Re: [Proto-Scripty] Re: enumerate hash
I'm sorry, but I don't understand your questions.
Maybe I can explain what these lines say:
1- this is a loop, like : "Take every pair of the Hash referenced as
HashtoBeTested"
Remember that a Hash is a collection of pairs. Each pair is composed of a key
and a value
2- for every pair, compare the value of the pair with ValueToTest
3- if they are equal, then remove this pair from the Hash
For such a removal, you have to identify the pair by its key, and not by its
value
Hope this helps,
Le 14 avr. 2010 à 15:38, chrysanthe m a écrit :
> Hi Christophe
> Thanks, but is there anything more to the syntax. Also how do you use that
> optional context parameter with this within the loop and for what enhanced
> value/processing does it give you?
>
> On Mon, Apr 12, 2010 at 4:59 AM, Christophe Decaux
> wrote:
> If I understand well, what you're asking for is pretty close to what you
> suggested in your original post:
>
> hashToBeTested.each(function(pair){
> if(valueToTest==pair.value){
> hashToBeTested.unset(pair.key);
> }
> }
>
>
> Christophe
>
> Le 10 avr. 2010 à 12:36, chrysanthe m a écrit :
>
>> Hi, again
>> Sorry for being obtuse. But can someone help me and even understand how to
>> write a function and call it on a hash that will take a value, compare it
>> against each of the keys in the hash, on match delete the key/value, and
>> return the hash. tia.
>>
>> On Thu, Apr 8, 2010 at 5:24 PM, chrysanthe m wrote:
>> Hi Alex
>> Thanks, but a newbie here so that was "drinking at a firehose". Let me
>> parse it to better understand.
>> First can you really invoke on two separate enumerable objects with that
>> [n,n1,n2] syntax? That is tremendous.
>> My problem is I need to first check the presence of a key before I unset it
>> b/c I found out unset-ing a non-existent key seems to zero the struct; also
>> it is more courteous, grin. So how would I construct the and parameterize
>> the annonymous function to do the check and if present "do it to itself".
>> Ideally I would like to pass in the enumerable, call the function and return
>> the modified(or not) enumerable in the function's return.
>>
>> On Thu, Apr 8, 2010 at 4:41 PM, Alex Wallace wrote:
>> Ah, I see. You can handle this using Enumerable's invoke. This code should
>> make it clear:
>>
>> a = new Hash({ x : "foo", y : "bar" });
>> b = new Hash({ x : "zam", y : "moof" });
>> a.get("x");
>> "foo"
>> b.get("x");
>> "zam"
>> [a,b].invoke("get","x");
>> ["foo", "zam"]
>> [a,b].invoke("unset","x")
>> ["foo", "zam"]
>> a.get("x")
>> (undefined)
>>
>> Cheers,
>> Alex
>>
>> On Thu, Apr 8, 2010 at 3:24 PM, chrysanthe m wrote:
>> Sorry sudden send resume in this reply
>>
>> Hello
>> I am having a difficult time trying to enumerate a hash to determine if a
>> give key is in the hash and if so delete it and its value.
>> If I could approach it index it would be
>> function remove(valueToTest, hashToBeTested){
>>for(i=0;i> if(valueToTest==hashToBeTested[i]) hashToBeTested.unset(valueToTest);
>>}
>>
>> Would I do it like
>>
>> hashToBeTested.each(function(valueToTest){
>> if(valueToTest==this)hashToBeTested.unset(valueToTest);
>> },hashToBeTested);
>> return hashToBeTested;
>>
>>
>> which I am sure is wrong syntactically if not semantically. Can someone
>> guide the proper way and more deeply the use of this?
>>
>>
>> On Thu, Apr 8, 2010 at 3:06 PM, chrysanthe m wrote:
>>
>>
>>
>>
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>>
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>
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Re: [Proto-Scripty] Re: enumerate hash
Hi Christophe
Thanks, but is there anything more to the syntax. Also how do you use that
optional context parameter with this within the loop and for what enhanced
value/processing does it give you?
On Mon, Apr 12, 2010 at 4:59 AM, Christophe Decaux <
christophe.dec...@gmail.com> wrote:
> If I understand well, what you're asking for is pretty close to what you
> suggested in your original post:
>
> hashToBeTested.each(function(pair){
> if(valueToTest==pair.value){
> hashToBeTested.unset(pair.key);
> }
> }
>
>
> Christophe
>
> Le 10 avr. 2010 à 12:36, chrysanthe m a écrit :
>
> Hi, again
> Sorry for being obtuse. But can someone help me and even understand how to
> write a function and call it on a hash that will take a value, compare it
> against each of the keys in the hash, on match delete the key/value, and
> return the hash. tia.
>
> On Thu, Apr 8, 2010 at 5:24 PM, chrysanthe m wrote:
>
>> Hi Alex
>> Thanks, but a newbie here so that was "drinking at a firehose". Let me
>> parse it to better understand.
>> First can you really invoke on two separate enumerable objects with that
>> [n,n1,n2] syntax? That is tremendous.
>> My problem is I need to first check the presence of a key before I unset
>> it b/c I found out unset-ing a non-existent key seems to zero the struct;
>> also it is more courteous, grin. So how would I construct the and
>> parameterize the annonymous function to do the check and if present "do it
>> to itself". Ideally I would like to pass in the enumerable, call the
>> function and return the modified(or not) enumerable in the function's
>> return.
>>
>> On Thu, Apr 8, 2010 at 4:41 PM, Alex Wallace wrote:
>>
>>> Ah, I see. You can handle this using Enumerable's invoke. This code
>>> should make it clear:
>>>
>>> a = new Hash({ x : "foo", y : "bar" });
>>> b = new Hash({ x : "zam", y : "moof" });
>>> a.get("x");
>>> "foo"
>>> b.get("x");
>>> "zam"
>>> [a,b].invoke("get","x");
>>> ["foo", "zam"]
>>> [a,b].invoke("unset","x")
>>> ["foo", "zam"]
>>> a.get("x")
>>> (undefined)
>>>
>>> Cheers,
>>> Alex
>>>
>>> On Thu, Apr 8, 2010 at 3:24 PM, chrysanthe m wrote:
>>>
Sorry sudden send resume in this reply
Hello
I am having a difficult time trying to enumerate a hash to determine if
a give key is in the hash and if so delete it and its value.
If I could approach it index it would be
function remove(valueToTest, hashToBeTested){
for(i=0;i>>> if(valueToTest==hashToBeTested[i])
hashToBeTested.unset(valueToTest);
}
Would I do it like
hashToBeTested.each(function(valueToTest){
if(valueToTest==this)hashToBeTested.unset(valueToTest);
},hashToBeTested);
return hashToBeTested;
which I am sure is wrong syntactically if not semantically. Can someone
guide the proper way and more deeply the use of this?
On Thu, Apr 8, 2010 at 3:06 PM, chrysanthe m wrote:
>
>
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>>
>>
>
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Re: [Proto-Scripty] Re: enumerate hash
If I understand well, what you're asking for is pretty close to what you
suggested in your original post:
hashToBeTested.each(function(pair){
if(valueToTest==pair.value){
hashToBeTested.unset(pair.key);
}
}
Christophe
Le 10 avr. 2010 à 12:36, chrysanthe m a écrit :
> Hi, again
> Sorry for being obtuse. But can someone help me and even understand how to
> write a function and call it on a hash that will take a value, compare it
> against each of the keys in the hash, on match delete the key/value, and
> return the hash. tia.
>
> On Thu, Apr 8, 2010 at 5:24 PM, chrysanthe m wrote:
> Hi Alex
> Thanks, but a newbie here so that was "drinking at a firehose". Let me parse
> it to better understand.
> First can you really invoke on two separate enumerable objects with that
> [n,n1,n2] syntax? That is tremendous.
> My problem is I need to first check the presence of a key before I unset it
> b/c I found out unset-ing a non-existent key seems to zero the struct; also
> it is more courteous, grin. So how would I construct the and parameterize
> the annonymous function to do the check and if present "do it to itself".
> Ideally I would like to pass in the enumerable, call the function and return
> the modified(or not) enumerable in the function's return.
>
> On Thu, Apr 8, 2010 at 4:41 PM, Alex Wallace wrote:
> Ah, I see. You can handle this using Enumerable's invoke. This code should
> make it clear:
>
> a = new Hash({ x : "foo", y : "bar" });
> b = new Hash({ x : "zam", y : "moof" });
> a.get("x");
> "foo"
> b.get("x");
> "zam"
> [a,b].invoke("get","x");
> ["foo", "zam"]
> [a,b].invoke("unset","x")
> ["foo", "zam"]
> a.get("x")
> (undefined)
>
> Cheers,
> Alex
>
> On Thu, Apr 8, 2010 at 3:24 PM, chrysanthe m wrote:
> Sorry sudden send resume in this reply
>
> Hello
> I am having a difficult time trying to enumerate a hash to determine if a
> give key is in the hash and if so delete it and its value.
> If I could approach it index it would be
> function remove(valueToTest, hashToBeTested){
>for(i=0;i if(valueToTest==hashToBeTested[i]) hashToBeTested.unset(valueToTest);
>}
>
> Would I do it like
>
> hashToBeTested.each(function(valueToTest){
> if(valueToTest==this)hashToBeTested.unset(valueToTest);
> },hashToBeTested);
> return hashToBeTested;
>
>
> which I am sure is wrong syntactically if not semantically. Can someone
> guide the proper way and more deeply the use of this?
>
>
> On Thu, Apr 8, 2010 at 3:06 PM, chrysanthe m wrote:
>
>
>
>
> --
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>
>
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>
>
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[Proto-Scripty] Re: enumerate hash
On Apr 10, 8:36 pm, chrysanthe m wrote:
> Hi, again
> Sorry for being obtuse. But can someone help me and even understand how to
> write a function and call it on a hash that will take a value, compare it
> against each of the keys in the hash, on match delete the key/value, and
> return the hash. tia.
Consider using a plain object:
var o = {foo:'foo', bar:'bar'};
function removeProperty(obj, prop) {
if (prop in obj) {
delete obj[prop];
} else {
return prop + ' not in object';
}
}
alert(o.foo);
removeProperty(o, 'foo');
alert(o.foo);
No need to "return" the object, it is modified in place.
--
Rob
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Re: [Proto-Scripty] Re: enumerate hash
Hi, again
Sorry for being obtuse. But can someone help me and even understand how to
write a function and call it on a hash that will take a value, compare it
against each of the keys in the hash, on match delete the key/value, and
return the hash. tia.
On Thu, Apr 8, 2010 at 5:24 PM, chrysanthe m wrote:
> Hi Alex
> Thanks, but a newbie here so that was "drinking at a firehose". Let me
> parse it to better understand.
> First can you really invoke on two separate enumerable objects with that
> [n,n1,n2] syntax? That is tremendous.
> My problem is I need to first check the presence of a key before I unset it
> b/c I found out unset-ing a non-existent key seems to zero the struct; also
> it is more courteous, grin. So how would I construct the and parameterize
> the annonymous function to do the check and if present "do it to itself".
> Ideally I would like to pass in the enumerable, call the function and return
> the modified(or not) enumerable in the function's return.
>
> On Thu, Apr 8, 2010 at 4:41 PM, Alex Wallace wrote:
>
>> Ah, I see. You can handle this using Enumerable's invoke. This code should
>> make it clear:
>>
>> a = new Hash({ x : "foo", y : "bar" });
>> b = new Hash({ x : "zam", y : "moof" });
>> a.get("x");
>> "foo"
>> b.get("x");
>> "zam"
>> [a,b].invoke("get","x");
>> ["foo", "zam"]
>> [a,b].invoke("unset","x")
>> ["foo", "zam"]
>> a.get("x")
>> (undefined)
>>
>> Cheers,
>> Alex
>>
>> On Thu, Apr 8, 2010 at 3:24 PM, chrysanthe m wrote:
>>
>>> Sorry sudden send resume in this reply
>>>
>>> Hello
>>> I am having a difficult time trying to enumerate a hash to determine if a
>>> give key is in the hash and if so delete it and its value.
>>> If I could approach it index it would be
>>> function remove(valueToTest, hashToBeTested){
>>>for(i=0;i>> if(valueToTest==hashToBeTested[i])
>>> hashToBeTested.unset(valueToTest);
>>>}
>>>
>>> Would I do it like
>>>
>>> hashToBeTested.each(function(valueToTest){
>>> if(valueToTest==this)hashToBeTested.unset(valueToTest);
>>> },hashToBeTested);
>>> return hashToBeTested;
>>>
>>>
>>> which I am sure is wrong syntactically if not semantically. Can someone
>>> guide the proper way and more deeply the use of this?
>>>
>>>
>>> On Thu, Apr 8, 2010 at 3:06 PM, chrysanthe m wrote:
>>>
>>>
>>> --
>>> You received this message because you are subscribed to the Google Groups
>>> "Prototype & script.aculo.us" group.
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>>>
>>
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>>
>
>
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Re: [Proto-Scripty] Re: enumerate hash
Hi Alex
Thanks, but a newbie here so that was "drinking at a firehose". Let me
parse it to better understand.
First can you really invoke on two separate enumerable objects with that
[n,n1,n2] syntax? That is tremendous.
My problem is I need to first check the presence of a key before I unset it
b/c I found out unset-ing a non-existent key seems to zero the struct; also
it is more courteous, grin. So how would I construct the and parameterize
the annonymous function to do the check and if present "do it to itself".
Ideally I would like to pass in the enumerable, call the function and return
the modified(or not) enumerable in the function's return.
On Thu, Apr 8, 2010 at 4:41 PM, Alex Wallace wrote:
> Ah, I see. You can handle this using Enumerable's invoke. This code should
> make it clear:
>
> a = new Hash({ x : "foo", y : "bar" });
> b = new Hash({ x : "zam", y : "moof" });
> a.get("x");
> "foo"
> b.get("x");
> "zam"
> [a,b].invoke("get","x");
> ["foo", "zam"]
> [a,b].invoke("unset","x")
> ["foo", "zam"]
> a.get("x")
> (undefined)
>
> Cheers,
> Alex
>
> On Thu, Apr 8, 2010 at 3:24 PM, chrysanthe m wrote:
>
>> Sorry sudden send resume in this reply
>>
>> Hello
>> I am having a difficult time trying to enumerate a hash to determine if a
>> give key is in the hash and if so delete it and its value.
>> If I could approach it index it would be
>> function remove(valueToTest, hashToBeTested){
>>for(i=0;i> if(valueToTest==hashToBeTested[i])
>> hashToBeTested.unset(valueToTest);
>>}
>>
>> Would I do it like
>>
>> hashToBeTested.each(function(valueToTest){
>> if(valueToTest==this)hashToBeTested.unset(valueToTest);
>> },hashToBeTested);
>> return hashToBeTested;
>>
>>
>> which I am sure is wrong syntactically if not semantically. Can someone
>> guide the proper way and more deeply the use of this?
>>
>>
>> On Thu, Apr 8, 2010 at 3:06 PM, chrysanthe m wrote:
>>
>>>
>>>
>>
>> --
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>> "Prototype & script.aculo.us" group.
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>> prototype-scriptacul...@googlegroups.com.
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>> prototype-scriptaculous+unsubscr...@googlegroups.com
>> .
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>> http://groups.google.com/group/prototype-scriptaculous?hl=en.
>>
>
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Re: [Proto-Scripty] Re: enumerate hash
Ah, I see. You can handle this using Enumerable's invoke. This code should
make it clear:
a = new Hash({ x : "foo", y : "bar" });
b = new Hash({ x : "zam", y : "moof" });
a.get("x");
"foo"
b.get("x");
"zam"
[a,b].invoke("get","x");
["foo", "zam"]
[a,b].invoke("unset","x")
["foo", "zam"]
a.get("x")
(undefined)
Cheers,
Alex
On Thu, Apr 8, 2010 at 3:24 PM, chrysanthe m wrote:
> Sorry sudden send resume in this reply
>
> Hello
> I am having a difficult time trying to enumerate a hash to determine if a
> give key is in the hash and if so delete it and its value.
> If I could approach it index it would be
> function remove(valueToTest, hashToBeTested){
>for(i=0;i if(valueToTest==hashToBeTested[i]) hashToBeTested.unset(valueToTest);
>}
>
> Would I do it like
>
> hashToBeTested.each(function(valueToTest){
> if(valueToTest==this)hashToBeTested.unset(valueToTest);
> },hashToBeTested);
> return hashToBeTested;
>
>
> which I am sure is wrong syntactically if not semantically. Can someone
> guide the proper way and more deeply the use of this?
>
>
> On Thu, Apr 8, 2010 at 3:06 PM, chrysanthe m wrote:
>
>>
>>
>
> --
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>
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[Proto-Scripty] Re: enumerate hash
Sorry sudden send resume in this reply
Hello
I am having a difficult time trying to enumerate a hash to determine if a
give key is in the hash and if so delete it and its value.
If I could approach it index it would be
function remove(valueToTest, hashToBeTested){
for(i=0;i wrote:
>
>
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