thank you for explaining this to me Amit. It works. Ron
The Verse of the Day
“Encouragement from God’s Word”
http://www.TheVerseOfTheDay.info
From: Amit Tandon
Sent: Friday, May 06, 2011 5:49 AM
To: Ron Piggott
Cc: php-db@lists.php.net
Subject: Re: [PHP-DB] COUNT and OUTER JOIN results
Dear Ron
Take your condition to ON cluause. So your on clause (for LEFT JOIN) would
read something like
ON `prayer_request_category`.`
reference` = `prayer_requests`.`prayer_request_category_reference`
AND
`prayer_requests`.`approval_
level` IN ( 1, 3 )
`prayer_requests`.`prayer_request_type` =
On 13 August 2010 13:43, Ron Piggott wrote:
> SELECT `bible_concordance_words`.`reference`,
> `bible_concordance_words`.`word`,
> COUNT(`bible_concordance_word_reference`.`bible_concordance_words_reference`)
> AS occurrences FROM `bible_concordance_words` INNER JOIN
> `bible_concordance_word_refer
Thanks for your help, Chris. You certainly got me going in the right
direction. In case anyone is interested, below is the completed
solution, with design elements, turned into a function so I can
easily call it several times.
function counter_maker ($database,$name,$link)
{
Kevin Murphy wrote:
Actually the design is in the code below I need to display the
counts from all of those queries in a grid. Basically, its just a
summary of a bunch of information. Another way to look at it would be a
several lines that say something like this:
You have $data1_count NE
Actually the design is in the code below I need to display the
counts from all of those queries in a grid. Basically, its just a
summary of a bunch of information. Another way to look at it would be
a several lines that say something like this:
You have $data1_count NEW records in data1
> Kevin Murphy asks:
> The following code works and accomplishes what I need it to do, but I
> am wondering if there is a better way to accomplish the same task. I
> have several tables of records and I need to count and then display.
> Even if I could just combine the first three queries (below)
Here is how I would do:
1. Group your visits by IP, order them in time and give each row a
sequential number starting with 1
(not completely trivial - exercise left to the reader)
Now you have a temporary table T ( ip, timestamp, rank )
2. Join the table to itself on two consecutive rows, and co
John,
>That's because you're displaying how many "rows" were returned from the
>query, not the value that COUNT() returns. A query with COUNT() is
>always going to return at least one row.
>
>$visitcount = mysql_result($query,0);
Yes, that was it! Thank you so much.
Lew
--
PHP Database Mailing
Lew Mark-Andrews wrote:
I get a count of 1 for the number of visits
($visitcount) using my following code. It should be 0.
---
code in check_visits.php
$sql = "SELECT COUNT(visitdate) FROM cardlist GROUP BY visitdate";
$query = mysql_query($sql) or die(" Cannot
query the database
On Mon, Dec 22, 2003 at 11:43:35AM +0900, Lew Mark-Andrews wrote:
> Table structure for cardlist:
> `visitdate` datetime default NULL,
> $sql = "SELECT COUNT(visitdate) FROM cardlist GROUP BY visitdate";
> $visitcount = mysql_num_rows($query);
> echo "Total number of visits: $visitcount"; // <
On Mon, 22 Sep 2003, Peter Beckman wrote:
> On Mon, 22 Sep 2003, Frank McIsaac wrote:
>
> > Hi all. I was wanting to make a page that takes a set date and
> > counts down to zero displaying days, minutes, and seconds. Basically, I
> > want it to count down from the current date and time
On Mon, 22 Sep 2003, Frank McIsaac wrote:
> Hi all. I was wanting to make a page that takes a set date and
> counts down to zero displaying days, minutes, and seconds. Basically, I
> want it to count down from the current date and time until a future date
> and time is reached (ie. Sept
Shaun wrote:
Is it possible to combine the COUNT & AVG functions using MySQL? I have a
table called Bookings and I need to find out the average number of bookings.
So I need to count the number of bookings in the table and then get the
Average, is this possible?
Learn SQL, please.
SELECT COUNT(co
Becoming Digital'" <[EMAIL PROTECTED]>; <[EMAIL PROTECTED]>
Sent: Tuesday, 10 June, 2003 13:14
Subject: RE: [PHP-DB] Count database-values
Edward,
Have you considered trying mysql_result()?
It appears that your query is going to always return a single piece of data:
Total. So
use the index number instead
of the column name as the documentation recommends, the performance should
be just fine.
Hope this helps.
Rich
> -Original Message-
> From: Becoming Digital [mailto:[EMAIL PROTECTED]
> Sent: Tuesday, June 10, 2003 12:50 PM
> To: [EMAIL PROTECTE
t; <[EMAIL PROTECTED]>
To: "'Becoming Digital'" <[EMAIL PROTECTED]>; <[EMAIL PROTECTED]>
Sent: Tuesday, 10 June, 2003 11:54
Subject: RE: [PHP-DB] Count database-values
> -Original Message-
> From: Becoming Digital [mailto:[EMAIL PROTECTED]
> Sent: 10
> }
>
> Edward Dudlik
> Becoming Digital
> www.becomingdigital.com
>
>
> - Original Message -
> From: "Becoming Digital" <[EMAIL PROTECTED]>
> To: <[EMAIL PROTECTED]>
> Sent: Tuesday, 10 June, 2003 06:43
> Subject: Re: [PHP-DB] Count databa
igital
www.becomingdigital.com
- Original Message -
From: "Becoming Digital" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Tuesday, 10 June, 2003 06:43
Subject: Re: [PHP-DB] Count database-values
> So far no problems, but I want to count all these values.
&g
> So far no problems, but I want to count all these values.
> I tried with SUM but with the following code it doesn't work:
>
> $squery = "SELECT SUM(bedrag) AS Total FROM finance WHERE posneg = 'af'";
>
> any suggestions how to do? I want to store it in a variabele ($total)
> so I can echo it. (E.
Hi Dave
Assuming you are using mysql try the following query
select count(Admin_id) as admin1, Admin_id as admin2 from TABLE_NAME group
by admin2
substituting TABLE_NAME for whatever you have called your table.
Hope this helps
Cheers
Tony James
- Original Message -
From: "Dave
assuming these are your fields:
post_id
admin_id
code would look something like:
admin_id;
print("Admin $i has $Admin[$i] posts.");
}
?>
___
Ryan Marrs
Web Developer
Sandler & Travis Trade Advisory Services, Inc.
248.474.7200 x 183
248.4
;
Sent: Thursday, April 11, 2002 6:52 AM
Subject: RE: [PHP-DB] count
> Something like this
> Select sum(ID) name from $table;
>
> Where name is some name that I come up with?
>
> >Ronald L. Allen (MCSE NT, MCP, CCNA)
> SR. LAN/WAN Administrator
> >SFOR - Hungary, Cro
SELECT SUM(column) as somename FROM table;
Mike
- Original Message -
From: "Ron Allen" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Thursday, April 11, 2002 6:52 AM
Subject: [PHP-DB] count
> I would like to count all the total records from a database. How would I
go
> about doing
USe the count() function in mysql.
Like this:
$query = "SELECT count(artist) as howmany FROM artist
WHERE artist LIKE
'b%' GROUP BY artist ORDER BY artist
ASC";
$result = mysql_query($query) or die("Select
Failed!");
echo "Total Number Of Artists In
\"B\": ";
echo mysql_num_rows($resul
On Sunday 10 February 2002 00:55, Barry Rumsey wrote:
> I have the following code:
> $query = "SELECT * FROM artist WHERE artist LIKE 'b%' ORDER BY artist
> ASC";
[snip]
> What I would like to know is how do I do a count on each result
> returned.e.g. Benny(4) , Bill(10)
Try:
$query = "SELECT
Afterthought -- you could make this self-maintaining by doing a select for
$PHP_SELF and inserting the record if mysql_num_rows() returned 0. Downside
is that it would add greatly to the overhead.
Miles
At 04:42 PM 1/16/2002 -0400, Miles Thompson wrote:
>Barry,
>
>Before leaping to the wrong c
Barry,
Before leaping to the wrong conclusion, what exactly do you want to count?
You can derive the number of times a page has been fetched from your web logs.
Alternately, you could add a table to your database, and at the top of the
page the link points to, after you've established your da
Barry,
I can't see where you've created $topictest.
Maybe, just before you define $queyr2, you should have the line
$topictest = $row[ "topcitext"];
I also think xp_stories_topicid should be xp_stories.topicid
Try echo 'ing $query2 and see what is printed.
Hope this helps, and that I've not m
Hi,
SELECT SUM(IF(id = '2',1,0)) AS field_name FROM table
Versatile command - you can use it for quite a lot of things.
Barry Rumsey wrote:
> Is it posible to do a count(*) on a tabe where id=2 and count just those that id =
>2
--
--
Dan Barton
Terrestrial Program Biologist
Asst. D
Barry,
Is it posible to do a count(*) on a tabe where id=2 and count just those that id = 2
=why don't you try it?
The answer is yes, because count(*) means count the entire number of non-null rows
selected.
See manual: 3.3.4.8 Counting Rows
=dn
--
PHP Database Mailing List (http://www
What is retrieved if you do a Select Count(*) from myDb where
condition = parameters?
Seems your result set should contain this value...
Phil J.
DC wrote:
> Hi All
> I cant quite work out how to count the number of rows in my mysql db that
> match a certain critieria and the show that number n
Cheers Brian
Thats sounds more like i am looking for
Although i have put the other code examples offered for this prob in my code
folder for later cause you never now when you'll need them.
Cheers
Dave C
""Brian S. Dunworth"" <[EMAIL PROTECTED]> wrote in message
[EMAIL PROTECTED]">news:[EMAI
At 10:06 AM 3/30/01 -0800, Larry Rivera wrote:
>I think you have to run multiple queries, ie run some loop after finding out
>what topics you wil count from e==>
>
>run a select distinct to get the topics
>run a while or for loop then run queries again like count(*) where
>topic='$topic'
Bette
Thanks i will give that ago.
"Andrei Skorokhod" <[EMAIL PROTECTED]> wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> if you just need the number
>
> SELECT COUNT(*) FROM table where
>
> At 06:34 PM 3/30/2001 +0100, DC wrote:
> >Hi All
> >I cant quite work out how t
try mysql_num_rows function
-Original Message-
From: DC [mailto:[EMAIL PROTECTED]]
Sent: Friday, March 30, 2001 9:34 AM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] count function?
Hi All
I cant quite work out how to count the number of rows in my mysql db that
match a certain critieria and
if you just need the number
SELECT COUNT(*) FROM table where
At 06:34 PM 3/30/2001 +0100, DC wrote:
>Hi All
>I cant quite work out how to count the number of rows in my mysql db that
>match a certain critieria and the show that number numericaly in my pages.
>
>Checked books, ph
al Message-
> From: DC [mailto:[EMAIL PROTECTED]]
> Sent: Friday, March 30, 2001 9:53 AM
> To: [EMAIL PROTECTED]
> Subject: Re: [PHP-DB] count function?
>
>
> Ok i think i need to expand my help request... my fault
>
> I have a db that uses ids for topics in a m
-Original Message-
From: DC [mailto:[EMAIL PROTECTED]]
Sent: Friday, March 30, 2001 9:53 AM
To: [EMAIL PROTECTED]
Subject: Re: [PHP-DB] count function?
Ok i think i need to expand my help request... my fault
I have a db that uses ids for topics in a message board ie each topic has
messag
Ok i think i need to expand my help request... my fault
I have a db that uses ids for topics in a message board ie each topic has
messages of various numbers in them.
>From my select a topic page i hope to put the number of messages in the
topic, so it visually looks like this sort of...
to
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