Hi All,
I have a problem working out a suitable algorithm either in PHP or MySQL.
Basically I have a DB that keeps track of breeding records. Each record
has a paired data, and a split-up date.
I need to generate some statistics to work out average numbers of pairs
per month, averaged on a
Hello,
Boaz Yahav wrote:
>
> Fail Over is not for when the cluster is too busy, it's for when the
> server dies, or when someone killed it's power, or when you loose your
> network, or when you get a blue screen (assuming you are on windows :).
Ok, it is the same. When the server is dead, the r
Hello,
Boaz Yahav wrote:
>
> I don't think you realize the nature of the site. Its an auction site
> and not a retail site.
> Prices need to be updated on thousands of clients simultaneously. Our
> goal is to
> refresh the data on the client every 3-10 seconds while having 1500
> online open
> a
Checking a small database for username/password combination would happen so
quick, it would be nearly impossible for two usernames to be entered in.
Your script should work properly, but to make sure no duplicates are
entered, you can change the column definition using the "ALTER columnName"
comma
I have a form in which users create their own login name. The code for
storing the login name they created does something like the following:
$userlogin is the name the user typed in the form
$sql = "select loginname from login where loginname='$userlogin'";
$result=mysql_query($sql);
$num=mysql_
For the form, use
and as for handling where the file get saved on the server-side, see:
http://www.php.net/manual/en/features.file-upload.php
On January 28, 2002 05:04 pm, you wrote:
> Hi there everyone,
>
> I'm writing an update utility for a database system, but I need to give the
> user the
Hi there everyone,
I'm writing an update utility for a database system, but I need to give the user the
option to select a file from their machine to upload to the server (Not to the DB
itself, but an images dir), what is the best way of doing this in PHP so that it
brings up a file requestor
I've been working on something like this since about September/October.
It's not too hard, but it did take more coding than I thought it would.
Now, there's a couple of ways you could do this. I chose the cheap (in
terms of the number of DB tables) way out.
The way I have it set up is this. You
I've done something similar by building a
multidimensional array of categories and subcats in
one query and then Loop thru this with a for each to
build the category structure.
Categories table looks like this
CatID | ParentID | CategoryName
Array is
$category_menu[$ParentID][$CatID]
I'm sure
Hi folks, I've got a question hopefully someone can shed some light on for
me.
I'm building an online store for a client, and one of the things he wants is
to organize his products into categories and subcategories.. not so unusual,
but the kicker is he wants to be able to associate a subcategory
Hi All,
Is there any function in PHP4.X or in Oracle8i to calculate number of
Business days ( excluding Saturday and Sunday) between two given dates?
Thanks in advance.
Sridhar.
-Original Message-
From: qartis [mailto:[EMAIL PROTECTED]]
Sent: Monday, January 28, 2002 1:38 PM
To: [EMAIL
thanks alot it helped
"Thomas "Omega" Henning" <[EMAIL PROTECTED]> wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> Hello how can i upload something from my hdd to the webserver using php?
>
> note: don't have ftp on the machine!!
>
> Thanks
>
> Thomas "omega" Henning
>
>
--
PHP
I think you might be looking for HTML form element.
"Duky Yuen" <[EMAIL PROTECTED]> wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> I want to make something like when you are attaching something to an
> email in hotmail. I want to make something that searches your own
> computer
> >If this file has a .php extension remote users will not have
> access to
> >the variables because the file is parsed by php and they
> never see the
> >actual file contents when requesting the document via the
> web. If you
> >are concerned with users on localhost having access to the
>
I've figured out a fairly secure program structure. Here's one option
(I'm sure there's as many ways to accomplish similar security as there
are people on this list):
First, a little info about the environment. It's a Linux OS running
Apache Web Server. Multi-user environment providing hosting
Hello Adv. Systems Design,
> I need to be able to update a field in MySQL, the catch is that I have to add on to
>text that is already there
and I have to be able to do it within MySQL (phpMyAdmin). My first idea was to do:
>
> SET prod_desc = prod_desc + "more info to tack on to end"
>
> but th
> SET prod_desc = prod_desc + "more info to tack on to end"
>
> but this is a mathematical function which returns 0!
update table set field = concat(field, "more info") where id = 1;
find the string functions in the mysql manual...
with kind regards,
Joffrey van Wageningen
--
PHP Database M
At 9:06 -0800 1/28/02, Adv. Systems Design wrote:
>hello all:
>
>I need to be able to update a field in MySQL, the catch is that I
>have to add on to text that is already there and I have to be able
>to do it within MySQL (phpMyAdmin). My first idea was to do:
>
>SET prod_desc = prod_desc + "mor
hello all:
I need to be able to update a field in MySQL, the catch is that I have to add on to
text that is already there and I have to be able to do it within MySQL (phpMyAdmin).
My first idea was to do:
SET prod_desc = prod_desc + "more info to tack on to end"
but this is a mathematical f
On Tuesday 29 January 2002 00:24, Markus Lervik wrote:
> On Monday 28 January 2002 18:06, Jason Wong wrote:
> $page behaves just fine :
[snip]
> page: 2 <- yup, it's incrementing, all right...
> nr_pages: 230
>
> Whack! Doesn't work any more... It's starting to drive me mad.
Me too. Post the
On Monday 28 January 2002 18:06, Jason Wong wrote:
> > Besides, I have a strange fetisch to do everything the hard way. : )
> Masochist :)
:D
> Anyway, as per the subject, how are you getting $page? I assume it is
> stored in the session. Is $page behaving correctly when you go from one
> page
On Monday 28 January 2002 23:45, Markus Lervik wrote:
> Well, in this particular case it won't work at all, because the SQL-query
> is dynamically created based on what the user wants to search for. It
> doesn't nessecary include all columns. The only static bit of the query is
> "FROM uusi_lehti
On Monday 28 January 2002 17:34, Jason Wong wrote:
>
> Crikey, it looks terribly complicated for what looks like something to page
> through a set of results.
>
> Wouldn't it be easier to do away with the ereg_replace()?
>
> if($go=="next") {
>if($page < $nr_pages && $page >= 0) {
> $pa
On Monday 28 January 2002 21:05, Markus Lervik wrote:
> On Monday 28 January 2002 14:57, Jason Wong wrote:
> > > Somehow when I print the value of $query, it looks fine.
> > > Then, when I change $query a bit and print it again,
> > > it looks fine.
> > > Change it a third time, and it suddenly ge
What I do, because I am using a test platform is to put the line with
pconnect() in a small text file, place this file somewhere on the disk,
outside of the web site root
and refer to that file with include() in my code.
This way, even if the PHP source code were compromised, the user name
and
Your select options have no values associated with them! Not sure if you did
this on purpose or not, but no value will be sent to next page.
Joe :)
"Raymond Lilleodegard" <[EMAIL PROTECTED]> wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> Hi all!
>
> I have this form with some c
Hi there, here's an upload form that might be what u are looking for:
Hope his helps you out :)
Joe
php page 1
Upload Photo:
php page 2 -- receiving/upload processing page
";
print $userfile_name . "";
// copy the file being posted
if(copy($userfile, "/ez/codesnipits/temprotatingimages/"
Hi guys,
I'm running mySQL 3.23.43 at the mo' with PHP-GTK 0.5.0. Long and the short
of the matter is, anyone running mySQL 4.0.2-alpha in anywhere near a
production
environment yet, and if so, how is it? My server is a Win2K Server SP2
box...so how steady are those windows binaries??? :-)
--
On Monday 28 January 2002 14:57, Jason Wong wrote:
> > Somehow when I print the value of $query, it looks fine.
> > Then, when I change $query a bit and print it again,
> > it looks fine.
> > Change it a third time, and it suddenly gets the value it
> > had in the beginning.
> Could you post som
Thanks Jason,
That was the answer I was looking for! It works like you suggested!!
Thanks
regards,
bart
-Oorspronkelijk bericht-
Van: Jason Wong [mailto:[EMAIL PROTECTED]]
Verzonden: maandag 28 januari 2002 13:52
Aan: [EMAIL PROTECTED]
Onderwerp: Re: [PHP-DB] mysql_insert_id - link_ide
On Monday 28 January 2002 20:45, Markus Lervik wrote:
> Hello!
>
> I have a problem with session_registered variables.
> It seems that my sessions behave quite erratic. Well,
> actually just one variable, $query.
>
> Somehow when I print the value of $query, it looks fine.
> Then, when I change $q
On Monday 28 January 2002 20:18, B. Verbeek wrote:
> I already run the query without the value of the primary-key field:
>
> $q_orders_id2 = "INSERT INTO orders(orders_datum, orders_sessid)";
> $q_orders_id2.= " VALUES ('$date', '$sid')";
> $r_orders_id2 = mysql_query($q_orders_id2, $sqllink
Hello!
I have a problem with session_registered variables.
It seems that my sessions behave quite erratic. Well,
actually just one variable, $query.
Somehow when I print the value of $query, it looks fine.
Then, when I change $query a bit and print it again,
it looks fine.
Change it a third
I already run the query without the value of the primary-key field:
>>
$q_orders_id2 = "INSERT INTO orders(orders_datum, orders_sessid)";
$q_orders_id2.= " VALUES ('$date', '$sid')";
$r_orders_id2 = mysql_query($q_orders_id2, $sqllink_id);
$orders_id = mysql_insert_id($sqllink_id);
<<
T
Hello,
How do I use the linkidentifier to get me the last_inserted_id
(mysql_insert_id) from a auto_increment-colomn?
Do I use:
>>
$q_orders_id2 = "INSERT INTO orders(orders_datum, orders_sessid)";
$q_orders_id2.= " VALUES ('$date', '$sid')";
$r_orders_id2 = mysql_query($q_orders_id2, $sql
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