[PHP] Re: Thread-Hijacking (was: Re: [PHP] Fwd: Is it possible???)

2013-06-25 Thread Maciek Sokolewicz
On 25 June 2013 10:02, Tamara Temple  wrote:

> Maciek Sokolewicz  wrote:
> > Please please please please don't do this!
>
> Please Please Please Do Not Hijack Threads.
>

Hijacking would be starting a completely different discussion in the same
thread. This wasn't a discussion-starter, rather a warning ;)

- Tul


[PHP] Thread-Hijacking (was: Re: [PHP] Fwd: Is it possible???)

2013-06-25 Thread Tamara Temple
Maciek Sokolewicz  wrote:
> Please please please please don't do this!

Please Please Please Do Not Hijack Threads.

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Re: [PHP] Fwd: Is it possible???

2013-06-24 Thread php
On Mon, Jun 24, 2013 at 06:17:33PM +0200, Maciek Sokolewicz wrote:

> Please please please please don't do this!

1) You did not answer the question, nor giving any related information.

2) This was debug-output. I see not point in optimizing.

3) print is language construct, just as is echo

4) the argument to print is converted to string anyways, so ...

5) the quotes around a single variable allows fast adding helping text while 
debugging; so it was on purpose


You are not the only one that has a coding style for a reason.


So back to topic: I guess the case-sensitive variables were the most helpfull 
hint for the 
thread-starter?

If not please send a complete example of your code.

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Re: [PHP] Fwd: Is it possible???

2013-06-24 Thread Marco Behnke



Am 24.06.2013 18:17, schrieb Maciek Sokolewicz:

On 24-6-2013 14:27, n...@nobswolf.info wrote:

You should give a complete programm so we can run exactly
the same you do, like this:


Please please please please don't do this!

First of all, I don't know why you would use the print *function* when
you can also use the echo language construct (better and faster). But



read and learn http://de2.php.net/manual/en/function.print.php

print is not actually a real function (it is a language construct)

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Re: [PHP] Fwd: Is it possible???

2013-06-24 Thread Carlos Medina

Amen!




Am 24.06.2013 18:17, schrieb Maciek Sokolewicz:
> On 24-6-2013 14:27, n...@nobswolf.info wrote:
>> You should give a complete programm so we can run exactly
>> the same you do, like this:
>>
>> >
>> $item_amount_in_store = 223;
>>
>> print ("$item_amount_in_store");
> Please please please please don't do this!
> 
> First of all, I don't know why you would use the print *function* when
> you can also use the echo language construct (better and faster). But
> that's not that important; it's not bad to use it, just imo a bit ugly
> (pet peeve ;)).
> 
> But more importantly:
> "$variable" is completely and utterly useless. You're basically creating
> a string, interpolating a variable in it, and adding no more content.
> This is effectively the same as saying:
> print("".$var."")
> Does that look right to you? To me it looks... wrong...
> 
> Why not just a simple:
> echo $var;
> or
> print($var) if you really must.
> 
> And if you really really must cast the variable to a string, you can
> always use the explicit:
> (string) $var
> 
>>
>> $update_amount = 7;
>> $item_amount_in_store += $update_amount;
>>
>> print (" + $update_amount = $item_amount_in_store  ");
>> ?>
>>
>> which gives this result:
>>
>> 223 + 7 = 230
>>
> 


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Re: [PHP] Fwd: Is it possible???

2013-06-24 Thread Maciek Sokolewicz

On 24-6-2013 14:27, n...@nobswolf.info wrote:

You should give a complete programm so we can run exactly
the same you do, like this:


Please please please please don't do this!

First of all, I don't know why you would use the print *function* when 
you can also use the echo language construct (better and faster). But 
that's not that important; it's not bad to use it, just imo a bit ugly 
(pet peeve ;)).


But more importantly:
"$variable" is completely and utterly useless. You're basically creating 
a string, interpolating a variable in it, and adding no more content. 
This is effectively the same as saying:

print("".$var."")
Does that look right to you? To me it looks... wrong...

Why not just a simple:
echo $var;
or
print($var) if you really must.

And if you really really must cast the variable to a string, you can 
always use the explicit:

(string) $var



$update_amount = 7;
$item_amount_in_store += $update_amount;

print (" + $update_amount = $item_amount_in_store  ");
?>

which gives this result:

223 + 7 = 230




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Re: [PHP] Fwd: Is it possible???

2013-06-24 Thread Sachin Raut
variables are case-sensitive.

$item_amount_in_store is different from
$item_amount_in_Store

1st variable contains all lowercase characters, while the 2nd one contains
"S" uppercase character.

happy coding
sachin




On Mon, Jun 24, 2013 at 5:32 PM, Karl-Arne Gjersøyen wrote:

> Error in my last post This is corrected:
>
> $item_amount_in_store = 223;
> $update_amount = 7;
> $item_amount_in_Store += $update_amount;
>
> It show the result = 227 and not 230. Why is this happen?
>
> Karl
>
> -- Forwarded message --
> From: Karl-Arne Gjersøyen 
> Date: 2013/6/24
> Subject: Is it possible???
> To: PHP Mailinglist 
>
>
> $item_amount_in_store = 223;
> $update_amount = 7;
> $update_item_amount_in_store += $update_amount;
> $update_amoint_in_store is now 227;
>
> Why? That should be 230!
>
> Karl
>
>
>
> --
> Hjemmeside: http://www.karl-arne.name/
>


Re: [PHP] Fwd: Is it possible???

2013-06-24 Thread nobs
You should give a complete programm so we can run exactly
the same you do, like this:



which gives this result:

223 + 7 = 230

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Re: [PHP] Fwd: Is it possible???

2013-06-24 Thread Stuart Dallas
On 24 Jun 2013, at 13:02, Karl-Arne Gjersøyen  wrote:

> Error in my last post This is corrected:
> 
> $item_amount_in_store = 223;
> $update_amount = 7;
> $item_amount_in_Store += $update_amount;
> 
> It show the result = 227 and not 230. Why is this happen?

Something else is going on to give you 227, but variable names are case 
sensitive which is why you're not getting what you expect.



Output:

int(223)
int(7)

-Stuart

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> -- Forwarded message --
> From: Karl-Arne Gjersøyen 
> Date: 2013/6/24
> Subject: Is it possible???
> To: PHP Mailinglist 
> 
> 
> $item_amount_in_store = 223;
> $update_amount = 7;
> $update_item_amount_in_store += $update_amount;
> $update_amoint_in_store is now 227;
> 
> Why? That should be 230!
> 
> Karl
> 
> 
> 
> -- 
> Hjemmeside: http://www.karl-arne.name/


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