Hi Dan,
> Hello all,
>
> I'm in the midst of creating an internet speed test system thingamabob for
> my website. It's basically finished...but ugly as sin. What I'd like to
do
> is have the results (an average of each domain tested) listed in a nice
> pretty table with alternating background c
This is the best contact description that I found so far on the net !
To contact Dan, the owner and lead technician, please email him at
[EMAIL PROTECTED] In case of dire emergency, crashed network, or other
pressing need you may also contact him 24 hours a day via cell phone at
xxx-xxx-xx. Please
I dont see what is your problem, your code do almost anything. Is you
pretend to generate the output in html as you show in the example, you just
have to add the color property in the "td" or "tr" tag, take care with the "
in the code. ex:
$dummy_var = 0;
$dummy_array = array("#dd", "#ff")
Hi,
You can use the modulus operator to create alternate colour rows.
A bit simpler in code ;)
See below -
echo "DomainAverage Speed\n";
// Define count variable which is tested in loop
$count = 1;
while ($mongorow = mysql_fetch_array($mongo, MYS
Or even simpler:
echo "DomainAverage Speed\n";
while ($mongorow = mysql_fetch_row($mongo, MYSQL_NUM))
{
$color = ("#e4e4e4")? "#ff" : "#e4e4e4";
echo "$mongorow[0]$mongorow[1]\n";
}
echo "";
Regards Henrik Hornemann
-Oprindelig meddelelse-
Fra: Paul Fitz [mailto:[EMAIL PROTECTED]
Hi,
Sorry, it should of course be
$color = ($color=="#e4e4e4")? "#ff" : "#e4e4e4";
-Oprindelig meddelelse-
Fra: Henrik Hornemann
Sendt: 26. januar 2004 13:38
Til: PHP DB
Emne: SV: [PHP-DB] Results with ledger stripes?
Or even simpler:
echo "DomainAverage Speed\n"; while
($mongorow
$bg1 = "#dd";
$bg2 = "#ff";
While ...
$bg3 = $bg2;
$bg2 = $bg1;
$bg1 = $bg3;
echo "
Makes sense?
<>< Ryan
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
Sent: Sunday, January 25, 2004 6:43 PM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] Results with ledger
I have Apache 1.3 and PHP 4 running on Windows 98 connecting to a local
MS SQL 7.0 server. MS SQL has the date as 2004-01-09 (-MM-DD), when
I print the date to a webpage with this PHP code:
printf("Date Picked Up: %s\nDate", date("Y/j/n",$row[0]);
I get this output:
1969/12/31
What is wr
One thing that is not a huge issue, just something to be aware of is the
default 2mb limit in the php.ini file. It is easily changed if you want
to upload bigger files.
- Paul
-Original Message-
From: John [mailto:[EMAIL PROTECTED]
Sent: Friday, January 23, 2004 10:04 PM
To: [EMAIL PROT
Hello All,
I am interested in storing images in a table. My question is - What
is the proper way of retrieving the images and displaying them on a
web page?
Will I need to go through the GD library and create an image from the
information stored in the table?
While PHP is not new to me, image
about once a quarter this question comes up and the answer is always
the same. Don't store them in the database, just store filenames and
store the files in the filesystem. That way you just generate a link and
treat it like any other image. Then when you query the database you
would create img ta
While I totally agree with Ryan, there are instances where I have found
that people do not follow best practices, namely Oracle (Oracle File
Storage) and many MySQL/PHP programs out there (OPT and Help Center
Live). So here is some code addressing both.
You would probably need an interpreter file
Thanks Ryan and Paul.
I agree, making references to the files is a more robust way of doing
things. In fact, that's the way I normally work.
I'm in the process of learning more about 'BLOBS' and exploring the
reality of storing images in a db/table versus the filesystem.
Anyway, thanks for the
The date() is for use with the 32-bit C time value returned by functions
like time(). Data from fields of type datetime are returned as strings in
the form Jan 9 2004 by the mssql extension as the default. To return it
using ISO format set mssql.datetimeconvert to "On" in the php.ini file, or
use
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