On Aug 4, 2:24 pm, Liviu Timar wrote:
> var Dynamic = Class.create({
> initialize: function(selector, container, script)
> {
> this.selector = selector;
> this.script = script;
> this.container = container;
>
>
Thank you for the response. You're right, I declared another variable
and now it works fine.
I have two other problems, though: I can't pass an aditional argument
to the event handler(changeContent) and I can't figure out how can I
make the content change automatic...
On Aug 5, 11:33 am, ColinFin
>
> $(div).update(thereturn);
>
That did the trick!
It's true that I don't make as much use of prototype as I could or
should. Most of the js/ajax on the site is written from scratch (way
back when I was learning how to use ajax). I added prototype later on
to do some of the 'bells and whist
Hi,
I am trying to setup some basic Ajax framework, and I was thinking to
use Ajax.Responders to intercept some events, but I meet the following
issues :
- First, it seems that the responders ignore an onSuccess() callback
passed through Ajax.Responders.register().
This may be a documentation err
Depending on when you wanted to pass the additional argument you could
just attach it to the argument chain on bind
this.changeContent = this.changeContent.bindAsEventListener(this,
extraArgument);
Since we're already looking at that line of code, be careful,
reassigning the function to a bound
Try adding e.preventDefault(); instead of Event.stop(e) and let me
know if that works?
On Tue, Aug 4, 2009 at 4:55 PM, Ash wrote:
> function callProcBasketEmail(e) {
> var pars = Form.serialize('email-form');
> var myAjax = new Ajax.Updater('email-response',
> 'procBasketEmail.php', {
>
Hi, I wasn't sure whether you meant in the 1st or second function, but
it doesn't make a difference in either.
I think it is the Event.observe('password-form', 'submit',
callProcBasketPassword); which is not working properly, although I
don't know how to debug it
On Aug 5, 6:48 pm, DJ Mangus w
Hello.
My problem when is apparent on my page. The div to be updated (and
link) are a long way down the page so users have to scroll down.
When they press the link and thus update the div the browsers scroller
returns to top, forcing the user to scroll down again to the div.
Is there any "quickfix
Can you explain it a bit better please... i cant really understand what you
mean by that
Thanks
Alex Mcauley
http://www.thevacancymarket.com
- Original Message -
From: "DJJQ"
To: "Prototype & script.aculo.us"
Sent: Wednesday, August 05, 2009 8:22 PM
Subject: [Proto-Scripty] Browser s
Oh my god my english was terrible in my post, sorry about that.
I'll try to explain the problem again:
On my php page I have a link a long way down the page, so users have
to scroll down a bit. the link triggers an ajax.update on the page.
When users press the link the browser returns to the top o
Maybe this might help. http://www.prototypejs.org/api/element/scrollto
On Wed, Aug 5, 2009 at 1:33 PM, DJJQ wrote:
>
> Oh my god my english was terrible in my post, sorry about that.
> I'll try to explain the problem again:
> On my php page I have a link a long way down the page, so users have
>
Are you getting any Javascript errors? Note: firefox and firebug is
your friend. Don't forget to break on all errors.
On Wed, Aug 5, 2009 at 11:22 AM, Ash wrote:
>
> Hi, I wasn't sure whether you meant in the 1st or second function, but
> it doesn't make a difference in either.
>
> I think it is
what does the link look like ?
Click me
Like that ?
Alex Mcauley
http://www.thevacancymarket.com
- Original Message -
From: "DJJQ"
To: "Prototype & script.aculo.us"
Sent: Wednesday, August 05, 2009 9:33 PM
Subject: [Proto-Scripty] Re: Browser scroller position after Ajax.Update
Yes that's right. Maybe that's the problem, should I javascript:null
it?
On Aug 5, 10:40 pm, "Alex McAuley"
wrote:
> what does the link look like ?
>
> Click me
>
> Like that ?
>
> Alex Mcauleyhttp://www.thevacancymarket.com
>
>
>
> - Original Message -
> From: "DJJQ"
> To: "Prototype &
Sorry, I forgot to specify. This is the code:
getContent: function()
{
var dyn = this;
new Ajax.Request(this.script, {
onSuccess: function(req)
{
dyn.content = req.respo
Nope...
If you are observing the click with observe()
just call Event.stop(event); on it
Example.
$('myHref').observe('click',function(event) {
Event.stop(event);
Your ajax code here.
});
That way it will degrade in browsers not having javascript and they will
just goto the href of
When I set firebug to break on all errors...
Submit the first form and I get (from prototype.js)
function getEventID(element) {
element is null3936 if (element._prototypeEventID) return
element._prototypeEventID[0]; (element is null error)
if I step past it and submit the second form I get the
Seems the element does not exist...
Does it exist in the DOM ?
Alex Mcauley
http://www.thevacancymarket.com
- Original Message -
From: "Ash"
To: "Prototype & script.aculo.us"
Sent: Wednesday, August 05, 2009 10:04 PM
Subject: [Proto-Scripty] Re: Beginners question, trouble with Event
when Firebug breaks on the error, check the DOM tab to see the
state at that particular moment.
On Wed, Aug 5, 2009 at 2:05 PM, Alex
McAuley wrote:
>
> Seems the element does not exist...
>
> Does it exist in the DOM ?
>
>
> Alex Mcauley
> http://www.thevacancymarket.com
> - Original Message
Sorry, i'm quite new to this, should I be looking for the form
id=password-form element in the DOM, not sure where to look for it in
the DOM tab of firebug?
Is this correct?
On Aug 5, 10:06 pm, DJ Mangus wrote:
> when Firebug breaks on the error, check the DOM tab to see the
> state at that pa
actually just checked firebug, best place would be html tab. DOM tab
lists the entire DOM which would be very hard to go through.
On Wed, Aug 5, 2009 at 2:12 PM, Ash wrote:
>
> Sorry, i'm quite new to this, should I be looking for the form
> id=password-form element in the DOM, not sure where to
yes, when I check the HTML tab, the form with the id=password-form has
not been created within the email-response div, even though I have
waited to check for it with the onSuccess line
EG
function callProcBasketEmail(e) {
var pars = Form.serialize('email-form');
var myAjax = new Ajax.Upd
good question. You might change Event.observe( . . . etc to
Event.observe.defer( . . . and see if that fixes it. Odd that the
node isn't available in the DOM at onSuccess but that might work
around it while I research.
On Wed, Aug 5, 2009 at 2:22 PM, Ash wrote:
>
> yes, when I check the HTML t
Thank you for your solution, but instead I changed to and it works like a charm.
On Aug 5, 11:00 pm, "Alex McAuley"
wrote:
> Nope...
>
> If you are observing the click with observe()
> just call Event.stop(event); on it
>
> Example.
>
> $('myHref').observe('click',function(event) {
> Event.st
That seems to be working!
Is Event.observe.defer a standard method, or is it only to be used in
certain cases?
I'm happy that it's working but I would really like to learn the
basics properly.
Thanks anyway for getting me up and running!
Ashley
On Aug 5, 10:32 pm, DJ Mangus wrote:
> good ques
The only problem with that solution is you provide no degradation to
people without javascript.
On 8/5/09, DJJQ wrote:
>
> Thank you for your solution, but instead I changed to href="javascript:null()"> and it works like a charm.
>
> On Aug 5, 11:00 pm, "Alex McAuley"
> wrote:
>> Nope...
>>
>
Kind of a hack but function.defer is useful in many other contexts.
On 8/5/09, Ash wrote:
>
> That seems to be working!
>
> Is Event.observe.defer a standard method, or is it only to be used in
> certain cases?
>
> I'm happy that it's working but I would really like to learn the
> basics properl
Ajax is Asyncronous so it gets executed along with other script ...
ergo its not serial like php and other stuff your prolly used to...
you can make a request synconous (script waits for the ajax request to
finish before continuing but its not recommended
Alex Mcauley
http://www.thevacancymark
yes but onSuccess shouldn't be called until after the ajax.updater is
completed. Therefore the DOM node should be available at that point.
On Wed, Aug 5, 2009 at 2:40 PM, Alex
McAuley wrote:
>
> Ajax is Asyncronous so it gets executed along with other script ...
> ergo its not serial like php a
Ok. I thought everyone had javscript by now :)
On Aug 5, 11:39 pm, DJ Mangus wrote:
> The only problem with that solution is you provide no degradation to
> people without javascript.
>
> On 8/5/09, DJJQ wrote:
>
>
>
>
>
>
>
> > Thank you for your solution, but instead I changed to > href="ja
I figured it out. I understand that the extra argument will be null
because it doesn't exist when the link is being clicked. The solution
I found was to make my own attribute "count" for the element: . This attribute can be read by using
readAttribute in the changeContent function.
After I will
I wonder why in this case, that onSuccess is executed before the DOM
node has been created.
Using a hack is okay to get me up and running but I would like to know
how to use ajax methods correctly
On Aug 5, 10:48 pm, DJ Mangus wrote:
> yes but onSuccess shouldn't be called until after the ajax.
pretty much yes but some shut it off for security reasons
On Wed, Aug 5, 2009 at 3:01 PM, DJJQ wrote:
>
> Ok. I thought everyone had javscript by now :)
>
> On Aug 5, 11:39 pm, DJ Mangus wrote:
>> The only problem with that solution is you provide no degradation to
>> people without javascript.
OK, just checked the source. onComplete is where ajax.updater
actually updates the node. onSuccess is called before that.
Workaround is to either a.) use defer like you did, or b.) use
Ajax.request and update it yourself onSuccess, then do your
Event.observe.
Plusses of option b is that it won'
Do you mean to use
function callProcBasketEmail(e) {
var pars = Form.serialize('email-form');
var myAjax = new Ajax.Updater('email-response',
'procBasketEmail.php', {
method: 'post',
parameters: pars,
onComplete: function(response)
{
Event.obser
I honestly think the defer is best at this point as oncomplete occurs
even on failed requests. Your choices are to rewrite your own stuff
instead of prototype functions (ie. Do your own success checks or do
your own updating) or just stick with defer.
On 8/5/09, Ash wrote:
>
> Do you mean to use
Hi
I have observer set for the whole document to catch click events on
links (a href) and prevent default action (open page from href,
event.stop). It works correct, but ... now I have onclick event
defined inside of each a-herf element and I need to catch/prevent this
event too. How to do that? I
Hi All,
I have a strange behavior with a pice of code I wrote using the latest
prototype release, here it is:
==
var debug = $('debug');
new Ajax.Request("http://twitter.com/statuses/
public_timeline.json", {
method: 'get',
onLoading: function(){
de
Dear all
I am new to javascript and prototype. I have difficulty in writing
function() in prototype because I am confused that function can be one
of the parameter..i.e. some_function(abc, function())
I have the following code, the two observe functions actually doing
the same thing, only with d
Best to try removing those at dom:loaded, maybe with something like
this:
document.observe('dom:loaded',function(){
$$(a).each(function(elm){elm.onclick = null});
});
That's just a guess...
But as far as I know, you can't stop these inline event handlers any
other way.
Walter
On A
Unless you work at Twitter, this will run afoul of the Single Origin
Policy, and you can't do this. (Ajax requests have to stick to the
domain and port that they are run from for their content.) If you
create a simple proxy and run it on your server, then you could
request /mytwitterproxy.
Hi,
One of the few good things about those old-style handlers is that
they're attributes, so finding the links is easy:
var hookedlinks = $$('a[onclick]');
Then if your goal is to remove the handler:
var n;
for (n = hookedlinks.length - 1; n >= 0; --n) {
hookedlinks[n].onclick = null;
}
O
Walter...
The link in his post describes how to do XDR in FF3.5!
Alex Mcauley
http://www.thevacancymarket.com
- Original Message -
From: "Walter Lee Davis"
To:
Sent: Thursday, August 06, 2009 6:27 AM
Subject: [Proto-Scripty] Re: HTTP OPTION REQUEST with FireFox 3.5
>
> Unless you wo
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