[PHP] Installing mcrypt

[Mike At Spy]

I am installing mcrypt on a linux server.  I first installed libmcrypt 2.5.7
and now am working on mcrypt 2.6.4.

When I do a ./configure for mcrypt 2.6.4, it gives me this error:

checking for libmcrypt - version = 2.5.0...
*** 'libmcrypt-config --version' returned 2.5.7, but LIBMCRYPT (2.5.6)
*** was found! If libmcrypt-config was correct, then it is best
*** to remove the old version of LIBMCRYPT. You may also be able to fix the
error
*** by modifying your LD_LIBRARY_PATH enviroment variable, or by editing
*** /etc/ld.so.conf. Make sure you have run ldconfig if that is
*** required on your system.
*** If libmcrypt-config was wrong, set the environment variable
LIBMCRYPT_CONFIG
*** to point to the correct copy of libmcrypt-config, and remove the file
config.cache
*** before re-running configure
configure: error: *** libmcrypt was not found

There has only been one version of libmcrypt (new server), so I'm not sure
why it thinks there is a 2.5.6 version on it.

Where do I find the LD_LIBRARY_PATH enviroment variable to change it?  Or is
there another solution?

Thanks!

-Mike

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[PHP] Changing the php.ini file

[Mike At Spy]

I changed a value for max uploads in my php.ini file (linux box); I
restarted apache, then the whole server, to get the new value to come up
and, generally, take affect.

Neither of those things did it.  Does anyone know what I need to do to get
the ini file re-read by the OS, or system, so that the new value goes into
effect?

Thanks,

-Mike

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RE: [PHP] Changing the php.ini file

[Mike At Spy]

I do have that in my form, it is set to 15 megs.  I set the server (php.ini)
to allow 15 megs.  Still can't get anything past 2 megs to upload. :\

Thanks for help,

-Mike


 -Original Message-
 From: Jay Blanchard [mailto:[EMAIL PROTECTED]
 Sent: Wednesday, November 05, 2003 9:15 AM
 To: Mike At Spy; [EMAIL PROTECTED]
 Subject: RE: [PHP] Changing the php.ini file


 [snip]
 I changed a value for max uploads in my php.ini file (linux box); I
 restarted apache, then the whole server, to get the new value to come up
 and, generally, take affect.

 Neither of those things did it.  Does anyone know what I need to do to
 get
 the ini file re-read by the OS, or system, so that the new value goes
 into
 effect?
 [/snip]

 In your upload dialog form do you have something similar to this

 input type=hidden name=MAX_FILE_SIZE value=3

 if so, it may need changing. If not, it may need adding.



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RE: [PHP] Re: Changing the php.ini file

[Mike At Spy]

I'll go double check to make sure I am hitting the right php.ini, but I
think that is the only one the server reported with a 'whereis'.

I am taking the data and writing it to a file, so the db isn't an issue.

I'll mess with some of other settings and see what happens.

:)

Thanks,

-Mike




 Oh, yes, this is a big one, you must reset the whole state power grid. :)

 Simply restarting Apache should do it. Check if your problem doesn't
 come from somewhere else - how are you checking if the changes took
 effect? Also, are you sure you're editing the proper php.ini and not
 some older install's or a backup or something? Check by setting some
 self-evident setting in php.ini and restarting Apache. Also, if you're
 sending the data to a database, make sure it's not the database who's
 barfing due to its own config settings or limitations.

 HTH

 Bogdan

 Mike At Spy wrote:

  I changed a value for max uploads in my php.ini file (linux box); I
  restarted apache, then the whole server, to get the new value to come up
  and, generally, take affect.
 
  Neither of those things did it.  Does anyone know what I need
 to do to get
  the ini file re-read by the OS, or system, so that the new
 value goes into
  effect?
 
  Thanks,
 
  -Mike

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RE: [PHP] Changing the php.ini file

[Mike At Spy]

I re-checked the files - nothing I change in the php.ini files seems to take
effect.  How do I check apache?

I saw the post_max_size thing and changed that to be equal to the
upload_max_filesize.  I'll make it a little higher.

Outside of that, I have a cobalt raq4 I am working on with this, and the
php.ini file is here:

/usr/local/bin/php.ini

Any other place an ini file might be?  I've certainly learned not to depend
on 'whereis' to list everything in the past.

:)

Thanks fot the help,

-Mike




 -Original Message-
 From: John W. Holmes [mailto:[EMAIL PROTECTED]
 Sent: Wednesday, November 05, 2003 9:25 AM
 To: Marek Kilimajer
 Cc: Mike At Spy; [EMAIL PROTECTED]
 Subject: Re: [PHP] Changing the php.ini file


 Marek Kilimajer wrote:

  post_max_size is another setting that has effect on uploads. It should
  be higher than upload_max_filesize.

 Make sure it isn't Apache doing the limiting, also. Some searching will
 tell you the setting, but Apache has a limit itself on the size of files
 it'll accept.

 --
 ---John Holmes...

 Amazon Wishlist: www.amazon.com/o/registry/3BEXC84AB3A5E/

 php|architect: The Magazine for PHP Professionals  www.phparch.com

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RE: [PHP] Changing the php.ini file

[Mike At Spy]

Bingo.  I didn't even notice that the phpinfo was saying the ini file was in
a different directory than the one I was looking at.

So much for 'whereis' - again. :\

:)

Thanks!

-Mike


 -Original Message-
 From: Ford, Mike [LSS] [mailto:[EMAIL PROTECTED]
 Sent: Wednesday, November 05, 2003 9:50 AM
 To: 'Mike At Spy'
 Cc: [EMAIL PROTECTED]
 Subject: RE: [PHP] Changing the php.ini file


 On 05 November 2003 14:39, Mike At Spy contributed these pearls of wisdom:

  I re-checked the files - nothing I change in the php.ini
  files seems to take
  effect.  How do I check apache?
 
  I saw the post_max_size thing and changed that to be equal to
  the upload_max_filesize.  I'll make it a little higher.
 
  Outside of that, I have a cobalt raq4 I am working on with
  this, and the
  php.ini file is here:
 
  /usr/local/bin/php.ini

 That's all possibly irrelevant.  Have you looked at your
 phpinfo() output to
 see where PHP is *expecting* to find the php.ini file?  And is there a
 php.ini file there?

 Cheers!

 Mike

 --
 Mike Ford,  Electronic Information Services Adviser,
 Learning Support Services, Learning  Information Services,
 JG125, James Graham Building, Leeds Metropolitan University,
 Beckett Park, LEEDS,  LS6 3QS,  United Kingdom
 Email: [EMAIL PROTECTED]
 Tel: +44 113 283 2600 extn 4730  Fax:  +44 113 283 3211


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[PHP] fwrite, fopen, or fread limit?

[Mike At Spy]

Does anyone know if the commands for fwrite, fopen, or fread have memory
limits in dealing with large files?

I created a system for uploading files to a server.  Small files work fine.
Larger ones (around 7 megs) do not work at all.

Thanks,

-Mike

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RE: [PHP] fwrite, fopen, or fread limit?

[Mike At Spy]

Yes, that was it.

Thanks! :)

-Mike


 -Original Message-
 From: Roger Spears [mailto:[EMAIL PROTECTED]
 Sent: Tuesday, November 04, 2003 12:45 PM
 To: Mike At Spy
 Subject: Re: [PHP] fwrite, fopen, or fread limit?
 
 
 check the php.ini file, there may be a file upload limit placed there.  
 I ran into a similar problem awhile backI think it's called 
 max_file_upload or something like that...
 
 Thanks,
 Roger
 
 Mike At Spy wrote:
 
 Does anyone know if the commands for fwrite, fopen, or fread have memory
 limits in dealing with large files?
 
 I created a system for uploading files to a server.  Small files 
 work fine.
 Larger ones (around 7 megs) do not work at all.
 
 Thanks,
 
 -Mike
 
   
 
 
 
 

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[PHP] value field filled by mysql output

[Mike At Spy]

I am creating a form for editing records output from a mysql db (edit as an
html form).  I've done this many times, but have never run into this issue.

I have code like this for the query:

$edit_list = mysql_query(SELECT general_inventory.quantity FROM
products_to_categories, general_inventory WHERE
products_to_categories.categories_id = $cat AND
products_to_categories.products_id = general_inventory.product_id ORDER BY
general_inventory.name);

And like this for getting the output, inside a while loop:

$edit_details = mysql_fetch_array ($edit_list);
$qty = $edit_details['quantity'];
td align='center'input type=text name='qty$ed' value='$qty'
size='3'/td

Now, I get more than one column in a row, but I abbreviated it for here and
for testing.  Every column comes out and fills in the form properly except
this one.

The issue I am having is that the value of the input text box is being
listed as '1', even if the database shows either a value of nothing
(meaning, blank) or a value of zero.

Anyone have any idea why this might be?

Thanks,

-Mike

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RE: [PHP] jpeg libraries.

[Mike At Spy]

 * Thus wrote Mike At Spy ([EMAIL PROTECTED]):
 
  It did install some jpeg stuff under /usr/local/bin, but I don't see
  anything added to /usr/local/lib.
 
  After that, I re-compiled php with:
 
  --with-jpeg
 
  But nothing changed.
 
  I re-compiled again with:
 
  --with-jpeg=/usr/local/bin

 try --with-jpeg=/usr/local


Thanks - tried that, but it didn't work.  i.e.  jpeg is still not enabled in
gd. :\

Does anyone know how to get jpeg enabled in gd?  I'm using php 4.3.3.

Thanks,

-Mike

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RE: [PHP] jpeg libraries.

[Mike At Spy]

Actually, I am using php 4.3.3 - which has gd 'bundled' in it. :)

I couldn't actually re-compile it then, could I; meaning, is there some way
of doing that separatly from php from the 'bundle'?  :)

Thanks,

-Mike



 -Original Message-
 From: Tom Rogers [mailto:[EMAIL PROTECTED]
 Sent: Thursday, August 28, 2003 7:27 PM
 To: Mike At Spy
 Cc: [EMAIL PROTECTED]
 Subject: Re: [PHP] jpeg libraries.


 Hi,

 Friday, August 29, 2003, 6:39:16 AM, you wrote:

 MAS I got the jpeg libraries from:

 MAS http://freshmeat.net/projects/libjpeg/?topic_id=105%2C809

 MAS And installed them; even did a make test to make sure everything was
 MAS correct.

 MAS It did install some jpeg stuff under /usr/local/bin, but I don't see
 MAS anything added to /usr/local/lib.

 MAS After that, I re-compiled php with:

 MAS --with-jpeg

 MAS But nothing changed.

 MAS I re-compiled again with:

 MAS --with-jpeg=/usr/local/bin

 MAS And nothing changed.

 MAS Anyone have any ideas as to what is going on?  Or a
 suggestion as to what to
 MAS look for?

 MAS Thanks,

 MAS -Mike


 You may also need to recompile gd

 --
 regards,
 Tom




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[PHP] imagejpeg function output

[Mike At Spy]

Just to make sure no one is lead astray - I still have an issue getting jpeg
enabled on a server with gd and php.  I am asking this question 'cause I am
doing some work on a different server where jpeg is enabled.

Anyway, I have this sort of setup:

$src_img = imagecreatefromjpeg($rand_image);
 $dst_img = imagecreate($destWidth,$destHeight);
 imagecopyresized($dst_img, $src_img, 0, 0, 0, 0, $destWidth,$destHeight,
$srcWidth, $srcHeight);
 imageJPEG($dst_img, $dest_file, 100);
 imagedestroy($src_img);

print $dest_file;

Now, from this I get a bunch of binary code like:

…•ª¸âq¼Ö”a µ*'ì ªNp䊤¡ r«V
ΦܿGà¾Çq¿å¼=‚©4±3u18º‹÷xj4ê%R£¥N¥J•j6ý•8FMN½Z~Öt©}bµdøŸûvjZˆ`ð÷Á¿Þ.ø
‘eg3%ïĝCágÃKYûNÕ

Which I sort of expected.

BUT; how do I show the picture ($dest_file) in the browser from here?

Thanks,

-Mike

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RE: [PHP] jpeg libraries.

[Mike At Spy]

 
  Does anyone know how to get jpeg enabled in gd?

 Yes.

  I'm using php 4.3.3.

 Unless dramatic changes were made in 4.3.3 then the procedure
 should be the
 same as the previous versions. Namely:

 --with-gd --with-jpeg-dir=/directory/where/jpeg/libs/are/installed

 manual  Image functions

Ok, now I did instal what I believe were the jpeg libraries, or at least
were lead to believe they were.  They came from this binary:

jpegsrc.v6b.tar.gz

Which I got from the jpeg libraries web site.  This installed:

[root jpeg-6b]# make -n install
/usr/bin/install -c cjpeg /usr/local/bin/cjpeg
/usr/bin/install -c djpeg /usr/local/bin/djpeg
/usr/bin/install -c jpegtran /usr/local/bin/jpegtran
/usr/bin/install -c rdjpgcom /usr/local/bin/rdjpgcom
/usr/bin/install -c wrjpgcom /usr/local/bin/wrjpgcom
/usr/bin/install -c -m 644 ./cjpeg.1 /usr/local/man/man1/cjpeg.1
/usr/bin/install -c -m 644 ./djpeg.1 /usr/local/man/man1/djpeg.1
/usr/bin/install -c -m 644 ./jpegtran.1 /usr/local/man/man1/jpegtran.1
/usr/bin/install -c -m 644 ./rdjpgcom.1 /usr/local/man/man1/rdjpgcom.1
/usr/bin/install -c -m 644 ./wrjpgcom.1 /usr/local/man/man1/wrjpgcom.1

None of which actually look like libraries to me (though just because
nothing was sent to the lib directory..).  :)

I tried comiling php with three different 'switches'.  Each time I wiped the
directory and started from a freshly unpacked php tarball.  I tried;

--with-jpeg
--with-jpeg=/usr/local/bin
--with-jpeg=/usr/local

None of which worked.

Any suggestions?? :)

Thanks!

-Mike

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RE: [PHP] imagejpeg function output

[Mike At Spy]

Hyeah, but since this is with a page, I keep getting the 'error,
headers already sent' thing.  How do I get past that?

:)

Thanks for your help!

-Mike


 -Original Message-
 From: Marek Kilimajer [mailto:[EMAIL PROTECTED]
 Sent: Friday, August 29, 2003 12:51 PM
 To: Mike At Spy
 Cc: [EMAIL PROTECTED]
 Subject: Re: [PHP] imagejpeg function output


 You need to send the right header, in this case
 header('Content-type: image/jpg');

 Mike At Spy wrote:
  Just to make sure no one is lead astray - I still have an issue
 getting jpeg
  enabled on a server with gd and php.  I am asking this question
 'cause I am
  doing some work on a different server where jpeg is enabled.
 
  Anyway, I have this sort of setup:
 
  $src_img = imagecreatefromjpeg($rand_image);
   $dst_img = imagecreate($destWidth,$destHeight);
   imagecopyresized($dst_img, $src_img, 0, 0, 0, 0,
 $destWidth,$destHeight,
  $srcWidth, $srcHeight);
   imageJPEG($dst_img, $dest_file, 100);
   imagedestroy($src_img);
 
  print $dest_file;
 
  Now, from this I get a bunch of binary code like:
 
  qa *' Np rV
 
 Gq=43u18xj4%RNJj68FMNZ~t}bdvjZ
 `?.
  eg3%??CgKYN
 
  Which I sort of expected.
 
  BUT; how do I show the picture ($dest_file) in the browser from here?
 
  Thanks,
 
  -Mike
 

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RE: [PHP] jpeg libraries.

[Mike At Spy]

Jason et al;

Thanks for all of your help up - I really appreciate it.

However, I still have the issue that while the jpeg libraries were
installed, the weren't. :\

This is what was installed through the only binary for jpeg libaries I can
find on the net off hand:

jpegsrc.v6b.tar.gz

yields:

[root jpeg-6b]# make -n install
/usr/bin/install -c cjpeg /usr/local/bin/cjpeg
/usr/bin/install -c djpeg /usr/local/bin/djpeg
/usr/bin/install -c jpegtran /usr/local/bin/jpegtran
/usr/bin/install -c rdjpgcom /usr/local/bin/rdjpgcom
/usr/bin/install -c wrjpgcom /usr/local/bin/wrjpgcom
/usr/bin/install -c -m 644 ./cjpeg.1 /usr/local/man/man1/cjpeg.1
/usr/bin/install -c -m 644 ./djpeg.1 /usr/local/man/man1/djpeg.1
/usr/bin/install -c -m 644 ./jpegtran.1 /usr/local/man/man1/jpegtran.1
/usr/bin/install -c -m 644 ./rdjpgcom.1 /usr/local/man/man1/rdjpgcom.1
/usr/bin/install -c -m 644 ./wrjpgcom.1 /usr/local/man/man1/wrjpgcom.1

None of which actually look like libraries to me (though just because
nothing was sent to the lib directory..).  :)

Does anyone know anything about how I can get the jpeg libraries installed?
Or where I can even get them - php keeps failing upon ./configure with:

configure: error: libjpeg.(a|so) not found

?

Thanks!

-Mike

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[PHP] GD PHP

[Mike At Spy]

Is there anything special I have to do to enable GD when using PHP 4.3.2?

I'm getting an error of:

Fatal error: Call to undefined function: imagecreatefromjpeg() in
/home/sites/site37/web/photos/functions.php on line 594

When I use the imagecreatefromjpeg() function.  Is it not usable with gd?
Should I be using imagecreatefromgd()?

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RE: [PHP] GD PHP

[Mike At Spy]

Cool - thanks. :)

-Mike


 -Original Message-
 From: Javier Tacon [mailto:[EMAIL PROTECTED]
 Sent: Thursday, August 28, 2003 11:33 AM
 To: Mike At Spy; [EMAIL PROTECTED]
 Subject: RE: [PHP] GD  PHP
 
 
 
 You need to compile PHP with the option --with-gd in the configure step.
 
 The function is imagecreatefromjpeg()
 
 
 -Mensaje original-
 De: Mike At Spy [mailto:[EMAIL PROTECTED]
 Enviado el: jueves, 28 de agosto de 2003 17:32
 Para: [EMAIL PROTECTED]
 Asunto: [PHP] GD  PHP
 
 
 
 Is there anything special I have to do to enable GD when using PHP 4.3.2?
 
 I'm getting an error of:
 
 Fatal error: Call to undefined function: imagecreatefromjpeg() in
 /home/sites/site37/web/photos/functions.php on line 594
 
 When I use the imagecreatefromjpeg() function.  Is it not usable with gd?
 Should I be using imagecreatefromgd()?
 
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RE: [PHP] GD PHP

[Mike At Spy]

I get an error about png libraries not found, though my configure line only
adds --with-gd to it from my previous configure (pretty recent).  Do I need
png and/or some sort of jpeg libraries installed first?

I don't mention png in my configure line:

./configure --prefix=/usr --with-apxs=/usr/sbin/apxs --with-gettext=/usr --e
nable-safe-mode --with-config-file-path=/etc/httpd --with-exec-dir=/usr/bin 
--with-zlib --enable-magic-quotes --with-regex=system --with-ttf --with-dba 
--with-gdbm --enable-mbstring --enable-mbstr-enc-trans --enable-track-vars -
-enable-wddx=shared --enable-mm=shared --enable-xml --enable-ftp --disable-d
ebug --with-libdir=/usr/lib --with-db3 --with-interbase=shared --with-pgsql=
shared --with-ldap --with-pdflib=shared --with-mcrypt --with-gd

Thanks,

-Mike



 -Original Message-
 From: Javier Tacon [mailto:[EMAIL PROTECTED]
 Sent: Thursday, August 28, 2003 11:33 AM
 To: Mike At Spy; [EMAIL PROTECTED]
 Subject: RE: [PHP] GD  PHP



 You need to compile PHP with the option --with-gd in the configure step.

 The function is imagecreatefromjpeg()


 -Mensaje original-
 De: Mike At Spy [mailto:[EMAIL PROTECTED]
 Enviado el: jueves, 28 de agosto de 2003 17:32
 Para: [EMAIL PROTECTED]
 Asunto: [PHP] GD  PHP



 Is there anything special I have to do to enable GD when using PHP 4.3.2?

 I'm getting an error of:

 Fatal error: Call to undefined function: imagecreatefromjpeg() in
 /home/sites/site37/web/photos/functions.php on line 594

 When I use the imagecreatefromjpeg() function.  Is it not usable with gd?
 Should I be using imagecreatefromgd()?

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 To unsubscribe, visit: http://www.php.net/unsub.php

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[PHP] jpeg libraries.

[Mike At Spy]

I got the jpeg libraries from:

http://freshmeat.net/projects/libjpeg/?topic_id=105%2C809

And installed them; even did a make test to make sure everything was
correct.

It did install some jpeg stuff under /usr/local/bin, but I don't see
anything added to /usr/local/lib.

After that, I re-compiled php with:

--with-jpeg

But nothing changed.

I re-compiled again with:

--with-jpeg=/usr/local/bin

And nothing changed.

Anyone have any ideas as to what is going on?  Or a suggestion as to what to
look for?

Thanks,

-Mike

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[PHP] Image Magick

[Mike At Spy]

Anyone here familiar with the installation of Image Magick and what files it
installs on your machine?

I had an admin put it on, and then took it off - but took it off by removing
what she thought were all of the files related to it.  I just found some
files I think that are.  They are located in the usr/local/bin directory and
are called:

animate
composite
convert
display
identify
mogrify
montage

The date/time of the files being put there seems to correspond with when the
admin put the program on, and names of the files seem to imply it to me.

And I just wanted to make sure I'm not going to screw up something else by
removing them. :)

Thanks!

-Mike

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[PHP] Bizarre SQl, if issue....

[Mike At Spy]

Hey, I've got a weird issue.  I have some code, an MySQL statement, that
returns an empty set, like this:

$person = mysql_query(Some Statement Here);

So, then I have an if/else statement:

if (!$person || $person == 0 || $person == '' || $person == '0') { $result =
1; }
else { $result = 4; }

If the SQL statement returns an empty set, shouldn't $result be equal to 1?
Instead, I'm getting $result = 4.

Hence all of the 'OR' conditions.  I would have have thought !$person would
be enough.

Thanks for any input!  :)

-Mike




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RE: [PHP] Bizarre SQl, if issue....

[Mike At Spy]

Here's the SQL - I tested it via command line and it comes back empty set.

SELECT ID FROM tblItems WHERE number = $place

Does that help?

-Mike



 -Original Message-
 From: Jay Blanchard [mailto:[EMAIL PROTECTED]
 Sent: Tuesday, July 29, 2003 1:31 PM
 To: Mike At Spy; [EMAIL PROTECTED]
 Subject: RE: [PHP] Bizarre SQl, if issue
 
 
 [snip]
 $person = mysql_query(Some Statement Here);
 
 if (!$person || $person == 0 || $person == '' || $person == '0') {
 $result =
 1; }
 else { $result = 4; }
 
 If the SQL statement returns an empty set, shouldn't $result be equal to
 1?
 Instead, I'm getting $result = 4.
 [/snip]
 
 Actually I think we need to see the query == Some Statement Here.
 $person in this case is either TRUE or FALSE
 
 


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RE: [PHP] Bizarre SQl, if issue....

[Mike At Spy]

I know.  I first tested for !$person but got the TRUE result when I should
have received FALSE (empty set).

Why would that be?

I added '0' and such just to see if I wasn't thinking straight. :\

-Mike




 -Original Message-
 From: Jay Blanchard [mailto:[EMAIL PROTECTED]
 Sent: Tuesday, July 29, 2003 1:44 PM
 To: Jay Blanchard; Mike At Spy; [EMAIL PROTECTED]
 Subject: RE: [PHP] Bizarre SQl, if issue


 [snip]

 ...lots of stuff...

 [/snip]

 What I forgot to say is that basically you were testing for query
 execution, not the number of rows returned from the database. If you
 want to test the number of rows or some other result from the query you
 have to go further.

 HTH!





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RE: [PHP] Bizarre SQl, if issue....

[Mike At Spy]

Off hand, I would agree.  And that is what I would expect.

However, the *exact* same setup on a different server gives me a result of
'FALSE' properly.  The other server has php 4.3.3 on it - the one giving the
improper response has php 4.1.2.

Could this be the issue?

-Mike



 -Original Message-
 From: Ford, Mike [LSS] [mailto:[EMAIL PROTECTED]
 Sent: Tuesday, July 29, 2003 1:47 PM
 To: 'Mike At Spy'; [EMAIL PROTECTED]
 Subject: RE: [PHP] Bizarre SQl, if issue


  -Original Message-
  From: Mike At Spy [mailto:[EMAIL PROTECTED]
  Sent: 29 July 2003 18:37

  
   $person = mysql_query(Some Statement Here);

 Please go back and read the manual page for mysql_query again
 (http://www.php.net/mysql_query).

 The above returns FALSE if the query is invalid, or a resource_id
 you can use to fetch the result (or information about it).  So
 most likely $person is now a MySQL resource id that doesn't match
 any of the conditions in your if statement, and also (more
 importantly) doesn't tell you whether you have an empty set or
 not.  I'd suggest mysql_num_rows() for that.

 Cheers!

 Mike

 -
 Mike Ford,  Electronic Information Services Adviser,
 Learning Support Services, Learning  Information Services,
 JG125, James Graham Building, Leeds Metropolitan University,
 Beckett Park, LEEDS,  LS6 3QS,  United Kingdom
 Email: [EMAIL PROTECTED]
 Tel: +44 113 283 2600 extn 4730  Fax:  +44 113 283 3211





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RE: [PHP] Bizarre SQl, if issue....

[Mike At Spy]

 [snip]
 Off hand, I would agree.  And that is what I would expect.

 However, the *exact* same setup on a different server gives me a result
 of
 'FALSE' properly.  The other server has php 4.3.3 on it - the one giving
 the
 improper response has php 4.1.2.




$which_person = mysql_query(SELECT ID FROM tblItems WHERE number =
$place);

$vthere = mysql_num_rows($which_person);

if ($vthere == '0') { True } else { False }


What should this return? True or False?

-Mike




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RE: [PHP] Bizarre SQl, if issue....

[Mike At Spy]

I did the var_dump and got:

bool(false)

While $vthere (from my previous post) returns 0 (zero) still.  :\

But proceeds as if 0 were a false statement when asked if $vthere equals
zero.  :\

-Mike



 -Original Message-
 From: Ford, Mike [LSS] [mailto:[EMAIL PROTECTED]
 Sent: Tuesday, July 29, 2003 2:07 PM
 To: 'Mike At Spy'; Ford, Mike [LSS]; [EMAIL PROTECTED]
 Subject: RE: [PHP] Bizarre SQl, if issue


  -Original Message-
  From: Mike At Spy [mailto:[EMAIL PROTECTED]
  Sent: 29 July 2003 19:01
 
  Off hand, I would agree.  And that is what I would expect.
 
  However, the *exact* same setup on a different server gives
  me a result of
  'FALSE' properly.  The other server has php 4.3.3 on it - the
  one giving the
  improper response has php 4.1.2.

 Hang on -- it's not clear to me which server is giving which response.

 Just to be clear, the proper response is to deliver a resource id
 if the query is valid, or FALSE if not.  Could it be that one
 server is consistently giving you a resource ID of 0, and the
 other isn't?  (I'm not even sure if a resource ID of zero is
 equivalent to a real zero, or what the result of doing an if
 ($resource_id) on it would be, but this might be a straw to
 clutch at!).  To see *exactly* what's being returned into $person
 from your mysql_query(), try doing var_dump($person).

 Cheers!

 Mike

 -
 Mike Ford,  Electronic Information Services Adviser,
 Learning Support Services, Learning  Information Services,
 JG125, James Graham Building, Leeds Metropolitan University,
 Beckett Park, LEEDS,  LS6 3QS,  United Kingdom
 Email: [EMAIL PROTECTED]
 Tel: +44 113 283 2600 extn 4730  Fax:  +44 113 283 3211

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RE: [PHP] Bizarre SQl, if issue....

[Mike At Spy]

Nothin' wrong with the SQL statement - it executes properly when I enter
values that actually pull something from a table.  When I enter values that
are not present in the table, I go on to have the other issue of it looking
like it is false, though it is not.  :\

-Mike



 -Original Message-
 From: Jay Blanchard [mailto:[EMAIL PROTECTED]
 Sent: Tuesday, July 29, 2003 2:24 PM
 To: Mike At Spy; Ford, Mike [LSS]; [EMAIL PROTECTED]
 Subject: RE: [PHP] Bizarre SQl, if issue


 [snip]
 I did the var_dump and got:

 bool(false)

 While $vthere (from my previous post) returns 0 (zero) still.  :\

 But proceeds as if 0 were a false statement when asked if $vthere equals
 zero.  :\

 -Mike
 [/snip]

 Is the query executing properly? Try this ...

 $sql = SELECT ID from tblItems WHERE number = ' . $place . ' );
 if(!($person = mysql_query($sql, $connect_variable))){
print(mysql_error() . \n);
exit();
 }

 It is a verbose test





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RE: [PHP] Bizarre SQl, if issue....

[Mike At Spy]

 [snip]
 Nothin' wrong with the SQL statement - it executes properly when I enter
 values that actually pull something from a table.  When I enter values
 that
 are not present in the table, I go on to have the other issue of it
 looking
 like it is false, though it is not.  :\
 [/snip]

 But you are testing the query from the command line, I want to test it
 from within the confines of the PHP script. Humor me?

No, I meant it works fine both at command line and in the script with values
assigned to it.

But I will humor you anyway.  The SQL thing you asked me to do brings back
an empty set (no result).  :)

-Mike





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RE: [PHP] Bizarre SQl, if issue....

[Mike At Spy]

 -Original Message-
 From: Jay Blanchard [mailto:[EMAIL PROTECTED]
 Sent: Tuesday, July 29, 2003 2:41 PM
 To: Mike At Spy; [EMAIL PROTECTED]
 Subject: RE: [PHP] Bizarre SQl, if issue


 [snip]
  I still want to know what you need to do, test for query execution or
  value? It is pretty cut and dried after that.

 Value.  If there is nothing found in the table that matches, do one
 thing.
 If there is, do another.  :)
 [/snip]

 Then you must test for something returned, not whether or not the query
 executed. Use mysql_num_rows($person);

I did!  Look at this again:

$which_person = mysql_query(SELECT ID FROM tblItems WHERE number =
$place);

$vthere = mysql_num_rows($which_person);

if ($vthere == '0') { True } else { False }

Yet it still returns as if this is FALSE (i.e. it executes the else {}. :\

:\

-Mike




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RE: [PHP] Bizarre SQl, if issue....

[Mike At Spy]

 -Original Message-
 From: Jay Blanchard [mailto:[EMAIL PROTECTED]
 Sent: Tuesday, July 29, 2003 2:48 PM
 To: Mike At Spy; [EMAIL PROTECTED]
 Subject: RE: [PHP] Bizarre SQl, if issue
 
 
 [snip]
 I did!  Look at this again:
 
 $which_person = mysql_query(SELECT ID FROM tblItems WHERE number =
 $place);
 
   $vthere = mysql_num_rows($which_person);
 
   if ($vthere == '0') { True } else { False }
 
 Yet it still returns as if this is FALSE (i.e. it executes the else {}.
 :\
 [/snip]
 
 try 
 
 if ($vthere == 0) { True } else { False }


Same result (actually, that was the first statement I tried). :\

-Mike



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RE: [PHP] Bizarre SQl, if issue....

[Mike At Spy]

 This is a reply to an e-mail that you wrote on Tue, 29 Jul 2003 at
 19:46, lines prefixed by '' were originally written by you.
  I did!  Look at this again:
  $which_person = mysql_query(SELECT ID FROM tblItems WHERE
 number =
  $place);
  $vthere = mysql_num_rows($which_person);
  if ($vthere == '0') { True } else { False }
  Yet it still returns as if this is FALSE (i.e. it executes the
 else
  {}. :

 As long as your query is returning 0 rows that code should work ok,
 but it is incorrect for correctness,
 if ($vthere == '0')
 should be
 if ($vthere == 0)
 As $vthere will contain an integer, not a string, but as you are
 using the == comparison operator instead of === PHP should
 convert them both to the same type before comparing.

 Can we see the snippet of the actual code that you are using?



Actually, what you see is *exactly* the code being used. Nothing has changed
about it.  And whether the variable is regarded as a string or a number, it
gives me the same stupid issue.  Not recognizing it as a True statement. :\

Is there any way possible that this could be the client's server?  I had to
beg to get 'em to recompile to 4.1.2 from 4.0.3.  There are using a version
of Linux I don't recognize (it isn't redhat or mandrake), but it looks like
their kernel is up to date.

On my redhat server (with php 4.3.3), the same code responds properly (i.e.
that $vthere ==0 is true).

:\

-Mike



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RE: [PHP] Bizarre SQl, if issue....

[Mike At Spy]

 [snip]
 if ($vthere == '0') { True } else { False }

  

  if ($vthere == 0) { True } else { False }


 Same result (actually, that was the first statement I tried). :\
 [/snip]

 Then the query is failing.

But the query returns no errors - both on my code I use to test errors and
the one you sent to me!  :\

And when I plug values into the query at command line - values that would
return an empty set, it executes and returns an empty set.

:)

Thanks,

-Mike



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RE: [PHP] Bizarre SQl, if issue....

[Mike At Spy]

Returns 0 (zero).

-Mike


 -Original Message-
 From: Jay Blanchard [mailto:[EMAIL PROTECTED]
 Sent: Tuesday, July 29, 2003 3:05 PM
 To: Mike At Spy; [EMAIL PROTECTED]
 Subject: RE: [PHP] Bizarre SQl, if issue
 
 
 [snip]
 And when I plug values into the query at command line - values that
 would
 return an empty set, it executes and returns an empty set.
 [/snip]
 
 If the query is returning an empty set the value of
 mysql_num_rows($person) == 0
 
 so
 
 $person = mysql_query(The Query);
 $thecount = mysql_num_rows($person);
 echo $thecount \n;
 
 And tell us what $thecount is...
 
 


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RE: [PHP] Bizarre SQl, if issue....

[Mike At Spy]

 [snip]
  $person = mysql_query(The Query);
  $thecount = mysql_num_rows($person);
  echo $thecount \n;
 
  And tell us what $thecount is...

 Returns 0 (zero).
 [/snip]

 Then
 if($thecount == 0){
$whatever = 1;
 } else {
$whatever = 4;
 }

 $whatever should be 1

But that is my point - and I think we are going in circles now.  It just
doesn't do that.  It returns 4 (as per your example). :\

-Mike




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RE: [PHP] Compiling PHP

[Mike At Spy]

I went over what you commented on - thanks for the input.  Most everything
did indeed stay.  This is what I get when going a make install now:

Installing PHP CLI binary:/usr/local/bin/
Installing PHP CLI man page:  /usr/local/man/man1/
Installing PHP SAPI module
[activating module `php4' in /etc/httpd/conf/httpd.conf]
cp libs/libphp4.so /usr/lib/apache/libphp4.so
cp: cannot stat `libs/libphp4.so': No such file or directory
apxs:Break: Command failed with rc=1
make: *** [install-sapi] Error 1


BTW, this all stems from another admin on the server wanting to upgrade
apache to 1.3.27 - when that was done, my php written in my scripts started
failing.  It doesn't even work now.  Whenever I have a script that passes a
value (example: a link going to somewhere.php?w=4), it does not process at
all (nothing happens - so w doesn't do anything).  Everything worked fine
until this started...

My config file I am using is now:

./configure --with-apxs=/usr/sbin/apxs --with-gd --with-mysql --with-png --w
ith-pear --with-config-file-path=/usr/local/apache  --with-zlib --with-jpeg 
--with-ttf --with-regex=php --with-db --with-gdbm --enable-mbstring --enable
-mm=shared --enable-xml --with-db3 --with-pgsql=shared --with-ldap

Thanks for any help,

-Mike





 -Original Message-
 From: Ralph Guzman [mailto:[EMAIL PROTECTED]
 Sent: Tuesday, July 08, 2003 5:51 PM
 To: 'Mike At Spy'; [EMAIL PROTECTED]
 Subject: RE: [PHP] Compiling PHP


 The error you are providing here is because you do not have the required
 libraries installed. Some of these modules require that the programs or
 libraries be installed, php does not install them for you.

 This is an extensive config. Are you sure you need all these. I see that
 you are trying to enable pgsql, mySQL, interbase. Will you be running
 all these databases on you server?

 I've looked through your config, and below are some notes I made.

 Hope this helps.


 ..


  --prefix=/usr
 is there a reason why you must install php to /usr. The default
 directory is /usr/local/lib?

  --with-apxs=/usr/sbin/apxs
 is your apache compiled with mod_so for apxs support?
 http://httpd.apache.org/docs/programs/apxs.html

  --enable-safe-mode
 this may restrict some php functions

  --with-exec-dir=/usr/bin
 this will allow executables in your /usr/bin directory. This might be a
 security risk. Why not let it default to /usr/local/php/bin?

  --with-zlib
 I think this should be --with-zlib-dir=DIR
 http://www.php.net/zlib

  --with-regex=system
 PHP supports regular expressions by default. Why don't you use
 --with-regex=php
 http://www.php.net/regex

  --with-ttf
 do you have the FreeType libraries installed?
 http://www.php.net/image

  --with-db
 does your server support this type of database?
 http://www.php.net/manual/en/ref.dbm.php

  --with-gdbm
 does your server support this type of database?

  --with-mbstring
 do you need multi-byte character support?
 http://www.php.net/mbstring

  --with-mbstr-enc-trans
 not sure what this does.

  --with-libdir
 not sure what this does.

  --with-interbase=shared
 are you running Interbase on your server?
 http://www.php.net/manual/en/ref.ibase.php

  --with-pgsql=shared
 are you running PostgreSQL on your server?
 http://www.php.net/manual/en/ref.pgsql.php

  --with-ldap
 do you have LDAP libraries installed?
 http://www.php.net/manual/en/ref.ldap.php

  --with-imap-ssl
 I think this should be --with-imap-ssl=[DIR]
  http://www.php.net/imap

  --with-mysql
 are you running MySQL on your server?
 http://www.php.net/manual/en/ref.mysql.php

 --with-gd
 Do you have the GD library installed?
 http://www.php.net/manual/en/ref.image.php

 --with-png
 Do you have PNG library installed?
 http://www.php.net/manual/en/ref.image.php



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[PHP] Going Back in PHP

[Mike At Spy]

I am trying to help one of our admins with a php config/setup issue on one
of our servers; the admin re-compiled php, but did not include all of the
correct settings.  Outside of having the previous make and config files, is
there any other files on the server that may hold the old settings so that
we can gather them and return to the previous way we had php set up?

Thanks,

-Mike



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[PHP] Compiling PHP

[Mike At Spy]

I am doing a new compile of PHP (4.3.3) - anyone know what this error is?

configure: error: libgds or libib_util not found!

Here is my configuration:

./configure --prefix=/usr --with-apxs=/usr/sbin/apxs --enable-safe-mode --wi
th-config-file-path=/etc/httpd --with-exec-dir=/usr/bin --with-zlib --enable
-magic-quotes --with-regex=system --with-ttf --with-db --with-gdbm --with-mb
string --with-mbstr-enc-trans --enable-track-vars --enable-wddx=shared --ena
ble-mm=shared --enable-xml --disable-debug --with-libdir  --with-interbase=s
hared --with-pgsql=shared --with-ldap --with-imap-ssl --with-mysql --disable
-url-fopen-wrapper --with-gd --with-png --with-pear

Thanks for any help!

-Mike



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RE: [PHP] Compiling PHP

[Mike At Spy]

Actually, I think I found the issue.  Now I am getting:

configure: error: build test failed.

And I changed my config to be:

./configure --prefix=/usr --with-apxs=/usr/sbin/apxs --with-gd --with-mysql 
--with-png --with-pear --with-gettext=/usr --enable-safe-mode --with-config-
file-path=/etc/httpd --with-exec-dir=/usr/bin --with-zlib --enable-magic-quo
tes --with-regex=system --with-ttf --with-db --with-gdbm --enable-mbstring -
-enable-mbstr-enc-trans --enable-track-vars --enable-wddx=shared --enable-mm
=shared --enable-xml --enable-ftp --disable-debug --with-libdir=/usr/local/l
ib --with-db3 --with-interbase=shared --with-pgsql=shared --with-ldap --with
-imap --with-pdflib=shared --with-kerberos


Anyone have any ideas?  I'm on linux redhat 7.3.

Thanks,

-Mike






 -Original Message-
 From: Mike At Spy [mailto:[EMAIL PROTECTED]
 Sent: Tuesday, July 08, 2003 3:47 PM
 To: [EMAIL PROTECTED]
 Subject: [PHP] Compiling PHP



 I am doing a new compile of PHP (4.3.3) - anyone know what this error is?

 configure: error: libgds or libib_util not found!

 Here is my configuration:

 ./configure --prefix=/usr --with-apxs=/usr/sbin/apxs
 --enable-safe-mode --wi
 th-config-file-path=/etc/httpd --with-exec-dir=/usr/bin
 --with-zlib --enable
 -magic-quotes --with-regex=system --with-ttf --with-db
 --with-gdbm --with-mb
 string --with-mbstr-enc-trans --enable-track-vars
 --enable-wddx=shared --ena
 ble-mm=shared --enable-xml --disable-debug --with-libdir
 --with-interbase=s
 hared --with-pgsql=shared --with-ldap --with-imap-ssl
 --with-mysql --disable
 -url-fopen-wrapper --with-gd --with-png --with-pear

 Thanks for any help!

 -Mike



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[PHP] mail() function

[Mike At Spy]

Is anyone familiar with the mail function and how it works on the server?  I
can't get it to work on a client's server, and this error shows up in the
error log:

PHP Warning:  U1À‰å]Éö¼': Unable to initialize module
Module compiled with debug=144, thread-safety=135 module API=1119810252
PHP compiled with debug=0, thread-safety=0 module API=20010901
These options need to match
 in Unknown on line 0
PHP Warning:  U1À‰å]Éö¼': Unable to initialize module
Module compiled with debug=144, thread-safety=167 module API=1120015052
PHP compiled with debug=0, thread-safety=0 module API=20010901
These options need to match
 in Unknown on line 0

If anyone has any suggestions as to what to look for, I would appreciate it.
I already tried 'pointing' php.ini directly to sendmail (which is in a
traditional spot: /usr/sbin/sendmail).

Thanks,

-Mike



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RE: [PHP] mail() function

[Mike At Spy]

I can't tell what the version is, but I can tell you that the kernel is:

2.4.7-10

Maybe it has something to do with what identity php or sendmail is running under?

Thanks,

-Mike



 -Original Message-
 From: Adam Voigt [mailto:[EMAIL PROTECTED]
 Sent: Monday, July 07, 2003 1:01 PM
 To: Mike At Spy
 Cc: [EMAIL PROTECTED]
 Subject: Re: [PHP] mail() function
 
 
 Yeah, umm, thats a weird error message.
 What server platform / OS?
 
 
 On Mon, 2003-07-07 at 12:58, Mike At Spy wrote:
  Is anyone familiar with the mail function and how it works on 
 the server?  I
  can't get it to work on a client's server, and this error shows 
 up in the
  error log:
  
  PHP Warning:  U1]': Unable to initialize module
  Module compiled with debug=144, thread-safety=135 module API=1119810252
  PHP compiled with debug=0, thread-safety=0 module API=20010901
  These options need to match
   in Unknown on line 0
  PHP Warning:  U1]': Unable to initialize module
  Module compiled with debug=144, thread-safety=167 module API=1120015052
  PHP compiled with debug=0, thread-safety=0 module API=20010901
  These options need to match
   in Unknown on line 0
  
  If anyone has any suggestions as to what to look for, I would 
 appreciate it.
  I already tried 'pointing' php.ini directly to sendmail (which is in a
  traditional spot: /usr/sbin/sendmail).
  
  Thanks,
  
  -Mike
 -- 
 Adam Voigt ([EMAIL PROTECTED])
 Linux/Unix Network Administrator
 The Cryptocomm Group
 
 
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RE: [PHP] mail() function

[Mike At Spy]

Never really thought about that, but the perms are set at 644 for the script trying to 
do the actual function.

I ran the command to find the version at command line, but the script that sends mail 
is part of a web site (so I am running it through my browser).

-Mike


 -Original Message-
 From: Brian S. Drexler [mailto:[EMAIL PROTECTED]
 Sent: Monday, July 07, 2003 2:06 PM
 To: 'Mike At Spy'
 Subject: RE: [PHP] mail() function
 
 
 I assume you are running this on the command line.  Does the file 
 have the correct permissions?
 
 -Original Message-
 From: Mike At Spy [mailto:[EMAIL PROTECTED]
 Sent: Monday, July 07, 2003 1:57 PM
 To: [EMAIL PROTECTED]; Mike At Spy
 Cc: [EMAIL PROTECTED]
 Subject: RE: [PHP] mail() function
 
 
 
 I can't tell what the version is, but I can tell you that the kernel is:
 
 2.4.7-10
 
 Maybe it has something to do with what identity php or sendmail 
 is running under?
 
 Thanks,
 
 -Mike
 
 
 
  -Original Message-
  From: Adam Voigt [mailto:[EMAIL PROTECTED]
  Sent: Monday, July 07, 2003 1:01 PM
  To: Mike At Spy
  Cc: [EMAIL PROTECTED]
  Subject: Re: [PHP] mail() function
  
  
  Yeah, umm, thats a weird error message.
  What server platform / OS?
  
  
  On Mon, 2003-07-07 at 12:58, Mike At Spy wrote:
   Is anyone familiar with the mail function and how it works on 
  the server?  I
   can't get it to work on a client's server, and this error shows 
  up in the
   error log:
   
   PHP Warning:  U1]': Unable to initialize module
   Module compiled with debug=144, thread-safety=135 module 
 API=1119810252
   PHP compiled with debug=0, thread-safety=0 module API=20010901
   These options need to match
in Unknown on line 0
   PHP Warning:  U1]': Unable to initialize module
   Module compiled with debug=144, thread-safety=167 module 
 API=1120015052
   PHP compiled with debug=0, thread-safety=0 module API=20010901
   These options need to match
in Unknown on line 0
   
   If anyone has any suggestions as to what to look for, I would 
  appreciate it.
   I already tried 'pointing' php.ini directly to sendmail (which is in a
   traditional spot: /usr/sbin/sendmail).
   
   Thanks,
   
   -Mike
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  Linux/Unix Network Administrator
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RE: [PHP] mail() function

[Mike At Spy]

They have it set to Show all errors except for notices.

-Mike


 -Original Message-
 From: Brian S. Drexler [mailto:[EMAIL PROTECTED]
 Sent: Monday, July 07, 2003 2:18 PM
 To: 'Mike At Spy'
 Subject: RE: [PHP] mail() function
 
 
 Ok, so if it is a command line issue it's not the problem you are 
 having with the mail script.  Does it give you any sort of error 
 from the browser or are the errors turned off in the php.ini?
 
 -Original Message-
 From: Mike At Spy [mailto:[EMAIL PROTECTED]
 Sent: Monday, July 07, 2003 2:17 PM
 To: [EMAIL PROTECTED]
 Cc: [EMAIL PROTECTED]
 Subject: RE: [PHP] mail() function
 
 
 
 
 Never really thought about that, but the perms are set at 644 for 
 the script trying to do the actual function.
 
 I ran the command to find the version at command line, but the 
 script that sends mail is part of a web site (so I am running it 
 through my browser).
 
 -Mike
 
 
  -Original Message-
  From: Brian S. Drexler [mailto:[EMAIL PROTECTED]
  Sent: Monday, July 07, 2003 2:06 PM
  To: 'Mike At Spy'
  Subject: RE: [PHP] mail() function
  
  
  I assume you are running this on the command line.  Does the file 
  have the correct permissions?
  
  -Original Message-
  From: Mike At Spy [mailto:[EMAIL PROTECTED]
  Sent: Monday, July 07, 2003 1:57 PM
  To: [EMAIL PROTECTED]; Mike At Spy
  Cc: [EMAIL PROTECTED]
  Subject: RE: [PHP] mail() function
  
  
  
  I can't tell what the version is, but I can tell you that the kernel is:
  
  2.4.7-10
  
  Maybe it has something to do with what identity php or sendmail 
  is running under?
  
  Thanks,
  
  -Mike
  
  
  
   -Original Message-
   From: Adam Voigt [mailto:[EMAIL PROTECTED]
   Sent: Monday, July 07, 2003 1:01 PM
   To: Mike At Spy
   Cc: [EMAIL PROTECTED]
   Subject: Re: [PHP] mail() function
   
   
   Yeah, umm, thats a weird error message.
   What server platform / OS?
   
   
   On Mon, 2003-07-07 at 12:58, Mike At Spy wrote:
Is anyone familiar with the mail function and how it works on 
   the server?  I
can't get it to work on a client's server, and this error shows 
   up in the
error log:

PHP Warning:  U1]': Unable to initialize module
Module compiled with debug=144, thread-safety=135 module 
  API=1119810252
PHP compiled with debug=0, thread-safety=0 module API=20010901
These options need to match
 in Unknown on line 0
PHP Warning:  U1]': Unable to initialize module
Module compiled with debug=144, thread-safety=167 module 
  API=1120015052
PHP compiled with debug=0, thread-safety=0 module API=20010901
These options need to match
 in Unknown on line 0

If anyone has any suggestions as to what to look for, I would 
   appreciate it.
I already tried 'pointing' php.ini directly to sendmail 
 (which is in a
traditional spot: /usr/sbin/sendmail).

Thanks,

-Mike
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   Linux/Unix Network Administrator
   The Cryptocomm Group
   
   
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[PHP] PHP and Apache

[Mike At Spy]

Recently, I had Apache upgraded on my linux redhat 7.3 server from 1.2.3 to
1.3.27.

PHP stopped working when trying to process html files with php in them.  In
the httpd.conf file, I have AllowOverride set to All.  In the Virtual Host
settings I have 'AddType application/x-httpd-php .html'.

HTML documents, which did process before the upgrade, no longer do.  Does
anyone know of any reason for this?  I've been searching on the web, but
most people go back to the ol' AllowOverride thing, which isn't the issue in
this case.

Thanks,

-Mike



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[PHP] header() issues....

[Mike At Spy]

Does anyone know if there are issues with using the header() function inside
frames?  Is there extra stuff that needs to be added to it to get it to work
correctly?

Or if there were issues with header in php 4.06?

Thanks,

-Mike



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RE: [PHP] Re: header(); Issue

[Mike At Spy]

I'll give one of the suggestions a whirl (or both).  I do have this same
sort of thing on a different server with a more recent version of PHP -
which is why I thought it might be a version issue. :)

-Mike


 -Original Message-
 From: Esteban Fernandez [mailto:[EMAIL PROTECTED]
 Sent: Thursday, June 19, 2003 12:41 PM
 To: [EMAIL PROTECTED]
 Subject: [PHP] Re: header(); Issue


 Try

 header(Location: .$Relative./outstanding.php?pdd=1pddid=.$poid.);

 EF.


 Spyproductions Support Team [EMAIL PROTECTED] escribió en el
 mensaje news:[EMAIL PROTECTED]
 
  I have this in a script:
 
  header(Location: $Relative/outstanding.php?pdd=1pddid=$poid);
 
  It works fine elsewhere in the script without the variables.
 Does anyone
  know if php 4.06 has issues with this?  Or am I making a boneheaded
 mistake
  here?
 
  $Relative is from an include, and outputs fine.  :)
 
  Thanks!
 
  :)
 
  -Mike
 
 



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[PHP] Agh! Driving me crazy!

[Mike At Spy]

Anyone see anything wrong with this line of code?

$fine = mysql_query(INSERT INTO
tblPOItems(poID,poItemUPC,poItemNumber,poItemDescription,poItemInnerCasePkg,
poInnerQuantity,poItemEstQuantity,poItemCostEach,poItemSuggestedSellPrice)
values('$poID', '$place[0]', '$inmb', '$ides', '$iicp', '$cases',
'$place[1]', '$iice', '$isgs');

I keep getting:

Query failed: You have an error in your SQL syntax near '' at line 1 Query
was: 1064 exiting.

I checked the column count a number of times.  Everything is fine there. Not
that it would matter as much since i am specifying it.  :\

Thanks,

-Mike



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RE: [PHP] Agh! Driving me crazy!

[Mike At Spy]

Gah!!!

:)

Thanks!

Thanks to all!  :)

-Mike


 -Original Message-
 From: Jennifer Goodie [mailto:[EMAIL PROTECTED]
 Sent: Wednesday, June 18, 2003 3:05 PM
 To: Mike At Spy; [EMAIL PROTECTED]
 Subject: RE: [PHP] Agh! Driving me crazy!


 You are missing the closing ) around the values you are inserting.

  Anyone see anything wrong with this line of code?
 
  $fine = mysql_query(INSERT INTO
  tblPOItems(poID,poItemUPC,poItemNumber,poItemDescription,poItemInn
  erCasePkg,
 
 poInnerQuantity,poItemEstQuantity,poItemCostEach,poItemSuggestedSellPrice)
  values('$poID', '$place[0]', '$inmb', '$ides', '$iicp', '$cases',
  '$place[1]', '$iice', '$isgs');
 
  I keep getting:
 
  Query failed: You have an error in your SQL syntax near '' at
 line 1 Query
  was: 1064 exiting.
 





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[PHP] setlocale() changes?

[Mike At Spy]

I've been getting a warning on one of my scripts since I upgraded from 4.1.2
to the most recent version of PHP.  The warning is:

Warning: setlocale(): Passing locale category name as string is deprecated.
Use the LC_* -constants instead


The script at the line that is failing sez:

setlocale (LC_TIME, $locale);

This script isn't mine off hand - what do I look for?  I'm not sure I
understand the error message.  :\

Thanks!

-Mike



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RE: [PHP] setlocale() changes?

[Mike At Spy]

Actually, I must apologize to you and the list.  I checked the function on
the php site *after* I asked and saw that was the issue immediately. :\

:)

-Mike


 -Original Message-
 From: Neil Freeman [mailto:[EMAIL PROTECTED]
 Sent: Wednesday, June 04, 2003 8:57 AM
 To: Mike At Spy
 Cc: [EMAIL PROTECTED]
 Subject: Re: [PHP] setlocale() changes?


 Try removing the double quotes around LC_TIME

 Neil

 Mike At Spy wrote:
 
 **
 *
  This Message Was Virus Checked With : SAVI 3.69 May 2003
  Last Updated/Checked 2nd June 2003
 
 **
 *
 
 
  I've been getting a warning on one of my scripts since I
 upgraded from 4.1.2
  to the most recent version of PHP.  The warning is:
 
  Warning: setlocale(): Passing locale category name as string is
 deprecated.
  Use the LC_* -constants instead
 
 
  The script at the line that is failing sez:
 
  setlocale (LC_TIME, $locale);
 
  This script isn't mine off hand - what do I look for?  I'm not sure I
  understand the error message.  :\
 
  Thanks!
 
  -Mike
 
 
 

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RE: [PHP] PHP vs. CGI

[Mike At Spy]

Sorry, yes.  :)

-Mike


 -Original Message-
 From: Leif K-Brooks [mailto:[EMAIL PROTECTED]
 Sent: Wednesday, March 05, 2003 4:45 PM
 To: [EMAIL PROTECTED]
 Cc: [EMAIL PROTECTED]
 Subject: Re: [PHP] PHP vs. CGI
 
 
 CGI meaning perl?
 
 SpyProductions Support Team wrote:
 
 Does PHP use less system resources than CGI on a server?
 
 I have a bulletin board which is incredibly active, but there is a PHP
 sister to it.
 
 Thanks,
 
 -Mike
 
 
 
   
 
 
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 unauthorized attempt to decrypt it will be prosecuted to the full 
 extent of the law.
 
 
 
 
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[PHP] Installation Configuration Question

[Mike At Spy]

Has anyone ever had an issue where PHP, for whatever reason, stopped
.htaccess files from working?

Thanks,

-Mike



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[PHP] PHP not working in html

[Mike At Spy]

PHP isn't working in my html docs - what changes do I need to make to get it
to do so?  Does it need to be recompiled?  Can I do it without re-compiling?

Thanks,

-Mike



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RE: [PHP] PHP not working in html

[Mike At Spy]

There isn't any .htaccess file in the directory - I added one with the line
you specified, and my directory comes up with a 'server misconfiguration
error'.  Any other ideas?  :)

Thanks!

-Mike





 In your .htaccess file remove anything that looks like this:
 AddHandler server-parsed .html

 And add this line:
 AddType application/x-httpd-php .php .htm .html

 Do a search for parse html php for more help.

 -Kevin

 - Original Message -
 From: Mike At Spy [EMAIL PROTECTED]
 To: [EMAIL PROTECTED]
 Sent: Thursday, November 07, 2002 2:16 PM
 Subject: [PHP] PHP not working in html


 
  PHP isn't working in my html docs - what changes do I need to
 make to get
 it
  to do so?  Does it need to be recompiled?  Can I do it without
 re-compiling?
 
  Thanks,
 
  -Mike
 
 
 
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[PHP] Weird, weird, weird!

[Mike At Spy]

Anyone ever have the experience of working on a site, working with MySQL and
then having something almost inexplicable happen?

I was working on a script, and had this weird event.  A very simple script
with this:

mysql_connect(localhost,user,pass);
mysql_select_db(dbname)
or die(Query Connection Database failed);
$old=date(z)-1;
mysql_query(DELETE FROM Users WHERE Date  $old);

$cartquery = mysql_query(SELECT CartItemsID,Date FROM CartItems)
or die(Query failed);
$cartnow  = mysql_query($cartquery);
$cr=0;
$cartme = mysql_num_rows($cartnow);  this is the line that is failing!
while ($cr  $cartme){
$cartrow=mysql_fetch_row($cartnow);
$CII=$cartrow[0];
$CDa=$cartrow[1];
$pieces=explode(:,$CDa);
$DCHK=$pieces[1];
if ($DCHK  $old) {
mysql_query(DELETE FROM CartItems WHERE CartItemsID = '$CII');
}
}

Started spitting this error at me:

Warning: Supplied argument is not a valid MySQL result resource in (exact
location snipped)

This is the line containing mysql_num_rows that is getting this error.

Someone please tell me I'm missing something obvious!  Yes, the connects to
MySQL database are fine.  I can run the query right in phpMyAdmin with no
issues.

If mysql_num_rows returns 0, or empty, it shouldn't be complaining, should
it?  It would just skip the loop, correct?

Thanks,

-Mike



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RE: [PHP] Re: Weird, weird, weird!

[Mike At Spy]

Damn! I should have seen that!

Oh well, at least it was something obvious.  ;-)

Thanks to you Jason, and everyone who replied to point out the obvious to my
tired brain (excuses, excuses!).

-Mike


 -Original Message-
 From: Jason Young [mailto:[EMAIL PROTECTED]]
 Sent: Tuesday, October 08, 2002 4:15 PM
 To: [EMAIL PROTECTED]
 Subject: [PHP] Re: Weird, weird, weird!


 You're doubling up on your mysql_query's .. the first one runs, and I
 don't know the ins and outs of PHP, but the second mysql_query causes
 the resource to not be available... had a similar problem recently.

 Take the mysql_query out of the $cartquery assignment.

 -Jason

 Mike At Spy wrote:
  Anyone ever have the experience of working on a site, working
 with MySQL and
  then having something almost inexplicable happen?
 
  I was working on a script, and had this weird event.  A very
 simple script
  with this:
 
  mysql_connect(localhost,user,pass);
  mysql_select_db(dbname)
  or die(Query Connection Database failed);
  $old=date(z)-1;
  mysql_query(DELETE FROM Users WHERE Date  $old);
 
  $cartquery = mysql_query(SELECT CartItemsID,Date FROM CartItems)
  or die(Query failed);
  $cartnow  = mysql_query($cartquery);
  $cr=0;
  $cartme = mysql_num_rows($cartnow);  this is the line that
 is failing!
  while ($cr  $cartme){
  $cartrow=mysql_fetch_row($cartnow);
  $CII=$cartrow[0];
  $CDa=$cartrow[1];
  $pieces=explode(:,$CDa);
  $DCHK=$pieces[1];
  if ($DCHK  $old) {
  mysql_query(DELETE FROM CartItems WHERE CartItemsID = '$CII');
  }
  }
 
  Started spitting this error at me:
 
  Warning: Supplied argument is not a valid MySQL result resource
 in (exact
  location snipped)
 
  This is the line containing mysql_num_rows that is getting this error.
 
  Someone please tell me I'm missing something obvious!  Yes, the
 connects to
  MySQL database are fine.  I can run the query right in
 phpMyAdmin with no
  issues.
 
  If mysql_num_rows returns 0, or empty, it shouldn't be
 complaining, should
  it?  It would just skip the loop, correct?
 
  Thanks,
 
  -Mike
 
 


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[PHP] Populating Other People's Forms

[Mike At Spy]

I would like to write a script that would populate someone else's form on
the net and get the results.

Off hand, I imagine I would use fopen() to open up the web page and pass
some variables to it.  The problem I have is that the form I want to
populate is a multi-step CGI.  Is this possible?  How do I continue to pass
variables to a second or third step, sending variables passed on what the
form says to do next (which is predictable)?

This is considering I do not have the cooperation of the web site I am
trying to fill out the form for step by step, and I would like to write this
so it is done in a behind-the-scenes, automated way.

For example:  A customer registered with me could ask for a product.  My
'agent' would go to the site where the product is sold, login, submit all of
the appropriate information for purchase and shipment, and then come back
with (hopefully) a success message (along with any pertinent information
from the purchase).

Anyone have any ideas, suggestions, or can point me in the right direction?

Thanks,

-Mike



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RE: [PHP] random array sort

[Mike At Spy]

You could use array_rand() to take stuff out of the array at random and then
stuff it all back into another array.

-Mike



 -Original Message-
 From: ROBERT MCPEAK [mailto:[EMAIL PROTECTED]]
 Sent: Tuesday, September 10, 2002 10:22 AM
 To: [EMAIL PROTECTED]
 Subject: [PHP] random array sort


 Could someone show me a quick and simple way to randomly sort array
 elements?  I can't seem to pinpoint the correct parameters in the docs.

 Thanks!

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RE: [PHP] random array sort

[Mike At Spy]

From what I understand about array_rand() and the example in the manual, it
does only pull one of each element of the array.  You could easily set up a
script to compare what it is pulling to what the array you putting it into
currently has in it if it didn't.

-Mike



 -Original Message-
 From: David Rice [mailto:[EMAIL PROTECTED]]
 Sent: Tuesday, September 10, 2002 10:49 AM
 To: [EMAIL PROTECTED]
 Subject: Re: [PHP] random array sort


 But if array_rand() truly pulls out random keys, how do you guarantee
 that you are not randomly pulling out the same key as you iterate
 through the array?

 Perhaps you could set the number of keys to return, to the size of the
 array, and somehow, magically, all the keys would be included in the
 returned array of keys.
 i.e. array_rand ( array , array_size)
 I have no idea what this would produce...
 -David

 On Tuesday, September 10, 2002, at 10:33 AM, Mike At Spy wrote:

 
  You could use array_rand() to take stuff out of the array at random and
  then
  stuff it all back into another array.
 
  -Mike
 
 
 
  -Original Message-
  From: ROBERT MCPEAK [mailto:[EMAIL PROTECTED]]
  Sent: Tuesday, September 10, 2002 10:22 AM
  To: [EMAIL PROTECTED]
  Subject: [PHP] random array sort
 
 
  Could someone show me a quick and simple way to randomly sort array
  elements?  I can't seem to pinpoint the correct parameters in the docs.
 
  Thanks!
 
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RE: [PHP] Agh! trim (#$@#@^%!!!)

[Mike At Spy]

Get this - it didn't work!  :(

I tried decreasing the -1 to -2 and so on, but nothing on that either.  :(

-Mike



 -Original Message-
 From: Rasmus Lerdorf [mailto:[EMAIL PROTECTED]]
 Sent: Tuesday, August 20, 2002 12:45 PM
 To: Mike At Spy
 Cc: [EMAIL PROTECTED]
 Subject: Re: [PHP] Agh! trim (#$@#@^%!!!)
 
 
 Well, perhaps you have something after the . in that string?
 
 You can strip off the last char of a string very simply with:
 
substr($str,0,-1)
 
 -Rasmus
 
 On Tue, 20 Aug 2002, Mike At Spy wrote:
 
 
  Hey!
 
  :)
 
  I have an issue with trim / triml.  Whenever I put a string in 
 to trimmed,
  it refuses to take the period at the end of the string off.
 
  I did put more things to trim first, but this is basically what 
 I am doing:
 
 
  $single = The date is 20-Aug-2002. // This is an example - see below
  $trimmed = rtrim($date, .);
 
 
  Is there an issue with this?  I've tried using trim() too.
 
  The source of $single is a reponse from a server.  I should 
 note that when I
  put this in as an experiment, it works fine.  When I get the 
 line from the
  server, it doesn't work!
 
  The only thing I can think of is the possibility that the . I 
 am seeing at
  the end of the line isn't really one (it looks like a duck, 
 copies like a
  duck, but...isn't a duck??!!).
 
  Is there a way to just strip the last character off regardless 
 of what it
  is?
 
  Thanks,
 
  -Mike
 
 
 
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RE: [PHP] Agh! trim (#$@#@^%!!!)

[Mike At Spy]

Here is the complete code - I have a lot of prints to watch things as they
happen. $whois is the result of a WHOIS search.



// beginning of my stuff

function get_date ($whois){
trim ($whois);
$whoisarray = explode (\n, $whois);
print_r(array_values ($whoisarray));

$total_elements = count ($whoisarray);

print pb$total_elements/b elements in this array;

$ce = 0;

while ($ce  $total_elements){

$single_line = array_pop ($whoisarray);

$expiration = strstr ($single_line,xpires);

if ($expiration != '' || 0) {

print pbThis is the line you want!  Line $ce that sez:
$single_line/bp;

// $single_line = preg_replace (.,  , $single_line);

$single_line = substr($single_line, 0, -2);

//  $single_line = rtrim ($single_line, \t\s\n\r);

$getdatearray = explode ( , $single_line);
print_r(array_values ($getdatearray));

$total_expire_elements = count ($getdatearray);

print pbr.$total_expire_elements;

$dc = 0;

while ($dc  $total_expire_elements){

$element = array_pop($getdatearray);

$date_dash = strstr($element,-);

if ($date_dash != '' || 0){

print pbrFirst Detection .$element;

// $trimmed = rtrim ($element, \t.);

print pbrLast print before date function 
.$element;

month_replace ($element);

print pbrResult after function .$element.pbr;

$MySQLDate=date_validate($element);
if (substr($MySQLDate, 0, 5)==Error) {
// Insert Error Code if you want
} else {
// Insert Valid Date Code if you want
}

print pThe MySQL Formated date is $MySQLDate;

}
else {}

$dc++;

 }

}
else {}

$ce++;

}

}
// end of my stuff


Thanks,

-Mike






 -Original Message-
 From: Jason Wong [mailto:[EMAIL PROTECTED]]
 Sent: Wednesday, August 21, 2002 8:53 AM
 To: [EMAIL PROTECTED]
 Subject: Re: [PHP] Agh! trim (#$@#@^%!!!)


 On Wednesday 21 August 2002 20:36, Mike At Spy wrote:
  Get this - it didn't work!  :(
 
  I tried decreasing the -1 to -2 and so on, but nothing on that
 either.  :(

 Post your exact code which didn't work.

 --
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 Open Source Software Systems Integrators
 * Web Design  Hosting * Internet  Intranet Applications Development *

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 You can't go home again, unless you set $HOME.
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RE: [PHP] Agh! trim (#$@#@^%!!!)

[Mike At Spy]

But isn't taking off characters or spaces considered modifying a string?

I'll take another look at the manual, thanks.

-Mike


 -Original Message-
 From: Darren Gamble [mailto:[EMAIL PROTECTED]]
 Sent: Wednesday, August 21, 2002 10:32 AM
 To: 'Mike At Spy'; [EMAIL PROTECTED]
 Subject: RE: [PHP] Agh! trim (#$@#@^%!!!)
 
 
 Good day,
 
 Well, for one, you are discarding the results of trim().
 
 Check out the online manual page for trim().  The trim'ed string is
 returned.  It does not say it modifies the string it is passed.
 
 
 Darren Gamble
 Planner, Regional Services
 Shaw Cablesystems GP
 630 - 3rd Avenue SW
 Calgary, Alberta, Canada
 T2P 4L4
 (403) 781-4948
 
 
  -Original Message-
  From: Mike At Spy [mailto:[EMAIL PROTECTED]]
  Sent: Wednesday, August 21, 2002 7:12 AM
  To: [EMAIL PROTECTED]
  Subject: RE: [PHP] Agh! trim (#$@#@^%!!!)
  
  
  
  Here is the complete code - I have a lot of prints to watch 
  things as they
  happen. $whois is the result of a WHOIS search.
  
  
  
  // beginning of my stuff
  
  function get_date ($whois){
  trim ($whois);
  $whoisarray = explode (\n, $whois);
  print_r(array_values ($whoisarray));
  
  $total_elements = count ($whoisarray);
  
  print pb$total_elements/b elements in this array;
  
  $ce = 0;
  
  while ($ce  $total_elements){
  
  $single_line = array_pop ($whoisarray);
  
  $expiration = strstr ($single_line,xpires);
  
  if ($expiration != '' || 0) {
  
  print pbThis is the line you want!  Line $ce that sez:
  $single_line/bp;
  
  // $single_line = preg_replace (.,  , $single_line);
  
  $single_line = substr($single_line, 0, -2);
  
  //  $single_line = rtrim ($single_line, \t\s\n\r);
  
  $getdatearray = explode ( , $single_line);
  print_r(array_values ($getdatearray));
  
  $total_expire_elements = count ($getdatearray);
  
  print pbr.$total_expire_elements;
  
  $dc = 0;
  
  while ($dc  $total_expire_elements){
  
  $element = array_pop($getdatearray);
  
  $date_dash = strstr($element,-);
  
  if ($date_dash != '' || 0){
  
  print pbrFirst Detection 
  .$element;
  
  // $trimmed = rtrim ($element, \t.);
  
  print pbrLast print before 
  date function .$element;
  
  month_replace ($element);
  
  print pbrResult after function 
  .$element.pbr;
  
  $MySQLDate=date_validate($element);
  if (substr($MySQLDate, 0, 5)==Error) {
  // Insert Error Code if you want
  } else {
  // Insert Valid Date Code if you want
  }
  
  print pThe MySQL Formated date is 
  $MySQLDate;
  
  
  }
  else {}
  
  $dc++;
  
   }
  
  
  }
  else {}
  
  $ce++;
  
  }
  
  }
  // end of my stuff
  
  
  Thanks,
  
  -Mike
  
  
  
  
  
  
   -Original Message-
   From: Jason Wong [mailto:[EMAIL PROTECTED]]
   Sent: Wednesday, August 21, 2002 8:53 AM
   To: [EMAIL PROTECTED]
   Subject: Re: [PHP] Agh! trim (#$@#@^%!!!)
  
  
   On Wednesday 21 August 2002 20:36, Mike At Spy wrote:
Get this - it didn't work!  :(
   
I tried decreasing the -1 to -2 and so on, but nothing on that
   either.  :(
  
   Post your exact code which didn't work.
  
   --
   Jason Wong - Gremlins Associates - www.gremlins.com.hk
   Open Source Software Systems Integrators
   * Web Design  Hosting * Internet  Intranet Applications 
  Development *
  
   /*
   You can't go home again, unless you set $HOME.
   */
  
  
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[PHP] Agh! trim (#$@#@^%!!!)

[Mike At Spy]

Hey!

:)

I have an issue with trim / triml.  Whenever I put a string in to trimmed,
it refuses to take the period at the end of the string off.

I did put more things to trim first, but this is basically what I am doing:


$single = The date is 20-Aug-2002. // This is an example - see below
$trimmed = rtrim($date, .);


Is there an issue with this?  I've tried using trim() too.

The source of $single is a reponse from a server.  I should note that when I
put this in as an experiment, it works fine.  When I get the line from the
server, it doesn't work!

The only thing I can think of is the possibility that the . I am seeing at
the end of the line isn't really one (it looks like a duck, copies like a
duck, but...isn't a duck??!!).

Is there a way to just strip the last character off regardless of what it
is?

Thanks,

-Mike



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RE: [PHP] Agh! trim (#$@#@^%!!!)

[Mike At Spy]

Sorry, I mistyped - $date should be $single.  

Thanks for the suggestions and help to everyone! - I will pursue them.  :)

-Mike


 -Original Message-
 From: Justin French [mailto:[EMAIL PROTECTED]]
 Sent: Tuesday, August 20, 2002 12:50 PM
 To: Mike At Spy; [EMAIL PROTECTED]
 Subject: Re: [PHP] Agh! trim (#$@#@^%!!!)
 
 
  $single = The date is 20-Aug-2002. // This is an example - see below
  $trimmed = rtrim($date, .);
 
 Where is $date?  I think your attempting to trim the wrong string.
 
 This worked for me:
 
 ?
 $single = The date is 20-Aug-2002.;
 $trimmed = rtrim($single, .);
 echo $trimmed;
 ?
 
 
 To slice off the last character of any string, you could use substr():
 
 ?
 $single = The date is 20-Aug-2002.;
 $trimmed = substr($single, 0, -1);
 echo $trimmed;
 ?
 
 
 Justin French
 
 
 
 on 21/08/02 2:35 AM, Mike At Spy ([EMAIL PROTECTED]) wrote:
 
  
  Hey!
  
  :)
  
  I have an issue with trim / triml.  Whenever I put a string in 
 to trimmed,
  it refuses to take the period at the end of the string off.
  
  I did put more things to trim first, but this is basically what 
 I am doing:
  
  
  $single = The date is 20-Aug-2002. // This is an example - see below
  $trimmed = rtrim($date, .);
  
  
  Is there an issue with this?  I've tried using trim() too.
  
  The source of $single is a reponse from a server.  I should 
 note that when I
  put this in as an experiment, it works fine.  When I get the 
 line from the
  server, it doesn't work!
  
  The only thing I can think of is the possibility that the . I 
 am seeing at
  the end of the line isn't really one (it looks like a duck, 
 copies like a
  duck, but...isn't a duck??!!).
  
  Is there a way to just strip the last character off regardless 
 of what it
  is?
  
  Thanks,
  
  -Mike
  
  
 
 
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 To unsubscribe, visit: http://www.php.net/unsub.php
 
 


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[PHP] PHP Compile: IMAP enabled?

[Mike At Spy]

If IMAP is entered under Loaded Modules in the apache section of a phpinfo
file, does that mean IMAP has been enabled?

Thanks,

-Mike



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[PHP] Parse Error Suggestions?

[Mike At Spy]

Anyone have any suggestions for getting better reporting on a generic Parse
Error?  Code is falling to the end of the script, and I can't find a problem
anywhere.

I looked on the PHP site for error reporting functions, but apparently they
do not handle Parse Errors.

Thanks,

-Mike



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RE: [PHP] Parse Error Suggestions?

[Mike At Spy]

 On Mon, 18 Mar 2002, Mike At Spy wrote:
  Anyone have any suggestions for getting better reporting on a generic
  Parse Error?  Code is falling to the end of the script, and I can't find
  a problem anywhere.

 I'd guess you left a curly brace open. Try opening the file in an editor
 that lets you balance your braces.


I thought the same thing exactly - but I have gone over them a dozen times
and I am getting nothing!

In fact, shouldn't any script run before the error?  i.e. - shouldn't a
print or echo before any script runs produce something?  Mine isn't!

-Mike



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