $name=Mouse Housing Products; $name=str_replace(Products,,$name); also the RTFM() function works too ed At 11:06 AM 5/29/2002 -0500, Jen Swofford wrote: I'm having a problem with this and suppose I'm looking for a handout. :| I am displaying names of product categories. The names of the categories are: Bird Cages Cat Toys Chinchilla Housing Products Dog Leashes Ferret Housing Products Mouse Housing Products What I want to do when displaying the names is to drop Products whenever it appears. What I want do display on the page instead is: Bird Cages Cat Toys Chinchilla Housing Dog Leashes Ferret Housing Mouse Housing And no, changing the names of the categories in the database is not an option. :) I'm completely missing the boat on this one... any help? Jen Swofford [EMAIL PROTECTED] -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] Resource ID#2 ????
Ok here is my problem, I set this up so a user selects a name form a select
box and that name or $user_id is then passed to this page so the user can
edit the contact info etc. However it does not pull the selected $user_id
and place each field into my form boxes, all I get is a Resource ID #2. Not
sure how I can over come this...
$table = auth_users;
$record = @mysql_query(SELECT * FROM $table WHERE user_id =
'$user_id',$dbh);
$var_form .= table width=\100%\ border=\0\ cellpadding=\7\form
name=\$user_id\ method=\post\ action=\del_account.php\
trtd width=\20%\ colspan=\2\bEdit Account
$user_id/b/td/tr
trtd width=\20%\First Name:/tdtd width=\80%\input
type=\text\ name=\$f_name\ size=\30\ maxlength=\30\
value=\$f_name\font class=\copyright\i.e. John/font/td/tr
trtd width=\20%\Last Name:/tdtd width=\80%\input
type=\text\ name=\$l_name\ size=\30\ maxlength=\30\
value=\$l_name\font class=\copyright\i.e. Doe/font/td/tr
trtd width=\20%\Email:/tdtd width=\80%\input
type=\text\ name=\$email_addy\ size=\30\ maxlength=\30\
value=\$email_addy\font class=\copyright\i.e.
[EMAIL PROTECTED]/font/td/tr
trtd width=\20%\User Name:/tdtd width=\80%\input
type=\text\ name=\$un\ size=\30\ maxlength=\30\ value=\$un\font
class=\copyright\i.e. j-doe/font/td/tr
trtd width=\20%\Password:/tdtd width=\80%\input
type=\password\ name=\$pw\ size=\30\ maxlength=\30\font
class=\copyright\(password must be alpha-numeric, i.e.
pAs5w0rd)/font/td/tr
trtd width=\20%\Confirm Password:/tdtd
width=\80%\input type=\password\ name=\$pw\ size=\30\
maxlength=\30\font class=\copyright\please confirm password
entered/font/td/tr
trtd width=\20%\nbsp;/tdtd width=\80%\input
type=\submit\ name=\add\ value=\edit user\nbsp;nbsp;input
type=\reset\ name=\reset\ value=\reset\/td/tr
/form/table;
echo $record;
} else {
blah blah
}
Thanks in advance,
Jas
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Re: [PHP-DB] dropping one word from column entries
Ed Gorski [EMAIL PROTECTED] wrote: use: $name=Mouse Housing Products; $name=str_replace(Products,,$name); also the RTFM() function works too I'd also trim it to get rid of any extra spaces that are left: $name = trim(str_replace(Products,,$name)); -- Stuart -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Resource ID#2 ????
On Thursday 30 May 2002 00:17, Jas wrote: Ok here is my problem, I set this up so a user selects a name form a select box and that name or $user_id is then passed to this page so the user can edit the contact info etc. However it does not pull the selected $user_id and place each field into my form boxes, all I get is a Resource ID #2. Not sure how I can over come this... $table = auth_users; $record = mysql_query(SELECT * FROM $table WHERE user_id = '$user_id',$dbh); Make liberal use of error checking (see manual) and mysql_error(). -- Jason Wong - Gremlins Associates - www.gremlins.com.hk Open Source Software Systems Integrators * Web Design Hosting * Internet Intranet Applications Development * /* grep me no patterns and I'll tell you no lines. */ -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] FW: hello ... best schema to a forum
-Mensagem original- De: José Moreira [mailto:[EMAIL PROTECTED]] Enviada: terça-feira, 28 de Maio de 2002 15:14 Para: [EMAIL PROTECTED] Assunto: FW: hello ... best schema to a forum Importância: Alta im trying to figure out the best mySQL schema to create a forum on my website ... to result in a tree-view style presentation what i have right now is a 3 table schema : categories sub-categories lines ... wich would result in a code parsing to emulate the tree the other way is a nodes-leaf schema that whould envolve recursive programming ... the result i wouuld want is something like, ex. º main º programming º php whats your opinion ? my regards, josé moreira portugal -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Resource ID#2 ????
If you look at the previously posted code at the bottom of the form there is a echo for the sql select statement that is echoing Resource id #2 on the page. Now that error is the correct field id number in the database, I am just not sure how to itemize the data from that table, at least I think. Any help would be great! Jas Jason Wong [EMAIL PROTECTED] wrote in message [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... On Thursday 30 May 2002 00:17, Jas wrote: Ok here is my problem, I set this up so a user selects a name form a select box and that name or $user_id is then passed to this page so the user can edit the contact info etc. However it does not pull the selected $user_id and place each field into my form boxes, all I get is a Resource ID #2. Not sure how I can over come this... $table = auth_users; $record = @mysql_query(SELECT * FROM $table WHERE user_id = '$user_id',$dbh); Make liberal use of error checking (see manual) and mysql_error(). -- Jason Wong - Gremlins Associates - www.gremlins.com.hk Open Source Software Systems Integrators * Web Design Hosting * Internet Intranet Applications Development * /* grep me no patterns and I'll tell you no lines. */ -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Resource ID#2 ????
I could be missing something, but it looks like you are using the result of
the mysql_query as the actual result. It actually returns some weird
identifier. To access the real info you'd have to use something like
mysql_fetch_array to get it.
Check out this and see if it helps:
http://www.php.net/manual/en/function.mysql-query.php
-Natalie
-Original Message-
From: Jas [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, May 29, 2002 12:18 PM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] Resource ID#2
Ok here is my problem, I set this up so a user selects a name form a select
box and that name or $user_id is then passed to this page so the user can
edit the contact info etc. However it does not pull the selected $user_id
and place each field into my form boxes, all I get is a Resource ID #2. Not
sure how I can over come this...
$table = auth_users;
$record = @mysql_query(SELECT * FROM $table WHERE user_id =
'$user_id',$dbh);
$var_form .= table width=\100%\ border=\0\ cellpadding=\7\form
name=\$user_id\ method=\post\ action=\del_account.php\
trtd width=\20%\ colspan=\2\bEdit Account
$user_id/b/td/tr
trtd width=\20%\First Name:/tdtd width=\80%\input
type=\text\ name=\$f_name\ size=\30\ maxlength=\30\
value=\$f_name\font class=\copyright\i.e. John/font/td/tr
trtd width=\20%\Last Name:/tdtd width=\80%\input
type=\text\ name=\$l_name\ size=\30\ maxlength=\30\
value=\$l_name\font class=\copyright\i.e. Doe/font/td/tr
trtd width=\20%\Email:/tdtd width=\80%\input
type=\text\ name=\$email_addy\ size=\30\ maxlength=\30\
value=\$email_addy\font class=\copyright\i.e.
[EMAIL PROTECTED]/font/td/tr
trtd width=\20%\User Name:/tdtd width=\80%\input
type=\text\ name=\$un\ size=\30\ maxlength=\30\ value=\$un\font
class=\copyright\i.e. j-doe/font/td/tr
trtd width=\20%\Password:/tdtd width=\80%\input
type=\password\ name=\$pw\ size=\30\ maxlength=\30\font
class=\copyright\(password must be alpha-numeric, i.e.
pAs5w0rd)/font/td/tr
trtd width=\20%\Confirm Password:/tdtd
width=\80%\input type=\password\ name=\$pw\ size=\30\
maxlength=\30\font class=\copyright\please confirm password
entered/font/td/tr
trtd width=\20%\nbsp;/tdtd width=\80%\input
type=\submit\ name=\add\ value=\edit user\nbsp;nbsp;input
type=\reset\ name=\reset\ value=\reset\/td/tr
/form/table;
echo $record;
} else {
blah blah
}
Thanks in advance,
Jas
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[PHP-DB] Outlook Out Of Office
i know this List isn't for this, but I'm about to go on vacation and I don't want to AutoReply everytime someone posts to this list. Does anyone know how I can set Out Of Office to skip sending a reply when the mail was sent to [EMAIL PROTECTED] ? I looked at the rules and all of the actions are the ones that I don't need. None of them are Don't send response ... I imagine this could be helpful for others as well. Ryan -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Resource ID#2 ????
On Thursday 30 May 2002 00:41, Jas wrote: If you look at the previously posted code at the bottom of the form there is a echo for the sql select statement that is echoing Resource id #2 on the page. Now that error is the correct field id number in the database, I am just not sure how to itemize the data from that table, at least I think. Any help would be great! You are confused -- #2 just happens to coincide with your field id. You're not RFTM. mysql_query() returns a result_id (Resource id #2). You feed this into a mysql_fetch_row() (or any of the other similar functions) to actually retrieve records. -- Jason Wong - Gremlins Associates - www.gremlins.com.hk Open Source Software Systems Integrators * Web Design Hosting * Internet Intranet Applications Development * /* 1: No code table for op: ++post */ -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Outlook Out Of Office
I couldn't find a way to exclude someone - even in the rules it didn't look like it had anything like that. It doesn't even look like you can skip it if you delete. You might want to try to the MS website - they have a pretty thorough FAQ and it's much better than the help that comes up with the paperclip (I didn't find it in there)! If you find anything, please let me know. I don't want to spam everyone with my Out of Office replies either :-) -Natalie -Original Message- From: Ryan Jameson (USA) [mailto:[EMAIL PROTECTED]] Sent: Wednesday, May 29, 2002 12:50 PM To: [EMAIL PROTECTED] Subject: [PHP-DB] Outlook Out Of Office i know this List isn't for this, but I'm about to go on vacation and I don't want to AutoReply everytime someone posts to this list. Does anyone know how I can set Out Of Office to skip sending a reply when the mail was sent to [EMAIL PROTECTED] ? I looked at the rules and all of the actions are the ones that I don't need. None of them are Don't send response ... I imagine this could be helpful for others as well. Ryan -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] Remote Update ONCE a day
Hi all, Two days ago I was requested to make a proyect for a non-profit company, and I'm doing the drwaings for the databases and programming which I will use. This company wants to run the program in a PC which will not hold the main DB (which will will at HQ), but they also not need the new information in real time. What I don't know, if there's a way for me to install two programs and two DBs and had them updated let's say once a day using PC-ANYWARE or internet. I think maybe the one way to do this, is by making the HQ computer, download a file which holds the las 24 hours changes to the working DB. Is it possible for me to make PHP update the working DB and also reflect those changes into a Text file? I hope there's a better way that I haven't tink of yet. Does anyone knows this? Thanx in advance, Cesar Aracena [EMAIL PROTECTED] Neuquen, Argentina
Re: [PHP-DB] Resource ID#2 ????
How can I get the form below to list the single record in a db that matches
the request of $user_id?
$table = auth_users;
$record = @mysql_query(SELECT * FROM $table WHERE user_id =
'$user_id',$dbh);
while ($row = mysql_fetch_row($record)) {
$user_id = $row['user_id'];
$f_name = $row['f_name'];
$l_name = $row['l_name'];
$email_addy = $row['email_addy'];
$un = $row['un'];
$pw = $row['pw']; }
$var_form .= table width=\100%\ border=\0\ cellpadding=\7\form
name=\$user_id\ method=\post\ action=\del_account.php\
trtd width=\20%\ colspan=\2\bEdit Account
$user_id/b/td/tr
trtd width=\20%\First Name:/tdtd width=\80%\input
type=\text\ name=\f_name\ size=\30\ maxlength=\30\
value=\$f_name\font class=\copyright\i.e. John/font/td/tr
trtd width=\20%\Last Name:/tdtd width=\80%\input
type=\text\ name=\l_name\ size=\30\ maxlength=\30\
value=\$l_name\font class=\copyright\i.e. Doe/font/td/tr
trtd width=\20%\Email:/tdtd width=\80%\input
type=\text\ name=\email_addy\ size=\30\ maxlength=\30\
value=\$email_addy\font class=\copyright\i.e.
[EMAIL PROTECTED]/font/td/tr
trtd width=\20%\User Name:/tdtd width=\80%\input
type=\text\ name=\un\ size=\30\ maxlength=\30\ value=\$un\font
class=\copyright\i.e. j-doe/font/td/tr
trtd width=\20%\Password:/tdtd width=\80%\input
type=\password\ name=\pw\ size=\30\ maxlength=\30\font
class=\copyright\(password must be alpha-numeric, i.e.
pAs5w0rd)/font/td/tr
trtd width=\20%\Confirm Password:/tdtd
width=\80%\input type=\password\ name=\pw\ size=\30\
maxlength=\30\font class=\copyright\please confirm password
entered/font/td/tr
trtd width=\20%\nbsp;/tdtd width=\80%\input
type=\submit\ name=\add\ value=\edit user\nbsp;nbsp;input
type=\reset\ name=\reset\ value=\reset\/td/tr
/form/table;
echo $record;
Thanks in advance,
Jas
Natalie Leotta [EMAIL PROTECTED] wrote in message
7546CB15C0A1D311BF0D0004AC4C4B0C024AC420@SSIMSEXCHNG">news:7546CB15C0A1D311BF0D0004AC4C4B0C024AC420@SSIMSEXCHNG...
I could be missing something, but it looks like you are using the result
of
the mysql_query as the actual result. It actually returns some weird
identifier. To access the real info you'd have to use something like
mysql_fetch_array to get it.
Check out this and see if it helps:
http://www.php.net/manual/en/function.mysql-query.php
-Natalie
-Original Message-
From: Jas [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, May 29, 2002 12:18 PM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] Resource ID#2
Ok here is my problem, I set this up so a user selects a name form a
select
box and that name or $user_id is then passed to this page so the user can
edit the contact info etc. However it does not pull the selected $user_id
and place each field into my form boxes, all I get is a Resource ID #2.
Not
sure how I can over come this...
$table = auth_users;
$record = @mysql_query(SELECT * FROM $table WHERE user_id =
'$user_id',$dbh);
$var_form .= table width=\100%\ border=\0\
cellpadding=\7\form
name=\$user_id\ method=\post\ action=\del_account.php\
trtd width=\20%\ colspan=\2\bEdit Account
$user_id/b/td/tr
trtd width=\20%\First Name:/tdtd width=\80%\input
type=\text\ name=\$f_name\ size=\30\ maxlength=\30\
value=\$f_name\font class=\copyright\i.e. John/font/td/tr
trtd width=\20%\Last Name:/tdtd width=\80%\input
type=\text\ name=\$l_name\ size=\30\ maxlength=\30\
value=\$l_name\font class=\copyright\i.e. Doe/font/td/tr
trtd width=\20%\Email:/tdtd width=\80%\input
type=\text\ name=\$email_addy\ size=\30\ maxlength=\30\
value=\$email_addy\font class=\copyright\i.e.
[EMAIL PROTECTED]/font/td/tr
trtd width=\20%\User Name:/tdtd width=\80%\input
type=\text\ name=\$un\ size=\30\ maxlength=\30\
value=\$un\font
class=\copyright\i.e. j-doe/font/td/tr
trtd width=\20%\Password:/tdtd width=\80%\input
type=\password\ name=\$pw\ size=\30\ maxlength=\30\font
class=\copyright\(password must be alpha-numeric, i.e.
pAs5w0rd)/font/td/tr
trtd width=\20%\Confirm Password:/tdtd
width=\80%\input type=\password\ name=\$pw\ size=\30\
maxlength=\30\font class=\copyright\please confirm password
entered/font/td/tr
trtd width=\20%\nbsp;/tdtd width=\80%\input
type=\submit\ name=\add\ value=\edit user\nbsp;nbsp;input
type=\reset\ name=\reset\ value=\reset\/td/tr
/form/table;
echo $record;
} else {
blah blah
}
Thanks in advance,
Jas
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[PHP-DB] mssql_connect problem
I removed some 'security' settings that Microsoft had recommended which had prevented Named Pipe connections to our Microsoft SQL server. Basically requiring everyone to use TCPIP connections. Which is very simple when using a sYstem DSN or ADODB or any number of ASP connection types. But the latest version of PHP 4.2.1 seems to have a bug in mssql.connect where it DOES NOT use TCPIP connection, it for some reason always wants to use Named Pipes, even when you use a FQDN,1433 which should force it to use TCPIP. I don't know why, and since PHP is free, there really isn't a single company in charge of fixing such a problem. Registry settings set back to: [HKEY_LOCAL_MACHINE\SYSTEM\CurrentControlSet\Control\LSA] RestrictAnonymous=dword: [HKEY_LOCAL_MACHINE\SYSTEM\CurrentControlSet\Services\LanManServer\Parameter s] RestrictNullSessAccess=dword: The following Registry Settings on SQL 2000 server caused PHP 4.2.1 mssql.connect to fail a connection even though ASP pages and ODBC.connect using a system DSN configured to use TCPIP had no problem [HKEY_LOCAL_MACHINE\SYSTEM\CurrentControlSet\Control\LSA] RestrictAnonymous=dword:0002 [HKEY_LOCAL_MACHINE\SYSTEM\CurrentControlSet\Services\LanManServer\Parameter s] RestrictNullSessAccess=dword:0001 Microsoft recommends these two settings for security purposes. I do not know why mssql_connect doesn't like those set on the SQL server. In theory putting ,1433 at the end of the servername should force mssql to use a tcpip connection, but it doesn't when passed thru IIS 5.0. If I ran the php script in a dos prompt under an admin account from the IIS system, it had no problem, but when under the IUSR account, it could not make the connection and would error with the trust issue. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] dropping one word from column entries
A cleaner option might be to do this before you get it to PHP at all, via your SQL query. Check out the string functions available, there are a number of substring-style things available, string position etc. HTH Beau // -Original Message- // From: Ed Gorski [mailto:[EMAIL PROTECTED]] // Sent: Thursday, 30 May 2002 12:09 AM // To: Jen Swofford; php-db@lists. php. net // Subject: Re: [PHP-DB] dropping one word from column entries // // // use: // // $name=Mouse Housing Products; // $name=str_replace(Products,,$name); // // also the RTFM() function works too // // ed // // At 11:06 AM 5/29/2002 -0500, Jen Swofford wrote: // I'm having a problem with this and suppose I'm looking for // a handout. :| // // I am displaying names of product categories. The names of // the categories // are: // // Bird Cages // Cat Toys // Chinchilla Housing Products // Dog Leashes // Ferret Housing Products // Mouse Housing Products // // What I want to do when displaying the names is to drop // Products whenever // it appears. What I want do display on the page instead is: // // Bird Cages // Cat Toys // Chinchilla Housing // Dog Leashes // Ferret Housing // Mouse Housing // // And no, changing the names of the categories in the // database is not an // option. :) I'm completely missing the boat on this one... // any help? // // Jen Swofford // [EMAIL PROTECTED] // // // // // -- // PHP Database Mailing List (http://www.php.net/) // To unsubscribe, visit: http://www.php.net/unsub.php // // // -- // PHP Database Mailing List (http://www.php.net/) // To unsubscribe, visit: http://www.php.net/unsub.php // -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] mysql exclusion in php
Hi there everyone, How can I do a search which excludes certain words if they put a - in the search string? I can do a search easily, but if they put a - infront of a word in the string, how can I then get MySQL to search all entries EXCEPT where the word with a - next to it appears? Thanks for everything. Chris
RE: [PHP-DB] mysql exclusion in php
chris, you'll need to do a little PHP manipulation, perhaps (pseudo) if -word. (regular expression?) for each -word SQL .= NOT LIKE '%word% AND' endforeach endif for each other word SQL .= LIKE '%word%' AND endforeach strip trailing AND clean up SQL as required query db - ok, obviously that's very rough, but i think something like that will work :) HTH Beau // -Original Message- // From: Chris Payne [mailto:[EMAIL PROTECTED]] // Sent: Thursday, 30 May 2002 12:22 PM // To: [EMAIL PROTECTED] // Subject: [PHP-DB] mysql exclusion in php // // // Hi there everyone, // // How can I do a search which excludes certain words if they // put a - in the search string? I can do a search easily, but // if they put a - infront of a word in the string, how can I // then get MySQL to search all entries EXCEPT where the word // with a - next to it appears? // // Thanks for everything. // // Chris // -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] Truncated Data
Hello,
I desperately need help... I've based my entire project on the use of input text
boxes that can be read or edited. Its a web form that gets its data from mysql
tables. For some reason when I write the code this way and use single quotes ('),
everything after a single quote in the string gets truncated:
echo input $ca name=university[$y] value='$university[$y]';
But when I use double quotes () like this:
echo input $ca name=university[$y] value=\$university[$y]\;
Everything after a gets truncated in the text string. When I first input the data
it goes into the mysql database fine. The problem only lies in when I import the
value into the html form. I even tried writing the code like this:
echo input $ca name=university[$y] value=$university[$y];
And here is what the source code shows:
input class=Inputa name=university[1] value=John's Wayne
But the input box shows only: John's
Oh, and I don't get the problem when I use textarea instead of input tags, but
they just won't do for the design.
Any help or advise would be greatly appreciated.
Larentium
[EMAIL PROTECTED]
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RE: [PHP-DB] Truncated Data
htmlspecialchars()
Beau
// -Original Message-
// From: Larentium [mailto:[EMAIL PROTECTED]]
// Sent: Thursday, 30 May 2002 10:40 AM
// To: [EMAIL PROTECTED]
// Subject: [PHP-DB] Truncated Data
//
//
// Hello,
//
// I desperately need help... I've based my entire project on
// the use of input text boxes that can be read or edited. Its
// a web form that gets its data from mysql tables. For some
// reason when I write the code this way and use single quotes
// ('), everything after a single quote in the string gets truncated:
//
// echo input $ca name=university[$y] value='$university[$y]';
//
// But when I use double quotes () like this:
//
// echo input $ca name=university[$y] value=\$university[$y]\;
//
// Everything after a gets truncated in the text string.
// When I first input the data it goes into the mysql database
// fine. The problem only lies in when I import the value into
// the html form. I even tried writing the code like this:
//
// echo input $ca name=university[$y] value=$university[$y];
//
// And here is what the source code shows:
// input class=Inputa name=university[1] value=John's Wayne
//
// But the input box shows only: John's
//
// Oh, and I don't get the problem when I use textarea
// instead of input tags, but they just won't do for the design.
// Any help or advise would be greatly appreciated.
//
//
// Larentium
// [EMAIL PROTECTED]
//
//
// --
// PHP Database Mailing List (http://www.php.net/)
// To unsubscribe, visit: http://www.php.net/unsub.php
//
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