Hello,
ascii package provides a alternative to org-babel/R. it allows to use Sweave
with org files (many thanks to Erik and his blog for this...).
http://eusebe.github.com/ascii/#_other_outputs
http://eusebe.github.com/ascii/org.html#undefined
david
2009/11/20 Thomas S. Dye t...@tsdye.com
Hi
On Fri, 2009-11-20 at 17:40 -0800, Santosh wrote:
Dear Rxperts!
I was wondering if it is possible to write a function which can take in
argument of a subset or condition.. Of course, I am aware of the alternate
methods like coplot, par.plot, xyplot etc... I am specifically interested in
Hi Anonymous, (Maybe next time include your name)
There are data objects in R that are designed for spatial data, look at
the sp package. Casting them into this format gives you an enormous
increase in flexibility with analyzing spatial data. See the example
below using your example:
Senlin Liang wrote:
I have a file with 3 cols as:
xyvalue
110.5000
121.8333
134.
210.7500
220.7500
234
310.7500
321.4167
335.1667
I read them in using
p - read.table(data.txt, header=TRUE)
My questoin: how to
On 11/21/2009 10:15 AM, Peng Yu wrote:
image(array,axes=F)
axis(side=1,at=seq(from=par()$usr[1],to=par()$usr[2],length=size),labels=some_labels)
I have the above code to plot a heatmap. But I want to make the labels
on the x-axis vertical. Could somebody let me know how to do it?
On 11/21/2009 12:23 PM, Peng Yu wrote:
The labels on the axis overlap. Is there a way to change their font
size smaller?
m=100
n=100
X=replicate(n,rnorm(m))
image(X,axes=F)
axis(side=1,at=seq(from=par()$usr[1],to=par()$usr[2],length=(m+1))[1:m],labels=replicate(m,
'A'),las=2)
Thanks to both of you. Problem's solved. Greatly appreciated. :]
Chris
Chris Li wrote:
Hi all,
I have got a dataset like the following:
3
5
7
3
9
7
i.e. random numbers with some repeats.
I want R to classify them for me. E.g. every row that has a value of 3
will be asigned
Hi Everyone,
I need to take the square root of the following matrix:
[,1] [,2][,3]
[1,] 0.5401984 -0.3998675 -1.3785897
[2,] -0.3998675 1.0561872 0.8158639
[3,] -1.3785897 0.8158639 1.6073119
I tried Choleski which fails. I then tried Choleski
I tried to follow instruction given by this webpage:
http://www.omegahat.org/RSJava/ . but I cant download. Is there another way
to download this package in R.
Thank you for your help
[[alternative HTML version deleted]]
__
R-help@r-project.org
Hi, Fabio,
I only have an idea on how to calculate deviance explained by the fixed
effects. If you remove fixed effects and introduce one null model such as
m2-lmer(response-var ~ 1+(1|Site/Area/Transect),family=binomial). Then,
(deviance(m2)-deviance(m1))/deviance(m2) will represent deviance
Dear R users,
I am frustrated by the residual sum of squares calculation. From Statistical
Medhods by Snedecor Cochran, I know sum(resid(model)^2) should be one
method. However, there is a automatic code in R for this operation:
deviance(model). When I compare the results from these two methods,
On Nov 21, 2009, at 7:46 AM, thierry CHEKOUO T. wrote:
I tried to follow instruction given by this webpage:
http://www.omegahat.org/RSJava/ . but I cant download. Is there
another way
to download this package in R.
How did you try? What error do you get?
--
David Winsemius, MD
Heritage
I am trying to compile the r.stream* set of addons.
Ubuntu 9.10 64 bit
I have installed the grass packages from the repositories
I have also compiled grass 6.5 from source.
I have taken the r.stream* from the addons svn and placed the sources
in the grass source tree - in the raster file
I run
Hello all,
I am trying to use the EBImage package,
(EBImage 3.2.0 and ImageMagick 6.5.7-9 2009-11-19 Q8 (dinamic linked)
with R 2.10.0 winXP)
but I get the following error:
#-
library(EBImage)
Loading required package: abind
?readImage
## Reads
Hi，all friends,
Please help me understand this sentence below:
“From this set, 858 columns not significantly correlated with the
response variable TBG at the 5% level were removed, leaving a set of 390
columns.” and “ the F-test's value for the one-parameter correlation with
the descriptor
Dear R users,
I would like to make my R code for MCMC faster. It is possible to integrate
C code into R but I think C is too complicated for me. I would need a C
introduction only for MCMC and I do not know if such a thing exists.
I was thinking of Python (and scipy). Where could I read about
This is not a problem of numDerv. The problem is that the function PP1 is
stochastic, i.e. it gives different values for the same argument p. This is
due to the function pmvnorm(), which I presume uses some kind of Monte Carlo
sampling to compute the integral of a multivariate normal.
On Nov 21, 2009, at 8:03 AM, bbslover wrote:
Hi，all friends,
Please help me understand this sentence below:
“From this set, 858 columns not significantly correlated with the
response variable TBG at the 5% level were removed, leaving a set of
390
columns.” and “ the F-test's value for
Hi Jean,
You can integrate R and Python using RSPython or Rpy. But why would
Python be faster than R? Both are interpreted languages and probably
about as fast (please someone correct me if I'm wrong). It probably only
help if there is a C mcmc implementation linked to python (that you link
On Sat, Nov 21, 2009 at 2:29 PM, Jean Legeande jean.legea...@gmail.com wrote:
Dear R users,
I would like to make my R code for MCMC faster. It is possible to integrate
C code into R but I think C is too complicated for me. I would need a C
introduction only for MCMC and I do not know if such
Sorry for making a mistake! It should be,
(m...@deviance[wrss]...@deviance[wrss])/m...@deviance[wrss]
willow1980 wrote:
Hi, Fabio,
I only have an idea on how to calculate deviance explained by the fixed
effects. If you remove fixed effects and introduce one null model such as
Check out examples in the lattice package and ggplot2 package.
For example let's say you plot points and confidence intervals. These packages
will then allow you to plot these values by group and by combinations of groups.
Look up conditioning and faceting in these packages.
On Wed, Nov 18, 2009
Hello
Thanks I will surely look into it
Regards
Our Thoughts have the Power to Change our Destiny.
Sunita
On Sat, Nov 21, 2009 at 9:22 PM, Juliet Hannah juliet.han...@gmail.comwrote:
Check out examples in the lattice package and ggplot2 package.
For example let's say you plot points and
Hi,
I got problem in using title function to create a title for multiple plots
presented together by par. As can be seen in the attached file, the title is
displayed truncated and the subtitle doesn't get displayed. Here is the code:
par(mfrow = c(1,2))
plot(c(1,2,3), c(9,8,7))
Hi Carol,
Try this
par(oma=c(2,2,2,2))
par(mfrow = c(1,2))
plot(c(1,2,3), c(9,8,7))
plot(c(1,2,3), c(9,8,7))
title(main = Main title, sub =Sub title,outer = TRUE, cex.main=1.5,
cex.sub = 1.5)
par(oma=c(2,2,2,2)) -- can be used to define outline of the plot. Arguments
here are for
On Nov 21, 2009, at 11:39 AM, Gary wrote:
Hi Carol,
Try this
par(oma=c(2,2,2,2))
par(mfrow = c(1,2))
plot(c(1,2,3), c(9,8,7))
plot(c(1,2,3), c(9,8,7))
title(main = Main title, sub =Sub title,outer = TRUE,
cex.main=1.5,
cex.sub = 1.5)
I'm curious about what you are seeing with that
On Sat, 21 Nov 2009, simona.racio...@libero.it wrote:
Hi Everyone,
I need to take the square root of the following matrix:
[,1] [,2][,3]
[1,] 0.5401984 -0.3998675 -1.3785897
[2,] -0.3998675 1.0561872 0.8158639
[3,] -1.3785897 0.8158639
One little thing that I think Barry
meant to say.
If the bottleneck is in your code, you
may be able to improve the situation
enough by merely rewriting the R code
of your function. If that doesn't work,
then you can move to C.
Patrick Burns
patr...@burns-stat.com
+44 (0)20 8525 0696
subtitle still doesn't get displayed
--- On Sat, 11/21/09, Gurmeet gurm...@email.unc.edu wrote:
From: Gurmeet gurm...@email.unc.edu
Subject: Re: [R] title problem
To: carol white wht_...@yahoo.com
Cc: r-help@r-project.org
Date: Saturday, November 21, 2009, 8:30 AM
Hi Carol,
Try this
You are right David/Carol. It seems outer=T does not work for Sub title.
I'm not sure what Carol is looking for, but in case you need separate sub
titles for each graph, then you may want to use more than one title
statement. Like:
par(oma=c(2,2,2,2))
par(mfrow = c(1,2))
plot(c(1,2,3), c(9,8,7))
Thanks Gary. No I want one subtitle for all plots below the main title.
subtitle should work but if doesn't at the worst case I could do as follows:
title(main = Main title\nSub title,outer = TRUE, cex.main=1.5,...)
--- On Sat, 11/21/09, Gary mail2garymil...@gmail.com wrote:
From: Gary
Charles C. Berry wrote:
On Sat, 21 Nov 2009, simona.racio...@libero.it wrote:
Hi Everyone,
I need to take the square root of the following matrix:
[,1] [,2][,3]
[1,] 0.5401984 -0.3998675 -1.3785897
[2,] -0.3998675 1.0561872 0.8158639
[3,]
Try the line= argument on title()
opar - par(oma = 4 * c(1, 1, 1, 1), no.readonly = TRUE)
par(mfrow = 1:2)
plot(1:3, 9:7)
plot(1:3, 7:9)
for(i in 1:3) title(main = i, line = i, outer = TRUE)
par(opar)
On Sat, Nov 21, 2009 at 12:47 PM, carol white wht_...@yahoo.com wrote:
Thanks Gary. No I want
On Nov 21, 2009, at 12:57 PM, Gabor Grothendieck wrote:
Try the line= argument on title()
opar - par(oma = 4 * c(1, 1, 1, 1), no.readonly = TRUE)
par(mfrow = 1:2)
plot(1:3, 9:7)
plot(1:3, 7:9)
for(i in 1:3) title(main = i, line = i, outer = TRUE)
par(opar)
I was not sure what Carol was
It seems that there is a problem in
displaying subtitle in general, independently from
multi-plot display. when I do
plot (c(1,2,3), c(9,8,7), type = l)
title(main = Main title, sub =Sub title,cex.main=2,
cex.sub = 2)
subtitle doesn't get displayed
--- On Sat, 11/21/09, David
Thank you Paul, Barry and Patrick.
I will do what you recommand (the profiling).
I have heard several times that for example Matlab would be faster than R...
This is why I thought of switching to Python, though it is also interpreted.
I thought it would be faster.
Best,
Jean
2009/11/21 Patrick
Cleber Borges wrote:
Hello all,
I am trying to use the EBImage package,
(EBImage 3.2.0 and ImageMagick 6.5.7-9 2009-11-19 Q8 (dinamic linked)
with R 2.10.0 winXP)
but I get the following error:
#-
library(EBImage)
Loading required package:
I think Gabor suggestion works. Adding line= option in title makes it
work. Here is a little modification of what Gabor suggested, Carol you may
try this code:
par(oma=c(3,1,4,1))
par(mfrow = c(1,2))
plot(c(1,2,3), c(9,8,7))
plot(c(1,2,3), c(9,8,7))
title(main = Main title line1\nMain title
Your code works for me on Windows Vista using R version 2.10.0
Patched (2009-11-16 r50456)
Try it starting from a fresh session.
On Sat, Nov 21, 2009 at 1:19 PM, carol white wht_...@yahoo.com wrote:
It seems that there is a problem in
displaying subtitle in general, independently from
carol white wrote:
It seems that there is a problem in
displaying subtitle in general, independently from
multi-plot display. when I do
plot (c(1,2,3), c(9,8,7), type = l)
title(main = Main title, sub =Sub title,cex.main=2,
cex.sub = 2)
You do not know that you have to look at the
On Nov 21, 2009, at 1:19 PM, Gary wrote:
I think Gabor suggestion works. Adding line= option in title makes
it work. Here is a little modification of what Gabor suggested,
Carol you may try this code:
par(oma=c(3,1,4,1))
par(mfrow = c(1,2))
plot(c(1,2,3), c(9,8,7))
plot(c(1,2,3),
We have been using pymc as an alternative to WinBUGS, and have been
very pleased with it. I've begun working on an R2Pymc package, but
don't have anything ready for sharing yet.
Here's the pymc page:
http://code.google.com/p/pymc/
and the repo is here:
http://github.com/pymc-devs/pymc
I've
Thanks Uwe for your reply.
I can open the lena-color.png file with several programs: firefox, M$
Picture Manager, IMDisplay (GUI of ImageMagick)
I converted lena-color.png in lena2.jpeg using M$ Picture Manager.
With a old version of rimage package, I can read JPEG files (only) with
I am trying to export a data frame to SPSS. I am using write.foreign to
export the .txt data file and the .sps SPSS syntax file to read the .txt
file into SPSS. I am running into problems because my data set includes
variable names that are longer than 8 characters, and the write.foreign
I would like to cumulatively sum rows in a matrix, in which each row has 1
NA value. The usual na.rm=TRUE does not seem to work with the command
cumsum. Is there another way to ignore the NAs or do I need to figure out a
different way to do this?
Here's an example matrix of title proportion:
Hi Carol,
Try this
par(oma=c(2,2,2,2))
par(mfrow = c(1,2))
plot(c(1,2,3), c(9,8,7))
plot(c(1,2,3), c(9,8,7))
title(main = Main title, sub =Sub title,outer = TRUE, cex.main=1.5,
cex.sub = 1.5)
par(oma=c(2,2,2,2)) -- can be used to define outline of the plot. Arguments
here are for
Within a very large matrix composed of a mix of values and NAs, e.g, matrix A:
[,1] [,2] [,3]
[1,]1 NA NA
[2,]3 NA NA
[3,]3 10 17
[4,]4 12 18
[5,]6 16 19
[6,]6 22 20
[7,]5 11 NA
I need to be able to consecutively number, in new
Thanks for you comment.
There is certainly some Monte Carlo sampling involved in mvtnorm but
why derivatives could not be computed? In theory, the derivatives
exist (eg. bivariate probit). Moreover, when used with optim, there
are some numerical derivatives computed... does it mean that mvtnorm
Hi guys, would like to ask a question about mc3.reg, I am new to R however I
have spent many hours understanding and getting all other functions to work
except this one. I am running mc3.reg and after getting the results would like
to do 2 things that are definitely possible, and managed to do
if I understand what you want correctly, then one approach is:
A - matrix(sample(50, 21), 7, 3)
A[sample(21, 5)] - NA
A
row(A) - apply(is.na(A), 2, cumsum)
I hope it helps.
Best,
Dimitris
Jim Bouldin wrote:
Within a very large matrix composed of a mix of values and NAs, e.g, matrix A:
Hello all,
Thank you for the previous assistance I received from this listserve!
My current question is: How can I create an appropriate matrix of
values from a GAM (actually a GAMM) to make a 3-D plot? This model is
fit as a tensor product spline of two predictors and I have used it to
make
Hi Tracy,
What do you want the program to do with the missing values? If you
want to treat them as zeros, you could use
cum.na - function(x) {
x[which(is.na(x))] - 0
return(cumsum(x))
}
cumsums - apply(proportion, 1, cum.na)
-Ista
On Sat, Nov 21, 2009 at 2:34 PM, Tracy Bowerman
I would like to cumulatively sum rows in a matrix, in which each row has 1
NA value, which I do NOT want to treat as 0s. The NAs are placeholders
where there is actually no data, which is not the same as a 0. The usual
na.rm=TRUE does not seem to work with the command cumsum. Is there
another
-Original Message-
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of Jim Bouldin
Sent: Saturday, November 21, 2009 10:34 AM
To: r-help@r-project.org
Subject: [R] consecutive numbering of elements in a matrix
Within a very large matrix
On 21/11/2009 3:11 PM, Paul Simonin wrote:
Hello all,
Thank you for the previous assistance I received from this listserve!
My current question is: How can I create an appropriate matrix of
values from a GAM (actually a GAMM) to make a 3-D plot? This model is
fit as a tensor product spline
-Original Message-
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of Tracy Bowerman
Sent: Saturday, November 21, 2009 12:19 PM
To: r-help
Subject: [R] how to ignore NA when using cumsum WHILE retaining NAs?
I would like to cumulatively sum rows
On Nov 21, 2009, at 3:25 PM, William Dunlap wrote:
-Original Message-
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of Jim Bouldin
Sent: Saturday, November 21, 2009 10:34 AM
To: r-help@r-project.org
Subject: [R] consecutive numbering of elements in
Try this:
apply(proportion, 1, function(x)cumsum(na.exclude(x)))
On Sat, Nov 21, 2009 at 5:34 PM, Tracy Bowerman
tracy.bower...@aggiemail.usu.edu wrote:
I would like to cumulatively sum rows in a matrix, in which each row has 1
NA value. The usual na.rm=TRUE does not seem to work with the
Thank you and apologies--I did not make it clear that there are no NAs
mixed in with the valid values. Rather, they all occur consecutively,
either toward the beginning of end of the column.
Jim
I didn't know what you wanted to do if there were NA's
in the middle of a column.
Bill Dunlap
Is there a way to make the
plot(cox.zph(model))
use some other symbol than open circles?
plot(cox.zph(model), pch=whatever) seems to have no effect.
Thanks.
--Chris Ryan
__
R-help@r-project.org mailing list
Thank you Whit.
So you have experience with both R and Python ? How do they compare ?
Best,
Jean
2009/11/21 Whit Armstrong armstrong.w...@gmail.com
We have been using pymc as an alternative to WinBUGS, and have been
very pleased with it. I've begun working on an R2Pymc package, but
don't
I think the issue is in the function fr,
?apply
apply returns a vector or array or list of values
So if the inner apply returns a list (this happens when different
number of elements in y are positive in different rows) then outer
apply cannot coerce it into the correct format to apply the
My hunch is that Python and R run at about the same speed, and both
use C libraries for speedups (Python primarily via the numpy package).
That's not necessarily true. There can be enormous differences
between interpreted languages, and R appears to be a particularly slow
one (which
On Nov 21, 2009, at 4:28 PM, cr...@binghamton.edu wrote:
Is there a way to make the
plot(cox.zph(model))
use some other symbol than open circles?
Yes, but after looking at the code, the points call does not have
trailing ... so, not without modifying the function:
library(survival)
David Winsemius wrote:
On Nov 21, 2009, at 1:19 PM, Gary wrote:
I think Gabor suggestion works. Adding line= option in title makes
it work. Here is a little modification of what Gabor suggested, Carol
you may try this code:
par(oma=c(3,1,4,1))
par(mfrow = c(1,2))
plot(c(1,2,3), c(9,8,7))
Dear R People:
I just installed R-2.10.0 on Karmic Koala Ubuntu, via the sudo apt-get
install r-base, etc.
However, when I try to install an Rcmdr Plugin package, I get the following:
install.packages(RcmdrPlugin.qual,depen=TRUE)
Warning in install.packages(RcmdrPlugin.qual, depen = TRUE) :
Dear R Helpers,
I am missing something very elementary here, and I don't seem to get it from
the help pages of the ave, seq and seq_along functions, so I wonder if you
could offer a quick help.
To use an example from an earlier post on this list, I have a dataframe of this
kind:
dat =
try this:
# create a factor and then convert back to numeric
x$nb - as.integer(factor(x$name, levels=unique(x$name))) + 99
x
name freq nb
1 Mary1 100
2 Mary2 100
3 Mary3 100
4 Sam1 101
5 Sam2 101
6 John1 102
7 John2 102
8 John3 102
9 John4 102
On Sat,
Bill Dunlap
Spotfire, TIBCO Software
wdunlap tibco.com
-Original Message-
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of Dana Sevak
Sent: Saturday, November 21, 2009 4:00 PM
To: r-help@r-project.org
Subject: [R] Help with indexing
Dear
Thank you Stefan. That's really interesting.
My guess is that Python is not much more complicated to program than R, and
that we can integrate some codes into R. If it can be 10 times faster,
that's great !
Best,
Jean
2009/11/21 Stefan Evert stefan.ev...@uos.de
My hunch is that Python and R
hello,
I am trying to do exploratory factor analysis with BRFSS dataset (
http://www.cdc.gov/brfss/technical_infodata/surveydata/2008.htm) for a
couple of days, but I was not able to do that and got frustrated. Can
anybody help me with step by step guide? BRFSS dataset provides ASCII or SAS
There is work going on on two byte compilers for R:
http://www.stat.uiowa.edu/~luke/R/compiler/
http://www.milbo.users.sonic.net/ra
You could check whether running under either of those speeds up your R
code sufficiently that you don't need to rewrite it.
On Sat, Nov 21, 2009 at 9:29 AM, Jean
Go back to your calculus text and review the definition of derivative:
f'(x) = lim h - 0 [f(x+h) - f(x)] / h
when f(x) and f(x + h) are random variables, the above limit does not exist.
In fact, f'(x) is also a random variable.
Now, if you want the derivative you have to use a multivariate
Dear R-helpers,
I'd like to use glmmPQL to predict binary responses based on a data.frame
data1
containing N entries (N1000):
target covariate1 covariate2 covariate3 ...covariateM
cluster
1341311 -0.30031885 0 0-2.886870e-07
1
38370
Exactly what have you tried and what did not work? I downloaded the
'.asc' (text) version of the data and it appears to be fixed format
with 1294 characters per line; there are about 414K lines of data in
the file. How much of the data do you need to extract? You can read
in a portion of the
I want to understand what heatmap.2() is exactly doing. So I tried the
following program. But the results by image() is still not the same as
the result by heatmap.2(). Could somebody let me know how to make both
results the same (in terms of the x and y axis label orders)?
On Nov 21, 2009, at 7:58 PM, chloe yoon wrote:
hello,
I am trying to do exploratory factor analysis with BRFSS dataset (
http://www.cdc.gov/brfss/technical_infodata/surveydata/2008.htm) for a
couple of days, but I was not able to do that and got frustrated. Can
anybody help me with step by
I would appreciate any help on this problem. I need to perform a sample size
analysis for a study comparing the performances of 2 different methods of
diagnostic classification. Assume that method 1 has an accuracy of p1
against known truths (a reference classification, as multiple categories),
Dear list member,
My question is related to input file format to an Anova from car package.
Here is an example of what I did:
My file format is like this (and I dislike the idea that I will need
to recode it):
Hormone day Block Treatment Plant Diameter High N.Leaves
SH 23 1 1 1 3.19 25.3 2
SH
On Nov 21, 2009, at 8:41 PM, David Winsemius wrote:
On Nov 21, 2009, at 7:58 PM, chloe yoon wrote:
hello,
I am trying to do exploratory factor analysis with BRFSS dataset (
http://www.cdc.gov/brfss/technical_infodata/surveydata/2008.htm)
for a
couple of days, but I was not able to do
exampledata - rnorm(1)
summary(exampledata)
Min. 1st Qu.Median Mean 3rd Qu. Max.
-4.03 -0.666200 -0.023390 -0.009384 0.664700 4.092000
desc - function(mydata) {
+require(e1071)
+quantls - quantile(x=mydata, probs=seq(from=0, to=1, by=0.25))
+
Hey everybody!
I have a problem with triming a string. I can get rid of the blank space in
front and at the back of a string and even trim a string at the back. But I
don't know how to do it in the front.
For Example: I have a string Blackberry and i want to delete the first 5
characters to get
i just found the following list, i wondered if anybody could add to this as i
have to characterize a large data set and am new to R...the list below was
so helpfulcan you add to this???
Just to forestall confusion amongst those who would like to use one of
the functions called describe...
Hello all...
I'm attempting to write my own GAM plot function, so I can overlay it
on top of an already existing plot.
Problem is that after I do the gam, e.g. m-gam(...), I cannot match
the graph that gam.plot outputs when I attempt to plot the values
from m$residuals,
Hi guys ,
Im trying to do principal component analysis in R . There is 2 ways of doing
it , I believe.
One is doing principal component analysis right away the other way is
standardizing the matrix first using s = scale(m)and then apply principal
component analysis.
How do I tell what
Hi,
with intention of to make register of a workaround...
I uninstalled the ImageMagick Q8 and installed a Q16 version and works
fine! :-)
example(EBImage) run for every demos!!!
Thanks
Cleber N. Borges
C:\Documents and Settings\Cleberconvert -version
Version: ImageMagick 6.5.7-9
Marcelo Laia wrote:
Dear list member,
My question is related to input file format to an Anova from car package.
Here is an example of what I did:
My file format is like this (and I dislike the idea that I will need
to recode it):
Hormone day Block Treatment Plant Diameter High N.Leaves
SH
You need to install pkg e1071. Surely the phrase
there is no package called 'e1071'
is a pretty strong clue.
-Peter Ehlers
frenchcr wrote:
exampledata - rnorm(1)
summary(exampledata)
Min. 1st Qu.Median Mean 3rd Qu. Max.
-4.03 -0.666200 -0.023390 -0.009384
Sorry, minor fix at end.
Peter Ehlers wrote:
Marcelo Laia wrote:
Dear list member,
My question is related to input file format to an Anova from car package.
Here is an example of what I did:
My file format is like this (and I dislike the idea that I will need
to recode it):
Hormone day
Hello,
We are looking to adjust the font size of the axis annotation on the graph
that results from use of the metaplot() function. Metaplot seems to respond
to cex and cex.lab to change those graphical parameters, but it doesn't
respond to cex.axis. Is there a way to work around this by creating
Dear List,
I have very little experience with lists and am having some very basic
problems. I don't know how to add columns to the lower levels of a list, or
how to take something from the upper level and add it as a column to the lower
level. I am analyzing animal movement data in the
Hi Ivansek,
Here is a suggestion using substr():
x - 'Blackberry'
substr(x, 6, nchar(x))
[1] berry
HTH,
Jorge
On Sat, Nov 21, 2009 at 4:05 PM, rok90 wrote:
Hey everybody!
I have a problem with triming a string. I can get rid of the blank space in
front and at the back of a string and
Here are three ways:
substring(blackberry, 6)
[1] berry
sub(^black, , blackberry)
[1] berry
sub(.{5}, , blackberry)
[1] berry
On Sat, Nov 21, 2009 at 4:05 PM, rok90 ivansek.lab...@gmail.com wrote:
Hey everybody!
I have a problem with triming a string. I can get rid of the blank space in
Dear R Community:
Recently, I have managed to plot some really useful graphs of my
research data using persp(). I have even figured out how to overplot
rectangular regions (corresponding to submatrices) with a different
color. This is accomplished by using par(new=T). I am now searching
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