Re: [Emc-users] CAM-related question

2011-03-14 Thread Stuart Stevenson
On Sat, Mar 12, 2011 at 4:30 PM, Viesturs Lācis viesturs.la...@gmail.comwrote: Hello, gentlemen! I would like to ask, if anyone has an idea, how to create a code to produce this kind of part (both files contain the same model, I just saved it in 2 different formats):

Re: [Emc-users] CAM-related question

2011-03-13 Thread Mark
I'd write a small program in c or python to solve this. You only need to solve the problem for 1/4 of the perimeter. After that, rotate and mirror Here are my thoughts on solving it: - find parameteric equations for an arc of the circle in 1st quadrant and the edge of the square -

Re: [Emc-users] CAM-related question

2011-03-13 Thread Lars Andersson
Suggest a search on the keyword lofting, this is similar (maybe) to your problem. -Original Message- From: Viesturs Lācis [mailto:viesturs.la...@gmail.com] Sent: den 12 mars 2011 23:30 To: Enhanced Machine Controller (EMC) Subject: [Emc-users] CAM-related question Hello, gentlemen

Re: [Emc-users] CAM-related question

2011-03-13 Thread dave
On Sun, 2011-03-13 at 11:45 -0400, Mark wrote: I'd write a small program in c or python to solve this. You only need to solve the problem for 1/4 of the perimeter. After that, rotate and mirror Here are my thoughts on solving it: - find parameteric equations for an arc of the circle

Re: [Emc-users] CAM-related question

2011-03-13 Thread Viesturs Lācis
2011/3/13 Mark mpic...@gmail.com: I'd write a small program in c or python to solve this. You only need to solve the problem for 1/4 of the perimeter. After that, rotate and mirror Here are my thoughts on solving it:   - find parameteric equations for an arc of the circle in 1st quadrant

Re: [Emc-users] CAM-related question

2011-03-13 Thread andy pugh
On 12 March 2011 22:30, Viesturs Lācis viesturs.la...@gmail.com wrote: So the problem is finding out the necessary tilt angle, which corresponds to the slope of the edge. I think that it is non-trivial. The problem is deciding which point on the bottom curve matches which point on the top

Re: [Emc-users] CAM-related question

2011-03-13 Thread dave
Ah, got it. rotate and tilt is almost all it needs. Is this for mental exercise or does this part have a purpose? Dave On Sun, 2011-03-13 at 18:13 +, Dave Caroline wrote: Dave its water jet/plasma so the head has all the rotation and 5 axis needed, Viesturs, I cannot see the item as

Re: [Emc-users] CAM-related question

2011-03-13 Thread Mark
On Sun, Mar 13, 2011 at 12:51 PM, Viesturs Lācis viesturs.la...@gmail.comwrote: Thanks! I am not sure that I understand correctly all the calculations You offer, but it gave me an idea, that since I am using circle as the basic shape, I could paste both contours in polar coordinate system

Re: [Emc-users] CAM-related question

2011-03-13 Thread andy pugh
On 13 March 2011 22:26, Viesturs Lācis viesturs.la...@gmail.com wrote: Honestly - I just would like to produce some range of samples, that would demonstrate, what a 5 axis waterjet machine is capable of. There was a time when I worked somewhere with a 4-axis wire EDM machine where lots of

[Emc-users] CAM-related question

2011-03-12 Thread Viesturs Lācis
Hello, gentlemen! I would like to ask, if anyone has an idea, how to create a code to produce this kind of part (both files contain the same model, I just saved it in 2 different formats): http://www.cutting.lv/fileadmin/user_upload/Test.IGS http://www.cutting.lv/fileadmin/user_upload/Test.STL