[PHP] users online
Hi, is this possible-- I need a user (already logged in) to click on a button and his username shown in a text box next to it. This is for a chat and they need to be seated similar to poker game where they sit-in/sit out. Any help apreciated ! -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Starting a big project
I'm about to start writing a big web app (mostly in PHP). But I'm not sure if I should layout the DB first then write the app, or should I just start writing the app and add stuff to the DB as I need it. How do you guys go about it? Thanks, Dan. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Starting a big project
By asking What do I need from the app? or What questions will the app have to answer? or What information does the client want? and going from there. Those are all just about the same question. From there you can determine needed inputs, tables, keys, etc. Cheers - Miles At 01:45 PM 5/1/2005, Danny Brow wrote: I'm about to start writing a big web app (mostly in PHP). But I'm not sure if I should layout the DB first then write the app, or should I just start writing the app and add stuff to the DB as I need it. How do you guys go about it? Thanks, Dan. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Starting a big project
I'm about to start writing a big web app (mostly in PHP). But I'm not sure if I should layout the DB first then write the app, or should I just start writing the app and add stuff to the DB as I need it. How do you guys go about it? Thanks, Dan. Dan, The single-greatest thing you can do if you haven't already is to get some paper, get a pen and sketch it all out. Plan your DB schema now, map out all the parts and get a working flow-chart. Then, work on building your framework/foundation (your DB would fall under here). Get all your db's and tables built and throw in some junk/test data. After that, start in on your code. I've always found that with a working DB (even with just test data), my progress is greater since I see results in real time and won't have to dev, hope it works and then find out when I'm setting up the DB that there's other problems. And all throughout this process keep referring to that flow-chart. Keep revising it and making/taking notes and ensure that it's accurate and concise. While it seems like a lot of overhead, the benefits you get from doing this when working on larger projects is invaluable. You always know how everything works and rarely need to grep countless lines of code looking for comments to figure out how something is working. In short - work from the bottom up and include the DB structure in that. Good luck have fun! -M -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] php5-mysqli
hi how can I ensure that php5-mysqli is correctly loaded? the server is SuSE9.3 and I have installed the package from yast, but one app (phpmyadmin) says it cannot find the mysql extension (although other apps can query the db). which config files are responsible for loading mysqli in apache/php5 ? -- NSK http://portal.wikinerds.org -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Starting a big project
On Sun, 2005-05-01 at 18:53 +0200, Gabriel Birke wrote: You could avoid the decision if you use the O/R mapper propel: http://propel.phpdb.org/wiki/ I'm using Pear DB (via PG). And then I'm going to port to postgresql. I've got most of the tools I'm going to use for the project worked out. Just figuring out what is better, DB layout - Write App, or Write app DB at the same time. Mike sent a real good answer, exactly what I was looking for. Thanks for you reply, I'm going to read up on propel even though I will probably not use it for this project. Thanks, Dan On 5/1/05, Danny Brow [EMAIL PROTECTED] wrote: I'm about to start writing a big web app (mostly in PHP). But I'm not sure if I should layout the DB first then write the app, or should I just start writing the app and add stuff to the DB as I need it. How do you guys go about it? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: Starting a big project
I'm about to start writing a big web app (mostly in PHP). But I'm not sure if I should layout the DB first then write the app, or should I just start writing the app and add stuff to the DB as I need it. How do you guys go about it? You can't predict everything, but if you don't try to develop a very detailed spec, including the table layouts, you will (IMHO) be sorry. -- Sandy Keathley Systems Administrator Lorentz Consulting Group, LLC Dallas, TX -- -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Problem with array
Hi All,
I have 2 function, 1 which calls another, that I am attempting to use in a
page with, currently, some problems.
In essence, I have a hierarchical recordset table called tbl_content (contid
and parid, where parid contains the contid of the record to which the
current record belongs). A record without a parid value indicates that the
record is a project level record. I have another table with messages that
have been attached to records in tbl_content, called tbl_content_messages.
Tbl_content_messages contains a contid field indicating the record from
tbl_content to which each message has been attached.
I'm trying to create a summary page at the project level (ie all records in
tbl_content that do not have a parid value) displaying the number of
messages in each project (ie, attached to any record in tbl_content that is
part of the hierarchy chain underneath the relevant project record).
To do this, for each project I'm trying to determine the list of child
contid values so that I can do a count(*) in tbl_content_messages using the
IN operator, so that only messages attached to records in that project's
hierarchy chain are counted.
To generate that child list in the summary page, I'm using:
?
$leaflist = listProjectChildren($d-contid); // $d-contid
contains the contid of the project being summarised
?
The two functions I'm calling are:
?
function listProjectChildren($contid, $list=''){
if ($contid''){
$arrtree = array();
$arrtree = buildProjectTree($contid, $level=1);
for ($i=0;$i count($arrtree);$i++){
$list .= '{$arrtree[$i][2]}',;
}
}
$list = substr($list, 0,-1);
unset($arrtree);
return $list;
}
function buildProjectTree($contid, $level=1){
if ($contid''){
global $arrtree;
$sql = SELECT contid, parid, title FROM tbl_content
WHERE parid='$contid';
$rs = mysql_query($sql);
while ($d= mysql_fetch_object($rs)){
$ind = count($arrtree);
$arrtree[$ind][0] = $d-title;
$arrtree[$ind][1] = $level;
$arrtree[$ind][2] = $d-contid;
$arrtree[$ind][3] = $d-parid;
buildProjectTree($d-contid, $level+1);
}
mysql_free_result($rs);
}
return $arrtree;
}
?
My problem is that when I'm iterating through all of the project level
records, it appears that the content of $arrtree is never reset. New entries
are simply placed on the end, causing the for. loop that builds the
returned $list variable in listProjectChildren() to progressively return
larger and larger lists of contid values. As you can see, I try to UNSET()
the array prior to returning the $list variable, but this doesn't seem to
help.
Can anyone help me figure out what I'm doing wrong?
Many thanks in advance!
Murray
[PHP] Re: Starting a big project
Hello, on 05/01/2005 01:45 PM Danny Brow said the following: I'm about to start writing a big web app (mostly in PHP). But I'm not sure if I should layout the DB first then write the app, or should I just start writing the app and add stuff to the DB as I need it. How do you guys go about it? If you want to implement a big project you should first make some analysis and plan it before going ahead to the implementation. For big projects, use case partioning is trongly encouraged. If you do not know what that is, I strongly encourage reading this book. It succing and straight to the point to get you started quickly. http://www.phpclasses.org/reviews/id/0201309815.html When you finnaly come to the point of an implementation, I suggest a model driven object oriented approch. This means that instead of hand coding all the tables and SQL by hand, you should design a model of the entities of information of your project and use an object-relational mapping tool so in your application you treat every entity as objects: clients, products, transactions, etc.. Everything is an object, as opposed to sparse data in database. Then let the object relational tool do the tedious job storing and retrieving data from a relational database with SQL. For this purpose, I suggest you use a tool like Metastorage, especially because your project is big. It will let you model your business objects and generates all access code and database schema in seconds. This will be very good for you because it will let you try different models that can be changed and regerated quickly until you figure the right model for your needs and keep changing it later if necessary. http://www.meta-language.net/metastorage.html -- Regards, Manuel Lemos PHP Classes - Free ready to use OOP components written in PHP http://www.phpclasses.org/ PHP Reviews - Reviews of PHP books and other products http://www.phpclasses.org/reviews/ Metastorage - Data object relational mapping layer generator http://www.meta-language.net/metastorage.html -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] php5-mysqli
On 5/1/05, NSK [EMAIL PROTECTED] wrote:
how can I ensure that php5-mysqli is correctly loaded?
if( !in_array( 'mysqli', get_loaded_extensions() ) )
{
if( !dl( 'mysqli.so' ) )
{
echo mysqli.so extension is not loaded;
}
}
the server is SuSE9.3
and I have installed the package from yast, but one app (phpmyadmin) says it
cannot find the mysql extension (although other apps can query the db).
In config.inc.php you might check that you have correctly specified
either mysql or mysqli in the $cfg['Servers'][$i]['extension']
setting.
which config files are responsible for loading mysqli in apache/php5 ?
The mysqli support in my PHP is built in using --with-mysqli during
the configure. You can also load the extension in the php.ini or with
the dl() function.
--
Greg Donald
Zend Certified Engineer
http://destiney.com/
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Re: [PHP] Problem with array
On Sun, May 1, 2005 10:21 am, Murray @ PlanetThoughtful said:
?
function listProjectChildren($contid, $list=''){
if ($contid''){
$arrtree = array();
$arrtree = buildProjectTree($contid, $level=1);
for ($i=0;$i count($arrtree);$i++){
$list .= '{$arrtree[$i][2]}',;
}
}
$list = substr($list, 0,-1);
unset($arrtree);
return $list;
}
The $arrtree in the function above has *NOTHING* to do with the $arrtree
in the function below.
Not connected at all, really.
function buildProjectTree($contid, $level=1){
if ($contid''){
global $arrtree;
//Start with an empty tree every time this function is called:
$arrtree = array();
$sql = SELECT contid, parid, title FROM
tbl_content
WHERE parid='$contid';
$rs = mysql_query($sql);
while ($d= mysql_fetch_object($rs)){
$ind = count($arrtree);
$arrtree[$ind][0] = $d-title;
$arrtree[$ind][1] = $level;
$arrtree[$ind][2] = $d-contid;
$arrtree[$ind][3] = $d-parid;
buildProjectTree($d-contid,
$level+1);
}
mysql_free_result($rs);
}
return $arrtree;
}
?
My problem is that when I'm iterating through all of the project level
records, it appears that the content of $arrtree is never reset. New
entries
are simply placed on the end, causing the for. loop that builds the
returned $list variable in listProjectChildren() to progressively return
larger and larger lists of contid values. As you can see, I try to UNSET()
the array prior to returning the $list variable, but this doesn't seem to
help.
Can anyone help me figure out what I'm doing wrong?
There is *NOTHING* in the code given here that makes it right to have
$arrtree be a GLOBAL variable in your function.
That means you are probably doing that wrong too.
Try it with just the line I added, and no global $arrtree; line.
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Re: [PHP] users online
On Sun, May 1, 2005 1:35 am, Anasta said:
Hi, is this possible--
I need a user (already logged in) to click on a button and his username
shown in a text box next to it.
This is for a chat and they need to be seated similar to poker game where
they sit-in/sit out.
?php echo $name;?
What am I not getting here?...
Maybe you want it to happen on the CLIENT which wouldn't be PHP?...
FORM ACTION=# METHOD=GETINPUT TYPE=SUBMIT VALUE=Who Am I?
onClick=JavaScript:showname('?php echo $name;?'); return true;/FORM
Your showname function in JavaScript will probably have to use the
'innerHtml' value or something like that to alter the text you want to
change. I forget exactly what it is, but this isn't a JavaScript list
anyway.
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[PHP] automatic PHP Template engine
Hi, I'm working on a template engine, and I want my template engine to be automaticly started when a .stl file is called from the browser. I know this can be done with mod_rewrite, but I really need a platform-independant solution. Has anybody some ideas on how to make it work everywhere (preferable also on hosts where you don't have access to configuration/shared hosting). regards, Evert -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Problem with array
Hi Richard, Color me confused. I removed global $arrtree; and added $arrtree = array(); to the function buildProjectTree() and now the parent function (listProjectChildren) returns no values at all. I've checked the page from which listProjectChildren() is being called, and $arrtree does not appear as a variable in it at all, so it seems global $arrtree; was doing SOMETHING, but at this point I have no idea what. Still trying to work this out, if anyone else has any suggestions? Much warmth, Murray -Original Message- From: Richard Lynch [mailto:[EMAIL PROTECTED] Sent: Monday, 2 May 2005 5:04 AM To: Murray @ PlanetThoughtful Cc: php-general@lists.php.net Subject: Re: [PHP] Problem with array On Sun, May 1, 2005 10:21 am, Murray @ PlanetThoughtful said: ? [Here there be snippage: please see original post for outline of problem] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Splitting Vars from MySQL in PHP
On Sat, April 30, 2005 8:16 pm, Rasmus Lerdorf said:
php -a
?php
$foo = array('a'='apple', 'b'='banana', 'c'='coconut');
while (list($k, $v) = each($foo)){
echo $k: $v\n;
}
?
Content-type: text/html
X-Powered-By: PHP/4.3.11
a: apple
b: banana
c: coconut
It has worked just fine with alpha indices since PHP 3.0rc2, at a
minimum,
cuz I've been doing it that long.
I dunno who was smoking what that day they typed the documentation :-)
I'm pretty sure it's not an undocumented feature that it works.
Richard, this is what the docs are talking about:
list($a,$b,$c,$d) = array('a','b','c','d');
echo $a,$b,$c,$d;
vs.
list($a,$b,$c,$d) = array('a'='a','b'='b','c'='c','d'='d');
echo $a,$b,$c,$d;
In your case you are calling each() which itself returns a numerically
indexed array.
I realized how stupid my post was about 30 seconds after sending it.
I plead sleep deprivation :-)
The correct answer, of course, was http://php.net/extract
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RE: [PHP] Problem with array
On Sun, May 1, 2005 1:08 pm, Murray @ PlanetThoughtful said: Color me confused. I removed global $arrtree; and added $arrtree = array(); to the function buildProjectTree() and now the parent function (listProjectChildren) returns no values at all. I've checked the page from which listProjectChildren() is being called, and $arrtree does not appear as a variable in it at all, so it seems global $arrtree; was doing SOMETHING, but at this point I have no idea what. Still trying to work this out, if anyone else has any suggestions? I'm not real clear on what you are trying to do in the first place, but if taking out the global messed up, put it back :-) Maybe add another global $arrtree in the other function so *BOTH* functions are using the same $arrtree? -- Like Music? http://l-i-e.com/artists.htm -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] automatic PHP Template engine
On Sun, May 1, 2005 12:54 pm, Evert | Rooftop Solutions said: I'm working on a template engine, and I want my template engine to be automaticly started when a .stl file is called from the browser. I know this can be done with mod_rewrite, but I really need a platform-independant solution. Has anybody some ideas on how to make it work everywhere (preferable also on hosts where you don't have access to configuration/shared hosting). At one end of the scale, you could write a Module for Apache, *just* like PHP is. At the other end, you could give documentation to users about using httpd.conf and/or .htaccess and Apache's ForceType directive to fire up PHP. Somewhere in the middle, I guess you could create an extension of PHP, just like php_mysql.[so|dll] and that *might* maybe give you the ability to hack enough things, including the installer/configure scripts that would do what you want... Probably not though, now that I think about it. I think the most realistic approach, honestly, is to just educate users/hosts how to easily send all your .stl scripts through PHP. If your .stl becomes even moderately popular, they'll do that, certainly *long* before they'll install your STL module to Apache. If a host won't let the webmaster use .htaccess (or whatever IIS does that's like that) then they're certainly not going to install/configure their server to use your .stl until it's wildly popular. You can't really get around that. Focus on making it the best damn Template system and making it *EASY* for most hosts to configure and QA it. To give you an analogy: In the indepdenent music industry, many artists think they want to get a Distribution deal, where some big-name company will get their music CDs into all the big-name stores like Tower. Nothing could be further from the truth, which is: Demand Drives Distribution It does one absolutely NO GOOD to have your CDs sitting on the shelf at Tower, or even Wal-Mart, if nobody ever heard of the band. The CDs will just collect dust and get shipped back at (ultimately) artist expense. In the case of .stl -- While making it easy to install/configure .stl is a laudable goal, you're simply not in a position to make it something the mass-market ultra-conservative control-panel-only webhosts will allow to be installed, no matter *HOW* easy it is. In fact, you're at the point now where such hosts will actively work to suppress your .stl engine, as an unproven un-tested un-trusted technology. Your effort (for now) needs to focus on the hosts who allow some degree of configuration/control to their clients. If a webmaster (or their host) can't (won't) do this in .htaccess (httpd.conf): Files ~ *.stl ForceType application/x-httpd-php /Files then you need to ignore them for now, until you're an 800-pound gorilla they can't ignore :-) WARNING: I may have the Files ... part wrong... -- Like Music? http://l-i-e.com/artists.htm -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Problem with array
-Original Message- From: Richard Lynch [mailto:[EMAIL PROTECTED] Sent: Monday, 2 May 2005 6:16 AM To: Murray @ PlanetThoughtful Cc: php-general@lists.php.net Subject: RE: [PHP] Problem with array On Sun, May 1, 2005 1:08 pm, Murray @ PlanetThoughtful said: Color me confused. I removed global $arrtree; and added $arrtree = array(); to the function buildProjectTree() and now the parent function (listProjectChildren) returns no values at all. I've checked the page from which listProjectChildren() is being called, and $arrtree does not appear as a variable in it at all, so it seems global $arrtree; was doing SOMETHING, but at this point I have no idea what. Still trying to work this out, if anyone else has any suggestions? I'm not real clear on what you are trying to do in the first place, but if taking out the global messed up, put it back :-) Maybe add another global $arrtree in the other function so *BOTH* functions are using the same $arrtree? (Laugh) It's probably because I'm not explaining myself well... Let me try to outline pseudo recordsets for the 2 tables: Tbl_content: Contid, parid 1, 2,1 3,1 4, 5,4 6,1 7,5 8,2 9,7 Tbl_content_messages: Msgid, contid 1,2 2,2 3,4 4,5 5,5 6,5 7,6 8,6 9,8 10,9 11,9 Okay, so what I'm trying to do is display a summary count of all of the messages in tbl_content_messages for each project in tbl_content (in this case the 2 records with contid of 1 and 4, as they have no parid value). The only way I could think to do this was to create a query that did a SELECT COUNT(*) from tbl_content_messages using the IN operator with a list of all of the contid values associated with each project. For the project associated with contid 1, the entire list of contids in the project would be 1,2,3,6,8. So, my select query for that project should look like: SELECT COUNT(*) FROM tbl_content_messages WHERE contid IN (1,2,3,6,8) Using the association of contid between tbl_content and tbl_content_messages, that should return a total count of 5 messages for the project hierarchy that begins with tbl_content record with contid of 1. Similarly, the next project in tbl_content, with contid of 4, would be summarized by: SELECT COUNT(*) FROM tbl_content_messages WHERE contid IN (4,5,7,9) Again, from the pseudo recordsets above, that should return a message count of 6. So, in the two functions from my original message I'm trying to build the IN list of contid values for each of the projects. In the page that calls the functions, I pull a recordset of all records in tbl_content that have no parid (and thus, by definition, are projects). Using a while loop, I move through the project recordset and for each record in it I have $leaflist = listProjectChildren($contid);. In the example above, for the project contid of 1, I am hoping to return from listProjectChildren() a variable that contains the value '1,2,3,6,8', so that this can be used in a SELECT COUNT(*) query using the IN operator to count all messages that are attached at any level in the project hierarchy underneath contid 1. I know this is probably needlessly convoluted, but I inherited this table structure from another developer and I'm trying to make sense of it in some way. Hope that explains a little better what I'm going on about. Thanks again, Murray -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] empty function and array indices
Hello!
Suppose I have the following code:
$a = array('a'=1, 'b'=2);
echo empty($a['c'])?'empty':'not empty';
echo $a['c'];
Why doesn't the 2nd line output a warning when error_reporting is set
to E_ALL? Is empty() some kind of special function where the validity
of indices is not checked? If that is the case, I have two questions:
1. Will this behavior persist in future versions of PHP?
2. Are there other functions or a general rule where PHP doesn't
output warnings when a nonexistant index is given?
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Re: [PHP] empty function and array indices
Gabriel Birke wrote:
Hello!
Suppose I have the following code:
$a = array('a'=1, 'b'=2);
echo empty($a['c'])?'empty':'not empty';
echo $a['c'];
Why doesn't the 2nd line output a warning when error_reporting is set
to E_ALL? Is empty() some kind of special function where the validity
of indices is not checked? If that is the case, I have two questions:
1. Will this behavior persist in future versions of PHP?
Sure
2. Are there other functions or a general rule where PHP doesn't
output warnings when a nonexistant index is given?
isset() as well for obvious reasons.
-Rasmus
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Re: [PHP] empty function and array indices
From the Manual:
empty() is the opposite of (boolean) var, except that no warning is
generated when the variable is not set
It appears that there is a revamp of what is considered to be empty in PHP
5.
http://php.net/empty
You might be better served with
array_key_exists()
such as:
echo array_key_exists('c', $a)? 'empty':'not empty';
Mark Cain
- Original Message -
From: Gabriel Birke [EMAIL PROTECTED]
To: php-general@lists.php.net
Sent: Sunday, May 01, 2005 4:47 PM
Subject: [PHP] empty function and array indices
Hello!
Suppose I have the following code:
$a = array('a'=1, 'b'=2);
echo empty($a['c'])?'empty':'not empty';
echo $a['c'];
Why doesn't the 2nd line output a warning when error_reporting is set
to E_ALL? Is empty() some kind of special function where the validity
of indices is not checked? If that is the case, I have two questions:
1. Will this behavior persist in future versions of PHP?
2. Are there other functions or a general rule where PHP doesn't
output warnings when a nonexistant index is given?
--
Immanuel doesn't pun, he Kant.
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Re: [PHP] php5-mysqli
NSK wrote: hi how can I ensure that php5-mysqli is correctly loaded? the server is SuSE9.3 and I have installed the package from yast, but one app (phpmyadmin) says it cannot find the mysql extension (although other apps can query the db). which config files are responsible for loading mysqli in apache/php5 ? pmp_mysqli !== php_mysql mysqli works only with mysql = 4.1.3, do you have this installed? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] empty function and array indices
On Sun, May 1, 2005 1:47 pm, Gabriel Birke said: Is empty() some kind of special function where the validity of indices is not checked? Bingo! That's rather the whole point of empty and isset. :-) The behaviour of empty has changed over time, with various releases. isset seems more stable in that regard, so I prefer to use that one. Also, to me, philosophically and from an application logic perspective, I generally want to do something different when some variable is not set at all, as opposed to having in it. But that's maybe just me. :-) YMMV -- Like Music? http://l-i-e.com/artists.htm -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Problem with array
On Sun, May 1, 2005 1:46 pm, Murray @ PlanetThoughtful said: -Original Message- From: Richard Lynch [mailto:[EMAIL PROTECTED] Sent: Monday, 2 May 2005 6:16 AM To: Murray @ PlanetThoughtful Cc: php-general@lists.php.net Subject: RE: [PHP] Problem with array On Sun, May 1, 2005 1:08 pm, Murray @ PlanetThoughtful said: Color me confused. I removed global $arrtree; and added $arrtree = array(); to the function buildProjectTree() and now the parent function (listProjectChildren) returns no values at all. I've checked the page from which listProjectChildren() is being called, and $arrtree does not appear as a variable in it at all, so it seems global $arrtree; was doing SOMETHING, but at this point I have no idea what. Still trying to work this out, if anyone else has any suggestions? I'm not real clear on what you are trying to do in the first place, but if taking out the global messed up, put it back :-) Maybe add another global $arrtree in the other function so *BOTH* functions are using the same $arrtree? (Laugh) It's probably because I'm not explaining myself well... Let me try to outline pseudo recordsets for the 2 tables: Tbl_content: Contid, parid 1, 2,1 3,1 4, 5,4 6,1 7,5 8,2 9,7 Tbl_content_messages: Msgid, contid 1,2 2,2 3,4 4,5 5,5 6,5 7,6 8,6 9,8 10,9 11,9 Okay, so what I'm trying to do is display a summary count of all of the messages in tbl_content_messages for each project in tbl_content (in this case the 2 records with contid of 1 and 4, as they have no parid value). Okay, I'm lost. You're tossing around words like project, but you've got a field contid and parid, and I read this three times and I don't know which is which. What's a cont? What's a par? I assume Msg is short for message. Type them out. Your fingers may hurt today, but your brain will thank you tomorrow. :-) The only way I could think to do this was to create a query that did a SELECT COUNT(*) from tbl_content_messages using the IN operator with a list of all of the contid values associated with each project. I think you maybe want LEFT OUTER JOIN to keep the projects with 0 messages. -- Like Music? http://l-i-e.com/artists.htm -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] form array
i've created file upload scripts in the past that allows multi-upload inputs using the bracket [] array in form. so now i have to create the same type of script but each file input field will also be followed by a text box for a file caption type thing. what would i used for the input text box? file: input type=file name=foo[] now for my text field? input type=text name=?? something like foo[caption][] ? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] automatic PHP Template engine
Richard Lynch wrote: On Sun, May 1, 2005 12:54 pm, Evert | Rooftop Solutions said: I'm working on a template engine, and I want my template engine to be automaticly started when a .stl file is called from the browser. I know this can be done with mod_rewrite, but I really need a platform-independant solution. Has anybody some ideas on how to make it work everywhere (preferable also on hosts where you don't have access to configuration/shared hosting). At one end of the scale, you could write a Module for Apache, *just* like PHP is. At the other end, you could give documentation to users about using httpd.conf and/or .htaccess and Apache's ForceType directive to fire up PHP. Somewhere in the middle, I guess you could create an extension of PHP, just like php_mysql.[so|dll] and that *might* maybe give you the ability to hack enough things, including the installer/configure scripts that would do what you want... Probably not though, now that I think about it. I think the most realistic approach, honestly, is to just educate users/hosts how to easily send all your .stl scripts through PHP. If your .stl becomes even moderately popular, they'll do that, certainly *long* before they'll install your STL module to Apache. [snip] I've should have mentioned: The template format is primairily going to be used by inside developers and partners. They want to be able to use it for every client they encounter, but are sometimes restricted by the clients (shared-)host. Thank you for your big explaination, I think I know enough to dive into the subject. regards, Evert -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Newbie Help
Hello All,
First of I'm new to this a hop I'm doing this right.
If some one can help me with my web site page. I'm trying to make it
call a page and I get a error line 42. Error:
http://bonhamlinux.org/idex.php?page=links/index.php
The code that I'm trying to do this is the following:
?php
if(isset($_GET ['page']))
{include($_GET ['page']..php);}
else
{echo(Page Not Set.);}
?
My site is: http://bonhamlinux.org
My email is: [EMAIL PROTECTED]
Thanks for all the help.
Thomas
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[PHP] Newbie Help
Hello All,
First of I'm new to this a hop I'm doing this right.
If some one can help me with my web site page. I'm trying to make it
call a page and I get a error line 42. Error:
http://bonhamlinux.org/idex.php?page=links/index.php
The code that I'm trying to do this is the following:
?php
if(isset($_GET ['page']))
{include($_GET ['page']..php);}
else
{echo(Page Not Set.);}
?
My site is: http://bonhamlinux.org
My email is: [EMAIL PROTECTED]
Thanks for all the help.
Thomas
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Re: [PHP] Newbie Help
On Sunday 01 May 2005 10:39 pm, Thomas Bonham wrote:
Hello All,
First of I'm new to this a hop I'm doing this right.
If some one can help me with my web site page. I'm trying to make it
call a page and I get a error line 42. Error:
http://bonhamlinux.org/idex.php?page=links/index.php
The code that I'm trying to do this is the following:
?php
if(isset($_GET ['page']))
{include($_GET ['page']..php);}
else
{echo(Page Not Set.);}
?
My site is: http://bonhamlinux.org
My email is: [EMAIL PROTECTED]
Thanks for all the help.
Thomas
I spot perhaps a typo in http://bonhamlinux.org/idex.php?page=links/index.php
Might that be 'index' instead?
Hth,
Andre
^^
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Re: [PHP] Newbie Help
Andre Dubuc wrote:
On Sunday 01 May 2005 10:39 pm, Thomas Bonham wrote:
Hello All,
First of I'm new to this a hop I'm doing this right.
If some one can help me with my web site page. I'm trying to make it
call a page and I get a error line 42. Error:
http://bonhamlinux.org/idex.php?page=links/index.php
The code that I'm trying to do this is the following:
?php
if(isset($_GET ['page']))
{include($_GET ['page']..php);}
else
{echo(Page Not Set.);}
?
My site is: http://bonhamlinux.org
My email is: [EMAIL PROTECTED]
Thanks for all the help.
Thomas
I spot perhaps a typo in
http://bonhamlinux.org/idex.php?page=links/index.php
Might that be 'index' instead?
Hth,
Andre
^^
Thanks for replying so fast.
That is not a typo because the index.php pages is the following:
?php
header(Location: idex.php?page=main);
?
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Re: [PHP] Newbie Help
Perhaps the path to the included files is incomplete:
according to your error message you are trying to open
links/index.php.php
Does it need both of the dot php's ??
Would it help to include the full path to the includes such as:
/home/bonhamli/public_html/links/index.php.php
so something like that.
Mark Cain
- Original Message -
From: Thomas Bonham [EMAIL PROTECTED]
To: php-general@lists.php.net
Sent: Sunday, May 01, 2005 10:39 PM
Subject: [PHP] Newbie Help
Hello All,
First of I'm new to this a hop I'm doing this right.
If some one can help me with my web site page. I'm trying to make it
call a page and I get a error line 42. Error:
http://bonhamlinux.org/idex.php?page=links/index.php
The code that I'm trying to do this is the following:
?php
if(isset($_GET ['page']))
{include($_GET ['page']..php);}
else
{echo(Page Not Set.);}
?
My site is: http://bonhamlinux.org
My email is: [EMAIL PROTECTED]
Thanks for all the help.
Thomas
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Re: [PHP] Newbie Help
I Think the .php.php is the problem but I don't know have to fix it.
Let me know if you won't to see the full src page.
Thomas
Mark Cain wrote:
Perhaps the path to the included files is incomplete:
according to your error message you are trying to open
links/index.php.php
Does it need both of the dot php's ??
Would it help to include the full path to the includes such as:
/home/bonhamli/public_html/links/index.php.php
so something like that.
Mark Cain
- Original Message -
From: Thomas Bonham [EMAIL PROTECTED]
To: php-general@lists.php.net
Sent: Sunday, May 01, 2005 10:39 PM
Subject: [PHP] Newbie Help
Hello All,
First of I'm new to this a hop I'm doing this right.
If some one can help me with my web site page. I'm trying to make it
call a page and I get a error line 42. Error:
http://bonhamlinux.org/idex.php?page=links/index.php
The code that I'm trying to do this is the following:
?php
if(isset($_GET ['page']))
{include($_GET ['page']..php);}
else
{echo(Page Not Set.);}
?
My site is: http://bonhamlinux.org
My email is: [EMAIL PROTECTED]
Thanks for all the help.
Thomas
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Re: [PHP] Newbie Help
Here is all of the page, except one or two and the
images.
Thomas
--- Mark Cain [EMAIL PROTECTED] wrote:
YES let see the src
- Original Message -
From: Thomas Bonham [EMAIL PROTECTED]
To: php-general@lists.php.net
Sent: Sunday, May 01, 2005 11:31 PM
Subject: Re: [PHP] Newbie Help
I Think the .php.php is the problem but I don't
know have to fix it.
Let me know if you won't to see the full src page.
Thomas
Mark Cain wrote:
Perhaps the path to the included files is
incomplete:
according to your error message you are trying
to open
links/index.php.php
Does it need both of the dot php's ??
Would it help to include the full path to the
includes such as:
/home/bonhamli/public_html/links/index.php.php
so something like that.
Mark Cain
- Original Message -
From: Thomas Bonham [EMAIL PROTECTED]
To: php-general@lists.php.net
Sent: Sunday, May 01, 2005 10:39 PM
Subject: [PHP] Newbie Help
Hello All,
First of I'm new to this a hop I'm doing this
right.
If some one can help me with my web site page.
I'm trying to make it
call a page and I get a error line 42. Error:
http://bonhamlinux.org/idex.php?page=links/index.php
The code that I'm trying to do this is the
following:
?php
if(isset($_GET ['page']))
{include($_GET ['page']..php);}
else
{echo(Page Not Set.);}
?
My site is: http://bonhamlinux.org
My email is: [EMAIL PROTECTED]
Thanks for all the help.
Thomas
--
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http://www.php.net/unsub.php
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Thomas Bonham
Linux Rocks
http://www.bonhamlinux.org
Cell 602 402 9786
E-mail [EMAIL PROTECTED]
YIM freeswimfreak
__
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Tired of spam? Yahoo! Mail has the best spam protection around
http://mail.yahoo.com
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Re: [PHP] Newbie Help
first remove the space between GET and [
I think this keeps your script from find the variable page
secondly the variable page already has the php extension being passed to
it via the GET statement
make the include like:
{include($_GET['page']);}
try it and let us know.
Mark Cain
The code that I'm trying to do this is the following:
?php
if(isset($_GET ['page']))
{include($_GET ['page']..php);}
else
{echo(Page Not Set.);}
?
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Re: [PHP] Newbie Help
Also, after I looked at more of your code you will need to specify the php
extension in only one of two places. Currently you are specifying it in 1)
the code below and in 2) nav.php and in nav.php you don't have it specified
for the main but you do for the other links. That means that the code
supplies the .php extension for main (which it needs to because it is simply
main and not main.php) but the other pages are specified as name.ext
with the .php. Then when that page name gets to the script, the script is
adding .php onto the variable -- resulting in main.php, links/index.php.php,
email/email.php.php and so forth.
Do it one place or the other -- but do it consistently.
Looks like you're close to getting it to work and I'm close to going to bed.
Mark Cain
The code that I'm trying to do this is the following:
?php
if(isset($_GET ['page']))
{include($_GET ['page']..php);}
else
{echo(Page Not Set.);}
?
My site is: http://bonhamlinux.org
My email is: [EMAIL PROTECTED]
Thanks for all the help.
Thomas
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[PHP] Submit name change
I need this to change the value of the button 'sit in' to the name of a
user --it doesnt work so anyone got any ideas or is what i am looking to do
impossible.
Either the button name can show the username or a text field can change from
blank to show the username when clicked.
FORM ACTION=?=$PHP_SELF? METHOD=GET
INPUT TYPE=SUBMIT VALUE=Sit in
onClick=JavaScript:showname('?php echo $uname;?');
return true;
/FORM
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