Hello everyone.
I'm encountering difficulties using my arrays.
while ($row = mysql_fetch_array($result)) {
$link[$c] = $row['link'];
$c = $c + 1;
}
This is where I try using it.
while ($row = mysql_fetch_array($result)) {
$date = $row['date'];
How do I put a limit of records that can be entered in a table?
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Hi,
I was wondering if there was any way to dissable something from the mouse
right click?
ex: When a user visits my site, I don't want them to be able to use the copy
shortcut on the right mouse click.
How would I do this?
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Anythig visibly wrong with this?
FORM METHOD=post ACTION=userinfolistbycompany2.php
INPUT TYPE=hidden name=uid value=? echo $uid; ?
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Hi,
When a field is declared as an integer, not null and is the primary,
how would I address it's empty set?
ex: if($value == ???)
{
bla
bla
bla
}
My condition wants there to be nothing in $value.
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$sql = SELECT first_name, last_name, address, state, zip_code, country,
company, occupation, telephone, fax, email, entry_name, password, package,
registration_date, valid_until, max_users
FROM $table_name
WHERE uid = \$uid\
;
$result = @mysql_query($sql,$connection)
hi,,,
can someone tell me how to access the value of count? please?
-
$db = @mysql_select_db($db_name, $connection) or die(Couldn't select
database.);
$sql = SELECT count(*)
FROM $table_name,
Hi,
Can anybody tell me what the code to close the browser is?
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Hi, I'm a real newbie at this stuff and I have a little problem... I read
the manual but the answer to my questions were not clear. What I am trying
do do is track down a user when he or she visits my site. I would like to
store some information about them into mySql...Information like,
Hi,
I'm having a problem with my Select statement. This is what i'm doing:
$connection = @mysql_connect(l, c, c) or die(Couldn't connect.);
$db = @mysql_select_db($db_name, $connection) or die(Couldn't select
database.);
$sql = SELECT *
FROM table_1
;
$result =
Hi,
Can someone please tell me what is wrong with this page. The problem is that
my option block is always stuck on the last record in the table. No matter
what option I choose, the information, address, city, state...etc, that is
passed is always the one of the last record in the table...Help!
Hi there, I was wondering if a function such as session_close() or
session_stop() existed. You see, i've been using session_destroy and/or
session_unregister but the problem is that they unregister and/or destroy
ALL my sessions in my server folder. What I am trying to do is just stop the
session
Hi,
I would like to know how to crop this string from this,
$string = \home\folder1\folder2\page1.php
to this
$string = page1.php
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Hello,
Can someone please show me how to use basename() correctly?
This is what I am doing:
$file = basename ($path);
$file = basename ($path,.php3);
This is the error I'm gettig:
Warning: Wrong parameter count for basename() in
/home/virtual/ppcu/home/httpd/html/jeremy/stats4.php on line 43
Help me!
I'm working with sessions and having some difficulty. I have my
session_register(variable) at the top of page 1 and page 2.
I use the session_unregister(variable) at the bottom of page 2, everything
seems to work fine at this point. The problem is,
sometimes the user needs to visit
Hi ,
I'm having problems with my session_unregister(). Maybe what i'm trying to
do can't be done but I would like someones opinion. This is what I am doing
and why i'm doing it.
session_start();
session_unregister(val_1);
session_register(val_1);
I am doing this to clear the contents of val_1
Hi ,
I was wondering if there was a way to retreive a column_name instead of a
value in a query?
For example if my table has the fieldfirstname, lastname, telephone,
movie1, movie2, movie3..
And my first record is JohnDoe 555-
good bad bad
Hi,
I get an error message which I can't figure out.
Its a Parse error: on line 142 which is the last line of the page containing
absolutly no code. The last line of code is simply /HTML..Did
anyone have a similar experience? Can anyone help me out please?
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Hi, I need a little bit of help.
My variable $team in the option block is always set to the last variable
that is readI would like it to contain the option that the user
clicks.Please help me!
My Select works properly
...
$result = @mysql_query($sql,$connection) or die(Couldn't
Sorry to bother you with what probably seems like a useless question but why
is this not skipping a line?
echo $team \n ;
Its in a while loop and the output is:
Bears Giants Jets etc
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For
Hi,
I wondering if it was possible to use limit on part of a query and not all.
this is my query which works the way it should.
$sql = SELECT users.names
FROM users, selection
Where users.name = selection.name and setting = 'on' limit 1
;
What I would
Hi,
Can somebody help me out?
My where clause is completely being ignored.
More specifically the . I tried to use != and that didn't work either.
However, when I substitute it with an = , It fuctions correctly.
Right now, the output is all the users.uid and all the users.username from
the table
Hello,
I was just wondering if there was a simple function like str_con or
something like that to concatenate strings?
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an somebody please fix up my query.
$connection = @mysql_connect(l, c, c) or die(Couldn't connect.);
$db = @mysql_select_db($db_name, $connection) or die(Couldn't select
database.);
$sql = SELECT distinct users.uid , users.username
FROM users LEFT OUTER JOIN picks using(id)
Hi ,
this is my query
SELECT users.uid FROM users, picks WHERE users.uid = picks.user_id;
this works correctly. The results are what they are supposed to be:
However, when I change the = sign to a or !=, The results are completely
incorrect.
--
picks.user_id
Sorry everone but I 'm having a hard time with joins
How do I add this clause:
users.uid = selection.user_uid from table selection
to this query:
$sql = SELECT users.uid, users.username
FROM users LEFT JOIN picks
ON users.uid = picks.user_id
WHERE picks.user_id IS NULL
Thank You.
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-Original Message-
From: Jeremy Morano [mailto:[EMAIL PROTECTED]]
Sent: Thursday, August 30, 2001 12:05 PM
To: [EMAIL PROTECTED]
Subject: JOIN
Sorry everone but I 'm having a hard time with joins
How do I add this clause:
users.uid selection.user_uid from table selection
Hi ,
Is there anyway of hiding the name of the website in the isset Enter
Network Password window?
if (isset( $PHP_AUTH_USER ) isset($PHP_AUTH_PW))
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Hi,
Is there anyway that I can hide my website name in the authenticate window?
if ( ! $auth ) {
header( 'WWW-Authenticate: Basic realm=Private);
header( 'HTTP/1.0 401 Unauthorized' );
echo 'Authorization Required.';
exit;
}
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Hello everyone, I'm having a problem with my option block... I'm trying to
pass the value of uid to the next page. I always get the last uid value in
table user. How can I change this so I get to pass the value of the user's
choice?
$sql = SELECT user.uid, user.first_name, user.last_name
Hi everone...
I'm having a little problem. The code below pops up a password dialog box
where the user types in a username and a password to be able to proceed.
However, if the user does not close the browser and goes back to the link,
which they pops up the diolog box again and they don't have
Hello,
Sorry to bother everyone. I was just wondering if php runs on NT?
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hi
can I use $PHP_AUTH_USER
as a global variable?
I'm having a hard time with it in my other pages.
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HI
I'm using
require(whatever.php)to access my variables...it works.
The problem is my whatever.php page shows up on top of my current page.
Is there a simple clear screen I can use???
I tried include and the same thing happens. What do I do?
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Can anybody tell me how to refresh or clear a screen in php code and if not,
please tell me,, It cannot be done.
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Does anybody know of a common bug where a variable contains what seems to be
a generated random number
instead of the input data that was given?
I'm inputting all sorts of info and only one variable is acting
strange..hmmm
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The employees here and I have noticed that we have a variable that works
when it wants to...
But for days at a time. One day it works fine all day. Another day it fills
up with garbage instead of what its supposed toBut whats particular
about this is that it lasts all day. Good or bad, the
this doesn't work,how should it be done?
insert into test (uid, companyUid)
values(1, select uid from companysTable where company = Micrsoft);
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Whats wrong with this?
$sql = INSERT INTO $table_name
(uid,companyUid, first_name, last_name, address, state, zip_code, country,
company, occupation, telephone, fax, email, user_name, password)
SELECT
\\, \uid from companyTable WHERE company= Itsolutions\,
I would like to know if there is a way to dissable the copy shortcut in my
pages?
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Hi, im trying to delete a record from a table where the value of a field
must be equal to the value of a field of another table.I know
this is wrong but I need to show you what I mean. I think I'm missing a very
important select statement to join them...can
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