Hi all,
I got this sets(20) of defined constants which using them as keys to an
array
eg
define(FNAME, fname);
farray = array( FNAME = hello ,...);
my question is how do I insert that directly into a javascript(to do
some client validation)
I need this:
var fname =
tony wrote:
Hi all,
I got this sets(20) of defined constants which using them as keys to an
array
eg
define(FNAME, fname);
farray = array( FNAME = hello ,...);
my question is how do I insert that directly into a javascript(to do
some client validation)
I need this:
var
that and it still doesn't work.
--- Jonathan
-Original Message-
From: Jim Hunter [mailto:[EMAIL PROTECTED]
Sent: Wednesday, March 12, 2003 2:59 PM
To: [EMAIL PROTECTED]
Subject: RE: [PHP-DB] Define()
Looking at your source you are still missing the php in the script. it
has to look
PROTECTED]
Subject: Re: [PHP-DB] Define()
Where is the $-sign in front of the vars???
Edwin
Jonathan Villa wrote:
Jim,
I don't think that matters. One can escape into PHP in several ways
(depending on the php.ini config of course)
1.?php
2.?
3.script language=php
4
I am developing an app which needs 3 constants. The value of these
constants comes from a database result.
This works fine. My problem is that they do not work very well. I am
developing on both windows/Linux (depending what I boot into).
This is the effect I want
$doc_dir = the string of
---Original Message---
From: [EMAIL PROTECTED]
Date: Wednesday, March 12, 2003 10:51:04 AM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] Define()
I am developing an app which needs 3 constants. The value of these
constants comes from a database result.
This works fine. My problem is that they do not work
]; [EMAIL PROTECTED]
Subject: Re: [PHP-DB] Define()
The reason it doesn't work may go beyond PHP. You are trying to make an
HREF
point to an exact location on your hard drive. When the user of your web
page clicks the link, they do not have that location on their system so
it
will fail. Always use
For starters, and in general, does anyone know why a view source would
not work in IE 6? This hasn't worked for weeks, so I usually have to
use Mozilla to view the source.
Anyway, Jim, this is my basic page setup.
?php
include_once(../common/store_config.php);
Villa [mailto:[EMAIL PROTECTED]
Sent: Wednesday, March 12, 2003 3:21 PM
To: [EMAIL PROTECTED]
Subject: RE: [PHP-DB] Define()
For starters, and in general, does anyone know why a view source would
not work in IE 6? This hasn't worked for weeks, so I usually have to
use Mozilla to view
]
Subject: RE: [PHP-DB] Define()
Yes! I ran into this once and it stumped me for a while. You
need to delete
the temporary internet files directory on the machine where
you're viewing
the source. Took me three days of looking on microsoft.com to
figure that
one out.
I'm not proud
-Original Message-
From: Jim Hunter [mailto:[EMAIL PROTECTED]
Sent: Wednesday, March 12, 2003 2:59 PM
To: [EMAIL PROTECTED]
Subject: RE: [PHP-DB] Define()
Looking at your source you are still missing the php in the script. it
has to look like:
form action=?php echo CTL_HOME_ROOT
=mysql_fetch_array($result)){
$WELCOME.=$row[my_name];
}
echo $WELCOME;
?
#end code
Dobromir Velev
-Original Message-
From: Matt Nigh [EMAIL PROTECTED]
To: [EMAIL PROTECTED] [EMAIL PROTECTED]
Date: Monday, July 02, 2001 1:01 AM
Subject: [PHP-DB] define variable by querying MySQL
hello
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