Re: [swift-users] Why there's no Character literals?

In Ruby they have special literals, like so: So this would be an array of chars %c{a b c d e f g} *___* *James⎥Head of Trolls* *ja...@supmenow.com ⎥supmenow.com * *Sup* *Runway East * *10 Finsbury Square* *London* *

Re: [swift-users] Why there's no Character literals?

Yes, but then a similar complaint could be made that I wanted a String this time. The only real way to tell the difference is to use something like single quotes. > On Jul 10, 2016, at 14:03, Rick Mann via swift-users > wrote: > > >> On Jul 10, 2016, at 11:44 , Saagar

Re: [swift-users] Why there's no Character literals?

Of course not. Struct Set is commonly known. let foo:Set = [1,2,3,4] let bar:Set = [1,2,3,4] If you do not specify them as Sets, foo and bar will be Arrays. Zhaoxin On Thu, Jul 7, 2016 at 5:35 PM, 王 黎明 wrote: > > In Swift, we must specify the type for Character

Re: [swift-users] Why there's no Character literals?

> On Jul 10, 2016, at 11:44 , Saagar Jha via swift-users > wrote: > > Well, what if you wanted to create a String with one character? There’s no > way to differentiate. That hardly seems like the justification. In that case, you'd specify the type: let s: String =

Re: [swift-users] Why there's no Character literals?

Well, what if you wanted to create a String with one character? There’s no way to differentiate. > On Jul 7, 2016, at 02:35, 王 黎明 via swift-users [swift-users@swift.org](mailto:swift-users@swift.org) wrote: > In Swift, we must specify the type for Character variables(because there’s no Character

[swift-users] Why there's no Character literals?

In Swift, we must specify the type for Character variables(because there’s no Character literals): let eol: Character = “\n” it's not a big problem, but, Is it the unique case that can’t use type infer? ___ swift-users mailing list