Re: [PHP] $$var

As per my experience so far, there is no such depth limit existing. The only limit is imposed by the system resources (like script execution time etc.) but not by PHP. Cheers NetEmp On Sun, Mar 6, 2011 at 8:42 PM, shiplu wrote: > Just being curious, I have a question. > How many times PHP inter

Re: [PHP] $$var

If $a = 'foo' and $$a = nothing (i.e. no value assigned to $foo) you will get an error if you tried to use this to do something else. On Sun, Mar 6, 2011 at 3:21 PM, tedd wrote: > At 6:42 PM +0530 3/6/11, Ashim Kapoor wrote: > >> Dear All, >> >> I was reading the php manual for session_register,

Re: [PHP] $$var

At 6:42 PM +0530 3/6/11, Ashim Kapoor wrote: Dear All, I was reading the php manual for session_register, and I found the following line there : - $_SESSION[$var] = $$var; Why do I need $$ there ? Can someone explain? Thank you, Ashim Ashim: You don't need to user session_register(). Che

Re: [PHP] $$var

∞ 2011/3/6 shiplu > Just being curious, I have a question. > How many times PHP interpreter will replace this variables? I mean how deep > it will be? > > If I use variable variables like > > $$a > how long i

Re: [PHP] $$var

Just being curious, I have a question. How many times PHP interpreter will replace this variables? I mean how deep it will be? If I use variable variables like $$a how long it will be evaluated? -- Shiplu Mok

Re: [PHP] $$var

> Hi Ashim, > > These are called Variable Variables. Ideally they should be avoided, > as they introduce unnecessary legibility issues. > > This is what it does in a nutshell, it's actually quite simple: > > $foo = 'bar'; > $bar = 'foobar'; > echo $$foo;//This prints foobar > > What it does is,

Re: [PHP] $$var

Hi Ashim, These are called Variable Variables. Ideally they should be avoided, as they introduce unnecessary legibility issues. This is what it does in a nutshell, it's actually quite simple: $foo = 'bar'; $bar = 'foobar'; echo $$foo;//This prints foobar What it does is, take the value of $

[PHP] $$var

Dear All, I was reading the php manual for session_register, and I found the following line there : - $_SESSION[$var] = $$var; Why do I need $$ there ? Can someone explain? Thank you, Ashim

Re: [PHP] Var within a var

This one time, at band camp, bob pilly <[EMAIL PROTECTED]> wrote: > Hi All > > Im trying to store a document template in mysql that has php var names > within it and then find it in the datebase and print it out with the var > names replaced with the var v

[PHP] Var within a var

Hi All Im trying to store a document template in mysql that has php var names within it and then find it in the datebase and print it out with the var names replaced with the var values. e.g i have this stored Dear $title $name we would like to.. I declare the vars $title and

Re: [PHP] var references question

* Thus wrote Brandon Goodin: > Greetings, > > > In the following example when I run the myscript.php I pass the $myarr into > the addVal function of the MyClass class. The var_dump in the addVal > function appropriately displays all of the elements of the array a,b,c and > d. However, the var_du

[PHP] var references question

Greetings, This is a little difficult to explain. So, below is an example I will work from. Forgive my ignorance here. I am a java developer using php4 and trying to figure out a particular scenario. In the following example when I run the myscript.php I pass the $myarr into the addVal func

Re: [PHP] var references

Thanks!, my syntax was a bit off, havn't had much sleep, but it kept slipping by me ;) Chris W. Parker wrote: Arthur Pelkey on Friday, February 06, 2004 9:46 AM said: $blat = $tue_5a; [snip] while($row = mysql_fetch_array($result)) { switch($blat) {

RE: [PHP] var references

Arthur Pelkey on Friday, February 06, 2004 9:46 AM said: > $blat = $tue_5a; [snip] > while($row = mysql_fetch_array($result)) { > switch($blat) { > case tue_5a: > $min_1 = $row[29]; > break; > } [snip] > Why can I not

[PHP] var references

I have the following: $blat = $tue_5a; $result = mysql_query("SELECT * FROM classes WHERE c_d_tue='1' AND c_s_tue_1_hr='5' AND c_s_tue_1_dn='am'"); while($row = mysql_fetch_array($result)) { switch($blat) { case tue_5a: $min_1 = $row[29]; break; } ?> class title:"> class minut

RE: [PHP] /VAR is driving me crazy - SOLVED

y 16, 2004 5:07 PM To: Boaz Yahav Cc: [EMAIL PROTECTED] Subject: Re: [PHP] /VAR is driving me crazy Boaz Yahav wrote: > Hi > > Does anyone have an idea what is so special about the string "/VAR" ? > If i create a form that submits to a php file and in the form i put >

Re: [PHP] /VAR is driving me crazy

Boaz Yahav wrote: Hi Does anyone have an idea what is so special about the string "/VAR" ? If i create a form that submits to a php file and in the form i put the string /VAR anywhere in the text or just /VAR I get an 404 error from apache on an existing file. If i take the same form and remove th

[PHP] /VAR is driving me crazy

Hi Does anyone have an idea what is so special about the string "/VAR" ? If i create a form that submits to a php file and in the form i put the string /VAR anywhere in the text or just /VAR I get an 404 error from apache on an existing file. If i take the same form and remove the /VAR string all

[PHP] var check not working...

For some reason this will not work... my $_POST variables check for no form variables and display a form... if they choose an item from a select box it queries the database for a field matching the $_post var and builds a new form creating 8 separate $_post variables to check for.. so far it wo

Re: [PHP] Trying to submit form to frame and pass php var

to submit form to frame and pass php var at the same time. <!-- function submitform(){ top.admin.document.adminform.submit(); } //--> and... Link look like: Delete What I need to do though, is run this exact script while passing ($delete=yes) as php at the same time? Basically, r

[PHP] Trying to submit form to frame and pass php var

Hello I was wondering if someone could help me out. Trying to submit form to frame and pass php var at the same time. <!-- function submitform(){ top.admin.document.adminform.submit(); } //--> and... Link look like: Delete What I need to do though, is run this exact script

Re: [PHP] var static

nguage.variables.scope.php (espero que te sirva) saludos aniceto lópez :: DYNAMICAL.BIZ web development & host services Barcelona - Spain -Mensaje original- Asunto: [PHP] var static I want to obtain only one instance of one class. In other to do that, I call to a static method, that creates

Re: [PHP] var static

Globals!? YUCK :) A better solution IMHO that maintains encapsulation, is to use a static var in a function: function &getClassVar( $name ) { return getAndSetClassVar( $name, false ); } function &setClassVar( $name, $value ) { return getAndSetClassVar( $name, true, $value ); } function &

Re: [PHP] var static

et/manual/en/language.variables.scope.php (espero que te sirva) saludos aniceto lópez :: DYNAMICAL.BIZ web development & host services Barcelona - Spain -Mensaje original- Asunto: [PHP] var static I want to obtain only one instance of one class. In other to do that, I call to a

Re: [PHP] var static

Hi, Friday, August 29, 2003, 3:01:45 AM, you wrote: AM> I want to obtain only one instance of one class. In other to do that, I call AM> to a static method, that creates the instance(if it doesnt exit) or returns AM> the reference of the instance. AM> The call to the static method is the next: AM

RE: [PHP] var static

pain -Mensaje original- Asunto: [PHP] var static I want to obtain only one instance of one class. In other to do that, I call to a static method, that creates the instance(if it doesnt exit) or returns the reference of the instance. The call to the static method is the next: $conexiond

[PHP] var static

I want to obtain only one instance of one class. In other to do that, I call to a static method, that creates the instance(if it doesnt exit) or returns the reference of the instance. The call to the static method is the next: $conexiondb=db::getInstancia(); Well, but if I call to db::getInsta

[PHP] var static

I want to obtain only one instance of one class. In other to do that, I call to a static method, that creates the instance(if it doesnt exit) or returns the reference of the instance. The call to the static method is the next: $conexiondb=db::getInstancia(); Well, but if I call to db::getInsta

Re: [PHP] Evaluate PHP var in stored sql statement?

lp Maxim. > > > > I've got quite a bit to learn. PHP is far more challenging than Cold > > Fusion. > > > > --Noah > > > > - Original Message - > > From: "Maxim Maletsky" <[EMAIL PROTECTED]> >

Re: [PHP] Evaluate PHP var in stored sql statement?

> --Noah > > - Original Message - > From: "Maxim Maletsky" <[EMAIL PROTECTED]> > To: "Noah" <[EMAIL PROTECTED]> > Cc: <[EMAIL PROTECTED]> > Sent: Friday, January 24, 2003 11:02 AM > Subject: Re: [PHP] Evaluate PHP var in stored sq

Re: [PHP] Evaluate PHP var in stored sql statement?

: Friday, January 24, 2003 11:02 AM Subject: Re: [PHP] Evaluate PHP var in stored sql statement? > > eval takes the string and executes PHP in that string. So, > > eval("\$myrow[2] = \"$myrow[2]\";"); > > is equivalent to: > > $myrow[2] = "$myrow[

Re: [PHP] Evaluate PHP var in stored sql statement?

> From: "Noah" <[EMAIL PROTECTED]> > To: <[EMAIL PROTECTED]> > Sent: Friday, January 24, 2003 4:39 PM > Subject: Re: [PHP] Evaluate PHP var in stored sql statement? > eval("\$myrow[2] = \"$myrow[2]\";"); > > What's the dea

Re: [PHP] Evaluate PHP var in stored sql statement?

; From: "Maxim Maletsky" <[EMAIL PROTECTED]> > To: "CF High" <[EMAIL PROTECTED]> > Cc: <[EMAIL PROTECTED]> > Sent: Friday, January 24, 2003 9:59 AM > Subject: Re: [PHP] Evaluate PHP var in stored sql statement? > > > > > > use eval() &

Re: [PHP] Evaluate PHP var in stored sql statement?

l php to evaluate the string as php code; i.e. text without quotes? Thanks for the help... --Noah - Original Message - From: "Maxim Maletsky" <[EMAIL PROTECTED]> To: "CF High" <[EMAIL PROTECTED]> Cc: <[EMAIL PROTECTED]> Sent: Friday, January 24, 2003

Re: [PHP] Evaluate PHP var in stored sql statement?

use eval() www.php.net/eval -- Maxim Maletsky [EMAIL PROTECTED] "CF High" <[EMAIL PROTECTED]> wrote... : > Hey all. > > I need to find out how to get PHP to evaluate a PHP variable stored in our > MySql database. > > Currently the variable is being read as a string; i.e. select * from tab

[PHP] Evaluate PHP var in stored sql statement?

Hey all. I need to find out how to get PHP to evaluate a PHP variable stored in our MySql database. Currently the variable is being read as a string; i.e. select * from table where column = $myrow[0] -- instead of evaluating $myrow[0] as a variable. The SQL statement is retrieved in the first c

RE: [PHP] Var question

Thanks guys.. I am moving away from ColdFusion to PHP and so I still forget about the isset() function. -Original Message- From: 1LT John W. Holmes [mailto:holmes072000@;charter.net] Sent: Thursday, October 24, 2002 8:53 AM To: [EMAIL PROTECTED]; [EMAIL PROTECTED] Subject: Re: [PHP] Var

Re: [PHP] Var question

is go a variable that is passed via post? I guess yes but you get this error without submitting yet. There are three solutions: 1. Change your error reporting level to 55: error_reporting(55). This will stop warning your undefined variables. 2. Prefix the variable with an at-mark: @$_POST['go

Re: [PHP] Var question

You can just check for if(isset($_POST['go'])) You don't really care what the value is since it's just a button. ---John Holmes... - Original Message - From: "Clint Tredway" <[EMAIL PROTECTED]> To: <[EMAIL PROTECTED]> Sent: Thursday, O

[PHP] Var question

I am building a form that posts to itself. I have the following to detect the submit button being clicked: If($_POST["go"] == "add link") I am getting a warning that says 'go' is undefined. How do I define this? Thanks, Clint -- PHP General Mailing List (http://www.php.net/) To unsubscribe,

[PHP] var-vars question

Hi folks, Linux, PHP3 I have the following problem: I have an object, which creates a form, wherein there are selects, which names accord to values in the database. But I didn´t get it to have a variable var, I´m sure it´s just a small thing, but I cannot see it Any suggestions ? TIA Oliver ec

Re: [PHP] $var , '$var'

[EMAIL PROTECTED]> Sent: Sunday, August 19, 2001 4:33 PM Subject: [PHP] $var , '$var' > > hi. > what is the difference between $var and '$var' ?/ > thanks. > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, e-mail: [EMAIL

Re: [PHP] $var , '$var'

--- Original Message - From: nafiseh saberi <[EMAIL PROTECTED]> To: <[EMAIL PROTECTED]> Sent: Sunday, August 19, 2001 2:33 AM Subject: [PHP] $var , '$var' | | hi. | what is the difference between $var and '$var' ?/ | thanks. | | -- | PHP General Mailing List (h

[PHP] $var , '$var'

hi. what is the difference between $var and '$var' ?/ thanks. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]

[PHP] Re: javascript var on a php var...

Romeo Manzur wrote: > > hi, I want to know how could I save a javascript variable on a php > variable??? > Thanks... It depends how the user will get to the php page: 1. Form If the user is about to submit a form and you want some Javascript variable from your page to end up as a php variable

RE: [PHP] javascript var on a php var...

window.location = 'http://url?yourVar=' + yourVar; > -Original Message- > From: Romeo Manzur [mailto:[EMAIL PROTECTED]] > Sent: 5 iulie 2001 07:56 > To: [EMAIL PROTECTED] > Subject: [PHP] javascript var on a php var... > > > hi, I want to know how cou

[PHP] javascript var on a php var...

hi, I want to know how could I save a javascript variable on a php variable??? Thanks... -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTE

Re: [PHP] var question

You can also look at environment variable $QUERY_STRING. For example, if ($HTTP_SERVER_VARS['QUERY_STRING'] == 'login') { ...do log in procedure If register_globals is on, all you need is if ($QUERY_STRING == 'login') If you might be passing other parameters

Re: [PHP] var question

Note: Yes, I meant string instrument. Any references to YoYo Ma will be dealt with swiftly and severly. -- Plutarck Should be working on something... ...but forgot what it was. ""Plutarck"" <[EMAIL PROTECTED]> wrote in message 9bfp5e$169$[EMAIL PROTECTED]">news:9bfp5e$169$[EMAIL PROTECTED]...

Re: [PHP] var question

ple think I just do it to annoy them. I just like the way "viola" sounds :) Plutarck Should be working on something... ...but forgot what it was. - Original Message - From: "Brian Clark" <[EMAIL PROTECTED]> To: "Plutarck" <[EMAIL PROTECTED]> Sent:

Re: [PHP] var question

Add an "=" on the end of your url. Viola. -- Plutarck Should be working on something... ...but forgot what it was. ""Jeroen Geusebroek"" <[EMAIL PROTECTED]> wrote in message [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... > Hi Guys, > > I have a question about the way PHP handles var/strings. > >

[PHP] var question

Hi Guys, I have a question about the way PHP handles var/strings. Let's say i have this URL: http://foo.bar.com/?login. And in my script i have this code: if($login) { echo "blab"; } or if(isset($login)) { echo "blab"; } It always returns FALSE. I think that is because the string is empty. Sh

RE: [PHP] VAR and variables

At 10:50 AM + 1/29/01, Tim Ward wrote: > > -Original Message- >> From: Steve Edberg [mailto:[EMAIL PROTECTED]] >> Sent: 25 January 2001 22:02 >> To: Matt; [EMAIL PROTECTED] >> Subject: Re: [PHP] VAR and variables >> >> >> At

Re: [PHP] VAR and variables

At 3:00 PM -0600 1/25/01, Matt wrote: >I have a question that may seem kind of silly, but I'm curious... > >When using PHP why would one use "var" to define a variable as >opposed to just regularly creating it? Because that's the way it is ;). The var is part of the syntax of a class definitio

[PHP] VAR and variables

I have a question that may seem kind of silly, but I'm curious... When using PHP why would one use "var" to define a variable as opposed to just regularly creating it? For example, if I have a class defined as below: class Simple { var $a; function Simple() { $this->a = 5; }