RE: Clause 2.10.3.3 of EN 60950-1:2006

2007-07-03 Thread emc-p...@ieee.org
All -

Let no one feel they can not impact standards development, even without
attending meetings.

After a few e-mails and one telephone call, I submit the following.

§2.10.3.3:

A very simple edit to the text is being proposed to make the application of
Table 2K and 2L clear.  Specifically (asterisks surrounding added text):

b) if the peak working voltage exceeds the peak value of the ac mains supply
voltage, the minimum clearance is the sum of the following two values:
* the minimum clearance from Table 2K **using a value for the peak 
working
voltage that is equal to the peak of the ac mains supply voltage**; and
* the appropriate additional clearance from Table 2L **using the value 
of
the peak working voltage**.


A couple of other insulation issues discussed in this forum were also
discussed.


LINEAR INTERPOLATION:

Linear interpolation for the values of Creepage Distance smaller than 0.1 mm,
are required to round up to the nearest 0.1 mm.  For values in Table 2N for
smaller than 0.1 mm (those for boards), an editorial change will make it clear
that, if rms working voltage falls between two values, use the next higher
Creepage Distance *or* round up to the nearest 0.1 mm.  As it turns out, this
was already in the works.


CLEARANCES TRUMPING CREEPAGE DISTANCES:

The last point (on interpolation) may be unworthy of debate, considering that,
with the addition of the small Creepage Distances allowed for boards, the
conflict that no Creepage Distance may be smaller than the otherwise required
Clearance will not be resolved soon.  Those who may recall or wish to look
into the matter on their own, will find that the smallest Clearances anywhere
in the standard are 16×, 8× and 4× (Tables 2K, 2M and G.2, respectively)
larger than the smallest Creepage Distance in Table 2N.

As it turns out, the very presence of the two columns for boards in Table 2N
is being debated, with advocates to remove them and to keep them.  As
represented to me, at issue is the practical concern of being able to measure
small Creepage Distances.  I have pointed out that there are freeware and
shareware software tools available, if the test houses are too frugal to
purchase the readily available optical instruments.

Finally, in the columns in Table 2N applicable to boards, for Pollution Degree
2, Material Group IIIb was intentionally left out.  I asked for a note similar
to the note already in the Conditions to Table 2N for Material Group IIIb in
Pollution Degree 3.  No response was given for this item, so it may be left
hanging and accepted as understood.


Regards,

Peter L. Tarver, PE
ptar...@ieee.org 

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RE: Clause 2.10.3.3 of EN 60950-1:2006

2007-06-29 Thread emc-p...@ieee.org
Hi Peter,

I think the way you read the standard is the most natural reading, but
the final answer isn't really clear from the standard alone.  It would
seem that the penalty for the extra volt of peak voltage (from 420 V to
421 V) is double what it should be (0.2 mm vs. 0.1mm).

If you get feedback from the US TAG member on this issue, please share!

Scott Aldous
Compliance Engineer
Advanced Energy
Tel: 970-407-6872
Fax: 970-407-5872


From: emc-p...@ieee.org [mailto:emc-p...@ieee.org] On Behalf Of Tarver,
Peter
Sent: Friday, June 29, 2007 2:01 PM
To: emc-p...@ieee.org
Subject: RE: Clause 2.10.3.3 of EN 60950-1:2006

 From: Tarver, Peter
 Sent: Friday, June 29, 2007 12:00 PM

Man, did I mess this up.  See  my corrections, below.

 For an AC MAINS SUPPLY not exceeding 300 V r.m.s. (420 V peak):
 
 b) if the PEAK WORKING VOLTAGE exceeds the peak value of the 
 AC MAINS SUPPLY voltage, ...
 
 If we have an ac mains rated up to 300 V (420 Vpk), and we 
 measure a peak voltage across a piece of insulation in the 
 primary circuit at 421 Vpk ... 
 
  ... the minimum CLEARANCE is the sum of the following two values:
 * the minimum CLEARANCE from Table 2K; and
 * the appropriate additional CLEARANCE from Table 2L
 
 What then have is:
 
 Vb = 421 Vpk, clearance = 4.1 mm (interpolating and rounding 
 up to the nearest 0.1 mm) + 


0.1 mm (interpolating and rounding up to the nearest 0.1 mm) = 4.2 mm.


I'm going through a few test cases for my own benefit and I am in the
process of writing a US TAG member to TC108 that is already addressing
clearance and creepage distances problems in the 2nd ed.

Regards,

Peter L. Tarver, PE
ptar...@ieee.org 

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RE: Clause 2.10.3.3 of EN 60950-1:2006

2007-06-29 Thread emc-p...@ieee.org
 From: Tarver, Peter
 Sent: Friday, June 29, 2007 12:00 PM

Man, did I mess this up.  See  my corrections, below.

 For an AC MAINS SUPPLY not exceeding 300 V r.m.s. (420 V peak):
 
 b) if the PEAK WORKING VOLTAGE exceeds the peak value of the 
 AC MAINS SUPPLY voltage, ...
 
 If we have an ac mains rated up to 300 V (420 Vpk), and we 
 measure a peak voltage across a piece of insulation in the 
 primary circuit at 421 Vpk ... 
 
  ... the minimum CLEARANCE is the sum of the following two values:
 * the minimum CLEARANCE from Table 2K; and
 * the appropriate additional CLEARANCE from Table 2L
 
 What then have is:
 
 Vb = 421 Vpk, clearance = 4.1 mm (interpolating and rounding 
 up to the nearest 0.1 mm) + 


0.1 mm (interpolating and rounding up to the nearest 0.1 mm) = 4.2 mm.


I'm going through a few test cases for my own benefit and I am in the
process of writing a US TAG member to TC108 that is already addressing
clearance and creepage distances problems in the 2nd ed.

Regards,

Peter L. Tarver, PE
ptar...@ieee.org 

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RE: Clause 2.10.3.3 of EN 60950-1:2006

2007-06-29 Thread emc-p...@ieee.org
 From: Aldous, Scott
 Sent: Friday, June 29, 2007 9:48 AM
  

Looking over the two versions of the standard, I can see that you're
correctly interpreting the 1st ed., but the 2nd ed. text changed things
all over the place in the insulation area.  I don't know if that was
MT2's intent, but that's the effect of either their intent or bad
standards writing leading to misinterpretations.  

At the risk of the wrath of the Gods on Mount Copyright, I'm going to
directly quote the standard, so we can better review the text and work
through an exercise, based on the 2nd ed. text.

For an AC MAINS SUPPLY not exceeding 300 V r.m.s. (420 V peak):

a) if the PEAK WORKING VOLTAGE does not exceed the peak value of the AC
MAINS SUPPLY voltage, minimum CLEARANCES are determined from Table 2K;

That seems plain enough; if the peak voltage across the insulation being
evaluated is less than or equal to the peak voltage of the ac mains,
only Table 2K applies.  Let's say we're at 420 Vpk:

Va = 420 Vpk, clearance = 4.0 mm for RI

A minor rearrangement:

For an AC MAINS SUPPLY not exceeding 300 V r.m.s. (420 V peak):

b) if the PEAK WORKING VOLTAGE exceeds the peak value of the AC MAINS
SUPPLY voltage, ...

If we have an ac mains rated up to 300 V (420 Vpk), and we measure a
peak voltage across a piece of insulation in the primary circuit at 421
Vpk ... 

 ... the minimum CLEARANCE is the sum of the following two values:
* the minimum CLEARANCE from Table 2K; and
* the appropriate additional CLEARANCE from Table 2L

What then have is:

Vb = 421 Vpk, clearance = 4.1 mm (interpolating and rounding up to the
nearest 0.1 mm) + 0.6 mm (interpolating and rounding up to the nearest
0.1 mm) = 4.7 mm.

I'm saying that the 2nd ed. is looking only at the peak voltage across
the insulation as the fulcrum where one derives the appropriate
clearance and sets aside the (clearer) method from the 1st ed.

 [SCOTT]: It would seem that we may be on the same page, 
 though perhaps I did not explain myself clearly after all.  
 So in the end, I still feel the conclusion offered by Nick's 
 customer is not correct.  Do you agree?  I'm not completely 
 sure that you do - it seems the point we still may disagree 
 on is what peak voltage to use when applying table 2K to the 
 point in Nick's circuit where the 840Vpk is present.

If we are to take an historical perspective, Nick's customer *might* be
incorrect and what we see in the 2nd ed. is the result of bad standards
writing.  However, considering the present text in a vacuum, Nick's
customer's interpretation seems correct.  Considering all of the other
bleepity-bleep bleeps MT2 threw into the clearance and creepage
requirements for the 2nd ed., you may be entirely right and Nick's
customer wrong.

The more I think about it, the more I think MT2 blew it.


Regards,

Peter L. Tarver, PE
ptar...@ieee.org 

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RE: Clause 2.10.3.3 of EN 60950-1:2006

2007-06-29 Thread emc-p...@ieee.org
Thanks Peter for your comments.  Mine interspersed below.

Scott Aldous
Compliance Engineer
Advanced Energy
Tel: 970-407-6872
Fax: 970-407-5872


 I wonder what peak working voltage should be used in table 2K 
 - the actual peak voltage or the peak voltage based on the 
 mains rms voltage?

[PETER]: If you look at the leading ¶s in §2.10.3.3, you can see answer to
that question.

[SCOTT]: I'm not sure I follow what you mean.

[PETER]: Table 2K is written assuming the peak voltage is exclusively from the
ac mains.  

[SCOTT]: Exactly.  Which is why I wonder if only the AC mains peak voltage
should be used when deriving a clearance from this table (except for the last
line of 2.10.3.3 which provides the exception).

[PETER]: The other peak working voltages (nee: peak repetitive voltages) are
from  primary circuit monkey business, but isn't new (see 60950-1, 1st ed,
§2.10.3.2, Tables 2H and 2J).

[SCOTT]: Correct, and the previous standard specifically states in 2.10.3.2
(first 2 dashes) that the clearance is the sum of:

- the minimum CLEARANCE value from table 2H for a WORKING VOLTAGE equal to
the AC MAINS SUPPLY voltage; and
- the appropriate additional CLEARANCE value from table 2J.

Pay particular attention to the verbiage between the asterisks that I added.

[PETER]: It depends on where the insulation is that the working voltage is
measured across.  Before the rectifier in a SMPS, which is similar to your
example, it would be appropriate to ignore Table 2L altogether.  In this case,
the minimum Clearance for Reinforced Insulation is 4.0 mm.

Much deeper into an SMPS from the rectifier, peak repetitive voltage crop up
that exceed those from the ac mains.

[SCOTT]: This seems like a better explanation than I have offered, but much
the same as my own thoughts.  I don't believe this contradicts the
interpretation I have offered.  In general, one would expect to find a peak
voltage higher than the standard mains peak only a bit deeper into the
circuitry.  I would assume that this is the case for Nick's example.  Where
such peaks exist, it would make sense to add the additional clearance from
table 2L to the base clearance from table 2K based on the mains peak voltage
only.  In this case 4.0mm + 1.2mm for a total of 5.2mm.

 Then, for the 400V mains, one would use table 2K only, based 
 on 840Vpk, giving 6.4mm for reinforced.

[PETER]: But where is the 840 Vpk coming from and where is it measured?  Not
the ac mains, which for a 400 V supply is 566 Vpk, leading to a or 4.8 mm
interpolated value (or 6.4 mm noninterpolated).  Assuming the 840 Vpk is in
the SMPS somewhere, 6.4 mm would apply only where it's present.

[SCOTT]: I think your interpretation above is correct, and coincides with what
I have offered.

 More intuitive, but is this the proper interpretation? 

[PETER]: I'd say not improper, but maybe not complete.

[SCOTT]: It would seem that we may be on the same page, though perhaps I did
not explain myself clearly after all.  So in the end, I still feel the
conclusion offered by Nick's customer is not correct.  Do you agree?  I'm not
completely sure that you do - it seems the point we still may disagree on is
what peak voltage to use when applying table 2K to the point in Nick's circuit
where the 840Vpk is present.


Regards,

Peter L. Tarver, PE
ptar...@ieee.org 

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RE: Clause 2.10.3.3 of EN 60950-1:2006

2007-06-29 Thread emc-p...@ieee.org
 From: Aldous, Scott
 Sent: Friday, June 29, 2007 8:56 AM
 
 Bummer - I was referring to an older version of the IEC 
 standard (60950-1:2001).

I kinda thought something like that.  With the 2nd ed of IEC 60950-1, the
clearance and creepage distances went through a huge rewrite.

 I wonder what peak working voltage should be used in table 2K 
 - the actual peak voltage or the peak voltage based on the 
 mains rms voltage?

If you look at the leading ¶s in §2.10.3.3, you can see answer to that
question.

 It doesn't seem to make sense that if table 2K already takes 
 into account higher peak voltages than one normally has, that 
 one would need to add additional clearance per table 2L.

Table 2K is written assuming the peak voltage is exclusively from the ac
mains.  The other peak working voltages (nee: peak repetitive voltages) are
from primary circuit monkey business, but isn't new (see 60950-1, 1st ed,
§2.10.3.2, Tables 2H and 2J).

 If one assumes nominal peak voltage on 230V of 230*1.414 = 
 about 325V, ignoring interpolation and using peak of 420, 
 then one obtains 4.0mm for reinforced plus the 1.2 from table 
 2L for a total of 5.2mm.

It depends on where the insulation is that the working voltage is measured
across.  Before the rectifier in a SMPS, which is similar to your example, it
would be appropriate to ignore Table 2L altogether.  In this case, the minimum
Clearance for Reinforced Insulation is 4.0 mm.

Much deeper into an SMPS from the rectifier, peak repetitive voltage crop up
that exceed those from the ac mains.

 Then, for the 400V mains, one would use table 2K only, based 
 on 840Vpk, giving 6.4mm for reinforced.

But where is the 840 Vpk coming from and where is it measured?  Not the ac
mains, which for a 400 V supply is 566 Vpk, leading to a or 4.8 mm
interpolated value (or 6.4 mm noninterpolated).  Assuming the 840 Vpk is in
the SMPS somewhere, 6.4 mm would apply only where it's present.

 More intuitive, but is this the proper interpretation? 

I'd say not improper, but maybe not complete.


Regards,

Peter L. Tarver, PE
ptar...@ieee.org 

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RE: Clause 2.10.3.3 of EN 60950-1:2006

2007-06-29 Thread emc-p...@ieee.org
Bummer - I was referring to an older version of the IEC standard
(60950-1:2001).  Everyone, please ignore my previous post (just when you
get comfortable with a standard, they go and change it!).  I assumed
secondary circuit because of the table number (per the old standard).

Now, looking at the correct standard (hopefully!)...

I wonder what peak working voltage should be used in table 2K - the
actual peak voltage or the peak voltage based on the mains rms voltage?
It doesn't seem to make sense that if table 2K already takes into
account higher peak voltages than one normally has, that one would need
to add additional clearance per table 2L.

If one assumes nominal peak voltage on 230V of 230*1.414 = about 325V,
ignoring interpolation and using peak of 420, then one obtains 4.0mm for
reinforced plus the 1.2 from table 2L for a total of 5.2mm.

Then, for the 400V mains, one would use table 2K only, based on 840Vpk,
giving 6.4mm for reinforced.

More intuitive, but is this the proper interpretation? 

Scott Aldous
Compliance Engineer
Advanced Energy
Tel: 970-407-6872
Fax: 970-407-5872


From: emc-p...@ieee.org [mailto:emc-p...@ieee.org] On Behalf Of Tarver,
Peter
Sent: Friday, June 29, 2007 9:36 AM
To: srichard...@blackwood-labs.co.uk; emc-p...@ieee.org
Subject: RE: Clause 2.10.3.3 of EN 60950-1:2006

Good morning, Scott.

 From: Aldous, Scott
 Sent: Friday, June 29, 2007 8:18 AM
 
 Table 2L is for minimum creepage distances, not clearance.

I don't know which version of EN 60950-1 you're referring to, but in the
2006 version, Table 2L most certainly applies to clearances.
  
 I see nothing in 60950-1 that indicates values from table 2L 
 are to be added to values from table 2K for clearances in 
 secondary circuits.

Maybe I missed something.  Where were secondary circuits mentioned in
the OP?  Since Table 2K is for clearances in primary circuits and
between primary and secondary circuits, and that all references were to
mains voltages (as far as I could tell), I don't think clearances _in_
secondary circuits (which would invoke Table 2M) are involved in the
question.


Regards,

Peter L. Tarver, PE
ptar...@ieee.org 

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RE: Clause 2.10.3.3 of EN 60950-1:2006

2007-06-29 Thread emc-p...@ieee.org
Good morning, Scott.

 From: Aldous, Scott
 Sent: Friday, June 29, 2007 8:18 AM
 
 Table 2L is for minimum creepage distances, not clearance.

I don't know which version of EN 60950-1 you're referring to, but in the
2006 version, Table 2L most certainly applies to clearances.
  
 I see nothing in 60950-1 that indicates values from table 2L 
 are to be added to values from table 2K for clearances in 
 secondary circuits.

Maybe I missed something.  Where were secondary circuits mentioned in
the OP?  Since Table 2K is for clearances in primary circuits and
between primary and secondary circuits, and that all references were to
mains voltages (as far as I could tell), I don't think clearances _in_
secondary circuits (which would invoke Table 2M) are involved in the
question.


Regards,

Peter L. Tarver, PE
ptar...@ieee.org 

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RE: Clause 2.10.3.3 of EN 60950-1:2006

2007-06-29 Thread emc-p...@ieee.org
 From: Nick Williams
 Sent: Friday, June 29, 2007 5:21 AM
 
 Compare the two scenarios...
 1. Say mains is 230V, i.e. below 300V so add clearances from 
 Table 2K 
 and 2L. Say peak working voltage is 840V. Clearance is 6.4+1.2=7.6mm 

From Table 2K, for a 840 Vpk working voltage across some bit of
Reinforced Insulation, 6.4 mm is correct.

For a 230V mains in Category II, Table 2J assumes a mains transient of
2,500 Vpk.

For Pollution Degree 3, the additional Clearance from Table 2L is 1.2
mm.

Your customer's interpretation appears correct.

 2. Say mains is 400V, i.e above 300V so minimum CLEARANCES 
 are determined 
 from Table 2K. No mention of adding value from Table 2L.
 The mains transient voltage class is 4000V, which means that 
 table 2K 
 calls up larger clearances for voltages below 840V, but at 840V and 
 above it makes no difference. Therefore clearance is 6.4mm.

That's the way the standard reads.

 Can't be right, can it?

It's Chiffon.  (a regional advertisement reference.)

 This isn't an academic pursuit; we urgently need to know so 
 thanks very 
 much for any comments.

Why this is the way it is, I really don't know, but must be based on TC
108's interpretation of IEC 60664-x, of which I have only an old copy.
Your customer can pursue this through either reviewing IEC 60664-x or
referring to Annex G of 60950-1.


Regards,

Peter L. Tarver, PE
ptar...@ieee.org 

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RE: Clause 2.10.3.3 of EN 60950-1:2006

2007-06-29 Thread emc-p...@ieee.org
Table 2L is for minimum creepage distances, not clearance.  I see
nothing in 60950-1 that indicates values from table 2L are to be added
to values from table 2K for clearances in secondary circuits.

Assuming (as 60950-1 does) that the overvoltage category of the product
is II, then:

Scenario 1

Mains voltage = 230V, giving a clearance of 5.0mm for reinforced (table
2K, based on 840V peak voltage)

Scenario 2

Mains voltage = 400V, giving a clearance of 5.0mm for reinforced (table
2K, based on 840V peak voltage)

It does seem counterintuitive that these numbers are the same, but
that's the way the standard is written.  It would also be the same
number for a secondary circuit not subject to transient overvoltages!
Maybe with a significantly boosted secondary voltage, transient effects
reaching the secondary from mains are less significant than the value of
working voltage itself?

Something to consider - is the mains voltage of 400V in question 400V
with reference to ground, or is this a 3 phase voltage?

Also, one must keep in mind the minimum 10mm air gap required for
reinforced between hazardous voltage and an accessible conductive part
of the enclosure of floor-standing equipment, or of the non-vertical top
surface of desk top equipment (should this apply).

Scott Aldous
Compliance Engineer
Advanced Energy
Tel: 970-407-6872
Fax: 970-407-5872

From: emc-p...@ieee.org [mailto:emc-p...@ieee.org] On Behalf Of Steve
Richardson
Sent: Friday, June 29, 2007 7:58 AM
To: emc-p...@ieee.org
Subject: RE: Clause 2.10.3.3 of EN 60950-1:2006

Hi Nick,

As I see it the clearance would be calculated as follows;

Scenario 1

Mains voltage = 230V (mains transient voltage is 2500V) giving a
clearance of 4.0 mm (table 2K) for reinforced, plus the additional
clearance of table 2L for a PWV of 840V which would be 1.2 mm (ignoring
extrapolation) giving a total of 5.2mm.

Scenario 2

Mains voltage = 400V, then Table 2K gives a minimum distance of 6.4mm
for reinforced with a PWV of 840V.

Does anybody interperet this differently?

Best regards,

Steve Richardson

Blackwood Compliance Laboratories



From: emc-p...@ieee.org [mailto:emc-p...@ieee.org] On Behalf Of Nick
Williams
Sent: 29 June 2007 13:21
To: emc-p...@ieee.org
Subject: Clause 2.10.3.3 of EN 60950-1:2006


I've been asked the following question by a client:


Compare the two scenarios...
1. Say mains is 230V, i.e. below 300V so add clearances from Table
2K and 2L. Say peak working voltage is 840V. Clearance is 
6.4+1.2=7.6mm
2. Say mains is 400V, i.e above 300V so minimum CLEARANCES are 
determined from Table 2K. No mention of adding value from Table 2L. 
The mains transient voltage class is 4000V, which means that table 
2K calls up larger clearances for voltages below 840V, but at 840V 
and above it makes no difference. Therefore clearance is 6.4mm.

Can't be right, can it?

This isn't an academic pursuit; we urgently need to know so thanks
very much for any comments.

Now, I'm not particularly familiar with this standard and the guy 
here who normally deals with this sort of thing is on holiday for 
three weeks, so I was hoping someone might be able to help out in the 
meanwhile.

I think the key to this is in understanding the meaning of PEAK 
WORKING VOLTAGE and understanding its relationship with the AC 
MAINS SUPPLY. Could someone with some practical experience shed some 
light on this?

Thanks and regards

Nick.

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RE: Clause 2.10.3.3 of EN 60950-1:2006

2007-06-29 Thread emc-p...@ieee.org
Hi Nick,

As I see it the clearance would be calculated as follows;

Scenario 1

Mains voltage = 230V (mains transient voltage is 2500V) giving a
clearance of 4.0 mm (table 2K) for reinforced, plus the additional
clearance of table 2L for a PWV of 840V which would be 1.2 mm (ignoring
extrapolation) giving a total of 5.2mm.

Scenario 2

Mains voltage = 400V, then Table 2K gives a minimum distance of 6.4mm
for reinforced with a PWV of 840V.

Does anybody interperet this differently?

Best regards,

Steve Richardson

Blackwood Compliance Laboratories



From: emc-p...@ieee.org [mailto:emc-p...@ieee.org] On Behalf Of Nick
Williams
Sent: 29 June 2007 13:21
To: emc-p...@ieee.org
Subject: Clause 2.10.3.3 of EN 60950-1:2006


I've been asked the following question by a client:


Compare the two scenarios...
1. Say mains is 230V, i.e. below 300V so add clearances from Table
2K and 2L. Say peak working voltage is 840V. Clearance is 
6.4+1.2=7.6mm
2. Say mains is 400V, i.e above 300V so minimum CLEARANCES are 
determined from Table 2K. No mention of adding value from Table 2L. 
The mains transient voltage class is 4000V, which means that table 
2K calls up larger clearances for voltages below 840V, but at 840V 
and above it makes no difference. Therefore clearance is 6.4mm.

Can't be right, can it?

This isn't an academic pursuit; we urgently need to know so thanks
very much for any comments.

Now, I'm not particularly familiar with this standard and the guy 
here who normally deals with this sort of thing is on holiday for 
three weeks, so I was hoping someone might be able to help out in the 
meanwhile.

I think the key to this is in understanding the meaning of PEAK 
WORKING VOLTAGE and understanding its relationship with the AC 
MAINS SUPPLY. Could someone with some practical experience shed some 
light on this?

Thanks and regards

Nick.

-

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