The most performant methods are to use well parameterized stored procedure or a
prepared parameterized statement.
: Ashay
-Original Message-
From: Niel Archer [mailto:n...@chance.now]
Sent: Wednesday, November 17, 2010 6:30 AM
To: php-db@lists.php.net
Subject: Re: [PHP-DB] query help
rom: Artur Ejsmont [mailto:ejsmont.ar...@gmail.com]
Sent: 17 noiembrie 2010 16:07
To: Vinay Kannan
Cc: PHP DB; php mysql
Subject: Re: [PHP-DB] query help
well i guess you could do that. but it gets complicated after a while
and there will be a lot of work and probably after a while you will get
> Hello PHP Gurus,
>
> I need your help on an insert query.
>
> I wanted to know if there is way to insert an array of values into a DB. An
> eg would explain this better :
>
> If I have 2 tables in a DB, 1) users has 3 columns 2) hobbies = 5 columns
>
> I was thinking of having a single functi
From: "Vinay Kannan"
To: "PHP DB" , "php mysql"
Sent: Wednesday, November 17, 2010 2:51:35 PM GMT +01:00 Amsterdam / Berlin /
Bern / Rome / Stockholm / Vienna
Subject: [PHP-DB] query help
Hello PHP Gurus,
I need your help on an insert query.
I wanted to kno
On Wed, Nov 17, 2010 at 8:51 AM, Vinay Kannan wrote:
> Hello PHP Gurus,
>
> I need your help on an insert query.
>
> I wanted to know if there is way to insert an array of values into a DB. An
> eg would explain this better :
>
> If I have 2 tables in a DB, 1) users has 3 columns 2) hobbies = 5 co
well i guess you could do that. but it gets complicated after a
while and there will be a lot of work and probably after a while you
will get into some problems. You have to handle escaping, special
types etc. Then what about performance? how to query the data ...
using similar approach or is
Hello PHP Gurus,
I need your help on an insert query.
I wanted to know if there is way to insert an array of values into a DB. An
eg would explain this better :
If I have 2 tables in a DB, 1) users has 3 columns 2) hobbies = 5 columns
I was thinking of having a single function which will perfor
Hey Everyone,
I can use some help here I have query where one can selects an
"style" then a "area" and finally "rating" through a drop menu. When
some selects a rating they select a range of ratings. For example:
Style: Traditional
Area: Yosemite
Rating: From: 5.5 To: 5.10c
This should
Hi Everyone, Happy Easter to you all.
I have this query, reasoning for posting on this
Mailing List is under it. :)
SELECT `username` , `score` FROM round" .
$round_number . " WHERE 1
ORDER BY `score` DESC LIMIT 0, 30
Is there a way to make it output the $round_number -1
(minus one number)?
I n
: [EMAIL PROTECTED]
Subject: Re: [PHP-DB] Query Help...
- Original Message -
From: "NIPP, SCOTT V (SBCSI)" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Monday, March 10, 2003 9:23 AM
Subject: [PHP-DB] Query Help...
> I am having a lot of trouble with a query that
- Original Message -
From: "NIPP, SCOTT V (SBCSI)" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Monday, March 10, 2003 9:23 AM
Subject: [PHP-DB] Query Help...
> I am having a lot of trouble with a query that works fine from a
> basic SQL command line
03 5:24 pm
> To: '[EMAIL PROTECTED]'
> Subject: [PHP-DB] Query Help...
>
>
> I am having a lot of trouble with a query that works fine from a
> basic SQL command line, but fails in my web script. Here is the
> portion of
> code including the query:
>
> my
I am having a lot of trouble with a query that works fine from a
basic SQL command line, but fails in my web script. Here is the portion of
code including the query:
mysql_select_db($database, $Prod);
$query_groups = "SELECT name FROM group";
$groups = mysql_query($query_groups, $Prod) or
I've implemented the scheme I briefly outlined in my last post (locking
for data integrity), and now I'm writing queries to get totals from my
logs, and I think I might be over-complicating things, and I'd like some
alternative views on the subject.
My "grandiose scheme" works like this:
Problem:
EMAIL PROTECTED]]
Sent: Sunday, December 16, 2001 5:05 PM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] Query Help
Hi people,
I have a small problem with a select cause that I need to use.
I basically need the following.
Select * from table where page =3D=3D page_name
The fields in the db are
Hi people,
I have a small problem with a select cause that I need to use.
I basically need the following.
Select * from table where page =3D=3D page_name
The fields in the db are
code,description,unit,price,category,minor_category
Then the display needs to be something along the lines of
al Message-
From: Matt Williams <[EMAIL PROTECTED]>
To: Andrey Hristov <[EMAIL PROTECTED]>
Cc: [EMAIL PROTECTED] <[EMAIL PROTECTED]>
Date: Monday, November 19, 2001 10:26
Subject: RE: [PHP-DB] Query help
>This doesn't work either.
>
>SELECT count(freerooms.r
This doesn't work either.
SELECT count(freerooms.room), WEEK(MAX(booking.date),1),
WEEK(MIN(booking.date),1) as total FROM freerooms LEFT JOIN booking
USING(room);
> > All good so far
> > now if I run this
> >
> > SELECT count(f.room),WEEK(MAX(b.date),1), WEEK(MIN(b.date),1)
> FROM freero
> > om
PROTECTED]>
Sent: Friday, November 16, 2001 5:32 PM
Subject: Re: [PHP-DB] Query help
> SELECT count(f.room),WEEK(MAX(b.date),1), WEEK(MIN(b.date),1) FROM freero
> oms f, booking b;
>
> will be
> SELECT count(f.room),WEEK(MAX(b.date),1), WEEK(MIN(b.date),1) FROM freero
>
USING
Other problems?
Write..
Regards,
Andrey Hristov
IcyGEN Corporation
http://www.icygen.com
BALANCED SOLUTIONS
- Original Message -
From: "Matt Williams" <[EMAIL PROTECTED]>
To: "Php-Db@Lists. Php." <[EMAIL PROTECTED]>
Sent: Friday, November 16, 2001
Not really this list but I'm after a quick bit of help.
If I run this query
select count(room) from freerooms;
->83
and this
SELECT WEEK(MAX(date),1), WEEK(MIN(date),1)as totalweeks FROM booking;
->4840
All good so far
now if I run this
SELECT count(f.room),WEEK(MAX(b.date),1), WEEK(MIN(b
can anyone figure out why the following code works fine when both select
variables = "ALL" and also when only 1 of the 2 ="ALL" but NOT when BOTH
select variables equal something other than "ALL"?
here is the code:
What area of the city would you like to dine in?
\n";
$select.="ALL\n";
w
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