RE: [PHP-DB] Datetime help in an INSERT...
I have actually discovered that the $td value is blank. The reason appears to be that the page is reloading when a button is pushed, and that is when the $td value is being lost. My question now is, how do I keep the $td value after the page is reloaded? I would rather keep the value from the original query than perform another database query to populate this value yet again. Thanks yet again for the help. -Original Message- From: CPT John W. Holmes [mailto:[EMAIL PROTECTED] Sent: Wednesday, June 04, 2003 2:14 PM To: NIPP, SCOTT V (SBCSI); [EMAIL PROTECTED] Cc: [EMAIL PROTECTED] Subject: Re: [PHP-DB] Datetime help in an INSERT... I am stumbling across something that I thought I have done before, and I am not having any luck finding an example of this. Basically, I am wanting to timestamp the date and time into new entries in a simple database table. The following section is the actual code for this, and I cannot figure out how to get the date/time stamp to populate into the database. Thanks in advance for the help. I suspect this is a very simple fix. $denylog = INSERT INTO deny (account, td, date) VALUES ($tmp, $td, NOW()); $denylog_result = mysql_query($denylog, $Prod) or die(mysql_error()); The error I am receiving is: You have an error in your SQL syntax near ' NOW())' at line 1 Are you sure $td has a value? If it's blank, you'd get an error like that. ---John Holmes... -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Datetime help in an INSERT...
I have actually discovered that the $td value is blank. The reason appears to be that the page is reloading when a button is pushed, and that is when the $td value is being lost. My question now is, how do I keep the $td value after the page is reloaded? I would rather keep the value from the original query than perform another database query to populate this value yet again. Thanks yet again for the help. Stick it in the session? cookie? URL? What is $td? ---John Holmes... -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Datetime help in an INSERT...
OK. I guess the next question would be what is the best option for performance? This portion of the app currently doesn't have any session functionality built in. I would be setting up the session for this sole purpose. I haven't worked with cookies yet. I suppose the URL method might work, I have just never like it because I think it looks unclean, just personal preference there. As to the $td question... This is a variable that holds the userid of the Technical Director who is the account approver. This portion of the app is simply an approval mechanism to an account request system that I am developing. The TD receives an e-mail with a link back to the approval page to approve the requested accounts. This approval then fires off an e-mail to the SA responsible for user accounts to inform him to create the newly approved account. Well, thanks again for the feedback. Hopefully I can get this going pretty quick. We are currently planning on rolling this app out to our user community on Monday. This is the last issue I have that I am aware of. -Original Message- From: CPT John W. Holmes [mailto:[EMAIL PROTECTED] Sent: Thursday, June 05, 2003 9:06 AM To: NIPP, SCOTT V (SBCSI); [EMAIL PROTECTED] Cc: [EMAIL PROTECTED] Subject: Re: [PHP-DB] Datetime help in an INSERT... I have actually discovered that the $td value is blank. The reason appears to be that the page is reloading when a button is pushed, and that is when the $td value is being lost. My question now is, how do I keep the $td value after the page is reloaded? I would rather keep the value from the original query than perform another database query to populate this value yet again. Thanks yet again for the help. Stick it in the session? cookie? URL? What is $td? ---John Holmes... -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Datetime help in an INSERT...
Not sure exactly how I would implement this. Currently the reload URL is being provided via the $PHP_SELF variable. I like using this, but suppose I could change this if truly necessary. Also, the $td is not currently being passed into the function that generates the two buttons and hence defines the reload URL. I would rather not pass any additional variables into this function as I just feel this is unclean. Thanks again for the idea, and any additional advice or suggestions are most appreciated. -Original Message- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] Sent: Thursday, June 05, 2003 9:01 AM To: NIPP, SCOTT V (SBCSI) Subject: RE: [PHP-DB] Datetime help in an INSERT... You could alway place it as a GET echo a href=\yourscript.com/yourpage.php?td=$td\; Gary Every Sr. UNIX Administrator Ingram Entertainment (615) 287-4876 Pay It Forward mailto:[EMAIL PROTECTED] mailto:[EMAIL PROTECTED] http://accessingram.com http://accessingram.com -Original Message- From: NIPP, SCOTT V (SBCSI) [ mailto:[EMAIL PROTECTED] mailto:[EMAIL PROTECTED] ] Sent: Thursday, June 05, 2003 8:57 AM To: 'CPT John W. Holmes'; [EMAIL PROTECTED] Cc: [EMAIL PROTECTED] Subject: RE: [PHP-DB] Datetime help in an INSERT... I have actually discovered that the $td value is blank. The reason appears to be that the page is reloading when a button is pushed, and that is when the $td value is being lost. My question now is, how do I keep the $td value after the page is reloaded? I would rather keep the value from the original query than perform another database query to populate this value yet again. Thanks yet again for the help. -Original Message- From: CPT John W. Holmes [ mailto:[EMAIL PROTECTED] mailto:[EMAIL PROTECTED] ] Sent: Wednesday, June 04, 2003 2:14 PM To: NIPP, SCOTT V (SBCSI); [EMAIL PROTECTED] Cc: [EMAIL PROTECTED] Subject: Re: [PHP-DB] Datetime help in an INSERT... I am stumbling across something that I thought I have done before, and I am not having any luck finding an example of this. Basically, I am wanting to timestamp the date and time into new entries in a simple database table. The following section is the actual code for this, and I cannot figure out how to get the date/time stamp to populate into the database. Thanks in advance for the help. I suspect this is a very simple fix. $denylog = INSERT INTO deny (account, td, date) VALUES ($tmp, $td, NOW()); $denylog_result = mysql_query($denylog, $Prod) or die(mysql_error()); The error I am receiving is: You have an error in your SQL syntax near ' NOW())' at line 1 Are you sure $td has a value? If it's blank, you'd get an error like that. ---John Holmes... -- PHP Database Mailing List ( http://www.php.net/ http://www.php.net/ ) To unsubscribe, visit: http://www.php.net/unsub.php http://www.php.net/unsub.php
RE: [PHP-DB] Datetime help in an INSERT...
I just responded to a separate but similar suggestion. The form elements, including the buttons, are all generated in a separate function. I am currently passing about 5 variables into this function and I am a little hesitant to pass any others. I am not sure about complexity, performance, etc. in passing so many variables into a function. Please let me know if anyone has any ideas on this. I doubt that this is happening, but I would really like for the code to be as easily maintainable as possible. -Original Message- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] Sent: Thursday, June 05, 2003 9:48 AM To: NIPP, SCOTT V (SBCSI) Subject: RE: [PHP-DB] Datetime help in an INSERT... a button is being pressed? so it is processing a form? if its in a form just pass along the value of $td via hidden input data... input type=hidden name=td value=? echo $td; ? jay merritt [EMAIL PROTECTED] [EMAIL PROTECTED] OK. I guess the next question would be what is the best option for performance? This portion of the app currently doesn't have any session functionality built in. I would be setting up the session for this sole purpose. I haven't worked with cookies yet. I suppose the URL method might work, I have just never like it because I think it looks unclean, just personal preference there. As to the $td question... This is a variable that holds the userid of the Technical Director who is the account approver. This portion of the app is simply an approval mechanism to an account request system that I am developing. The TD receives an e-mail with a link back to the approval page to approve the requested accounts. This approval then fires off an e-mail to the SA responsible for user accounts to inform him to create the newly approved account. Well, thanks again for the feedback. Hopefully I can get this going pretty quick. We are currently planning on rolling this app out to our user community on Monday. This is the last issue I have that I am aware of. -Original Message- From: CPT John W. Holmes [mailto:[EMAIL PROTECTED] Sent: Thursday, June 05, 2003 9:06 AM To: NIPP, SCOTT V (SBCSI); [EMAIL PROTECTED] Cc: [EMAIL PROTECTED] Subject: Re: [PHP-DB] Datetime help in an INSERT... I have actually discovered that the $td value is blank. The reason appears to be that the page is reloading when a button is pushed, and that is when the $td value is being lost. My question now is, how do I keep the $td value after the page is reloaded? I would rather keep the value from the original query than perform another database query to populate this value yet again. Thanks yet again for the help. Stick it in the session? cookie? URL? What is $td? ---John Holmes... -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Datetime help in an INSERT...
Thought I was on track, but stumped again... I am now getting a completely different error that I cannot figure out how it is related. I have passed the $td variable into the function and then get it back as a POST variable from a hidden field within the function. Here is the error I am now seeing; Unknown column 'sn4265' in 'field list' This one is really throwing me at the moment as the only place the value sn4265 is stored is in the $sbcuid variable. This $sbcuid variable is not a part of the INSERT that I am performing which I think is generating this error. I am guessing that you guys will need more info to help out with this now. Just let me know what you want. Thanks again. -Original Message- From: CPT John W. Holmes [mailto:[EMAIL PROTECTED] Sent: Thursday, June 05, 2003 10:07 AM To: NIPP, SCOTT V (SBCSI) Subject: Re: [PHP-DB] Datetime help in an INSERT... Just pass the variable to your function. If you're using a form, then make it a hidden element. ---John Holmes... - Original Message - From: NIPP, SCOTT V (SBCSI) [EMAIL PROTECTED] To: 'CPT John W. Holmes' [EMAIL PROTECTED] Sent: Thursday, June 05, 2003 10:53 AM Subject: RE: [PHP-DB] Datetime help in an INSERT... Do you think URL propagation is a better option than passing another variable into the function and then passing it back out through a hidden form element? Here was another snippet from another suggestion on this. a button is being pressed? so it is processing a form? if its in a form just pass along the value of $td via hidden input data... input type=hidden name=td value=? echo $td; ? jay merritt [EMAIL PROTECTED] [EMAIL PROTECTED] -Original Message- From: CPT John W. Holmes [mailto:[EMAIL PROTECTED] Sent: Thursday, June 05, 2003 9:53 AM To: NIPP, SCOTT V (SBCSI) Subject: Re: [PHP-DB] Datetime help in an INSERT... Propagating it in the URL is probably the best method. ---John Holmes... - Original Message - From: NIPP, SCOTT V (SBCSI) [EMAIL PROTECTED] To: 'CPT John W. Holmes' [EMAIL PROTECTED]; [EMAIL PROTECTED] Cc: [EMAIL PROTECTED] Sent: Thursday, June 05, 2003 10:44 AM Subject: RE: [PHP-DB] Datetime help in an INSERT... OK. I guess the next question would be what is the best option for performance? This portion of the app currently doesn't have any session functionality built in. I would be setting up the session for this sole purpose. I haven't worked with cookies yet. I suppose the URL method might work, I have just never like it because I think it looks unclean, just personal preference there. As to the $td question... This is a variable that holds the userid of the Technical Director who is the account approver. This portion of the app is simply an approval mechanism to an account request system that I am developing. The TD receives an e-mail with a link back to the approval page to approve the requested accounts. This approval then fires off an e-mail to the SA responsible for user accounts to inform him to create the newly approved account. Well, thanks again for the feedback. Hopefully I can get this going pretty quick. We are currently planning on rolling this app out to our user community on Monday. This is the last issue I have that I am aware of. -Original Message- From: CPT John W. Holmes [mailto:[EMAIL PROTECTED] Sent: Thursday, June 05, 2003 9:06 AM To: NIPP, SCOTT V (SBCSI); [EMAIL PROTECTED] Cc: [EMAIL PROTECTED] Subject: Re: [PHP-DB] Datetime help in an INSERT... I have actually discovered that the $td value is blank. The reason appears to be that the page is reloading when a button is pushed, and that is when the $td value is being lost. My question now is, how do I keep the $td value after the page is reloaded? I would rather keep the value from the original query than perform another database query to populate this value yet again. Thanks yet again for the help. Stick it in the session? cookie? URL? What is $td? ---John Holmes... -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Datetime help in an INSERT...
I am now getting a completely different error that I cannot figure out how it is related. I have passed the $td variable into the function and then get it back as a POST variable from a hidden field within the function. Here is the error I am now seeing; Unknown column 'sn4265' in 'field list' This one is really throwing me at the moment as the only place the value sn4265 is stored is in the $sbcuid variable. This $sbcuid variable is not a part of the INSERT that I am performing which I think is generating this error. I am guessing that you guys will need more info to help out with this now. Just let me know what you want. Thanks again. Well, if $sbcuid isn't being used, something with its value is. What does the query look like? Common sense would say that if you're having trouble with a query, you'd at least post that bit of code, right? ---John W. Holmes... Amazon Wishlist: http://www.amazon.com/o/registry/3BEXC84AB3A5E PHP Architect - A monthly magazine for PHP Professionals. Get your copy today. http://www.phparch.com/ -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] Datetime help in an INSERT...
I am stumbling across something that I thought I have done before, and I am not having any luck finding an example of this. Basically, I am wanting to timestamp the date and time into new entries in a simple database table. The following section is the actual code for this, and I cannot figure out how to get the date/time stamp to populate into the database. Thanks in advance for the help. I suspect this is a very simple fix. $denylog = INSERT INTO deny (account, td, date) VALUES ($tmp, $td, NOW()); $denylog_result = mysql_query($denylog, $Prod) or die(mysql_error()); Scott Nipp Phone: (214) 858-1289 E-mail: [EMAIL PROTECTED] Web: http:\\ldsa.sbcld.sbc.com -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Datetime help in an INSERT...
The error I am receiving is: You have an error in your SQL syntax near ' NOW())' at line 1 -Original Message- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] Sent: Wednesday, June 04, 2003 1:45 PM To: NIPP, SCOTT V (SBCSI) Subject: Re: [PHP-DB] Datetime help in an INSERT... what kind of error are you getting? I am stumbling across something that I thought I have done before, and I am not having any luck finding an example of this. Basically, I am wanting to timestamp the date and time into new entries in a simple database table. The following section is the actual code for this, and I cannot figure out how to get the date/time stamp to populate into the database. Thanks in advance for the help. I suspect this is a very simple fix. $denylog = INSERT INTO deny (account, td, date) VALUES ($tmp, $td, NOW()); $denylog_result = mysql_query($denylog, $Prod) or die(mysql_error()); Scott Nipp Phone: (214) 858-1289 E-mail: [EMAIL PROTECTED] Web: http:\\ldsa.sbcld.sbc.com -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Datetime help in an INSERT...
If you are using MySql with the date field is of type timestamp, you should have to insert anything using the query. It will update automatically when the record is inserted and/or updated. ie; $denylog = INSERT INTO deny (account, td ) VALUES ($tmp, $td ); Randy -Original Message- From: NIPP, SCOTT V (SBCSI) [mailto:[EMAIL PROTECTED] Sent: Wednesday, June 04, 2003 1:47 PM To: '[EMAIL PROTECTED]' Cc: '[EMAIL PROTECTED]' Subject: RE: [PHP-DB] Datetime help in an INSERT... The error I am receiving is: You have an error in your SQL syntax near ' NOW())' at line 1 -Original Message- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] Sent: Wednesday, June 04, 2003 1:45 PM To: NIPP, SCOTT V (SBCSI) Subject: Re: [PHP-DB] Datetime help in an INSERT... what kind of error are you getting? I am stumbling across something that I thought I have done before, and I am not having any luck finding an example of this. Basically, I am wanting to timestamp the date and time into new entries in a simple database table. The following section is the actual code for this, and I cannot figure out how to get the date/time stamp to populate into the database. Thanks in advance for the help. I suspect this is a very simple fix. $denylog = INSERT INTO deny (account, td, date) VALUES ($tmp, $td, NOW()); $denylog_result = mysql_query($denylog, $Prod) or die(mysql_error()); Scott Nipp Phone: (214) 858-1289 E-mail: [EMAIL PROTECTED] Web: http:\\ldsa.sbcld.sbc.com -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Datetime help in an INSERT...
Correction ( I typed this in a hurry ) ... If you are using MySql and the date field is of type timestamp, you should _not_ have to insert anything using the query. It will update automatically when the record is inserted and/or updated. ie; $denylog = INSERT INTO deny (account, td ) VALUES ($tmp, $td ); Randy -Original Message- From: Rankin, Randy [mailto:[EMAIL PROTECTED] Sent: Wednesday, June 04, 2003 1:56 PM To: '[EMAIL PROTECTED]' Subject: RE: [PHP-DB] Datetime help in an INSERT... If you are using MySql with the date field is of type timestamp, you should have to insert anything using the query. It will update automatically when the record is inserted and/or updated. ie; $denylog = INSERT INTO deny (account, td ) VALUES ($tmp, $td ); Randy -Original Message- From: NIPP, SCOTT V (SBCSI) [mailto:[EMAIL PROTECTED] Sent: Wednesday, June 04, 2003 1:47 PM To: '[EMAIL PROTECTED]' Cc: '[EMAIL PROTECTED]' Subject: RE: [PHP-DB] Datetime help in an INSERT... The error I am receiving is: You have an error in your SQL syntax near ' NOW())' at line 1 -Original Message- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] Sent: Wednesday, June 04, 2003 1:45 PM To: NIPP, SCOTT V (SBCSI) Subject: Re: [PHP-DB] Datetime help in an INSERT... what kind of error are you getting? I am stumbling across something that I thought I have done before, and I am not having any luck finding an example of this. Basically, I am wanting to timestamp the date and time into new entries in a simple database table. The following section is the actual code for this, and I cannot figure out how to get the date/time stamp to populate into the database. Thanks in advance for the help. I suspect this is a very simple fix. $denylog = INSERT INTO deny (account, td, date) VALUES ($tmp, $td, NOW()); $denylog_result = mysql_query($denylog, $Prod) or die(mysql_error()); Scott Nipp Phone: (214) 858-1289 E-mail: [EMAIL PROTECTED] Web: http:\\ldsa.sbcld.sbc.com -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Datetime help in an INSERT...
No, the field is a Datetime field rather than a Timestamp field. -Original Message- From: Rankin, Randy [mailto:[EMAIL PROTECTED] Sent: Wednesday, June 04, 2003 1:59 PM To: '[EMAIL PROTECTED]' Subject: RE: [PHP-DB] Datetime help in an INSERT... Correction ( I typed this in a hurry ) ... If you are using MySql and the date field is of type timestamp, you should _not_ have to insert anything using the query. It will update automatically when the record is inserted and/or updated. ie; $denylog = INSERT INTO deny (account, td ) VALUES ($tmp, $td ); Randy -Original Message- From: Rankin, Randy [mailto:[EMAIL PROTECTED] Sent: Wednesday, June 04, 2003 1:56 PM To: '[EMAIL PROTECTED]' Subject: RE: [PHP-DB] Datetime help in an INSERT... If you are using MySql with the date field is of type timestamp, you should have to insert anything using the query. It will update automatically when the record is inserted and/or updated. ie; $denylog = INSERT INTO deny (account, td ) VALUES ($tmp, $td ); Randy -Original Message- From: NIPP, SCOTT V (SBCSI) [mailto:[EMAIL PROTECTED] Sent: Wednesday, June 04, 2003 1:47 PM To: '[EMAIL PROTECTED]' Cc: '[EMAIL PROTECTED]' Subject: RE: [PHP-DB] Datetime help in an INSERT... The error I am receiving is: You have an error in your SQL syntax near ' NOW())' at line 1 -Original Message- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] Sent: Wednesday, June 04, 2003 1:45 PM To: NIPP, SCOTT V (SBCSI) Subject: Re: [PHP-DB] Datetime help in an INSERT... what kind of error are you getting? I am stumbling across something that I thought I have done before, and I am not having any luck finding an example of this. Basically, I am wanting to timestamp the date and time into new entries in a simple database table. The following section is the actual code for this, and I cannot figure out how to get the date/time stamp to populate into the database. Thanks in advance for the help. I suspect this is a very simple fix. $denylog = INSERT INTO deny (account, td, date) VALUES ($tmp, $td, NOW()); $denylog_result = mysql_query($denylog, $Prod) or die(mysql_error()); Scott Nipp Phone: (214) 858-1289 E-mail: [EMAIL PROTECTED] Web: http:\\ldsa.sbcld.sbc.com -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Datetime help in an INSERT...
I am stumbling across something that I thought I have done before, and I am not having any luck finding an example of this. Basically, I am wanting to timestamp the date and time into new entries in a simple database table. The following section is the actual code for this, and I cannot figure out how to get the date/time stamp to populate into the database. Thanks in advance for the help. I suspect this is a very simple fix. $denylog = INSERT INTO deny (account, td, date) VALUES ($tmp, $td, NOW()); $denylog_result = mysql_query($denylog, $Prod) or die(mysql_error()); The error I am receiving is: You have an error in your SQL syntax near ' NOW())' at line 1 Are you sure $td has a value? If it's blank, you'd get an error like that. ---John Holmes... -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Datetime help in an INSERT...
1. Change your field name from date to something like datefield (or backtick
it)
2. Place single quotes within your VALUES parens, e.g.
$denylog = INSERT INTO deny (account, td, datefield ) VALUES ('$tmp',
'$td', NOW() )
Gary Every
Sr. UNIX Administrator
Ingram Entertainment
(615) 287-4876
Pay It Forward
mailto:[EMAIL PROTECTED]
http://accessingram.com
-Original Message-
From: NIPP, SCOTT V (SBCSI) [mailto:[EMAIL PROTECTED]
Sent: Wednesday, June 04, 2003 2:06 PM
To: 'Rankin, Randy'; '[EMAIL PROTECTED]'
Subject: RE: [PHP-DB] Datetime help in an INSERT...
No, the field is a Datetime field rather than a Timestamp field.
-Original Message-
From: Rankin, Randy [mailto:[EMAIL PROTECTED]
Sent: Wednesday, June 04, 2003 1:59 PM
To: '[EMAIL PROTECTED]'
Subject: RE: [PHP-DB] Datetime help in an INSERT...
Correction ( I typed this in a hurry ) ...
If you are using MySql and the date field is of type
timestamp, you should
_not_
have to insert anything using the query. It will update
automatically when
the record is inserted and/or updated.
ie; $denylog = INSERT INTO deny (account, td ) VALUES ($tmp, $td );
Randy
-Original Message-
From: Rankin, Randy [mailto:[EMAIL PROTECTED]
Sent: Wednesday, June 04, 2003 1:56 PM
To: '[EMAIL PROTECTED]'
Subject: RE: [PHP-DB] Datetime help in an INSERT...
If you are using MySql with the date field is of type
timestamp, you should
have to insert anything using the query. It will update
automatically when
the record is inserted and/or updated.
ie; $denylog = INSERT INTO deny (account, td ) VALUES ($tmp, $td );
Randy
-Original Message-
From: NIPP, SCOTT V (SBCSI) [mailto:[EMAIL PROTECTED]
Sent: Wednesday, June 04, 2003 1:47 PM
To: '[EMAIL PROTECTED]'
Cc: '[EMAIL PROTECTED]'
Subject: RE: [PHP-DB] Datetime help in an INSERT...
The error I am receiving is:
You have an error in your SQL syntax near ' NOW())' at line 1
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
Sent: Wednesday, June 04, 2003 1:45 PM
To: NIPP, SCOTT V (SBCSI)
Subject: Re: [PHP-DB] Datetime help in an INSERT...
what kind of error are you getting?
I am stumbling across something that I thought I have
done before,
and I am not having any luck finding an example of this.
Basically, I am
wanting to timestamp the date and time into new entries in a simple
database
table. The following section is the actual code for this,
and I cannot
figure out how to get the date/time stamp to populate into
the database.
Thanks in advance for the help. I suspect this is a very
simple fix.
$denylog = INSERT INTO deny (account, td, date) VALUES ($tmp, $td,
NOW());
$denylog_result = mysql_query($denylog, $Prod) or
die(mysql_error());
Scott Nipp
Phone: (214) 858-1289
E-mail: [EMAIL PROTECTED]
Web: http:\\ldsa.sbcld.sbc.com
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RE: [PHP-DB] Datetime help in an INSERT...
I think this is the real problem. Basically, the $td variable is defined intially, but upon clicking a button the page reloads itself and I believe that at this time it is losing the $td variable. I am not quite sure how to prevent this from occurring. Thanks again for all the help so far. -Original Message- From: CPT John W. Holmes [mailto:[EMAIL PROTECTED] Sent: Wednesday, June 04, 2003 2:14 PM To: NIPP, SCOTT V (SBCSI); [EMAIL PROTECTED] Cc: [EMAIL PROTECTED] Subject: Re: [PHP-DB] Datetime help in an INSERT... I am stumbling across something that I thought I have done before, and I am not having any luck finding an example of this. Basically, I am wanting to timestamp the date and time into new entries in a simple database table. The following section is the actual code for this, and I cannot figure out how to get the date/time stamp to populate into the database. Thanks in advance for the help. I suspect this is a very simple fix. $denylog = INSERT INTO deny (account, td, date) VALUES ($tmp, $td, NOW()); $denylog_result = mysql_query($denylog, $Prod) or die(mysql_error()); The error I am receiving is: You have an error in your SQL syntax near ' NOW())' at line 1 Are you sure $td has a value? If it's blank, you'd get an error like that. ---John Holmes... -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Datetime help in an INSERT...
2. Place single quotes within your VALUES parens, e.g.
If they are really strings. Integers or dates in a MMDD format do not
require quotes.
$denylog = INSERT INTO deny (account, td, datefield ) VALUES ('$tmp',
'$td', NOW() )
---John Holmes...
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