Re: [PHP] Scope of Variables and use of global and this-var
On Jul 15, 2009, at 3:28 PM, tedd wrote: My way -- every time I open a database, I do so by including the configuration.php file that holds the logon/password et other data to connect with the database. When I'm done with what I want from the database, I close it. If one does not close it, then what are the consequences? And do any consequences persist, and how? Or is it just a consideration for a limited time? What limits the risk? In case there is a good article about this, I'd love a link.. Thanks! -G Cheers, tedd -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Scope of Variables and use of global and this-var
On Thu, Jul 16, 2009 at 9:53 AM, Govindagovinda.webdnat...@gmail.com wrote: On Jul 15, 2009, at 3:28 PM, tedd wrote: My way -- every time I open a database, I do so by including the configuration.php file that holds the logon/password et other data to connect with the database. When I'm done with what I want from the database, I close it. If one does not close it, then what are the consequences? And do any consequences persist, and how? Or is it just a consideration for a limited time? What limits the risk? In case there is a good article about this, I'd love a link.. Thanks! -G Cheers, tedd If you're not using persistent connections, they'll all get closed when the script completes. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Scope of Variables and use of global and this-var
At 12:21 PM +0200 7/14/09, Anton Heuschen wrote: In my index.php page I then use $dbconnect again but do I simply use $dbconnect again ... or must I say global $dbconnect and then use it in the rest of the DB calls? or use GLOBALS .. Anton: My way -- every time I open a database, I do so by including the configuration.php file that holds the logon/password et other data to connect with the database. When I'm done with what I want from the database, I close it. I do not store anything in GLOBALS. Cheers, tedd -- --- http://sperling.com http://ancientstones.com http://earthstones.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Scope of Variables and use of global and this-var
This is just a general question, I am not 100% on when to use global $var , and $this-var and how/what about the GLOBAL vars Lets say I have one file I call config.php here I connect to the db, to ldap etc the connection var I can then use in a file on its own ... obviously after I include config.php lets say in config.php my DB connect was $dbconnect In my index.php page I then use $dbconnect again but do I simply use $dbconnect again ... or must I say global $dbconnect and then use it in the rest of the DB calls? or use GLOBALS .. Within a class I can use $this-var correct ... but its not something to be used in a basic procedural if I can call it that page... Lets say with my config.php and its connection to the db ...where I have $dbconnect .. in a class I can also use it, do I access this var straight as $dbconnect or use $this-dbconnect = $dbconnect (and define it as global $dbconnect first before doing this) I am getting my results and seems to working most of the time, but not sure if I am using calls to global or $this-var ..when its not required and calling the var direct would of sufficed. I have never really used GLOBAL vars, so not sure how this ties in or if it might be even more helpful ... Some suggestions or pointers or examples would be appreciated just to clear up some confusion. Regards Oh and if one class uses methods in another class do I instansiate a new object of the other class I have seen use of OtherClass::Method is this better method of $obj = new OtherClass() use
Re: [PHP] Scope of Variables and use of global and this-var
On Tue, Jul 14, 2009 at 6:21 AM, Anton Heuschenanto...@gmail.com wrote:
This is just a general question,
I am not 100% on when to use global $var , and $this-var and how/what
about the GLOBAL vars
Lets say I have one file I call config.php here I connect to the db, to
ldap etc the connection var I can then use in a file on its own ...
obviously after I include config.php lets say in config.php my DB
connect was $dbconnect
In my index.php page I then use $dbconnect again but do I simply use
$dbconnect again ... or must I say global $dbconnect and then use it in the
rest of the DB calls? or use GLOBALS .. Within a class I can use $this-var
correct ... but its not something to be used in a basic procedural if I
can call it that page...
Lets say with my config.php and its connection to the db ...where I have
$dbconnect .. in a class I can also use it, do I access this var
straight as $dbconnect or use $this-dbconnect = $dbconnect (and define it
as global $dbconnect first before doing this)
I am getting my results and seems to working most of the time, but not sure
if I am using calls to global or $this-var ..when its not required and
calling the var direct would of sufficed.
I have never really used GLOBAL vars, so not sure how this ties in or if it
might be even more helpful ...
Some suggestions or pointers or examples would be appreciated just to clear
up some confusion.
Regards
Oh and if one class uses methods in another class do I instansiate a
new object of the other class I have seen use of OtherClass::Method
is this better method of $obj = new OtherClass() use
You're really opening a big can of worms here, but it'll be a good
adventure. Just keep at it and try reading some real books on the
subject.
If you include a file, all of those variables are magically in the
current scope. So when you include config.php inside your index.php,
you can use $dbconnect directly.
Use $this- when you are inside a class using a dynamic call on a
method or property of that class.
class Foo {
protected $bar;
public function __construct() {
$this-bar = 'wee';
}
public function setBar($value) {
$this-bar = $value;
}
}
Inside the class you would use this- to reference bar or call any of
that classes methods/props. Outside you would use it like this:
$foo = new Foo;
$foo-setBar('blah');
If you haven't used globals yet, please do not feel compelled to do so
now. There are all sorts of ways of dealing with passing around your
application state. Globals can be used by a skilled programmer of
course, but I'd shy away from them.
I'd also recommend reading some of these pages:
http://www.php.net/manual/en/language.variables.scope.php
http://www.php.net/manual/en/language.oop5.php
Hope this helps!
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Re: [PHP] Scope of Variables and use of global and this-var
do you need to use global?
IMO you should use just 1 global variable, thats is what I call entry point
My scripts looks like...
require_once 'loader.php';
Loader::registerAutoload();
$foo = new Foo();
$foo-doStuff();
This way you can develop faster and do maintenance better avoiding
problems with third-party.
Here you have some rules for remember how to access
you want a $var from outside and you are outside an object or
function? = use the $var
you want a $var from outside you are inside an object or function? =
global $var o $GLOBALS['vars'] (better to pass it as arg)
you want a $var from an object and you are inside the same object? =
use $this-var (better $this-getVar() )
you want a $var from an object and you are inside other object? = use
$object-getVar() or Class::getVar()
It is a good practice to declare the object members as protected and
provide s/getters for each member (when your design allow it). Also
you can overload by using the __get, __set and __call
It is really easy to make an automagic object
Class AutoMagic
{
protected $_vars = array();
public/*mixed*/
function __get(/*string*/$name)
{
return isset( $this-{ $name } ) ? $this-_vars[
strtolower($name) ] : null;
}
public/*mixed*/
function __set(/*string*/$name,/*mixed*/$value)
{
return $this-_vars[ strtolower($name) ] = $value;
}
public/*boolean*/
function __isset(/*string*/$name)
{
return array_key_exists( strtolower($name), $this-_vars );
}
public/*void*/
function __unset(/*string*/$name)
{
if( isset( $this-{ $name } ))
unset( $this-_vars[ strtolower($name) ] );
}
public/*mixed*/
function __call(/*string*/$method,array $args)
{
$type = strtolower( substr( $method, 0, 3 ) );
$property = substr( $method, 3 );
switch( $type )
{
case 'get':
return $this-{ $property };
case 'set':
if( !array_key_exists(0, $args) )
trigger_error( 'Bad call in ' .
get_class($this) . '::' . $method
.'. Method needs an argument' );
return $this-{ $property } = $args[0];
case 'has':
return isset( $this-{ $property } );
case 'del':
unset( $this-{ $property } );
return;
}
trigger_error( 'Bad call in ' . get_class($this) . '::' .
$method );
}
}
On Tue, Jul 14, 2009 at 10:01 AM, Darren
Karstensdarrenkarst...@googlemail.com wrote:
Oh and if one class uses methods in another class do I instansiate a
new object of the other class I have seen use of OtherClass::Method
is this better method of $obj = new OtherClass() use
The :: is used to access static methods of a class. Static methods can
be used without creating an instance of the class because they dont
use any of the classes member variables.
For example say you have a class with a function for calculating the
area of a rectangle:
class SomeMathFunctions {
public function calculateRectangle($width, $height) {
return $width*$height;
}
}
To use this function you would need to first create an instance of the
class then call the method using the normal - :
$funcs = new SomeMathFunctions();
$area = $funcs-calculateRectange(10,15);
But if you create the function as static by using public static
function calculateRectangle($width, $height) {
then you can access the method by using just 1 call:
$area = SomeMathFunctions::calculateRectange(10,15);
So for creating utility functions its better to use static methods
since you dont get the overhead of creating a new instance of the
class.
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[PHP] Scope woe
Hello again guys,
I was wondering the best way to tackle the following problem:
I've got a class, containing a property which is another object. So from
outside I should be able to do
$firstobject-propertycontainingobject-methodinsidethatobject();
The $firstobject variable is in the global namespace (having been made with
$firstobject = new FirstObject;), and I'm having a problem that I'm sure
many people have when accessing it inside another class, so:
class otherObject
{
static function messwithotherthings ()
{
$firstobject-propertycontainingobject-methodinsidethatobject();
}
}
But $firstobject is blank, which makes sense because in there it is pointing
to the local variable within the method.
To solve this, I could add 'global $firstobject' inside every method, but
this is very redundant and boring. I've tried a couple of things like
adding:
private $firstobject = $GLOBALS['firstobject'];
But apparently that's bad syntax. I was just wondering the best way to get
around this?
Thanks a lot for your help,
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:O)
Re: [PHP] Scope of the variables around PHP class
Define a class function and pass the array via this function or pass it
via the classes constructor.
VamVan wrote:
Hello Guys,
I have a problem here. I hope you can help me resolving it.
Please see the code below
array.php has $array1 = ('hello'='heelo',)
require_once('array.php');
class Classa {
}
How can I access the array values in my class? I want to understand the
scope.
Thanks
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[PHP] Scope of the variables around PHP class
Hello Guys,
I have a problem here. I hope you can help me resolving it.
Please see the code below
array.php has $array1 = ('hello'='heelo',)
require_once('array.php');
class Classa {
}
How can I access the array values in my class? I want to understand the
scope.
Thanks
Re: [PHP] Scope of the variables around PHP class
VamVan wrote:
Hello Guys,
I have a problem here. I hope you can help me resolving it.
Please see the code below
array.php has $array1 = ('hello'='heelo',)
require_once('array.php');
class Classa {
}
How can I access the array values in my class? I want to understand the
scope.
You can't, unless you make $array a global variable which is not a
proper solution.
You could do something like this:
class MyClass {
private $my_array = array();
function __construct()
{
require_once ('array.php');
$this-my_array = $array1;
}
}
Then you can use $this-my_array inside the class and it's automatically
loaded when you create a new object.
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[PHP] scope and return array( ); problems
hi all,
I have this function:
function preg_array($pattern, $array, $r_array)
{
global $match;
global $r_array;
foreach ($array as $key = $value)
{
if (preg_match($pattern, $value,$match))
{
$GA=array_slice($match,1);
break;
}
}
return array ($GA, $match);
}
[PHP] scope and return array( ); problems
Hi all,
I have this code ( but you already know it ;-) :
function preg_array($pattern, $array, $r_array)
{
global $match;
global $r_array;
foreach ($array as $key = $value)
{
if (preg_match($pattern, $value,$match))
{
$r_array=array_slice($match,1);
break;
}
}
return array ($r_array, $match);
}
$GA = array();
preg_array(/^GA\s+(\d+.\d+)\s+(\d+.\d+)/i, $PF, $GA)
but the array $GA is empty outside the function, i tried to declare $GA also
as global inside the function and it didn't change the output.
It works if the function is change to this :
function preg_array($pattern, $array, $GA)
{
global $match;
global $GA;
foreach ($array as $key = $value)
{
if (preg_match($pattern, $value,$match))
{
$GA=array_slice($match,1);
break;
}
}
return array ($GA, $match);
}
What's wrong with the first version of the preg_array function? do I really
need to have the same array name in order to retrieve the third argument of
the function?
Thanks for your help,
yvan
Re: [PHP] scope and return array( ); problems
On Wed, April 18, 2007 5:33 pm, Yvan Strahm wrote:
I have this function:
function preg_array($pattern, $array, $r_array)
{
global $match;
global $r_array;
Passing in $r_array *AND* declaring it global is just plain silly.
Do one or the other, but not both.
If the array is LARGE, you may also want to consider writing this with
array_map and a create_function so that you can have the iteration
happening in C instead of in PHP...
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Re: [PHP] Scope of include
# [EMAIL PROTECTED] / 2007-01-17 21:49:05 -0800: Hello php list: If I include a php script inside a php function definition and then call the function in another script. What is the scope of variables in the included script? Are they local to the function that calls include with the file name? Yes. -- How many Vietnam vets does it take to screw in a light bulb? You don't know, man. You don't KNOW. Cause you weren't THERE. http://bash.org/?255991 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Scope of include
At 9:49 PM -0800 1/17/07, jekillen wrote: Hello php list: If I include a php script inside a php function definition and then call the function in another script. What is the scope of variables in the included script? Are they local to the function that calls include with the file name? Thanks in advance; I'm not sure where to look for this answer; JK JK: Whenever I have a question about an include, I just cut/paste (i.e., replace) the include statement with the include script. That way I know exactly what it does. hth's tedd -- --- http://sperling.com http://ancientstones.com http://earthstones.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Scope of include
On Thu, 2007-01-18 at 10:29 -0500, tedd wrote: At 9:49 PM -0800 1/17/07, jekillen wrote: Hello php list: If I include a php script inside a php function definition and then call the function in another script. What is the scope of variables in the included script? Are they local to the function that calls include with the file name? Thanks in advance; I'm not sure where to look for this answer; JK JK: Whenever I have a question about an include, I just cut/paste (i.e., replace) the include statement with the include script. That way I know exactly what it does. Sounds like a maintenance nightmare :| To answer his question though, variables not declared via the global keyword and not accessed via the super global variables ($GLOBALS, $_SESSION, etc) inherit the scope in which the include statement occurs. Therefore, if in the included file all you have is: $foo = 'foo'; Then it's scope is the function including the file. Cheers, Rob. -- .. | InterJinn Application Framework - http://www.interjinn.com | :: | An application and templating framework for PHP. Boasting | | a powerful, scalable system for accessing system services | | such as forms, properties, sessions, and caches. InterJinn | | also provides an extremely flexible architecture for | | creating re-usable components quickly and easily. | `' -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Scope of include
Robert Cummings wrote: To answer his question though, variables not declared via the global keyword and not accessed via the super global variables ($GLOBALS, $_SESSION, etc) inherit the scope in which the include statement occurs. Therefore, if in the included file all you have is: $foo = 'foo'; Then it's scope is the function including the file. It's important to have this clear in your head when dealing with included files, so I wrote an example that will hopefully demonstrate it for the OP... http://dev.stut.net/php/scope/ -Stut -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Scope of include
Hello php list: If I include a php script inside a php function definition and then call the function in another script. What is the scope of variables in the included script? Are they local to the function that calls include with the file name? Thanks in advance; I'm not sure where to look for this answer; JK -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Scope of include
On 1/17/07, jekillen [EMAIL PROTECTED] wrote:
Hello php list:
If I include a php script inside a php function definition and then
call the
function in another script. What is the scope of variables in the
included
script? Are they local to the function that calls include with the file
name?
Thanks in advance;
I'm not sure where to look for this answer;
JK
Does your included PHP script contain any functions? Or is it more like:
file1.php contents:
function my_function () {
if (i_feel_like_it) {
include(inc.php);
}
}
and inc.php contains variables at the global level such as:
inc.php:
$var1 = 2;
$var2 = 3;
Am I close?
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Re: [PHP] Scope of include
On 1/17/07, Andrew Kreps [EMAIL PROTECTED] wrote:
On 1/17/07, jekillen [EMAIL PROTECTED] wrote:
Hello php list:
If I include a php script inside a php function definition and then
call the
function in another script. What is the scope of variables in the
included
script? Are they local to the function that calls include with the file
name?
Thanks in advance;
I'm not sure where to look for this answer;
JK
FYI, I just ran a quick scope test based on my guess of your
situation. If you include a PHP file containing global variables
inside a function, the variables will _only_ be available after you
include the file, and only for the duration of the function. They
will not exist after the function ends, even if you specify global
$var1; in your other functions, or at the global level of your script.
This was tested using PHP 5.0.4.
Here is my sample code:
test.php:
?
print Top Level: Var1: $var1 Var2: $var2\nbr;
test1();
test2();
function test1 ()
{
print Before: Var1: $var1 Var2: $var2\nbr;
include(testinc.php);
print After: Var1: $var1 Var2: $var2\nbr;
}
function test2 ()
{
print Test2: Var1: $var1 Var2: $var2\nbr;
}
print Bottom Level: Var1: $var1 Var2: $var2\nbr;
testinc.php:
?
$var1 = 1;
$var2 = 2;
?
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Re: [PHP] scope of classes in PHP
Stuart Bailey wrote: Hi I'm developing an app to administer LDAP (phpLdapAdmin is too complex for the customer). I have created an LDAP class, in a file class_ldap.php. It include methods for connecting to the server, binding a DN (effectively login), and adding posix groups. I have an index.php with include_once 'class_ldap.php', which allows me to login using the HTTP authentication mechanism. The connect method stores the resulting connection resource in a global variable (included in a config.php file). When I then go to add the posix group (from add_group.php, that also includes class_ldap.php), I find that the global connection variable is not valid. My question is, do I need to connect and authenticate with the LDAP server every time I want to perform an action, or is there a way to establish a you need to establish a connection at the start of every request php handles, typically you perform one [major] 'action' per request so the short answer is: 'yes'. the connection to the LDAP server is a 'resource' type variable - php 'resources' are only valid for the duration of the script. connection for the user's session, that is cleared when the user logs out. Many thanks, Stuart. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] scope of classes in PHP
Hi I'm developing an app to administer LDAP (phpLdapAdmin is too complex for the customer). I have created an LDAP class, in a file class_ldap.php. It include methods for connecting to the server, binding a DN (effectively login), and adding posix groups. I have an index.php with include_once 'class_ldap.php', which allows me to login using the HTTP authentication mechanism. The connect method stores the resulting connection resource in a global variable (included in a config.php file). When I then go to add the posix group (from add_group.php, that also includes class_ldap.php), I find that the global connection variable is not valid. My question is, do I need to connect and authenticate with the LDAP server every time I want to perform an action, or is there a way to establish a connection for the user's session, that is cleared when the user logs out. Many thanks, Stuart. -- --- Stuart Bailey BSc (hons) CEng CITP MBCS LinuSoft (Proprietor) Linux Specialist (01953) 601294 (07778) 383739 http://www.linusoft.co.uk -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Scope issue
GH wrote: Hi I am having an issue with I think it is the scope of variables: I have a file that I am including which has the following ?php // +-- // | PHP Source // +-- // echo got language.phpbr /; global $langauge; $language['project_name'] = P.L.I.M.S; $language['sub_project_name'] = DCR CC; ? In my main file, I am attempting to from with in a function call $language['project_name'] and i am failing... can you offer any advice? Unless you are *inside* of a function definition, 'global' makes no sense whatsoever in PHP. Get rid of it unless you are inside function body. But in your main script *DO* put: global $language; inside of your function body -- That's where you need it to be. You may also want to consider passing $language in as an argument to your function. Or, if it *MUST* be a global variable, use $LANGUAGE so that it stands out in the rest of your script. -- Like Music? http://l-i-e.com/artists.htm -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Scope issue
Hi I am having an issue with I think it is the scope of variables: I have a file that I am including which has the following ?php // +-- // | PHP Source // +-- // echo got language.phpbr /; global $langauge; $language['project_name'] = P.L.I.M.S; $language['sub_project_name'] = DCR CC; ? In my main file, I am attempting to from with in a function call $language['project_name'] and i am failing... can you offer any advice? Thanks -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Scope issue
In my main file, I am attempting to from with in a function call $language['project_name'] and i am failing... can you offer any advice? Are there any specific reasons that you need to set the variable to global scope? It's typically recommended that unless you need to, to pass the variable into the function and return the modified value if you plan on changing it. -M -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] scope problem
Apparently I'm having some kind of meltdown here. Can anyone explain the
logic behind why the following variable has the original value and how I can
pull/push the value to access it at the end?
while loop
{
$variable = 100;
while loop
{
switch($othervar)
{
case 1:
$variable = $variable + 100;
break;
case 2:
$variable = $variable + 200;
break;
case 3:
$variable = $variable + 300;
break;
}
echo $variable.br;
}
echo brThe final value is .$variable.br;
}
This gives values something to the tune of...
200
400
700
100
I usually have variables set outside of a while loop that increment based on
the contents of the loop and I could swear that they hold the value on the
other side of the loop. I don't usually use break; in my scripts unless I'm
using switch. However, I would think that if using break was throwing me,
that the value wouldn't print on each cycle of the loop.
TIA
Larry
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Re: [PHP] scope problem
Hello Larry, Friday, March 5, 2004, 4:01:39 PM, you wrote: LB This gives values something to the tune of... LB 200 LB 400 LB 700 LB 100 Hard to say with so little code, but... Your first where loop is probably running twice, i.e. resetting variable back to 100 after the 2nd (internal) where loop has finished modifying it. Move $variable = 100 above the first where loop and see what happens. -- Best regards, Richard Davey http://www.phpcommunity.org/wiki/296.html -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] scope problem
Thanks for the help, but it turned out to be the nut on top of the keyboard! Something I missed. Good to know my concept of scope with php is still healthy (at least). Thanks -Original Message- From: Richard Davey [mailto:[EMAIL PROTECTED] Sent: Friday, March 05, 2004 11:17 AM To: PHP List Subject: Re: [PHP] scope problem Hello Larry, Friday, March 5, 2004, 4:01:39 PM, you wrote: LB This gives values something to the tune of... LB 200 LB 400 LB 700 LB 100 Hard to say with so little code, but... Your first where loop is probably running twice, i.e. resetting variable back to 100 after the 2nd (internal) where loop has finished modifying it. Move $variable = 100 above the first where loop and see what happens. -- Best regards, Richard Davey http://www.phpcommunity.org/wiki/296.html -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Scope: global $GLOBALS[]
I checked the manual but I still don't get it.
http://us2.php.net/manual/en/language.variables.scope.php
I'm setting a variable $pics with a form by post method. It's on a
screen that is included, then it needs to be applied to another
screen that will take it's place when it's all re-processed.
template
include header
include SCREEN (picture or settings)
include footer
Now, the template sets $pics to a default and then I can pull up the
picture screen and setting $pics global makes it work but if I go to the
settings screen to change $pic, it doesn't stick, even if I set it
global there. I'm not sure if I need to set global once in the template
or not there but in each screen I want to use it.
template:
global $pics;
if (!isset($pics)){$pics = 8;}
picture screen:
global $pics;
# works fine with the setting 8 from the template
settings screen:
global $pics;
print $pics; #for debugging, always follows template setting
if (!isset($pics)){$pics = 5;}
if ($_POST){
if (isset ($_POST['thumbs'])){
$pics = $_POST['thumbs'];
print settings have been changed;
}
}
?
form name=mail action=?php SCREEN_DIR . /settings.php ?
method=post
label for=thumbsnumber of thumbnails per page: /label
input type=text name=thumbs id=thumbs size=2
value=?php print $pics ?
button type=submitOK/button
/form
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[PHP] scope of class atts in methods
Hi all,
a quick question about using PHP's objects, specifically in terms of the
scope of class attributes:
Normally, in PHP, a variable in a function is local to that function and
is NOT a reference to a similarly-named variable outside the function,
right? To the best of my knowledge, there are several ways to allow
access to an outside variable from within a function:
1) Declare the variable as global with the global keyword
2) Access it from the $GLOBALS array
3) Pass the variable to the function as a parameter
and probably others, but it's really beside the point because I don't
have a question about normal functions. What I am really wondering is
if there is any formal rules about the scope of Class Attributes in
Class definitions and in methods -- they do not behave identical to
PHP's functions. For instance, I can access a class attribute from
within a method of that class without explicitly declaring that
attribute global inside the method, or without explicitly passing that
attribute as a parameter to the method. So they seem to behave as if
they are always global.
But if I want to make a change to that class attribute from within a
method, am I affecting a copy of the class attribute, or the class
attribute itself? The reason I ask is because I have a Class that is
behaving oddly. Here is the relevant part of the code:
Class Folder
{
// declare class attributes
var $contents = array();
// a method to add to $contents
function add_to_contents($item)
{
$this-contents[] = $item;
}
// a method to remove from $contents
function rm_item($index)
{
unset($this-contents[$index]);
}
}
The crux of my question is, does this have the effect that it appears to
have? I am hoping someone with thorough understanding of the internals
of PHP can give me a definitive answer. My tests are coming up with
strange results, so I haven't figured it out on my own yet.
Thanks in advance,
Erik
PS: FYI, if you unset an array element, there is still an index for that
element -- the array does not reindex itself. A good solution to this,
that a fellow lister named Nathan gave me, is to array_push() a dummy
var onto the end of the array and then array_pop() it back off -- this
reindexes the array. But I am finding that somehow my arrays are
remembering old elements that I could have sworn I unset, so I am
asking the above question about the scope of class attributes in methods.
Erik Price
Web Developer Temp
Media Lab, H.H. Brown
[EMAIL PROTECTED]
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Re: [PHP] scope of class atts in methods
If anyone read this post, you probably already forgot about it, but I
just wanted to clarify that I found the source of the problem and it was
a coding mistake on my part, not a problem with PHP's array
implementation.
Erik
On Thursday, June 6, 2002, at 03:11 PM, Erik Price wrote:
Hi all,
a quick question about using PHP's objects, specifically in terms of
the scope of class attributes:
Normally, in PHP, a variable in a function is local to that function
and is NOT a reference to a similarly-named variable outside the
function, right? To the best of my knowledge, there are several ways
to allow access to an outside variable from within a function:
1) Declare the variable as global with the global keyword
2) Access it from the $GLOBALS array
3) Pass the variable to the function as a parameter
and probably others, but it's really beside the point because I don't
have a question about normal functions. What I am really wondering is
if there is any formal rules about the scope of Class Attributes in
Class definitions and in methods -- they do not behave identical to
PHP's functions. For instance, I can access a class attribute from
within a method of that class without explicitly declaring that
attribute global inside the method, or without explicitly passing that
attribute as a parameter to the method. So they seem to behave as if
they are always global.
But if I want to make a change to that class attribute from within a
method, am I affecting a copy of the class attribute, or the class
attribute itself? The reason I ask is because I have a Class that is
behaving oddly. Here is the relevant part of the code:
Class Folder
{
// declare class attributes
var $contents = array();
// a method to add to $contents
function add_to_contents($item)
{
$this-contents[] = $item;
}
// a method to remove from $contents
function rm_item($index)
{
unset($this-contents[$index]);
}
}
The crux of my question is, does this have the effect that it appears
to have? I am hoping someone with thorough understanding of the
internals of PHP can give me a definitive answer. My tests are coming
up with strange results, so I haven't figured it out on my own yet.
Thanks in advance,
Erik
PS: FYI, if you unset an array element, there is still an index for
that element -- the array does not reindex itself. A good solution to
this, that a fellow lister named Nathan gave me, is to array_push() a
dummy var onto the end of the array and then array_pop() it back off --
this reindexes the array. But I am finding that somehow my arrays are
remembering old elements that I could have sworn I unset, so I am
asking the above question about the scope of class attributes in
methods.
Erik Price
Web Developer Temp
Media Lab, H.H. Brown
[EMAIL PROTECTED]
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[PHP] Scope problem in while loop
According to the PHP 4 docs all variables are global unless within a
function. I've got the following test code which should output 2, but
outputs 1. The while loop creates it's own class object (which seems strange
since it isn't explicitly instantiated by my code; I would think it would
cause errors).
The reason I created an object for my variable (actually, I started testing
with regular strings) is that I've had similar scoping problems in perl,
where variables got out of scope within loops (or even if statements). In
perl, declaring an object outside these structures will protect it's scope.
Not so in PHP I see.
Can anyone explain this behavior? Do I have to create functions that return
values every time I need a loop that modifies a variable?
?php
class Ccust_data {
function Cform_data() {
$this-test = ;
}
}
$o = new Ccust_data();
$o-test = 1;
while ($y = 0) {
global $o-test;
$o-test = 2;
$y = 1;
}
echo \$o-test = $o-test\n;
?
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sysTame
Mac Consulting/Sales
phn 561.589.6449
mobile email[EMAIL PROTECTED]
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Re: [PHP] Scope problem in while loop
On Mon, 2002-03-11 at 18:51, Randall Perry wrote:
According to the PHP 4 docs all variables are global unless within a
function. I've got the following test code which should output 2, but
outputs 1. The while loop creates it's own class object (which seems strange
since it isn't explicitly instantiated by my code; I would think it would
cause errors).
Actually, on PHP 4.2.0-dev, I get a parse error on the 'global $o-test;'
line (you can't globalize an object attribute).
If I remove that line, the code does indeed produce '$o-test = 1;'.
That's because the loop never executes. Consider this change:
while ($y = 0) {
echo In the loop.\n;
$o-test = 2;
$y = 1;
}
When executed, 'In the loop' is never printed. This is because the loop
never executes--because the while() condition is wrong. The '=' should
be a '==' or '==='. What's happening at the moment is that the while()
condition '$y = 0' is assigning 0 to $y, not comparing 0 to $y. The
overall value of that expression, then, is 0--which evaluates to false.
So the while loop never runs. If I change the '=' to '==', I get the
correct output:
Notice: Undefined variable: y in
/home/torben/public_html/phptest/__phplist.html on line 27
In the loop.
$o-test = 2
The notice is easily corrected by initializing $y before testing its
value. The following should work for you:
?php
error_reporting(E_ALL);
class Ccust_data {
function Cform_data() {
$this-test = ;
}
}
$o = new Ccust_data();
$o-test = 1;
$y = 0;
while ($y == 0) {
echo In the loop.\n;
$o-test = 2;
$y = 1;
}
echo \$o-test = $o-test\n;
?
What does this code do for you?
Torben
The reason I created an object for my variable (actually, I started testing
with regular strings) is that I've had similar scoping problems in perl,
where variables got out of scope within loops (or even if statements). In
perl, declaring an object outside these structures will protect it's scope.
Not so in PHP I see.
Can anyone explain this behavior? Do I have to create functions that return
values every time I need a loop that modifies a variable?
?php
class Ccust_data {
function Cform_data() {
$this-test = ;
}
}
$o = new Ccust_data();
$o-test = 1;
while ($y = 0) {
global $o-test;
$o-test = 2;
$y = 1;
}
echo \$o-test = $o-test\n;
?
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RE: [PHP] Scope problem in while loop
I may be wrong, but that's exactly what I ended up having to do... but
don't quote me - I'm just learning OOP
http://www.apokalyptik.com/forum/viewtopic.php?topic=140forum=60
-Original Message-
From: Randall Perry [mailto:[EMAIL PROTECTED]]
Sent: Monday, March 11, 2002 6:52 PM
To: [EMAIL PROTECTED]
Subject: [PHP] Scope problem in while loop
According to the PHP 4 docs all variables are global unless within a
function. I've got the following test code which should output 2, but
outputs 1. The while loop creates it's own class object (which seems
strange
since it isn't explicitly instantiated by my code; I would think it
would
cause errors).
The reason I created an object for my variable (actually, I started
testing
with regular strings) is that I've had similar scoping problems in perl,
where variables got out of scope within loops (or even if statements).
In
perl, declaring an object outside these structures will protect it's
scope.
Not so in PHP I see.
Can anyone explain this behavior? Do I have to create functions that
return
values every time I need a loop that modifies a variable?
?php
class Ccust_data {
function Cform_data() {
$this-test = ;
}
}
$o = new Ccust_data();
$o-test = 1;
while ($y = 0) {
global $o-test;
$o-test = 2;
$y = 1;
}
echo \$o-test = $o-test\n;
?
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sysTame
Mac Consulting/Sales
phn 561.589.6449
mobile email[EMAIL PROTECTED]
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Re: [PHP] Scope problem in while loop
Whoops, you're right. Classic 'C' mistake using = instead of ==. Never mind
:(
On Mon, 2002-03-11 at 18:51, Randall Perry wrote:
According to the PHP 4 docs all variables are global unless within a
function. I've got the following test code which should output 2, but
outputs 1. The while loop creates it's own class object (which seems strange
since it isn't explicitly instantiated by my code; I would think it would
cause errors).
Actually, on PHP 4.2.0-dev, I get a parse error on the 'global $o-test;'
line (you can't globalize an object attribute).
If I remove that line, the code does indeed produce '$o-test = 1;'.
That's because the loop never executes. Consider this change:
while ($y = 0) {
echo In the loop.\n;
$o-test = 2;
$y = 1;
}
When executed, 'In the loop' is never printed. This is because the loop
never executes--because the while() condition is wrong. The '=' should
be a '==' or '==='. What's happening at the moment is that the while()
condition '$y = 0' is assigning 0 to $y, not comparing 0 to $y. The
overall value of that expression, then, is 0--which evaluates to false.
So the while loop never runs. If I change the '=' to '==', I get the
correct output:
Notice: Undefined variable: y in
/home/torben/public_html/phptest/__phplist.html on line 27
In the loop.
$o-test = 2
The notice is easily corrected by initializing $y before testing its
value. The following should work for you:
?php
error_reporting(E_ALL);
class Ccust_data {
function Cform_data() {
$this-test = ;
}
}
$o = new Ccust_data();
$o-test = 1;
$y = 0;
while ($y == 0) {
echo In the loop.\n;
$o-test = 2;
$y = 1;
}
echo \$o-test = $o-test\n;
?
What does this code do for you?
Torben
The reason I created an object for my variable (actually, I started testing
with regular strings) is that I've had similar scoping problems in perl,
where variables got out of scope within loops (or even if statements). In
perl, declaring an object outside these structures will protect it's scope.
Not so in PHP I see.
Can anyone explain this behavior? Do I have to create functions that return
values every time I need a loop that modifies a variable?
?php
class Ccust_data {
function Cform_data() {
$this-test = ;
}
}
$o = new Ccust_data();
$o-test = 1;
while ($y = 0) {
global $o-test;
$o-test = 2;
$y = 1;
}
echo \$o-test = $o-test\n;
?
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sysTame
Mac Consulting/Sales
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[PHP] scope issue?
-BEGIN PGP SIGNED MESSAGE- Hash: SHA1 Hi, I have the solution to my problem here but can't see why i need it? this snippet takes $AuthId from a form and but does not work (doesn't seem to pass it to the function) case edit: $tips-get_author($AuthId); $content=edit_author_form($tips-auth_id); break; but this works fine... case edit: $id=$AuthId; $tips-get_author($id); $content=edit_author_form($tips-auth_id); break; Why? Many thanks - -- - --- www.explodingnet.com |Projects, Forums and +Articles for website owners - -- Nick Wilson -- |and designers. -BEGIN PGP SIGNATURE- Version: GnuPG v1.0.6 (GNU/Linux) iD4DBQE8i5SQHpvrrTa6L5oRAuh7AKCmdRmslIv+sexSyW+vtuad8flu0wCXYaKt bjROMlsgU5XtiZ2ewhybJQ== =6ZTA -END PGP SIGNATURE- -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] @ Scope
When you @ "at" a command (supress error messaging) within a function, is
the scope of the @ within the function?
Example:
CloseODBC(1);
# is error message supressed here too?
function CloseODBC($connection_id)
{
# error messaging supressed
@odbc_close($connection_id);
}
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Re: [PHP] @ Scope
My understanding is, it simple supress the any messages generated from
the result. So I guess it is local.
Karl J. Stubsjoen wrote:
When you @ "at" a command (supress error messaging) within a function, is
the scope of the @ within the function?
Example:
CloseODBC(1);
# is error message supressed here too?
function CloseODBC($connection_id)
{
# error messaging supressed
@odbc_close($connection_id);
}
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Re: [PHP] @ Scope
On Wednesday 14 February 2001 17:36, Karl J. Stubsjoen wrote:
When you @ "at" a command (supress error messaging) within a function,
is the scope of the @ within the function?
Example:
CloseODBC(1);
# is error message supressed here too?
function CloseODBC($connection_id)
{
# error messaging supressed
@odbc_close($connection_id);
}
Huh?
When you call CloseODBC (), the code in that function is executed - and
there odbc_close() is called with the "@" - so it doesn't report an error.
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