Re: [PHP] extract() question

[Jason G.]

I needed this once, but I could not figure out how to just create the vars 
in current scope.

If my_extract() is called from within a function, then the variables will 
not be available unless you declare them global (which kinda makes the 
function pointless).

Any ideas?

-Jason Garber
IonZoft.com


At 06:55 PM 11/18/2001 -0500, Joe Stump wrote:
You may want to do something like this instead:

?

   function my_extract($arr)
   {
 if(is_array($arr)  sizeof($arr))
 {
   while(list($key,$val) = each($arr)
   {
 $new_var = str_replace(' ','_',$key);
 global $$new_var;
 $$new_var = $val;
   }
 }
   }

?

--Joe


On Sun, Nov 18, 2001 at 04:21:46PM -0500, David Bernier wrote:
  There is this array which I would like to convert into a series 
 variables using the extract function:
 
  ?
  $oz = array(
   lion = courage,
   dorothy = kansas,
   scarecrow = brain
   tin man = heart);
 
  extract($oz);
  ?
 
  now, I would like to access my new variables. it is obviously easy for 
 $lion, $dorothy, and $scarecrow but it isn't for tin man.
 
  from this, I have 3 or 4 questions:
  1) has $oz[tin man] been passed into a variable?
  2) if yes, how do I access the variable that came out of $oz[tin man]?
  3) let's pretend that I have no control over the names of the keys for 
 $oz, how should I have called extract() to tell it to replace the space 
 between tin and man by a underscore character?
  4)  finally, is there a way to access and retrieve that values of the 
 symbol table without knowing their names?
 
  David
 

Joe Stump [EMAIL PROTECTED]

How would this sentence be different if pi equaled 3?


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[PHP] extract() question

[David Bernier]

There is this array which I would like to convert into a series variables using the 
extract function: 

?
$oz = array(
 lion = courage, 
 dorothy = kansas, 
 scarecrow = brain
 tin man = heart); 

extract($oz);
?

now, I would like to access my new variables. it is obviously easy for $lion, 
$dorothy, and $scarecrow but it isn't for tin man.

from this, I have 3 or 4 questions:
1) has $oz[tin man] been passed into a variable?
2) if yes, how do I access the variable that came out of $oz[tin man]?
3) let's pretend that I have no control over the names of the keys for $oz, how should 
I have called extract() to tell it to replace the space between tin and man by a 
underscore character?
4)  finally, is there a way to access and retrieve that values of the symbol table 
without knowing their names?

David

Re: [PHP] extract() question

[Joe Stump]

You may want to do something like this instead:

?

  function my_extract($arr)
  {
if(is_array($arr)  sizeof($arr))
{
  while(list($key,$val) = each($arr)
  {
$new_var = str_replace(' ','_',$key);
global $$new_var;
$$new_var = $val;
  }
}
  }

?

--Joe


On Sun, Nov 18, 2001 at 04:21:46PM -0500, David Bernier wrote:
 There is this array which I would like to convert into a series variables using the 
extract function: 
 
 ?
 $oz = array(
  lion = courage, 
  dorothy = kansas, 
  scarecrow = brain
  tin man = heart); 
 
 extract($oz);
 ?
 
 now, I would like to access my new variables. it is obviously easy for $lion, 
$dorothy, and $scarecrow but it isn't for tin man.
 
 from this, I have 3 or 4 questions:
 1) has $oz[tin man] been passed into a variable?
 2) if yes, how do I access the variable that came out of $oz[tin man]?
 3) let's pretend that I have no control over the names of the keys for $oz, how 
should I have called extract() to tell it to replace the space between tin and 
man by a underscore character?
 4)  finally, is there a way to access and retrieve that values of the symbol table 
without knowing their names?
 
 David
 

Joe Stump [EMAIL PROTECTED]

How would this sentence be different if pi equaled 3? 




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