[sage-support] How would I list just the 3 cycles in AlternatingGroup()

I can generate a list from any given group, but how would I go about generating a list of just 3 or 5 cycles? --~--~-~--~~~---~--~~ To post to this group, send email to sage-support@googlegroups.com To unsubscribe from this group, send email to

[sage-support] Re: How would I list just the 3 cycles in AlternatingGroup()

the order of the element? On Thu, May 14, 2009 at 7:53 PM, jimfar jamesfar...@mac.com wrote: I can generate a list from any given group, but how would I go about generating a list of just 3 or 5 cycles? --~--~-~--~~~---~--~~ To post to this group, send email

[sage-support] Re: How would I list just the 3 cycles in AlternatingGroup()

, May 14, 2009 at 8:57 PM, jimfar jamesfar...@mac.com wrote: I can find the order of the element, but I am looking to generate a list of all of the 3 cycles in something like AlternatingGroup(5) where the list will not go on for too long. On May 14, 5:04 pm, David Joyner wdjoy...@gmail.com

[sage-support] How do I find the inverse of an element in an Alternating Group?

After generating sage: B=AlternatingGroup(5) and verifying an element is in it, sage: c=(1,2,3) sage: c in B True How do I find the inverse of c in B? --~--~-~--~~~---~--~~ To post to this group, send email to sage-support@googlegroups.com To unsubscribe from

[sage-support] Re: How do I find the inverse of an element in an Alternating Group?

Thank you very much On May 6, 7:47 pm, Robert Bradshaw rober...@math.washington.edu wrote: On May 6, 2009, at 7:44 PM, jimfar wrote: After generating sage: B=AlternatingGroup(5) and verifying an element is in it, sage: c=(1,2,3) sage: c in B True How do I find the inverse of c

[sage-support] How do I show a permutation group is the alternating group?

I have generated a group using, sage: B=PermutationGroup(['(1,2,4,5,3)','(2,3,1,4,5)']) And I know I can generate a list of the elements and determine the order, but how do I show that this is actually sage: AlternatingGroup(5). Is there a command to verify that B=AlternatingGroup(5)?

[sage-support] Re: How do I show a permutation group is the alternating group?

thank you very much On May 4, 11:57 pm, Michael Welsh yom...@yomcat.geek.nz wrote: sage: B=PermutationGroup(['(1,2,4,5,3)','(2,3,1,4,5)']) sage: B == AlternatingGroup(5) True sage: B == AlternatingGroup(7) False On 5/05/2009, at 6:47 PM, jimfar wrote: I have generated a group using