SV: [PHP-DB] I am new to PHP
Hi,
I would guess your problem is in the third file:
mysql_query( UPDATE books SET isbn='$ud_isbn' ,title='$ud_title',
author='$ud_author',edition='$ud_edition',course_id='$ud_course_id',quan
tity = '$ud_quantity', stack_no =
'$ud_stack_no'
WHERE isbn='$ud_id');
The WHERE clause should probaly be id='$ud_id'
Otherwise try to elaborate on what happens.
Hth Henrik Hornemann
-Oprindelig meddelelse-
Fra: andy amol [mailto:[EMAIL PROTECTED]
Sendt: 15. april 2004 06:18
Til: [EMAIL PROTECTED]
Emne: [PHP-DB] I am new to PHP
Hi,
I have a problem with the second file. I am not able to update the
data from the php program. Any help on that would be appreciated.
Any modification which would be reduce the code like directly using the
Update command would be appreciated.
thanks in advance.
Here are the 3 files.
File1
---
htmlheadtitleBook Update Form/title/head
body
?
$db=project;
$link = mysql_connect(localhost,name,passwd);
if (! $link)
die(Couldn't connect to MySQL);
mysql_select_db($db , $link)
or die(Couldn't open $db: .mysql_error());
$result = mysql_query( SELECT * FROM books )
or die(SELECT Error: .mysql_error());
$num_rows = mysql_num_rows($result);
print There are $num_rows records.P;
print table width=800 border=1\n;
while ($get_info = mysql_fetch_row($result)){
print tr\n;
foreach ($get_info as $field)
print \ttdfont face=arial size=2/$field/font/td\n; print
/tr\n; } print /table\n; mysql_close($link); //form
method=POST action=book_change_form.php ? br form method=POST
action=book_change_form.php pre Enter ISBN Number to Edit: input
type=text name=id size=10 input type=submit
value=Submitinput type=reset /pre /form /body /html
File 2
-
htmlheadtitleBook change form/title/head
body
?
$id=$_POST['id'];
$db=project;
//mysql_connect(localhost,$_POST['username'],$_POST['pass']);
$link = mysql_connect(localhost,name,passwd);
if (! $link)
die(Couldn't connect to MySQL);
mysql_select_db($db , $link)
or die(Couldn't open $db: .mysql_error());
$query= SELECT * FROM books WHERE id='$id';
$result=mysql_query($query); $num=mysql_num_rows($result); //echo $num;
$i=0; while ($i $num)
{
$isbn=mysql_result($result,$i,isbn);
$title=mysql_result($result,$i,title);
$author=mysql_result($result,$i,author);
$edition=mysql_result($result,$i,edition);
$course_id=mysql_result($result,$i,course);
$quantity=mysql_result($result,$i,quantity);
$stack_no=mysql_result($result,$i,stack_no);
?
table width=300 cellpadding=10 cellspacing=0 border=2 tr
align=center valign=top td align=center colspan=1 rowspan=1
bgcolor=#64b1ff h3Edit and Submit/h3 form
action=book_change_record.php method=post input type=hidden
name=username value=?php print
$_POST['username']?
input type=hidden name=pass value=?php print $_POST['pass']?
input type=hidden name=ud_id value=? echo $id ?
ISBN:input type=text name=ud_isbn value=? print
$isbn?br
Title: input type=text name=ud_title value=? print
$title?br
Author: input type=text name=ud_author value=? print
$author?br
Edition: input type=text name=ud_edition value=? print
$edition?br
Course Id: input type=text name=ud_course_id value=? print
$course_id?br
Quantity:input type=text name=ud_quantity value=? print
$quantity?br
Stack Number:input type=text name=ud_stack_no value=? echo
$stack_no?br
input type=Submit value=Update
/form
/td/tr/table
?
++$i;
}//end while
?
/body
/html
//
File 3
htmlheadtitleBook Change Record/title/head
body
?
$user=$_POST['username'];
$password=$_POST['password'];
$ud_id=$_POST['ud_id'];
$ud_isbn=$_POST['ud_isbn'];
$ud_title=$_POST['ud_title'];
$ud_author=$_POST['ud_author']; $ud_edition=$_POST['ud_edition'];
$ud_course_id=$_POST['ud_course_id'];
$ud_quantity=$_POST['ud_quantity'];
$ud_stack_no=$_POST['ud_stack_no'];
$db=project;
$link = mysql_connect(localhost,name,passwd);
if (! $link)
die(Couldn't connect to MySQL);
mysql_select_db($db , $link)
or die(Couldn't open $db: .mysql_error());
mysql_query( UPDATE books SET isbn='$ud_isbn' ,title='$ud_title',
author='$ud_author',edition='$ud_edition',course_id='$ud_course_id',quan
tity = '$ud_quantity', stack_no =
'$ud_stack_no'
WHERE isbn='$ud_id');
echo Record Updated;
mysql_close($link);
?
form method=POST action=book_update_form.php
input type=hidden name=username value=?php print
$_POST['username']?
input type=hidden name=pass value=?php print
$_POST['password']?
input type=submit value=Change Another
/formbr
form method=POST action=book.php
input type=hidden name=username value=?php print
$_POST['username']?
input type=hidden name=pass value=?php print
$_POST['password']?
input type=submit value=Book Interface
/form
/body
/html
-
Do you Yahoo!?
Yahoo! Tax Center - File online by April 15th
--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe,
Re: [PHP-DB] quotations in value field
On Apr 14, 2004, at 15:33, Ford, Mike [LSS] wrote: On 14 April 2004 15:21, Mikael Grön wrote: Well, I guess a combination of htmlspecialchars and some other function to convert it back, before it gets sent of in the _plain text mails_. You don't need to convert it back -- that happens automatically when the form is resubmitted. Cheers! Mike Ofcourse it does! I knew that.. ;) Thanks a bunch Mike! Regards, Mikael G -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] New To PHP
I ma trying to learn PHP and am having difficulty with understanding it. Is there a good PHP creator that will create PHP which will let me specify what all I need to have done so that I can go back and try to figure out just how it all fits together? Thanks, Tom KI8IZ http://www.wooster-isp.net -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] New To PHP
I found Lerdorf and Tatroe's Programming PHP (O'Reilly 2002) extremely helpful in understanding the why of PHP. Mark -Original Message- From: Tom Cloyes [mailto:[EMAIL PROTECTED] Sent: Thursday, April 15, 2004 7:54 AM To: [EMAIL PROTECTED] Subject: [PHP-DB] New To PHP I ma trying to learn PHP and am having difficulty with understanding it. Is there a good PHP creator that will create PHP which will let me specify what all I need to have done so that I can go back and try to figure out just how it all fits together? Thanks, Tom KI8IZ http://www.wooster-isp.net -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] New To PHP
What I did to learn PHP was to surf to http://www.hotscripts.com/ and look at other peoples code. Writing it yourself looking at the hotscript codes also helps you understand the logic of it. Mike On Apr 15, 2004, at 12:53, Tom Cloyes wrote: I ma trying to learn PHP and am having difficulty with understanding it. Is there a good PHP creator that will create PHP which will let me specify what all I need to have done so that I can go back and try to figure out just how it all fits together? Thanks, Tom KI8IZ http://www.wooster-isp.net -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] New To PHP
Mark, Thanks for responding. I have read the books: PHP4 A Beginners Guide by McCarty from Osborne Mastering PHP 4.1 by Allen and Hornberger from Sybex and have poked around in PHP Cookbook by Sklar and Trachtenberg from O'Reilly Also have read books on MySQL, and am left scratching my head. Have found a couple of programs that look promising, and the first one I've tried - phpmaker - http://www.hkvstore.com/ - is a cookie-cutter type that really makes a lot of code. Will have to work with it to see if I can get it to do what I need it to do. Was wondering if any of you had experience with one of these or do you hand code everything. My client wants to go live in a month and the only thing left is the one database and the interaction with it, that and the integration with Xoops. I will look into the book you recommended and continue to poke around. Any pointers will be gladly accepted. Thanks, T At 08:11 AM 4/15/04 -0400, Galbreath, Mark A wrote: I found Lerdorf and Tatroe's Programming PHP (O'Reilly 2002) extremely helpful in understanding the why of PHP. Mark -Original Message- From: Tom Cloyes [mailto:[EMAIL PROTECTED] Sent: Thursday, April 15, 2004 7:54 AM To: [EMAIL PROTECTED] Subject: [PHP-DB] New To PHP I ma trying to learn PHP and am having difficulty with understanding it. Is there a good PHP creator that will create PHP which will let me specify what all I need to have done so that I can go back and try to figure out just how it all fits together? Thanks, Tom KI8IZ http://www.wooster-isp.net -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php Tom KI8IZ http://www.wooster-isp.net -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] New To PHP
Nice resource! Thanks for sharing! Mark -Original Message- From: Mikael Grön [mailto:[EMAIL PROTECTED] Sent: Thursday, April 15, 2004 9:00 AM To: Tom Cloyes; [EMAIL PROTECTED] Subject: Re: [PHP-DB] New To PHP What I did to learn PHP was to surf to http://www.hotscripts.com/ and look at other peoples code. Writing it yourself looking at the hotscript codes also helps you understand the logic of it. Mike On Apr 15, 2004, at 12:53, Tom Cloyes wrote: I ma trying to learn PHP and am having difficulty with understanding it. Is there a good PHP creator that will create PHP which will let me specify what all I need to have done so that I can go back and try to figure out just how it all fits together? Thanks, Tom KI8IZ http://www.wooster-isp.net -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] New To PHP
Lisi, Thank you for your reply, and I've bookmarked both sites as well as downloaded a few scripts that look promising. I've also found another creator that may just be what I'm looking for - dbquiksite - http://www.dbqwiksite.com/. Thanks again, T At 03:20 PM 4/15/04 +0200, [EMAIL PROTECTED] wrote: Not sure about a creator but there are plenty of existing scripts on the Net you can download and browse to see how they fit together. You can install and run them, play around with the code, and see the effects of your changes. Try hotscripts.com/PHP/ or php.resourceindex.com to start with. -Lisi = = = Original message = = = I ma trying to learn PHP and am having difficulty with understanding it. Is there a good PHP creator that will create PHP which will let me specify what all I need to have done so that I can go back and try to figure out just how it all fits together? Thanks, Tom KI8IZ http://www.wooster-isp.net -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php ___ Sent by ePrompter, the premier email notification software. Free download at http://www.ePrompter.com. Tom KI8IZ http://www.wooster-isp.net -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] Re: PHP OO Problem
Thanks Justin, I found the problem. I am using the OOP with sessions. The idea is use um object and put it into the session and change it when is necessary. However, instead of change the information in the object and then change the object that is in the session, it is adding more information in the object. As a result, my session has the size increased from 1 to 5, from 5 to 15, from 15 to 40, etc... Is there any way to destroy the object in PHP? Thanks. Justin Patrin [EMAIL PROTECTED] escreveu na mensagem news:[EMAIL PROTECTED] Andre Matos wrote: Hi List, Two months ago I developed a project using PHP and MySQL without problem. Now, I am developing using PHP and MySQL, but using PHP Object Oriented. My problem is that the access is become slowly after few accesses or if I perform a reload some times. The unique way to revert is to restart the Apache. Is anyone had this problem? Is this problem related to PHP OO or may something that I used in my programs? Thanks. Andre [EMAIL PROTECTED] Pretty much all of the larger PHP systems around are OO. PEAR is OO. If OO was the problem, it would have been fixed far before now. Likely you're using more resources inadvertently or not closing resources. Try checking specific functions to see if they're slowing you down. If you need more help, post some code and it will get looked at. -- paperCrane Justin Patrin -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Re: PHP OO Problem
Is there any way to destroy the object in PHP? http://us2.php.net/manual/en/function.unset.php Chris -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] finding data
I am trying to find data, or if not found set a variable to Err. myvalue being a
variable in my database and $zchar being my value to find.
The following result is never 1 even if no values were found, so the result is always
2. If the finding value does exist in my database this does find the correct value:
if (!$result = mysql_query(SELECT * FROM bivalues WHERE myvalue = '$zchar'))
{
echo 'result 1 - not found';
$myresut = Err;
}
else
{
{echo 'result 2 - found it'
}
The following result is never 2 even if the value actually exist in my database, so
the result is always 1:
if (!$result = mysql_query(SELECT * FROM bivalues WHERE myvalue = $zchar))
{
echo 'result 1 - not found';
$myresult = Err;
}
else
{
{echo 'result 2 - found it'
}
Thanks for any help,
Doug
--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] Re: finding data
the way I would do this is with count()
$row = mysql_fetch_assoc(SELECT count(*) as c FROM bivalues WHERE
myvalue = '$zchar')
if ($row['c'] 0)
{
echo 'result 2 - found it'
}else{
echo 'NOT found'
}
hope it helps
Pete
Douglas D Hull wrote:
I am trying to find data, or if not found set a variable to Err. myvalue being a variable in my database and $zchar being my value to find.
The following result is never 1 even if no values were found, so the result is always
2. If the finding value does exist in my database this does find the correct value:
if (!$result = mysql_query(SELECT * FROM bivalues WHERE myvalue = '$zchar'))
{
echo 'result 1 - not found';
$myresut = Err;
}
else
{
{echo 'result 2 - found it'
}
The following result is never 2 even if the value actually exist in my database, so
the result is always 1:
if (!$result = mysql_query(SELECT * FROM bivalues WHERE myvalue = $zchar))
{
echo 'result 1 - not found';
$myresult = Err;
}
else
{
{echo 'result 2 - found it'
}
Thanks for any help,
Doug
--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Re: finding data
The way I would do it:
$result = mysql_query(select * from bivalues WHERE myvalue - '$zchar');
if (mysql_num_rows($result) {
echo Result 2 - found it;
} else {
echo Not found;
}
This leaves you with the option to start processing the data as soon as
error checking is over. Using Count, you'll have to re-retrieve the
data from the database, which takes twice as long time as doing it only
once.. (or thereabout).
The problem you had is that no matter if the query presents results or
not, the result variable is only set to 0 (thus the !$result syntax
gives results) when there's been an error in the mysql query. Simply an
empty table will not return an error!
Mike
On Apr 15, 2004, at 16:54, pete M wrote:
the way I would do this is with count()
$row = mysql_fetch_assoc(SELECT count(*) as c FROM bivalues WHERE
myvalue = '$zchar')
if ($row['c'] 0)
{
echo 'result 2 - found it'
}else{
echo 'NOT found'
}
hope it helps
Pete
Douglas D Hull wrote:
I am trying to find data, or if not found set a variable to Err.
myvalue being a variable in my database and $zchar being my value to
find.
The following result is never 1 even if no values were found, so the
result is always 2. If the finding value does exist in my database
this does find the correct value:
if (!$result = mysql_query(SELECT * FROM bivalues WHERE myvalue =
'$zchar'))
{
echo 'result 1 - not found';
$myresut = Err;
}
else
{
{echo 'result 2 - found it'
}
The following result is never 2 even if the value actually exist in
my database, so the result is always 1:
if (!$result = mysql_query(SELECT * FROM bivalues WHERE myvalue =
$zchar))
{
echo 'result 1 - not found';
$myresult = Err;
}
else
{
{echo 'result 2 - found it'
}
Thanks for any help,
Doug
--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] FPDF Help
Anyone who is familiar with using FPDF to generate PDFs, I'd really
appreciate some suggestions here:
I am using the following code, virtually identical to that used in the
FPDF tutorial examples. But I keep getting a parse error for the first
line containing the variable $this. In the tutorial they do not
declare this variable prior to using it the same way as in the example
below, but when I try and do this, it's a no go.
Any ideas? Suggestions?
the code
--
define('FPDF_FONTPATH','../../../font/');
require('../fpdf.php');
class PDF extends FPDF
{
function Header()
{
//Arial 12
$this-SetFont('Arial','',12);
//Move to the right
$this-Cell(80);
//Title
$this-Cell(30,10,'Title',1,0,'C');
//Line break
$this-Ln(20);
}
function Footer()
{
//Position at 1.5 cm from bottom
$this-SetY(-15);
//Arial italic 8
$this-SetFont('Arial','I',8);
//Page number
$this-Cell(0,10,'Page '.$this-PageNo().'/{nb}',0,0,'C');
}
$pdf=new PDF();
$pdf-AliasNbPages();
$pdf-AddPage();
$pdf-SetFont('Times','',12);
for($i=1;$i=40;$i++)
{
$pdf-Cell(0,10,'Printing line number '.$i,0,1);
}
$pdf-Output();
}
Nathan Mealey
Director of Operations
Cycle-Smart, Inc.
P.O. Box 1482
Northampton, MA
01061-1482
[EMAIL PROTECTED]
(413) 587-3133
(413) 210-7984 Mobile
(512) 681-7043 Fax
--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] Problems switching from MySQL 3.23 - 4.0
Hi, I have a page that grabs some data from a MySQL 3.23.58 database on a RedHat 9 box. I'm trying to migrate the db to a Suse box running MySQL 4.0.15. When I connect to the MySQL 4.0 DB, I get strange results. For example, there's a certain query that just returns the number of records in one of the tables: $c = $db-getOne(SELECT count(*) FROM tle); print($c); Against the 3.23 DB, this works fine. Against the 4.0 DB this prints out Object. Other queries return the same thing. What gives?? Some more details: Webserver Box: RedHat 9 Apache 2.0.40 PHP 4.2.2 The MySQL 3.2.3 DB also runs on this box. The MySQL 4.0 DB runs on a seperate Suse box. The Database structure data is identical on both systems. Ideas? Thanks Eric - This message was sent using Endymion MailMan. http://www.endymion.com/products/mailman/ -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] Date SELECT with IF
Hi, Is it possible to have a clause in a mysql SELECT statement? I would the query to display the date except where it equals the default 000-00-00 to display n/a or something similar. For example SELECT DATE_FORMAT(B.Booking_End_Date, \%Y-%m-%d\) AS 'Booking End Date' FROM Bookings (IF Booking_End_Date = '-00-00' DISPLAY 'n/a'); I hope this illustrates what I am trying to achieve! Thanks for your help -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Date SELECT with IF
SELECT IF( B.Booking_End_Date != -00-00, DATE_FORMAT( B.Booking_End_Date, %Y-%m-%d ), N/A ) AS Booking_End_Date FROM Bookings AS B, etc. HTH Ignatius _ - Original Message - From: Shaun [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Thursday, April 15, 2004 7:44 PM Subject: [PHP-DB] Date SELECT with IF Hi, Is it possible to have a clause in a mysql SELECT statement? I would the query to display the date except where it equals the default 000-00-00 to display n/a or something similar. For example SELECT DATE_FORMAT(B.Booking_End_Date, \%Y-%m-%d\) AS 'Booking End Date' FROM Bookings (IF Booking_End_Date = '-00-00' DISPLAY 'n/a'); I hope this illustrates what I am trying to achieve! Thanks for your help -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Date SELECT with IF
try the WHERE clause. SELECT name, address, phone, date FROM usertable WHERE date = '-00-00' And please, look at the mysql documentation, or at least the tutorial. -- Marcjon -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] Hi I am new to PHP
I have posted my problem at No: 33892 of this mailing list. I have received 1 reply. No: 33897 My exact problem with second file is as follows: Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource on line 15 Can you help me to solve problem, any help would be appreciated. Thanks. - Do you Yahoo!? Yahoo! Tax Center - File online by April 15th
[PHP-DB] Re: Hi I am new to PHP
It means there is a problem with your query, if you send the query back to the group someone may be able to help. Andy Amol [EMAIL PROTECTED] wrote in message news:[EMAIL PROTECTED] I have posted my problem at No: 33892 of this mailing list. I have received 1 reply. No: 33897 My exact problem with second file is as follows: Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource on line 15 Can you help me to solve problem, any help would be appreciated. Thanks. - Do you Yahoo!? Yahoo! Tax Center - File online by April 15th -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] lamer noob question
So I'm building this website; the first I've tried to build using a mostly dynamic
structure. What I've done is create a mysql table, with two fields: id and page_val.
The idea is you call the page like http://www.someplace.com/page.php?id=404 and it'll
spit back (in this case) the infamous 404 not found page. I've got it so it'll spit
back stuff from the DB, but only if I hard-code it...which defies the whole point of
this exercise.
Here's what I've got thus far:
!DOCTYPE html PUBLIC -//W3C//DTD HTML 4.01 Transitional//EN
html
head
titleWelcome to boardlady.com!/title
link rel=stylesheet type=text/css href=styles.css
SCRIPT language=JavaScript1.2 src=main.jstype=text/javascript/SCRIPT
/head
body
DIV id=TipLayer
style=visibility:hidden;position:absolute;z-index:1000;top:-100/DIV
SCRIPT language=JavaScript1.2 src=style.js type=text/javascript/SCRIPT
table width=750
trtd
table
trtdimg src=banner-1.gif alt=The Board Lady - Eva-M. Hollmann/tdtdOver
b3,281/b Served!/td/tr
/table
tabletrtd class=sideboxa href=index.html
onMouseOver=stm(Text[00],Style[12]) onMouseOut=htm()HOME/abrbrbra
href=intro.html onMouseOver=stm(Text[01],Style[12])
onMouseOut=htm()INTRO/abrbrbra href=repairs.html
onMouseOver=stm(Text[02],Style[12]) onMouseOut=htm()REPAIRS/abrbrbra
href=prices.html onMouseOver=stm(Text[03],Style[12])
onMouseOut=htm()PRICES/abrbrbra href=faq.html
onMouseOver=stm(Text[04],Style[12]) onMouseOut=htm()FAQ/abrbrbra
href=trailer.html onMouseOver=stm(Text[05],Style[12])
onMouseOut=htm()TRAILER/abrbrbra href=contact.html
onMouseOver=stm(Text[06],Style[12]) onMouseOut=htm()CONTACT ME/abrbrbra
href=directions.html onMouseOver=stm(Text[07],Style[12])
onMouseOut=htm()DIRECTIONS/a/td
td valign=top
!--Begin main body text--
?php
define ('DB_USER', 'user');
define ('DB_PASSWORD', '');
define ('DB_HOST', 'localhost');
define ('DB_NAME', 'database');
$dbc = mysql_connect (DB_HOST, DB_USER, DB_PASSWORD) OR die ('Could not connect to
database: ' . mysql_error());
@mysql_select_db (DB_NAME) OR die ('Could not connect to database: ' . mysql_error());
if ($page_req == ) {$id=index;}
elseif ($page_req == index) {$id=index;}
else { $id=404;}
$query = SELECT page_val FROM boardlady_site WHERE id =404;
$result = @mysql_query ($query);
while ($row = mysql_fetch_array($result)) {echo $row[0];}
mysql_close();
?
!--End main body text--
/td
/tr
trtd colspan=2centerdiv class=footer onMouseOver=stm(Text[08],Style[12])
onMouseOut=htm()This site a href=copyright.html style=color:#2f2f2f;
font-size:xx-small;text-decoration:none;font-weight:bold; target=newcopyright
(C)/a 2004 by Eva-M. Hollmann. All rights reserved./divdiv
class=footerbrWebsite design by Dan at a href=http://www.dibcomputers.com;
style=color:#2f2f2f; font-size:xx-small;text-decoration:none;font-weight:bold;
target=newDIB Computers./a/div/center/td/tr/table
/td/tr/table
/body
/html
First off, I need to know how to fetch variables out of the URL. I know this is
/supposed/ to be easy...but dammit I just can't get it to work. The other part that's
pissing me off is trying to stuff a variable inside my query variable...no matter what
I try I get a syntax error.
Yeah, I'm that noob. So were we all.
Thanks in advance,
Dan
[PHP-DB] Re: lamer noob question
Dan Bowkley wrote:
So I'm building this website; the first I've tried to build using a mostly dynamic structure. What I've done is create a mysql table, with two fields: id and page_val. The idea is you call the page like http://www.someplace.com/page.php?id=404 and it'll spit back (in this case) the infamous 404 not found page. I've got it so it'll spit back stuff from the DB, but only if I hard-code it...which defies the whole point of this exercise.
Here's what I've got thus far:
!DOCTYPE html PUBLIC -//W3C//DTD HTML 4.01 Transitional//EN
html
head
titleWelcome to boardlady.com!/title
link rel=stylesheet type=text/css href=styles.css
SCRIPT language=JavaScript1.2 src=main.jstype=text/javascript/SCRIPT
/head
body
DIV id=TipLayer
style=visibility:hidden;position:absolute;z-index:1000;top:-100/DIV
SCRIPT language=JavaScript1.2 src=style.js type=text/javascript/SCRIPT
table width=750
trtd
table
trtdimg src=banner-1.gif alt=The Board Lady - Eva-M. Hollmann/tdtdOver b3,281/b
Served!/td/tr
/table
tabletrtd class=sideboxa href=index.html onMouseOver=stm(Text[00],Style[12]) onMouseOut=htm()HOME/abrbrbra href=intro.html onMouseOver=stm(Text[01],Style[12]) onMouseOut=htm()INTRO/abrbrbra href=repairs.html onMouseOver=stm(Text[02],Style[12]) onMouseOut=htm()REPAIRS/abrbrbra href=prices.html
onMouseOver=stm(Text[03],Style[12]) onMouseOut=htm()PRICES/abrbrbra href=faq.html onMouseOver=stm(Text[04],Style[12]) onMouseOut=htm()FAQ/abrbrbra href=trailer.html onMouseOver=stm(Text[05],Style[12]) onMouseOut=htm()TRAILER/abrbrbra href=contact.html onMouseOver=stm(Text[06],Style[12]) onMouseOut=htm()CONTACT
ME/abrbrbra href=directions.html onMouseOver=stm(Text[07],Style[12]) onMouseOut=htm()DIRECTIONS/a/td
td valign=top
!--Begin main body text--
?php
define ('DB_USER', 'user');
define ('DB_PASSWORD', '');
define ('DB_HOST', 'localhost');
define ('DB_NAME', 'database');
$dbc = mysql_connect (DB_HOST, DB_USER, DB_PASSWORD) OR die ('Could not connect to
database: ' . mysql_error());
@mysql_select_db (DB_NAME) OR die ('Could not connect to database: ' . mysql_error());
if ($page_req == ) {$id=index;}
elseif ($page_req == index) {$id=index;}
else { $id=404;}
$query = SELECT page_val FROM boardlady_site WHERE id =404;
$result = @mysql_query ($query);
while ($row = mysql_fetch_array($result)) {echo $row[0];}
mysql_close();
?
!--End main body text--
/td
/tr
trtd colspan=2centerdiv class=footer onMouseOver=stm(Text[08],Style[12]) onMouseOut=htm()This site a href=copyright.html style=color:#2f2f2f;
font-size:xx-small;text-decoration:none;font-weight:bold; target=newcopyright (C)/a 2004 by Eva-M. Hollmann. All rights reserved./divdiv class=footerbrWebsite design by Dan at a
href=http://www.dibcomputers.com; style=color:#2f2f2f; font-size:xx-small;text-decoration:none;font-weight:bold; target=newDIB Computers./a/div/center/td/tr/table
/td/tr/table
/body
/html
First off, I need to know how to fetch variables out of the URL. I know this is /supposed/ to be easy...but dammit I just can't get it to work. The other part that's pissing me off is trying to stuff a variable inside my query variable...no matter what I try I get a syntax error..
Yeah, I'm that noob. So were we all.
Thanks in advance,
Dan
The query vars are in the $_GET, $_POST, and $_REQUEST superglobals.
Look up superglobals on php.net to see what they are. Here's a modified
DB query string for you:
$query = 'SELECT page_val FROM boardlady_site WHERE id ='.$_REQUEST['id'];
You will probably also want to change your $page_req vars up above.
This is all likely happening to you because register_globals is turned
off for you in your php.ini. Believe me, this is a good thing. Use the
superglobal arrays instead.
--
paperCrane Justin Patrin
--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] Hi I am new to PHP
Hi,
I have a problem with the second file. I am not able to update the
data from the php program. Any help on that would be appreciated.
Any modification which would be reduce the code like directly using the
Update command would be appreciated.
thanks in advance.
My exact problem with second file is as follows:
Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource on
line 15
Here are the 3 files.
File1
---
htmlheadtitleBook Update Form/title/head
body
?
$db=project;
$link = mysql_connect(localhost,name,passwd);
if (! $link)
die(Couldn't connect to MySQL);
mysql_select_db($db , $link)
or die(Couldn't open $db: .mysql_error());
$result = mysql_query( SELECT * FROM books )
or die(SELECT Error: .mysql_error());
$num_rows = mysql_num_rows($result);
print There are $num_rows records.P;
print table width=800 border=1\n;
while ($get_info = mysql_fetch_row($result)){
print tr\n;
foreach ($get_info as $field)
print \ttdfont face=arial size=2/$field/font/td\n;
print /tr\n;
}
print /table\n;
mysql_close($link);
//form method=POST action=book_change_form.php
?
br
form method=POST action=book_change_form.php
pre
Enter ISBN Number to Edit: input type=text name=id size=10
input type=submit value=Submitinput type=reset
/pre
/form
/body
/html
File 2
-
htmlheadtitleBook change form/title/head
body
?
$id=$_POST['id'];
$db=project;
//mysql_connect(localhost,$_POST['username'],$_POST['pass']);
$link = mysql_connect(localhost,name,passwd);
if (! $link)
die(Couldn't connect to MySQL);
mysql_select_db($db , $link)
or die(Couldn't open $db: .mysql_error());
$query= SELECT * FROM books WHERE id='$id';
$result=mysql_query($query);
$num=mysql_num_rows($result);
//echo $num;
$i=0;
while ($i $num)
{
$isbn=mysql_result($result,$i,isbn);
$title=mysql_result($result,$i,title);
$author=mysql_result($result,$i,author);
$edition=mysql_result($result,$i,edition);
$course_id=mysql_result($result,$i,course);
$quantity=mysql_result($result,$i,quantity);
$stack_no=mysql_result($result,$i,stack_no);
?
table width=300 cellpadding=10 cellspacing=0 border=2
tr align=center valign=top
td align=center colspan=1 rowspan=1 bgcolor=#64b1ff
h3Edit and Submit/h3
form action=book_change_record.php method=post
input type=hidden name=username value=?php print
$_POST['username']?
input type=hidden name=pass value=?php print $_POST['pass']?
input type=hidden name=ud_id value=? echo $id ?
ISBN:input type=text name=ud_isbn value=? print
$isbn?br
Title: input type=text name=ud_title value=? print
$title?br
Author: input type=text name=ud_author value=? print
$author?br
Edition: input type=text name=ud_edition value=? print
$edition?br
Course Id: input type=text name=ud_course_id value=? print
$course_id?br
Quantity:input type=text name=ud_quantity value=? print
$quantity?br
Stack Number:input type=text name=ud_stack_no value=? echo
$stack_no?br
input type=Submit value=Update
/form
/td/tr/table
?
++$i;
}//end while
?
/body
/html
//
File 3
htmlheadtitleBook Change Record/title/head
body
?
$user=$_POST['username'];
$password=$_POST['password'];
$ud_id=$_POST['ud_id'];
$ud_isbn=$_POST['ud_isbn'];
$ud_title=$_POST['ud_title'];
$ud_author=$_POST['ud_author'];
$ud_edition=$_POST['ud_edition'];
$ud_course_id=$_POST['ud_course_id'];
$ud_quantity=$_POST['ud_quantity'];
$ud_stack_no=$_POST['ud_stack_no'];
$db=project;
$link = mysql_connect(localhost,name,passwd);
if (! $link)
die(Couldn't connect to MySQL);
mysql_select_db($db , $link)
or die(Couldn't open $db: .mysql_error());
mysql_query( UPDATE books SET isbn='$ud_isbn' ,title='$ud_title',
author='$ud_author',edition='$ud_edition',course_id='$ud_course_id',
quantity = '$ud_quantity', stack_no =
'$ud_stack_no'
WHERE isbn='$ud_id');
echo Record Updated;
mysql_close($link);
?
form method=POST action=book_update_form.php
input type=hidden name=username value=?php print
$_POST['username']?
input type=hidden name=pass value=?php print
$_POST['password']?
input type=submit value=Change Another
/formbr
form method=POST action=book.php
input type=hidden name=username value=?php print
$_POST['username']?
input type=hidden name=pass value=?php print
$_POST['password']?
input type=submit value=Book Interface
/form
/body
/html
-
Do you Yahoo!?
Yahoo! Tax Center - File online by April 15th
Re: [PHP-DB] Hi I am new to PHP
On Thu, 15 Apr 2004 14:58:09 -0700 (PDT)
andy amol [EMAIL PROTECTED] wrote:
Hi,
I have a problem with the second file. I am not able to update the
data from the php program. Any help on that would be appreciated.
Any modification which would be reduce the code like directly using
the Update command would be appreciated.
thanks in advance.
My exact problem with second file is as follows:
Warning: mysql_num_rows(): supplied argument is not a valid MySQL
result resource on line 15
Andy,
This is probably not the entire error message. The above error message would have
shown the name of the php script that is broken. This would have made it easier for
whoever
Here are the 3 files.
File1
Looks okay...
File 2
-
htmlheadtitleBook change form/title/head
body
?
$id=$_POST['id'];
$db=project;
//mysql_connect(localhost,$_POST['username'],$_POST['pass']);
$link = mysql_connect(localhost,name,passwd);
if (! $link)
die(Couldn't connect to MySQL);
A better way to write this is
$link = mysql_connect(localhost,name,passwd)
or die(Couldn't connect to MySQL);
mysql_select_db($db , $link)
or die(Couldn't open $db: .mysql_error());
$query= SELECT * FROM books WHERE id='$id';
$result=mysql_query($query);
$num=mysql_num_rows($result);
//echo $num;
$i=0;
while ($i $num)
{
This could be rewritten as
while ($row = mysql_fetch_assoc($result);) {
The reason wil soon become apparent.
Okay, using mysql_result() functions calls is expensive as far as resources go.
$isbn=mysql_result($result,$i,isbn);
Each of these lines change into similar to the following example line
echo $row[isbn];
$title=mysql_result($result,$i,title);
echo $row[title];
$author=mysql_result($result,$i,author);
echo $row[author];
$edition=mysql_result($result,$i,edition);
echo $row[edition];
$course_id=mysql_result($result,$i,course);
echo $row[course];
$quantity=mysql_result($result,$i,quantity);
echo $row[quantity];
$stack_no=mysql_result($result,$i,stack_no);
echo $row[stack_no];
The reason for doing this is that each call to mysql_result() requires PHP to ask the
MySQL server for the cell specified. Even if your web server and MySQL server is on
the same machine, you will still notice a speed increase if you do just one fetch per
row rather than a fetch per field in the row. You would use mysql_result() if you are
wanting only one cell from a query result.
Otherwise this the rest of the looks pretty good.
?
/body
/html
//
File 3
htmlheadtitleBook Change Record/title/head
body
?
$user=$_POST['username'];
$password=$_POST['password'];
Move this line up to the other database connection values.
The rest of the file looks okay...
--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] Re: Hi I am new to PHP
[EMAIL PROTECTED] (Andy Amol) wrote in news:[EMAIL PROTECTED]: I have posted my problem at No: 33892 of this mailing list. I have received 1 reply. No: 33897 My exact problem with second file is as follows: Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource on line 15 Can you help me to solve problem, any help would be appreciated. Thanks. Your sql syntax is probably wrong. Somewhere before line 15 you are presumably using mysql_query to submit your query. Try adding to that line or exit( 'Error: ' .mysql_error() ); which will halt your script and return a useful error string from mysql if there is an error. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] Link to do query
Hi, I have a Tipster Website that lists a Tipster Ladder. So it shows their name and their current score. What I want to do is make their name clickable and upon clicking the name it loads that persons profile which is fetched from the mysql db. Now which would be the best way to do this? I have NEVER done a link query before but am familiar with forms. Would I best best to have it something like this: http://mydomain.com/profile.php?user=blah And do a query that fetches the user=blah bit? Or throw them in a form somehow? I have to be honest, with a link with the url above I am not familiar on how to grab the user=blah bit and throw it into a query. So a demo example would be great so I can learn/add to it. All suggestions, examples appreciated here. Thanks! J Find local movie times and trailers on Yahoo! Movies. http://au.movies.yahoo.com -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
