Re[2]: [PHP] Help!! with array's Please

[Richard Kurth]

Hello Tom,

Thursday, February 27, 2003, 7:39:52 PM, you wrote:

TR> Hi,

TR> Friday, February 28, 2003, 12:20:38 PM, you wrote:

RK>> I really need somebody to help me with this I am totally lost on what
RK>> to do

RK>> I need a way to read the following text file and add to or delete from
RK>> or change the data.
RK>> I have been able to move it all into an array using this code
RK>> $groups= file("group");
RK>> for ($i=0; $i<$number_in_group; $i++){
RK>> $groups[0];
RK>> $groups[3]; <-- this is the part of the array that I need to change
RK>> }
RK>> But I can not figure out how to search the array and delete from or add
RK>> to the array at a given point. I would like to say add another user to
RK>> the end of site6 or delete a user from site3.
RK>> Could somebody give me a hand here. I have read the manual for arrays
RK>> and still can't figure it out.

RK>> site1:x:503:tester1
RK>> site2:x:504:tester2,tester2a
RK>> site3:x:505:tester3,tester3a,tester3b
RK>> site4:x:506:tester4
RK>> site5:x:507:tester5,tester5a,tester5b
RK>> site6:x:508:tester6
RK>> site7:x:509:tester7,tester7a,tester7b  

RK>> -- 
RK>> Best regards,
RK>>  Richard  mailto:[EMAIL PROTECTED]

TR> your groups array will look like this

TR> groups[0] = site1:x:503:tester1
TR> groups[1] = site2:x:504:tester2,tester2a
TR> so loop through the array

TR> $x = 0;
TR> while(list($key,$val) = each($groups)){

TR> //you need split the array values like this
TR>   list($name,$pass,$gid,$user_list) = split (":", $groups[$x]);
TR>   //see if we have the right one
TR>   if($name = $wanted_name){ //site6
TR>  //then split the usernames into a sub array
TR>  $users = explode(',',$userlist);
TR>  // to add
TR>  $users[] = $newuser;
TR>  // to delete
TR>  unset($users[3])
TR>  // now add it back
TR>  $userlist = implode(',',$users)
TR>  $list = $name.':'.$pass.':'.$gid.':'.$userlist;
TR>  $groups[$x] = $list;
TR>   }
TR>   $x++;
TR>   //here you could fputs to a temp file then copy to the original
TR>   // after finished
TR> }

TR> Then write groups back to disk
TR> -- 
TR> regards,
TR> Tom

Thanks for the help!!

I still can't seam to get it to add a new user at the end of a line of
the selected site name.
Also how do I use the unset($users[3]) do I first have to determine
what number the one I what to delete is.
Here is what I have so far
$newuser="tester45";
$wanted_name="site7";
$groups= file("group");
$x = 0;
while(list($key,$val) = each($groups)){
//you need split the array values like this
 list($name,$pass,$gid,$user_list) = split (":", $groups[$x]);
 //see if we have the right one
 if($name = $wanted_name){ //site6
//then split the usernames into a sub array
 $users = explode(',',$userlist);
 // to add
 $users[] = $newuser;
  // to delete
 //unset($users[3]);
 // now add it back
 $userlist = implode(',',$users);
 $list = $name.':'.$pass.':'.$gid.':'.$userlist;
 $groups[$x] = $list;
  }
  
  $x++;
$handle = fopen("group2", 'a');
fputs($handle, $groups[$x]);
  //here you could fputs to a temp file then copy to the original
  // after finished
}
//Then write groups back to disk





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 Richardmailto:[EMAIL PROTECTED]


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Re: [PHP] Re: mysqldump

[Tom Rogers]

Hi,

Thursday, February 27, 2003, 2:55:48 PM, you wrote:
JTJ> Thanks!

>> exec("mysqldump -c -q database -u user -ppassword", $sql);

JTJ> Why is there no space between the -p and password?

>>-ppassword

JTJ> Am I wrong?

JTJ> Thanks,
JTJ> John

Probably because a space is a valid char in password

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Tom


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Re: [PHP] Function returns an array of objects...

[Tom Rogers]

Hi,

Friday, February 28, 2003, 4:24:54 PM, you wrote:
AS> so i have a function that creates objects (with member variables) and 
AS> pushes those objects onto the array. after adding all of the objects, 
AS> the function then returns the array...

AS> i'm having trouble accessing the members of each object in the 
AS> array...i'm trying to do something like this:

AS> class Object {
AS> var $id;
AS> function Object($param) {
AS> $this->id = $param;
AS> }
AS> }

AS> function getArrayOfObjects() {
AS> $theArray = array();
AS> for ($i = 0; $i < 10; $i++) {
AS> $theArray[] = new Objects($i);
AS> }
AS> return $theArray;
AS> }

AS> $temp = getArrayOfObjects();
echo $temp[0]->>id;  // this should display "0"

AS> do i have to do something with references or dereference the id 
AS> variable some other way? i'm coming from java where something like this 
AS> is extremely easy...

AS> thanks
AS> amit

Try like this  (note the 2 & symbols)

function &getArrayOfObjects() {
$theArray = array();
for ($i = 0; $i < 10; $i++) {
$theArray[] =& new Objects($i);
}
return $theArray;
}
$temp = getArrayOfObjects();
echo $temp[0]->id;
-- 
regards,
Tom


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Re: [PHP] Passing url?variables

[Leif K-Brooks]

http://www.php.net/manual/en/security.registerglobals.php

Mike wrote:

Hi,

I'm running Apache 2.0 and PHP 4.2.2 on a RedHat 8.0 Machine. I'm unable
to pass variables through a URL like index.php?test=something. Can
anyone help here? I've looked through both my httpd.conf and php.ini
files and didn't see anything...
-Michael

 

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[PHP] php install help

[Karl James]

Hey guys,

Im having problems getting my helloworld.php file to 
Work on the apache server.
My phpinfo.php works perfect.
I know the code is write
The error message I get is
#
Internal Server Error
The server encountered an internal error or misconfiguration and was
unable to complete your request.
Please contact the server administrator, [EMAIL PROTECTED] and
inform them of the time the error occurred, and anything you might have
done that may have caused the error.

More information about this error may be available in the server error
log.





How can I correct this
The linked I used is.
Localhost/phpinfo.php
And the one that is not working is
Localhost/helloworld.php
ultimatefootballleague.com/index.php
[EMAIL PROTECTED]
 



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[PHP] Passing url?variables

[Mike]

Hi,

I'm running Apache 2.0 and PHP 4.2.2 on a RedHat 8.0 Machine. I'm unable
to pass variables through a URL like index.php?test=something. Can
anyone help here? I've looked through both my httpd.conf and php.ini
files and didn't see anything...

-Michael


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[PHP] Function returns an array of objects...

[Amit Snyderman]

so i have a function that creates objects (with member variables) and 
pushes those objects onto the array. after adding all of the objects, 
the function then returns the array...

i'm having trouble accessing the members of each object in the 
array...i'm trying to do something like this:

class Object {
var $id;
function Object($param) {
$this->id = $param;
}
}
function getArrayOfObjects() {
$theArray = array();
for ($i = 0; $i < 10; $i++) {
$theArray[] = new Objects($i);
}
return $theArray;
}
$temp = getArrayOfObjects();
echo $temp[0]->id;   // this should display "0"
do i have to do something with references or dereference the id 
variable some other way? i'm coming from java where something like this 
is extremely easy...

thanks
amit
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[PHP] RE: mysqldump

[Uttam]

snip from manual for -p option:

|-

-p[password], --password[=...]

Password to use when connecting to server. If a password is not given on the
command line, you will be prompted for it.  Note that if you use the short
form -p you can't have a space between the option and the password.

-|

regds,
-Original Message-
From: Niels Andersen [mailto:[EMAIL PROTECTED]
Sent: Thursday, February 27, 2003 16:09
To: [EMAIL PROTECTED]
Subject: Re: mysqldump


There mey, but need not be a space. As far as I know, the option scanner
in
mysqldump ignores spaces between short options and their values.


"John Taylor-Johnston" <[EMAIL PROTECTED]> wrote in
message
news:[EMAIL PROTECTED]
> Thanks!
>
> > exec("mysqldump -c -q database -u user -ppassword", $sql);
>
> Why is there no space between the -p and password?
>
> >-ppassword
>
> Am I wrong?
>
> Thanks,
> John
>




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Re: [PHP] help with getting php going(2)

[Kim Kohen]

G'day Karl

> Hey guys I finally got my phpinfo file to show on apache server
> But when I try to do a hello world or browser check I get a 500 error
> message

FWIW, I've seen this error when I've had mac line endings instead of unix.

cheers

kim


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[PHP] help with getting php going(2)

[Karl James]

Title: Message





Hey guys I finally got my phpinfo file to show on apache server
But when I try to do a hello world or browser check I 
get a 500 error message
Can anyone help me out, and educate me what I’m doing 
wrong.
 

This is my 
script