, July 05, 2011 5:47 PM
To: Robert Cummings
Cc: Dajka Tamás; php-general@lists.php.net
Subject: Re: [PHP] Foreach question
Just use count($arr) in your for-header, as it get's executed again
for each loop.
?php
$arr = array(array('id'=1), array('id'=2));
for($i=0;$icount($arr);$i
Hi all,
I've bumped into an interesting thing with foreach. I really don't know, if
this is normal working, or why it is, so I got curious.
The script:
foreach ( $cats as $c ) {
echo $c['id'];
if ( $c['id'] 5 ) {
Hi there
I think that foreach in your first example just knowns that this
should be the last loop (as the array only contains 1 element at
start) and so stops there.
In your 2nd example however the first loop isn't the last, so the
array get's checked again, and now there's another element, so...
On 11-07-05 09:40 AM, Dajka Tamas wrote:
Hi all,
I've bumped into an interesting thing with foreach. I really don't know, if
this is normal working, or why it is, so I got curious.
The script:
foreach ( $cats as$c ) {
echo $c['id'];
if ( $c['id'] 5 )
Or maybe he tried to do the following?
?php
foreach ( $cats as$c ) {
echo $c['id'];
if ($c['id'] 5) {
$cats[] = array('id' = ($c['id'] + 1));
}
}
?
2011/7/5 Robert Cummings rob...@interjinn.com:
On 11-07-05 09:40 AM,
: Robert Cummings [mailto:rob...@interjinn.com]
Sent: Tuesday, July 05, 2011 4:06 PM
To: Dajka Tamas
Cc: php-general@lists.php.net
Subject: Re: [PHP] Foreach question
On 11-07-05 09:40 AM, Dajka Tamas wrote:
Hi all,
I've bumped into an interesting thing with foreach. I really don't know
elements from the array...
Cheers,
Tamas
-Original Message-
From: Louis Huppenbauer [mailto:louis.huppenba...@gmail.com]
Sent: Tuesday, July 05, 2011 4:12 PM
To: Robert Cummings
Cc: Dajka Tamas; php-general@lists.php.net
Subject: Re: [PHP] Foreach question
Or maybe he tried
On 11-07-05 10:20 AM, Dajka Tamás wrote:
Hi,
Yeah, I'm really want to do that, since I'm working with the elements of the
original array ( skipped that part in sample code ).
I've tried your suggestion, but it gives the same result, so on just one input
is just gives back '1'.
Ahhh... you
I don't think that it does this:
if ( count($elements) == 1 ) then loop 1;
else loop normally;
It's probably more something like that:
$i=count($elements);
loop:
$i--;
if($i == 0)
$last_loop = true;
else
$last_loop = false
if($last_loop)
exit;
else
goto loop;
But aside from
with two elements? ( since the first elements copy is pushed as third element,
etc )
-Original Message-
From: Robert Cummings [mailto:rob...@interjinn.com]
Sent: Tuesday, July 05, 2011 4:28 PM
To: Dajka Tamás
Cc: php-general@lists.php.net
Subject: Re: [PHP] Foreach question
On 11-07-05
On 11-07-05 10:39 AM, Dajka Tamás wrote:
Ok, but if it would be that way I shouldn't get '122334455' for second output,
no? The item count increments with every iteration of the loop.
Or you're saying that, it checks for an existance of nextitem before every
loop, and that will fail with
On 11-07-05 10:39 AM, Dajka Tamás wrote:
Ok, but if it would be that way I shouldn't get '122334455' for second output,
no? The item count increments with every iteration of the loop.
Or you're saying that, it checks for an existance of nextitem before every
loop, and that will fail with just
On 11-07-05 09:40 AM, Dajka Tamas wrote:
foreach ( $cats as$c ) {
echo $c['id'];
if ( $c['id'] 5 ) {
$c['id']++;
$cats[] = $c;
}
}
Given that you seem to want the above
On 11-07-05 10:48 AM, Dajka Tamás wrote:
Thanks, that was interesting :) I think I got one step further in understanding
PHP :)
BTW, I've changed the loop to 'for' and it's working well :)
Can you show us your for loop? I'm not immediately sure how you use a
for loop to traverse a growing
On Tue, Jul 5, 2011 at 2:40 PM, Dajka Tamas vi...@vipernet.hu wrote:
I've bumped into an interesting thing with foreach. I really don't know, if
this is normal working, or why it is, so I got curious.
The script:
foreach ( $cats as $c ) {
echo $c['id'];
if (
Just use count($arr) in your for-header, as it get's executed again
for each loop.
?php
$arr = array(array('id'=1), array('id'=2));
for($i=0;$icount($arr);$i++) {
echo $arr[$i]['id'];
if($i 6) {
$arr[] = array('id' =
On 11-07-05 11:46 AM, Louis Huppenbauer wrote:
Just use count($arr) in your for-header, as it get's executed again
for each loop.
?php
$arr = array(array('id'=1), array('id'=2));
for($i=0;$icount($arr);$i++) {
echo $arr[$i]['id'];
if($i 6) {
Hey Everyone...
So I am attempting to pull 2 random records from a MySQL database, so
I wrote a function which I'll paste below. I had it mostly working
with a while() statement, but I wanted to try a foreach to see if I
could get the formatting a little bit better.
Basically... What it
On Tue, Jul 29, 2008 at 3:25 PM, Jason Pruim [EMAIL PROTECTED] wrote:
function random($random){
$randomQuery = SELECT * FROM `current` ORDER BY Rand() LIMIT 2;
$result = mysql_query($randomQuery);
$row[] = $result;
foreach($row as $key = $value) {
$random[$key] = $value;
You cannot do this:
$row[] = $result;
You need to loop around this:
$row = mysql_fetch_assoc($result);
Thank you,
Micah Gersten
onShore Networks
Internal Developer
http://www.onshore.com
Jason Pruim wrote:
Hey Everyone...
So I am attempting to pull 2 random records from a MySQL
On Jul 29, 2008, at 3:33 PM, Daniel Brown wrote:
On Tue, Jul 29, 2008 at 3:25 PM, Jason Pruim [EMAIL PROTECTED]
wrote:
function random($random){
$randomQuery = SELECT * FROM `current` ORDER BY Rand() LIMIT
2;
$result = mysql_query($randomQuery);
$row[] = $result;
On Nov 15, 2007, at 7:50 PM, Juan Marcelo Rodríguez wrote:
2007/11/15, Philip Thompson [EMAIL PROTECTED]:
On Nov 15, 2007 5:12 PM, Juan Marcelo Rodríguez
[EMAIL PROTECTED]
wrote:
Yes, I made a mistake in the first sentence.
The code is :
[...]
foreach ($equipos as $key = $val){
echo trtd;
HI,
I'm working with an associative array, and generating its data a form. I use
foreach to loops the contents of the array and echo to print the table and
the data. Everything goes well, however I would like to add a counter to
print the row's number.
The question : Am I able to add a counter
Yes, I made a mistake in the first sentence.
The code is :
[...]
foreach ($equipos as $key = $val){
echo trtd;
echo 1 . /tdtd; // I would like to add the counter here reeplacing
1
print input type=\radio\ name=$key value=\l\ / . /tdtd;
echo $key . /tdtd;
print input type=\radio\ name=$key
2007/11/15, Philip Thompson [EMAIL PROTECTED]:
On Nov 15, 2007 5:12 PM, Juan Marcelo Rodríguez
[EMAIL PROTECTED]
wrote:
Yes, I made a mistake in the first sentence.
The code is :
[...]
foreach ($equipos as $key = $val){
echo trtd;
echo 1 . /tdtd; // I would like to add the
Thanks.
I solved it using this :
$x = 0;
foreach ($equipos as $key = $val){
$x = $x + 1;
echo trtd;
echo $x . /tdtd;
2007/11/15, Michael McGlothlin [EMAIL PROTECTED]:
$x = 0;
foreach ( $blah as $bleh ) {
$x = $x + 1;
print $x: $bleh;
}
HI,
I'm working with an associative array, and
On Nov 15, 2007 5:12 PM, Juan Marcelo Rodríguez [EMAIL PROTECTED]
wrote:
Yes, I made a mistake in the first sentence.
The code is :
[...]
foreach ($equipos as $key = $val){
echo trtd;
echo 1 . /tdtd; // I would like to add the counter here
reeplacing
1
echo trtd.($key+1)./tdtd;
Juan Marcelo Rodríguez wrote:
I'm working with an associative array, and generating its data a form. I use
foreach to loops the contents of the array and echo to print the table and
the data. Everything goes well, however I would like to add a counter to
print the row's number.
The question :
$x = 0;
foreach ( $blah as $bleh ) {
$x = $x + 1;
print $x: $bleh;
}
HI,
I'm working with an associative array, and generating its data a form. I use
foreach to loops the contents of the array and echo to print the table and
the data. Everything goes well, however I would like to add a counter
On Sun, April 8, 2007 6:29 pm, [EMAIL PROTECTED] wrote:
I have ..
foreach( $_POST as $key ) {
echo $keybr /;
}
You are actually echoing out the VALUE, not the KEY...
and that gives me
item1
item2
item3
item4
item5br /
Unless your VALUE has item1\nitem2\nitem3\nitem4\nitem5 in
-general@lists.php.net
Sent: Monday, April 09, 2007 5:20 AM
Subject: Re: [PHP] foreach question
[EMAIL PROTECTED] wrote:
both examples do the same thing..
no, ex1 only has 1 br /
so outputs like..
item1item2item3item4item5br /
Where as I want this..
item1br /
item2br
I have ..
foreach( $_POST as $key ) {
echo $keybr /;
}
and that gives me
item1
item2
item3
item4
item5br /
how do I write it to give me
item1br /
item2br /
item3br /
item4br /
item5br /
Thanks
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit:
[EMAIL PROTECTED] wrote:
I have ..
foreach( $_POST as $key ) {echo $keybr /;
}
and that gives me
item1
item2
item3
item4
item5br /
how do I write it to give me
item1br /
item2br /
item3br /
item4br /
item5br /
Thanks
both examples do the same thing..
--
PHP General Mailing List
PROTECTED]
Cc: php-general@lists.php.net
Sent: Monday, April 09, 2007 1:22 AM
Subject: Re: [PHP] foreach question
[EMAIL PROTECTED] wrote:
I have ..
foreach( $_POST as $key ) {echo $keybr /;
}
and that gives me
item1
item2
item3
item4
item5br /
how do I write it to give me
item1br /
item2br
]
Cc: php-general@lists.php.net
Sent: Monday, April 09, 2007 1:22 AM
Subject: Re: [PHP] foreach question
[EMAIL PROTECTED] wrote:
I have ..
foreach( $_POST as $key ) {echo $keybr /;
}
and that gives me
item1
item2
item3
item4
item5br /
how do I write it to give me
item1br /
item2br
AM
Subject: Re: [PHP] foreach question
[EMAIL PROTECTED] wrote:
I have ..
foreach( $_POST as $key ) {echo $keybr /;
}
and that gives me
item1
item2
item3
item4
item5br /
how do I write it to give me
item1br /
item2br /
item3br /
item4br /
item5br
the full script to the list.
Lori
- Original Message - From: Sebe [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Cc: php-general@lists.php.net
Sent: Monday, April 09, 2007 1:22 AM
Subject: Re: [PHP] foreach question
[EMAIL PROTECTED] wrote:
I have ..
foreach( $_POST as $key ) {echo $keybr
be better to post the full script to the list.
Lori
- Original Message - From: Sebe [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Cc: php-general@lists.php.net
Sent: Monday, April 09, 2007 1:22 AM
Subject: Re: [PHP] foreach question
[EMAIL PROTECTED] wrote:
I have ..
foreach( $_POST as $key
PROTECTED]
To: [EMAIL PROTECTED]
Cc: php-general@lists.php.net
Sent: Monday, April 09, 2007 5:20 AM
Subject: Re: [PHP] foreach question
[EMAIL PROTECTED] wrote:
both examples do the same thing..
no, ex1 only has 1 br /
so outputs like..
item1item2item3item4item5br /
Where as I want
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