[PHP-DB] help me
i can't use start_secsion(); in php4, it say: error : can't ofen(\tmp/4363jghsfjkhshga.. like this...
Re: [PHP-DB] help me
Hello khac, hmm what platform are you running on? what are PHP settings for writing sessions? Check out permissions for /tmp directory, check out free space on disk. -- Best regards, Martin mail [EMAIL PROTECTED] mobile +421.907.303.393 icq34358414 wwwhttp://www.corwin.sk PGP key fingerprint 21365ca05ecfd8aeb1cf19c838fff033 In those days spirits were brave, the stakes were high, men were real men, women were real women and small furry creatures from Alpha Centauri were real small furry creatures from Alpha Centauri. by Douglas Adams Friday, January 10, 2003, 1:07:54 AM, you wrote: kd i can't use start_secsion(); in php4, it say: kd error : can't ofen(\tmp/4363jghsfjkhshga.. like this... -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] help me
Are you running on windows or Linux??? This looks like a Windows problem - you have to set your SESSION_SAVE_PATH in php.ini AND make sure the folder you specify exists and is accessible to PHP. HTH, Richy == Richard Black Senior Developer, DataVisibility Ltd - http://www.datavisibility.com Tel: 0141 951 3481 Email: [EMAIL PROTECTED] khac duy khacduyst@sg. To: [EMAIL PROTECTED] netnam.vn cc: Subject: [PHP-DB] help me 10/01/2003 00:07 i can't use start_secsion(); in php4, it say: error : can't ofen(\tmp/4363jghsfjkhshga.. like this... This email has been scanned for all viruses by the MessageLabs SkyScan service. For more information on a proactive anti-virus service working around the clock, around the globe, visit http://www.messagelabs.com -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] help me
when using start_session the code tries to write a file to the tmp dir... think you are working under windows so make in c: a \tmp dir !!! then it should work -Original Message- From: khac duy [mailto:[EMAIL PROTECTED]] Sent: vrijdag 10 januari 2003 1:08 To: [EMAIL PROTECTED] Subject: [PHP-DB] help me i can't use start_secsion(); in php4, it say: error : can't ofen(\tmp/4363jghsfjkhshga.. like this... -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] how use random in php
in php only support shuffe(); function,i want random a array,how
RE: [PHP-DB] how use random in php
check www.php.net and search for array... then you will get a list of all the array functions try to find it out yourself first please -mark- -Original Message- From: khac duy [mailto:[EMAIL PROTECTED]] Sent: vrijdag 10 januari 2003 1:15 To: [EMAIL PROTECTED] Subject: [PHP-DB] how use random in php in php only support shuffe(); function,i want random a array,how -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] LEFT JOIN not working
I have a page with many ads that stores both the number of times an ad is displayed and how many times it gets clicked. These are stored in two different tables (since different information is stored for each) but both have identical name columns. I am trying to display both # times displayed and # times clicked in the same table in an admin page. Here is my query: SELECT ads_clickrate.name, ads_clickrate.link, SUM(ads_displayrate.count) as display, COUNT(ads_clickrate.date) as click FROM ads_displayrate LEFT JOIN ads_clickrate ON ads_displayrate.name = ads_clickrate.name WHERE YEAR(ads_clickrate.date) = '2003' AND MONTH(ads_clickrate.date) = '01' GROUP BY ads_clickrate.name ORDER BY ads_clickrate.name I want to display for each ad the number of times displayed, and then number of times clicked if applicable, if not 0. The query is only returning rows for ads that have been clicked on. Is the problem because I have a COUNT column for one table, with a group by? Is this causing the display to be grouped also? If you need more information how the table is set up let me know, I'm really stumped here. Thanks, -Lisi -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] LEFT JOIN not working
problem 1: move the WHERE clauses to the ON clauses problem 2: Obviously your intent with COUNT(ads_clickrate.date) is to count the number of non-null occurences of click. But COUNT() is not the appropriate function to do this (it will simply give you the number of rows inside a group). Try replacing COUNT(ads_clickrate.date) by SUM( IF( ads_clickrate.date IS NULL, 0, 1 ) ) HTH Ignatius - Original Message - From: Lisi [EMAIL PROTECTED] To: PHP-DB [EMAIL PROTECTED] Sent: Thursday, January 09, 2003 10:44 AM Subject: [PHP-DB] LEFT JOIN not working I have a page with many ads that stores both the number of times an ad is displayed and how many times it gets clicked. These are stored in two different tables (since different information is stored for each) but both have identical name columns. I am trying to display both # times displayed and # times clicked in the same table in an admin page. Here is my query: SELECT ads_clickrate.name, ads_clickrate.link, SUM(ads_displayrate.count) as display, COUNT(ads_clickrate.date) as click FROM ads_displayrate LEFT JOIN ads_clickrate ON ads_displayrate.name = ads_clickrate.name WHERE YEAR(ads_clickrate.date) = '2003' AND MONTH(ads_clickrate.date) = '01' GROUP BY ads_clickrate.name ORDER BY ads_clickrate.name I want to display for each ad the number of times displayed, and then number of times clicked if applicable, if not 0. The query is only returning rows for ads that have been clicked on. Is the problem because I have a COUNT column for one table, with a group by? Is this causing the display to be grouped also? If you need more information how the table is set up let me know, I'm really stumped here. Thanks, -Lisi -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] LEFT JOIN not working
Your 4th row ought to have an identifier of some sort. From your SELECT statement, this seems to be the name. Why does it not have a name? Probably what you want is a row with a name but a NULL value for ads_clickrate.date. (by the way it is EXTREMELY advisable to use an abstract identifier, such as an id, unique and required, instead of name) Ignatius - Original Message - From: Lisi [EMAIL PROTECTED] To: Ignatius Reilly [EMAIL PROTECTED]; PHP-DB [EMAIL PROTECTED] Sent: Thursday, January 09, 2003 12:18 PM Subject: Re: [PHP-DB] LEFT JOIN not working OK, this helped a bit. Now I have, in addition to the three rows of ads that have ben clicked on, a fourth row with no ad name, 0 clickthroughs, and 24 displays. That plus the other three account for all the displayed ads. However, since it is returning a null value for any ad name that has not been clicked on, and then it's grouped by ad name, it lumps all non-clicked ads into one row. What I need is to see each ad on a separate row, which is what I thought a LEFT JOIN was supposed to do. Any suggestions? Thanks, -Lisi At 11:07 AM 1/9/03 +0100, Ignatius Reilly wrote: problem 1: move the WHERE clauses to the ON clauses problem 2: Obviously your intent with COUNT(ads_clickrate.date) is to count the number of non-null occurences of click. But COUNT() is not the appropriate function to do this (it will simply give you the number of rows inside a group). Try replacing COUNT(ads_clickrate.date) by SUM( IF( ads_clickrate.date IS NULL, 0, 1 ) ) HTH Ignatius - Original Message - From: Lisi [EMAIL PROTECTED] To: PHP-DB [EMAIL PROTECTED] Sent: Thursday, January 09, 2003 10:44 AM Subject: [PHP-DB] LEFT JOIN not working I have a page with many ads that stores both the number of times an ad is displayed and how many times it gets clicked. These are stored in two different tables (since different information is stored for each) but both have identical name columns. I am trying to display both # times displayed and # times clicked in the same table in an admin page. Here is my query: SELECT ads_clickrate.name, ads_clickrate.link, SUM(ads_displayrate.count) as display, COUNT(ads_clickrate.date) as click FROM ads_displayrate LEFT JOIN ads_clickrate ON ads_displayrate.name = ads_clickrate.name WHERE YEAR(ads_clickrate.date) = '2003' AND MONTH(ads_clickrate.date) = '01' GROUP BY ads_clickrate.name ORDER BY ads_clickrate.name I want to display for each ad the number of times displayed, and then number of times clicked if applicable, if not 0. The query is only returning rows for ads that have been clicked on. Is the problem because I have a COUNT column for one table, with a group by? Is this causing the display to be grouped also? If you need more information how the table is set up let me know, I'm really stumped here. Thanks, -Lisi -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] LEFT JOIN not working
Oops! Sorry, I missed it the first time. Your query should start as: SELECT ads_displayrate.name instead of SELECT ads_clickrate.name then you will always have a non-NULL name (coming from the table on the left of the LEFT JOIN). HTH Ignatius, from Brussels Where the fuck is Belgium? D. Ivester, CEO, Coca Cola - Original Message - From: Lisi [EMAIL PROTECTED] To: Ignatius Reilly [EMAIL PROTECTED]; PHP-DB [EMAIL PROTECTED] Sent: Thursday, January 09, 2003 1:11 PM Subject: Re: [PHP-DB] LEFT JOIN not working Exactly my question - why does it not have a name? How would I modify my query to get a row with a name but null value for date? I thought the join would take care of this, but I'm obviously not doing it right. You mention a unique identifier, there is a separate table with a row for each ad, containing name, URL, and a unique ID number (autoincrement). Should this table be included somehow in the query? How would this help? Thanks, -Lisi At 12:45 PM 1/9/03 +0100, Ignatius Reilly wrote: Your 4th row ought to have an identifier of some sort. From your SELECT statement, this seems to be the name. Why does it not have a name? Probably what you want is a row with a name but a NULL value for ads_clickrate.date. (by the way it is EXTREMELY advisable to use an abstract identifier, such as an id, unique and required, instead of name) Ignatius - Original Message - From: Lisi [EMAIL PROTECTED] To: Ignatius Reilly [EMAIL PROTECTED]; PHP-DB [EMAIL PROTECTED] Sent: Thursday, January 09, 2003 12:18 PM Subject: Re: [PHP-DB] LEFT JOIN not working OK, this helped a bit. Now I have, in addition to the three rows of ads that have ben clicked on, a fourth row with no ad name, 0 clickthroughs, and 24 displays. That plus the other three account for all the displayed ads. However, since it is returning a null value for any ad name that has not been clicked on, and then it's grouped by ad name, it lumps all non-clicked ads into one row. What I need is to see each ad on a separate row, which is what I thought a LEFT JOIN was supposed to do. Any suggestions? Thanks, -Lisi At 11:07 AM 1/9/03 +0100, Ignatius Reilly wrote: problem 1: move the WHERE clauses to the ON clauses problem 2: Obviously your intent with COUNT(ads_clickrate.date) is to count the number of non-null occurences of click. But COUNT() is not the appropriate function to do this (it will simply give you the number of rows inside a group). Try replacing COUNT(ads_clickrate.date) by SUM( IF( ads_clickrate.date IS NULL, 0, 1 ) ) HTH Ignatius - Original Message - From: Lisi [EMAIL PROTECTED] To: PHP-DB [EMAIL PROTECTED] Sent: Thursday, January 09, 2003 10:44 AM Subject: [PHP-DB] LEFT JOIN not working I have a page with many ads that stores both the number of times an ad is displayed and how many times it gets clicked. These are stored in two different tables (since different information is stored for each) but both have identical name columns. I am trying to display both # times displayed and # times clicked in the same table in an admin page. Here is my query: SELECT ads_clickrate.name, ads_clickrate.link, SUM(ads_displayrate.count) as display, COUNT(ads_clickrate.date) as click FROM ads_displayrate LEFT JOIN ads_clickrate ON ads_displayrate.name = ads_clickrate.name WHERE YEAR(ads_clickrate.date) = '2003' AND MONTH(ads_clickrate.date) = '01' GROUP BY ads_clickrate.name ORDER BY ads_clickrate.name I want to display for each ad the number of times displayed, and then number of times clicked if applicable, if not 0. The query is only returning rows for ads that have been clicked on. Is the problem because I have a COUNT column for one table, with a group by? Is this causing the display to be grouped also? If you need more information how the table is set up let me know, I'm really stumped here. Thanks, -Lisi -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] two inserts at once?
This Code Snippet works:
$newfaq_query = INSERT INTO `faq` (`faqid`, `question`, `answer`) VALUES
('', '$question', '$answer');
$newfeaturesResult = mysql_query($newfeatures_query);
But I'd like to combine that query with this one:
INSERT INTO `faqRelatedToProduct` (`id`, `fgNumber`, `faqId`) VALUES ('',
'$fgNumber', '$faqid');
So that both are executed at the same time.
The variables $question, $answer, $fgNumber come from a form, the faqid is
a auto increment field, as is id... but it seems I need to know the value
of faqid to relate it correctly to the fgNumber...
Is there a way to combine the two queries?
Michael
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[PHP-DB] [mysql - php] Newline to BR problem
I'm trying to place a text from a textfield into a database and displaying it on another page. All works fine and well but my problem is: If i place newline characters (press enter) in the forms textfield they don't show up on my display page. This is logical because newlines are not br codes. So i must replace the newline thingies with br code. Should this be done BEFORE i put the text in the database or AFTER i put the text in the database and what functions can i use Maybe it's a newbie question but it's on my mind for a few days now and i haven't found an answer yet, thanx! -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] two inserts at once?
If you are using MySQL, you can't.
(none of my business, but why not simplifying your table names: faqProduct
instead of faqRelatedToProduct ?)
Ignatius
- Original Message -
From: Michael Knauf/Niles [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Thursday, January 09, 2003 6:04 PM
Subject: [PHP-DB] two inserts at once?
This Code Snippet works:
$newfaq_query = INSERT INTO `faq` (`faqid`, `question`, `answer`) VALUES
('', '$question', '$answer');
$newfeaturesResult = mysql_query($newfeatures_query);
But I'd like to combine that query with this one:
INSERT INTO `faqRelatedToProduct` (`id`, `fgNumber`, `faqId`) VALUES ('',
'$fgNumber', '$faqid');
So that both are executed at the same time.
The variables $question, $answer, $fgNumber come from a form, the faqid is
a auto increment field, as is id... but it seems I need to know the value
of faqid to relate it correctly to the fgNumber...
Is there a way to combine the two queries?
Michael
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[PHP-DB] preventing page from resubmitting when refreshing page
I have a page that has a form on the first part that posts to itself and
dumps the contents of the form into a database.
All this is well and good - I'm using
if ($_POST['submit']) {
}
to detect the submission and everything is doing as it should.
Thing is if you refresh the page that displays the results it then posts to
the database again. I've tried some error trapping but in the same way the
page hold the post variables it just redoes what it has done rather than re
running the script.
Is there something i can do on browser refresh to prevent this or prevent my
mysql database from duplicating the records?
any help would be appreciated.
cheers
mikek
--
Mike Karthauser
Managing Director - Brightstorm Ltd
Email[EMAIL PROTECTED]
Web http://www.brightstorm.co.uk
Tel 0117 9426653 (office)
07939 252144 (mobile)
SnailmailUnit 8, 14 King Square,
Bristol BS2 8JJ
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RE: [PHP-DB] [mysql - php] Newline to BR problem
You want to look at nl2br() function. It takes newlines from a text like: Hello My name is Aaron Which when outputted normally would look like: Hello my name is aaron Using echo nl2br($dbquery); would produce: Hellobrbr My name isbrbr Aaronbrbr In your HTML code which then would output in a browse like the above. Aaron -Original Message- From: Ro Stonemountain [mailto:[EMAIL PROTECTED]] Sent: January 9, 2003 10:53 AM To: [EMAIL PROTECTED] Subject: [PHP-DB] [mysql - php] Newline to BR problem I'm trying to place a text from a textfield into a database and displaying it on another page. All works fine and well but my problem is: If i place newline characters (press enter) in the forms textfield they don't show up on my display page. This is logical because newlines are not br codes. So i must replace the newline thingies with br code. Should this be done BEFORE i put the text in the database or AFTER i put the text in the database and what functions can i use Maybe it's a newbie question but it's on my mind for a few days now and i haven't found an answer yet, thanx! -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] preventing page from resubmitting when refreshing page
I use logic like this to avoid this problem:
Submit data from form to a separate PHP script that handles the database
submission then forwards to a results page which queries the database for
the information from an ID passed along with the page forward.
If you do this, when you refresh the results page, the only thing that gets
performed is the SELECT since the INSERT/UPDATE logic is in a separate
script.
There may be other ways, but that's what I do. Hope this helps.
Rich
-Original Message-
From: mike karthauser [mailto:[EMAIL PROTECTED]]
Sent: Thursday, January 09, 2003 12:24 PM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] preventing page from resubmitting when
refreshing page
I have a page that has a form on the first part that posts to
itself and
dumps the contents of the form into a database.
All this is well and good - I'm using
if ($_POST['submit']) {
}
to detect the submission and everything is doing as it should.
Thing is if you refresh the page that displays the results it
then posts to
the database again. I've tried some error trapping but in the
same way the
page hold the post variables it just redoes what it has done
rather than re
running the script.
Is there something i can do on browser refresh to prevent
this or prevent my
mysql database from duplicating the records?
any help would be appreciated.
cheers
mikek
--
Mike Karthauser
Managing Director - Brightstorm Ltd
Email[EMAIL PROTECTED]
Web http://www.brightstorm.co.uk
Tel 0117 9426653 (office)
07939 252144 (mobile)
SnailmailUnit 8, 14 King Square,
Bristol BS2 8JJ
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Re: [PHP-DB] preventing page from resubmitting when refreshing page
Is there something i can do on browser refresh to prevent this or prevent my mysql database from duplicating the records? Instead of using INSERT in your query use REPLACE INTO. Alternately, after you are done processing the form, do this: header( location: $PHP_SELF?$QUERY_STRING ); exit() So the page will redirect to itself and it'll be like you went to it the first time. These are just two of I'm sure the many other options what will come through. Chris -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Authenticating through a php script
Jeremy,
LDAP authentication happens in two stages: connect and bind. The connect
stage is just establishing a connection with the LDAP server
(ldap_connect()). No username or password is necesary in this stage.
Once your connection is established, you attempt a bind (ldap_bind())to
verify a username/password on the LDAP server. Here's some PHP code that
will do it or you:
?php
$ldap_server = example.com; // change to your LDAP server host name
$ldap_port = 389; // might be different for your server
$pw = yourpassword; // change to your password
$dn = cn=dave,ou=people,dc=example,dc=com; // change to the dn you want to
authenticate
$connect_result = ldap_connect( $ldap_server, $ldap_port );
// Did we connect?
if( ! $connect_result )
{
echo Could not connect to '$server_name' on port '$server_port';
}
$bind_result = ldap_bind( $connect_result, $admin_dn, $admin_pw );
// Did we bind?
if( ! $bind_result )
{
echo Bad username/password;
}
else
{
echo Correct username/password!;
}
?
Here's some good documentation on the topic:
http://www.php.net/manual/en/ref.ldap.php
Let us know how it goes.
--Dave
On Thu, 2003-01-09 at 10:01, Jeremy Peterson wrote:
I am working on a script that will authenticate on a central system my
company has devised for us to use (LDAP) and then authenticate them to
other sites that I want them to access (Online Databases and other
electronic resources I do not control but pay lots of money for all
students to access).
I have seen this done on a product produced by Epixtech called RPA
(Remote Patron Authentication). This is an authentication system that
avoids using a proxy server. It basically handles the authentication
(LDAP) and sends the appropriate information to the other secure
source (Online Database, Electronic Resources, or my online catalog's
patron information.) Typically there are multiple ways it will
authenticate for the user to other resources. URL referer, ip
authentication, fill in an user/password form for the user. I just
can't get the user/password portion to work on a protected site. My tests
of sending post information to another one of my scripts works fine. But
it doesn't work as of yet.
I have worked a bit with scripts that send post information through
sendToHost function (fsockopen and fputs). But nothing is really
working here. Does anyone know how I should go about this? All
suggestions will be great!
Thanks a bunch,
Jeremy
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[PHP-DB] If select query doesn't net any results
I am a programming novice and just created my first php application. However I have a
situation I
don't know the answer to.
My db queries (mysql) are written like this:
$qtrans= select * from $table where (conditionals) order by some field;
$link=mysql_connect ($host, $user, $password);
$result=mysql_db_query($dbname, $qtrans, $link);
while ($row = mysql_fetch_array($result)) {
do stuff with the array here
}
I would like to created an if statement that only occurs if the query gets a result.
If there are
no records that meet the query conditionals and my array ends up with null, I do not
want my if
statement to take place.
Is this easy enough to do? Any help would be great.
Thank you,
Michael Cortes
Fort LeBoeuf School District
34 East 9th Street
PO Box 810
Waterford PA 16411-0810
814.796.4795
Fax1 814.796.3358
Fax2 978-389-1258
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RE: [PHP-DB] If select query doesn't net any results
if (mysql_num_rows($result) 1) {
//do stuff
}
This is only this easy with mySQL... :-)
Ryan
-Original Message-
From: Michael Cortes [mailto:[EMAIL PROTECTED]]
Sent: Thursday, January 09, 2003 11:07 AM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] If select query doesn't net any results
I am a programming novice and just created my first php application. However I have a
situation I
don't know the answer to.
My db queries (mysql) are written like this:
$qtrans= select * from $table where (conditionals) order by some field;
$link=mysql_connect ($host, $user, $password);
$result=mysql_db_query($dbname, $qtrans, $link);
while ($row = mysql_fetch_array($result)) {
do stuff with the array here
}
I would like to created an if statement that only occurs if the query gets a result.
If there are
no records that meet the query conditionals and my array ends up with null, I do not
want my if
statement to take place.
Is this easy enough to do? Any help would be great.
Thank you,
Michael Cortes
Fort LeBoeuf School District
34 East 9th Street
PO Box 810
Waterford PA 16411-0810
814.796.4795
Fax1 814.796.3358
Fax2 978-389-1258
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Re: [PHP-DB] If select query doesn't net any results
I would like to created an if statement that only occurs if the query gets a result.
If there are
no records that meet the query conditionals and my array ends up with null, I do not
want my if
statement to take place.
Is this easy enough to do? Any help would be great.
if( mysql_num_rows( $result ) 0 ) {
// Records were returned
// Do something here
//
}
Chris
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Re: [PHP-DB] two inserts at once?
On Friday 10 January 2003 01:04, Michael Knauf/Niles wrote:
This Code Snippet works:
$newfaq_query = INSERT INTO `faq` (`faqid`, `question`, `answer`) VALUES
('', '$question', '$answer');
$newfeaturesResult = mysql_query($newfeatures_query);
But I'd like to combine that query with this one:
INSERT INTO `faqRelatedToProduct` (`id`, `fgNumber`, `faqId`) VALUES ('',
'$fgNumber', '$faqid');
So that both are executed at the same time.
The current php-mysql interface only allows single queries at a time.
The variables $question, $answer, $fgNumber come from a form, the faqid is
a auto increment field, as is id... but it seems I need to know the value
of faqid to relate it correctly to the fgNumber...
The retrieve faqid use mysql_insert_id().
--
Jason Wong - Gremlins Associates - www.gremlins.biz
Open Source Software Systems Integrators
* Web Design Hosting * Internet Intranet Applications Development *
/*
The more you sweat in peace, the less you bleed in war.
*/
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Re: [PHP-DB] LEFT JOIN not working
Oops! I missed again. If you specify conditions pertaining to the right-hand table, such as: ads_clickrate.date = '2001', Then you will lose all result rows for which the right-hand data is NULL. Not the expected result. So your restricting WHERE clauses must apply to the left-hand table only. Therefore: WHERE YEAR(ads_displayrate.date) = '2003' AND MONTH(ads_displayrate.date) = '01' (if your table ads_displayrate has such date fields). HTH Ignatius - Original Message - From: Lisi [EMAIL PROTECTED] To: Ignatius Reilly [EMAIL PROTECTED] Sent: Thursday, January 09, 2003 6:54 PM Subject: Re: [PHP-DB] LEFT JOIN not working Cool! It's mostly working now, the only problem is it's ignoring the other clauses in the ON clause that select the desired date. Perhaps it's not supposed to be connected this way? How would I select specific dates? Thanks again, -Lisi At 01:20 PM 1/9/03 +0100, you wrote: Oops! Sorry, I missed it the first time. Your query should start as: SELECT ads_displayrate.name instead of SELECT ads_clickrate.name then you will always have a non-NULL name (coming from the table on the left of the LEFT JOIN). HTH Ignatius, from Brussels Where the fuck is Belgium? D. Ivester, CEO, Coca Cola - Original Message - From: Lisi [EMAIL PROTECTED] To: Ignatius Reilly [EMAIL PROTECTED]; PHP-DB [EMAIL PROTECTED] Sent: Thursday, January 09, 2003 1:11 PM Subject: Re: [PHP-DB] LEFT JOIN not working Exactly my question - why does it not have a name? How would I modify my query to get a row with a name but null value for date? I thought the join would take care of this, but I'm obviously not doing it right. You mention a unique identifier, there is a separate table with a row for each ad, containing name, URL, and a unique ID number (autoincrement). Should this table be included somehow in the query? How would this help? Thanks, -Lisi At 12:45 PM 1/9/03 +0100, Ignatius Reilly wrote: Your 4th row ought to have an identifier of some sort. From your SELECT statement, this seems to be the name. Why does it not have a name? Probably what you want is a row with a name but a NULL value for ads_clickrate.date. (by the way it is EXTREMELY advisable to use an abstract identifier, such as an id, unique and required, instead of name) Ignatius - Original Message - From: Lisi [EMAIL PROTECTED] To: Ignatius Reilly [EMAIL PROTECTED]; PHP-DB [EMAIL PROTECTED] Sent: Thursday, January 09, 2003 12:18 PM Subject: Re: [PHP-DB] LEFT JOIN not working OK, this helped a bit. Now I have, in addition to the three rows of ads that have ben clicked on, a fourth row with no ad name, 0 clickthroughs, and 24 displays. That plus the other three account for all the displayed ads. However, since it is returning a null value for any ad name that has not been clicked on, and then it's grouped by ad name, it lumps all non-clicked ads into one row. What I need is to see each ad on a separate row, which is what I thought a LEFT JOIN was supposed to do. Any suggestions? Thanks, -Lisi At 11:07 AM 1/9/03 +0100, Ignatius Reilly wrote: problem 1: move the WHERE clauses to the ON clauses problem 2: Obviously your intent with COUNT(ads_clickrate.date) is to count the number of non-null occurences of click. But COUNT() is not the appropriate function to do this (it will simply give you the number of rows inside a group). Try replacing COUNT(ads_clickrate.date) by SUM( IF( ads_clickrate.date IS NULL, 0, 1 ) ) HTH Ignatius - Original Message - From: Lisi [EMAIL PROTECTED] To: PHP-DB [EMAIL PROTECTED] Sent: Thursday, January 09, 2003 10:44 AM Subject: [PHP-DB] LEFT JOIN not working I have a page with many ads that stores both the number of times an ad is displayed and how many times it gets clicked. These are stored in two different tables (since different information is stored for each) but both have identical name columns. I am trying to display both # times displayed and # times clicked in the same table in an admin page. Here is my query: SELECT ads_clickrate.name, ads_clickrate.link, SUM(ads_displayrate.count) as display, COUNT(ads_clickrate.date) as click FROM ads_displayrate LEFT JOIN ads_clickrate ON ads_displayrate.name = ads_clickrate.name WHERE YEAR(ads_clickrate.date) = '2003' AND MONTH(ads_clickrate.date) = '01' GROUP BY ads_clickrate.name ORDER BY ads_clickrate.name
Re: [PHP-DB] Authenticating through a php script
David,
I have ldap working, my problem is the second half of my question.
The problem script workflow:
1. Authenticate on LDAP (Resolved)
2. Connect to different authenticated site for the user (Not sure where to
go now.)
My guess was to send the post information to where the form action points
to. Having done this, all I get is a blank page. I guess if PHP sends
the post information then the client will be out of the authentication
loop. There must be a better way. But I don't think I have enough
information to know how to proceed.
Somehow I have to get the browser to send the http post rather than
PHP. Is this possible.
Jeremy
P.S.
The script I am using right now incorporates Chris Alsop's class:
!-- CLASS START --
?php
## Archive:c_http.class
## Description:Basic http class functions (only post right now)
## Author: Chris Alsop - [EMAIL PROTECTED] (rumblefiz)
## Property Of:Everyone
## Date Created: 07/01/2001
## Mod History:07/01/2001 Chris Alsop - Initial Coding
##
==
class c_http {
## DECLARE CLASS VARIABLES
var $QUERY_STRING;
var $TARGET_DOMAIN;
var $TARGET_FILE;
var $RESPONSE;
## END CLASS VARIABLE DECLARATION -
## FUNCTION: c_http()
## ARGS: $psQueryString : String
## $psTargetDomain : String
## $psTargetFile : String
##
function c_http($psQueryString,
$psTargetDomain,$psTargetFile) {
$this-QUERY_STRING = $psQueryString;
$this-TARGET_DOMAIN = $psTargetDomain;
$this-TARGET_FILE = $psTargetFile;
}
## END FUNCTION: c_http() *
## FUNCTION: post()
## ARGS: None
## RETURNS: Boolean
##
function post() {
$qs = $this-QUERY_STRING;
$domain = $this-TARGET_DOMAIN;
$thefile = $this-TARGET_FILE;
if(!$fp = fsockopen($domain,80)) {
print Socket not openbr;
return false;
exit();
}
$postData = POST http://$domain/$thefile HTTP/1.0\r\n;
$postData .= Content-type:
application/x-www-form-urlencoded\r\n;
$postData .= Content-length: .strlen($qs).\r\n\r\n;
$postData .= $qs;
if(!fputs($fp,$postData)) {
return false;
exit();
}
$data = ;
while(!feof($fp)) $data .= fgets($fp,32000);
$pos = 0;
for($i=0; $i2000; $i++) {
if(strtoupper(substr($data,$i,4)) == \r\n\r\n) {
$pos = $i+4; $i = 2000;
}
}
$data = substr($data,$pos);
$base = base href ;
$base = $base . =;
$base = $base . 'http://$domain/' ;
$base = $base . ;
if (eregi(body,$data)) {
$data = eregi_replace(body,$base.BODY,$data);
} else {
$data = $base . $data;
}
$this-RESPONSE = $data;
fclose($fp);
return true;
}
## END FUNCTION: post() ***
}
?
!-- CLASS END --
!-- Test Script --
?php
/*Form information I am trying to send to- example only
form name=MyForm action=login.php method=post
Please log into MyMBI
ID INPUT TYPE=text NAME=meuser SIZE=15
PasswordINPUT TYPE=password NAME=password SIZE=15
INPUT TYPE=submit VALUE=Sign inBR
/FORM
*/
//setting up the varibles
// print hi test 1p;
$post_info = meuser=***password=**;
$oHttp = new c_http($post_info,my.mbinet.net,/login.php);
if(!$oHttp-post()) {
echo error;
}
echo $oHttp-RESPONSE;
// first arg is the query string you want to post. it must be urlencoded.
if you want the current querystring you can use $QUERY_STRING. the second
arg is the domain and the third is the file (or script) that is getting
posted to.
?
At 10:28 AM 1/9/2003 -0700, David Smith wrote:
Jeremy,
LDAP authentication happens in two stages: connect and bind. The connect
stage is just establishing a connection with the LDAP server
(ldap_connect()). No username or password is necesary in this stage.
Once your connection is established, you attempt a bind (ldap_bind())to
verify a username/password on the LDAP server. Here's some PHP code that
will do it or you:
?php
$ldap_server = example.com; // change to your LDAP server host name
$ldap_port = 389; // might be different for your server
$pw = yourpassword; // change to your password
$dn =
[PHP-DB] Stumped...
I am getting an error that is proving very difficult to isolate and was hoping for help. The error is: Column count doesn't match value count at row 1. I would include the code, but it is about 350 lines, and I am not sure where to narrow it down at. Any ideas? Thanks. Scott Nipp Phone: (214) 858-1289 E-mail: [EMAIL PROTECTED] Web: http:\\ldsa.sbcld.sbc.com -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Stumped...
Post your SQL statement. -Original Message- From: NIPP, SCOTT V (SBCSI) [mailto:[EMAIL PROTECTED]] Sent: Thursday, January 09, 2003 1:37 PM To: '[EMAIL PROTECTED]' Subject: [PHP-DB] Stumped... I am getting an error that is proving very difficult to isolate and was hoping for help. The error is: Column count doesn't match value count at row 1. I would include the code, but it is about 350 lines, and I am not sure where to narrow it down at. Any ideas? Thanks. Scott Nipp Phone: (214) 858-1289 E-mail: [EMAIL PROTECTED] Web: http:\\ldsa.sbcld.sbc.com -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Stumped...
it sounds like you are doing an INSERT and the table has fewer columns then the VALUES clause has. Check your code for an INSERT statement then match your values up with the table structure, check for hidden commas in your value information. Jim ---Original Message--- From: NIPP, SCOTT V (SBCSI) Date: Thursday, January 09, 2003 10:41:21 AM To: '[EMAIL PROTECTED]' Subject: [PHP-DB] Stumped... I am getting an error that is proving very difficult to isolate and was hoping for help. The error is: Column count doesn't match value count at row 1. I would include the code, but it is about 350 lines, and I am not sure where to narrow it down at. Any ideas? Thanks. Scott Nipp Phone: (214) 858-1289 E-mail: [EMAIL PROTECTED] Web: http:\\ldsa.sbcld.sbc.com -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php .
RE: [PHP-DB] Stumped...
Nevermind. I just stumbled across the nature of my problem on Deja.com. Thanks anyway and sorry for bugging you guys about what really was a simple problem. -Original Message- From: Hutchins, Richard [mailto:[EMAIL PROTECTED]] Sent: Thursday, January 09, 2003 12:36 PM To: NIPP, SCOTT V (SBCSI); '[EMAIL PROTECTED]' Subject: RE: [PHP-DB] Stumped... Post your SQL statement. -Original Message- From: NIPP, SCOTT V (SBCSI) [mailto:[EMAIL PROTECTED]] Sent: Thursday, January 09, 2003 1:37 PM To: '[EMAIL PROTECTED]' Subject: [PHP-DB] Stumped... I am getting an error that is proving very difficult to isolate and was hoping for help. The error is: Column count doesn't match value count at row 1. I would include the code, but it is about 350 lines, and I am not sure where to narrow it down at. Any ideas? Thanks. Scott Nipp Phone: (214) 858-1289 E-mail: [EMAIL PROTECTED] Web: http:\\ldsa.sbcld.sbc.com -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] If select query doesn't net any results
...
if ($result) {
while ($row...
...
}
$result will be 0 (false) if nothing satisfies the query. Any other
comparison is just extra typing with no improvement in logic.
Regards,
Doug
On Thu, 09 Jan 2003 13:06:51 -0500, Michael Cortes wrote:
I am a programming novice and just created my first php application. However I have
a situation I
don't know the answer to.
My db queries (mysql) are written like this:
$qtrans= select * from $table where (conditionals) order by some field;
$link=mysql_connect ($host, $user, $password);
$result=mysql_db_query($dbname, $qtrans, $link);
while ($row = mysql_fetch_array($result)) {
do stuff with the array here
}
I would like to created an if statement that only occurs if the query gets a result.
If there are
no records that meet the query conditionals and my array ends up with null, I do not
want my if
statement to take place.
Is this easy enough to do? Any help would be great.
Thank you,
Michael Cortes
Fort LeBoeuf School District
34 East 9th Street
PO Box 810
Waterford PA 16411-0810
814.796.4795
Fax1 814.796.3358
Fax2 978-389-1258
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Re: [PHP-DB] two inserts at once?
Well what do ya know, this works! Thanks for the pointer.
if ($tableid==newfaq) {
echo adding FAQBR;
$newfaq_query = INSERT INTO `faq` (`faqid`, `question`, `answer`)
VALUES ('', '$question', '$answer');
$newfaqResult = mysql_query($newfaq_query);
$newfaq_query2 = INSERT into `faqRelatedToProduct` (`id`,
`fgNumber`, `faqid`) VALUES ('', '$fgNumber', last_insert_id() );
$newfaqResult2 = mysql_query($newfaq_query2);
echo $newfaq_query.BR.$newfaq_query2;
}
Michael
Jason Wong
php-db@gremlins.To: [EMAIL PROTECTED]
biz cc:
Subject: Re: [PHP-DB] two inserts at
once?
01/09/03 01:08 PM
Please respond to
php-db
On Friday 10 January 2003 01:04, Michael Knauf/Niles wrote:
This Code Snippet works:
$newfaq_query = INSERT INTO `faq` (`faqid`, `question`, `answer`)
VALUES
('', '$question', '$answer');
$newfeaturesResult = mysql_query($newfeatures_query);
But I'd like to combine that query with this one:
INSERT INTO `faqRelatedToProduct` (`id`, `fgNumber`, `faqId`) VALUES ('',
'$fgNumber', '$faqid');
So that both are executed at the same time.
The current php-mysql interface only allows single queries at a time.
The variables $question, $answer, $fgNumber come from a form, the faqid
is
a auto increment field, as is id... but it seems I need to know the value
of faqid to relate it correctly to the fgNumber...
The retrieve faqid use mysql_insert_id().
--
Jason Wong - Gremlins Associates - www.gremlins.biz
Open Source Software Systems Integrators
* Web Design Hosting * Internet Intranet Applications Development *
/*
The more you sweat in peace, the less you bleed in war.
*/
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Niles Audio Corporation
This mail is confidential
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Re: [PHP-DB] Authenticating through a php script
I haven't looked over all your code in detail, but the problem you
describe seems to be best solved using PHP Sessions. Sessions store data
between browser refreshes. You could store whether a user has been
authenticated via LDAP, and then on a subsequent page, you can reference
that information to determine how to proceed.
Here's the doc: http://www.php.net/manual/en/ref.session.php
--Dave
On Thu, 2003-01-09 at 11:29, Jeremy Peterson wrote:
David,
I have ldap working, my problem is the second half of my question.
The problem script workflow:
1. Authenticate on LDAP (Resolved)
2. Connect to different authenticated site for the user (Not sure where to
go now.)
My guess was to send the post information to where the form action points
to. Having done this, all I get is a blank page. I guess if PHP sends
the post information then the client will be out of the authentication
loop. There must be a better way. But I don't think I have enough
information to know how to proceed.
Somehow I have to get the browser to send the http post rather than
PHP. Is this possible.
Jeremy
P.S.
The script I am using right now incorporates Chris Alsop's class:
!-- CLASS START --
?php
## Archive:c_http.class
## Description:Basic http class functions (only post right now)
## Author: Chris Alsop - [EMAIL PROTECTED] (rumblefiz)
## Property Of:Everyone
## Date Created: 07/01/2001
## Mod History:07/01/2001 Chris Alsop - Initial Coding
##
==
class c_http {
## DECLARE CLASS VARIABLES
var $QUERY_STRING;
var $TARGET_DOMAIN;
var $TARGET_FILE;
var $RESPONSE;
## END CLASS VARIABLE DECLARATION -
## FUNCTION: c_http()
## ARGS: $psQueryString : String
## $psTargetDomain : String
## $psTargetFile : String
##
function c_http($psQueryString,
$psTargetDomain,$psTargetFile) {
$this-QUERY_STRING = $psQueryString;
$this-TARGET_DOMAIN = $psTargetDomain;
$this-TARGET_FILE = $psTargetFile;
}
## END FUNCTION: c_http() *
## FUNCTION: post()
## ARGS: None
## RETURNS: Boolean
##
function post() {
$qs = $this-QUERY_STRING;
$domain = $this-TARGET_DOMAIN;
$thefile = $this-TARGET_FILE;
if(!$fp = fsockopen($domain,80)) {
print Socket not openbr;
return false;
exit();
}
$postData = POST http://$domain/$thefile HTTP/1.0\r\n;
$postData .= Content-type:
application/x-www-form-urlencoded\r\n;
$postData .= Content-length: .strlen($qs).\r\n\r\n;
$postData .= $qs;
if(!fputs($fp,$postData)) {
return false;
exit();
}
$data = ;
while(!feof($fp)) $data .= fgets($fp,32000);
$pos = 0;
for($i=0; $i2000; $i++) {
if(strtoupper(substr($data,$i,4)) == \r\n\r\n) {
$pos = $i+4; $i = 2000;
}
}
$data = substr($data,$pos);
$base = base href ;
$base = $base . =;
$base = $base . 'http://$domain/' ;
$base = $base . ;
if (eregi(body,$data)) {
$data = eregi_replace(body,$base.BODY,$data);
} else {
$data = $base . $data;
}
$this-RESPONSE = $data;
fclose($fp);
return true;
}
## END FUNCTION: post() ***
}
?
!-- CLASS END --
!-- Test Script --
?php
/*Form information I am trying to send to- example only
form name=MyForm action=login.php method=post
Please log into MyMBI
ID INPUT TYPE=text NAME=meuser SIZE=15
PasswordINPUT TYPE=password NAME=password SIZE=15
INPUT TYPE=submit VALUE=Sign inBR
/FORM
*/
//setting up the varibles
// print hi test 1p;
$post_info = meuser=***password=**;
$oHttp = new c_http($post_info,my.mbinet.net,/login.php);
if(!$oHttp-post()) {
echo error;
}
echo $oHttp-RESPONSE;
// first arg is the query string you want to post. it must be urlencoded.
if you want the current querystring you can use $QUERY_STRING. the second
arg is the domain and the third is the file (or script) that
[PHP-DB] which DBMS... MySQL or PostgreSQL
I want to start my Open-Source Project.. PHP-Based RPG Webgame in the next 2 months.. Till now, I still confuse in choosing 2 DBMS. MySQL and PostgreSQL. In your opinions, which DB should I use in consider that my Game will content a very big database including Player data, player Stats, Story and Scenario Database , etc. which one that easy to access, fast, and could maintain the sql file in small size.. and easy to backup Thanks for your advise. #Please join Open Community Forum... http://openity.tk #We're free to discuss anything, you're free to create your own topic in your own language. :D ---DuFronte--- http://kapsul.org No Fuckin' Shits !!
Re: [PHP-DB] which DBMS... MySQL or PostgreSQL
On Friday 10 January 2003 03:48, dufronte wrote: I want to start my Open-Source Project.. PHP-Based RPG Webgame in the next 2 months.. Till now, I still confuse in choosing 2 DBMS. MySQL and PostgreSQL. In your opinions, which DB should I use in consider that my Game will content a very big database including Player data, player Stats, Story and Scenario Database , etc. which one that easy to access, fast, and could maintain the sql file in small size.. and easy to backup This question has recently been asked and answered -- search the archives (both php-db and php-general). Also google MySQL vs PostgreSQL should be helpful. -- Jason Wong - Gremlins Associates - www.gremlins.biz Open Source Software Systems Integrators * Web Design Hosting * Internet Intranet Applications Development * /* It is better to wear out than to rust out. */ -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] which DBMS... MySQL or PostgreSQL
Oh yeah.. I see... thx for the info... #Please join Open Community Forum... http://openity.tk #We're free to discuss anything ---DuFronte--- http://kapsul.org No Fuckin' Shits !! -Original Message- From: Jason Wong [mailto:[EMAIL PROTECTED]] Sent: Friday, January 10, 2003 2:56 AM To: [EMAIL PROTECTED] Subject: Re: [PHP-DB] which DBMS... MySQL or PostgreSQL On Friday 10 January 2003 03:48, dufronte wrote: I want to start my Open-Source Project.. PHP-Based RPG Webgame in the next 2 months.. Till now, I still confuse in choosing 2 DBMS. MySQL and PostgreSQL. In your opinions, which DB should I use in consider that my Game will content a very big database including Player data, player Stats, Story and Scenario Database , etc. which one that easy to access, fast, and could maintain the sql file in small size.. and easy to backup This question has recently been asked and answered -- search the archives (both php-db and php-general). Also google MySQL vs PostgreSQL should be helpful. -- Jason Wong - Gremlins Associates - www.gremlins.biz Open Source Software Systems Integrators * Web Design Hosting * Internet Intranet Applications Development * /* It is better to wear out than to rust out. */ -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] which DBMS... MySQL or PostgreSQL
Hmm.. so it means that I should choose PG ??? #Please join Open Community Forum... http://openity.tk #We're free to discuss anything ---DuFronte--- http://kapsul.org No Fuckin' Shits !! -Original Message- From: Jason Wong [mailto:[EMAIL PROTECTED]] Sent: Friday, January 10, 2003 2:56 AM To: [EMAIL PROTECTED] Subject: Re: [PHP-DB] which DBMS... MySQL or PostgreSQL On Friday 10 January 2003 03:48, dufronte wrote: I want to start my Open-Source Project.. PHP-Based RPG Webgame in the next 2 months.. Till now, I still confuse in choosing 2 DBMS. MySQL and PostgreSQL. In your opinions, which DB should I use in consider that my Game will content a very big database including Player data, player Stats, Story and Scenario Database , etc. which one that easy to access, fast, and could maintain the sql file in small size.. and easy to backup This question has recently been asked and answered -- search the archives (both php-db and php-general). Also google MySQL vs PostgreSQL should be helpful. -- Jason Wong - Gremlins Associates - www.gremlins.biz Open Source Software Systems Integrators * Web Design Hosting * Internet Intranet Applications Development * /* It is better to wear out than to rust out. */ -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] which DBMS... MySQL or PostgreSQL
Hmm.. so it means that I should choose PG ??? That's not something we can answer as it very much depends on your needs. Look at the features that PG has v. the features that MySQL has and decide based on that. If you don't need the functionality PG offers that MySQL doesn't, go with MySQL as it's faster and easier to learn. Otherwise go with PG. Chris -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] OR on multiple columns
Jason Wong wrote: On Thursday 09 January 2003 08:36, David Chamberlin wrote: I was reading the mysql docs and noticed a section on searching on multiple keys (stupid question - keys=columns?). It says doing an OR on multiple keys is inefficient, and you should use a temp table. Here's their example: CREATE TEMPORARY TABLE tmp SELECT field1_index, field2_index FROM test_table WHERE field1_index = '1'; INSERT INTO tmp SELECT field1_index, field2_index FROM test_table WHERE field2_index = '1'; SELECT * from tmp; DROP TABLE tmp; My question is, is there a point at which this temp table is less efficient? That may depend upon your particular circumstances, and hence running your own tests on both methods would give you the best answer. OK, so what's the best way to go about profiling this? Everything runs on my ISP's server. Thanks, Dave -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] If select query doesn't net any results
...
if ($result) {
while ($row...
...
}
$result will be 0 (false) if nothing satisfies the query. Any other
comparison is just extra typing with no improvement in logic.
No, it only returns false/0 if the query fails, meaning there was an
error and the query couldn't be executed. The query can execute just
fine, return no rows, and so the result would be true.
What you have is extra typing with no improvement in logic. ;)
If you need to know the number of rows returned, then use the
if(mysql_num_rows() method. If you don't, then you can do this:
if($row = mysql_fetch_row($result))
{
do{
//do whatever with $row data
}while($row = mysql_fetch_row($result));
}
else
{ echo no rows returned from query; }
If you simply do not want something done if no rows are returned, then
the simple while($row = mysql_fetch_row($result)) method works fine, as
the while() will only be true if rows were returned and skipped if no
rows are returned.
---John W. Holmes...
PHP Architect - A monthly magazine for PHP Professionals. Get your copy
today. http://www.phparch.com/
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[PHP-DB] Design suggestions - performance improvement
Hi all, I am currently building a site for a cinema to display session times, film synopsis' etc... I have built the database as follows: TABLE: film_detail FilmID FilmName FilmRunTime FilmRating FilmSynopsis etc... TABLE session_data session_ID session_filmID session_StartTime session_Date The session_data table might contain a large number of records with the same film ID, and the same Start Date to cover a large number of sessions that we would have of the same film on the same day. I want to know what is the best way to retrieve this joint info from the DB. currently, I run a single select statement requesting the fields I want from both tables, where the session_Date equals a given date. This returns x number of rows, depending on the number of sessions for all films for that given day. However, this means that I am retrieving the Film Synopsis, cast, runtime etc multiple times... The data will be returned to the user as below: FILM TITLE (rating) session_times--- will list all sessions - such as 8.45am, 10.15am, 12.00pm, 2.00pm etc etc FILM RUNTIME FILM CAST FILM SYNOPSIS is this an effective way to return to he data? or should I be using individual queries? Any comments or suggestions would be most appreciated.. Cheers, M@
Re: [PHP-DB] Authenticating through a php script
Dave,
I am afraid I am not communicating what I am trying to do.
I have multiple databases that my library purchases. FirstSearch,
Ebscohost, etc. These company's have there own authentication systems that
I have no control over. A lot of them give user names and passwords that
can access their secure database; however I will not give out this
information to students. I want to design a system that will log the
students on directly without them ever seeing the log in screen.
A) Does this make sense in what I am trying to do?
B) How can I do it?
Jeremy
At 12:38 PM 1/9/2003 -0700, David Smith wrote:
I haven't looked over all your code in detail, but the problem you
describe seems to be best solved using PHP Sessions. Sessions store data
between browser refreshes. You could store whether a user has been
authenticated via LDAP, and then on a subsequent page, you can reference
that information to determine how to proceed.
Here's the doc: http://www.php.net/manual/en/ref.session.php
--Dave
On Thu, 2003-01-09 at 11:29, Jeremy Peterson wrote:
David,
I have ldap working, my problem is the second half of my question.
The problem script workflow:
1. Authenticate on LDAP (Resolved)
2. Connect to different authenticated site for the user (Not sure
where to
go now.)
My guess was to send the post information to where the form action points
to. Having done this, all I get is a blank page. I guess if PHP sends
the post information then the client will be out of the authentication
loop. There must be a better way. But I don't think I have enough
information to know how to proceed.
Somehow I have to get the browser to send the http post rather than
PHP. Is this possible.
Jeremy
P.S.
The script I am using right now incorporates Chris Alsop's class:
!-- CLASS START --
?php
## Archive:c_http.class
## Description:Basic http class functions (only post right now)
## Author: Chris Alsop - [EMAIL PROTECTED] (rumblefiz)
## Property Of:Everyone
## Date Created: 07/01/2001
## Mod History:07/01/2001 Chris Alsop - Initial Coding
##
==
class c_http {
## DECLARE CLASS VARIABLES
var $QUERY_STRING;
var $TARGET_DOMAIN;
var $TARGET_FILE;
var $RESPONSE;
## END CLASS VARIABLE DECLARATION -
## FUNCTION: c_http()
## ARGS: $psQueryString : String
## $psTargetDomain : String
## $psTargetFile : String
##
function c_http($psQueryString,
$psTargetDomain,$psTargetFile) {
$this-QUERY_STRING = $psQueryString;
$this-TARGET_DOMAIN = $psTargetDomain;
$this-TARGET_FILE = $psTargetFile;
}
## END FUNCTION: c_http() *
## FUNCTION: post()
## ARGS: None
## RETURNS: Boolean
##
function post() {
$qs = $this-QUERY_STRING;
$domain = $this-TARGET_DOMAIN;
$thefile = $this-TARGET_FILE;
if(!$fp = fsockopen($domain,80)) {
print Socket not openbr;
return false;
exit();
}
$postData = POST http://$domain/$thefile HTTP/1.0\r\n;
$postData .= Content-type:
application/x-www-form-urlencoded\r\n;
$postData .= Content-length: .strlen($qs).\r\n\r\n;
$postData .= $qs;
if(!fputs($fp,$postData)) {
return false;
exit();
}
$data = ;
while(!feof($fp)) $data .= fgets($fp,32000);
$pos = 0;
for($i=0; $i2000; $i++) {
if(strtoupper(substr($data,$i,4)) == \r\n\r\n) {
$pos = $i+4; $i = 2000;
}
}
$data = substr($data,$pos);
$base = base href ;
$base = $base . =;
$base = $base . 'http://$domain/' ;
$base = $base . ;
if (eregi(body,$data)) {
$data = eregi_replace(body,$base.BODY,$data);
} else {
$data = $base . $data;
}
$this-RESPONSE = $data;
fclose($fp);
return true;
}
## END FUNCTION: post() ***
}
?
!-- CLASS END --
!-- Test Script --
?php
/*Form information I am trying to send to- example only
form name=MyForm action=login.php method=post
Please log into MyMBI
ID INPUT
[PHP-DB] Examine button
Hello everybody!!! I'm writing to you to ask if somebody knows how can I do to emulate the examine button to retrive a file's path to save that string in the database. Specifically, it's a photo, that've got to search in the directory's window. Thanks in advance! Sabina Alejandra Schneider [EMAIL PROTECTED]
RE: [PHP-DB] Examine button
Hello everybody!!! I'm writing to you to ask if somebody knows how can I do to emulate the examine button to retrive a file's path to save that string in the database. Specifically, it's a photo, that've got to search in the directory's window. Thanks in advance! Yeah, you probably got no response the first time you posted this because no one knows what you're talking about. Well, at least I don't. What does this have to do with PHP? ---John W. Holmes... PHP Architect - A monthly magazine for PHP Professionals. Get your copy today. http://www.phparch.com/ -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] resetting $res from mysql_fetch_row()?
John W. Holmes wrote: any hint on resetting a $res from mysql_fetch_row()? www.php.net/mysql_data_seek Thanks, does help. -- // Donny -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] Relationship or not.
I have a bit of a challenge on and only being a newbie I will need to
call on some experienced PHP'ers.
I have two tables in a databse. Tasks and Files. They relate to each
other via Tasks.ID and Files.FID.
I have successfully created an uploading form which adds images to a
directory and records the files details into the files table. So I can
now display the results If I need to from the files table.
My challenge is this.
I have created a Result set which displays all the Tasks. This
displays through a repeated row and so on.
What I need to do is some sort of an if statement in each task display.
If (there are files.fid that relate to this tasks.ID){
Display results !!! //Calls on some HTML/PHP and attatchs file info to
a generic image to click on.
}
Else {
Display Nothing !!!
}
So to put it simple. I need to display all the tasks (got that) and also
the file info that realtes to each task. I am unsure of how to code this
relational stuff. A bit out of my reach at the moment.
Cheers
Bruce
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RE: [PHP-DB] Relationship or not.
I forgot to mention there will likely be more than the one file that
relates to a task.
-Original Message-
From: Bruce Levick
Sent: Friday, January 10, 2003 2:40 PM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] Relationship or not.
I have a bit of a challenge on and only being a newbie I will need to
call on some experienced PHP'ers.
I have two tables in a databse. Tasks and Files. They relate to each
other via Tasks.ID and Files.FID.
I have successfully created an uploading form which adds images to a
directory and records the files details into the files table. So I can
now display the results If I need to from the files table.
My challenge is this.
I have created a Result set which displays all the Tasks. This
displays through a repeated row and so on.
What I need to do is some sort of an if statement in each task display.
If (there are files.fid that relate to this tasks.ID){
Display results !!! //Calls on some HTML/PHP and attatchs file info to
a generic image to click on. }
Else {
Display Nothing !!!
}
So to put it simple. I need to display all the tasks (got that) and also
the file info that realtes to each task. I am unsure of how to code this
relational stuff. A bit out of my reach at the moment.
Cheers
Bruce
--
PHP Database Mailing List (http://www.php.net/)
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Re: [PHP-DB] OR on multiple columns
On Friday 10 January 2003 06:41, David Chamberlin wrote: That may depend upon your particular circumstances, and hence running your own tests on both methods would give you the best answer. OK, so what's the best way to go about profiling this? Short answer: microtime() Long answer: check the archives, check the usual script sites (www.hotscripts.com, www.zend.com, www.phpclasses.org etc) for timing classes/functions/etc. Everything runs on my ISP's server. That's not an issue. -- Jason Wong - Gremlins Associates - www.gremlins.biz Open Source Software Systems Integrators * Web Design Hosting * Internet Intranet Applications Development * /* Fly me away to the bright side of the moon ... */ -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] denying access to folders/files
Gary Every Sr. UNIX Administrator Ingram Entertainment (615) 287-4876 Pay It Forward mailto:[EMAIL PROTECTED] http://accessingram.com This is fine and dandy, but how do I prevent that person from taking the direct link to the file and giving it to someone else? I'm sure there is a much better and simpler way. Idea's? Answer: Use auto_prepend.php to authenticate the user. Thanks in advance. -- Darren Bentley [EMAIL PROTECTED] -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] denying access to folders/files
Not sure what's the question or the answer below... but anyway. To protect your files, store them outside of the webroot or in the database and use a PHP file to serve them up. The PHP file will check the authentication or whatever of the user and if it's valid, serve up the file to them with a proper header() call and sending the data of the file. ---John W. Holmes... PHP Architect - A monthly magazine for PHP Professionals. Get your copy today. http://www.phparch.com/ -Original Message- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]] Sent: Thursday, January 09, 2003 9:56 AM To: [EMAIL PROTECTED]; [EMAIL PROTECTED] Cc: [EMAIL PROTECTED]; [EMAIL PROTECTED] Subject: RE: [PHP-DB] denying access to folders/files Gary Every Sr. UNIX Administrator Ingram Entertainment (615) 287-4876 Pay It Forward mailto:[EMAIL PROTECTED] http://accessingram.com This is fine and dandy, but how do I prevent that person from taking the direct link to the file and giving it to someone else? I'm sure there is a much better and simpler way. Idea's? Answer: Use auto_prepend.php to authenticate the user. Thanks in advance. -- Darren Bentley [EMAIL PROTECTED] -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
