RE: [PHP] Foreach question
And that's exactly how I did it :)
Since 'for' is traditionally pre-testing with excetuting the condition prior
looping it's working well :)
Thanks for all the help!
Cheers,
Tamas
-Original Message-
From: Louis Huppenbauer [mailto:louis.huppenba...@gmail.com]
Sent: Tuesday, July 05, 2011 5:47 PM
To: Robert Cummings
Cc: Dajka Tamás; php-general@lists.php.net
Subject: Re: [PHP] Foreach question
Just use count($arr) in your for-header, as it get's executed again
for each loop.
?php
$arr = array(array('id'=1), array('id'=2));
for($i=0;$icount($arr);$i++) {
echo $arr[$i]['id'];
if($i 6) {
$arr[] = array('id' = $arr[$i]['id']+1);
}
}
?
2011/7/5 Robert Cummings rob...@interjinn.com:
On 11-07-05 10:48 AM, Dajka Tamás wrote:
Thanks, that was interesting :) I think I got one step further in
understanding PHP :)
BTW, I've changed the loop to 'for' and it's working well :)
Can you show us your for loop? I'm not immediately sure how you use a for
loop to traverse a growing number of entries in an array without either
updating the extents of the traversal or using for( ; ; ) which is the same
as while( 1 ). Or are you now using the low level array traversal functions
like reset() and next()?
Cheers,
Rob.
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[PHP] Foreach question
Hi all,
I've bumped into an interesting thing with foreach. I really don't know, if
this is normal working, or why it is, so I got curious.
The script:
foreach ( $cats as $c ) {
echo $c['id'];
if ( $c['id'] 5 ) {
$c['id']++;
$cats[] = $c;
}
}
Input 1:
$cats = array( array( 'id' = 1 ) );
Output 1:
1
Input 2:
$cats = array( array( 'id' = 1 ), array( 'id' = 2 ) );
Output 2:
122334455
Why is this? Is this normal behaviour?
Thanks,
Tamas
Re: [PHP] Foreach question
Hi there
I think that foreach in your first example just knowns that this
should be the last loop (as the array only contains 1 element at
start) and so stops there.
In your 2nd example however the first loop isn't the last, so the
array get's checked again, and now there's another element, so...
I think that's more or less normal behaviour.
Sincerely yours
Louis
2011/7/5 Dajka Tamas vi...@vipernet.hu:
Hi all,
I've bumped into an interesting thing with foreach. I really don't know, if
this is normal working, or why it is, so I got curious.
The script:
foreach ( $cats as $c ) {
echo $c['id'];
if ( $c['id'] 5 ) {
$c['id']++;
$cats[] = $c;
}
}
Input 1:
$cats = array( array( 'id' = 1 ) );
Output 1:
1
Input 2:
$cats = array( array( 'id' = 1 ), array( 'id' = 2 ) );
Output 2:
122334455
Why is this? Is this normal behaviour?
Thanks,
Tamas
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Re: [PHP] Foreach question
On 11-07-05 09:40 AM, Dajka Tamas wrote:
Hi all,
I've bumped into an interesting thing with foreach. I really don't know, if
this is normal working, or why it is, so I got curious.
The script:
foreach ( $cats as$c ) {
echo $c['id'];
if ( $c['id'] 5 ) {
$c['id']++;
$cats[] = $c;
}
}
That's a bizarre loop... you're feeding references to elements of the
array back into the array over which the loop is iterating. If you
REALLY want to do what you are doing, then do the following:
?php
foreach( array_keys( $cats ) as $key )
{
$c = $cats[$key];
echo $c['id'];
if( $c['id'] 5 )
{
$c['id']++;
$cats[] = $c;
}
}
?
Cheers,
Rob.
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Re: [PHP] Foreach question
Or maybe he tried to do the following?
?php
foreach ( $cats as$c ) {
echo $c['id'];
if ($c['id'] 5) {
$cats[] = array('id' = ($c['id'] + 1));
}
}
?
2011/7/5 Robert Cummings rob...@interjinn.com:
On 11-07-05 09:40 AM, Dajka Tamas wrote:
Hi all,
I've bumped into an interesting thing with foreach. I really don't know,
if
this is normal working, or why it is, so I got curious.
The script:
foreach ( $cats as$c ) {
echo $c['id'];
if ( $c['id'] 5 ) {
$c['id']++;
$cats[] = $c;
}
}
That's a bizarre loop... you're feeding references to elements of the array
back into the array over which the loop is iterating. If you REALLY want to
do what you are doing, then do the following:
?php
foreach( array_keys( $cats ) as $key )
{
$c = $cats[$key];
echo $c['id'];
if( $c['id'] 5 )
{
$c['id']++;
$cats[] = $c;
}
}
?
Cheers,
Rob.
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RE: [PHP] Foreach question
Hi,
Yeah, I'm really want to do that, since I'm working with the elements of the
original array ( skipped that part in sample code ).
I've tried your suggestion, but it gives the same result, so on just one input
is just gives back '1'.
What troubles me, that foreach gives an inconsistent working. Why is 'foreach'
checking element count at all and working differently with different element
counts? That's not normal is my opinion. 'foreach' shouldn't do this:
if ( count($elements) == 1 ) then loop 1;
else loop normally;
and that's what is does now, since when it's more than one element it's working
like a while loop, with checking the condition before ( and after ) every run.
( if 'foreach' would check that the current run is the last one before
executing the current loop, the results would be the same with each case )
Cheers,
Tamas
-Original Message-
From: Robert Cummings [mailto:rob...@interjinn.com]
Sent: Tuesday, July 05, 2011 4:06 PM
To: Dajka Tamas
Cc: php-general@lists.php.net
Subject: Re: [PHP] Foreach question
On 11-07-05 09:40 AM, Dajka Tamas wrote:
Hi all,
I've bumped into an interesting thing with foreach. I really don't know, if
this is normal working, or why it is, so I got curious.
The script:
foreach ( $cats as$c ) {
echo $c['id'];
if ( $c['id'] 5 ) {
$c['id']++;
$cats[] = $c;
}
}
That's a bizarre loop... you're feeding references to elements of the
array back into the array over which the loop is iterating. If you
REALLY want to do what you are doing, then do the following:
?php
foreach( array_keys( $cats ) as $key )
{
$c = $cats[$key];
echo $c['id'];
if( $c['id'] 5 )
{
$c['id']++;
$cats[] = $c;
}
}
?
Cheers,
Rob.
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RE: [PHP] Foreach question
Tried, gives the same result with one element :(
What's working:
$cats = array( array( 'id' = 1 ) );
while ( $c = array_shift($cats) ) {
echo $c['id'];
if ( $c['id'] 5 ) {
$c['id']++;
$cats[] = $c;
}
}
But this is 'while' and it pops all elements from the array...
Cheers,
Tamas
-Original Message-
From: Louis Huppenbauer [mailto:louis.huppenba...@gmail.com]
Sent: Tuesday, July 05, 2011 4:12 PM
To: Robert Cummings
Cc: Dajka Tamas; php-general@lists.php.net
Subject: Re: [PHP] Foreach question
Or maybe he tried to do the following?
?php
foreach ( $cats as$c ) {
echo $c['id'];
if ($c['id'] 5) {
$cats[] = array('id' = ($c['id'] + 1));
}
}
?
2011/7/5 Robert Cummings rob...@interjinn.com:
On 11-07-05 09:40 AM, Dajka Tamas wrote:
Hi all,
I've bumped into an interesting thing with foreach. I really don't know,
if
this is normal working, or why it is, so I got curious.
The script:
foreach ( $cats as$c ) {
echo $c['id'];
if ( $c['id'] 5 ) {
$c['id']++;
$cats[] = $c;
}
}
That's a bizarre loop... you're feeding references to elements of the array
back into the array over which the loop is iterating. If you REALLY want to
do what you are doing, then do the following:
?php
foreach( array_keys( $cats ) as $key )
{
$c = $cats[$key];
echo $c['id'];
if( $c['id'] 5 )
{
$c['id']++;
$cats[] = $c;
}
}
?
Cheers,
Rob.
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Re: [PHP] Foreach question
On 11-07-05 10:20 AM, Dajka Tamás wrote:
Hi,
Yeah, I'm really want to do that, since I'm working with the elements of the
original array ( skipped that part in sample code ).
I've tried your suggestion, but it gives the same result, so on just one input
is just gives back '1'.
Ahhh... you want the behaviour of the multiple elements... I presumed
you wanted the other way around.
What troubles me, that foreach gives an inconsistent working. Why is 'foreach'
checking element count at all and working differently with different element
counts? That's not normal is my opinion. 'foreach' shouldn't do this:
if ( count($elements) == 1 ) then loop 1;
else loop normally;
and that's what is does now, since when it's more than one element it's working
like a while loop, with checking the condition before ( and after ) every run.
( if 'foreach' would check that the current run is the last one before
executing the current loop, the results would be the same with each case )
You're making an assumption that it is checking the count. It may just
be pre-determining whether another element exists for the next
iteration. Consider the following pseudo code:
nextItem = items-reset();
while( nextItem )
{
item = nextItem;
nextItem = items-next();
// Do stuff.
}
There's lots of ways to program a loop... and your PHP foreach loop is
being converted to something entirely different internally. The above
doesn't count elements, but it will result in the same behaviour as you
are experiencing.
Cheers,
Rob.
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Re: [PHP] Foreach question
I don't think that it does this: if ( count($elements) == 1 ) then loop 1; else loop normally; It's probably more something like that: $i=count($elements); loop: $i--; if($i == 0) $last_loop = true; else $last_loop = false if($last_loop) exit; else goto loop; But aside from that, I would propose you the same thing Robert already did - Just use while or some other loop (for maybe?). -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Foreach question
Ok, but if it would be that way I shouldn't get '122334455' for second output,
no? The item count increments with every iteration of the loop.
Or you're saying that, it checks for an existance of nextitem before every
loop, and that will fail with just one element, but will always return true
with two elements? ( since the first elements copy is pushed as third element,
etc )
-Original Message-
From: Robert Cummings [mailto:rob...@interjinn.com]
Sent: Tuesday, July 05, 2011 4:28 PM
To: Dajka Tamás
Cc: php-general@lists.php.net
Subject: Re: [PHP] Foreach question
On 11-07-05 10:20 AM, Dajka Tamás wrote:
Hi,
Yeah, I'm really want to do that, since I'm working with the elements of the
original array ( skipped that part in sample code ).
I've tried your suggestion, but it gives the same result, so on just one
input is just gives back '1'.
Ahhh... you want the behaviour of the multiple elements... I presumed
you wanted the other way around.
What troubles me, that foreach gives an inconsistent working. Why is
'foreach' checking element count at all and working differently with
different element counts? That's not normal is my opinion. 'foreach'
shouldn't do this:
if ( count($elements) == 1 ) then loop 1;
else loop normally;
and that's what is does now, since when it's more than one element it's
working like a while loop, with checking the condition before ( and after )
every run. ( if 'foreach' would check that the current run is the last one
before executing the current loop, the results would be the same with each
case )
You're making an assumption that it is checking the count. It may just
be pre-determining whether another element exists for the next
iteration. Consider the following pseudo code:
nextItem = items-reset();
while( nextItem )
{
item = nextItem;
nextItem = items-next();
// Do stuff.
}
There's lots of ways to program a loop... and your PHP foreach loop is
being converted to something entirely different internally. The above
doesn't count elements, but it will result in the same behaviour as you
are experiencing.
Cheers,
Rob.
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Re: [PHP] Foreach question
On 11-07-05 10:39 AM, Dajka Tamás wrote: Ok, but if it would be that way I shouldn't get '122334455' for second output, no? The item count increments with every iteration of the loop. Or you're saying that, it checks for an existance of nextitem before every loop, and that will fail with just one element, but will always return true with two elements? ( since the first elements copy is pushed as third element, etc ) Exactly... it's not counting at all. If it were, you wouldn't get to so many iterations with only 2 entries in the array. I can't remember exactly how PHP stores arrays (some kind of bucket structure), but it's likely it traverses the items like a linked list using pointers from one to the next for efficiency. Cheers, Rob. -- E-Mail Disclaimer: Information contained in this message and any attached documents is considered confidential and legally protected. This message is intended solely for the addressee(s). Disclosure, copying, and distribution are prohibited unless authorized. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Foreach question
On 11-07-05 10:39 AM, Dajka Tamás wrote: Ok, but if it would be that way I shouldn't get '122334455' for second output, no? The item count increments with every iteration of the loop. Or you're saying that, it checks for an existance of nextitem before every loop, and that will fail with just one element, but will always return true with two elements? ( since the first elements copy is pushed as third element, etc ) BTW, there are reasons you might calculate next item before iterating. If the current iteration removes the current item, then nextItem would still be valid (theoretically :). It's more often the case you might remove the current item, than try to remove the next item in a foreach iteration. Cheers, Rob. -- E-Mail Disclaimer: Information contained in this message and any attached documents is considered confidential and legally protected. This message is intended solely for the addressee(s). Disclosure, copying, and distribution are prohibited unless authorized. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Foreach question
On 11-07-05 09:40 AM, Dajka Tamas wrote:
foreach ( $cats as$c ) {
echo $c['id'];
if ( $c['id'] 5 ) {
$c['id']++;
$cats[] = $c;
}
}
Given that you seem to want the above functionality obtained when more
than one element exists in the input array... the simplest way (I can
bother to think up) to achieve what you want with little extra work is
to do the following:
?php
$cats['_control_'] = null;
foreach ( $cats as $c )
{
if( $c === null )
{
continue;
}
echo $c['id'];
if ( $c['id'] 5 )
{
$c['id']++;
$cats[] = $c;
}
}
unset( $cats['_control_'] );
?
Cheers,
Rob.
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Re: [PHP] Foreach question
On 11-07-05 10:48 AM, Dajka Tamás wrote: Thanks, that was interesting :) I think I got one step further in understanding PHP :) BTW, I've changed the loop to 'for' and it's working well :) Can you show us your for loop? I'm not immediately sure how you use a for loop to traverse a growing number of entries in an array without either updating the extents of the traversal or using for( ; ; ) which is the same as while( 1 ). Or are you now using the low level array traversal functions like reset() and next()? Cheers, Rob. -- E-Mail Disclaimer: Information contained in this message and any attached documents is considered confidential and legally protected. This message is intended solely for the addressee(s). Disclosure, copying, and distribution are prohibited unless authorized. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Foreach question
On Tue, Jul 5, 2011 at 2:40 PM, Dajka Tamas vi...@vipernet.hu wrote:
I've bumped into an interesting thing with foreach. I really don't know, if
this is normal working, or why it is, so I got curious.
The script:
foreach ( $cats as $c ) {
echo $c['id'];
if ( $c['id'] 5 ) {
$c['id']++;
$cats[] = $c;
}
}
Input 1:
$cats = array( array( 'id' = 1 ) );
Output 1:
1
Input 2:
$cats = array( array( 'id' = 1 ), array( 'id' = 2 ) );
Output 2:
122334455
Why is this? Is this normal behaviour?
Looking at the implementation of foreach in the source, the pointer to the
next item in the array is calculated after evaluating the condition but
before executing that loop. Thus, with a single array element it decides
it's at the end of the array before the first loop. My C is a little rusty
so I might have the details slightly wrong, but that's the crux of what's
happening.
Whether that's normal and expected or a bug is one of the internals team,
but my guess is that it's a feature rather than a bug.
-Stuart
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3ft9 Ltd
http://3ft9.com/
Re: [PHP] Foreach question
Just use count($arr) in your for-header, as it get's executed again
for each loop.
?php
$arr = array(array('id'=1), array('id'=2));
for($i=0;$icount($arr);$i++) {
echo $arr[$i]['id'];
if($i 6) {
$arr[] = array('id' = $arr[$i]['id']+1);
}
}
?
2011/7/5 Robert Cummings rob...@interjinn.com:
On 11-07-05 10:48 AM, Dajka Tamás wrote:
Thanks, that was interesting :) I think I got one step further in
understanding PHP :)
BTW, I've changed the loop to 'for' and it's working well :)
Can you show us your for loop? I'm not immediately sure how you use a for
loop to traverse a growing number of entries in an array without either
updating the extents of the traversal or using for( ; ; ) which is the same
as while( 1 ). Or are you now using the low level array traversal functions
like reset() and next()?
Cheers,
Rob.
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Re: [PHP] Foreach question
On 11-07-05 11:46 AM, Louis Huppenbauer wrote:
Just use count($arr) in your for-header, as it get's executed again
for each loop.
?php
$arr = array(array('id'=1), array('id'=2));
for($i=0;$icount($arr);$i++) {
echo $arr[$i]['id'];
if($i 6) {
$arr[] = array('id' = $arr[$i]['id']+1);
}
}
?
Ok, so the extents are being updated on each pass of the loop :)
Cheers,
Rob.
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[PHP] foreach question
Hey Everyone...
So I am attempting to pull 2 random records from a MySQL database, so
I wrote a function which I'll paste below. I had it mostly working
with a while() statement, but I wanted to try a foreach to see if I
could get the formatting a little bit better.
Basically... What it does is grab 2 records at random from the
database, and display the images. What I want is something that looks
like this: img1 VS img2
right now though... I'm at a lose to figure out why it's not returning
any records but not throwing any errors... Any ideas what I'm missing?
?PHP
//function for pulling random pictures from the database
function random($random){
$randomQuery = SELECT * FROM `current` ORDER BY Rand() LIMIT 2;
$result = mysql_query($randomQuery);
$row[] = $result;
foreach($row as $key = $value) {
$random[$key] = $value;
}
return $random;
}//End of function
?
Any ideas?
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Re: [PHP] foreach question
On Tue, Jul 29, 2008 at 3:25 PM, Jason Pruim [EMAIL PROTECTED] wrote:
function random($random){
$randomQuery = SELECT * FROM `current` ORDER BY Rand() LIMIT 2;
$result = mysql_query($randomQuery);
$row[] = $result;
foreach($row as $key = $value) {
$random[$key] = $value;
}
return $random;
}//End of function
?
You're missing mysql_fetch_array(), mysql_fetch_assoc(), or
something of the like.
Example:
?php
// code
$result = mysql_query($randomQuery);
$row = mysql_fetch_array($result);
foreach($row as $k = $v) {
$random[$k] = $v;
}
// code
}
?
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Re: [PHP] foreach question
You cannot do this:
$row[] = $result;
You need to loop around this:
$row = mysql_fetch_assoc($result);
Thank you,
Micah Gersten
onShore Networks
Internal Developer
http://www.onshore.com
Jason Pruim wrote:
Hey Everyone...
So I am attempting to pull 2 random records from a MySQL database, so
I wrote a function which I'll paste below. I had it mostly working
with a while() statement, but I wanted to try a foreach to see if I
could get the formatting a little bit better.
Basically... What it does is grab 2 records at random from the
database, and display the images. What I want is something that looks
like this: img1 VS img2
right now though... I'm at a lose to figure out why it's not returning
any records but not throwing any errors... Any ideas what I'm missing?
?PHP
//function for pulling random pictures from the database
function random($random){
$randomQuery = SELECT * FROM `current` ORDER BY Rand() LIMIT 2;
$result = mysql_query($randomQuery);
$row[] = $result;
foreach($row as $key = $value) {
$random[$key] = $value;
}
return $random;
}//End of function
?
Any ideas?
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Re: [PHP] foreach question
On Jul 29, 2008, at 3:33 PM, Daniel Brown wrote:
On Tue, Jul 29, 2008 at 3:25 PM, Jason Pruim [EMAIL PROTECTED]
wrote:
function random($random){
$randomQuery = SELECT * FROM `current` ORDER BY Rand() LIMIT
2;
$result = mysql_query($randomQuery);
$row[] = $result;
foreach($row as $key = $value) {
$random[$key] = $value;
}
return $random;
}//End of function
?
You're missing mysql_fetch_array(), mysql_fetch_assoc(), or
something of the like.
Example:
?php
// code
$result = mysql_query($randomQuery);
$row = mysql_fetch_array($result);
foreach($row as $k = $v) {
$random[$k] = $v;
}
// code
}
?
Added that, then changed how I was calling it and it works great
now... Thanks for looking... The problem was definitely between the
chair and the keyboard on this one.
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Re: [PHP] Foreach question
On Nov 15, 2007, at 7:50 PM, Juan Marcelo Rodríguez wrote:
2007/11/15, Philip Thompson [EMAIL PROTECTED]:
On Nov 15, 2007 5:12 PM, Juan Marcelo Rodríguez
[EMAIL PROTECTED]
wrote:
Yes, I made a mistake in the first sentence.
The code is :
[...]
foreach ($equipos as $key = $val){
echo trtd;
echo 1 . /tdtd; // I would like to add the counter here
reeplacing
1
echo trtd.($key+1)./tdtd;
This is assuming $key starts at 0 and increments by 1 each
iteration
However, if you can't assume that, just have a separate counter:
?php
$counter = 0;
foreach ($a as $b = $c) {
echo trtd.(++$counter)./tdtd;
...
}
very good idea.
It also assumes that the array in numerically indexed and corresponds
to the value you expect. The counter is safer.
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[PHP] Foreach question
HI, I'm working with an associative array, and generating its data a form. I use foreach to loops the contents of the array and echo to print the table and the data. Everything goes well, however I would like to add a counter to print the row's number. The question : Am I able to add a counter within foreach to print the row number in each row using echo ?. I tried a few things but I couldn't. Thanks! Juan
Re: [PHP] Foreach question
Yes, I made a mistake in the first sentence.
The code is :
[...]
foreach ($equipos as $key = $val){
echo trtd;
echo 1 . /tdtd; // I would like to add the counter here reeplacing
1
print input type=\radio\ name=$key value=\l\ / . /tdtd;
echo $key . /tdtd;
print input type=\radio\ name=$key value=\e\ / . /tdtd;
echo $val . /tdtd;
print input type=\radio\ name=$key value=\b\ / . /tdtd;
}
?
I use the array to generate the name of the radio and so on. However I had
problems with the counter.
Thanks
2007/11/15, Stut [EMAIL PROTECTED]:
Juan Marcelo Rodríguez wrote:
I'm working with an associative array, and generating its data a form. I
use
foreach to loops the contents of the array and echo to print the table
and
the data. Everything goes well, however I would like to add a counter to
print the row's number.
The question : Am I able to add a counter within foreach to print the
row
number in each row using echo ?. I tried a few things but I couldn't.
The mind boggles when wondering what you tried.
$counter = 1;
foreach ($array as $val)
{
// Do your stuff here
// Increment the counter
$counter++;
}
-Stut
--
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Re: [PHP] Foreach question
2007/11/15, Philip Thompson [EMAIL PROTECTED]:
On Nov 15, 2007 5:12 PM, Juan Marcelo Rodríguez
[EMAIL PROTECTED]
wrote:
Yes, I made a mistake in the first sentence.
The code is :
[...]
foreach ($equipos as $key = $val){
echo trtd;
echo 1 . /tdtd; // I would like to add the counter here
reeplacing
1
echo trtd.($key+1)./tdtd;
This is assuming $key starts at 0 and increments by 1 each iteration
However, if you can't assume that, just have a separate counter:
?php
$counter = 0;
foreach ($a as $b = $c) {
echo trtd.(++$counter)./tdtd;
...
}
very good idea.
thanks!
Juan
HTH
~Philip
Re: [PHP] Foreach question (solved)
Thanks.
I solved it using this :
$x = 0;
foreach ($equipos as $key = $val){
$x = $x + 1;
echo trtd;
echo $x . /tdtd;
2007/11/15, Michael McGlothlin [EMAIL PROTECTED]:
$x = 0;
foreach ( $blah as $bleh ) {
$x = $x + 1;
print $x: $bleh;
}
HI,
I'm working with an associative array, and generating its data a form. I
use
foreach to loops the contents of the array and echo to print the table
and
the data. Everything goes well, however I would like to add a counter to
print the row's number.
The question : Am I able to add a counter within foreach to print the
row
number in each row using echo ?. I tried a few things but I couldn't.
Thanks!
Juan
--
Michael McGlothlin
Southwest Plumbing Supply
Re: [PHP] Foreach question
On Nov 15, 2007 5:12 PM, Juan Marcelo Rodríguez [EMAIL PROTECTED]
wrote:
Yes, I made a mistake in the first sentence.
The code is :
[...]
foreach ($equipos as $key = $val){
echo trtd;
echo 1 . /tdtd; // I would like to add the counter here
reeplacing
1
echo trtd.($key+1)./tdtd;
This is assuming $key starts at 0 and increments by 1 each iteration
However, if you can't assume that, just have a separate counter:
?php
$counter = 0;
foreach ($a as $b = $c) {
echo trtd.(++$counter)./tdtd;
...
}
HTH
~Philip
Re: [PHP] Foreach question
Juan Marcelo Rodríguez wrote:
I'm working with an associative array, and generating its data a form. I use
foreach to loops the contents of the array and echo to print the table and
the data. Everything goes well, however I would like to add a counter to
print the row's number.
The question : Am I able to add a counter within foreach to print the row
number in each row using echo ?. I tried a few things but I couldn't.
The mind boggles when wondering what you tried.
$counter = 1;
foreach ($array as $val)
{
// Do your stuff here
// Increment the counter
$counter++;
}
-Stut
--
http://stut.net/
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Re: [PHP] Foreach question
$x = 0;
foreach ( $blah as $bleh ) {
$x = $x + 1;
print $x: $bleh;
}
HI,
I'm working with an associative array, and generating its data a form. I use
foreach to loops the contents of the array and echo to print the table and
the data. Everything goes well, however I would like to add a counter to
print the row's number.
The question : Am I able to add a counter within foreach to print the row
number in each row using echo ?. I tried a few things but I couldn't.
Thanks!
Juan
--
Michael McGlothlin
Southwest Plumbing Supply
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Re: [PHP] foreach question
On Sun, April 8, 2007 6:29 pm, [EMAIL PROTECTED] wrote:
I have ..
foreach( $_POST as $key ) {
echo $keybr /;
}
You are actually echoing out the VALUE, not the KEY...
and that gives me
item1
item2
item3
item4
item5br /
Unless your VALUE has item1\nitem2\nitem3\nitem4\nitem5 in it, I
don't how this could happen...
Use view source in your browser.
--
Some people have a gift link here.
Know what I want?
I want you to buy a CD from some indie artist.
http://cdbaby.com/browse/from/lynch
Yeah, I get a buck. So?
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Re: [PHP] foreach question
Quoting Lori Lay [EMAIL PROTECTED]:
[EMAIL PROTECTED] wrote:
Sorry this is the full script...
whois.php
html
bodyspan style=font-size:13;font-family:Arial,Verdana;
form method='POST' action='whois.php'
pbEnter Domain Names (one per line)/b/p
textarea name='domain' cols=50 rows=8
style=font-size:13;font-family:Arial,Verdana;/textareap
Gotcha! A textarea does not produce an array. Even though the user
should be separating the lines with a line break, this turns into one
long string with line breaks in it, not separate array elements. You
will have to do this manually. Actually, you could probably use nl2br
to insert BR's before the line breaks (it doesn't replace them, but
that's usually good enough).
Lori
much better, it all makes sense now. This is what I would do:
?php
$array = split(\n, $_POST['domain']);
foreach( $array as $key ) {
echo $keybr;
}
?
Siavash
input type='submit' value=Submit Domain Query
/form
pbuWhois Results:/u/b/p
?php
foreach( $_POST as $key ) {
echo $keybr;
}
?
/body
/html
- Original Message - From: Lori Lay [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Cc: php-general@lists.php.net
Sent: Monday, April 09, 2007 5:20 AM
Subject: Re: [PHP] foreach question
[EMAIL PROTECTED] wrote:
both examples do the same thing..
no, ex1 only has 1 br /
so outputs like..
item1item2item3item4item5br /
Where as I want this..
item1br /
item2br /
item3br /
item4br /
item5br /
ie a line break after every item.
Silly question, perhaps, but are you sure $_POST is an array (with 5
elements)? What you have written should produce a break after each
item if POST is a 5 element array. However if POST is a single
element with the five items concatenated together, then they would be
printed the way you have it listed above...
It might be better to post the full script to the list.
Lori
- Original Message - From: Sebe [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Cc: php-general@lists.php.net
Sent: Monday, April 09, 2007 1:22 AM
Subject: Re: [PHP] foreach question
[EMAIL PROTECTED] wrote:
I have ..
foreach( $_POST as $key ) {echo $keybr /;
}
and that gives me
item1
item2
item3
item4
item5br /
how do I write it to give me
item1br /
item2br /
item3br /
item4br /
item5br /
Thanks
both examples do the same thing..
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[PHP] foreach question
I have ..
foreach( $_POST as $key ) {
echo $keybr /;
}
and that gives me
item1
item2
item3
item4
item5br /
how do I write it to give me
item1br /
item2br /
item3br /
item4br /
item5br /
Thanks
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Re: [PHP] foreach question
[EMAIL PROTECTED] wrote:
I have ..
foreach( $_POST as $key ) {echo $keybr /;
}
and that gives me
item1
item2
item3
item4
item5br /
how do I write it to give me
item1br /
item2br /
item3br /
item4br /
item5br /
Thanks
both examples do the same thing..
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Re: [PHP] foreach question
both examples do the same thing..
no, ex1 only has 1 br /
so outputs like..
item1item2item3item4item5br /
Where as I want this..
item1br /
item2br /
item3br /
item4br /
item5br /
ie a line break after every item.
- Original Message -
From: Sebe [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Cc: php-general@lists.php.net
Sent: Monday, April 09, 2007 1:22 AM
Subject: Re: [PHP] foreach question
[EMAIL PROTECTED] wrote:
I have ..
foreach( $_POST as $key ) {echo $keybr /;
}
and that gives me
item1
item2
item3
item4
item5br /
how do I write it to give me
item1br /
item2br /
item3br /
item4br /
item5br /
Thanks
both examples do the same thing..
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Re: [PHP] foreach question
[EMAIL PROTECTED] wrote:
both examples do the same thing..
no, ex1 only has 1 br /
so outputs like..
item1item2item3item4item5br /
Where as I want this..
item1br /
item2br /
item3br /
item4br /
item5br /
ie a line break after every item.
hmm, if you're getting 5 results from the loop each should already have
a br /
so i dont understand what is wrong but the code it's set to put out a
line break after each item. maybe i'm blind but the code is fine (with
the exception that i don't use double quotes).
- Original Message - From: Sebe [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Cc: php-general@lists.php.net
Sent: Monday, April 09, 2007 1:22 AM
Subject: Re: [PHP] foreach question
[EMAIL PROTECTED] wrote:
I have ..
foreach( $_POST as $key ) {echo $keybr /;
}
and that gives me
item1
item2
item3
item4
item5br /
how do I write it to give me
item1br /
item2br /
item3br /
item4br /
item5br /
Thanks
both examples do the same thing..
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Re: [PHP] foreach question
Your code is fine and it should work.
but in any case, try:
foreach ($_POST as $key){
echo $key . 'br /';
}
Also, what php version, and what browser are you using?
good luck,
Siavash
[EMAIL PROTECTED] wrote:
both examples do the same thing..
no, ex1 only has 1 br /
so outputs like..
item1item2item3item4item5br /
Where as I want this..
item1br /
item2br /
item3br /
item4br /
item5br /
ie a line break after every item.
hmm, if you're getting 5 results from the loop each should already have
a br /
so i dont understand what is wrong but the code it's set to put out a
line break after each item. maybe i'm blind but the code is fine (with
the exception that i don't use double quotes).
- Original Message - From: Sebe [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Cc: php-general@lists.php.net
Sent: Monday, April 09, 2007 1:22 AM
Subject: Re: [PHP] foreach question
[EMAIL PROTECTED] wrote:
I have ..
foreach( $_POST as $key ) {echo $keybr /;
}
and that gives me
item1
item2
item3
item4
item5br /
how do I write it to give me
item1br /
item2br /
item3br /
item4br /
item5br /
Thanks
both examples do the same thing..
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Re: [PHP] foreach question
[EMAIL PROTECTED] wrote:
both examples do the same thing..
no, ex1 only has 1 br /
so outputs like..
item1item2item3item4item5br /
Where as I want this..
item1br /
item2br /
item3br /
item4br /
item5br /
ie a line break after every item.
Silly question, perhaps, but are you sure $_POST is an array (with 5
elements)? What you have written should produce a break after each item
if POST is a 5 element array. However if POST is a single element with
the five items concatenated together, then they would be printed the way
you have it listed above...
It might be better to post the full script to the list.
Lori
- Original Message - From: Sebe [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Cc: php-general@lists.php.net
Sent: Monday, April 09, 2007 1:22 AM
Subject: Re: [PHP] foreach question
[EMAIL PROTECTED] wrote:
I have ..
foreach( $_POST as $key ) {echo $keybr /;
}
and that gives me
item1
item2
item3
item4
item5br /
how do I write it to give me
item1br /
item2br /
item3br /
item4br /
item5br /
Thanks
both examples do the same thing..
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Re: [PHP] foreach question
Sorry this is the full script...
whois.php
html
bodyspan style=font-size:13;font-family:Arial,Verdana;
form method='POST' action='whois.php'
pbEnter Domain Names (one per line)/b/p
textarea name='domain' cols=50 rows=8
style=font-size:13;font-family:Arial,Verdana;/textareap
input type='submit' value=Submit Domain Query
/form
pbuWhois Results:/u/b/p
?php
foreach( $_POST as $key ) {
echo $keybr;
}
?
/body
/html
- Original Message -
From: Lori Lay [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Cc: php-general@lists.php.net
Sent: Monday, April 09, 2007 5:20 AM
Subject: Re: [PHP] foreach question
[EMAIL PROTECTED] wrote:
both examples do the same thing..
no, ex1 only has 1 br /
so outputs like..
item1item2item3item4item5br /
Where as I want this..
item1br /
item2br /
item3br /
item4br /
item5br /
ie a line break after every item.
Silly question, perhaps, but are you sure $_POST is an array (with 5
elements)? What you have written should produce a break after each item
if POST is a 5 element array. However if POST is a single element with
the five items concatenated together, then they would be printed the way
you have it listed above...
It might be better to post the full script to the list.
Lori
- Original Message - From: Sebe [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Cc: php-general@lists.php.net
Sent: Monday, April 09, 2007 1:22 AM
Subject: Re: [PHP] foreach question
[EMAIL PROTECTED] wrote:
I have ..
foreach( $_POST as $key ) {echo $keybr /;
}
and that gives me
item1
item2
item3
item4
item5br /
how do I write it to give me
item1br /
item2br /
item3br /
item4br /
item5br /
Thanks
both examples do the same thing..
--
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Re: [PHP] foreach question
[EMAIL PROTECTED] wrote:
Sorry this is the full script...
whois.php
html
bodyspan style=font-size:13;font-family:Arial,Verdana;
form method='POST' action='whois.php'
pbEnter Domain Names (one per line)/b/p
textarea name='domain' cols=50 rows=8
style=font-size:13;font-family:Arial,Verdana;/textareap
Gotcha! A textarea does not produce an array. Even though the user
should be separating the lines with a line break, this turns into one
long string with line breaks in it, not separate array elements. You
will have to do this manually. Actually, you could probably use nl2br
to insert BR's before the line breaks (it doesn't replace them, but
that's usually good enough).
Lori
input type='submit' value=Submit Domain Query
/form
pbuWhois Results:/u/b/p
?php
foreach( $_POST as $key ) {
echo $keybr;
}
?
/body
/html
- Original Message - From: Lori Lay [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Cc: php-general@lists.php.net
Sent: Monday, April 09, 2007 5:20 AM
Subject: Re: [PHP] foreach question
[EMAIL PROTECTED] wrote:
both examples do the same thing..
no, ex1 only has 1 br /
so outputs like..
item1item2item3item4item5br /
Where as I want this..
item1br /
item2br /
item3br /
item4br /
item5br /
ie a line break after every item.
Silly question, perhaps, but are you sure $_POST is an array (with 5
elements)? What you have written should produce a break after each
item if POST is a 5 element array. However if POST is a single
element with the five items concatenated together, then they would be
printed the way you have it listed above...
It might be better to post the full script to the list.
Lori
- Original Message - From: Sebe [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Cc: php-general@lists.php.net
Sent: Monday, April 09, 2007 1:22 AM
Subject: Re: [PHP] foreach question
[EMAIL PROTECTED] wrote:
I have ..
foreach( $_POST as $key ) {echo $keybr /;
}
and that gives me
item1
item2
item3
item4
item5br /
how do I write it to give me
item1br /
item2br /
item3br /
item4br /
item5br /
Thanks
both examples do the same thing..
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