Sorry if i am being imprecise, but actually i cant describe it better than
in my opening post. I want X, Y and Phi in terms of everything else.
Maybe i was wrong in assuming that i could simply pass sympy the system of
equations and it would deliver the solutions in a form that i could then
On 14 June 2016 at 20:30, wrote:
> I had the same idea earlier, but i dropped it because my intuition was, that
> three quadratic equations are worse than three linear and one quadratic
> equation :-)
>
> Since you brought this approach up again, i tried it now, but
I had the same idea earlier, but i dropped it because my intuition was,
that three quadratic equations are worse than three linear and one
quadratic equation :-)
Since you brought this approach up again, i tried it now, but sympy does
not seem to find a solution.
You can check out my code
On 11 June 2016 at 17:52, wrote:
>
> Yes, exactly, its the linear bearings that can be at different locations and
> force therefore the board to different positions, those are the ones that i
> am interested in!
Rather than thinking about x, y and theta think about the
Yes, exactly, its the linear bearings that can be at different locations
and force therefore the board to different positions, those are the ones
that i am interested in!
On Saturday, June 11, 2016 at 6:49:34 PM UTC+2, Jason Moore wrote:
>
> If the blue dots are fixed on the board, doesn't the
If the blue dots are fixed on the board, doesn't the linear bearings remove
all degrees of freedom? I don't see how this thing can move.
Jason
moorepants.info
+01 530-601-9791
On Sat, Jun 11, 2016 at 8:57 AM, wrote:
> They describe the location of the board (the blue
They describe the location of the board (the blue rectangle) in relation to
its "normal" position by a rotation about an angle of phi and a translation
of x and y.
On Saturday, June 11, 2016 at 5:40:26 PM UTC+2, Jason Moore wrote:
>
> Where are phi, x, y on the diagram?
>
>
> Jason
>
Where are phi, x, y on the diagram?
Jason
moorepants.info
+01 530-601-9791
On Sat, Jun 11, 2016 at 6:35 AM, wrote:
> I guess its hard to get from my description, so i uploaded a drawing to
> visualize the physical problem: http://pasteboard.co/1Bvt53hY.png
>
> Thanks
I guess its hard to get from my description, so i uploaded a drawing to
visualize the physical problem: http://pasteboard.co/1Bvt53hY.png
Thanks for your interest!
On Saturday, June 11, 2016 at 3:13:52 PM UTC+2, janosc...@gmail.com wrote:
>
>
> Physically, the rows of A are three points fixed
Physically, the rows of A are three points fixed on a movable board.
These points run freely in three linear bearings which are placed on a
fixed base.
The linear bearings are described in hesse normal form in the rows of
matrix C.
The robust motion matrix B is the transformation which
Physically what are all the matrices. Do A and C also describe rotations.
Please give the actual physics problem as well as the resulting math.
On Sat, Jun 11, 2016 at 6:37 AM, wrote:
> My description was a little compressed, so i had to clean up the code to
> match my
My description was a little compressed, so i had to clean up the code to
match my description again ...
The code is available here: http://pastebin.com/MMW3B88h
I hope its readable for you.
Am Donnerstag, 9. Juni 2016 20:24:35 UTC+2 schrieb Jason Moore:
>
> Can you please share the code so we
Can you please share the code so we can see what you are doing?
Jason
moorepants.info
+01 530-601-9791
On Wed, Jun 8, 2016 at 11:58 PM, wrote:
> I am trying to solve a system of equations with sympy that arises from a
> constraint of the form:
>
> (A x B) x C = D
>
I am trying to solve a system of equations with sympy that arises from a
constraint of the form:
(A x B) x C = D
where
* A, B, C and D are 3x3 matrices
* the diagonal of D should be zero
* B is a "rigid motion 2D" transformation, with elements cos(phi),
+-sin(phi), x and y
* A and C are
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