Re: [PHP-DB] Re: Storing Variable Function Info

2002-07-24 Thread Martin Clifford
You're trying to use double quotes, in which the variable is evaluated and the stored value is shown, right? Try using single quotes. For example, with $name = Martin. echo My name is $name.; OUTPUT: My name is Martin. echo 'My name is $name.'; OUTPUT: My name is $name. It's interpreted

Re: [PHP-DB] Re: Storing Variable Function Info

2002-07-24 Thread Raquel Rice
On Wed, 24 Jul 2002 16:49:38 -0400 Martin Clifford Martin Clifford [EMAIL PROTECTED] wrote: You're trying to use double quotes, in which the variable is evaluated and the stored value is shown, right? Try using single quotes. For example, with $name = Martin. echo My name is $name.;

Re: [PHP-DB] Re: Storing Variable Function Info

2002-07-24 Thread Jason Wong
On Thursday 25 July 2002 05:11, Raquel Rice wrote: Thank you, Martin, for your informative response. If I understand correctly what you're saying, it would work to do (in psuedo code and reduce to simplest form): store_to_db(text = My name is $name.) Here $name will be evaluated and