With the help of Court Shrock, who answered by original request for help, I
have managed to create an array of form data that can be fed to a mySQL
UPDATE query. In case anyone else needs to do this, here's the solution I
reached.
The existing data is read from the database and placed in cells
On Thursday 14 March 2002 16:20, John Hughes wrote:
$sql = UPDATE parent_log
SET
classroom = \$classroom\,
homework = \$homework\,
library = \$library\,
fieldtrip = \$fieldtrip\,
pta = \$pta\,
mast = \$mast\,
meetings = \$meetings\,
other = \$other\
WHERE
Rehab,
i have an input field in a form that accept date called $date and in
databse i made it of type $date so its defualt is -00-00
the problem is when i say:
if($date!=-00-00)
{do something}
he doesn't understand $date!=-00-00
Please copy-paste the actual error message.
Manual reference:
http://www.php.net/manual/en/function.mysql-connect.php
resource mysql_connect ( [string server [, string username [, string
password [, bool new_link)
Seeing it is not a web page you're connecting to, try removing the
http://;.
localhost has particular meaning within the
Hi,
I would like to solve this problem on my apache-php instalation
Fatal error: Call to undefined function: ibase_connect() in
/home/pcash/public_html/includes/conexioninterbase.inc on line 7
To solve first i have try to do
[root@www download]# rpm -i php-interbase-3.0.16-2bc.i386.rpm
i have this
select name=category
option value='Arts'Antiques Arts/option
then i pass this to next page:
script
c=document.forms[0].category.options[document.forms[0].category.selectedIndex].text
location.href=additems.php?category=+c
/script
in url it shows like this:
you can't pass a literal in a url - it makes it think that it's the next
variable.
-Original Message-
From: its me [mailto:[EMAIL PROTECTED]]
Sent: 14 March 2002 11:21
To: [EMAIL PROTECTED]
Subject: [PHP-DB] need help guys
i have this
select name=category
option value='Arts'Antiques
Can you send us the full script?? Why can't you just do a submit???
The problem is the ampersand () in the middle. This is a place marker which
marks the start of the next variable in the query string.
If you absolutely *HAVE* to submit the data this way, you'll need to convert
it to the escape
hi Rehab
Because your submitted text on the url contains an '' anthing after this
character will be parsed as a new variable.
Instead of
location.href=additems.php?category=+c
try
location.href=additems.php?category=+escape(c)
this will encode the '' aswell as spaces to preserve
Hi,
thanx I try that.
andy
PS: yes I did, but did not try it yet. Thanx
Dl Neil [EMAIL PROTECTED] schrieb im Newsbeitrag
0c8601c1cae2$d26b6dc0$c200a8c0@jrbrown">news:0c8601c1cae2$d26b6dc0$c200a8c0@jrbrown...
Hi Andy,
I have a timestamp in my table to store a date. Now I have to update
Hello everyone,
I am a little new to the list. I have been reading a lot of the posts but have not
submitted yet. But I ran into a problem I was hoping I might get e little help or at
least get a point in the right direction.
I have a table called tblCategories with field category_ID
I was successful in compiling php with the options --with-oracle
and --with-oci8.
but when I tried to make a SELECT query to the database I got the
following error message:
OCIDebug: oci_do_connect: id=1
OCIDebug: oci_parse select login, password from users id=2 conn=1
Warning:
Chad,
Try something like this:
-
?
$qry = SELECT category_id, category_name from tblCategories;
$result = mysql_query($query);
?
form method=POST name=criteria action=my_postpage.php
select name=categories
if( strcmp($date,-00-00) )
{ do something}
-Original Message-
From: its me [mailto:[EMAIL PROTECTED]]
Sent: Thursday, March 14, 2002 12:16 AM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] date problem
i have an input field in a form that accept date called $date and in databse
i made it
Hi,
I have a windows 2000 Database Server with IBM DB2 V7.2 FP5
I have a linux web server with Apache/PHP
I installed IBM DB2 IMAGE Extender and enable my database for it.
Now I'm uploading a file to the server and I want to copy this file in the
database.
I'm using the following script:
We've been considering the following implementation of a class pointer
within another class. Our goal here is to minimize the number of database
connections per function call. It seems to work just fine, but I wanted to
post this up for comments. PHP 4.1.1 doesn't seem to have a problem with
Thanks everyone for the help,
I know with other lists, sometimes when you finally get you problem to work you
post your answer. Anyway, just in case anyone was wondering, here is what I ended up
doing:
?
mysql_connect(localhost,$user,$pass);
mysql_select_db($db);
I'll have to re-think extending the class with our database class. In the
past they may not have worked well. Admittedly, our classes were written
poorly. But, now that we're massively redesigning, that may work very well.
Thanks for getting my brain-juices flowing again.
Gary
Gurhan Ozen
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