"$event[cal_description]";
echo "\n";
echo "\n";
} while ($event = mysql_fetch_array($events));
} else {
echo "No Public Events Are Currently Scheduled...";
}
?>
----- Original Message -
From: "Matthew Ferry" <[EMAIL PROTECTED]>
To:
This is a join - Read up on them, they're very useful and don't require
the overhead of a sub-query.
SELECT egw_cal.* FROM egw_cal_dates
LEFT JOIN egw_cal using (cal_id)
where egw_cal_dates.cal_start > $tstamp
AND egw_cal.cal_category = '501'
-Micah
On 02/12/2007
Try this as your SQL. It should give you all the results, then you can use PHP
to sort it all out.
SELECT * FROM egw_cal WHERE cal_category='501' and cal_id in (SELECT cal_id
FROM egw_cal_dates where cal_start > $tstamp)
-TG
= = = Original message = = =
Hello Everyone
Got a simple / st
Matthew Ferry wrote:
Hello Everyone
Got a simple / stupid question.
Worked on this all night. I'm over looking something very basic here.
The query "event_time" brings back the calendar id for each event that is
pending in the future.
ie 12, 13, 14, 26 (There could be 100 of them out
Hello Everyone
Got a simple / stupid question.
Worked on this all night. I'm over looking something very basic here.
The query "event_time" brings back the calendar id for each event that is
pending in the future.
ie 12, 13, 14, 26 (There could be 100 of them out there)
The second quer
Chris Carter wrote:
What wrong with this syntax, its not giving any error on runtime but I am
facing a blank page while paging.
$query=" SELECT * FROM gurgaonmalls WHERE mallname = '$mallname' limit $eu,
$limit ";
Have you tried...
echo " $query ";
...to unsure the variables have the values
What wrong with this syntax, its not giving any error on runtime but I am
facing a blank page while paging.
$query=" SELECT * FROM gurgaonmalls WHERE mallname = '$mallname' limit $eu,
$limit ";
--
View this message in context:
http://www.nabble.com/SQL-query-error-tf2831052.html#a7903857
Sent f
OK, this makes my day clear!!
I have versión 3.23.49-3 of MySQL
Thanks Dwight!
-Original Message-
From: Dwight Altman [mailto:[EMAIL PROTECTED]
Sent: Jueves, 28 de Septiembre de 2006 11:32 a.m.
To: php-db@lists.php.net
Subject: RE: [PHP-DB] SQL query
Check your version. Subselects
Check your version. Subselects were only added in MySQL Version 4.1.
Regards,
Dwight
> -Original Message-
> From: Edwin Cruz [mailto:[EMAIL PROTECTED]
> Sent: Thursday, September 28, 2006 10:53 AM
> To: 'Miguel Guirao'; php-db@lists.php.net
> Subject: RE: [PH
iembre de 2006 09:09 a.m.
> Para: php-db@lists.php.net
> Asunto: [PHP-DB] SQL query
>
>
>
>
> Hello list,
>
> Whats wrong with my SQL query:
>
> $query="select email from usuarios where userName = (select
> username from fussv where folio = 'FUSS-1
Hello list,
Whats wrong with my SQL query:
$query="select email from usuarios where userName = (select username from
fussv where folio = 'FUSS-130-2006')";
I get an error!
I have tested the two individual sentences and they worked OK!
---
Miguel Guirao Aguilera
Logisti
From: "Muhammed Mamedov" <[EMAIL PROTECTED]>
> Try this
>
> "SELECT DISTINCT(file_name), Count(file_name) AS cnt FROM $table_name
WHERE
> date
> > BETWEEN '2003-10-01' AND '2003-12-31' group by file_name order by cnt;
> > desc"
If you're GROUPing by "file_name" then you don't need DISTINCT(file
ROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Thursday, January 15, 2004 1:01 PM
Subject: [PHP-DB] SQL query...
> "SELECT DISTINCT(file_name), Count(file_name) FROM $table_name WHERE date
> BETWEEN '2003-10-01' AND '2003-12-31' group by file_name order by ?
itin
- Original Message -
From: <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Thursday, January 15, 2004 4:31 PM
Subject: [PHP-DB] SQL query...
> "SELECT DISTINCT(file_name), Count(file_name) FROM $table_name WHERE date
> BETWEEN '2003-10-01' AND
Ah...
you can name the count()..
live and learn, cheers dude...
"brett king" <[EMAIL PROTECTED]>
15/01/2004 11:17
Please respond to
<[EMAIL PROTECTED]>
To
<[EMAIL PROTECTED]>, <[EMAIL PROTECTED]>
cc
Subject
RE: [PHP-DB] SQL query...
"SELECT DIS
"SELECT DISTINCT(file_name), Count(file_name) FROM $table_name WHERE date
BETWEEN '2003-10-01' AND '2003-12-31' group by file_name order by ???
desc"
In the above sql statement, I'm trying to achieve:
1. select all file names, between two dates.
2. list them, and order by the highest number o
"SELECT DISTINCT(file_name), Count(file_name) FROM $table_name WHERE date
BETWEEN '2003-10-01' AND '2003-12-31' group by file_name order by ???
desc"
In the above sql statement, I'm trying to achieve:
1. select all file names, between two dates.
2. list them, and order by the highest number
om: Louie Miranda [mailto:[EMAIL PROTECTED]
Sent: quinta-feira, 15 de Janeiro de 2004 8:00
To: [EMAIL PROTECTED]
Subject: [PHP-DB] sql query, editing?
I have this code below, it fetches data on a mysql database. I was
hoping you could give me a code hint on where could, my goal is to
display this
I have this code below, it fetches data on a mysql database. I was hoping
you could give me a code hint on where could, my goal is to display this
data on a browser which i did already and be able to edit it via a form.
edit? -> table1=value -> table2=value
I dont know where to start. please help
why does this
select date(date_file_created) from files
create the error
error near near '(date_file_created) from files' at line 1
trying to extract the date part of the date_tile filed
tia
pete
--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.
> i'm starting out in this whole thing, and i'm trying to program a zine
> that
> uses a sql database for content and calls the content into a template.
> what
> i am unclear on how to do is set up the links so that I can get the
info
> from the database. anyone willing to help me out?
www.youdom
i'm starting out in this whole thing, and i'm trying to program a zine that
uses a sql database for content and calls the content into a template. what
i am unclear on how to do is set up the links so that I can get the info
from the database. anyone willing to help me out?
--
PHP Database Ma
id INT NOT NULL AUTO_INCREMENT PRIMARY KEY
Adam
On Sat, 7 Sep 2002, Bryan McLemore wrote:
> Hi Guys I have written this SQL Query :
>
> CREATE TABLE tasks (id INT AUTO_INCREMENT, name VARCHAR(50), desc TEXT, address
>VARCHAR(50), startDate DATE, lastWork DATE, progress
Hi Guys I have written this SQL Query :
CREATE TABLE tasks (id INT AUTO_INCREMENT, name VARCHAR(50), desc TEXT, address
VARCHAR(50), startDate DATE, lastWork DATE, progress INT(3))
I'm sending it in through php and I can't get it to work correctly. Please help.
Also, I would like to make id
TED]]
Sent: Wednesday, July 17, 2002 8:44 PM
To: PHP DB Mailing List (E-mail)
Subject: [PHP-DB] SQL query prob
I'll try that one again
I have a query:
$sql = "SELECT * FROM contacts ORDER BY ContactType";
There are two types of contacts:
* Commissioners
* Staff
As they a
I'll try that one again
I have a query:
$sql = "SELECT * FROM contacts ORDER BY ContactType";
There are two types of contacts:
* Commissioners
* Staff
As they are ordered by the ContactType then 'Commissioners' are
displayed first followed by 'Staff'.
I'd like to be able to display a h
query will
helps you.
Regards,
SenthilVelavan.P
- Original Message -
From: <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Saturday, June 15, 2002 2:39 AM
Subject: [PHP-DB] sql query problem
> I have a database layout similar to this-
>
> id order title name
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]]
Sent: Friday, June 14, 2002 3:10 PM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] sql query problem
I have a database layout similar to this-
id order title namepagecat
0 0 title1 blueap
1 2
I have a database layout similar to this-
id order title namepagecat
0 0 title1 blueap
1 2 blue1 page1 ap
2 3 blue2 page2 ap
3 1 blue3 page3 ap
I would like to get title1 (title col
nd also tru echoing the value of that SQL statement (assign it to a var
> first) to make sure you are getting the right thing.
>
> HTH
>
> /b
>
> // -Original Message-
> // From: CrossWalkCentral [mailto:[EMAIL PROTECTED]]
> // Sent: Tuesday, 19 February 2002 9:31
ntral [mailto:[EMAIL PROTECTED]]
// Sent: Tuesday, 19 February 2002 9:31 AM
// To: [EMAIL PROTECTED]
// Subject: [PHP-DB] sql query
//
//
// I am having a minor problem doing a simple sql query.
//
// Error performing service query : You have an error in your
// SQL syntax near '' at l
I am having a minor problem doing a simple sql query.
Error performing service query : You have an error in your SQL syntax near '' at line 1
Here is a snip of the code: Please let me know what you think.
if ($submit):
$status="0";
// REQUEST INFO FOR SERVICES
$results = mysql_query(
"SELECT
l.com/doc/A/N/ANSI_diff_Sub-selects.html
-Original Message-
From: Pierre
Sent: Mon 11/12/2001 12:20 AM
To: Gonzalez, Lorenzo; [EMAIL PROTECTED]
Cc:
Subject: Re: [PHP-DB] SQL query
Thanks but I th
Thanks but I think subselect is not possible with MYSQL.
Pierre
- Original Message -
From: Gonzalez, Lorenzo <[EMAIL PROTECTED]>
To: Pierre <[EMAIL PROTECTED]>; <[EMAIL PROTECTED]>
Sent: Monday, November 12, 2001 1:08 PM
Subject: RE: [PHP-DB] SQL query
> in other
om: Pierre
Sent: Sun 11/11/2001 10:01 PM
To: [EMAIL PROTECTED]
Cc:
Subject: [PHP-DB] SQL query
I have two tables, one call category, the other chapter
Category table
[id][name]
[1][a]
I have two tables, one call category, the other chapter
Category table
[id][name]
[1][a]
[2][b]
[3][c]
[4][d]
Chapter table
[id][FK_name]
[1][a]
[2][a]
[3][c]
I would like to get the list of names of the Category table that are NOT present in
the Chapter table.
On this example, I should find
hi:
I have 2 tables, lesson and lesson_gle, where lesson
holds lesson data and lesson_gle holds repeating data
that are how the lesson correlates to various state
standards (one lesson can have many
correlations)...one particular lesson may have a math
correlation as well as a language arts corre
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