Re: [PHP] array key's: which is correct?
Tanel Tammik wrote: Hi, which one is correct or better? $array[3] = ''; or $array['3'] = ''; $i = 7; $array[$i] = ''; or $array[$i] = ''; Sometimes it is good to illustrate the correct answer: ?php $array = array ( '1' = '1', '2' = '2', 'three' = 'three', '4.0' = '4.0', 5.0 = 5.0, ); var_dump( array_keys( $array ) ); ? The answer is surprising (well, not really :) and certainly advocates against making literal strings of integers or manually converting a string integer to a real integer or using floating point keys. Cheers, Rob. -- E-Mail Disclaimer: Information contained in this message and any attached documents is considered confidential and legally protected. This message is intended solely for the addressee(s). Disclosure, copying, and distribution are prohibited unless authorized. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] array key's: which is correct?
On Tue, 2010-06-08 at 09:38 -0400, Robert Cummings wrote: Tanel Tammik wrote: Hi, which one is correct or better? $array[3] = ''; or $array['3'] = ''; $i = 7; $array[$i] = ''; or $array[$i] = ''; Sometimes it is good to illustrate the correct answer: ?php $array = array ( '1' = '1', '2' = '2', 'three' = 'three', '4.0' = '4.0', 5.0 = 5.0, ); var_dump( array_keys( $array ) ); ? The answer is surprising (well, not really :) and certainly advocates against making literal strings of integers or manually converting a string integer to a real integer or using floating point keys. Cheers, Rob. -- E-Mail Disclaimer: Information contained in this message and any attached documents is considered confidential and legally protected. This message is intended solely for the addressee(s). Disclosure, copying, and distribution are prohibited unless authorized. Yeah, I found that out the hard way when I was trying to make an array of Gantt tasks, and realised that all my nice task numbers were changed! Thanks, Ash http://www.ashleysheridan.co.uk
Re: [PHP] array key's: which is correct?
On Tue, Jun 08, 2010 at 09:38:58AM -0400, Robert Cummings wrote: Tanel Tammik wrote: Hi, which one is correct or better? $array[3] = ''; or $array['3'] = ''; $i = 7; $array[$i] = ''; or $array[$i] = ''; Sometimes it is good to illustrate the correct answer: ?php $array = array ( '1' = '1', '2' = '2', 'three' = 'three', '4.0' = '4.0', 5.0 = 5.0, ); var_dump( array_keys( $array ) ); ? The answer is surprising (well, not really :) and certainly advocates against making literal strings of integers or manually converting a string integer to a real integer or using floating point keys. Curse you, Rob Cummings! ;-} I was stunned at the results of this. I assumed that integers cast as strings would remain strings as indexes. Not so. And then float indexes cast to ints. Argh! My advice to the original poster was slightly incorrect. But I would still encourage you to avoid enclosing variables in double-quotes unnecessarily. (And integers in single-quotes for that matter.) Paul -- Paul M. Foster -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] array key's: which is correct?
On Tue, 2010-06-08 at 10:35 -0400, Paul M Foster wrote: On Tue, Jun 08, 2010 at 09:38:58AM -0400, Robert Cummings wrote: Tanel Tammik wrote: Hi, which one is correct or better? $array[3] = ''; or $array['3'] = ''; $i = 7; $array[$i] = ''; or $array[$i] = ''; Sometimes it is good to illustrate the correct answer: ?php $array = array ( '1' = '1', '2' = '2', 'three' = 'three', '4.0' = '4.0', 5.0 = 5.0, ); var_dump( array_keys( $array ) ); ? The answer is surprising (well, not really :) and certainly advocates against making literal strings of integers or manually converting a string integer to a real integer or using floating point keys. Curse you, Rob Cummings! ;-} I was stunned at the results of this. I assumed that integers cast as strings would remain strings as indexes. Not so. And then float indexes cast to ints. Argh! My advice to the original poster was slightly incorrect. But I would still encourage you to avoid enclosing variables in double-quotes unnecessarily. (And integers in single-quotes for that matter.) Paul -- Paul M. Foster The obvious way around this would be to include some sort of character in the index that can't be cast to an integer, so instead of $array[1.0] which would equate to $array[1] maybe add an underscore to make it $array['_1.0']. It's not the prettiest of solutions, but it does mean that indexes are kept as you intended, and you need only strip out the first character, although I imagine a lot of string manipulation on a large array would decrease performance. Thanks, Ash http://www.ashleysheridan.co.uk
Re: [PHP] array key's: which is correct?
On 8 June 2010 16:38, Ashley Sheridan a...@ashleysheridan.co.uk wrote: On Tue, 2010-06-08 at 10:35 -0400, Paul M Foster wrote: On Tue, Jun 08, 2010 at 09:38:58AM -0400, Robert Cummings wrote: Tanel Tammik wrote: Hi, which one is correct or better? $array[3] = ''; or $array['3'] = ''; $i = 7; $array[$i] = ''; or $array[$i] = ''; Sometimes it is good to illustrate the correct answer: ?php $array = array ( '1' = '1', '2' = '2', 'three' = 'three', '4.0' = '4.0', 5.0 = 5.0, ); var_dump( array_keys( $array ) ); ? The answer is surprising (well, not really :) and certainly advocates against making literal strings of integers or manually converting a string integer to a real integer or using floating point keys. Curse you, Rob Cummings! ;-} I was stunned at the results of this. I assumed that integers cast as strings would remain strings as indexes. Not so. And then float indexes cast to ints. Argh! My advice to the original poster was slightly incorrect. But I would still encourage you to avoid enclosing variables in double-quotes unnecessarily. (And integers in single-quotes for that matter.) Paul -- Paul M. Foster The obvious way around this would be to include some sort of character in the index that can't be cast to an integer, so instead of $array[1.0] which would equate to $array[1] maybe add an underscore to make it $array['_1.0']. It's not the prettiest of solutions, but it does mean that indexes are kept as you intended, and you need only strip out the first character, although I imagine a lot of string manipulation on a large array would decrease performance. Floats in quotes are not cast to int when used as array keys. Just an FYI :) Regards Peter -- hype WWW: http://plphp.dk / http://plind.dk LinkedIn: http://www.linkedin.com/in/plind BeWelcome/Couchsurfing: Fake51 Twitter: http://twitter.com/kafe15 /hype -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] array key's: which is correct?
On Tue, 2010-06-08 at 16:44 +0200, Peter Lind wrote: On 8 June 2010 16:38, Ashley Sheridan a...@ashleysheridan.co.uk wrote: On Tue, 2010-06-08 at 10:35 -0400, Paul M Foster wrote: On Tue, Jun 08, 2010 at 09:38:58AM -0400, Robert Cummings wrote: Tanel Tammik wrote: Hi, which one is correct or better? $array[3] = ''; or $array['3'] = ''; $i = 7; $array[$i] = ''; or $array[$i] = ''; Sometimes it is good to illustrate the correct answer: ?php $array = array ( '1' = '1', '2' = '2', 'three' = 'three', '4.0' = '4.0', 5.0 = 5.0, ); var_dump( array_keys( $array ) ); ? The answer is surprising (well, not really :) and certainly advocates against making literal strings of integers or manually converting a string integer to a real integer or using floating point keys. Curse you, Rob Cummings! ;-} I was stunned at the results of this. I assumed that integers cast as strings would remain strings as indexes. Not so. And then float indexes cast to ints. Argh! My advice to the original poster was slightly incorrect. But I would still encourage you to avoid enclosing variables in double-quotes unnecessarily. (And integers in single-quotes for that matter.) Paul -- Paul M. Foster The obvious way around this would be to include some sort of character in the index that can't be cast to an integer, so instead of $array[1.0] which would equate to $array[1] maybe add an underscore to make it $array['_1.0']. It's not the prettiest of solutions, but it does mean that indexes are kept as you intended, and you need only strip out the first character, although I imagine a lot of string manipulation on a large array would decrease performance. Floats in quotes are not cast to int when used as array keys. Just an FYI :) Regards Peter They are. Go look at Robs earlier example. Even building upon that to make a float value where it doesn't equate to an integer, it is still cast as an integer unless it's inside a string: $array = array ( '1' = '1', '2' = '2', 'three' = 'three', '4.0' = '4.0', 5.0 = 5.0, 6.5= 6.5, ); var_dump( array_keys( $array ) ); That's Robs code, but I added in the last element to show how a float index is converted to an integer. Putting the float value inside a string solves the issue. Thanks, Ash http://www.ashleysheridan.co.uk
Re: [PHP] array key's: which is correct?
On 8 June 2010 16:53, Ashley Sheridan a...@ashleysheridan.co.uk wrote: On Tue, 2010-06-08 at 16:44 +0200, Peter Lind wrote: On 8 June 2010 16:38, Ashley Sheridan a...@ashleysheridan.co.uk wrote: On Tue, 2010-06-08 at 10:35 -0400, Paul M Foster wrote: On Tue, Jun 08, 2010 at 09:38:58AM -0400, Robert Cummings wrote: Tanel Tammik wrote: Hi, which one is correct or better? $array[3] = ''; or $array['3'] = ''; $i = 7; $array[$i] = ''; or $array[$i] = ''; Sometimes it is good to illustrate the correct answer: ?php $array = array ( '1' = '1', '2' = '2', 'three' = 'three', '4.0' = '4.0', 5.0 = 5.0, ); var_dump( array_keys( $array ) ); ? The answer is surprising (well, not really :) and certainly advocates against making literal strings of integers or manually converting a string integer to a real integer or using floating point keys. Curse you, Rob Cummings! ;-} I was stunned at the results of this. I assumed that integers cast as strings would remain strings as indexes. Not so. And then float indexes cast to ints. Argh! My advice to the original poster was slightly incorrect. But I would still encourage you to avoid enclosing variables in double-quotes unnecessarily. (And integers in single-quotes for that matter.) Paul -- Paul M. Foster The obvious way around this would be to include some sort of character in the index that can't be cast to an integer, so instead of $array[1.0] which would equate to $array[1] maybe add an underscore to make it $array['_1.0']. It's not the prettiest of solutions, but it does mean that indexes are kept as you intended, and you need only strip out the first character, although I imagine a lot of string manipulation on a large array would decrease performance. Floats in quotes are not cast to int when used as array keys. Just an FYI :) Regards Peter They are. Go look at Robs earlier example. Even building upon that to make a float value where it doesn't equate to an integer, it is still cast as an integer unless it's inside a string: $array = array ( '1' = '1', '2' = '2', 'three' = 'three', '4.0' = '4.0', 5.0 = 5.0, 6.5 = 6.5, ); var_dump( array_keys( $array ) ); That's Robs code, but I added in the last element to show how a float index is converted to an integer. Putting the float value inside a string solves the issue. Did you read what I wrote? ***Floats in quotes*** are not cast to int when used as array keys. Just an FYI :) I tested Robs example, that's how I know that floats in quotes are not converted to ints, whether or not you use '4.0' or '6.5' Regards Peter -- hype WWW: http://plphp.dk / http://plind.dk LinkedIn: http://www.linkedin.com/in/plind BeWelcome/Couchsurfing: Fake51 Twitter: http://twitter.com/kafe15 /hype -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] array key's: which is correct?
On Tue, 2010-06-08 at 17:11 +0200, Peter Lind wrote: On 8 June 2010 16:53, Ashley Sheridan a...@ashleysheridan.co.uk wrote: On Tue, 2010-06-08 at 16:44 +0200, Peter Lind wrote: On 8 June 2010 16:38, Ashley Sheridan a...@ashleysheridan.co.uk wrote: On Tue, 2010-06-08 at 10:35 -0400, Paul M Foster wrote: On Tue, Jun 08, 2010 at 09:38:58AM -0400, Robert Cummings wrote: Tanel Tammik wrote: Hi, which one is correct or better? $array[3] = ''; or $array['3'] = ''; $i = 7; $array[$i] = ''; or $array[$i] = ''; Sometimes it is good to illustrate the correct answer: ?php $array = array ( '1' = '1', '2' = '2', 'three' = 'three', '4.0' = '4.0', 5.0 = 5.0, ); var_dump( array_keys( $array ) ); ? The answer is surprising (well, not really :) and certainly advocates against making literal strings of integers or manually converting a string integer to a real integer or using floating point keys. Curse you, Rob Cummings! ;-} I was stunned at the results of this. I assumed that integers cast as strings would remain strings as indexes. Not so. And then float indexes cast to ints. Argh! My advice to the original poster was slightly incorrect. But I would still encourage you to avoid enclosing variables in double-quotes unnecessarily. (And integers in single-quotes for that matter.) Paul -- Paul M. Foster The obvious way around this would be to include some sort of character in the index that can't be cast to an integer, so instead of $array[1.0] which would equate to $array[1] maybe add an underscore to make it $array['_1.0']. It's not the prettiest of solutions, but it does mean that indexes are kept as you intended, and you need only strip out the first character, although I imagine a lot of string manipulation on a large array would decrease performance. Floats in quotes are not cast to int when used as array keys. Just an FYI :) Regards Peter They are. Go look at Robs earlier example. Even building upon that to make a float value where it doesn't equate to an integer, it is still cast as an integer unless it's inside a string: $array = array ( '1' = '1', '2' = '2', 'three' = 'three', '4.0' = '4.0', 5.0 = 5.0, 6.5 = 6.5, ); var_dump( array_keys( $array ) ); That's Robs code, but I added in the last element to show how a float index is converted to an integer. Putting the float value inside a string solves the issue. Did you read what I wrote? ***Floats in quotes*** are not cast to int when used as array keys. Just an FYI :) I tested Robs example, that's how I know that floats in quotes are not converted to ints, whether or not you use '4.0' or '6.5' Regards Peter -- hype WWW: http://plphp.dk / http://plind.dk LinkedIn: http://www.linkedin.com/in/plind BeWelcome/Couchsurfing: Fake51 Twitter: http://twitter.com/kafe15 /hype Sorry, my bad, I misread your email, you were right! Thanks, Ash http://www.ashleysheridan.co.uk
Re: [PHP] array key's: which is correct?
On Tue, Jun 08, 2010 at 04:44:53PM +0200, Peter Lind wrote: On 8 June 2010 16:38, Ashley Sheridan a...@ashleysheridan.co.uk wrote: On Tue, 2010-06-08 at 10:35 -0400, Paul M Foster wrote: On Tue, Jun 08, 2010 at 09:38:58AM -0400, Robert Cummings wrote: Tanel Tammik wrote: Hi, which one is correct or better? $array[3] = ''; or $array['3'] = ''; $i = 7; $array[$i] = ''; or $array[$i] = ''; Sometimes it is good to illustrate the correct answer: ?php $array = array ( '1' = '1', '2' = '2', 'three' = 'three', '4.0' = '4.0', 5.0 = 5.0, ); var_dump( array_keys( $array ) ); ? The answer is surprising (well, not really :) and certainly advocates against making literal strings of integers or manually converting a string integer to a real integer or using floating point keys. Curse you, Rob Cummings! ;-} I was stunned at the results of this. I assumed that integers cast as strings would remain strings as indexes. Not so. And then float indexes cast to ints. Argh! My advice to the original poster was slightly incorrect. But I would still encourage you to avoid enclosing variables in double-quotes unnecessarily. (And integers in single-quotes for that matter.) Paul -- Paul M. Foster The obvious way around this would be to include some sort of character in the index that can't be cast to an integer, so instead of $array[1.0] which would equate to $array[1] maybe add an underscore to make it $array['_1.0']. It's not the prettiest of solutions, but it does mean that indexes are kept as you intended, and you need only strip out the first character, although I imagine a lot of string manipulation on a large array would decrease performance. Floats in quotes are not cast to int when used as array keys. Just an FYI :) Umm, yes, you are correct. I pasted Rob's code into a test file, added some other print_r()s and such, just to look at the whole issue. I'm *still* examining the results, trying to wrap my wits around why things are done this way. Paul -- Paul M. Foster -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] array key's: which is correct?
Paul M Foster wrote: On Tue, Jun 08, 2010 at 04:44:53PM +0200, Peter Lind wrote: On 8 June 2010 16:38, Ashley Sheridan a...@ashleysheridan.co.uk wrote: On Tue, 2010-06-08 at 10:35 -0400, Paul M Foster wrote: On Tue, Jun 08, 2010 at 09:38:58AM -0400, Robert Cummings wrote: Tanel Tammik wrote: Hi, which one is correct or better? $array[3] = ''; or $array['3'] = ''; $i = 7; $array[$i] = ''; or $array[$i] = ''; Sometimes it is good to illustrate the correct answer: ?php $array = array ( '1' = '1', '2' = '2', 'three' = 'three', '4.0' = '4.0', 5.0 = 5.0, ); var_dump( array_keys( $array ) ); ? The answer is surprising (well, not really :) and certainly advocates against making literal strings of integers or manually converting a string integer to a real integer or using floating point keys. Curse you, Rob Cummings! ;-} I was stunned at the results of this. I assumed that integers cast as strings would remain strings as indexes. Not so. And then float indexes cast to ints. Argh! My advice to the original poster was slightly incorrect. But I would still encourage you to avoid enclosing variables in double-quotes unnecessarily. (And integers in single-quotes for that matter.) Paul -- Paul M. Foster The obvious way around this would be to include some sort of character in the index that can't be cast to an integer, so instead of $array[1.0] which would equate to $array[1] maybe add an underscore to make it $array['_1.0']. It's not the prettiest of solutions, but it does mean that indexes are kept as you intended, and you need only strip out the first character, although I imagine a lot of string manipulation on a large array would decrease performance. Floats in quotes are not cast to int when used as array keys. Just an FYI :) Umm, yes, you are correct. I pasted Rob's code into a test file, added some other print_r()s and such, just to look at the whole issue. I'm *still* examining the results, trying to wrap my wits around why things are done this way. If I were to hazard a guess as to the why of the current functionality, I would say converting an integer string to a real i nt is optimal with respect to both memory and processing when trying to find values by key. As for floating points... Due to the inability to accurately represent some floating point numbers in binary, one would often not get what one expects even when converting to a string. So maybe integer was chosen since it was more optimal than a string. Cheers, Rob. -- E-Mail Disclaimer: Information contained in this message and any attached documents is considered confidential and legally protected. This message is intended solely for the addressee(s). Disclosure, copying, and distribution are prohibited unless authorized. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Array group and sum values.
I have this:
while ($row = mysql_fetch_array($theData[0])) {
$col1[] = $row[0];
$col2[] = lookup($row[1]); // this goes off and gets the country name.
I then loop through col1 and col2 to produce something like this:
52 ARMENIA
215 CANADA
57 CANADA
261 COLOMBIA
53 EGYPT
62 INDIA
50 INDIA
Is there a way I can group these?
Thanks!
--
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Re: [PHP] Array group and sum values.
Paul Halliday wrote:
I have this:
while ($row = mysql_fetch_array($theData[0])) {
$col1[] = $row[0];
$col2[] = lookup($row[1]); // this goes off and gets the country name.
I then loop through col1 and col2 to produce something like this:
52ARMENIA
215 CANADA
57CANADA
261 COLOMBIA
53EGYPT
62INDIA
50INDIA
Is there a way I can group these?
Thanks!
Group them??
How about this
while ($row = mysql_fetch_array($theData[0])) {
$col1[lookup($row[1])][] = $row[0];
which, using the data you showed, will give you this
Array
(
[ARMENIA] = Array
(
[0] = 52
)
[CANADA] = Array
(
[0] = 215
[1] = 57
)
[COLOMBIA] = Array
(
[0] = 261
)
[EGYPT] = Array
(
[0] = 53
)
[INDIA] = Array
(
[0] = 62
[1] = 50
)
)
--
Jim Lucas
Some men are born to greatness, some achieve greatness,
and some have greatness thrust upon them.
Twelfth Night, Act II, Scene V
by William Shakespeare
--
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Re: [PHP] Array group and sum values.
On Tue, May 11, 2010 at 2:25 PM, Jim Lucas li...@cmsws.com wrote:
Paul Halliday wrote:
I have this:
while ($row = mysql_fetch_array($theData[0])) {
$col1[] = $row[0];
$col2[] = lookup($row[1]); // this goes off and gets the country name.
I then loop through col1 and col2 to produce something like this:
52 ARMENIA
215 CANADA
57 CANADA
261 COLOMBIA
53 EGYPT
62 INDIA
50 INDIA
Is there a way I can group these?
Thanks!
Group them??
How about this
while ($row = mysql_fetch_array($theData[0])) {
$col1[lookup($row[1])][] = $row[0];
which, using the data you showed, will give you this
Array
(
[ARMENIA] = Array
(
[0] = 52
)
[CANADA] = Array
(
[0] = 215
[1] = 57
)
[COLOMBIA] = Array
(
[0] = 261
)
[EGYPT] = Array
(
[0] = 53
)
[INDIA] = Array
(
[0] = 62
[1] = 50
)
)
--
Jim Lucas
Some men are born to greatness, some achieve greatness,
and some have greatness thrust upon them.
Twelfth Night, Act II, Scene V
by William Shakespeare
I was actually hoping to have them arranged like:
$col1[0] = INDIA
$col2[0] = 112
$col1[1] = CANADA
$col2[1] = 272
...
Thanks.
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Array group and sum values.
Paul Halliday wrote:
On Tue, May 11, 2010 at 2:25 PM, Jim Lucas li...@cmsws.com wrote:
Paul Halliday wrote:
I have this:
while ($row = mysql_fetch_array($theData[0])) {
$col1[] = $row[0];
$col2[] = lookup($row[1]); // this goes off and gets the country name.
I then loop through col1 and col2 to produce something like this:
52ARMENIA
215 CANADA
57CANADA
261 COLOMBIA
53EGYPT
62INDIA
50INDIA
Is there a way I can group these?
Thanks!
Group them??
How about this
while ($row = mysql_fetch_array($theData[0])) {
$col1[lookup($row[1])][] = $row[0];
which, using the data you showed, will give you this
Array
(
[ARMENIA] = Array
(
[0] = 52
)
[CANADA] = Array
(
[0] = 215
[1] = 57
)
[COLOMBIA] = Array
(
[0] = 261
)
[EGYPT] = Array
(
[0] = 53
)
[INDIA] = Array
(
[0] = 62
[1] = 50
)
)
--
Jim Lucas
Some men are born to greatness, some achieve greatness,
and some have greatness thrust upon them.
Twelfth Night, Act II, Scene V
by William Shakespeare
I was actually hoping to have them arranged like:
$col1[0] = INDIA
$col2[0] = 112
$col1[1] = CANADA
$col2[1] = 272
...
Thanks.
Well, then take what I gave you and do this:
$group[lookup($row[1])][] = $row[0];
foreach ( $group AS $x = $y )
{
$col1[] = $x;
$col2[] = array_sum($y);
}
In the end you will end up with this
plaintext?php
$data = array(
array(52, 'ARMENIA'),
array(215, 'CANADA'),
array(57, 'CANADA'),
array(261, 'COLOMBIA'),
array(53, 'EGYPT'),
array(62, 'INDIA'),
array(50, 'INDIA'),
);
foreach ( $data AS $row )
{
$group[$row[1]][] = $row[0];
}
print_r($group);
foreach ( $group AS $x = $y )
{
$col1[] = $x;
$col2[] = array_sum($y);
}
print_r($col1);
print_r($col2);
--
Jim Lucas
Some men are born to greatness, some achieve greatness,
and some have greatness thrust upon them.
Twelfth Night, Act II, Scene V
by William Shakespeare
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Array group and sum values.
On Tue, May 11, 2010 at 4:03 PM, Jim Lucas li...@cmsws.com wrote:
Paul Halliday wrote:
On Tue, May 11, 2010 at 2:25 PM, Jim Lucas li...@cmsws.com wrote:
Paul Halliday wrote:
I have this:
while ($row = mysql_fetch_array($theData[0])) {
$col1[] = $row[0];
$col2[] = lookup($row[1]); // this goes off and gets the country name.
I then loop through col1 and col2 to produce something like this:
52 ARMENIA
215 CANADA
57 CANADA
261 COLOMBIA
53 EGYPT
62 INDIA
50 INDIA
Is there a way I can group these?
Thanks!
Group them??
How about this
while ($row = mysql_fetch_array($theData[0])) {
$col1[lookup($row[1])][] = $row[0];
which, using the data you showed, will give you this
Array
(
[ARMENIA] = Array
(
[0] = 52
)
[CANADA] = Array
(
[0] = 215
[1] = 57
)
[COLOMBIA] = Array
(
[0] = 261
)
[EGYPT] = Array
(
[0] = 53
)
[INDIA] = Array
(
[0] = 62
[1] = 50
)
)
--
Jim Lucas
Some men are born to greatness, some achieve greatness,
and some have greatness thrust upon them.
Twelfth Night, Act II, Scene V
by William Shakespeare
I was actually hoping to have them arranged like:
$col1[0] = INDIA
$col2[0] = 112
$col1[1] = CANADA
$col2[1] = 272
...
Thanks.
Well, then take what I gave you and do this:
$group[lookup($row[1])][] = $row[0];
foreach ( $group AS $x = $y )
{
$col1[] = $x;
$col2[] = array_sum($y);
}
In the end you will end up with this
plaintext?php
$data = array(
array(52, 'ARMENIA'),
array(215, 'CANADA'),
array(57, 'CANADA'),
array(261, 'COLOMBIA'),
array(53, 'EGYPT'),
array(62, 'INDIA'),
array(50, 'INDIA'),
);
foreach ( $data AS $row )
{
$group[$row[1]][] = $row[0];
}
print_r($group);
foreach ( $group AS $x = $y )
{
$col1[] = $x;
$col2[] = array_sum($y);
}
print_r($col1);
print_r($col2);
Perfect! and a lot simpler than I thought.
Thanks.
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Re: [PHP] Array group and sum values.
On 05/11/2010 02:17 PM, Paul Halliday wrote:
On Tue, May 11, 2010 at 4:03 PM, Jim Lucas li...@cmsws.com wrote:
Paul Halliday wrote:
On Tue, May 11, 2010 at 2:25 PM, Jim Lucas li...@cmsws.com wrote:
Paul Halliday wrote:
I have this:
while ($row = mysql_fetch_array($theData[0])) {
$col1[] = $row[0];
$col2[] = lookup($row[1]); // this goes off and gets the country name.
I then loop through col1 and col2 to produce something like this:
52ARMENIA
215 CANADA
57CANADA
261 COLOMBIA
53EGYPT
62INDIA
50INDIA
Is there a way I can group these?
Thanks!
Group them??
How about this
while ($row = mysql_fetch_array($theData[0])) {
$col1[lookup($row[1])][] = $row[0];
which, using the data you showed, will give you this
Array
(
[ARMENIA] = Array
(
[0] = 52
)
[CANADA] = Array
(
[0] = 215
[1] = 57
)
[COLOMBIA] = Array
(
[0] = 261
)
[EGYPT] = Array
(
[0] = 53
)
[INDIA] = Array
(
[0] = 62
[1] = 50
)
)
--
Jim Lucas
Some men are born to greatness, some achieve greatness,
and some have greatness thrust upon them.
Twelfth Night, Act II, Scene V
by William Shakespeare
I was actually hoping to have them arranged like:
$col1[0] = INDIA
$col2[0] = 112
$col1[1] = CANADA
$col2[1] = 272
...
Thanks.
I would probably do this:
$col1 = $col2 = array();
while ($row = mysql_fetch_array($theData[0])) {
$country = lookup($row[1]);
if(($found = array_search($country, $col1)) !== false) {
$col2[$found] += $row[0];
} else {
$col1[] = $country;
$col2[] = $row[0];
}
}
--
Thanks!
-Shawn
http://www.spidean.com
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Re: [PHP] Array group and sum values.
On 05/11/2010 04:09 PM, Shawn McKenzie wrote:
On 05/11/2010 02:17 PM, Paul Halliday wrote:
On Tue, May 11, 2010 at 4:03 PM, Jim Lucas li...@cmsws.com wrote:
Paul Halliday wrote:
On Tue, May 11, 2010 at 2:25 PM, Jim Lucas li...@cmsws.com wrote:
Paul Halliday wrote:
I have this:
while ($row = mysql_fetch_array($theData[0])) {
$col1[] = $row[0];
$col2[] = lookup($row[1]); // this goes off and gets the country
name.
I then loop through col1 and col2 to produce something like this:
52ARMENIA
215 CANADA
57CANADA
261 COLOMBIA
53EGYPT
62INDIA
50INDIA
Is there a way I can group these?
Thanks!
Group them??
How about this
while ($row = mysql_fetch_array($theData[0])) {
$col1[lookup($row[1])][] = $row[0];
which, using the data you showed, will give you this
Array
(
[ARMENIA] = Array
(
[0] = 52
)
[CANADA] = Array
(
[0] = 215
[1] = 57
)
[COLOMBIA] = Array
(
[0] = 261
)
[EGYPT] = Array
(
[0] = 53
)
[INDIA] = Array
(
[0] = 62
[1] = 50
)
)
--
Jim Lucas
Some men are born to greatness, some achieve greatness,
and some have greatness thrust upon them.
Twelfth Night, Act II, Scene V
by William Shakespeare
I was actually hoping to have them arranged like:
$col1[0] = INDIA
$col2[0] = 112
$col1[1] = CANADA
$col2[1] = 272
...
Thanks.
I would probably do this:
$col1 = $col2 = array();
while ($row = mysql_fetch_array($theData[0])) {
$country = lookup($row[1]);
if(($found = array_search($country, $col1)) !== false) {
$col2[$found] += $row[0];
} else {
$col1[] = $country;
$col2[] = $row[0];
}
}
Although I myself would prefer it to be in this format:
$result = array();
foreach($rows as $row) {
$country = lookup($row[1]);
if(isset($result[$country])) {
$result[$country] += $row[0];
} else {
$result[$country] = $row[0];
}
}
Which would give:
array
(
INDIA = 112
CANADA = 272
//etc...
)
Then to use, just:
foreach($result as $country = $value) {
echo $country . ' ' . $value; // or whatever
}
--
Thanks!
-Shawn
http://www.spidean.com
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[PHP] Array to csv or excel in php
hallo there everyone.. i got an array from my database Help with Code Tagshttp://www.daniweb.com/forums/misc-explaincode.html?TB_iframe=trueheight=400width=680 *PHP Syntax* (Toggle Plain Texthttp://www.daniweb.com/forums/post1194347.html# ) 1. $save=split([|;],$listOfItems); and what i want i s after making some changes to the attributes on the array above to export them on an csv or excel format but directly as a message to the browser .. i dont want it to be saved on the server ... what i cant understand from the examples i found on the net .. is how to handle the files and which are created cause i just have the array in a php file nothing more... another thing i have in mind is to export from the ldap server the files directly but seems to me as the wrong way to do it thanks
Re: [PHP] Array to csv or excel in php
On Mon, Apr 19, 2010 at 9:45 AM, Manolis Vlachakis
vlachakis.mano...@gmail.com wrote:
hallo there everyone..
i got an array from my database
Help with Code
Tagshttp://www.daniweb.com/forums/misc-explaincode.html?TB_iframe=trueheight=400width=680
*PHP Syntax* (Toggle Plain
Texthttp://www.daniweb.com/forums/post1194347.html#
)
1. $save=split([|;],$listOfItems);
and what i want i s after making some changes to the attributes on the array
above to export them on an csv or excel format
but directly as a message to the browser ..
i dont want it to be saved on the server ...
what i cant understand from the examples i found on the net ..
is how to handle the files and which are created cause
i just have the array in a php file nothing more...
another thing i have in mind is to export from the ldap server the files
directly but seems to me as the wrong way to do it
thanks
Often when outputting csv, I usually do something like this:
?php
$fp = fopen('php://output', 'w') or die('Could not open stream');
foreach ($data as $row) {
// Assumes that $row will be an array.
// Manipulate the data in $row if necessary.
fputcsv($fp, $row);
}
?
So far, it has worked pretty well and is much faster than any other
way I have found to output the CSV data by iterating through the
arrays manually.
Andrew
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Re: [PHP] Array to csv or excel in php
On 19 April 2010 17:00, Andrew Ballard aball...@gmail.com wrote:
On Mon, Apr 19, 2010 at 9:45 AM, Manolis Vlachakis
vlachakis.mano...@gmail.com wrote:
hallo there everyone..
i got an array from my database
Help with Code
Tagshttp://www.daniweb.com/forums/misc-explaincode.html?TB_iframe=trueheight=400width=680
*PHP Syntax* (Toggle Plain
Texthttp://www.daniweb.com/forums/post1194347.html#
)
1. $save=split([|;],$listOfItems);
and what i want i s after making some changes to the attributes on the array
above to export them on an csv or excel format
but directly as a message to the browser ..
i dont want it to be saved on the server ...
what i cant understand from the examples i found on the net ..
is how to handle the files and which are created cause
i just have the array in a php file nothing more...
another thing i have in mind is to export from the ldap server the files
directly but seems to me as the wrong way to do it
thanks
Often when outputting csv, I usually do something like this:
?php
$fp = fopen('php://output', 'w') or die('Could not open stream');
foreach ($data as $row) {
// Assumes that $row will be an array.
// Manipulate the data in $row if necessary.
fputcsv($fp, $row);
}
?
An interesting idea. I'd do:
echo implode(',', $row);
regards
Peter
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Re: [PHP] Array to csv or excel in php
On Mon, Apr 19, 2010 at 11:14 AM, Peter Lind peter.e.l...@gmail.com wrote:
On 19 April 2010 17:00, Andrew Ballard aball...@gmail.com wrote:
On Mon, Apr 19, 2010 at 9:45 AM, Manolis Vlachakis
1. $save=split([|;],$listOfItems);
and what i want i s after making some changes to the attributes on the array
above to export them on an csv or excel format
but directly as a message to the browser ..
i dont want it to be saved on the server ...
Often when outputting csv, I usually do something like this:
?php
$fp = fopen('php://output', 'w') or die('Could not open stream');
foreach ($data as $row) {
// Assumes that $row will be an array.
// Manipulate the data in $row if necessary.
fputcsv($fp, $row);
}
?
An interesting idea. I'd do:
echo implode(',', $row);
If it's very simple data that works, but it doesn't allow for the
optional enclosure characters that fputcsv() uses in cases where a
data element includes the column and/or row delimiter characters. I
had originally written something using an array_map callback that did
the optional enclosures as needed and then used echo implode() as you
suggest, but found the solution I posted was shorter and faster. YMMV
Andrew
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Re: [PHP] Array to csv or excel in php
On 19 April 2010 17:40, Andrew Ballard aball...@gmail.com wrote:
On Mon, Apr 19, 2010 at 11:14 AM, Peter Lind peter.e.l...@gmail.com wrote:
On 19 April 2010 17:00, Andrew Ballard aball...@gmail.com wrote:
On Mon, Apr 19, 2010 at 9:45 AM, Manolis Vlachakis
1. $save=split([|;],$listOfItems);
and what i want i s after making some changes to the attributes on the
array
above to export them on an csv or excel format
but directly as a message to the browser ..
i dont want it to be saved on the server ...
Often when outputting csv, I usually do something like this:
?php
$fp = fopen('php://output', 'w') or die('Could not open stream');
foreach ($data as $row) {
// Assumes that $row will be an array.
// Manipulate the data in $row if necessary.
fputcsv($fp, $row);
}
?
An interesting idea. I'd do:
echo implode(',', $row);
If it's very simple data that works, but it doesn't allow for the
optional enclosure characters that fputcsv() uses in cases where a
data element includes the column and/or row delimiter characters. I
had originally written something using an array_map callback that did
the optional enclosures as needed and then used echo implode() as you
suggest, but found the solution I posted was shorter and faster. YMMV
Andrew
Yeah, was considering that point as well. I'd use the echo if the
array values are getting modified anyway. Otherwise your solution is
probably simpler.
Regards
Peter
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Re: [PHP] Array to csv or excel in php
For non-simple data I have been using PEAR's File_CSV package. It's
proven itself very useful in
regards to not having to determine in my own code whether something
needs to be quoted etc etc - especially if the output CSV needs to be
wholly RFC 4180 compliant.
The documentation of it is rather minimal - at the moment you are
dependant on the test/example files and the API docs but grokking how
to use it is rather easy.
k.
On Mon, Apr 19, 2010 at 4:40 PM, Andrew Ballard aball...@gmail.com wrote:
On Mon, Apr 19, 2010 at 11:14 AM, Peter Lind peter.e.l...@gmail.com wrote:
On 19 April 2010 17:00, Andrew Ballard aball...@gmail.com wrote:
On Mon, Apr 19, 2010 at 9:45 AM, Manolis Vlachakis
1. $save=split([|;],$listOfItems);
and what i want i s after making some changes to the attributes on the
array
above to export them on an csv or excel format
but directly as a message to the browser ..
i dont want it to be saved on the server ...
Often when outputting csv, I usually do something like this:
?php
$fp = fopen('php://output', 'w') or die('Could not open stream');
foreach ($data as $row) {
// Assumes that $row will be an array.
// Manipulate the data in $row if necessary.
fputcsv($fp, $row);
}
?
An interesting idea. I'd do:
echo implode(',', $row);
If it's very simple data that works, but it doesn't allow for the
optional enclosure characters that fputcsv() uses in cases where a
data element includes the column and/or row delimiter characters. I
had originally written something using an array_map callback that did
the optional enclosures as needed and then used echo implode() as you
suggest, but found the solution I posted was shorter and faster. YMMV
Andrew
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RE: [PHP] Array to csv or excel in php
[snip] to export them on an csv or excel format[/snip] Stupid browser tricks http://www.evolt.org/node/26896 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Array differences
On Tue, 2010-04-13 at 23:01 -0600, Ashley M. Kirchner wrote: I have the following scenario: $array1 = array(12, 34, 56, 78, 90); $array2 = array(12, 23, 56, 78, 89); $result = array_diff($array1, $array2); print_r($result); This returns: Array ( [1] = 34 [4] = 90 ) However what I really want is a two-way comparison. I want elements that don't exist in either to be returned: 34 and 90 because they don't exist in $array2, AND 23 and 89 because they don't exist in $array1. So, is that a two step process of first doing an array_diff($array1, $array2) then reverse it by doing array_diff($array2, $array1) and merge/unique the results? Any caveats with that? $array1 = array(12, 34, 56, 78, 90); $array2 = array(12, 23, 56, 78, 89); $diff1 = array_diff($array1, $array2); $diff2 = array_diff($array2, $array1); $result = array_unique(array_merge($diff1, $diff2)); print_r($result); -- A I don't see any problems with doing it that way. This will only work as you intended if both arrays have the same number of elements I believe, otherwise you might end up with a situation where your final array has duplicates of the same number: $array1 = $array(1, 2, 3, 4, 5, 6); $array2 = $aray(1, 3, 2, 5); Thanks, Ash http://www.ashleysheridan.co.uk
Re: [PHP] Array differences
Ashley Sheridan wrote: On Tue, 2010-04-13 at 23:01 -0600, Ashley M. Kirchner wrote: However what I really want is a two-way comparison. I want elements that don't exist in either to be returned: I don't see any problems with doing it that way. By some freak chance I made an array diff class about 2 weeks ago which covers what you need. attached :) usage: $diff = new ArrayDiff( $old , $new ); $diff-l; // deleted items $diff-r; // inserted items $diff-u; // unchanged items The script is optimised for huge arrays, thus it's slower for small arrays than the usual array_diff but with large arrays it's quicker. Regards Nathan -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Array differences
On Wed, Apr 14, 2010 at 12:03 PM, Nathan Rixham nrix...@gmail.com wrote: Ashley Sheridan wrote: On Tue, 2010-04-13 at 23:01 -0600, Ashley M. Kirchner wrote: However what I really want is a two-way comparison. I want elements that don't exist in either to be returned: I don't see any problems with doing it that way. By some freak chance I made an array diff class about 2 weeks ago which covers what you need. attached :) usage: $diff = new ArrayDiff( $old , $new ); $diff-l; // deleted items $diff-r; // inserted items $diff-u; // unchanged items The script is optimised for huge arrays, thus it's slower for small arrays than the usual array_diff but with large arrays it's quicker. Regards Nathan -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php nice one :) i'll put it in a work-preperation folder for htmlMicroscope then, one of these days :) -- - Greetings from Rene7705, I have made some free open source webcomponents designed and written by me available through: http://code.google.com/u/rene7705/ , or http://mediabeez.ws (latest dev versions, currently offline) Personal info about me is available through http://www.facebook.com/rene7705 - -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Array differences
On 4/14/2010 2:39 AM, Ashley Sheridan wrote: On Tue, 2010-04-13 at 23:01 -0600, Ashley M. Kirchner wrote: $array1 = array(12, 34, 56, 78, 90); $array2 = array(12, 23, 56, 78, 89); $diff1 = array_diff($array1, $array2); $diff2 = array_diff($array2, $array1); $result = array_unique(array_merge($diff1, $diff2)); print_r($result); I don't see any problems with doing it that way. This will only work as you intended if both arrays have the same number of elements I believe, otherwise you might end up with a situation where your final array has duplicates of the same number: $array1 = $array(1, 2, 3, 4, 5, 6); $array2 = $aray(1, 3, 2, 5); Wouldn't array_unique() take care of that though? Your example above returns 4 and 6, which would be correct. A -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Array differences
Maybe this one works? array_diff(array_unique($array1 + $array2), array_intersect($array1, $array2)) On Wed, Apr 14, 2010 at 4:39 AM, Ashley Sheridan a...@ashleysheridan.co.uk wrote: On Tue, 2010-04-13 at 23:01 -0600, Ashley M. Kirchner wrote: I have the following scenario: $array1 = array(12, 34, 56, 78, 90); $array2 = array(12, 23, 56, 78, 89); $result = array_diff($array1, $array2); print_r($result); This returns: Array ( [1] = 34 [4] = 90 ) However what I really want is a two-way comparison. I want elements that don't exist in either to be returned: 34 and 90 because they don't exist in $array2, AND 23 and 89 because they don't exist in $array1. So, is that a two step process of first doing an array_diff($array1, $array2) then reverse it by doing array_diff($array2, $array1) and merge/unique the results? Any caveats with that? $array1 = array(12, 34, 56, 78, 90); $array2 = array(12, 23, 56, 78, 89); $diff1 = array_diff($array1, $array2); $diff2 = array_diff($array2, $array1); $result = array_unique(array_merge($diff1, $diff2)); print_r($result); -- A I don't see any problems with doing it that way. This will only work as you intended if both arrays have the same number of elements I believe, otherwise you might end up with a situation where your final array has duplicates of the same number: $array1 = $array(1, 2, 3, 4, 5, 6); $array2 = $aray(1, 3, 2, 5); Thanks, Ash http://www.ashleysheridan.co.uk -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Array differences
No because that only does a one-way comparison. It only tells me what's missing from $array2. I need it from both arrays. That's why I'm comparing 1 versus 2, then 2 versus 1, and then doing a merge/unique on the result. $array1 = array(1, 2, 3, 4, 5, 6); $array2 = array(1, 3, 2, 8, 9); $result = array_diff(array_unique($array1 + $array2), array_intersect($array1, $array2)); = (4, 5, 6) Versus: $array1 = array(1, 2, 3, 4, 5, 6); $array2 = array(1, 3, 2, 8, 9); $diff1 = array_diff($array1, $array2); $diff2 = array_diff($array2, $array1); $result = array_unique(array_merge($diff1, $diff2)); = (4, 5, 6, 8, 9) This second $result is what I want. So far I haven't noticed any problems doing it this way ... yet. I'm sure someone will tell me otherwise. Ash -Original Message- From: Ryan Sun [mailto:ryansu...@gmail.com] Sent: Wednesday, April 14, 2010 8:45 AM To: a...@ashleysheridan.co.uk Cc: Ashley M. Kirchner; php-general@lists.php.net Subject: Re: [PHP] Array differences Maybe this one works? array_diff(array_unique($array1 + $array2), array_intersect($array1, $array2)) On Wed, Apr 14, 2010 at 4:39 AM, Ashley Sheridan a...@ashleysheridan.co.uk wrote: On Tue, 2010-04-13 at 23:01 -0600, Ashley M. Kirchner wrote: I have the following scenario: $array1 = array(12, 34, 56, 78, 90); $array2 = array(12, 23, 56, 78, 89); $result = array_diff($array1, $array2); print_r($result); This returns: Array ( [1] = 34 [4] = 90 ) However what I really want is a two-way comparison. I want elements that don't exist in either to be returned: 34 and 90 because they don't exist in $array2, AND 23 and 89 because they don't exist in $array1. So, is that a two step process of first doing an array_diff($array1, $array2) then reverse it by doing array_diff($array2, $array1) and merge/unique the results? Any caveats with that? $array1 = array(12, 34, 56, 78, 90); $array2 = array(12, 23, 56, 78, 89); $diff1 = array_diff($array1, $array2); $diff2 = array_diff($array2, $array1); $result = array_unique(array_merge($diff1, $diff2)); print_r($result); -- A I don't see any problems with doing it that way. This will only work as you intended if both arrays have the same number of elements I believe, otherwise you might end up with a situation where your final array has duplicates of the same number: $array1 = $array(1, 2, 3, 4, 5, 6); $array2 = $aray(1, 3, 2, 5); Thanks, Ash http://www.ashleysheridan.co.uk -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Array differences
Ashley M. Kirchner wrote: $array1 = array(1, 2, 3, 4, 5, 6); $array2 = array(1, 3, 2, 8, 9); $diff1 = array_diff($array1, $array2); $diff2 = array_diff($array2, $array1); $result = array_unique(array_merge($diff1, $diff2)); = (4, 5, 6, 8, 9) Hi Ash, Isn't the array_unique() unnecessary? Mike -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Array differences
-Original Message- From: lala [mailto:l...@mail.theorb.net] Sent: Wednesday, April 14, 2010 10:15 AM To: Ashley M. Kirchner Cc: php-general@lists.php.net Subject: Re: [PHP] Array differences Ashley M. Kirchner wrote: $array1 = array(1, 2, 3, 4, 5, 6); $array2 = array(1, 3, 2, 8, 9); $diff1 = array_diff($array1, $array2); $diff2 = array_diff($array2, $array1); $result = array_unique(array_merge($diff1, $diff2)); = (4, 5, 6, 8, 9) Hi Ash, Isn't the array_unique() unnecessary? Mike Thinking about it, it should be unnecessary, but at the same time I want to absolutely sure that I get unique values out of the two diffs. Ash -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Array differences
I have the following scenario: $array1 = array(12, 34, 56, 78, 90); $array2 = array(12, 23, 56, 78, 89); $result = array_diff($array1, $array2); print_r($result); This returns: Array ( [1] = 34 [4] = 90 ) However what I really want is a two-way comparison. I want elements that don't exist in either to be returned: 34 and 90 because they don't exist in $array2, AND 23 and 89 because they don't exist in $array1. So, is that a two step process of first doing an array_diff($array1, $array2) then reverse it by doing array_diff($array2, $array1) and merge/unique the results? Any caveats with that? $array1 = array(12, 34, 56, 78, 90); $array2 = array(12, 23, 56, 78, 89); $diff1 = array_diff($array1, $array2); $diff2 = array_diff($array2, $array1); $result = array_unique(array_merge($diff1, $diff2)); print_r($result); -- A
Re: [PHP] Array differences
On Wed, Apr 14, 2010 at 7:01 AM, Ashley M. Kirchner ash...@pcraft.com wrote: I have the following scenario: $array1 = array(12, 34, 56, 78, 90); $array2 = array(12, 23, 56, 78, 89); $result = array_diff($array1, $array2); print_r($result); This returns: Array ( [1] = 34 [4] = 90 ) However what I really want is a two-way comparison. I want elements that don't exist in either to be returned: 34 and 90 because they don't exist in $array2, AND 23 and 89 because they don't exist in $array1. So, is that a two step process of first doing an array_diff($array1, $array2) then reverse it by doing array_diff($array2, $array1) and merge/unique the results? Any caveats with that? $array1 = array(12, 34, 56, 78, 90); $array2 = array(12, 23, 56, 78, 89); $diff1 = array_diff($array1, $array2); $diff2 = array_diff($array2, $array1); $result = array_unique(array_merge($diff1, $diff2)); print_r($result); -- A ok, adding this to the todo-list for htmlMicroscope... ETA on delivery of 1.3.0-final: about 2 to 3 months i'm afraid. Gotta get a new laundromat for my home too and stuff like that :) -- - Greetings from Rene7705, I have made some free open source webcomponents designed and written by me available through: http://code.google.com/u/rene7705/ , or http://mediabeez.ws (latest dev versions, currently offline) Personal info about me is available through http://www.facebook.com/rene7705 - -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] array or list of objects of different types
Hi all, I want to be able to have an array of elements of different types. As an example: the first element is a boolean, the second is an integer, and the thirs is a string. In php there is no typing, i'm just wondering if there is a way to have that, it would be a lot better than having an array of strings and have to convert each element. Thank you __ The new Internet Explorer® 8 - Faster, safer, easier. Optimized for Yahoo! Get it Now for Free! at http://downloads.yahoo.com/ca/internetexplorer/
RE: [PHP] Array Search Problem
Hi,
At the time when I am writing this, looks like I already got the functions I
needed. It turned out that I had to use some array_combine, sorting the items
by keys instead of values as well as using array_keys to get the values I
needed.
Thanks for pointing me towards the right direction.
Alice
From: rene7...@gmail.com
Date: Thu, 11 Mar 2010 07:12:15 +0100
Subject: Re: [PHP] Array Search Problem
To: aj...@alumni.iu.edu
CC: php-general@lists.php.net
(almost) all the tricks are in the comments of the help page for a
function, on php.net
but all functions accept only a given (and usually documented) set of
parameter(type)s, so you'll probably have to prepare the var, or even
call the function in a loop, outputting to yet another descriptively
named array that'll be used as wanted list later in the code.
On Wed, Mar 10, 2010 at 6:57 PM, Alice Wei aj...@alumni.iu.edu wrote:
did you read the help for those functions on php.net?
Yes, I found a recursive way to find out the index like I wanted, by
doing something like
$from = explode(-, $from);
$state_colors= explode(-, $state_colors);
$change = explode(-,$change);
$count = count($new_array);
$i=0;
foreach ($new_array as $key = $value){
echo $i . . $key . is . $value . miles awaybr /;
$i++;
}
You can see it is not very elegant, and plus, I created the $new_array so I
could do the ordering according to the values of the change array. I can
tell that since this is not a single array, which is probably why
array_search does not work.
Since I don't need the value of my new_array here, I am still finding
out how to strip off the values here without having to flatten my array.
Is what I am trying to do here possible? Or, is there a trick in
array_search that I could use to find the index without having to strip off
anything?
Thanks for your help.
Alice
On Wed, Mar 10, 2010 at 4:12 PM, Alice Wei aj...@alumni.iu.edu wrote:
Hi,
I have the code as shown in the following that I am trying to create
the image of based on the file loaded into the file and additional edits.
The problem here appears to be that no matter what value I have in the
$distance_to_destination variable, it does not affect any changes on the
map. What I am trying to do here is to create a map based on the
pre-passed
through colors of individual states from another program, but I have to
match up the colors based on the values of the correct states.
I figured that I may have problems with
$key= array_search($location2,$from); //Find out the position of the
index in the array
$colors_style = ;fill: . $state_colors[$key]; //Use the index from
array_search to apply to the color index
Obviously, it is not applying the colors to the states that I would like
other than doing it one by one as the order of what is in the $from
variable. Could someone please give me some hints on how I could do the
array_search here based on the value of the values in the
$distance_to_distance and apply the color to the states?
?php
header(Content-type: image/svg+xml); //Outputting an SVG
$from = $_GET['from'];
$state_colors= $_GET['state_colors'];
$distance_to_destination= $_GET['distance_to_destination'];
$from = explode(-, $from);
$state_colors= explode(-, $state_colors);
$change = explode(-,$change);
#Load the Map
$ourFileName= USA_Counties_with_FIPS_and_names.svg;
$fh = fopen($ourFileName, r) or die(Can't open file);
$contents = fread($fh,filesize($ourFileName));
$lines2= file($ourFileName);
foreach ($lines2 as $line_num = $line2) {
$style_line_num = $line_num+3;
$line2 = trim($line2);
if(preg_match(/^style/,$line2)) {
$rest = substr($line2,0,-1);
for ($j=$line_num;$j=$style_line_num;$j++){
if(preg_match(/inkscape:label/,$lines2[$j])) {
$location = explode(=,$lines2[$j]);
$location2 = substr($location[1],1,-6);
if(in_array($location2, $from)) {
$key= array_search($location2,$from); //Find out the
position of the index in the array
$colors_style = ;fill: . $state_colors[$key]; //Use the
index from array_search to apply to the color index
$rest2 = substr($line2,0,-1). $colors_style . \;
echo $rest2 . \n;
}
else echo $line2 . \n;
} //end preg_match inkscape
} //end for loop
} //If preg_match style
else echo $line2 . \n; //else if preg_match style
} //end for each
fclose($fh);
?
Thanks for your help.
Alice
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[PHP] Array Search Problem
Hi,
I have the code as shown in the following that I am trying to create the
image of based on the file loaded into the file and additional edits. The
problem here appears to be that no matter what value I have in the
$distance_to_destination variable, it does not affect any changes on the map.
What I am trying to do here is to create a map based on the pre-passed through
colors of individual states from another program, but I have to match up the
colors based on the values of the correct states.
I figured that I may have problems with
$key= array_search($location2,$from); //Find out the position of the index
in the array
$colors_style = ;fill: . $state_colors[$key]; //Use the index from
array_search to apply to the color index
Obviously, it is not applying the colors to the states that I would like other
than doing it one by one as the order of what is in the $from variable. Could
someone please give me some hints on how I could do the array_search here based
on the value of the values in the $distance_to_distance and apply the color
to the states?
?php
header(Content-type: image/svg+xml); //Outputting an SVG
$from = $_GET['from'];
$state_colors= $_GET['state_colors'];
$distance_to_destination= $_GET['distance_to_destination'];
$from = explode(-, $from);
$state_colors= explode(-, $state_colors);
$change = explode(-,$change);
#Load the Map
$ourFileName= USA_Counties_with_FIPS_and_names.svg;
$fh = fopen($ourFileName, r) or die(Can't open file);
$contents = fread($fh,filesize($ourFileName));
$lines2= file($ourFileName);
foreach ($lines2 as $line_num = $line2) {
$style_line_num = $line_num+3;
$line2 = trim($line2);
if(preg_match(/^style/,$line2)) {
$rest = substr($line2,0,-1);
for ($j=$line_num;$j=$style_line_num;$j++){
if(preg_match(/inkscape:label/,$lines2[$j])) {
$location = explode(=,$lines2[$j]);
$location2 = substr($location[1],1,-6);
if(in_array($location2, $from)) {
$key= array_search($location2,$from); //Find out the position of
the index in the array
$colors_style = ;fill: . $state_colors[$key]; //Use the index
from array_search to apply to the color index
$rest2 = substr($line2,0,-1). $colors_style . \;
echo $rest2 . \n;
}
else echo $line2 . \n;
} //end preg_match inkscape
} //end for loop
} //If preg_match style
else echo $line2 . \n; //else if preg_match style
} //end for each
fclose($fh);
?
Thanks for your help.
Alice
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[PHP] Array Search Not Working?
Hi,
I have two arrays here that I have combined into a new array, as shown here:
$from = explode(-, $from);
$change = explode(-,$change);
$new_array = array_combine($from,$change);
I then tried reading it from a file and do string matches, trying to find out
the key using the array_search of the individual array elements. I seem to
have no such luck, even when I copied one of the elements after I do a
print_r($new_array);
Here is the code,
foreach ($lines2 as $line_num = $line2) {
$style_line_num = $line_num+3;
if(preg_match(/^style/,$line2)) {
if(preg_match(/inkscape:label/,$lines2[$style_line_num])) {
$location = explode(=,$lines2[$style_line_num]);
$location2 = substr($patient_location[1],1,-6);
if(in_array($location2, $from)) {
$key= array_search($location2,$new_array); //Find out the position
of the index in the array
echo Key . $key . br; //This only gives me a blank space
after the word Key
}
} //end preg_match inkscape
} //If preg_match style
I looked at the example from
http://php.net/manual/en/function.array-search.php, and looks like what I am
trying to do here is possible, and yet, why am I not getting a proper key
return?
Thanks for your help.
Alice
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Re: [PHP] Array Search Problem
did you read the help for those functions on php.net?
On Wed, Mar 10, 2010 at 4:12 PM, Alice Wei aj...@alumni.iu.edu wrote:
Hi,
I have the code as shown in the following that I am trying to create the
image of based on the file loaded into the file and additional edits. The
problem here appears to be that no matter what value I have in the
$distance_to_destination variable, it does not affect any changes on the map.
What I am trying to do here is to create a map based on the pre-passed
through colors of individual states from another program, but I have to match
up the colors based on the values of the correct states.
I figured that I may have problems with
$key= array_search($location2,$from); //Find out the position of the index
in the array
$colors_style = ;fill: . $state_colors[$key]; //Use the index from
array_search to apply to the color index
Obviously, it is not applying the colors to the states that I would like
other than doing it one by one as the order of what is in the $from variable.
Could someone please give me some hints on how I could do the array_search
here based on the value of the values in the $distance_to_distance and
apply the color to the states?
?php
header(Content-type: image/svg+xml); //Outputting an SVG
$from = $_GET['from'];
$state_colors= $_GET['state_colors'];
$distance_to_destination= $_GET['distance_to_destination'];
$from = explode(-, $from);
$state_colors= explode(-, $state_colors);
$change = explode(-,$change);
#Load the Map
$ourFileName= USA_Counties_with_FIPS_and_names.svg;
$fh = fopen($ourFileName, r) or die(Can't open file);
$contents = fread($fh,filesize($ourFileName));
$lines2= file($ourFileName);
foreach ($lines2 as $line_num = $line2) {
$style_line_num = $line_num+3;
$line2 = trim($line2);
if(preg_match(/^style/,$line2)) {
$rest = substr($line2,0,-1);
for ($j=$line_num;$j=$style_line_num;$j++){
if(preg_match(/inkscape:label/,$lines2[$j])) {
$location = explode(=,$lines2[$j]);
$location2 = substr($location[1],1,-6);
if(in_array($location2, $from)) {
$key= array_search($location2,$from); //Find out the position of
the index in the array
$colors_style = ;fill: . $state_colors[$key]; //Use the index
from array_search to apply to the color index
$rest2 = substr($line2,0,-1). $colors_style . \;
echo $rest2 . \n;
}
else echo $line2 . \n;
} //end preg_match inkscape
} //end for loop
} //If preg_match style
else echo $line2 . \n; //else if preg_match style
} //end for each
fclose($fh);
?
Thanks for your help.
Alice
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RE: [PHP] Array Search Problem
did you read the help for those functions on php.net?
Yes, I found a recursive way to find out the index like I wanted, by doing
something like
$from = explode(-, $from);
$state_colors= explode(-, $state_colors);
$change = explode(-,$change);
$count = count($new_array);
$i=0;
foreach ($new_array as $key = $value){
echo $i . . $key . is . $value . miles awaybr /;
$i++;
}
You can see it is not very elegant, and plus, I created the $new_array so I
could do the ordering according to the values of the change array. I can tell
that since this is not a single array, which is probably why array_search does
not work.
Since I don't need the value of my new_array here, I am still finding out
how to strip off the values here without having to flatten my array. Is what
I am trying to do here possible? Or, is there a trick in array_search that I
could use to find the index without having to strip off anything?
Thanks for your help.
Alice
On Wed, Mar 10, 2010 at 4:12 PM, Alice Wei aj...@alumni.iu.edu wrote:
Hi,
I have the code as shown in the following that I am trying to create the
image of based on the file loaded into the file and additional edits. The
problem here appears to be that no matter what value I have in the
$distance_to_destination variable, it does not affect any changes on the
map. What I am trying to do here is to create a map based on the pre-passed
through colors of individual states from another program, but I have to
match up the colors based on the values of the correct states.
I figured that I may have problems with
$key= array_search($location2,$from); //Find out the position of the
index in the array
$colors_style = ;fill: . $state_colors[$key]; //Use the index from
array_search to apply to the color index
Obviously, it is not applying the colors to the states that I would like
other than doing it one by one as the order of what is in the $from
variable. Could someone please give me some hints on how I could do the
array_search here based on the value of the values in the
$distance_to_distance and apply the color to the states?
?php
header(Content-type: image/svg+xml); //Outputting an SVG
$from = $_GET['from'];
$state_colors= $_GET['state_colors'];
$distance_to_destination= $_GET['distance_to_destination'];
$from = explode(-, $from);
$state_colors= explode(-, $state_colors);
$change = explode(-,$change);
#Load the Map
$ourFileName= USA_Counties_with_FIPS_and_names.svg;
$fh = fopen($ourFileName, r) or die(Can't open file);
$contents = fread($fh,filesize($ourFileName));
$lines2= file($ourFileName);
foreach ($lines2 as $line_num = $line2) {
$style_line_num = $line_num+3;
$line2 = trim($line2);
if(preg_match(/^style/,$line2)) {
$rest = substr($line2,0,-1);
for ($j=$line_num;$j=$style_line_num;$j++){
if(preg_match(/inkscape:label/,$lines2[$j])) {
$location = explode(=,$lines2[$j]);
$location2 = substr($location[1],1,-6);
if(in_array($location2, $from)) {
$key= array_search($location2,$from); //Find out the position
of the index in the array
$colors_style = ;fill: . $state_colors[$key]; //Use the
index from array_search to apply to the color index
$rest2 = substr($line2,0,-1). $colors_style . \;
echo $rest2 . \n;
}
else echo $line2 . \n;
} //end preg_match inkscape
} //end for loop
} //If preg_match style
else echo $line2 . \n; //else if preg_match style
} //end for each
fclose($fh);
?
Thanks for your help.
Alice
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Re: [PHP] Array Search Problem
(almost) all the tricks are in the comments of the help page for a
function, on php.net
but all functions accept only a given (and usually documented) set of
parameter(type)s, so you'll probably have to prepare the var, or even
call the function in a loop, outputting to yet another descriptively
named array that'll be used as wanted list later in the code.
On Wed, Mar 10, 2010 at 6:57 PM, Alice Wei aj...@alumni.iu.edu wrote:
did you read the help for those functions on php.net?
Yes, I found a recursive way to find out the index like I wanted, by
doing something like
$from = explode(-, $from);
$state_colors= explode(-, $state_colors);
$change = explode(-,$change);
$count = count($new_array);
$i=0;
foreach ($new_array as $key = $value){
echo $i . . $key . is . $value . miles awaybr /;
$i++;
}
You can see it is not very elegant, and plus, I created the $new_array so I
could do the ordering according to the values of the change array. I can
tell that since this is not a single array, which is probably why
array_search does not work.
Since I don't need the value of my new_array here, I am still finding
out how to strip off the values here without having to flatten my array.
Is what I am trying to do here possible? Or, is there a trick in
array_search that I could use to find the index without having to strip off
anything?
Thanks for your help.
Alice
On Wed, Mar 10, 2010 at 4:12 PM, Alice Wei aj...@alumni.iu.edu wrote:
Hi,
I have the code as shown in the following that I am trying to create
the image of based on the file loaded into the file and additional edits.
The problem here appears to be that no matter what value I have in the
$distance_to_destination variable, it does not affect any changes on the
map. What I am trying to do here is to create a map based on the pre-passed
through colors of individual states from another program, but I have to
match up the colors based on the values of the correct states.
I figured that I may have problems with
$key= array_search($location2,$from); //Find out the position of the
index in the array
$colors_style = ;fill: . $state_colors[$key]; //Use the index from
array_search to apply to the color index
Obviously, it is not applying the colors to the states that I would like
other than doing it one by one as the order of what is in the $from
variable. Could someone please give me some hints on how I could do the
array_search here based on the value of the values in the
$distance_to_distance and apply the color to the states?
?php
header(Content-type: image/svg+xml); //Outputting an SVG
$from = $_GET['from'];
$state_colors= $_GET['state_colors'];
$distance_to_destination= $_GET['distance_to_destination'];
$from = explode(-, $from);
$state_colors= explode(-, $state_colors);
$change = explode(-,$change);
#Load the Map
$ourFileName= USA_Counties_with_FIPS_and_names.svg;
$fh = fopen($ourFileName, r) or die(Can't open file);
$contents = fread($fh,filesize($ourFileName));
$lines2= file($ourFileName);
foreach ($lines2 as $line_num = $line2) {
$style_line_num = $line_num+3;
$line2 = trim($line2);
if(preg_match(/^style/,$line2)) {
$rest = substr($line2,0,-1);
for ($j=$line_num;$j=$style_line_num;$j++){
if(preg_match(/inkscape:label/,$lines2[$j])) {
$location = explode(=,$lines2[$j]);
$location2 = substr($location[1],1,-6);
if(in_array($location2, $from)) {
$key= array_search($location2,$from); //Find out the
position of the index in the array
$colors_style = ;fill: . $state_colors[$key]; //Use the
index from array_search to apply to the color index
$rest2 = substr($line2,0,-1). $colors_style . \;
echo $rest2 . \n;
}
else echo $line2 . \n;
} //end preg_match inkscape
} //end for loop
} //If preg_match style
else echo $line2 . \n; //else if preg_match style
} //end for each
fclose($fh);
?
Thanks for your help.
Alice
_
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Re: [PHP] array conversion
Or:
$a = array ('Cats', 'white', 'Dogs', 'black', 'Mice', 'grey', 'Camels',
'brown');
$b = '';// Just in case it has some leftover
value
$k = 2* (int) (count ($a)/2); // ensure even no of terms
$i = 0; while ($i $k)
{
$b[$a[$i++]] = $a[$i++]; // ***
}
And this works:
$i = 0; $k = array_keys($b);
while ($i count($b)) {echo 'h5'.$i.': '.$k[$i].' = '.
$b[$k[$i++]].'/h5'; }
0: Cats = white
1: Dogs = black
2: Mice = grey
3: Camels = brown
( *** I have always been wary of using statements like this because I was
unsure when the
incrementing would occur, so I tried it.)
Clancy
On Fri, 19 Feb 2010 02:26:49 -0500, simples...@gmail.com (Adam Richardson)
wrote:
Or,
function new_arr(array $arr)
{
$count = count($arr);
if ($count % 2 != 0) throw new Exception('The new_arr() function
requires an even number of elements.');
for ($i = 0; $i $count; $i += 2)
{
$new_arr[$arr[$i]] = $arr[$i + 1];
}
return $new_arr;
}
$test = new_arr(array('k1', 'v1', 'k2', 'v2', 'k3', 'v3'));
exit(var_dump($test));
On Fri, Feb 19, 2010 at 1:19 AM, Larry Garfield la...@garfieldtech.comwrote:
On Thursday 18 February 2010 11:58:28 pm Paul M Foster wrote:
On Fri, Feb 19, 2010 at 01:20:12PM +0800, Dasn wrote:
Hi guys. How to convert an array like:
Array
(
[0] = key1
[1] = value1
[2] = key2
[3] = value2
)
to
Array
(
[key1] = value1
[key2] = value2
)
Is there a built-in function to do this?
Please Cc me. :)
Thank you in advance.
I don't believe so, but rolling your own should not be too hard:
$a = array($key1, $value1, $key2, $value2);
$b = array();
$numitems = count($a);
for ($i = 0; $i $numitems; $i++) {
if ($i % 2 == 0) {
$saved_key = $a[$i];
}
elseif ($i % 2 == 1) {
$b[$saved_key] = $a[$i];
}
}
Code is crude and untested, but you get the idea.
Paul
This would be even shorter, I think:
foreach ($items as $i = $value) {
$temp[$i % 2][] = $value;
}
$done = array_combine($temp[0], $temp[1]);
(Also untested, just off the cuff...)
--Larry Garfield
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Re: [PHP] array conversion
On 19 February 2010 07:26, Adam Richardson simples...@gmail.com wrote:
Or,
function new_arr(array $arr)
{
$count = count($arr);
if ($count % 2 != 0) throw new Exception('The new_arr() function
requires an even number of elements.');
for ($i = 0; $i $count; $i += 2)
{
$new_arr[$arr[$i]] = $arr[$i + 1];
}
return $new_arr;
}
$test = new_arr(array('k1', 'v1', 'k2', 'v2', 'k3', 'v3'));
exit(var_dump($test));
On Fri, Feb 19, 2010 at 1:19 AM, Larry Garfield la...@garfieldtech.comwrote:
On Thursday 18 February 2010 11:58:28 pm Paul M Foster wrote:
On Fri, Feb 19, 2010 at 01:20:12PM +0800, Dasn wrote:
Hi guys. How to convert an array like:
Array
(
[0] = key1
[1] = value1
[2] = key2
[3] = value2
)
to
Array
(
[key1] = value1
[key2] = value2
)
Is there a built-in function to do this?
Please Cc me. :)
Thank you in advance.
I don't believe so, but rolling your own should not be too hard:
$a = array($key1, $value1, $key2, $value2);
$b = array();
$numitems = count($a);
for ($i = 0; $i $numitems; $i++) {
if ($i % 2 == 0) {
$saved_key = $a[$i];
}
elseif ($i % 2 == 1) {
$b[$saved_key] = $a[$i];
}
}
Code is crude and untested, but you get the idea.
Paul
This would be even shorter, I think:
foreach ($items as $i = $value) {
$temp[$i % 2][] = $value;
}
$done = array_combine($temp[0], $temp[1]);
(Also untested, just off the cuff...)
--Larry Garfield
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I'd say that this cat is well and truly skinned!
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http://nephtaliproject.com
--
-
Richard Quadling
Standing on the shoulders of some very clever giants!
EE : http://www.experts-exchange.com/M_248814.html
EE4Free : http://www.experts-exchange.com/becomeAnExpert.jsp
Zend Certified Engineer : http://zend.com/zce.php?c=ZEND002498r=213474731
ZOPA : http://uk.zopa.com/member/RQuadling
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Re: [PHP] array conversion
At 10:48 AM + 2/19/10, Richard Quadling wrote: On 19 February 2010 07:26, Adam Richardson simples...@gmail.com wrote: Or, Code fight!!! http://www.webbytedd.com/ccc/array/ After reviewing the entries, mine does not provide any significant difference. I did it as a mental exercise after looking at several built-in array functions (array_flip(), array_combine(), etc. ) that I thought might solve the problem, but didn't. tedd -- --- http://sperling.com http://ancientstones.com http://earthstones.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] array conversion
On 19 February 2010 15:52, tedd tedd.sperl...@gmail.com wrote: At 10:48 AM + 2/19/10, Richard Quadling wrote: On 19 February 2010 07:26, Adam Richardson simples...@gmail.com wrote: Or, Code fight!!! http://www.webbytedd.com/ccc/array/ After reviewing the entries, mine does not provide any significant difference. I did it as a mental exercise after looking at several built-in array functions (array_flip(), array_combine(), etc. ) that I thought might solve the problem, but didn't. tedd -- --- http://sperling.com http://ancientstones.com http://earthstones.com Just wanting to join in. ?php $array = array ( 'key1', 'value1', 'key2', 'value2', ); $result = array(); while(!is_null($result[array_shift($array)] = array_shift($array))); array_pop($result); print_r($result); ? outputs ... Array ( [key1] = value1 [key2] = value2 ) -- - Richard Quadling Standing on the shoulders of some very clever giants! EE : http://www.experts-exchange.com/M_248814.html EE4Free : http://www.experts-exchange.com/becomeAnExpert.jsp Zend Certified Engineer : http://zend.com/zce.php?c=ZEND002498r=213474731 ZOPA : http://uk.zopa.com/member/RQuadling -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] array conversion
Hi guys. How to convert an array like: Array ( [0] = key1 [1] = value1 [2] = key2 [3] = value2 ) to Array ( [key1] = value1 [key2] = value2 ) Is there a built-in function to do this? Please Cc me. :) Thank you in advance. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] array conversion
On Fri, Feb 19, 2010 at 01:20:12PM +0800, Dasn wrote:
Hi guys. How to convert an array like:
Array
(
[0] = key1
[1] = value1
[2] = key2
[3] = value2
)
to
Array
(
[key1] = value1
[key2] = value2
)
Is there a built-in function to do this?
Please Cc me. :)
Thank you in advance.
I don't believe so, but rolling your own should not be too hard:
$a = array($key1, $value1, $key2, $value2);
$b = array();
$numitems = count($a);
for ($i = 0; $i $numitems; $i++) {
if ($i % 2 == 0) {
$saved_key = $a[$i];
}
elseif ($i % 2 == 1) {
$b[$saved_key] = $a[$i];
}
}
Code is crude and untested, but you get the idea.
Paul
--
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Re: [PHP] array conversion
On Thursday 18 February 2010 11:58:28 pm Paul M Foster wrote:
On Fri, Feb 19, 2010 at 01:20:12PM +0800, Dasn wrote:
Hi guys. How to convert an array like:
Array
(
[0] = key1
[1] = value1
[2] = key2
[3] = value2
)
to
Array
(
[key1] = value1
[key2] = value2
)
Is there a built-in function to do this?
Please Cc me. :)
Thank you in advance.
I don't believe so, but rolling your own should not be too hard:
$a = array($key1, $value1, $key2, $value2);
$b = array();
$numitems = count($a);
for ($i = 0; $i $numitems; $i++) {
if ($i % 2 == 0) {
$saved_key = $a[$i];
}
elseif ($i % 2 == 1) {
$b[$saved_key] = $a[$i];
}
}
Code is crude and untested, but you get the idea.
Paul
This would be even shorter, I think:
foreach ($items as $i = $value) {
$temp[$i % 2][] = $value;
}
$done = array_combine($temp[0], $temp[1]);
(Also untested, just off the cuff...)
--Larry Garfield
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Re: [PHP] array conversion
Or,
function new_arr(array $arr)
{
$count = count($arr);
if ($count % 2 != 0) throw new Exception('The new_arr() function
requires an even number of elements.');
for ($i = 0; $i $count; $i += 2)
{
$new_arr[$arr[$i]] = $arr[$i + 1];
}
return $new_arr;
}
$test = new_arr(array('k1', 'v1', 'k2', 'v2', 'k3', 'v3'));
exit(var_dump($test));
On Fri, Feb 19, 2010 at 1:19 AM, Larry Garfield la...@garfieldtech.comwrote:
On Thursday 18 February 2010 11:58:28 pm Paul M Foster wrote:
On Fri, Feb 19, 2010 at 01:20:12PM +0800, Dasn wrote:
Hi guys. How to convert an array like:
Array
(
[0] = key1
[1] = value1
[2] = key2
[3] = value2
)
to
Array
(
[key1] = value1
[key2] = value2
)
Is there a built-in function to do this?
Please Cc me. :)
Thank you in advance.
I don't believe so, but rolling your own should not be too hard:
$a = array($key1, $value1, $key2, $value2);
$b = array();
$numitems = count($a);
for ($i = 0; $i $numitems; $i++) {
if ($i % 2 == 0) {
$saved_key = $a[$i];
}
elseif ($i % 2 == 1) {
$b[$saved_key] = $a[$i];
}
}
Code is crude and untested, but you get the idea.
Paul
This would be even shorter, I think:
foreach ($items as $i = $value) {
$temp[$i % 2][] = $value;
}
$done = array_combine($temp[0], $temp[1]);
(Also untested, just off the cuff...)
--Larry Garfield
--
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--
Nephtali: PHP web framework that functions beautifully
http://nephtaliproject.com
[PHP] Array
The following line gives me an error message when there aren't any
values in the array --- how do I accommodate this?
Warning: Invalid argument supplied for foreach()
foreach ($_SESSION['order'] AS $key = $value ) {
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Re: [PHP] Array
On Sat, 2009-10-24 at 06:57 -0400, Ron Piggott wrote:
The following line gives me an error message when there aren't any
values in the array --- how do I accommodate this?
Warning: Invalid argument supplied for foreach()
foreach ($_SESSION['order'] AS $key = $value ) {
Do an isset() on $_SESSION['order'] first to determine if the variable
even exists, then do is_array() to determine if it's an array or not
before trying to iterate it. My guess is that $_SESSION['order'] isn't
an array all the time.
Thanks,
Ash
http://www.ashleysheridan.co.uk
Re: [PHP] Array
On Sat, Oct 24, 2009 at 7:59 AM, Ashley Sheridan
a...@ashleysheridan.co.ukwrote:
On Sat, 2009-10-24 at 06:57 -0400, Ron Piggott wrote:
The following line gives me an error message when there aren't any
values in the array --- how do I accommodate this?
Warning: Invalid argument supplied for foreach()
foreach ($_SESSION['order'] AS $key = $value ) {
Do an isset() on $_SESSION['order'] first to determine if the variable
even exists, then do is_array() to determine if it's an array or not
before trying to iterate it. My guess is that $_SESSION['order'] isn't
an array all the time.
Thanks,
Ash
http://www.ashleysheridan.co.uk
foreach works with array and instances.
Unless the class implements Transversable, it's public properties are used
on the loop.
foreach($object as $prop = $value )
//php translates the foreach into something like this...
foreach(get_object_vars($object) as $prop = $value )
--
Martin Scotta
Re: [PHP] Array
The code I have so far for orders is below. When a product hasn't been
added it does what I want it to --- in giving the message Your shopping
cart is empty. When a product is added, but then the user changes
their mind I use the following lines of code to remove the selection:
UNSET($_SESSION['order'][$reference]['quantity']);
UNSET($_SESSION['order'][$reference]);
It still leaves the variable $_SESSION['order'] as an array, even if
there are no selections in it. The PHP command is_array is useless of
weed out when there are no products.
What I would like to have happen is if the shopping cart is empty then
the message Your shopping cart is empty be displayed 100% of the time.
How do I achieve this? What changes to my code below need to happen?
?php
if ( isset($_SESSION['order']) ) {
#customer has begun creating order
foreach ($_SESSION['order'] AS $key = $value ) {
echo Product: . $key . Quantity: .
$_SESSION['order'][$key]['quantity'] . br\r\n;
}
} else {
#no products selected
echo ul class=\lists\\r\n;
echo liYour shopping cart is empty/li\r\n;
echo /ul\r\n;
}
-Original Message-
From: Martin Scotta martinsco...@gmail.com
To: a...@ashleysheridan.co.uk
Cc: ron.pigg...@actsministries.org, PHP General
php-general@lists.php.net
Subject: Re: [PHP] Array
Date: Sat, 24 Oct 2009 11:50:14 -0300
On Sat, Oct 24, 2009 at 7:59 AM, Ashley Sheridan
a...@ashleysheridan.co.uk wrote:
On Sat, 2009-10-24 at 06:57 -0400, Ron Piggott wrote:
The following line gives me an error message when there aren't
any
values in the array --- how do I accommodate this?
Warning: Invalid argument supplied for foreach()
foreach ($_SESSION['order'] AS $key = $value ) {
Do an isset() on $_SESSION['order'] first to determine if the
variable
even exists, then do is_array() to determine if it's an array or
not
before trying to iterate it. My guess is that $_SESSION['order']
isn't
an array all the time.
Thanks,
Ash
http://www.ashleysheridan.co.uk
foreach works with array and instances.
Unless the class implements Transversable, it's public properties are
used on the loop.
foreach($object as $prop = $value )
//php translates the foreach into something like this...
foreach(get_object_vars($object) as $prop = $value )
--
Martin Scotta
Re: [PHP] Array
AHH. The count() command does the trick. Ron
-Original Message-
From: Ron Piggott ron.pigg...@actsministries.org
Reply-to: ron.pigg...@actsministries.org
To: Martin Scotta martinsco...@gmail.com, phps...@gmail.com
Cc: a...@ashleysheridan.co.uk, PHP General php-general@lists.php.net
Subject: Re: [PHP] Array
Date: Sat, 24 Oct 2009 11:43:12 -0400
The code I have so far for orders is below. When a product hasn't been
added it does what I want it to --- in giving the message Your shopping
cart is empty. When a product is added, but then the user changes
their mind I use the following lines of code to remove the selection:
UNSET($_SESSION['order'][$reference]['quantity']);
UNSET($_SESSION['order'][$reference]);
It still leaves the variable $_SESSION['order'] as an array, even if
there are no selections in it. The PHP command is_array is useless of
weed out when there are no products.
What I would like to have happen is if the shopping cart is empty then
the message Your shopping cart is empty be displayed 100% of the time.
How do I achieve this? What changes to my code below need to happen?
?php
if ( isset($_SESSION['order']) ) {
#customer has begun creating order
foreach ($_SESSION['order'] AS $key = $value ) {
echo Product: . $key . Quantity: .
$_SESSION['order'][$key]['quantity'] . br\r\n;
}
} else {
#no products selected
echo ul class=\lists\\r\n;
echo liYour shopping cart is empty/li\r\n;
echo /ul\r\n;
}
-Original Message-
From: Martin Scotta martinsco...@gmail.com
To: a...@ashleysheridan.co.uk
Cc: ron.pigg...@actsministries.org, PHP General
php-general@lists.php.net
Subject: Re: [PHP] Array
Date: Sat, 24 Oct 2009 11:50:14 -0300
On Sat, Oct 24, 2009 at 7:59 AM, Ashley Sheridan
a...@ashleysheridan.co.uk wrote:
On Sat, 2009-10-24 at 06:57 -0400, Ron Piggott wrote:
The following line gives me an error message when there aren't
any
values in the array --- how do I accommodate this?
Warning: Invalid argument supplied for foreach()
foreach ($_SESSION['order'] AS $key = $value ) {
Do an isset() on $_SESSION['order'] first to determine if the
variable
even exists, then do is_array() to determine if it's an array or
not
before trying to iterate it. My guess is that $_SESSION['order']
isn't
an array all the time.
Thanks,
Ash
http://www.ashleysheridan.co.uk
foreach works with array and instances.
Unless the class implements Transversable, it's public properties are
used on the loop.
foreach($object as $prop = $value )
//php translates the foreach into something like this...
foreach(get_object_vars($object) as $prop = $value )
--
Martin Scotta
--
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Re: [PHP] Array
Ron Piggott wrote:
The code I have so far for orders is below. When a product hasn't been
added it does what I want it to --- in giving the message Your shopping
cart is empty. When a product is added, but then the user changes
their mind I use the following lines of code to remove the selection:
UNSET($_SESSION['order'][$reference]['quantity']);
UNSET($_SESSION['order'][$reference]);
It still leaves the variable $_SESSION['order'] as an array, even if
there are no selections in it. The PHP command is_array is useless of
weed out when there are no products.
What I would like to have happen is if the shopping cart is empty then
the message Your shopping cart is empty be displayed 100% of the time.
How do I achieve this? What changes to my code below need to happen?
?php
if ( isset($_SESSION['order']) ) {
#customer has begun creating order
foreach ($_SESSION['order'] AS $key = $value ) {
echo Product: . $key . Quantity: .
$_SESSION['order'][$key]['quantity'] . br\r\n;
}
} else {
#no products selected
echo ul class=\lists\\r\n;
echo liYour shopping cart is empty/li\r\n;
echo /ul\r\n;
}
Or use unset, but unset the entire order: unset($_SESSION['order'])
--
Thanks!
-Shawn
http://www.spidean.com
--
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Re: [PHP] Array
Ron Piggott wrote:
The code I have so far for orders is below. When a product hasn't been
added it does what I want it to --- in giving the message Your shopping
cart is empty. When a product is added, but then the user changes
their mind I use the following lines of code to remove the selection:
UNSET($_SESSION['order'][$reference]['quantity']);
UNSET($_SESSION['order'][$reference]);
It still leaves the variable $_SESSION['order'] as an array, even if
there are no selections in it. The PHP command is_array is useless of
weed out when there are no products.
What I would like to have happen is if the shopping cart is empty then
the message Your shopping cart is empty be displayed 100% of the time.
How do I achieve this? What changes to my code below need to happen?
?php
if ( isset($_SESSION['order']) ) {
#customer has begun creating order
foreach ($_SESSION['order'] AS $key = $value ) {
echo Product: . $key . Quantity: .
$_SESSION['order'][$key]['quantity'] . br\r\n;
}
} else {
#no products selected
echo ul class=\lists\\r\n;
echo liYour shopping cart is empty/li\r\n;
echo /ul\r\n;
}
Try this
?php
...
if ( isset($_SESSION['order']) # Does it exist
is_array($_SESSION['order']) # Is it an array
count($_SESSION['order']) 0 # Does it have at least 1 element
) {
#customer has begun creating order
foreach ($_SESSION['order'] AS $key = $value ) {
echo Product: {$key} Quantity:
{$_SESSION['order'][$key]['quantity']}br\r\n;
}
} else {
#no products selected
echo ul class=\lists\\r\n;
echo liYour shopping cart is empty/li\r\n;
echo /ul\r\n;
}
...
?
-Original Message-
From: Martin Scotta martinsco...@gmail.com
To: a...@ashleysheridan.co.uk
Cc: ron.pigg...@actsministries.org, PHP General
php-general@lists.php.net
Subject: Re: [PHP] Array
Date: Sat, 24 Oct 2009 11:50:14 -0300
On Sat, Oct 24, 2009 at 7:59 AM, Ashley Sheridan
a...@ashleysheridan.co.uk wrote:
On Sat, 2009-10-24 at 06:57 -0400, Ron Piggott wrote:
The following line gives me an error message when there aren't
any
values in the array --- how do I accommodate this?
Warning: Invalid argument supplied for foreach()
foreach ($_SESSION['order'] AS $key = $value ) {
Do an isset() on $_SESSION['order'] first to determine if the
variable
even exists, then do is_array() to determine if it's an array or
not
before trying to iterate it. My guess is that $_SESSION['order']
isn't
an array all the time.
Thanks,
Ash
http://www.ashleysheridan.co.uk
foreach works with array and instances.
Unless the class implements Transversable, it's public properties are
used on the loop.
foreach($object as $prop = $value )
//php translates the foreach into something like this...
foreach(get_object_vars($object) as $prop = $value )
--
Jim Lucas
Some men are born to greatness, some achieve greatness,
and some have greatness thrust upon them.
Twelfth Night, Act II, Scene V
by William Shakespeare
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Re: [PHP] Array references - how to unset() ?
Yes,thanks and I sorry for my poor english 2009/9/3 Robert Cummings rob...@interjinn.com: hack988 hack988 wrote: Reference vars in php would not be unset if it reference by another var,so you must keep original var had'nt being reference. You can't reference a reference in PHP. If you take the reference of a variable that is itself a reference then you are taking a reference to the referenced value and not the reference variable itself. This is illustrated in the following example: ?php $foo = '123'; $fee = '987'; $blah = $foo; $bleh = $blah; $blah = $fee; echo 'blah: '.$blah.\n; echo 'bleh: '.$bleh.\n; ? What I think you meant to say, is that a value is not unset as long as it has at least one variable referencing it. You most certainly unset the reference if you apply unset to it, it is the value referenced that may remain. Cheers, Rob. -- http://www.interjinn.com Application and Templating Framework for PHP -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Array references - how to unset() ?
$ARR = array(
'a' = array('b' = 'blah')
);
function set($key)
{
global $ARR;
foreach ($key as $i = $k) {
if ($i == 0) {
$sourcevar = $ARR[$k];
} else {
$sourcevar = $sourcevar[$k];
}
}
// unset($sourcevar); // will cancel the reference - we want to
unset the ['b'], but how?
$sourcevar = null; // will set it NULL, but won't unset...
foreach ($ARR ... // I could run a cleanup, that would go through all of
the array and unset what is NULL, but I would need to use REFERENCES
again!! array_walk_recursive() is also worthless... any ideas?
}
set( array('a', 'b') );
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Re: [PHP] Array references - how to unset() ?
Martin Zvarík wrote:
$ARR = array(
'a' = array('b' = 'blah')
);
function set($key)
{
global $ARR;
foreach ($key as $i = $k) {
if ($i == 0) {
$sourcevar = $ARR[$k];
} else {
$sourcevar = $sourcevar[$k];
}
}
// unset($sourcevar); // will cancel the reference - we want to
unset the ['b'], but how?
$sourcevar = null; // will set it NULL, but won't unset...
foreach ($ARR ... // I could run a cleanup, that would go through all of
the array and unset what is NULL, but I would need to use REFERENCES
again!! array_walk_recursive() is also worthless... any ideas?
}
set( array('a', 'b') );
unset( $ARR[$k] )
Cheers,
Rob.
--
http://www.interjinn.com
Application and Templating Framework for PHP
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Re: [PHP] Array references - how to unset() ?
Robert Cummings napsal(a):
Martin Zvarík wrote:
$ARR = array(
'a' = array('b' = 'blah')
);
function set($key)
{
global $ARR;
foreach ($key as $i = $k) {
if ($i == 0) {
$sourcevar = $ARR[$k];
} else {
$sourcevar = $sourcevar[$k];
}
}
// unset($sourcevar); // will cancel the reference - we want to
unset the ['b'], but how?
$sourcevar = null; // will set it NULL, but won't unset...
foreach ($ARR ... // I could run a cleanup, that would go through all
of the array and unset what is NULL, but I would need to use
REFERENCES again!! array_walk_recursive() is also worthless... any
ideas?
}
set( array('a', 'b') );
unset( $ARR[$k] )
Cheers,
Rob.
Thanks for reply, but I want to:
unset($ARR['a']['b'])
Imagine I have this:
$KEYS = array('a', 'b', 'c');
And I want to:
unset($ARR['a']['b']['c'])
It's probably impossible, unless I do something dirty like this:
list($rootA, $rootB, $rootC) = $KEYS;
if (isset($rootC)) unset($x[$rootA][$rootB][$rootC]);
elseif (isset($rootB)) unset($x[$rootA][$rootB]);
elseif (isset($rootA)) unset($x[$rootA]);
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Re: [PHP] Array references - how to unset() ?
Martin Zvarík wrote:
Robert Cummings napsal(a):
Martin Zvarík wrote:
$ARR = array(
'a' = array('b' = 'blah')
);
function set($key)
{
global $ARR;
foreach ($key as $i = $k) {
if ($i == 0) {
$sourcevar = $ARR[$k];
} else {
$sourcevar = $sourcevar[$k];
}
}
// unset($sourcevar); // will cancel the reference - we want to
unset the ['b'], but how?
$sourcevar = null; // will set it NULL, but won't unset...
foreach ($ARR ... // I could run a cleanup, that would go through all
of the array and unset what is NULL, but I would need to use
REFERENCES again!! array_walk_recursive() is also worthless... any
ideas?
}
set( array('a', 'b') );
unset( $ARR[$k] )
Cheers,
Rob.
Thanks for reply, but I want to:
unset($ARR['a']['b'])
Imagine I have this:
$KEYS = array('a', 'b', 'c');
And I want to:
unset($ARR['a']['b']['c'])
This is possible. You're just not giving enough consideration to your
exit strategy :)
?php
function unset_deep( $array, $keys )
{
$final = array_pop( $keys );
foreach( $keys as $key )
{
$array = $array[$key];
}
unset( $array[$final] );
}
$value = array
(
'a' = array
(
'b' = array
(
'c' = 'C',
'd' = 'D',
'e' = 'E'
),
),
);
$keys = array('a', 'b', 'c');
unset_deep( $value, $keys );
print_r( $value );
?
Cheers,
Rob.
--
http://www.interjinn.com
Application and Templating Framework for PHP
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Array references - how to unset() ?
AHA !!!
OMG... how come I did not see that!?
Instead this:
$array = $array[$final];
unset($array);
This:
unset($array[$final]);
3 AM in the morning... that must be the reason! .)
Thanks.
This is possible. You're just not giving enough consideration to your
exit strategy :)
?php
function unset_deep( $array, $keys )
{
$final = array_pop( $keys );
foreach( $keys as $key )
{
$array = $array[$key];
}
unset( $array[$final] );
}
$value = array
(
'a' = array
(
'b' = array
(
'c' = 'C',
'd' = 'D',
'e' = 'E'
),
),
);
$keys = array('a', 'b', 'c');
unset_deep( $value, $keys );
print_r( $value );
?
Cheers,
Rob.
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] array() returns something weird
Hello! I am almost certain I am hitting some kind of bug. All of a sudden, array() stops returning an empty array and starts returning something weird. The weird thing behaves as NULL in most circumstances (e.g. gettype() says NULL), except: $foo=array(); // -- weird thing returned $foo[]=bar; causes Fatal error: [] operator not supported for strings, which is different from the regular behavior of: $foo=null; $foo[]=bar; // -- $foo simply becomes an array The problem is not limited to one place in code, and indeed before the fatal caused by append-assignment I get several warnings like array_diff_key(): Argument #1 is not an array, where the offending argument receives a result of array(). The effect is not random, i.e. it always breaks identically when the same script processes the same data. However I was so far unable to create a minimal test case that triggers the bug. My script is rather involved, and here are some things it uses: - Exceptions - DOM to-fro SimpleXML - lots of multi-level output buffering Disabling Zend Optimizer doesn't help. Disabling Zend Memory Manager is apparently impossible. Memory usage is below 10MB out of 128MB limit. Any similar experiences? Ideas what to check for? Workarounds? From phpinfo(): PHP Version: 5.2.9 (can't easily upgrade - shared host) System: FreeBSD 7.1-RELEASE-p4 FreeBSD 7.1-RELEASE-p4 #0: Wed Apr 15 15:48:43 UTC 2009 amd64 Configure Command: './configure' '--enable-bcmath' '--enable-calendar' '--enable-dbase' '--enable- exif' '--enable-fastcgi' '--enable-force-cgi-redirect' '--enable-ftp' '-- enable-gd-native-ttf' '--enable-libxml' '--enable-magic-quotes' '--enable- maintainer-zts' '--enable-mbstring' '--enable-pdo=shared' '--enable-safe-mode' '--enable-soap' '--enable-sockets' '--enable-ucd-snmp-hack' '--enable-wddx' '--enable-zend-multibyte' '--enable-zip' '--prefix=/usr' '--with-bz2' '--with- curl=/opt/curlssl/' '--with-curlwrappers' '--with-freetype-dir=/usr/local' '-- with-gd' '--with-gettext' '--with-imap=/opt/php_with_imap_client/' '--with- imap-ssl=/usr/local' '--with-jpeg-dir=/usr/local' '--with-libexpat- dir=/usr/local' '--with-libxml-dir=/opt/xml2' '--with-libxml-dir=/opt/xml2/' '--with-mcrypt=/opt/libmcrypt/' '--with-mhash=/opt/mhash/' '--with-mime-magic' '--with-mysql=/usr/local' '--with-mysql-sock=/tmp/mysql.sock' '--with- mysqli=/usr/local/bin/mysql_config' '--with-openssl=/usr/local' '--with- openssl-dir=/usr/local' '--with-pdo-mysql=shared' '--with-pdo-sqlite=shared' '--with-pgsql=/usr/local' '--with-pic' '--with-png-dir=/usr/local' '--with- pspell' '--with-snmp' '--with-sqlite=shared' '--with-tidy=/opt/tidy/' '--with- ttf' '--with-xmlrpc' '--with-xpm-dir=/usr/local' '--with-xsl=/opt/xslt/' '-- with-zlib' '--with-zlib-dir=/usr' Thanks in advance, Szczepan Holyszewski -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] array() returns something weird
2009/8/22 Szczepan Hołyszewski webmas...@strefarytmu.pl: Hello! I am almost certain I am hitting some kind of bug. All of a sudden, array() stops returning an empty array and starts returning something weird. The weird thing behaves as NULL in most circumstances (e.g. gettype() says NULL), except: $foo=array(); // -- weird thing returned $foo[]=bar; causes Fatal error: [] operator not supported for strings, which is different from the regular behavior of: Hi there, Without seeing the actual code, it's hard to say what the problem is. However, I'd be pretty surprised if you've actually run into a bug in PHP--I would first suspect a bug in your code. No offense intended--that's just how it usually plays out. :) What it looks like to me is that something is causing $foo to be a string before the '$foo[] = bar;' line is encountered. What do you get if you put a gettype($foo); just before that line? $foo=null; $foo[]=bar; // -- $foo simply becomes an array The problem is not limited to one place in code, and indeed before the fatal caused by append-assignment I get several warnings like array_diff_key(): Argument #1 is not an array, where the offending argument receives a result of array(). This would appear to support my suspicion, but try inserting the gettype($foo) (or better, var_export($foo);) just before one of the lines which triggers the error, and post the results. Can you post the code in a .zip file or online somewhere? If not, that's cool, but it will probably make it harder to help you track it down if you can't. Regards, Torben The effect is not random, i.e. it always breaks identically when the same script processes the same data. However I was so far unable to create a minimal test case that triggers the bug. My script is rather involved, and here are some things it uses: - Exceptions - DOM to-fro SimpleXML - lots of multi-level output buffering Disabling Zend Optimizer doesn't help. Disabling Zend Memory Manager is apparently impossible. Memory usage is below 10MB out of 128MB limit. Any similar experiences? Ideas what to check for? Workarounds? From phpinfo(): PHP Version: 5.2.9 (can't easily upgrade - shared host) System: FreeBSD 7.1-RELEASE-p4 FreeBSD 7.1-RELEASE-p4 #0: Wed Apr 15 15:48:43 UTC 2009 amd64 Configure Command: './configure' '--enable-bcmath' '--enable-calendar' '--enable-dbase' '--enable- exif' '--enable-fastcgi' '--enable-force-cgi-redirect' '--enable-ftp' '-- enable-gd-native-ttf' '--enable-libxml' '--enable-magic-quotes' '--enable- maintainer-zts' '--enable-mbstring' '--enable-pdo=shared' '--enable-safe-mode' '--enable-soap' '--enable-sockets' '--enable-ucd-snmp-hack' '--enable-wddx' '--enable-zend-multibyte' '--enable-zip' '--prefix=/usr' '--with-bz2' '--with- curl=/opt/curlssl/' '--with-curlwrappers' '--with-freetype-dir=/usr/local' '-- with-gd' '--with-gettext' '--with-imap=/opt/php_with_imap_client/' '--with- imap-ssl=/usr/local' '--with-jpeg-dir=/usr/local' '--with-libexpat- dir=/usr/local' '--with-libxml-dir=/opt/xml2' '--with-libxml-dir=/opt/xml2/' '--with-mcrypt=/opt/libmcrypt/' '--with-mhash=/opt/mhash/' '--with-mime-magic' '--with-mysql=/usr/local' '--with-mysql-sock=/tmp/mysql.sock' '--with- mysqli=/usr/local/bin/mysql_config' '--with-openssl=/usr/local' '--with- openssl-dir=/usr/local' '--with-pdo-mysql=shared' '--with-pdo-sqlite=shared' '--with-pgsql=/usr/local' '--with-pic' '--with-png-dir=/usr/local' '--with- pspell' '--with-snmp' '--with-sqlite=shared' '--with-tidy=/opt/tidy/' '--with- ttf' '--with-xmlrpc' '--with-xpm-dir=/usr/local' '--with-xsl=/opt/xslt/' '-- with-zlib' '--with-zlib-dir=/usr' Thanks in advance, Szczepan Holyszewski -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] array() returns something weird
What it looks like to me is that something is causing $foo to be a
string before the '$foo[] = bar;' line is encountered. What do you
get if you put a gettype($foo); just before that line?
$foo=null;
$foo[]=bar; // -- $foo simply becomes an array
NULL. That is the problem. I _did_ put a gettype($foo) before the actual line.
OK, here are exact four lines of my code:
$ret=array();
foreach(self::$_allowed as $r = $a)
if ($a)
$ret[]=$r;
As you can see, there is not a shred of a chance for $ret to become something
other than empty array between initialization and the last line in the above
snippet which causes the fatal errror. There's no __staticGet in 5.2.9, so
self::$_allowed cannot have side effects.
Secondly, the above code starts failing after it has executed successfully
dozens of times (and yes, the last line _does_ get executed; in fact self::
$_allowed contains configuration information that doesn't change at runtime).
Thirdly...
The problem is not limited to one place in code, and indeed before the
fatal caused by append-assignment I get several warnings like
array_diff_key(): Argument #1 is not an array, where the offending
argument receives a result of array().
This would appear to support my suspicion, but try inserting the
gettype($foo) (or better, var_export($foo);) just before one of the
lines which triggers the error, and post the results.
No, I don't think it supports your suspicion. Conversely, it indicates that
once array() returns a strangelet, it starts returning strangelets all over
the place. Initially it only triggers warnings but eventually one of the
returned strangelets is used in a way that triggers a fatal error.
As per your request:
//at the beginning of the script:
$GLOBALS['offending_line_execution_count']=0;
// /srv/home/[munged]/public_html/scripts/common.php line 161 and on
// instrumented as per your request:
public static function GetAllowed() {
if (debug_mode()) echo
++$GLOBALS['offending_line_execution_count'].br/;
$ret=array();
if (debug_mode()) echo var_export($ret).br/;
foreach(self::$_allowed as $r = $a)
if ($a)
$ret[]=$r;
if (self::$_allowEmpty) $ret[]=;
return $ret;
}
Output tail:
---
28
array ( )
29
array ( )
30
array ( )
31
array ( )
32
array ( )
Warning: array_diff_key() [function.array-diff-key]: Argument #1 is not an
array
in /srv/home/u80959ue/public_html/v3/scripts/SimpliciText.php on line 350
Warning: Invalid argument supplied for foreach() in
/srv/home/u80959ue/public_html/v3/scripts/SimpliciText.php on line 351
Warning: array_merge() [function.array-merge]: Argument #2 is not an array in
/srv/home/u80959ue/public_html/v3/scripts/SimpliciText.php on line 357
Warning: Invalid argument supplied for foreach() in
/srv/home/u80959ue/public_html/scripts/common.php on line 28
Warning: Invalid argument supplied for foreach() in
/srv/home/u80959ue/public_html/scripts/common.php on line 28
Warning: Invalid argument supplied for foreach() in
/srv/home/u80959ue/public_html/scripts/common.php on line 28
33
NULL
Fatal error: [] operator not supported for strings in
/srv/home/u80959ue/public_html/scripts/common.php on line 168
--
The warnings come from other uses of array().
But wait! There is this invocation of debug_mode() between initialization of
$ret var_export. Let's factor it out to be safe:
$debugmode=debug_mode();
if ($debugmode) echo
++$GLOBALS['offending_line_execution_count'].br/;
$ret=array();
if ($debugmode) echo var_export($ret).br/;
And now the output ends with:
Warning: Invalid argument supplied for foreach() in
/srv/home/u80959ue/public_html/scripts/common.php on line 28
33
Fatal error: [] operator not supported for strings in
/srv/home/u80959ue/public_html/scripts/common.php on line 169
No NULL after 33? What the heck is going on? Does array() now return something
that var_exports to an empty string, or does it destroy local variables? Let's
see:
if ($debugmode) echo var_export($ret).br/; else echo
WTF?!?!?br/;
And the output:
Warning: Invalid argument supplied for foreach() in
/srv/home/u80959ue/public_html/scripts/common.php on line 28
33
WTF?!?!?
Fatal error: [] operator not supported for strings in
/srv/home/u80959ue/public_html/scripts/common.php on line 169
---
Indeed, the use of array(), once it starts misbehaving, wreaks havoc in the
local scope (possibly including the
Re: [PHP] array() returns something weird
2009/8/22 Szczepan Hołyszewski webmas...@strefarytmu.pl:
What it looks like to me is that something is causing $foo to be a
string before the '$foo[] = bar;' line is encountered. What do you
get if you put a gettype($foo); just before that line?
$foo=null;
$foo[]=bar; // -- $foo simply becomes an array
NULL. That is the problem. I _did_ put a gettype($foo) before the actual line.
OK, here are exact four lines of my code:
$ret=array();
foreach(self::$_allowed as $r = $a)
if ($a)
$ret[]=$r;
As you can see, there is not a shred of a chance for $ret to become something
other than empty array between initialization and the last line in the above
snippet which causes the fatal errror. There's no __staticGet in 5.2.9, so
self::$_allowed cannot have side effects.
Secondly, the above code starts failing after it has executed successfully
dozens of times (and yes, the last line _does_ get executed; in fact self::
$_allowed contains configuration information that doesn't change at runtime).
Thirdly...
The problem is not limited to one place in code, and indeed before the
fatal caused by append-assignment I get several warnings like
array_diff_key(): Argument #1 is not an array, where the offending
argument receives a result of array().
This would appear to support my suspicion, but try inserting the
gettype($foo) (or better, var_export($foo);) just before one of the
lines which triggers the error, and post the results.
No, I don't think it supports your suspicion. Conversely, it indicates that
once array() returns a strangelet, it starts returning strangelets all over
the place. Initially it only triggers warnings but eventually one of the
returned strangelets is used in a way that triggers a fatal error.
As per your request:
//at the beginning of the script:
$GLOBALS['offending_line_execution_count']=0;
// /srv/home/[munged]/public_html/scripts/common.php line 161 and on
// instrumented as per your request:
public static function GetAllowed() {
if (debug_mode()) echo
++$GLOBALS['offending_line_execution_count'].br/;
$ret=array();
if (debug_mode()) echo var_export($ret).br/;
foreach(self::$_allowed as $r = $a)
if ($a)
$ret[]=$r;
if (self::$_allowEmpty) $ret[]=;
return $ret;
}
Output tail:
---
28
array ( )
29
array ( )
30
array ( )
31
array ( )
32
array ( )
Warning: array_diff_key() [function.array-diff-key]: Argument #1 is not an
array
in /srv/home/u80959ue/public_html/v3/scripts/SimpliciText.php on line 350
Warning: Invalid argument supplied for foreach() in
/srv/home/u80959ue/public_html/v3/scripts/SimpliciText.php on line 351
Warning: array_merge() [function.array-merge]: Argument #2 is not an array in
/srv/home/u80959ue/public_html/v3/scripts/SimpliciText.php on line 357
Warning: Invalid argument supplied for foreach() in
/srv/home/u80959ue/public_html/scripts/common.php on line 28
Warning: Invalid argument supplied for foreach() in
/srv/home/u80959ue/public_html/scripts/common.php on line 28
Warning: Invalid argument supplied for foreach() in
/srv/home/u80959ue/public_html/scripts/common.php on line 28
33
NULL
Fatal error: [] operator not supported for strings in
/srv/home/u80959ue/public_html/scripts/common.php on line 168
--
The warnings come from other uses of array().
But wait! There is this invocation of debug_mode() between initialization of
$ret var_export. Let's factor it out to be safe:
$debugmode=debug_mode();
if ($debugmode) echo
++$GLOBALS['offending_line_execution_count'].br/;
$ret=array();
if ($debugmode) echo var_export($ret).br/;
And now the output ends with:
Warning: Invalid argument supplied for foreach() in
/srv/home/u80959ue/public_html/scripts/common.php on line 28
33
Fatal error: [] operator not supported for strings in
/srv/home/u80959ue/public_html/scripts/common.php on line 169
No NULL after 33? What the heck is going on? Does array() now return something
that var_exports to an empty string, or does it destroy local variables? Let's
see:
if ($debugmode) echo var_export($ret).br/; else echo
WTF?!?!?br/;
And the output:
Warning: Invalid argument supplied for foreach() in
/srv/home/u80959ue/public_html/scripts/common.php on line 28
33
WTF?!?!?
Fatal error: [] operator not supported for strings in
/srv/home/u80959ue/public_html/scripts/common.php on line 169
---
Indeed, the use of
Re: [PHP] array() returns something weird
well, when I saw ur post I got immediately the thought I would bed it has to
do with some stuff of $this or self.
I did play arround a bit with class creation the last days and yes, with
using self parent and $this I did put the HTTPPD in unstable and sometimes
it died without beeing able to send any error.
well this doesn't help very mutch.
I have two point:
(1)ur code is ( sorry ) lazy written, invest the brackets !! ur code writing
is predestinated for that type of error. shooting variable types arround by
pulling out of foreach loops, if's, is typical.
(2) using static variables are known for type missmatch errors just anything
has acces to them even if the containing class is not instantinated. many
dirty things can happen unless of corse they are not private.
further sugestions: check if you work on ur arrays with functions returning
array on success but false on fail or something like that. also a typical
source for that type of error
are u using magic __set ? I ran into a type change as well with it
good luck
ralph_def...@yahoo.de
Szczepan Holyszewski webmas...@strefarytmu.pl wrote in message
news:200908222152.55846.webmas...@strefarytmu.pl...
What it looks like to me is that something is causing $foo to be a
string before the '$foo[] = bar;' line is encountered. What do you
get if you put a gettype($foo); just before that line?
$foo=null;
$foo[]=bar; // -- $foo simply becomes an array
NULL. That is the problem. I _did_ put a gettype($foo) before the actual
line.
OK, here are exact four lines of my code:
$ret=array();
foreach(self::$_allowed as $r = $a)
if ($a)
$ret[]=$r;
As you can see, there is not a shred of a chance for $ret to become
something
other than empty array between initialization and the last line in the
above
snippet which causes the fatal errror. There's no __staticGet in 5.2.9, so
self::$_allowed cannot have side effects.
Secondly, the above code starts failing after it has executed successfully
dozens of times (and yes, the last line _does_ get executed; in fact
self::
$_allowed contains configuration information that doesn't change at
runtime).
Thirdly...
The problem is not limited to one place in code, and indeed before the
fatal caused by append-assignment I get several warnings like
array_diff_key(): Argument #1 is not an array, where the offending
argument receives a result of array().
This would appear to support my suspicion, but try inserting the
gettype($foo) (or better, var_export($foo);) just before one of the
lines which triggers the error, and post the results.
No, I don't think it supports your suspicion. Conversely, it indicates
that
once array() returns a strangelet, it starts returning strangelets all
over
the place. Initially it only triggers warnings but eventually one of the
returned strangelets is used in a way that triggers a fatal error.
As per your request:
//at the beginning of the script:
$GLOBALS['offending_line_execution_count']=0;
// /srv/home/[munged]/public_html/scripts/common.php line 161 and on
// instrumented as per your request:
public static function GetAllowed() {
if (debug_mode()) echo
++$GLOBALS['offending_line_execution_count'].br/;
$ret=array();
if (debug_mode()) echo var_export($ret).br/;
foreach(self::$_allowed as $r = $a)
if ($a)
$ret[]=$r;
if (self::$_allowEmpty) $ret[]=;
return $ret;
}
Output tail:
---
28
array ( )
29
array ( )
30
array ( )
31
array ( )
32
array ( )
Warning: array_diff_key() [function.array-diff-key]: Argument #1 is not an
array
in /srv/home/u80959ue/public_html/v3/scripts/SimpliciText.php on line 350
Warning: Invalid argument supplied for foreach() in
/srv/home/u80959ue/public_html/v3/scripts/SimpliciText.php on line 351
Warning: array_merge() [function.array-merge]: Argument #2 is not an array
in
/srv/home/u80959ue/public_html/v3/scripts/SimpliciText.php on line 357
Warning: Invalid argument supplied for foreach() in
/srv/home/u80959ue/public_html/scripts/common.php on line 28
Warning: Invalid argument supplied for foreach() in
/srv/home/u80959ue/public_html/scripts/common.php on line 28
Warning: Invalid argument supplied for foreach() in
/srv/home/u80959ue/public_html/scripts/common.php on line 28
33
NULL
Fatal error: [] operator not supported for strings in
/srv/home/u80959ue/public_html/scripts/common.php on line 168
--
The warnings come from other uses of array().
But wait! There is this invocation of debug_mode() between initialization
of
$ret var_export. Let's factor it out to be safe:
$debugmode=debug_mode();
if ($debugmode) echo ++$GLOBALS['offending_line_execution_count'].br/;
$ret=array();
if ($debugmode) echo var_export($ret).br/;
And now the output ends with:
Warning: Invalid argument supplied for foreach() in
Re: [PHP] array() returns something weird
Hm. . .it does look odd. Searching the bugs database at http://bugs.php.net does turn up one other report (at http://bugs.php.net/bug.php?id=47870 ) of array() returning NULL in certain hard-to-duplicate circumstances on FreeBSD, Yes, I found it even before posting here, but I wasn't sure whether to file a new report or comment under this one. If your intuition is that these bugs are related, then I will do the latter. Thank you for your attention. I don't suppose you have a development environment on another machine where you can test another version of PHP? Assuming you mean a FreeBSD environment, nope :( but I will try on Linux tomorrow. Regards, Szczepan Holyszewski -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] array() returns something weird
2009/8/22 Szczepan Hołyszewski webmas...@strefarytmu.pl: Hm. . .it does look odd. Searching the bugs database at http://bugs.php.net does turn up one other report (at http://bugs.php.net/bug.php?id=47870 ) of array() returning NULL in certain hard-to-duplicate circumstances on FreeBSD, Yes, I found it even before posting here, but I wasn't sure whether to file a new report or comment under this one. If your intuition is that these bugs are related, then I will do the latter. Thank you for your attention. Well, the only things I'm basing my suspicion on are the nature of the problem, the OS similarity and the fact that it seems to be difficult to reproduce the problem reliably. The major problem with this guess is that the original bug report does state that the bug did not show up under 5.2. I don't suppose you have a development environment on another machine where you can test another version of PHP? Assuming you mean a FreeBSD environment, nope :( but I will try on Linux tomorrow. OK. I do think (as I'm sure you know) that the best test would be in a matching environment (since the result was reported to be different under Linux for that bug), but of course that's not always realistic. Regards, Szczepan Holyszewski I hope your problem can be resolved. If it does turn out to be a bug in PHP I hope that will be enough to convince your host to upgrade. Regards, Torben -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Array
How do I change this ELSEIF into an array?
} elseif ( ( $page ) AND ( $page home_page ) AND ( $page
verse_of_the_day_activate ) AND ( $page member_services ) AND ( $page
member_services_login ) AND ( $page member_services_logoff ) AND ( $page
resource_center ) AND ( $page network ) ) {
Re: [PHP] Array
On Mon, Aug 10, 2009 at 9:28 AM, Ron
Piggottron.pigg...@actsministries.org wrote:
How do I change this ELSEIF into an array?
} elseif ( ( $page ) AND ( $page home_page ) AND ( $page
verse_of_the_day_activate ) AND ( $page member_services ) AND ( $page
member_services_login ) AND ( $page member_services_logoff ) AND (
$page resource_center ) AND ( $page network ) ) {
Something like:
} elseif (!in_array($page, array(, home_page,
verse_of_the_day_activate, ...))) {
should work.
Regards,
Jonathan
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Array
Ron Piggott wrote:
How do I change this ELSEIF into an array?
} elseif ( ( $page ) AND ( $page home_page ) AND ( $page verse_of_the_day_activate ) AND ( $page member_services ) AND (
$page member_services_login ) AND ( $page member_services_logoff ) AND ( $page resource_center ) AND ( $page network ) ) {
Put all the compared values into an array, then check that $page is not
in_array().
Cheers,
Rob.
--
http://www.interjinn.com
Application and Templating Framework for PHP
--
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Re: [PHP] Array
Ron Piggott wrote:
How do I change this ELSEIF into an array?
} elseif ( ( $page ) AND ( $page home_page ) AND ( $page
verse_of_the_day_activate ) AND ( $page member_services ) AND ( $page
member_services_login ) AND ( $page member_services_logoff ) AND (
$page resource_center ) AND ( $page network ) ) {
?php
$d = array(
home_page,
member_services,
member_services_login,
network,
resource_center,
verse_of_the_day_activate,
);
} elseif ( !empty($page) in_array($page, $d) ) {
?
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[PHP] array manipulation
The more I get into arrays, the less I understand.
I have a ridiculously simple task which excapes me completely.
I need to ouput all fields in 1 column from 1 table in two phases sorted
alphabetically.
So, I have the query, I have the results. But since I need to split the
list into 2 parts, I need indexes. I cannot use the table index as it
does not correspond to the alphabetical order of the data column. In
order to get the index, I sort the resulting array and that now gives me
34 arrays each containing an array of my results. Wonderful!
But how do I now extract the arrays from the array?
Here is what I'm trying to do:
$SQL = SELECT category
FROM categories
ORDER BY category ASC
;
$category = array();
if ( ( $results = mysql_query($SQL, $db) ) !== false ) {
while ( $row = mysql_fetch_assoc($results) ) {
$category[$row['category']] = $row;
}
sort($category);
//var_dump($category);
echo table ;
$count = mysql_num_rows($results);
$lastIndex = $count/2 -1; echo $lastIndex;
$ii = 0;
$cat = '';
//print_r($category['0']['category']);
foreach($category as $index = $value) {
$ii++;
if ($ii != $lastIndex) {
$cat .= $value, ;
}
else {
$cat .= $valuebr /;
}
$catn = preg_replace(/[^a-zA-Z0-9]/, , $cat);
//echo pre$category/pre;
echo tr
tda href='../categories/, $catn, .php', $cat, /a
/td
/tr ;
}
}
echo /table;
What should I be using in the foreach line?
Please help!
--
unheralded genius: A clean desk is the sign of a dull mind.
-
Phil Jourdan --- p...@ptahhotep.com
http://www.ptahhotep.com
http://www.chiccantine.com/andypantry.php
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Re: [PHP] array manipulation
Sorry, bout that.
My brain wasn't working right.
It was a lot simpler than I thought. Forget the foreach.
I used a counter. :-[
PJ wrote:
The more I get into arrays, the less I understand.
I have a ridiculously simple task which excapes me completely.
I need to ouput all fields in 1 column from 1 table in two phases sorted
alphabetically.
So, I have the query, I have the results. But since I need to split the
list into 2 parts, I need indexes. I cannot use the table index as it
does not correspond to the alphabetical order of the data column. In
order to get the index, I sort the resulting array and that now gives me
34 arrays each containing an array of my results. Wonderful!
But how do I now extract the arrays from the array?
Here is what I'm trying to do:
$SQL = SELECT category
FROM categories
ORDER BY category ASC
;
$category = array();
if ( ( $results = mysql_query($SQL, $db) ) !== false ) {
while ( $row = mysql_fetch_assoc($results) ) {
$category[$row['category']] = $row;
}
sort($category);
//var_dump($category);
echo table ;
$count = mysql_num_rows($results);
$lastIndex = $count/2 -1; echo $lastIndex;
$ii = 0;
$cat = '';
//print_r($category['0']['category']);
foreach($category as $index = $value) {
$ii++;
if ($ii != $lastIndex) {
$cat .= $value, ;
}
else {
$cat .= $valuebr /;
}
$catn = preg_replace(/[^a-zA-Z0-9]/, , $cat);
//echo pre$category/pre;
echo tr
tda href='../categories/, $catn, .php', $cat, /a
/td
/tr ;
}
}
echo /table;
What should I be using in the foreach line?
Please help!
--
unheralded genius: A clean desk is the sign of a dull mind.
-
Phil Jourdan --- p...@ptahhotep.com
http://www.ptahhotep.com
http://www.chiccantine.com/andypantry.php
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Re: [PHP] array manipulation
soln: YOU NEED A 2 WEEK HOLLIDAY at least! You need to learn to say no.
Tim-Hinnerk Heuer
http://www.ihostnz.com
Samuel Goldwynhttp://www.brainyquote.com/quotes/authors/s/samuel_goldwyn.html
- A wide screen just makes a bad film twice as bad.
2009/4/17 PJ af.gour...@videotron.ca
The more I get into arrays, the less I understand.
I have a ridiculously simple task which excapes me completely.
I need to ouput all fields in 1 column from 1 table in two phases sorted
alphabetically.
So, I have the query, I have the results. But since I need to split the
list into 2 parts, I need indexes. I cannot use the table index as it
does not correspond to the alphabetical order of the data column. In
order to get the index, I sort the resulting array and that now gives me
34 arrays each containing an array of my results. Wonderful!
But how do I now extract the arrays from the array?
Here is what I'm trying to do:
$SQL = SELECT category
FROM categories
ORDER BY category ASC
;
$category = array();
if ( ( $results = mysql_query($SQL, $db) ) !== false ) {
while ( $row = mysql_fetch_assoc($results) ) {
$category[$row['category']] = $row;
}
sort($category);
//var_dump($category);
echo table ;
$count = mysql_num_rows($results);
$lastIndex = $count/2 -1; echo $lastIndex;
$ii = 0;
$cat = '';
//print_r($category['0']['category']);
foreach($category as $index = $value) {
$ii++;
if ($ii != $lastIndex) {
$cat .= $value, ;
}
else {
$cat .= $valuebr /;
}
$catn = preg_replace(/[^a-zA-Z0-9]/, , $cat);
//echo pre$category/pre;
echo tr
tda href='../categories/, $catn, .php', $cat, /a
/td
/tr ;
}
}
echo /table;
What should I be using in the foreach line?
Please help!
--
unheralded genius: A clean desk is the sign of a dull mind.
-
Phil Jourdan --- p...@ptahhotep.com
http://www.ptahhotep.com
http://www.chiccantine.com/andypantry.php
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[PHP] Hello, I have a question about php array max number
Hello, I have an array including 2000 records in database, but when fetch all of them, why just get 1500 records? Does that depend on my computer? Peter __ Information from ESET NOD32 Antivirus, version of virus signature database 3997 (20090409) __ The message was checked by ESET NOD32 Antivirus. http://www.eset.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Hello, I have a question about php array max number
Hello, I have an array including 2000 records in database, but when fetch all of them, why just get 1500 records? Does that depend on my computer? Peter __ Information from ESET NOD32 Antivirus, version of virus signature database 3997 (20090409) __ The message was checked by ESET NOD32 Antivirus. http://www.eset.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Hello, I have a question about php array max number
On Thu, Apr 9, 2009 at 2:36 PM, PeterDu pete...@telus.net wrote: Hello, I have an array including 2000 records in database, but when fetch all of them, why just get 1500 records? Does that depend on my computer? Peter __ Information from ESET NOD32 Antivirus, version of virus signature database 3997 (20090409) __ The message was checked by ESET NOD32 Antivirus. http://www.eset.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php Could be the memory limit on the server, could be the query only returning 1500 rows. -- Bastien Cat, the other other white meat
[PHP] Re: Hello, I have a question about php array max number
On Thu, 9 Apr 2009 10:08:12 -0700, PeterDu wrote: Hello, I have an array including 2000 records in database, but when fetch all of them, why just get 1500 records? Does that depend on my computer? Well, at least you hi-jacked a thread that did not pertain to PHP and put it back On Topic! -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Array Brain Freeze
Hello all, I have the follwoing piece of code: //reference a stored procedure $procedure = Execute Procedure informix.arrest_char($part_id); //run the stored procedure $char_query = ifx_query($procedure, $connect_id); //get the result of the stored procedure $char_result = ifx_fetch_row($char_query); //print out the returned values. print_r($char_result); This all works just fine and I have values returned. What I am trying to do is assign one of the array items to a variable. In the past I have done so like this: $stat_1 = $char_result['stat_1']; But for some odd reason $stat_1 doesn't contain anything. Am I going crazy or am I doing something wrong? Thanks, Dan
[PHP] array/iteration issue!!
hi. i have the following test multidiminsional array. i'm trying to figure out how to iterate through the array, to produce something like foo, physics, sss foo, physics, sffgg foo, english, sss foo, english, sffgg can't quite seem to get it right!! thoughts/comments... etc... thanks $a=array(college= foo, dept=array(dept= physics, class=array(class1=sss,class2=sffgg) ), dept=array(dept= english, class=array(class1=sss,class2=sffgg) ) ); -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] array/iteration issue!!
On Thu, 2008-11-27 at 17:31 -0800, bruce wrote: hi. i have the following test multidiminsional array. i'm trying to figure out how to iterate through the array, to produce something like foo, physics, sss foo, physics, sffgg foo, english, sss foo, english, sffgg can't quite seem to get it right!! thoughts/comments... etc... thanks $a=array(college= foo, dept=array(dept= physics, class=array(class1=sss,class2=sffgg) ), dept=array(dept= english, class=array(class1=sss,class2=sffgg) ) ); You can't. You're array is valid but the second 'dept' key overwrites the first. Thus the physics dept is lost. Check it for yourself... print_r( $a ) Cheers, Rob. -- http://www.interjinn.com Application and Templating Framework for PHP -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] array/iteration issue!!
hey robert.. ok.. so if i changed the array to have a dept1, and a dept2 $a=array(college= foo, dept1=array(dept= physics, class=array(class1=sss,class2=sffgg) ), dept2=array(dept= english, class=array(class1=sss,class2=sffgg) ) ); how would i iterate through this..?? thanks -Original Message- From: Robert Cummings [mailto:[EMAIL PROTECTED] Sent: Thursday, November 27, 2008 6:18 PM To: bruce Cc: 'PHP General list' Subject: Re: [PHP] array/iteration issue!! On Thu, 2008-11-27 at 17:31 -0800, bruce wrote: hi. i have the following test multidiminsional array. i'm trying to figure out how to iterate through the array, to produce something like foo, physics, sss foo, physics, sffgg foo, english, sss foo, english, sffgg can't quite seem to get it right!! thoughts/comments... etc... thanks $a=array(college= foo, dept=array(dept= physics, class=array(class1=sss,class2=sffgg) ), dept=array(dept= english, class=array(class1=sss,class2=sffgg) ) ); You can't. You're array is valid but the second 'dept' key overwrites the first. Thus the physics dept is lost. Check it for yourself... print_r( $a ) Cheers, Rob. -- http://www.interjinn.com Application and Templating Framework for PHP -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] array/iteration issue!!
On Thu, 2008-11-27 at 18:55 -0800, bruce wrote:
hey robert..
ok.. so if i changed the array to have a dept1, and a dept2
$a=array(college= foo,
dept1=array(dept= physics,
class=array(class1=sss,class2=sffgg)
),
dept2=array(dept= english,
class=array(class1=sss,class2=sffgg)
)
);
how would i iterate through this..??
Your array is terribly structured. But the following provides traversal
in the way you want:
?php
$a = array
(
college = foo,
dept1 = array
(
dept = physics,
class = array
(
class1 = sss,
class2 = sffgg
)
),
dept2 = array
(
dept = english,
class = array
(
class1 = sss,
class2 = sffgg
)
)
);
$college = $a['college'];
foreach( $a as $deptKey = $deptInfo )
{
if( strpos( $deptKey, 'dept' ) === 0 )
{
$dept = $deptInfo['dept'];
foreach( $deptInfo['class'] as $class )
{
echo $college, $dept, $class\n;
}
}
}
?
Cheers,
Rob.
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Application and Templating Framework for PHP
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RE: [PHP] array/iteration issue!!
hey robert!!
thanks. and yeah, you're right, it's not the best.. so tell me, given that
i'm ripping through this on the fly, and i can have the structure in any way
i choose. this is just to simulate/populate some test tbls.. what's a better
way to create an array structure to have a collegename, followed by some
deptnames, followed by some classnames for the depts...
perhaps something like this??
$a = array
(
college = foo,
array
(
dept = physics,
class = array
(
class1 = sss,
class2 = sffgg
)
),
array
(
dept = english,
class = array
(
class1 = sss,
class2 = sffgg
)
)
);
-Original Message-
From: Robert Cummings [mailto:[EMAIL PROTECTED]
Sent: Thursday, November 27, 2008 7:10 PM
To: bruce
Cc: 'PHP General list'
Subject: RE: [PHP] array/iteration issue!!
On Thu, 2008-11-27 at 18:55 -0800, bruce wrote:
hey robert..
ok.. so if i changed the array to have a dept1, and a dept2
$a=array(college= foo,
dept1=array(dept= physics,
class=array(class1=sss,class2=sffgg)
),
dept2=array(dept= english,
class=array(class1=sss,class2=sffgg)
)
);
how would i iterate through this..??
Your array is terribly structured. But the following provides traversal
in the way you want:
?php
$a = array
(
college = foo,
dept1 = array
(
dept = physics,
class = array
(
class1 = sss,
class2 = sffgg
)
),
dept2 = array
(
dept = english,
class = array
(
class1 = sss,
class2 = sffgg
)
)
);
$college = $a['college'];
foreach( $a as $deptKey = $deptInfo )
{
if( strpos( $deptKey, 'dept' ) === 0 )
{
$dept = $deptInfo['dept'];
foreach( $deptInfo['class'] as $class )
{
echo $college, $dept, $class\n;
}
}
}
?
Cheers,
Rob.
--
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Application and Templating Framework for PHP
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RE: [PHP] array/iteration issue!!
On Thu, 2008-11-27 at 19:36 -0800, bruce wrote:
hey robert!!
thanks. and yeah, you're right, it's not the best.. so tell me, given that
i'm ripping through this on the fly, and i can have the structure in any way
i choose. this is just to simulate/populate some test tbls.. what's a better
way to create an array structure to have a collegename, followed by some
deptnames, followed by some classnames for the depts...
perhaps something like this??
$a = array
(
college = foo,
array
(
dept = physics,
class = array
(
class1 = sss,
class2 = sffgg
)
),
array
(
dept = english,
class = array
(
class1 = sss,
class2 = sffgg
)
)
);
Not quite. The following is probably what you want:
?php
$colleges = array
(
array
(
'name' = 'Blah Blah University',
'depts' = array
(
array
(
'name'= 'physics',
'classes' = array
(
'sss',
'sffgg',
),
),
array
(
'name'= 'english',
'classes' = array
(
'sss',
'sffgg',
),
),
),
),
array
(
'name' = 'Glah Gleh University',
'depts' = array
(
array
(
'name'= 'physics',
'classes' = array
(
'sss',
'sffgg',
),
),
array
(
'name'= 'english',
'classes' = array
(
'sss',
'sffgg',
),
),
),
),
);
foreach( $colleges as $college )
{
$collegeName = $college['name'];
foreach( $college['depts'] as $dept )
{
$deptName = $dept['name'];
foreach( $dept['classes'] as $className )
{
echo $collegeName, $deptName, $className\n;
}
}
}
?
Cheers,
Rob.
--
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Application and Templating Framework for PHP
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Re: [PHP] array/iteration issue!!
Robert Cummings wrote:
On Thu, 2008-11-27 at 19:36 -0800, bruce wrote:
hey robert!!
thanks. and yeah, you're right, it's not the best.. so tell me, given that
i'm ripping through this on the fly, and i can have the structure in any way
i choose. this is just to simulate/populate some test tbls.. what's a better
way to create an array structure to have a collegename, followed by some
deptnames, followed by some classnames for the depts...
perhaps something like this??
$a = array
(
college = foo,
array
(
dept = physics,
class = array
(
class1 = sss,
class2 = sffgg
)
),
array
(
dept = english,
class = array
(
class1 = sss,
class2 = sffgg
)
)
);
Not quite. The following is probably what you want:
?php
$colleges = array
(
array
(
'name' = 'Blah Blah University',
'depts' = array
(
array
(
'name'= 'physics',
'classes' = array
(
'sss',
'sffgg',
),
),
array
(
'name'= 'english',
'classes' = array
(
'sss',
'sffgg',
),
),
),
),
array
(
'name' = 'Glah Gleh University',
'depts' = array
(
array
(
'name'= 'physics',
'classes' = array
(
'sss',
'sffgg',
),
),
array
(
'name'= 'english',
'classes' = array
(
'sss',
'sffgg',
),
),
),
),
);
foreach( $colleges as $college )
{
$collegeName = $college['name'];
foreach( $college['depts'] as $dept )
{
$deptName = $dept['name'];
foreach( $dept['classes'] as $className )
{
echo $collegeName, $deptName, $className\n;
}
}
}
?
Cheers,
Rob.
This is actually a much smaller data structure.
$colleges = array
(
'Blah Blah University' =
array
(
'physics' = array
(
'sss',
'sffgg',
),
'english' = array
(
'sss',
'sffgg',
)
),
'Glah Gleh University' =
array
(
'physics' = array
(
'sss',
'sffgg',
),
'english' = array
(
'sss',
'sffgg',
),
)
);
foreach( $colleges as $collegeName = $depts )
{
foreach( $depts as $deptName = $classes)
{
foreach( $classes as $className )
{
echo $collegeName, $deptName, $className\n;
}
}
}
Thank you,
Micah Gersten
onShore Networks
Internal Developer
http://www.onshore.com
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RE: [PHP] array/iteration issue!!
much props guys!!!
thanks!!
-Original Message-
From: Micah Gersten [mailto:[EMAIL PROTECTED]
Sent: Thursday, November 27, 2008 8:23 PM
To: Robert Cummings
Cc: bruce; 'PHP General list'
Subject: Re: [PHP] array/iteration issue!!
Robert Cummings wrote:
On Thu, 2008-11-27 at 19:36 -0800, bruce wrote:
hey robert!!
thanks. and yeah, you're right, it's not the best.. so tell me, given
that
i'm ripping through this on the fly, and i can have the structure in any
way
i choose. this is just to simulate/populate some test tbls.. what's a
better
way to create an array structure to have a collegename, followed by some
deptnames, followed by some classnames for the depts...
perhaps something like this??
$a = array
(
college = foo,
array
(
dept = physics,
class = array
(
class1 = sss,
class2 = sffgg
)
),
array
(
dept = english,
class = array
(
class1 = sss,
class2 = sffgg
)
)
);
Not quite. The following is probably what you want:
?php
$colleges = array
(
array
(
'name' = 'Blah Blah University',
'depts' = array
(
array
(
'name'= 'physics',
'classes' = array
(
'sss',
'sffgg',
),
),
array
(
'name'= 'english',
'classes' = array
(
'sss',
'sffgg',
),
),
),
),
array
(
'name' = 'Glah Gleh University',
'depts' = array
(
array
(
'name'= 'physics',
'classes' = array
(
'sss',
'sffgg',
),
),
array
(
'name'= 'english',
'classes' = array
(
'sss',
'sffgg',
),
),
),
),
);
foreach( $colleges as $college )
{
$collegeName = $college['name'];
foreach( $college['depts'] as $dept )
{
$deptName = $dept['name'];
foreach( $dept['classes'] as $className )
{
echo $collegeName, $deptName, $className\n;
}
}
}
?
Cheers,
Rob.
This is actually a much smaller data structure.
$colleges = array
(
'Blah Blah University' =
array
(
'physics' = array
(
'sss',
'sffgg',
),
'english' = array
(
'sss',
'sffgg',
)
),
'Glah Gleh University' =
array
(
'physics' = array
(
'sss',
'sffgg',
),
'english' = array
(
'sss',
'sffgg',
),
)
);
foreach( $colleges as $collegeName = $depts )
{
foreach( $depts as $deptName = $classes)
{
foreach( $classes as $className )
{
echo $collegeName, $deptName, $className\n;
}
}
}
Thank you,
Micah Gersten
onShore Networks
Internal Developer
http://www.onshore.com
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Re: [PHP] array/iteration issue!!
On Thu, 2008-11-27 at 22:22 -0600, Micah Gersten wrote:
This is actually a much smaller data structure.
$colleges = array
(
'Blah Blah University' =
array
(
'physics' = array
(
'sss',
'sffgg',
),
'english' = array
(
'sss',
'sffgg',
)
),
'Glah Gleh University' =
array
(
'physics' = array
(
'sss',
'sffgg',
),
'english' = array
(
'sss',
'sffgg',
),
)
);
foreach( $colleges as $collegeName = $depts )
{
foreach( $depts as $deptName = $classes)
{
foreach( $classes as $className )
{
echo $collegeName, $deptName, $className\n;
}
}
}
Yes, I thought of that one too, but it's less flexible. What if you need
to add other fields to the college, or department. Then you'd need to
redo the whole structure to something more similar to what I did. Since
bruce was having issues, I gave him a flexible format that could handle
other fields if they arose.
Cheers,
Rob.
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RE: [PHP] array/iteration issue!!
both ways work...!!!
this is a really simple/quick issue to populate some test db tbls.. i've
only played with multi php arrays (sp??) in passing... and my days of being
a serious eng/software guy are long over!!
although.. with this economy!
thanks
-Original Message-
From: Robert Cummings [mailto:[EMAIL PROTECTED]
Sent: Thursday, November 27, 2008 8:40 PM
To: Micah Gersten
Cc: bruce; 'PHP General list'
Subject: Re: [PHP] array/iteration issue!!
On Thu, 2008-11-27 at 22:22 -0600, Micah Gersten wrote:
This is actually a much smaller data structure.
$colleges = array
(
'Blah Blah University' =
array
(
'physics' = array
(
'sss',
'sffgg',
),
'english' = array
(
'sss',
'sffgg',
)
),
'Glah Gleh University' =
array
(
'physics' = array
(
'sss',
'sffgg',
),
'english' = array
(
'sss',
'sffgg',
),
)
);
foreach( $colleges as $collegeName = $depts )
{
foreach( $depts as $deptName = $classes)
{
foreach( $classes as $className )
{
echo $collegeName, $deptName, $className\n;
}
}
}
Yes, I thought of that one too, but it's less flexible. What if you need
to add other fields to the college, or department. Then you'd need to
redo the whole structure to something more similar to what I did. Since
bruce was having issues, I gave him a flexible format that could handle
other fields if they arose.
Cheers,
Rob.
--
http://www.interjinn.com
Application and Templating Framework for PHP
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
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[PHP] Array of PDO objects
Hi, I want to know if I can set an array with PDO objects, thus: $foo = array(new PDO(...), new PDO(...)); $oSt = $foo[0]-prepare(...); and so on... I tried that aproach and PHP is always complaining about using prepare() in a non-object... --- .-. | Miguel J. Jiménez | | Sector Público, ISOTROL S.A.| | [EMAIL PROTECTED] | :-: | KeyID 0xFFE63EC6 hkp://pgp.rediris.es:11371 | :-: | Edificio BLUENET, Avda. Isaac Newton nº3, 4ª planta.| | Parque Tecnológico Cartuja '93, 41092 Sevilla (ESP).| | Tlfn: +34 955 036 800 (ext.1805) - Fax: +34 955 036 849 | | http://www.isotrol.com | :-: | UTM ED-50 X:765205.09 Y:4144614.91 Huso: 29 | :-: | Me dijeron: 'instala Windows, se listo'; así que | | instalé primero Windows y luego fui listo y lo borré| | para instalar Linux| '-' signature.asc Description: PGP signature
Re: [PHP] Array of PDO objects
2008/6/6 Miguel J. Jiménez [EMAIL PROTECTED]: Hi, I want to know if I can set an array with PDO objects, thus: $foo = array(new PDO(...), new PDO(...)); $oSt = $foo[0]-prepare(...); and so on... I tried that aproach and PHP is always complaining about using prepare() in a non-object... i doubt it has anything to do w/ PDO. have you tried var_dump() to inspect the contents of $foo[0] ? and also, have you tried creating the PDO instances w/ the same arguments outside of the array construct to determine if there is any difference? -nathan
RE: [PHP] array recursion from database rows
Bob, Post your failing code and we'l be glad to give you pointers on fixing it. This list doesn't exist to write code for you (unless your dropping coin into our paypal account) but all of us are willing to help with posted code. Wolf -Original Message- From: Bob [EMAIL PROTECTED] Sent: Saturday, May 24, 2008 2:25 PM To: php-general@lists.php.net Subject: [PHP] array recursion from database rows Hi. I have a database table I have created for navigation. The table fields are uid, parent_id, menu_name. Each entry is either a top level element with a parent_id of 0 or a child which has a parent_id that relates to the parent uid. What I am trying to do is recurse through a set of rows adding the child(ren) of a parent to a multi-dimensional array. Does anyone know how I can do this, I've tried (unsuccessfully) to traverse the rows to create this array but I keep failing miserably. This is probably very easy for the people on this list so I am hoping someone could help me out. Thanks in advance. Cheers. Bob -- [The entire original message is not included] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] array recursion from database rows
Hi. I have a database table I have created for navigation. The table fields are uid, parent_id, menu_name. Each entry is either a top level element with a parent_id of 0 or a child which has a parent_id that relates to the parent uid. What I am trying to do is recurse through a set of rows adding the child(ren) of a parent to a multi-dimensional array. Does anyone know how I can do this, I've tried (unsuccessfully) to traverse the rows to create this array but I keep failing miserably. This is probably very easy for the people on this list so I am hoping someone could help me out. Thanks in advance. Cheers. Bob -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] array recursion from database rows
On 5/24/08, Bob [EMAIL PROTECTED] wrote: Hi. I have a database table I have created for navigation. The table fields are uid, parent_id, menu_name. Each entry is either a top level element with a parent_id of 0 or a child which has a parent_id that relates to the parent uid. What I am trying to do is recurse through a set of rows adding the child(ren) of a parent to a multi-dimensional array. Does anyone know how I can do this, I've tried (unsuccessfully) to traverse the rows to create this array but I keep failing miserably. This is probably very easy for the people on this list so I am hoping someone could help me out. Thanks in advance. Cheers. Bob if you order your result set by record id and parent id then your set should be much easier to loop thru, when you hit an empty parent id field its a new parent and you could use the row id (or whaever) as the key and then keep adding the children until you hit a new (empty) parent id -- Bastien Cat, the other other white meat
Re: [PHP] Array pointer to a function
On Tue, Apr 8, 2008 at 12:00 AM, hce [EMAIL PROTECTED] wrote:
Hi,
Is it possible for an array to point a function:
Asignmanet
$ArrayPointer = $this-MyFunction;
Invoke:
$ArraryPointer();
i would recommend you investigate variable functions
1. http://www.php.net/manual/en/functions.variable-functions.php
so you dont exactly get functional language behavior; but you can 'pass
around a function'. so for example; if you have
?php
function someFunc() {}
/**
* then you can pass around strings that refer to it; as in
*/
$someFuncPointer = 'someFunc';
/**
* then you can call it using the variable function construct; as in
*/
$someFuncPointer(); // invoking someFunc()
?
you can pass parameters to such an invocation; as in
?php
$someFuncPointer(1, $b, $yaddaYadda);
?
and it works for object instances
?php
class MyClass { function doStuff() {} }
$b = new MyClass();
$b-doStuff();
?
and it works for static object method calls
?php
class OtherClass { static function doMoreStuff() {} }
$b = 'doMoreStuff';
?
you can also store the class name or instance in variables and it still
works. here the output of a little php -a session
?php
class M { static function b() {} function n() {} }
$m = 'M';
$b = 'b';
$m::$b();
$n = new M();
$n-b();
$n-$b();
?
and thats just the tip of the iceberg! there is also the php psuedo type
callback; and there are some other functions that are pertinent.
call_user_func(); // very similar to variable functions
call_user_func_array()
-nathan
Re: [PHP] Array pointer to a function
On Tue, 2008-04-08 at 14:00 +1000, hce wrote: Hi, Is it possible for an array to point a function: Asignmanet $ArrayPointer = $this-MyFunction; Invoke: $ArraryPointer(); No, you can't do what you've done above. What you can do is... ?php $ptr = array( 'obj' = $this, 'method' = 'MyFunction' ); $ptr['obj']-$ptr['method'](); ? Cheers, Rob. -- http://www.interjinn.com Application and Templating Framework for PHP -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] PHP: array with null shows different with print_r and var_dump
Hello,
I am new to PHP and PHP community.
Following program outputs different values with print_r and var_dump.
$array = array(null, NULL);
print_r($array); prints values like below
Array
(
[0] =
[1] =
)
where as var_dump($array) prints values like below
array(2) {
[0]=
NULL// Does this convert to null to NULL?
[1]=
NULL
}
Can you tell me why the above difference?
--
Thanks,
Sanjay Mantoor
Re: [PHP] PHP: array with null shows different with print_r and var_dump
On Tue, Apr 1, 2008 at 11:49 PM, Sanjay Mantoor
[EMAIL PROTECTED] wrote:
Hello,
I am new to PHP and PHP community.
Following program outputs different values with print_r and var_dump.
$array = array(null, NULL);
print_r($array); prints values like below
Array
(
[0] =
[1] =
)
print_r converts null, which is a variable type, like integer, string,
float, etc, into an empty string.
where as var_dump($array) prints values like below
array(2) {
[0]=
NULL// Does this convert to null to NULL?
null is case-insensitive, so it doesn't matter how you type it.
[1]=
NULL
}
var_dump converts null into the string NULL.
Can you tell me why the above difference?
--
-Casey
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