Hello everyone
I am trying to use the mysql BDB tables option for safe transaction tables.
I have finally activated BDB support with a 3.23.. mysql Max binary version
using the latest version of php...
I use the following script to test if the BEGIN & COMMIT option works but i
always get th
For a PHP-application on Windows NT, I am using an Oracle database and the
database-interface db_oci8.inc (a PHP-class, downloaded from the net).
To be able to make the connection to the database, the class has to know the
databasename, username, and password. At the moment, it is hardcoded in t
On Unix it is possible to make an include file with all the settings
like $user, $passwd and so on and store it somewhere in the
filesystem (not under your htdocs-path)
So no one can access this file via web
You can include this file with its variables with the include() - statement
...
Im
Hi,
I suggest you use a .php file to declare your database variables and include
it everywhere you need it. Even if someone guesses the name of this file
when he tries to open it, nothing will be outputed to the screen.
an example file is
Than you'll have to set the permissions of this file in
> Hi all',
> I have a mysql_query that reads:
>
> $testResult = mysql_query("SELECT * FROM login_table where Pass =
> password('$password')") or die ("ouch");
>
is $password the var that stores the password ? i don't understand why you
have password('$password')
$testResult = mysql_query("SELEC
You can try to modify the connect string because php's connect to database
through TCP/TP.
Tell me the result.
Graycloud <[EMAIL PROTECTED]> wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> Hello, My php is running at RedHatLinux ,but now I want to connect to a
> MssqlServer2000 d
I want to INSERT a variable like this using MySQL. If I use this
\"(${"C_First_Name"}.$x)\",
or
\"(${C_First_Name}.$x)\",
or
\"${C_First_Name}.$x\",
only the $x gets interpolated in the insertion. If I use
\"${"C_First_Name$x"}\",
only $C_First_Name get interpolated. Any solutions? Thanks.
J
Hi Jeff.
$varname = "C_First_Name".$x;
// e.g. if $x == 3 then ...
echo $$varname; // ... prints the content of $C_First_Name3
Hope this is what you wanted ?!
Greetinx,
Mike
Michael Rudel
- Web-Development, Systemadministration -
Besuchen Sie uns am 20. und 21. August 2001 auf der
online-
Hi All,
Microsoft SQL Server used to be identical with Sybase (back arround version 4.xx).
This makes it possible to use the sybase extension (using FreeTDS) on a *nix box to
talk to a SQL Server on a NT/2000 box.
Due to product development SQL 2000's db-library is no longer 100% compatible. Th
I have a Linux Server, with Apache 1.3.19 + PHP 4.0.6 and MySQL 3.23.37, and
i have a trouble with Transactions in PHP code:
When i write a transaction, and some error (PHP lang error) occurs, the
transaction are autocommited, and only part of the querys are made, with the
inconsistence of data,
Hi, I'm not quite getting it. If $x is 1 here is what happens.
$varname = "C_First_Name".$x;
echo $$varname;
then $$varname prints as $C_First_Name1. However $C_First_Name1
prints the contents of the variable.
Jeff Oien
> Hi Jeff.
>
> $varname = "C_First_Name".$x;
>
> // e.g. if $x == 3 the
I found a solution but not sure if it's the most efficient.
I need to first define a simpler variable:
$C_First_Name = "${"C_First_Name".$x}";
then INSERT VALUE $C_First_Name.
Jeff Oien
> Hi Jeff.
>
> $varname = "C_First_Name".$x;
>
> // e.g. if $x == 3 then ...
> echo $$varname; // ... prin
Hello...
What would I need to change to get my php compile to staticly link only
the oracle libraries? I need to distribute the php stuff to multiple
servers and I would prefer not to have to move the libclntsh.so.8.0 and
libwtc8.so to every machine.
I would think this is a libtool ar
I can't figure this out. The first code works as far as inserting into a
MySQL database with the !result error checking. The second with the
error code commented out doesn't. I can't figure out why.
Jeff Oien
if ($M_First_Name) {
$sql = "INSERT INTO $table_name
(First_Name, Last_Name, Family_Posi
Try using ' instead of \" like:
if ($M_First_Name) {
$sql = "INSERT INTO $table_name
(First_Name, Last_Name, Family_Position, Address, Address1, City, State,
Zip, Email,
Home_Phone, Work_Phone, Coop_Month, Timestamp) VALUES
('$M_First_Name', '$M_Last_Name', '$MatherFamilyPosition','$M_Address1',
I have a field that's timestamp(12) which should be MMDDhhmm
but what I'm getting is
010718125000
what I was expecting was
200107181250
How can I get what I was expecting? Thanks.
Jeff Oien
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Hi
I've just installed RHL 7.1, and would like to test out the PHP4.0.6 ODBC
functions. How can I get the DSO for this easily instead of recompiling.
Is there a website I can download this extension from?
Thanks
Peter
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Hello...
You might try:
ftp://ftp.redhat.com/pub/redhat/linux/rawhide/i386/RedHat/RPMS/
there are php 4.0.6 rpms
you might have to update a few other things, openssl, freetype, etc
or recompile
rpm --rebuild
ftp://ftp.redhat.com/pub/redhat/linux/rawhide/SRPMS/SRPMS/php-4.0.6-2.src.rpm
E. Peter
Thanks. I was using MySQL by DuBois book as a reference.
Jeff
> According to the manual, 12 is YYMMDDHHMMSS and 14 is MMDDHHMMSS.
>
> http://www.mysql.com/documentation/mysql/bychapter/manual_Reference.html#DATETIME
>
>
> "Jeff Oien" <[EMAIL PROTECTED]> wrote:
> I have a field that's time
Hi there everyone,
Thanks to everyone that replied to my session help - but i'm still having problems. I
use the below to open a session - Say at the start of my website:
where username and pass would be defined by a variable - either from a form or
hardcoded.
Now, if I use on the SAME p
Hi There,
Thank you SO much for all your help with Sessions, I didn't find information anywhere
else which said you had to put at the top of EVERY page so I
assumed that initialised it on the first page.
All of your help is very much appreciated and added about 10 years to my life span :-)
R
Hi Marios,
Unfortunately i'm very new to PHP so i'm not sure how to do some of this (Sorry).
Cookies are deffinately enabled.
Chris
> Firstly, try initializing the variable, and then registering.
> Also are you accessing the user and pass variables in a function in the
> other pages?...if so
** Reply to note from [EMAIL PROTECTED] 18 Jul 2001 14:24:27 -
Hello, Chris:
> I currently run a unix web server from a company in the UK, i'm
> getting a cable modem soonish and was wondering if I can run a
> server from home rather than hiring one as I am now? If so what
> will I need? I
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I am using Apache, PHP4 and MySQL 3.23 on NT and i cannot get php to
create a new database. If i create the database through the command
line PHP will not acces it. All the settings on PHP look OK. It has
worked in the past and I cannot understand why
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I am using Apache, PHP4 and MySQL 3.23 on NT and i cannot get php to
create a new database. If i create the database through the command
line PHP will not acces it. All the settings on PHP look OK. It has
worked in the past and I cannot understand why
This is my page to extract image (as blob) in a interbase table.
I call it with :echo "src=\"blob2img.php?id_product=".$id_product."\" ";
but i don't see the image
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I personally tend to use arrays for my sessions, i just find it easier that
way this sort of thing works for me:-
$SESSION["user"]=$whatever;
$SESSION["password"]=$whatever;
echo("Welcome ". $SESSION["user"] .", Please Click On A Link");
- Original Message -
From: <[EMAIL PROTECTED
Greetings, Sharmad!
At 18.07.2001, 07:41, you wrote:
SN> Thanks Alexey,
SN> I have set the passwd for the root user,but now how do i set
SN> the passwd for other users.
CREATE USER another_user WITH PASSWORD 'password';
or
ALTER USER another_user WITH PASSWORD 'password';
SN>
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